
TL;DR
This paper presents counterexamples to Hedetniemi's conjecture, showing that the chromatic number of the product of two graphs can be less than the minimum of their individual chromatic numbers.
Contribution
It provides the first known counterexamples to Hedetniemi's conjecture, challenging a long-standing assumption in graph theory.
Findings
Counterexamples where $ ext{chromatic}(G imes H) < ext{min}( ext{chromatic}(G), ext{chromatic}(H))$
Demonstrates the conjecture does not hold universally
Implications for graph coloring theory and related problems
Abstract
The chromatic number of can be smaller than the minimum of the chromatic numbers of finite simple graphs and .
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Counterexamples to Hedetniemi’s conjecture
Yaroslav Shitov
Abstract.
The chromatic number of can be less than the minimum of the chromatic numbers of finite simple graphs and .
The tensor product of finite simple graphs and has vertex set , and pairs and are adjacent if and only if and . One can easily see that because a proper coloring of the graph can be lifted to the coloring of . Similarly, a proper coloring of leads to a proper coloring of with the same number of colors, so we get
[TABLE]
The classical conjecture of S. T. Hedetniemi [8] posited the equality for all and . More than 50 years have passed since the conjecture appeared, and it keeps attracting serious attention of researchers working in graph theory and combinatorics; we mention four exhaustive survey papers [9, 11, 13, 18] for more detailed information on the topic. Here, we briefly recall that Hedetniemi’s conjecture was proved in many special cases, including graphs with chromatic number at most four [3], graphs containing large cliques [1, 2, 16], circular graphs and products of cycles [15], and Kneser graphs and hypergraphs [6]. The conjecture gave an impetus to the study of multiplicative graphs, which remains remarkably active and important in its own right [5, 12, 17]. A generalization of Hedetniemi’s conjecture to fractional chromatic numbers turned out to be true [19], but the version with directed graphs is false [10], as well as the one with infinite chromatic numbers [7, 14]. We show that the inequality (H) can be strict for finite simple graphs.
A standard tool in the study of Hedetniemi’s conjecture is the concept of the exponential graph as introduced in [3]. Let be a positive integer, and let be a finite graph that we allow to contain loops; the graph has all mappings as vertices, and two distinct mappings are adjacent if, and only if, the condition holds whenever . The relevance of to the problem is easy to see because the graph has the proper -coloring . The idea of our approach lies in the fact that the proper -colorings of become quite well-behaved if the graph is fixed and gets large; let us proceed to technical details and exact statements. A basic result in [3] tells that the constant mappings form a -clique in , which means that these mappings get different colors in a proper -coloring. So a relabeling of colors can turn any proper -coloring into a suited one, in which a color is assigned to the constant mapping sending every vertex of to .
Observation 1**.**
If is a suited proper -coloring of , then .
Proof.
The mapping is adjacent to the constant mapping for any not in , so cannot get colored with such a . ∎
Claim 2**.**
Consider a graph with and a suited proper -coloring of . Then there is a vertex of such that color classes are -robust, which means that, for any , there is a satisfying , where stands for the closed neighborhood of in .
Proof.
For any color and any vertex , we define as the set of all that satisfy . According to Observation 1, every vertex of belongs to at least one of the classes .
Assume that is a large class, that is, it contains more than elements, and consider an arbitrary mapping . If every element of admitted a vertex with , then there would be at most ways to choose and , while the remaining vertices would contribute at most a factor of . This contradicts the cardinality assumption on , so we can actually find a under which is an only vertex taking the color and also . In other words, the equality cannot hold unless there is a vertex satisfying .
If there is a vertex for which is large for at least colors , then we are done. Conversely, we can define more than mappings for which the value of on a vertex does not equal those colors for which is large. None of these mappings belongs to a large class , but the non-large classes are too small to cover all of them. ∎
Now we are ready to proceed with counterexamples. For a simple graph , we define the graph by adding the loops to all the vertices, and the strong product as the graph with vertex set and edges between and when, and only when, or .
Claim 3**.**
Let be a finite simple graph with finite girth . Then, for sufficiently large , one has with .
Proof.
The restriction of a suited proper coloring to the mappings that are constant on the cliques is a proper coloring up to the identification of every such clique with . We find a vertex as in Claim 2 and define the clique in by setting, for all and ,
(1.1) for all satisfying ,
(1.2) for all satisfying ,
(1.3) for all satisfying .
Due to the assumption on the girth of , no pair of vertices defined in (1.1) and (1.2) can be adjacent in and monochromatic at the same time; the condition (1.3) uses different colors for different , and these colors are also different from those of the neighboring vertices dealt with in (1.1). Therefore, is indeed a clique and requires colors. Using the pigeonhole principle, one finds a such that , and due to Observation 1 we have . Further, it is only classes that are not -robust with respect to in the terminology of Claim 2, so we can find a -robust class . Finally, we note that the mapping defined as, for all ,
(2.1) for all in the closed neighborhood ,
(2.2) for all satisfying ,
is adjacent to in . Since is -robust, we cannot have by Lemma 2, but rather we have according to Observation 1. So we have , which is a contradiction. ∎
The classical paper [4] proves the existence of graphs with arbitrarily large girth and fractional chromatic number; so we can find a graph of girth at least that satisfies . We set and pass to sufficiently large ; we immediately get and also by Claim 3. The equality follows by standard theory [3] as the mapping is a proper -coloring of any graph of the form .
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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