Synchronizing Boolean networks asynchronously

TL;DR

This paper investigates the existence and minimal length of synchronizing words in a specific class of Boolean networks called and-or-nets, providing bounds under certain graph conditions and complexity results for decision problems.

Contribution

It establishes bounds on synchronizing word lengths for and-or-nets on strongly connected graphs without positive cycles and analyzes the computational complexity of related decision problems.

Findings

If the graph is strongly connected with no positive cycles, then either all and-or-nets have short synchronizing words or the graph is a cycle with none.

A bound of at most 10(√5+1)^n on the length of synchronizing words is provided, which is smaller than the general ernb1y bound.

Deciding whether all and-or-nets on a given graph have a synchronizing word is coNP-hard.

Abstract

The {\em asynchronous automaton} associated with a Boolean network $f:\{0,1\}^n\to\{0,1\}^n$, considered in many applications, is the finite deterministic automaton where the set of states is $\{0,1\}^n$, the alphabet is $[n]$, and the action of letter $i$ on a state $x$ consists in either switching the $i$th component if $f_i(x)\neq x_i$ or doing nothing otherwise. These actions are extended to words in the natural way. A word is then {\em synchronizing} if the result of its action is the same for every state. In this paper, we ask for the existence of synchronizing words, and their minimal length, for a basic class of Boolean networks called and-or-nets: given an arc-signed digraph $G$ on $[n]$, we say that $f$ is an {\em and-or-net} on $G$ if, for every $i\in [n]$, there is $a$ such that, for all state $x$, $f_i(x)=a$ if and only if $x_j=a$ ($x_j\neq a$) for every positive (negative) arc from $j$ to $i$; so if $a=1$ ($a=0$) then $f_i$ is a conjunction (disjunction) of positive or negative literals. Our main result is that if $G$ is strongly connected and has no positive cycles, then either every and-or-net on $G$ has a synchronizing word of length at most $10(\sqrt{5}+1)^n$, much smaller than the bound $(2^n-1)^2$ given by the well known \v{C}ern\'y's conjecture, or $G$ is a cycle and no and-or-net on $G$ has a synchronizing word. This contrasts with the following complexity result: it is coNP-hard to decide if every and-or-net on $G$ has a synchronizing word, even if $G$ is strongly connected or has no positive cycles.