A note on summability in Banach spaces

TL;DR

This paper investigates conditions under which series in Banach spaces are absolutely convergent, focusing on Asplund spaces and Dunford-Pettis operators, and provides a new proof related to vector measures.

Contribution

It establishes new criteria for absolute convergence of series in Banach spaces involving Dunford-Pettis operators and Asplund spaces, with applications to vector measures.

Findings

Series are absolutely convergent under specified conditions.

Provides a new proof that vector measures in Asplund spaces have finite variation.

Connects weakly unconditionally Cauchy series with absolute convergence in Banach spaces.

Abstract

Let $Z$ and $X$ be Banach spaces. Suppose that $X$ is Asplund. Let $\mathcal{M}$ be a bounded set of operators from $Z$ to $X$ with the following property: a bounded sequence $(z_n)_{n\in \mathbb{N}}$ in $Z$ is weakly null if, for each $M \in \mathcal{M}$, the sequence $(M(z_n))_{n\in \mathbb{N}}$ is weakly null. Let $(z_n)_{n\in \mathbb{N}}$ be a sequence in $Z$ such that: (a) for each $n\in \mathbb{N}$, the set $\{M(z_n):M\in \mathcal{M}\}$ is relatively norm compact; (b) for each sequence $(M_n)_{n\in \mathbb{N}}$ in $\mathcal{M}$, the series $\sum_{n=1}^\infty M_n(z_n)$ is weakly unconditionally Cauchy. We prove that if $T\in \mathcal{M}$ is Dunford-Pettis and $\inf_{n\in \mathbb{N}}\|T(z_n)\|\|z_n\|^{-1}>0$, then the series $\sum_{n=1}^\infty T(z_n)$ is absolutely convergent. As an application, we provide another proof of the fact that a countably additive vector measure taking values in an Asplund Banach space has finite variation whenever its integration operator is Dunford-Pettis.