The isomorphism problem for analytic discs with self-crossings on the boundary

TL;DR

This paper investigates the isomorphism problem for multiplier algebras associated with analytic discs with boundary self-crossings, establishing conditions under which these algebras are isomorphic and characterizing the maps involved.

Contribution

It extends previous results by analyzing the impact of boundary self-crossings on the isomorphism of multiplier algebras and characterizes the possible isomorphisms.

Findings

Algebraic isomorphism implies same self-crossings up to automorphism.

Isomorphisms are given by composition with specific maps between varieties.

Constructs a continuum of non-isomorphic multiplier algebras with identical crossing patterns.

Abstract

Suppose $V$ is the unit disc $\mathbb{D}$ embedded in the $d$-dimensional unit ball $\mathbb{B}_d$ and attached to the unit sphere. Consider the space $\mathcal{H}_V$, the restriction of the Drury-Arveson space to the variety $V$, and its multiplier algebra $\mathcal{M}_V = \operatorname{Mult}(\mathcal{H}_V)$. The isomorphism problem is the following: Is $V_1 \cong V_2$ equivalent to $\mathcal{M}_{V_1} \cong \mathcal{M}_{V_2}$? A theorem of Alpay, Putinar and Vinnikov states that for $V$ without self-crossings on the boundary $\mathcal{M}_V$ is the space of bounded analytic functions on $V$. We consider what happens when there are self-crossings on the boundary and prove that if $\mathcal{M}_{V_1} \cong \mathcal{M}_{V_2}$ algebraically, then $V_1$ and $V_2$ must have the same self-crossings up to a unit disc automorphism. We prove that an isomorphism between $\mathcal{M}_{V_1}$ and $\mathcal{M}_{V_2}$ can only be given by a composition with a map from $V_1$ to $V_2$. In the case of a single simple self-crossing we show that there are only two possible candidates for this map and find these candidates. Finally, we provide a continuum of $V$'s with the same self-crossing pattern such that their multiplier algebras are all mutually non-isomorphic.