Free energy equivalence between mean-field models and nonsparsely diluted mean-field models

TL;DR

This paper rigorously proves that the free energy of nonsparsely diluted mean-field models matches that of their corresponding mean-field models in the thermodynamic limit, extending previous results to a broader class of models.

Contribution

It generalizes the equivalence of free energies between diluted and mean-field models to nonsparsely diluted models with Bernoulli-distributed edges.

Findings

Free energy of nonsparsely diluted models equals that of mean-field models.

Results apply to ferromagnetic and spin-glass models with discrete spins.

Extends previous work on densely diluted Curie-Weiss models.

Abstract

We studied nonsparsely diluted mean-field models that differ from sparsely diluted mean-field models, such as the Viana--Bray model. When the existence probability of each edge follows a Bernoulli distribution, we rigorously prove that the free energy of nonsparsely diluted mean-field models with appropriate parameterization coincides exactly with that of the corresponding mean-field models in ferromagnetic and spin-glass models composed of any discrete spin $S$ in the thermodynamic limit. Our results is a broad generalization of the result of a previous study [Bovier and Gayrard, J. Stat. Phys. 72, 643 (1993)], where the densely diluted mean-field ferromagnetic Ising model (diluted Curie--Weiss model) with appropriate parameterization was analyzed rigorously, and it was proven that its free energy was exactly equivalent to that of the corresponding mean-field model (Curie--Weiss model).