Prime and semiprime submodules of $R^n$ and a related Nullstellensatz for $M_n(R)$

TL;DR

This paper characterizes semiprime submodules of $R^n$ and establishes a Nullstellensatz-like result for matrix rings over polynomial rings, linking algebraic properties to geometric conditions.

Contribution

It introduces the concept of semiprime submodules in $R^n$ and proves they are intersections of prime submodules, extending to a Nullstellensatz for matrix rings over polynomial rings.

Findings

Semiprime submodules are intersections of prime submodules.

Every semiprime left ideal of $M_n(R)$ is an intersection of prime left ideals.

A Nullstellensatz for $M_n(R)$ relates membership in semiprime ideals to geometric conditions.

Abstract

Let $R$ be a commutative ring with $1$ and $n$ a natural number. We say that a submodule $N$ of $R^n$ is semiprime if for every $f=(f_1,\ldots,f_n) \in R^n$ such that $f_i f \in N$ for $i=1,\ldots,n$ we have $f \in N$. Our main result is that every semiprime submodule of $R^n$ is equal to the intersection of all prime submodules containing it. It follows that every semiprime left ideal of $M_n(R)$ is equal to the intersection of all prime left ideals that contain it. For $R=k[x_1,\ldots,x_d]$ where $k$ is an algebraically closed field we can rephrase this result as a Nullstellensatz for $M_n(R)$: For every $G_1,\ldots,G_m,F \in M_n(R)$, $F$ belongs to the smallest semiprime left ideal of $M_n(R)$ that contains $G_1,\ldots,G_m$ iff for every $a \in k^d$ and $v \in k^n$ such that $G_1(a)v=\ldots=G_m(a)v=0$ we have $F(a)v=0$.