On the transfinite symmetric strong diameter two property
Stefano Ciaci

TL;DR
This paper explores transfinite extensions of the symmetric strong diameter two property in Banach spaces, analyzing their stability under various operations and characterizing spaces with these properties using cardinal functions.
Contribution
It introduces and studies transfinite analogues of the symmetric strong diameter two property, including stability results and characterizations for spaces of the form C_0(X).
Findings
Stability of transfinite properties under c_0, ℓ_∞ sums, and tensor products.
Characterization of C_0(X) spaces with these properties via cardinal functions.
Examples of Banach spaces that do or do not have these properties.
Abstract
We study transfinite analogues of the symmetric strong diameter two property. We investigate the stability of these properties under , sums and under projective tensor products. Moreover, we characterize Banach spaces of the form , where is a T locally compact space, which posses these transfinite properties via cardinal functions over . As an application, we are able to produce a variety of examples of Banach spaces which enjoy or fail these properties.
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Taxonomy
TopicsAdvanced Banach Space Theory · Advanced Topology and Set Theory · Advanced Operator Algebra Research
On the transfinite symmetric strong diameter two property
Institute of Mathematics and Statistics, University of Tartu, Narva mnt 18, 51009 Tartu, Estonia
[email protected] https://stefanociaci.science.blog/
Abstract.
We study transfinite analogues of the symmetric strong diameter two property. We investigate the stability of these properties under , sums and under projective tensor products. Moreover, we characterize Banach spaces of the form , where is a T4 locally compact space, which posses these transfinite properties via cardinal functions over . As an application, we are able to produce a variety of examples of Banach spaces which enjoy or fail these properties.
Key words and phrases:
Diameter two property, sum, Projective tensor product, Cardinal function
2020 Mathematics Subject Classification:
46B04, 46B20, 54A25
This work was supported by the Estonian Research Council grants (PSG487) and (PRG1501).
1. Introduction
Given an infinite-dimensional real Banach space , its topological dual, its unit ball and its unit sphere are denoted by , and , respectively.
Definition 1.1**.**
A Banach space has the symmetric strong diameter two property () if, and only if, for every and , there are such that , and for all .
The was introduced in [2], but the original definition contains the additional requirement that , which is redundant. Indeed, if we require that , since , then and, therefore, Definition 1.1 is equivalent to the original one.
Examples of Banach spaces enjoying the include Lindenstrauss spaces, uniform algebras, almost square Banach spaces, Banach spaces with an infinite dimensional centralizer, somewhat regular subspaces of spaces, where is an infinite locally compact Hausdorff space, and Müntz spaces (see [8]).
In [3] transfinite analogues of the were defined, but, before recalling these definitions, let us introduce some notation. Given , and , we say that -norms if, for every , there is such that . In addition, we say that norms if it -norms it for all .
Definition 1.2**.**
[3, Definition 5.3] Let be a Banach space and an infinite cardinal.
- (i)
has the if, for every set of cardinality and , there are , which -norms , and satisfying with .
- (ii)
has the if, for every set of cardinality , there are , which norms , and satisfying .
In the following, we aim to investigate these transfinite extensions of the and, in particular, to show differences in their behaviour when compared to the regular .
Now, let us also recall the transfinite extensions of almost squareness and the strong diameter two property.
Definition 1.3**.**
[3, Definition 2.1] Let be a Banach space and a cardinal.
- (i)
is if, for every set of cardinality and , there exists such that holds for all .
- (ii)
is if, for every set of cardinality , there exists such that holds for all .
Definition 1.4**.**
[5, Definitions 2.11 and 2.12] Let be a Banach space and an infinite cardinal.
- (i)
has the if, for every set of cardinality and , there are , which -norms , and satisfying for all .
- (ii)
has the if, for every set of cardinality , there are , which norms , and satisfying for all .
It is clear that every (, respectively) Banach space enjoys the (, respectively). Moreover, it was shown in [3, Proposition 5.4] that the (, respectively) implies the (, respectively). To sum up, the following implications hold true.
1.1. Content of the paper
In Section 2, we study the stability of the transfinite with respect to operations between Banach spaces.
We provide a complete description concerning and sums (see Theorems 2.1 and 2.2), which informally state that these sums of Banach spaces enjoy the if, and only if, we can always find one component which satisfies a property which arbitrarily well approximates the . Thanks to these characterizations, we show that, for example, the Banach spaces and enjoy the (see Example 2.4).
We also investigate the behaviour of the under projective tensor products. Namely, we prove that the Banach space has the , whenever and enjoy the property.
We conclude this section by studying the difference in behaviour of the transfinite compared to the finite . In particular, we prove that, for the transfinite case, it is not possible to replace the functionals with relatively weakly open sets in Definition 1.2, even though it is possible for the traditional (see Fact 2.6 (ii)). Moreover, we prove that an equivalent internal description of the (see Fact 2.6 (iii)) also fails in the transfinite case.
Section 3 is dedicated to extend the class of known examples which possess the transfinite . To this aim, we search for a description in the class of spaces, whenever is a T4 locally compact space. The main result of this section states that the Banach space fails the , where is the successor cardinal of the density character of , but it enjoys the , where is the cellularity of (see Theorem 3.1).
Thanks to this result, new examples are provided, e.g. and fail the , enjoys the and has the , whenever .
1.2. Notation
Given a sequence of Banach spaces we define
[TABLE]
endowed with the usual supremum norm. Moreover, we set
[TABLE]
Eventually, given a cardinal , we call its cofinality and its successor cardinal.
2. Stability results
In this section we investigate the behaviour of the transfinite with respect to operations between Banach spaces.
2.1. Direct sums
Given a sequence of Banach spaces , it is known that the sum is always [1, Example 3.1] and, therefore, has the . Moreover, it was proved in [3, Proposition 4.3] that the sum of a family of Banach spaces is and thus has the , whenever . For these reasons, in the following we will focus only on countable sums with respect to the , for .
Theorem 2.1**.**
Let be a sequence of Banach spaces and . If, for every , there is such that, for every set of cardinality , there exist and such that , -norms and , then enjoys the . If in addition , then the vice-versa also holds.
Proof.
Fix a set of cardinality and . Let be an enumeration of and find as in the statement for .
By assumption there are and such that , and hold for every .
For each and , find satisfying . Moreover, since , there exists such that
[TABLE]
Now call
[TABLE]
and .
Notice that
[TABLE]
which means that the set -norms .
On the other hand, and
[TABLE]
holds for all . Therefore, enjoys the .
For the vice-versa, fix and, for every , of cardinality . Call
[TABLE]
and notice that , because . Therefore, there exist a set , which -norms , and such that and .
Since , there exists satisfying . Moreover, from the fact that, in particular, -norms the set , we deduce that the set -norms .
Eventually, notice that, given ,
[TABLE]
which concludes the proof. ∎
Notice that the same proof can be adjusted to sums too. As a matter of fact, it is not needed to find as in the proof of Theorem 2.1 and one can define
[TABLE]
By doing so, the following theorem is easily proved, up to a few minor changes.
Theorem 2.2**.**
Let be a family of Banach spaces and . If, for every , there is such that, for every set of cardinality , there exist and such that , -norms and , then enjoys the . If in addition , then the vice-versa also holds.
Corollary 2.3**.**
Let and be Banach spaces and . Either or enjoy the if, and only if, enjoys the .
Proof.
Apply Theorem 2.2 with . ∎
Example 2.4**.**
Let . We claim that enjoys the , despite the fact that it is a sum of reflexive spaces. To this aim, fix and choose any satisfying .
Now fix a set of cardinality and let be an enumeration for . Moreover, find, for each , satisfying .
Since the support of the ’s is at most countable and , there exists an ordinal such that holds for all . Call and notice that
[TABLE]
holds for every . Notice that, up to a small perturbation argument, we showed that the Banach spaces ’s satisfy the hypothesis of Theorem 2.1, thus the claim is proved.
It is then clear that also the Banach space enjoys the thanks to Theorem 2.2.
Remark 2.5*.*
One might wonder whether Theorem 2.1 can be pushed further and used to obtain sums which possess the . Unfortunately this doesn’t happen, as a matter of fact, the space fails the because, if by absurd it had the property, then Theorem 2.11 would apply and this would lead to a contradiction when combined with Theorem 2.9.
2.2. Tensor product
It is known that the is preserved by taking projective tensor products [10, Theorem 2.2]. In the cited paper, the authors’ proof relies on the following characterization of the .
Fact 2.6**.**
[8, Theorem 2.1]** Let be a Banach space. The following assertions are equivalent:
- (i)
* has the .*
- (ii)
Given non-empty relatively weakly open sets in and , there exist such that , and for all .
- (iii)
Given , there exist nets and in such that and, with respect to the weak topology on , and hold for all .
As we will later demonstrate, Fact 2.6 doesn’t hold true for the whenever . Therefore, a different proof is required to extend [10, Theorem 2.2] to the transfinite setting.
Theorem 2.7**.**
Let and be Banach spaces and . If and have the , then the projective tensor product enjoys the .
Proof.
Fix a set of cardinality and . Recall that the Banach space is isometrically isomorphic to the space of bounded bilinear forms acting on [12, Theorem 2.9], hence, for every , there exists satisfying .
Given , define
[TABLE]
Since has the , there are and ’s in such that and, for all , and .
Now, given , call
[TABLE]
Since has the , there are and ’s in such that and, for all , and .
Define and . Notice that , moreover, the fact that is due to [10, Lemma 2.1]. Eventually, let us prove that the set -norms .
[TABLE]
which proves the claim and thus concludes the proof. ∎
Remark 2.8*.*
It is known that requiring only one component to have the is not enough in order to ensure the projective tensor product to enjoy the [11, Corollary 3.9]. Up to a few changes, the same ideas can be used to show that requiring in the statement of Theorem 2.7 only one component to enjoy the is not enough. Let us sketch the argument required to prove this statement.
We will later show that has the (see Example 3.3), nevertheless, we claim that the Banach space doesn’t enjoy the .
Since is not finitely representable in , so it is not finitely representable in either (notice that each finite dimensional subspace of is isometrically isomorphic to some finite dimensional subspace of , and vice-versa). Thanks to a simple transfinite analogue of [11, Lemma 3.7] (replacing finite dimensional spaces with spaces of density ) we conclude that is not -octahedral (see [4, Definition 5.3]), moreover, we can infer that [12, Theorem 5.3]. Therefore, by applying [5, Theorem 3.2], we conclude that fails the .
2.3. Some more remarks
Previously we claimed that the transfinite analogue of Fact 2.6 doesn’t hold true. Let us now prove this statement for the implication (i)(ii) by continuing the investigation began in Example 2.4. As a matter of fact, the Banach space enjoys the , nevertheless we claim that it fails condition (ii) from Fact 2.6 with respect to . This claim follows from the following theorem.
Theorem 2.9**.**
Let be a sequence of Banach spaces. If, given any sequence of relatively weakly open sets in and , there exist and in such that , and for all , then there exists such that is not uniformly convex.
Proof.
Let , where the ’s are any chosen elements satisfying the following conditions:
[TABLE]
Now consider the relatively weakly open sets
[TABLE]
Fix and find and such that and hold for all .
Since , we can find such that . On the other hand, since , we have that
[TABLE]
hence
[TABLE]
therefore
[TABLE]
Now, the fact that implies
[TABLE]
Finally, let us compute the modulus of convexity of .
[TABLE]
which implies that is not uniformly convex. ∎
Let us now turn our attention to the implication (i)(iii) from Fact 2.6. We claim that also this fails in the transfinite context.
Example 2.10**.**
We will prove that fails the (see Example 3.3). Nevertheless, condition (iii) from Fact 2.6 is satisfied in a very strong way. In fact, fix , an ordinal and call and . It is then clear that and that, with respect to the weak topology, and holds for every . In other words, since , we showed that satisfies condition (iii) from Fact 2.6 with respect to .
Despite Theorem 2.9 and Example 2.10, it is possible to recover some transfinite analogue of Fact 2.6, but only for the .
Proposition 2.11**.**
Let be a Banach space and . Consider the following statements:
- (i)
* has the .*
- (ii)
Given a family consisting of many relatively weakly open sets in , a relatively weakly open neighborhood of [math] in and , there are and satisfying and for all .
- (iii)
Given of cardinality , there are nets and in satisfying and, with respect to the weak topology, and for all .
Then (i)(ii)(iii).
Proof.
(i)(ii). Fix a family consisting of many relatively weakly open sets in , a relatively weakly open neighborhood of [math] in and . For every , thanks to Bourgain’s lemma [7, Lemma II.1], we can find functionals , and convex coefficients such that
[TABLE]
Moreover, we can find and satisfying
[TABLE]
Since has the and , there exist and in satisfying and for all and . Now, given , define
[TABLE]
and notice that . Moreover,
[TABLE]
In order to conclude, it only remains to prove that . But this is clear because, for every we have that
[TABLE]
which means that , hence .
(ii)(iii). Fix a set of cardinality and temporarily fix a weak neighborhood of [math]. Define and find and satisfying and for all .
Now semi-order the family of weakly open neighborhoods of [math] with respect to the inclusion and consider the nets and . It is clear that , and holds for all . Moreover, up to a perturbation argument, we can assume that all ’s belong to . Thus the claim is proved. ∎
Let us show that the implication (iii)(ii) from Proposition 2.11 fails. As already witnessed by Example 2.10, satisfies condition (iii) in a very strong way, nevertheless it fails the . Therefore, we only need to notice that condition (ii) with respect to clearly implies possessing the , thus the claim is proved.
It remains unclear whether the implication (ii)(i) hold.
3. spaces
In [2] it was proved that , for infinite Hausdorff locally compact, always has the . In this section we aim to extend the class of examples which enjoy the transfinite by trying to characterize under which conditions spaces have this property. Before doing so, let us introduce a bit of notation about some cardinal functions.
Let be a topological space. Define the density character of as
[TABLE]
A cellular family in is a family of mutually disjoint open sets in . Define the cellularity of as
[TABLE]
It is well known that . We refer the reader to [9] for a detailed treatment about these cardinal functions and more.
Before stating the main result of this section, let us recall that, thanks to the Riesz–Markov representation theorem, every continuous linear functional on admits a unique representation as a regular countably additive Borel measure on .
Theorem 3.1**.**
Let be a locally compact space.
- (i)
* fails the .*
- (ii)
If , then has the .
Proof.
. Let be dense in . Consider the set and suppose by contradiction that has the . Then we can find functions and satisfying
[TABLE]
Since is dense, then we can find such that , which contradicts the fact that .
. Fix and a set of cardinality . Find a cellular family in of size and, given any and , define
[TABLE]
Notice that
[TABLE]
Therefore, there is satisfying for every . Notice that, without loss of generality, we can assume that . In fact, if that’s not the case, then we can replace with some non-empty open set satisfying .
Find functions such that and, since ’s are regular, compact sets satisfying . Now construct Urysohn’s functions and in satisfying
[TABLE]
Define
[TABLE]
and notice that . Moreover, given any and ,
[TABLE]
∎
It remains unclear whether the statement of Theorem 3.1 can be written using only one cardinal function. Namely, we don’t know the answer to the following two questions.
Question 3.2**.**
Let be a locally compact space. Is it true that fails the ? Is it true that enjoys the , whenever ?
Example 3.3**.**
Let us now employ Theorem 3.1 to produce some new examples of spaces enjoying or failing the transfinite .
- (i)
Let be a separable locally compact Hausdorff space. It is clear that , hence fails the .
- (ii)
It is known that [9, 7.22], therefore enjoys the .
- (iii)
Let be a Boolean algebra and let be the Stone space associated to . It is clear that the set defines a cellular family in .
Now let us consider a regular positive Borel measure over some T4 locally compact space . Call the set of measurable sets modulo the negligible sets in . It is known that is isometrically isomorphic to (see e.g. pages 27–29 in [6]), therefore we conclude that enjoys the , whenever .
In particular, whenever and is the counting measure over , , thus it follows that enjoys the , but it fails the , because .
To conclude this section, let us provide a criterion to identify cellular families in particular classes of topological spaces, including Alexandrov-discrete spaces.
Proposition 3.4**.**
Let be a space and an infinite cardinal. If there are many points in such that every non-empty intersection of at most many neighborhoods is still a neighborhood, then .
Proof.
Let be a set of cardinality such that every non-empty intersection of at most many neighborhoods of is still a neighborhood for every . For every distinct find a closed neighborhood of which doesn’t contain . By assumption
[TABLE]
is an open neighborhood of . Notice that, given distinct we have that
[TABLE]
In other words, defines a cellular family of size . ∎
Notice that the assumption in Proposition 3.4 is far from being necessary. As a matter of fact, it is consistent with ZFC that contains no P-points, that is, points for which every containing them is a neighborhood, nevertheless, as already recalled in Example 3.3, has a cellular family of cardinality .
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