Approximation Algorithms for Interdiction Problem with Packing Constraints

TL;DR

This paper develops approximation algorithms for a bilevel interdiction problem with packing constraints, providing the first PTAS for certain cases and establishing hardness results, advancing understanding of strategic resource allocation.

Contribution

It introduces an $(s_B+ ext{epsilon})$-approximation algorithm for the general problem with constant dimensions, and a PTAS for the bilevel knapsack case, also proving hardness bounds.

Findings

Provides an $(s_B+ ext{epsilon})$-approximation algorithm for constant dimensions.

First O(1)-approximation (PTAS) for bilevel knapsack problem when $s_B=1$.

Shows no $(4/3- ext{epsilon})$-approximation exists for certain parameters.

Abstract

We study a bilevel optimization problem which is a zero-sum Stackelberg game. In this problem, there are two players, a leader and a follower, who pick items from a common set. Both the leader and the follower have their own (multi-dimensional) budgets, respectively. Each item is associated with a profit, which is the same to the leader and the follower, and will consume the leader's (follower's) budget if it is selected by the leader (follower). The leader and the follower will select items in a sequential way: First, the leader selects items within the leader's budget. Then the follower selects items from the remaining items within the follower's budget. The goal of the leader is to minimize the maximum profit that the follower can obtain. Let $s_A$ and $s_B$ be the dimension of the leader's and follower's budget, respectively. A special case of our problem is the bilevel knapsack problem studied by Caprara et al. [SIAM Journal on Optimization, 2014], where $s_A=s_B=1$. We consider the general problem and obtain an $(s_B+\epsilon)$-approximation algorithm when $s_A$ and $s_B$ are both constant. In particular, if $s_B=1$, our algorithm implies a PTAS for the bilevel knapsack problem, which is the first O(1)-approximation algorithm. We also complement our result by showing that there does not exist any $(4/3-\epsilon)$-approximation algorithm even if $s_A=1$ and $s_B=2$. We also consider a variant of our problem with resource augmentation when $s_A$ and $s_B$ are both part of the input. We obtain an O(1)-approximation algorithm with O(1)-resource augmentation, that is, we give an algorithm that returns a solution which exceeds the given leader's budget by O(1) times, and the objective value achieved by the solution is O(1) times the optimal objective value that respects the leader's budget.