Diophantine $D(n)$-quadruples in $\mathbb{Z}[\sqrt{4k + 2}]$

TL;DR

This paper proves the existence of infinitely many Diophantine quadruples in quadratic integer rings for specific forms of n, expanding understanding of such sets in algebraic number theory.

Contribution

It establishes the existence of infinitely many D(n)-quadruples in quadratic rings for certain n forms under specified conditions, with explicit examples for d=10.

Findings

Existence of infinitely many D(n)-quadruples for n=4m+4k√d with certain m,k

Existence of infinitely many D(n)-quadruples for n=(4m+2)+4k√d under conditions

Examples supporting quadruples with property D(n) for d=10

Abstract

Let $d$ be a square-free integer and $\mathbb{Z}[\sqrt{d}]$ a quadratic ring of integers. For a given $n\in\mathbb{Z}[\sqrt{d}]$, a set of $m$ non-zero distinct elements in $\mathbb{Z}[\sqrt{d}]$ is called a Diophantine $D(n)$-$m$-tuple (or simply $D(n)$-$m$-tuple) in $\mathbb{Z}[\sqrt{d}]$ if product of any two of them plus $n$ is a square in $\mathbb{Z}[\sqrt{d}]$. Assume that $d \equiv 2 \pmod 4$ is a positive integer such that $x^2 - dy^2 = -1$ and $x^2 - dy^2 = 6$ are solvable in integers. In this paper, we prove the existence of infinitely many $D(n)$-quadruples in $\mathbb{Z}[\sqrt{d}]$ for $n = 4m + 4k\sqrt{d}$ with $m, k \in \mathbb{Z}$ satisfying $m \not\equiv 5 \pmod{6}$ and $k \not\equiv 3 \pmod{6}$. Moreover, we prove the same for $n = (4m + 2) + 4k\sqrt{d}$ when either $m \not\equiv 9 \pmod{12}$ and $k \not\equiv 3 \pmod{6}$, or $m \not\equiv 0 \pmod{12}$ and $k \not\equiv 0 \pmod{6}$. At the end, some examples supporting the existence of quadruples in $\mathbb{Z}[\sqrt{d}]$ with the property $D(n)$ for the above exceptional $n$'s are provided for $d = 10$.