Relations between integrated correlators in $\mathcal{N}=4$ Supersymmetric Yang--Mills Theory

TL;DR

This paper develops methods to evaluate integrated correlators in $ ext{SU}(N)$ $ ext{N}=4$ supersymmetric Yang--Mills theory for any $N$ and finite coupling, revealing new relations and lattice sum representations.

Contribution

The authors introduce techniques to compute the integrated correlator $ ext{H}_N$ to all orders in $1/N$, establishing its relation to $ ext{C}_N$ and expressing expansion coefficients as lattice sums.

Findings

Derived all-order $1/N$ expansion of $ ext{H}_N$

Found relations between $ ext{H}_N$ and $ ext{C}_N$ at all orders

Estimated correlators at finite $N$ and $ au$ with high accuracy

Abstract

Integrated correlation functions in $\mathcal{N}=4$ supersymmetric Yang--Mills theory with gauge group $SU(N)$ can be expressed in terms of the localised $S^4$ partition function, $Z_N$, deformed by a mass $m$. Two such cases are $\mathcal{C}_N=(\text{Im} \tau)^2 \partial_\tau\partial_{\bar\tau} \partial_m^2\log Z_N\vert_{m=0}$ and $\mathcal{H}_N=\partial_m^4\log Z_N\vert_{m=0}$, which are modular invariant functions of the complex coupling $\tau$. While $\mathcal{C}_N$ was recently written in terms of a two-dimensional lattice sum for any $N$ and $\tau$, $\mathcal{H}_N$ has only been evaluated up to order $1/N^3$ in a large-$N$ expansion in terms of modular invariant functions with no known lattice sum realisation. Here we develop methods for evaluating $\mathcal{H}_N$ to any desired order in $1/N$ and finite $\tau$. We use this new data to constrain higher loop corrections to the stress tensor correlator, and give evidence for several intriguing relations between $\mathcal{H}_N$ and $\mathcal{C}_N$ to all orders in $1/N$. We also give evidence that the coefficients of the $1/N$ expansion of $\mathcal{H}_N$ can be written as lattice sums to all orders. Lastly, these large $N$ and finite $\tau$ results are used to accurately estimate the integrated correlators at finite $N$ and finite $\tau$.