Positive solutions of inhomogeneous Kirchhoff type equations with indefinite data
Aolin Chen, Qiuyi Dai

TL;DR
This paper investigates conditions for the existence of positive solutions to inhomogeneous Kirchhoff type equations with indefinite data, providing necessary and sufficient criteria.
Contribution
It offers new necessary and sufficient conditions for positive solutions in Kirchhoff equations with indefinite data.
Findings
Established criteria for existence of positive solutions
Identified conditions under which solutions exist
Contributed to the theory of Kirchhoff equations with indefinite data
Abstract
Inhomogeneous Kirchhoff type equations with indefinite data are considered. Some necessary and sufficient conditions for the existence of positive solutions of the problem under consideration are presented.
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Taxonomy
TopicsNonlinear Partial Differential Equations · Advanced Mathematical Modeling in Engineering · Stability and Controllability of Differential Equations
Positve solutions of inhomogeneous Kirchhoff type
equations with indefinite data
00footnotetext: E-mail addresses: [email protected], [email protected].
This work is supported by NNSFC (Grant:No.11671128).
Aolin Chen, Qiuyi Dai
- LCSM, College of Mathematics and Statistics, Hunan Normal University,*
Changsha Hunan 410081,P. R. China
Abstract
Let be a bounded domain in with smooth boundary . Denote by the subset of such that for any the following problem
[TABLE]
has a solution. Assume that and . We consider Dirichlet problem of inhomogeneous Kirchhoff type equation
[TABLE]
where with for , and for .
Main results we proved in the present paper can be summarized as
(i) If , then, for any and , problem (0.2) has at least one solution.
(ii) If and for some positive number given by (1.5) in Section 1, then problem (0.2) is solvable if and only if . Moreover, the solution is unique for small enough.
(iii) If and , then problem (0.2) has at least two solutions for small enough and has no solution for large enough.
(iv) If , then problem (0.2) has at least one solution for small enough if and only if , and has no solution for large enough.
Compared to the semilinear case (that is the case ), the appearance of the nonlocal term in Kirchhoff type equations changes tremendously the profile of the solution set in the case . For more detailed explanation, see Remark 1.4 in Section 1.
Key words: Inhomogeneous Kirchhoff type equations, positive solution, Ekeland’s variational principle
1. Introduction
Let be a bounded domain in with smooth boundary , and . For any , we use to denote the standard Lebesgue’s space endowed with norm . In this paper, we consider the following Dirichlet problem of inhomogeneous Kirchhoff type equation
[TABLE]
where , , and with for , and for .
Since the differential equation in problem (1.1) contains an integral over , it is no longer a pointwise identity. Therefore, it is often called nonlocal problem. Nonlocal boundary value problems like problem (1.1) model several physical and biological systems where describes a process which depend on the average of itself, such as the population density. We refer the reader to [42, 2, 3, 13, 14] for some related works. Concerning problem (1.1) itself, the prototype of it is the Kirchhoff wave equation which was proposed by Kirchhoff in [29] as an extension of the classical D’Alembert’s wave equation, by considering the effect of the changing in the length of the string during the vibration. For more mathematical and physical background of Kirchhoff equations, we refer to [4, 10, 20, 28] and the references cited there in.
In the case , problem (1.1) is reduced to the following well studied semilinear problem
[TABLE]
To our best knowledge, the study of problem (1.2) was initiated by [8] in which A. Bahri and H. Berestycki tried to find infinitely many nontrivial solutions by perturbation method. Since then, problem (1.2) has attracted many attentions, see for example [9, 40, 36] etc. What we emphases here are positive solutions of problem (1.2). In this respect, many authors have made their contributions under the assumption that , see for example [31, 21, 22]. The condition has been improved in [16, 19, 18] by Q. Y. Dai, Y. G. Gu, J. F. Yang and L. H. Peng. To recall the results of [16, 19, 18], We denote by the subset of such that for any the following problem
[TABLE]
has a solution. Obviously, includes sign-changing function. With the notation , main results of [16, 19, 18] can be summarized as Theorem I* Assume that . Then the following statements hold.*
(i)* If and , then there exists a positive number such that problem (1.2) has at least two positive solutions for any , and has no positive solution for .*
(ii)* If and is starshaped, then there exists a positive number such that problem (1.2) has at least one positive solution for any if and only if , and has no positive solution for . *
It is worth pointing out here that sub-supersolution method plays an important role in the study of semilinear problem.
Back to the Kirchhoff type equations (that is the case ), it attracts more and more attentions in the recent years. See for example [6, 32, 12, 11, 33, 34, 26, 39, 35, 44, 47, 10, 15, 20, 45, 17, 37, 28, 43, 30, 46]. Most literatures available so far are concerning with ground state solutions for homogenous Kirchhoff equations. However, it is worth mentioning that N. Azzouz and A. Bensedik [31] have studied in [7] the following inhomogenous problem
[TABLE]
where .
By making use of sub-supersolution method, they proved that if satisfies the following conditions:
is a continuous and for any , for some ,
is a nonincreasing function,
The function is increasing,
then, for any , there are positive numbers such that problem (1.4) has at least one nonnegative solution for , and has no nonnegative solution for
Using the notation of N. Azzouz and A. Bensedik, we have in our problem (1.1). This obviously beyond the consideration of [7]. Moreover, since is increasing and unbounded in our problem, the comparison principle may cease to validate (see [27]), and sub-supersolution method is no longer available for Kirchhoff type equation itself. Therefore, some new ideas are needed for finding positive solutions of problem (1.1) when the data changes sign and is supercritical. Next, we are going to state our main results of the present paper. To this end, we fix some notations first.
Let be the standard Sobolev space and be the Sobolev constant defined by
[TABLE]
Set and . For , we introduce a positive constant by the following formula:
[TABLE]
Bearing above notations in mind, we can express our main results of this paper in the following theorems. Theorem 1.1* If and , then problem (1.1) has at least one positive solution for any .* Theorem 1.2* If and , then problem (1.1) has positive solution for any if and only if . Moreover, the solution is unique for small enough if in addition .* Theorem 1.3* If and , then there are two positive constants such that problem (1.1) has at least two positive solutions for , and has no nonnegative solution for .* Remark 1.4* From Theorem I (i), Theorem 1.1 and Theorem 1.2, we see that the appearance of the nonlocal term in Kirchhoff type equation changes the profile of solution set in two aspects when . One is that the positive solvability of semilinear problem needs a finite restriction on the parameter ,whereas Kirchhoff type equation is always positively solvable for any positive parameter ; the other one is that semilinear problem has always two positive solutions for small parameter , whereas Kirchhoff type equation has only one positive solution for small parameter and large when .* Theorem 1.5* If and is starshaped, then there are two positive constants such that problem (1.1) has positive solution for any if and only if , and has no positive solution for .* Remark 1.6* If not specially declared, all solutions of this paper are in classical sense.* The rest of the paper is organized as follows. The case is discussed in Section 2. The discussion of the case is placed in Section 3. The last Section 4 devotes to discuss the case .
2. The case
Keeping notations , , and of the previous section in use, we study the case in this section. The main results we will prove are following Theorems. Theorem 2.1* If and , then problem (1.1) has at least one positive solution for any .* Theorem 2.2* If , and , then problem (1.1) has positive solution for any if and only if . Moreover, the solution is unique for small enough if in addition .*
To prove Theorem 2.1, we need a result about the solvability of the following problem
[TABLE]
where . Which can be stated as
Lemma 2.3* Problem (2.1) is solvable if and only if .*
Proof: On one hand, if is a solution of problem (2.1), then it is easy to check that is a solution of the following problem
[TABLE]
Hence, .
On the other hand, if , then problem (2.2) has a solution . Based on the observation of the above paragraph, we can find a solution of problem (2.1) with the form . It is easy to check that is indeed a solution of problem (2.1) provided that is a positive solution of the following algebraic equation
[TABLE]
Noting that is strictly increasing in , and
[TABLE]
we see that the equation has a unique solution in . Therefore, problem (2.1) is solvable for . This completes the proof of Lemma 2.3.
Proof of Theorem 2.1: To prove Theorem 2.1, we denote by the standard Sobolev space with norm , and consider the following functional defined on .
[TABLE]
We claim that is bounded from below on and
[TABLE]
In fact, by Hölder’s and Young’s inequality, we get
[TABLE]
with being the first eigenvalue of Dirichlet Laplacian. By Sobolev’s inequality, we have
[TABLE]
for some positive constant independent of . Therefore,
[TABLE]
which implies that due to .
By evaluating the minimum of function on , we get
[TABLE]
Combining (2.4) and (2.5) together, we have
[TABLE]
This implies that is bounded from below on .
Setting
[TABLE]
we can claim that
[TABLE]
In fact, the first inequality in (2.8) follows from (2.6) and (2.7). To prove the second inequality in (2.8), we denote by the nontrivial solution of problem (2.1). The existence of follows from Lemma 2.3 since . Moreover, verifies
[TABLE]
Therefore, we have
[TABLE]
This and the definition of imply
[TABLE]
By Ekeland’s variational principle (see [38]), we know that there exists a sequence such that
[TABLE]
Since is finite and , we conclude that is bounded in . Therefore, up to a subsequence, we may assume that
[TABLE]
for some function .
Consequently, we have
[TABLE]
Since
[TABLE]
it follows from (2.11) and the fact that
[TABLE]
This implies . Therefore, strongly in .
For any , we have
[TABLE]
By sending to in the above equation, we get
[TABLE]
Therefore, is a weak solution of the following problem
[TABLE]
Furthermore, we can prove is positive in by strong comparison principle of Laplace operator. In fact, by the assumption , we know from Lemma 2.3 that there exists a function which satisfies.
[TABLE]
By (2.12) and (2.13), we can easily see
[TABLE]
Therefore, by comparison principle for weak solutions, we have
[TABLE]
This and (2.12) imply that is a nonnegative weak solution of problem (1.1). Moreover, by regularity theory of elliptic equations, we know further that is a nonnegative classical solution of (1.1). Finally, by strong comparison principle of Laplace operator, we have
[TABLE]
Therefore, is a positive solution of problem (1.1), and the proof of Theorem 2.1 is completed.
To prove Theorem 2.2, we need the following result which was proven in [17].
Lemma 2.4*([17]) If and , then the following problem has no solution.*
[TABLE]
The following lemma is crucial for proving Theorem 2.2. Lemma 2.5* If , and is a positive solution of problem (1.1) corresponding to parameter , then we have*
[TABLE]
Proof: We adopt a contradiction argument. Suppose that the conclusion of Lemma 2.5 is not true, then there would exist a sequence , and such that
[TABLE]
and
Since , we get easily from (2.16) that
[TABLE]
for some positive constant independent of . Furthermore, by a bootstrap argument and Schauder’s estimates of elliptic equations, we have
[TABLE]
for some constant independent of and . Therefore, up to a subsequence, converges in to a nonnegative function which satisfies
[TABLE]
Since , we can deduce from the strong maximum principle that for any . Therefore, is a solution of problem (2.15). This contradicts Lemma 2.4.
Lemma 2.6* If , and , then problem (1.1) has at most one positive solution for parameter small enough.* Proof: Let and be two arbitrary positive solutions of problem (1.1). That is, and satisfy
[TABLE]
What we should do is that in for small enough parameter . To this end, we set , and . By (2.18) and mean value theorem, we know that there exists a function such that verifies
[TABLE]
Multiplying the above equality by and integrating on , we get
[TABLE]
By mean value theorem and triangle inequality, we have
[TABLE]
Where .
Since , by Poincare inequality we have
[TABLE]
Where and is the first eigenvalue of the Dirichlet Laplacian.
From (2.19), (2.20) and (2.21), we get
[TABLE]
Since and , by Lemma 2.5 we know that
[TABLE]
Combining (2.22) and (2.23) together imply that there exists a positive number such that for any . Therefore, in for any because on . This completes the proof of Lemma 2.6.
Proof of Theorem 2.2: In the sequel, we always assume that and . If , then Theorem 2.1 guarantees the existence of positive solution for problem (1.1). If in addition , then Lemma 2.6 implies that the uniqueness claim in Theorem 2.2 is true. Therefore, to complete the proof of Theorem 2.2, we just need to prove that the necessary condition for positive solvability of problem (1.1) for is . To make this end, we assume that problem (1.1) has positive solution for any . Let be positive solution of problem (1.1) with respect to parameter . By Lemma 2.5, we have
[TABLE]
Let , then satisfies
[TABLE]
Multiplying the differential equation in problem (2.24) by and integrating the result equation over , we get
[TABLE]
that is,
[TABLE]
Denote by the first eigenvalue of Dirichlet Laplacian. By Hölder’s, Poincare’s and Young’s inequality, we have
[TABLE]
Since , there is a positive constant such that
[TABLE]
From this and Poincare’s inequality, we have
[TABLE]
Combining (2.26), (2.27) and (2.29) together, we get
[TABLE]
The above inequality and a bootstrap argument show that there exists a positive constant independent of such that
[TABLE]
Furthermore, by standard elliptic regularity theory, we can find a positive constant independent of such that
[TABLE]
Therefore, up to a subsequence, we may assume that
[TABLE]
Sending to [math] in problem (2.24), we see that verifies
[TABLE]
Therefore, . This completes the proof of Theorem 2.2.
3. The case
This section devotes to deal with the case . The main purpose is to prove the following result. Theorem 3.1* If and , then there are two positive constants such that problem (1.1) has at least two positive solutions for , and has no positive solution for .* Remark 3.2* Instead of multiplicity results, if we focus only on the existence result, then the condition may be made a small relaxation (see Lemma 3.3 of this section).*
To prove Theorem 3.1, we denote by the standard Sobolev space, and consider functional
[TABLE]
defined on . It is obvious that any critical point of is a weak solution of problem
[TABLE]
Let denote inner neighborhood of . Setting
[TABLE]
Obviously, . In fact, any nontrivial function with property in and belongs to , but not belongs to . Instead of condition , we will find a positive solution of problem (1.1) in the following lemma under the condition . Lemma 3.3* If and , then there exists a positive number such that problem (1.1) has a positive solution for any with property that and converges, as , to a solution of the following problem*
[TABLE]
Proof: We prove this lemma by the following steps.
Step1: There are positive numbers , , and elements independent of such that
[TABLE]
for any . Where .
In fact, if we denote by the first eigenvalue of the eigenvalue problem
[TABLE]
then we have
[TABLE]
Therefore,
[TABLE]
By the assumption and Sobolev’s inequality, we have
[TABLE]
with independent of .
Combining (3.7) and (3.8) together, we get
[TABLE]
Hence
[TABLE]
Noting , we can choose positive number independent of so small that
[TABLE]
Taking
[TABLE]
we get
[TABLE]
Since , we may take . To choose a suitable , we denote by the first eigenfunction corresponding to . By the definition of , we have
[TABLE]
for any . Noting , we have
[TABLE]
Therefore, we can choose a large constant independent of such that and
[TABLE]
Taking , we have for any . In summary, for the above choices of , , , and , we have
[TABLE]
for any . This concludes Step1.
Step2: For any , problem (3.2) has a solution with property .
To conclude Step 2, for any , we set
[TABLE]
and
[TABLE]
where is a fixed constant given in Step1.
By Step1 and mountain pass theorem without condition, we know that there is a sequence such that
[TABLE]
Because of , it is easy to verify that satisfies condition. Therefore, up to a subsequence, converges strongly in to a function which satisfies
[TABLE]
and
[TABLE]
This makes Step2.
Step3: There exists a positive number such that, for any , the solution obtained in Step 2 for problem (3.2) is positive. Therefore, is a positive solution to problem (1.1) and for any .
We divide the proof of Step3 into two cases. One is , and the other is .
If , then by Lemma 2.3, we know that problem (2.1) has a nonnegative solution for any . Since is a solution of (3.2) for , we have
[TABLE]
for any . Therefore, by strong comparison principle of Laplace operator, we have
[TABLE]
for any .
If , we first claim that there exists a positive constant independent of such that
[TABLE]
where is the critical value defined in Step2, and is the constant given in Step1.
In fact, for any , is continuous in . Since , by intermediate value theorem, we have for some . Hence, for any , we can conclude from Step1 that
[TABLE]
Therefore, for any , there holds
[TABLE]
To derive a upper bound of , we take . Obviously, . By the definition of , we have
[TABLE]
For and , we can get from the definition of that
[TABLE]
Setting
[TABLE]
we see that is independent of , and
[TABLE]
Therefore, claim (3.14) is valid
Taking into account, we can conclude from (3.12) and (3.14) that there exists a positive constant independent of such that
[TABLE]
By bootstrap argument and standard regularity theory of elliptic equations, we can conclude from the above estimate that
[TABLE]
for , some positive constant independent of , and .
Next, we show that is positive in . Since , there exists a neighborhood of such that for . Set . At first, we can claim that there exists a positive constant such that
[TABLE]
Otherwise, there would exist a sequence as , and a sequence such that
[TABLE]
By (3.15), up to a subsequence, we may assume that converges in to function which satisfies
[TABLE]
Noticing that
[TABLE]
we have . Therefore, by strong maximum principle, we have
[TABLE]
In particular,
[TABLE]
Because is closed and bounded, we may assume that . Consequently, by (3.16), we have
[TABLE]
This contradicts (3.18).
On the second, we can easily see that in for . In fact, for any , satisfies
[TABLE]
Therefore, for any , we have
[TABLE]
due to for any .
Noting on , by strong maximum principle, we have in for any . In conclusion, we have in for any . This completes the proof of the conclusion stated in Step3.
Finally, combining the statements of Step1, Step2 and Step3 together, we reach Lemma 3.3. Lemma 3.4* If and , then there exists a positive number such that, for any , problem (1.1) has at least one positive solution with property .* Proof: Let , and be positive numbers determined in Lemma 3.3. Set , and define
[TABLE]
we can claim that . In fact, by the assumption , we know that problem (2.1) has a solution which satisfies
[TABLE]
From this we can infer that
[TABLE]
Therefore, if we choose , then
[TABLE]
This implies that for any . Noting , we have
[TABLE]
By the definition of , we have
[TABLE]
Let . For any fixed , if is a minimizing sequence of , then we can claim that
[TABLE]
for some positive constant . Otherwise, up to a subsequence, we may assume
[TABLE]
Since , and
[TABLE]
we have
[TABLE]
This is a contradiction.
By Ekeland’s variational principle, we can find a sequence such that
[TABLE]
Since , a similar argument to that used in the proof of Theorem 2.1 implies that, up to a subsequence, converges in to a function . Moreover, by a similar argument used in the proof of Lemma 3.3, we can prove that is a positive solution of problem (1.1). This completes the proof of Lemma 3.4.
To prove the nonexistence part of Theorem 3.1, we need the following result about semilinear problem Lemma 3.5*([16, 19]) If , or and is star-shaped, then, for any , there exists a positive number such that the semilinear problem*
[TABLE]
has at least one solution for , and has no solution for . Moreover, there exist a positive constant independent of such that for any solution of problem (3.21) with respect to parameter , there holds
[TABLE]
The nonexistence part of Theorem 3.1 is a special case of the following lemma. Lemma 3.6* If , or and is star-shaped, then, for any , there exists a positive number such that problem (1.1) has no positive solution for any .* Proof: If problem (1.1) has a nonnegative solution with respect to parameter , then we can see that is a solution of
[TABLE]
Therefore, by Lemma 3.5, we should have
[TABLE]
with being the fixed number given in Lemma 3.5.
Furthermore, by the definition of and Lemma 3.5, we see that the following inequality hold for absolute positive constant given in Lemma 3.5.
[TABLE]
Noting , we can conclude from the above inequality that
[TABLE]
for some positive constant independent of .
Substituting (3.24) into (3.23), we get
[TABLE]
This implies that problem (1.1) has no positive solution for . Therefore, the proof of Lemma 3.6 is completed. Proof of Theorem 3.1: If and , then it follows easily from Lemma 3.3 and Lemma 3.4 that there exists a positive number such that problem (1.1) has at least two positive solutions and with property and for any . The nonexistence part of Theorem 3.1 follows directly from Lemma 3.6. Therefore, we complete the proof of Theorem 3.1.
4. The case
In this section, we investigate the case , and aim to proving the following theorem Theorem 4.1* If and is starshaped, then for any there are two positive number and such that problem (1.1) has at least one positive solution for any if and only if , and has no positive solution for .* Since , we can not use variational method to get positive solution for problem (1.1). At the same time, comparison principle may cease to validate for Kirchhoff type equations (see [27]), we are also lack of sub-supersolution method for Kirchhoff type equation itself. Hence, some new ideas are needed for finding positive solutions of problem (1.1) in this supercritical case. Here, we propose an iterative method based on the comparison principle of Laplace operator. The iterative sequence is no more monotone, but is still bounded. This is presented in the following lemma. Lemma 4.2* If , then there exists a positive number such that problem (1.1) has at least one positive solution for any .* Proof: Since , we can easily see that, for any , the following problem has a solution .
[TABLE]
Let be the solution of the following problem
[TABLE]
Choosing so small that
[TABLE]
and setting , we can easily check that
[TABLE]
for any .
Taking (4.1) and (4.3) into account, we infer from the strong comparison principle for Laplace operator that
[TABLE]
Let . To obtain a solution of problem (1.1) for any , we construct an approximation sequence in the following way.
Initially, we set . Then, we get from by solving the following problem
[TABLE]
By induction method, we can see that
[TABLE]
Indeed, from (4.4) , we firstly have
[TABLE]
If we inductively assume
[TABLE]
then what we should do is to proving
[TABLE]
Obviously, (4.8) can be deduced from (4.7) and the comparison principle of Laplace operator. In fact, on one hand, (4.1), (4.5) and (4.7) imply that
[TABLE]
Therefore, it follows from the comparison principle of Laplace operator that
[TABLE]
On the other hand, (4.3), (4.5) and (4.7) imply
[TABLE]
Hence, by the comparison principle of Laplace operator, we have
[TABLE]
Combining (4.10) and (4.12) together, we get (4.8). This concludes (4.6) by induction method.
With (4.6) established, we can deduce from (4.5) and (4.3) that
[TABLE]
From this and Schaulder’s estimate, we have
[TABLE]
for some positive constant and independent of . Therefore, up to a subsequence, we may conclude that converges in to a function which is obviously a nonnegative solution of problem (1.1). The positivity of follows from the strong comparison principle of Laplace operator. This completes the proof of Lemma 4.2.
The necessarity part of Theorem 4.1 includes in the following lemma
Lemma 4.3* Assume that , and is starshaped. If there exists a positive number such that problem (1.1) has positive solution for any , then .* To prove Lemma 4.3, we need the following well known Pohozaev identity. **Lemma 4.4 **([25]) Let be a smooth bounded domain and suppose that is a continuous map and that satisfies
[TABLE]
If denotes the unit outward normal to at , then satisfies
[TABLE]
where , and is the gradient of with respect to the variable . Proof of Lemma 4.3: No loss of generality, we may assume that is star-shaped with respect to the origin . That is for any . Let be positive solution of problem (1.1) with respect to parameter . Setting
[TABLE]
we see that satisfies
[TABLE]
Applying Lemma 4.4 to problem (4.15), we have
[TABLE]
with . it worth mentioning here that due to .
Since is star-shaped with respect to , we have
[TABLE]
Therefore
[TABLE]
By (4.15), we have
[TABLE]
Combining (4.16) and (4.17) together, we get
[TABLE]
This implies that
[TABLE]
for some positive constant independent of .
Therefore, up to a subsequence, we have
[TABLE]
That is
[TABLE]
for any .
By (4.17)) and (4.18), we have
[TABLE]
for some positive constant independent of . Consequently, for any , we have
[TABLE]
By (4.15), for any , we have
[TABLE]
Sendding to [math] in (4.22), and taking (4.19) and (4.21) account, we get
[TABLE]
This and the regularity theory of elliptic equations imply that is a solution of problem (1.3). Moreover, due to . Therefore, . This completes the proof of Lemma 4.3.
Proof of Theorem 4.1 Combining Lemma 3.6, Lemma 4.2 and Lemma 4.3 together, we reach the conclusion of Theorem 4.1.
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