On the stability of laminar flows between plates
Yaniv Almog, Bernard Helffer

TL;DR
This paper proves the linear stability of certain laminar flows between plates at high Reynolds numbers, under specific conditions on the flow profile and boundary conditions, extending understanding of flow stability in fluid dynamics.
Contribution
It establishes linear stability results for laminar flows between plates in the high Reynolds number limit, covering nearly Couette flows and flows with non-zero second derivatives, under various boundary conditions.
Findings
Flow is linearly stable for nearly Couette flows at high Reynolds numbers.
Flow is linearly stable when the second derivative of the velocity profile is non-zero.
Stability holds under no-slip or fixed traction boundary conditions.
Abstract
Consider a two-dimensional laminar flow between two plates, so that , given by , where satisfies in . We prove that the flow is linearly stable in the large Reynolds number limit, in two different cases: (nearly Couette flows), in . We assume either no-slip or fixed traction force conditions on the plates, and an arbitrary large (but much smaller than the Reynolds number) period in the direction.
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On the stability of laminar flows between plates
Y. Almog∗, Department of Mathematics,
Ort Braude College,
Carmiel 2161002, Israel
and
B. Helffer, Laboratoire de Mathématiques Jean Leray,
CNRS and Université de Nantes,
2 rue de la Houssinière, 44322 Nantes Cedex France
Abstract
Consider a two-dimensional laminar flow between two plates, so that , given by , where satisfies in . We prove that the flow is linearly stable in the large Reynolds number limit, in two different cases:
- •
(nearly Couette flows),
- •
in .
We assume either no-slip or fixed traction force conditions on the plates, and an arbitrary large (but much smaller than the Reynolds number) period in the direction.
Contents
1 Introduction
Consider the incompressible Navier-Stokes equations in the two-dimensional pipe
[TABLE]
where and .
We require periodicity in the direction, i.e., for all we have
[TABLE]
for some , which may be arbitrary large, but must satisfy as . An initial condition on at must be placed as well. The vector denotes the fluid velocity field which belongs, for all , to
[TABLE]
where the divergence is taken in the spatial coordinates.
Here for some means that for any , it holds that . Similarly, means that for any , . Recall that
[TABLE]
The pressure belongs, for all , to
[TABLE]
The trace of on the boundary is constant on each connected component of :
[TABLE]
The parameter denotes the inverse of the flow’s Reynolds number . Beyond the above no-slip boundary condition we shall also consider a prescribed constant traction force on the boundary (or Navier-slip conditions [15]), i.e.,
[TABLE]
where denote the prescribed traction force on .
We consider the stability of a stationary pair where the flow is of the form, for ,
[TABLE]
For such flows, (1.1) is satisfied for if and only if there exists some constant and such that, for ,
[TABLE]
Depending on the boundary condition (no-slip or fixed traction force), should satisfy an inhomogeneous Dirichlet condition or an inhomogeneous Neumann condition .
We shall not confine ourselves, however, in the sequel to such unperturbed velocity fields and discuss a more general class of motions (cf. also [17, p. 154]), which can be obtained if we add a non-uniform body force to the right-hand-side of (1.1). Such a generalization can be useful if one attempts to examine the stability of a flow in an arbitrary 2D cross-section but uniform in the longitudinal direction. The linearized operator associated with (1.1), at the flow , assumes the form
[TABLE]
where
[TABLE]
where given by
[TABLE]
and belongs to either
[TABLE]
or to
[TABLE]
where
[TABLE]
Remark 1.1**.**
- •
Note that when no-slip boundary conditions, introduced in (1.1), are applied, then . Otherwise, if we select (1.3) instead, then .
- •
Note that that for any there exists and such that with satisfying the periodicity condition .
We now attempt to define a spectral problem for . We seek an estimate for the solution for some and in a suitable space of the equation
[TABLE]
To this end we need to define the function space in which the solution should reside, and then to formulate an effective spectral problem involving only , so that is recovered in a final step directly from .
The local stability of the flow (1.4) has been addressed mostly by physicists and and engineers [17, 33, 50, 43]. The Poiseuille flow (), which falls outside the scope of this work, and the Couette flow (), , have received some special attention. Thus, for Couette flows it has been established, using a mix of numerical and analytical techniques that Couette flow is always stable [47, 42], and established numerically [40] that Poiseuille flow looses its stability for . In [44] a survey of results published in Russian is presented where the locus of part of the spectrum (but not its left margin) for Couette and Poiseuille flows is approximated in the limit .
In the recent years a number of rigorous mathematical works addressing the spectral problem associated with (1.7) have been published. In particular, in [15], both resolvent and semigroup estimates have been obtained for the case of Couette flow (). We shall relate the results in [15] to the present work in more detail in the sequel. More recently in [11] it has been established that the semigroup can be represented as a sum of the one generated by an unbounded Couette flow and an exponentially fast decaying boundary term. For symmetric flows in a channel (including the Poiseuille flow) it has been proved in [22] that the laminar flow looses stability for sufficiently small and sufficiently large . The stability analysis of a Prandtl boundary layer, leading to a similar problem in , was studied in [19, 23, 24]. In three dimensions, the stability of radially symmetric Poiseuille flow for sufficiently small has been proved in [16]. It is also worthwhile mentioning [30, 48] addressing Kolmogorov flows.
The case , or the inviscid case, has been studied much more extensively in the Mathematics literature. Some of the recent works include [49, 32, 31] which study both the resolvent and the semigroup associated with the linearized operator. Naturally, resolvent estimates in the inviscid case are crucial while attempting to obtain resolvent estimates for (see also [22, 23, 24]), but since the results in the above references are specifically designed to obtain stability results for the Euler equation we derive our own resolvent estimates in Section 4.
It should be emphasized that experimental observations (cf. [14]) conclude that Couette and Poiseuille flows loose their stability for Reynolds numbers that are much lower than . It is commonly believed that these instabilities arise due to finite, though small, initial conditions. Thus, it has been established in [9, 10] that unbounded Couette flows (in instead of as is presently considered), assuming a period , are finitely stable for sufficiently initial data. Similar results are obtained in [8] in a three dimentional settings.
To obtain non-linear stability one needs in [9, 10, 8] to use semigroup estimates (and not only the locus of the eigenvalues as in [44]), associated with time dependent equation
[TABLE]
in or .
Unlike the unbounded Couette flow in [9, 10, 8], the semigroup associated with more general laminar flows in is not explicitly known. In the present contribution we thus consider, in the limit , velocity fields satisfying in , of two different types:
- •
nearly Couette flows, so that
[TABLE]
- •
velocity fields for which in .
We prove that these laminar flows are stable and provide estimates for their associated semigroup norm. We believe that these linear estimates would be useful when considering the nonlinear stability of these flows in a bounded interval.
The rest of this contribution is arranged as follows.
In the next section we formulate the spectral problem by using Hodge decomposition. Since the standard Hodge decomposition [20] is not a direct sum in this periodic setup, we define a space of zero-flux perturbations, and then formulate our main results in this space.
In Section 3 we present the problem in terms of the stream function and its Fourier coefficients and arrive at the Orr-Sommerfeld operator.
In Section 4 we consider the inviscid problem (where ) in Fourier space.
Section 5 includes some resolvent estimates obtained for one-dimensional Schrödinger operators on the entire real line and for their Dirichlet realization in .
In Section 6 we consider the same Schrödinger operator on and but this time in a Sobolev space of functions satisfying certain orthogonality conditions (cf. [44]).
Section 7 provides inverse estimates for the Orr-Sommerfeld operator for the fixed-traction problem, whereas Section 8 provides the same estimates for the no-slip realization.
In Section 9 we prove the main results.
Finally in the appendix we bring some auxiliary estimates obtained for Airy functions and generalized Airy functions.
2 Spectral problem formulation and main results
We now amend the spectral question presented in (1.7) to a more standard spectral problem. To this end we use a variant of Hodge decomposition adapted to our periodic setting (see [20, Theorem 3.4] for the standard case), which allows us to eliminate . Though expert readers are probably familiar with these ideas, we find it useful to recall them for the general reader’s convenience.
2.1 Hodge theory
Let
[TABLE]
where the scalar product for the Hilbert space is given by
[TABLE]
and the two closed subspaces of
[TABLE]
and
[TABLE]
We have
Lemma 2.1**.**
[TABLE]
Proof.
Let , and denote its partial Fourier transform with respect to , i.e.,
[TABLE]
It can be easily verified that, for any ,
[TABLE]
From the above we can conclude that for , and
With the above in mind, we introduce
[TABLE]
The orthogonality condition reads
[TABLE]
We can now prove the following Hodge decomposition:
Lemma 2.2**.**
* and are orthogonal subspaces of and*
[TABLE]
Proof.
Let . Let further and denote the weak solutions of
[TABLE]
and
[TABLE]
In the above
[TABLE]
It can be easily verified, by using the Lax-Milgram Lemma, that there exists a unique solution for (2.6). Similarly, by using (see Remark 1.1) the ansatz
[TABLE]
there where , it follows that there exists a unique, solution of (2.5). (Note that the Neumann condition in the second line of (2.5) is satisfied in sense.) Equivalently, we can say that is the unique periodic solution, orthogonal to the constant function, of
[TABLE]
for every -periodic
Clearly, , , , and, by the periodicity of and , it holds that
[TABLE]
Finally we set to obtain that and hence, by Lemma 2.1, .
2.2 Zero flux solution
Since for , we need to introduce the following spaces, as the domain of the operator in the spectral formulation
[TABLE]
Remark 2.3**.**
We note that the orthogonality requirement (2.4) is in accordance with the requirement which should be applied if the periodicity requirement is dropped. Formally, therefore, should serve as a good approximation for the space
[TABLE]
*in the limit .
We later explain in Remark 2.8 how one can more generally determine all the solutions of (1.7) in from its solution in .*
Let then denote the orthogonal projection on . We may express explicitly for some by
[TABLE]
where is the solution of (2.6).
Rewriting (1.7) in the form
[TABLE]
we observe that . Then, projecting on , we may write, for
[TABLE]
With the above in mind, we now define as an unbounded operator on whose domain is (which is clearly dense in )
[TABLE]
By this definition we have
[TABLE]
which appears to be a proper formulation of the resolvent equation.
Proposition 2.4**.**
* is semi-bounded on and has compact resolvent. Furthermore,*
[TABLE]
Proof.
Let . As we have
[TABLE]
verifying, thereby, semi-boundedness. More precisely, the resolvent set of contains . The semigroup estimate (2.13) is then a consequence of the Hille-Yosida theorem. The compactness of the resolvent is proved by observing that is compactly embedded in .
Remark 2.5**.**
- •
Suppose that for some and , we have
[TABLE]
Then, by the compactness of the resolvent the spectrum is discrete, and hence it holds that
[TABLE]
- •
It results from (2.14) that there exists , such that for any , , and , it holds that
[TABLE]
where denotes the norm. In the sequel we use the same notation, depending on context, also for the norm.
If is in the resolvent set of , we recover by
[TABLE]
Once we have derived we can obtain in the following manner
Proposition 2.6**.**
Let satisfy (2.16). Then, there exists a unique such that (1.7) holds for .
Proof.
From (2.12) it follows that
[TABLE]
It remains to prove the existence of a unique satisfying
[TABLE]
This, however, easily follows from the proof of Lemma 2.2, i.e., one obtain as the unique solution of (2.5) with in the place of .
Corollary 2.7**.**
If is in the resolvent set of , then for any there exists a unique pair such that (1.7) holds.
We use the term “the zero flux solution of (1.7)” for this solution.
Remark 2.8**.**
- •
From the proof of Proposition 2.6 we learn, in addition, that if and is a corresponding eigenfunction in then there exists such that satisfies (1.7) with . We cannot exclude, at the moment, the possibility that is not a simple eigenvalue.
- •
The proof shows also that, for any , the map (as defined in the corollary) is continuous from onto .
- •
Once the zero flux solution of (1.7) has been found in , we can also solve the problem more generally in . More precisely, if , then for any and any , there exists a unique pair satisfying (1.7) and
[TABLE]
Let denote the solution of (1.7) in . The proof is obtained by adding to an appropriate function of only. We omit the rather standad details in the interest of brevity.
2.3 Longitudinal average
We begin by defining the projection by
[TABLE]
and then extend it to by writing
[TABLE]
We first show
Lemma 2.9**.**
* is a projection on . Moreover for any , we have .*
Proof.
Let . Then where is a solution of (2.6). We may then write, using the periodicity of ,
[TABLE]
Obviously, , and the orthogonality of to in follows from
[TABLE]
Hence . It can now be easily verified that .
Lemma 2.10**.**
The projector commutes with .
Proof.
Let . Then, by the proof of Lemma 2.2
[TABLE]
where is a solution of (2.6) and is a solution of (2.5).
Clearly,
[TABLE]
where is given by (2.7) (with instead of ).
Hence
[TABLE]
and by uniqueness of the Hodge decomposition we obtain
[TABLE]
Next, we compute . Observing (see (2.10)) that
[TABLE]
we get
[TABLE]
We can now prove the following commutation result
Lemma 2.11**.**
For any , commutes with .
Proof.
We simply observe that for all
[TABLE]
and use the commutation of and .
An immediate consequence follows
Proposition 2.12**.**
For any it holds that
[TABLE]
2.4 The semigroup
Since our main results are stated for we bring, for the convenience of the reader, the following, rather straightforward, estimate for .
Proposition 2.13**.**
Let . Then,
[TABLE]
Proof.
Let , s.t , where , and satisfy
[TABLE]
Since , we can conclude, as in (2.21) that
[TABLE]
Hence, using (1.6) and (2.23), we conclude that
[TABLE]
Thus, since ,there exists, by (2.8), a function such that
[TABLE]
in .
Taking the inner product with in then yields, for any , in view of (2.4)
[TABLE]
In the case we use Poincaré inequality to obtain
[TABLE]
where is the first eigenvalue of the Dirichlet problem in , or,
[TABLE]
In the case we have , and hence we can write
[TABLE]
relying on the fact that is orthogonal, by (2.4), to the first eigenfunction of the Neumann problem in . Note that
[TABLE]
From the above, together with (2.26), we conclude (2.25).
2.5 Main results
Throughout this work we assume that:
Assumption 2.14**.**
* does not vanish in , or*
[TABLE]
The statement of the main results below involves the spectral properties of the complex Airy operator on
[TABLE]
We also need below
[TABLE]
where .
Finally we define, for any and ,
[TABLE]
and then set for convenience of notation
[TABLE]
For , and , we recall that
[TABLE]
is defined in (2.9b) and (2.11) (where appears in the definition of and is the periodicity).
For , we introduce
[TABLE]
Theorem 2.15**.**
The following statements hold for any .
Let satisfy
[TABLE]
Then, for any , there exist , and such that for all and we have
[TABLE]
where is given by (2.19). 2. 2.
For all , there exist , and such that, for any satisfying , and it holds that
[TABLE]
For the case , we first define, for some , the operator whose differential operator is given by (2.30a) and its domain by
[TABLE]
We show later (see Proposition 6.4 and Corollary 6.7) that is a closed operator and that
[TABLE]
is finite and positive. For , and , we recall that
[TABLE]
is defined in (2.9a) and (2.11).
Theorem 2.16**.**
For all , the following properties hold.
Let satisfy (2.34). Then, for any , there exist , and such that for all and we have
[TABLE] 2. 2.
For all , there exist , and such that, for any satisfying and it holds that
[TABLE]
Note that together with Proposition 2.13, Theorems 2.15 and 2.16 provide stability of the semigroup for any .
Remark 2.17**.**
Note that for Couette flow, where and , one obtains that (2.39) is true for any , and that (2.36) is true for all . This provides better estimate for the exponential rate of decay than in [15, Proposition 6.1] which proves semigroup decay only for sufficiently small .
3 The Orr-Sommerfeld operator
We focus attention in the sequel on and its resolvent.
3.1 Stream Function
When considering a two-dimensional incompressible fluid flow, it is customary to introduce a stream function, i.e., to let . Its introduction is again related to Hodge decomposition theory.
Lemma 3.1**.**
Let . Then, there exists a unique such that and . If in addition, , then and satisfies on if and on if .
Proof.
Existence and uniqueness of follow from the proof of Lemma 2.2. In particular, for any we have where is a solution of (2.6). The second part of the lemma is immediate.
We next substitute into (1.6) and take the curl of the ensuing equation, which leads to the following equation, in the distributional sense,
[TABLE]
with ,
[TABLE]
We treat as an unbounded operator on , where
[TABLE]
is equipped with the norm. Note that additional regularity is needed while attempting to use results obtained on for spectral problem for . We shall obtain the necessary regularity at a later stage. Similarly, we introduce for and
[TABLE]
and assign to it the norm. In the interest of brevity we write in the sequel . For no-slip boundary conditions we take
[TABLE]
For fixed traction, the domain of is given by
[TABLE]
We can now make the following statement
Lemma 3.2**.**
The operator is invertible for each and .
Proof.
Let and satisfy for some and . Let denote the unique vector field in satisfying . As
[TABLE]
it follows that
[TABLE]
Due to the periodicity of our function spaces and the fact that the coefficients of the differential operator and the associated boundary conditions do not depend on , it is natural to consider the operator in a Fourier space. Hence, we introduce satisfying
[TABLE]
for ().
We then obtain the Hilbertian sum
[TABLE]
The unbounded operator on , which is commonly referred to as the Orr-Sommerfeld operator is given by
[TABLE]
in which
[TABLE]
[TABLE]
and, for ,
[TABLE]
in which
[TABLE]
In the sequel, unless stated otherwise, we consider and as independent parameters.
We now define two different realizations associated with the differential operator appearing in (3.4). The domain of , corresponding to the prescribed traction force boundary condition, is given by
[TABLE]
whereas the operator , corresponding to the no-slip condition, is defined on
[TABLE]
The domain of is similarly defined by (3.9) for and (3.10) for .
3.2 Inverse estimates
The Orr-Sommerfeld operator given by (3.4) has extensively been studied in the Physics literature [17, 50, 43]. Very few rigorous studies, however, address its spectrum (cf. [42] in the Couette case ) and none, to the best of our knowledge provide estimates for it inverse norm in . Assuming that , the inverse of is bounded. To estimate its norm, one needs a proper uniform bound of for all . Hence we write,
[TABLE]
where, for , ,
[TABLE]
Clearly, for any and ,
[TABLE]
with
[TABLE]
Consequently, for any and , we have, the following inequality
[TABLE]
Note that and hence, it is sufficient to consider in the above. We emphasize that the supremum with respect to , and of is obtained while ignoring the dependence of on . Note also that tends to as . Hence we shall attempt to obtain a bound on for large values of , since we are interested in the small limit.
Throughout this work we recall that we always assume Assumption 2.14. Without any loss of generality we can assume that
[TABLE]
Indeed, the case can similarly be treated after applying the transformation .
In view of (3.11), we attempt to obtain, in the large limit, a bound on . To this end, we introduce
[TABLE]
We define , for or when and , on
[TABLE]
In the case and we set
[TABLE]
where .
Note that and hence we consider it only in the case .
One can formally obtain from by dividing it by and taking the limit which corresponds to the limit . This is why it has been commonly referred to as the “inviscid operator” in [17].
We note that the formal limit of the Orr-Sommerfeld operator as is very different from that of the Schrödinger operator (). In the latter case, we expect the resolvent to be small away from the set were . This fact was used in [3, 4], for instance, to obtain resolvent estimates via localization techniques. For , the best one can expect is that would be small outside a close neighborhood of the set where . We note that raises considerable interest independently of the viscous operator (cf. [17, Sections 21-24] and [37]).
4 The inviscid operator
We consider here the inviscid operator (often called the Rayleigh operator ) associated with the differential operator (3.13), whose domain of definition is given either by (3.14) where or , or by (3.15) in the case for . The spectrum and the inverse of have been studied in the context of both inviscid (Euler) and viscous flows and their stability [17, 37, 22, 23, 49, 31, 32]. In particular, the inverse norm has been estimated in [22] for symmetric shear flows in a channel in the limit . Similar estimates are obtained in [23] for boundary-layer type flows in a semi-infinite domain. In [49, 31, 32] weighted norm estimates are obtained for . These norms are hard to implement when seeking inverse estimates for the Orr-Sommerfeld operator (3.4). The purpose of this section is therefore to offer a systematic study of using standard Sobolev norms, with emphasis on the limit for .
4.1 The case : preliminaries
We begin by showing that is a closed operator on . In the cases where is given by (3.14) the proof is standard and will therefore be omitted.
Proposition 4.1**.**
Let satisfy Assumption 2.14 and . Then , whose domain is given by (3.15), is closed as an unbounded operator on and the space
[TABLE]
is dense in under the graph norm.
Proof.
Let denote a sequence in such that
[TABLE]
To prove the proposition we need to show that and that .
Let . We use Hardy’s inequality for weighted Sobolev spaces associated with the intervals and separately.
Set then, for
[TABLE]
Recall the one-dimensional Hardy inequality (see for example [34, Eq. 0.6] or [12, Lemma 2.1]) which holds for any ,
[TABLE]
Note that (4.2) follows by extension from Hardy’s inequality in , given for any s.t. , we have
[TABLE]
Hence, for any (and hence for the restriction to of any )
[TABLE]
From (4.1) and (4.4) we deduce that is a Cauchy sequence in and in . Hence there are two corresponding limits and , with and . By continuity we have , and . This shows that . Finally it is clear that in and hence .
The density argument is a consequence, after localization, of Proposition 2.1 in [13].
The cases are easier, since one can apply Hardy’s inequality only once, in .
Consider the case of Couette flow in , which is one of the most popular examples of uniaxial flows ([47, 42, 7]. In this case
[TABLE]
We can construct in some cases the explicit solution of the inhomogeneous problem
[TABLE]
For example, when , and . It can be easily verified that
[TABLE]
It can be easily verified that satisfies (4.5).
While it seems at a first glance that is injective for all , it is wrong for . It has indeed a non-trivial solution of the form
[TABLE]
While for all , it does satisfy (4.8) in the sense of distributions.
We now look at the injectivity of when . We have already explicitly obtained a non trivial element in . More generally, we prove
Lemma 4.2**.**
For all , , it holds that
[TABLE]
Proof.
We observe that if is in the kernel, we have and
[TABLE]
where is the jump undergoes through . Since belongs to , we may use the Lax-Milgram Lemma for the Dirichlet problem to obtain a unique solution for
[TABLE]
It follows that .
Using [13, Proposition 3.1] and the same argument as in the proof of [13, Theorem 3.1] one can show that , which is a bounded operator from the Hilbert space into , is a Fredholm operator of index for . With the aid of Lemma 4.2, we can then conclude the surjectivity of for any or more precisely the existence of a right inverse. We note that surjectivity of follows from the surjectivity we prove in the sequel.
Remark 4.3**.**
When , we can prove (4.7) in the following alternative manner. Recall the solution of we have obtained in (4.6). If , we can solve (4.5) by dividing it by . When we write to obtain
[TABLE]
which can be easily solved as . It is not clear, however, how to extend by density the above solution to any .
In the next subsection, we obtain the surjectivity of (for any satisfying (3.12)) via a non-explicit compactness argument.
4.2 Construction of a right inverse of
We begin by establishing the surjectivity of
Lemma 4.4**.**
Suppose that (3.12) holds, and that for some . Then, for any and there exists some satisfying . Furthermore, there exists , such that for all , and , satisfies
[TABLE]
where denotes the norm of in the Sobolev space .
Proof.
Let . With (3.13) in mind, we can use the following alternative form of , which is valid wherever ,
[TABLE]
We look first for some satisfying the regularized equation
[TABLE]
We may set to obtain
[TABLE]
Taking the inner product with then yields
[TABLE]
This immediately implies, by the Lax-Milgram Lemma, that (and hence also ) uniquely exists in .
Since , there exists such that . Let be defined by (2.29). Clearly, we have
[TABLE]
Hence
[TABLE]
Upon translation we apply Hardy’s inequality (4.3), and the fact that (permitting the extension in so that ), it holds that
[TABLE]
A similar bound can be established on . Hence, by (4.11),
[TABLE]
Substituting once again into (4.11) yields, in addition,
[TABLE]
We note that (4.12) and (4.13) do not imply convergence of in to where is a solution of (3.13) (with ). As a matter of fact it is expected that, in most cases, will be unbounded in . We thus use (4.13) and (4.12) to obtain that
[TABLE]
It follows, either by Poincaré’s inequality or by (4.12), that is bounded in a ball of size in . By weak compactness, there exists a sequence tending to [math] such that converges weakly in to a limit as in the same ball, and hence
[TABLE]
It remains to establish that is a weak solution of (3.13) for . We thus write (4.10) in its weak form for some
[TABLE]
Letting and then taking the limit yields by the above established weak convergence in that
[TABLE]
Consequently, is a weak solution of (3.13) satisfying (3.12). Finally, since for all we have
[TABLE]
we easily obtain from (4.15) that
[TABLE]
The lemma is proved.
Remark 4.5**.**
As in the case of a Couette flow, one can show that the index of as a Fredholm operator from the Hilbert space (equipped with the graph norm) into is one for . Since the multiplication by is a compact operator from into we may conclude from Fredholm theory that
[TABLE]
and have the same index. Then, we observe that the multiplication operator by has index [math], and hence and again have the same index. Consequently, the index of equals to one, and by Lemma 4.4 it holds that . We note that one can construct a direct proof of injectivity with much greater difficulty.
We have proved above, the surjectivity of . By Fredholm theory, there is a natural right inverse which associates with the solution of which is orthogonal to in for the scalar product
[TABLE]
Note that coincides with the ordinary product whenever .
Employing the estimates of Lemma 4.4 we now prove:
Proposition 4.6**.**
Suppose that (3.12) holds, and that for some . Then, there exists , such that for all ,
[TABLE]
Proof.
We first observe that the solution constructed in Lemma 4.4 satisfies
[TABLE]
To obtain we now need to subtract , where is the orthogonal projector from onto . Obviously,
[TABLE]
establishing, thereby, a bound on the right inverse in . To estimate in we observe that by (4.4) there exists such that for any , , and
[TABLE]
4.3 Nearly Couette velocity fields
We now attempt to estimate in the case where . We shall begin with the case where , defined in (2.31), is small. To this end we introduce
[TABLE]
The following result proves that under suitable assumptions on , the infimum of over , where is positive.
Lemma 4.7**.**
For any , there exists and such that for any satisfying , we have
[TABLE]
Proof.
Writing in the form
[TABLE]
we attempt to estimate the second term on the right hand side. For some to be chosen later, we consider two different cases depending on the size of .
**Case I:.
**Integration by parts yields, accounting for the Dirichlet condition satisfies at ,
[TABLE]
We estimate the right-hand-side as follows
[TABLE]
Sobolev’s embedding and Poincaré’s inequality then yield that for some ,
[TABLE]
Case II:.
As we conclude that there exists such that
[TABLE]
Poincaré’s inequality was applied to obtain the last estimate. We can now set in (4.22) and in (4.22), to obtain
[TABLE]
The lemma is proved by using Poincaré’s inequality once again.
Remark 4.8**.**
Let . Suppose that there exist and satisfying or, in other words, that there exists an embedded eigenvalue . Taking the scalar product of with , we now observe that
[TABLE]
On the other hand, since depends continuously on , we obtain a contradiction, for a sequence in tending to , between (4.23) and (4.19) for sufficiently small . Hence does not possess any eigenvalue in [49, Section 3].
Without the assumption that is small we may still show
Lemma 4.9**.**
For any , there exists such that for any we have
[TABLE]
Proof.
Indeed, we obtain by (4.20), Poincaré’s inequality and Sobolev’s embeddings, that for any and any there exists such that, for any and ,
[TABLE]
For , semiboundedness of follows immediately from (4.22).
We now obtain an estimate for which is neither singular as (unlike (4.50)), nor does it necessitate any assumption on the injectivity of . Instead, we simply assume (4.19). We also observe that for any where is defined in (2.29).
Proposition 4.10**.**
For any and , there exists a constant such that for any satisfying (4.19) we have:
For all ,
[TABLE] 2. 2.
For all ,
[TABLE] 3. 3.
For all ,
[TABLE]
Proof.
Proof of (4.24).
Let and for some with . We begin by observing that
[TABLE]
and note that by (4.19), which is assumed to hold here,
[TABLE]
The left hand side of (4.28) can be estimated as follows
[TABLE]
To obtain (4.29), we consider two different cases.
We first apply the following computation, valid whenever , and ,
[TABLE]
In the case we may write
[TABLE]
and proceed as before. The case is similar. Hence (4.29) is proved in both cases.
Sobolev’s embedding and Poincaré’s inequality then yield
[TABLE]
Together with (4.28), it implies for ,
[TABLE]
and hence also (4.24).
Proof of (4.25).
Let . Then we have
[TABLE]
If we integrate by parts to obtain
[TABLE]
Use of Hölder’s inequality and Sobolev embedding lead, for every , to the conclusion that there exists such that
[TABLE]
where we have used the fact that the -norm ( being the Hölder conjugate) of can be uniformly bounded for
[TABLE]
Combining the above with (4.33), and making use of Sobolev embedding once again yield
[TABLE]
By (4.28) we obtain that
[TABLE]
from which (4.25) easily follows for , and then for by the inequality .
Proof of (4.26).
We first observe that
[TABLE]
where .
If , we estimate the right-hand-side as follows
[TABLE]
If , we write
[TABLE]
and proceed as before. The case is similar. Thus, without any restriction on , we get
[TABLE]
Substituting the above into (4.36) then yields
[TABLE]
Combining the above with (4.28), we obtain
[TABLE]
from which (4.26) easily follows
We shall need in Section 8 the following immediate consequence of Proposition 4.10.
Corollary 4.11**.**
For any there exists such that for all , satisfying (4.19), and it holds that
[TABLE]
Proof.
Let and . By (4.28) we have that
[TABLE]
As we may write
[TABLE]
Combining the above with (4.42) yields (4.41) with the aid of Poincaré’s inequality.
In the next lemma we address the optimality of (4.26).
Lemma 4.12**.**
Let satisfy (3.12). Then, (4.26) is optimal, i.e., there exists a sequence and such that , , and
[TABLE]
Proof.
We prove (4.43) for . Consider then for some with and . Let satisfy
[TABLE]
We may rewrite this equation in the form
[TABLE]
Integrating once yields
[TABLE]
Integrating again leads to
[TABLE]
The Dirichlet boundary condition at is then satisfied through the requirement that satisfies
[TABLE]
Making use of Fubini’s Theorem, we finally obtain
[TABLE]
We now write
[TABLE]
It can be verified (as in the proof of (4.30)) that for some positive, independent of , constants and ,
[TABLE]
Consequently, as we have
[TABLE]
We seek a sequence with and a decreasing sequence tending to [math] for which (4.43) holds. Let then
[TABLE]
For sufficiently large we have that . We then define by
[TABLE]
Clearly , and .
By (4.46) we then have as tends to ,
[TABLE]
We now write, for ,
[TABLE]
As
[TABLE]
where , we obtain, for ,
[TABLE]
Consequently,
[TABLE]
Substituting the above into (4.44a) and (4.44b) yields, for all ,
[TABLE]
where
Clearly, for all ,
[TABLE]
the convergence being uniform in .
We now prove (4.43) by establishing that
[TABLE]
which will immediately imply and consequently (4.43).
To this end we need to prove that
[TABLE]
We now use (4.45) together with the fact that to obtain that
[TABLE]
Since and , for some , we can conclude (4.49) from the above.
4.4 Non-vanishing
We dedicate this subsection to the case when and which may result from a combination of non-vanishing pressure gradient and relative velocity between the plates at . Note that in this case there are no eigenvalues of embedded in (see [49, Section 3]). We begin by establishing the following, rather straightforward, result.
Proposition 4.13**.**
Suppose that on , then, for any for which and , is invertible. Moreover, for any there exists , such that, for any with , , and satisfying (2.34), it holds that
[TABLE]
Proof.
For a pair such that , with , we write,
[TABLE]
Consequently, since (hence has constant sign) we obtain
[TABLE]
Let be chosen at a later stage and consider the following two cases.
In the case , we immediately deduce from (4.52) that there exists such that
[TABLE]
In the case , as
[TABLE]
we can use (4.52) once again to obtain that, for , there exists such that
[TABLE]
Since we can use Poincaré’s inequality to obtain for sufficiently large that there exists such that, for any (and ),
[TABLE]
which, combined with (4.53) yields (4.50).
Once injectivity of is established, we may apply Fredholm theory to prove its surjectivity. By the compactness of the multiplication with from into , we can conclude, as in Remark 4.5, that the index of is the same as the index of (U+i\lambda)\Big{(}-\frac{d^{2}}{dx^{2}}+\alpha^{2}\Big{)}\,. Since for , on , it follows that the indices of and from onto are the same. Consequently, the index of is [math] and surjectivity follows from injectivity.
It should be noted that (4.9) is unsatisfactory. Clearly, it is significantly inferior to (4.24)-(4.26), where a bound of for is obtained. We seek, therefore, a better estimate for that will be applicable in Sections 7 and 8.
Proposition 4.14**.**
Let and . There exist and such that for all and satisfying (2.34) we have
[TABLE]
Proof.
In the case where we (uniquely) select where . Otherwise if () we set ().
Step 1: For and define by
[TABLE]
We prove that there exists such that, for all and it holds that
[TABLE]
*for all pairs satisfying .
As
[TABLE]
we may use (4.51) to obtain
[TABLE]
We note that, for any , there exists such that
[TABLE]
Note that
[TABLE]
and consequently, the constant , which depends on of is uniformly bounded for all satisfying (2.34) whenever . In the case where we may use (4.33) and Sobolev embeddings.
On the other hand,
[TABLE]
we may conclude that
[TABLE]
and hence, there exists , such that
[TABLE]
Substituting the above into (4.58) yields
[TABLE]
We now observe, as in (4.37) (but with a lower bound in mind), that, for some positive and (note that ), it holds
[TABLE]
Hence, for another constant , we get
[TABLE]
To estimate the first term on the right-hand-side of (4.60) we first observe that for some we have
[TABLE]
Then we notice that for any such that we have by (4.3) and some integration by parts
[TABLE]
Recalling that , we thus apply the above inequality to
[TABLE]
in and to obtain
[TABLE]
which when substituted into (4.60) readily yields (4.57) via Cauchy’s inequality. Note that, for , (4.57) is trivial as .
Step 2: Let . We prove that for any , and , there exists and such that, for , , , and ,
[TABLE]
holds for any pair satisfying .
Let satisfy
[TABLE]
Let and set
[TABLE]
Note that by the choice of , satisfies also the boundary condition at .
It can be easily verified that
[TABLE]
By construction we have that , and hence we can rewrite the above equality (using (3.13) twice) in the form
[TABLE]
Taking the scalar product with and integrating by parts then yield
[TABLE]
As in the proof of (4.59), the first term on the right-hand side is estimated as follows
[TABLE]
To estimate the second term on the right-hand-side, we note that by Hardy’s inequality, we have
[TABLE]
From (4.65) we get
[TABLE]
Then, we write for the third term on the right-hand-side of (4.63), using integration by parts and the upper bound on
[TABLE]
Consequently, by (4.62),
[TABLE]
Hence, using Poincaré’s inequality,
[TABLE]
from which we conclude the existence of such that for any , we have
[TABLE]
To estimate the last term on the right-hand-side of (4.63), we use (4.38) and (4.65) to obtain
[TABLE]
Substituting (4.68) together with (4.64), (4.66), and (4.67) into (4.63) yields that there exists such that for every it holds that
[TABLE]
By Hardy’s inequality (4.2), Poincaré’s inequality, and (4.57) we obtain, for , , and , that
[TABLE]
Selecting then yields, for any , and ,
[TABLE]
As we then write
[TABLE]
Recalling the definitions of , and , we immediately conclude that
[TABLE]
which together with (4.57) gives
[TABLE]
Substituting (4.70) and (4.69) into (4.71) yields
[TABLE]
Hence, we can choose first and then such that (4.61) follows for and .
Step 3: We prove (4.61) under the assumption that
[TABLE]
with
[TABLE]
We recall (4.27) which reads
[TABLE]
For the last term we have, using Poincaré’s inequality and Sobolev’s embeddings
[TABLE]
where is given by (4.73).
Consequently, by (4.59)
[TABLE]
Using Young’s inequality we obtain
[TABLE]
Hence, for (4.61) follows immediately from the above inequality in conjunction with Poincaré’s inequality.
Step 4: We prove that there exist , and such that, for all , , and ,
[TABLE]
holds for any pair such that .
Without any loss of generality we can assume that . As
[TABLE]
or equivalently, by (3.13),
[TABLE]
Taking the scalar product with and integrating by parts then yield
[TABLE]
For the first term on the right-hand-side of (4.76) we use (4.59).
Next, we estimate the second inner product on the right-hand-side of (4.76) by splitting the domain of integration in two sub-intervals: and .
The integral over .
To estimate the integral over we use the identity
[TABLE]
to obtain that
[TABLE]
As
[TABLE]
we may conclude, having in mind that and are bounded, that
[TABLE]
Furthermore, employing Hardy’s inequality and Cauchy-Schwarz inequality yields
[TABLE]
Substituting the above inequalities into (4.77) yields
[TABLE]
The integrals over .
We now estimate the integrals over for the inner products on the right-hand-side of (4.76). To this end we write, using Hardy’s inequality (4.2) and lower bounds of ,
[TABLE]
Returning to the estimate of the right hand side of (4.76), we use (4.80), and the fact that (following from by definition of ) together with Poincaré’s inequality, to obtain
[TABLE]
and
[TABLE]
Combining the above and (4.79) yields
[TABLE]
Substituting (4.81) together with (4.59) into (4.76), yields
[TABLE]
From Hardy’s inequality in the form (4.2) we then conclude
[TABLE]
Combined with the following straightforward observation
[TABLE]
this yields,
[TABLE]
Hence, there exists and such that (4.75) holds for all and .
Step 5: *We prove that there exist and such that (4.75) holds for all and . *
Without any loss of generality we assume . We begin by rewriting in the form
[TABLE]
Taking the inner product with on the left yields
[TABLE]
Let
[TABLE]
Let
[TABLE]
Let denote the unique zero of . We may now use Hardy’s inequality to obtain the existence of such that for all , all ,
[TABLE]
Next we use the analog of (4.82)
[TABLE]
which leads, together with (4.84), to
[TABLE]
On the other hand we have from (4.83) and (4.38)
[TABLE]
Combining the above with (4.84) yields first
[TABLE]
hence, for sufficiently small ,
[TABLE]
Finally, using (4.85) once again leads to the existence of and such that if
[TABLE]
and we obtain (4.75) in this case as well.
Step 6: *Prove (4.56).
By (4.75) (established in steps 4 and 5 for ) and (4.61) (proved in steps 2 and 3 for ), there exist and such that for we have
[TABLE]
As , we can immediately conclude (4.56b). To conclude (4.56a,c) we first observe that
[TABLE]
and then use Hölder inequality
[TABLE]
valid for any , together with (4.38), and (4.30).
For later reference we also need the following estimate which can be deduced from the proofs of Propositions 4.13 and 4.14.
Proposition 4.15**.**
Let . Then, there exists such that, for all , such that , and satisfying (2.34) it holds that
[TABLE]
Proof.
Let be as in the statement of Proposition 4.14. Let , , and . For , (4.89) is an immediate result of (4.88).
Consider then the case . By (4.51) and (4.59), we obtain that
[TABLE]
Consequently, as , there exists such that
[TABLE]
Then, we use (4.54) to establish that
[TABLE]
from which we conclude, with the aid of (4.90), that
[TABLE]
Using Poincaré’s inequality we can now establish (4.89).
Corollary 4.16**.**
Under the assumptions of Proposition 4.15 there exists such that
[TABLE]
The proof follows immediately from (4.91) and step 6 of the proof of Proposition 4.14.
5 Some Schrödinger operators and their resolvents
In this section we derive several refinements of estimates obtained in [29, 4] for the resolvent of , (as in (3.6)) defined over different domains. As in the rest of this contribution, we are assuming (2.29). These estimates will be used in Sections 7 and 8.
5.1 The entire real line
We begin by stating the following result on .
Proposition 5.1**.**
For , let be given by
[TABLE]
with domain
[TABLE]
Then, for all positive , , , , and , there exist and , such that for all and satisfying
[TABLE]
it holds that
[TABLE]
and
[TABLE]
Proof.
The estimation of the first term on the left-hand-side of (5.4), can be obtained, for (with ) as in the proof of [29, Theorem 1.1 (ii)]. The difference is that the interval is infinite and that we impose here less regularity on the potential. To accommodate potential in the proof in [29], we construct a partition of unity composed of intervals of size ), and select instead of (as in p. 16, line 6 in [29]). The remaining details are skipped.
We now observe that
[TABLE]
For , we deduce
[TABLE]
which gives the estimate of the first term on the left-hand-side of (5.4) for .
To estimate the second term on the right-hand-side of (5.4), we return to (5.6) to conclude from the bound of , we have just obtained, that
[TABLE]
Finally, to prove (5.5) we use the identity
[TABLE]
to obtain with the aid of (5.4) that
[TABLE]
from which (5.5) easily follows.
5.2 A Dirichlet problem
We now obtain some resolvent estimate for the Dirichlet realization of in .
Proposition 5.2**.**
For any and , there exist and such that for all and
[TABLE]
and
[TABLE]
Furthermore, for every there exists such that for all
[TABLE]
Proof.
By [29, Theorem 1.1] we have, under the assumptions of the proposition,
[TABLE]
We next observe that for any
[TABLE]
which together with (5.11) yields
[TABLE]
To complete the proof of (5.8) we write, with ,
[TABLE]
From (5.11) and (5.12) we then obtain that
[TABLE]
completing, thereby, the proof of (5.8). We establish (5.9) in the same way we have established (5.5).
It remains to prove (5.10). Let and satisfy
[TABLE]
Let and denote functions such that
[TABLE]
Let be such that (otherwise, if for all , we arbitrarily set ).
Let
[TABLE]
As
[TABLE]
we obtain, observing that is uniformly bounded,
[TABLE]
Furthermore, since
[TABLE]
we obtain
[TABLE]
and hence, by (5.8),
[TABLE]
Substituting the above into (5.16) yields, with the aid of (5.8) and (5.9),
[TABLE]
Setting , we obtain in a similar manner
[TABLE]
and hence, with the aid of (5.8), we can conclude that
[TABLE]
We can now conclude, assuming first , with the aid (4.37),
[TABLE]
Otherwise, if , we rewrite (5.13) in the form
[TABLE]
to obtain from (5.18) that
[TABLE]
The proof of (5.10) can now be completed using (5.8).
We can now deduce the following corollary
Corollary 5.3**.**
For any and , there exist and such that for all , , , and it holds that
[TABLE]
Proof.
Let and set . By (5.8), there exist and such that, for
[TABLE]
Consequently, using the interpolation inequality
[TABLE]
and the Sobolev embedding
[TABLE]
we can conclude that
[TABLE]
For later reference we also need the following refined estimate.
Proposition 5.4**.**
For any and , , there exist and such that, for all , , and ,
[TABLE]
Proof.
Let be given by (5.14) and for any
[TABLE]
Let further
[TABLE]
implying that
[TABLE]
Step 1: We prove that, for any , there exist and such that, for all , , , ,
[TABLE]
where is chosen so that and
[TABLE]
Clearly,
[TABLE]
which implies
[TABLE]
To estimate we use the identity
[TABLE]
from which we easily conclude, using the fact that is bounded by assumption, that
[TABLE]
Finally we note that
[TABLE]
Suppose first that .
Since by (5.27) it holds that we may use (5.24) to obtain
[TABLE]
which together with (5.26) yields (5.22).
**Suppose now that .
**This time we have by (5.27) that , and hence we get from (5.24)
[TABLE]
To estimate the last term on the right-hand-side of (5.28), we use (5.25) once again and get instead of (5.26)
[TABLE]
or, alternatively, for any ,
[TABLE]
Substituting the above into (5.28) then yields
[TABLE]
Observing that
[TABLE]
yields (5.22) by choosing a sufficiently small value of .
To proceed to the next step, we need to define, yet, two additional dependent cutoff functions. Let then for , and in satisfy
[TABLE]
We further require that there exists and such that for any and
[TABLE]
Step 2: We prove that there exist , and such that, for all , there exists such that
[TABLE]
*for any pair satisfying (5.23).
*By (5.22) we have
[TABLE]
We now integrate the above inequality with respect to over . By changing the order of integration we obtain that for all
[TABLE]
Note that
[TABLE]
for any in the support of . We rewrite the above in the form
[TABLE]
As we have
[TABLE]
Finally, we have for all ,
[TABLE]
Note that vanishes for (for ) and . Note further that
[TABLE]
Combining the above with (5.33), (5.32), and (5.31) easily yields (5.30).
Step 3: We now prove (5.21).
Writing
[TABLE]
we obtain from (5.8) and the definitions and properties of the cut-off functions and ,
[TABLE]
where .
We now use (5.29) (with ) together with (5.22) to obtain that
[TABLE]
from which we can conclude, using the inequality for , that
[TABLE]
Substituting the above into (5.34), yields that, for some , it holds:
[TABLE]
Using (5.30) (used with replaced by and for large enough) then yields
[TABLE]
Combining the above with again (5.30) yields (5.21), by choosing a sufficiently large value of .
5.3 estimates
In this subsection we establish new estimates for the resolvent of , defined by (5.1) and (5.2). We first observe that the proof of Proposition 5.4 can be applied to the entire real line case, replacing the estimates of resolvent for the Dirichlet problem by the corresponding estimates of the resolvent for . Hence, we may state the following
Lemma 5.5**.**
For any , any and there exists and such that, for all , and ,
[TABLE]
We continue this subsection with the following estimate
Lemma 5.6**.**
For any and , there exist and such that, for all , , , and any supported in , we have
[TABLE]
Proof.
Let denote a fixed positive value and . Let further , supported on , and satisfy
[TABLE]
By (5.4)-(5.5) and (4.38), we have
[TABLE]
which proves the first inequality of (5.36).
Let satisfy . Let and be given by (5.14) and (5.15) and
[TABLE]
Taking the inner product of (5.37) with yields for the imaginary part (see (5.17) with instead of )
[TABLE]
By (5.35) we have that
[TABLE]
To estimate we use the identity
[TABLE]
to obtain from (5.4), (5.35), and (5.39)
[TABLE]
Substituting the above into (5.38) yields
[TABLE]
As
[TABLE]
we obtain from (5.40) that
[TABLE]
Then, using (5.41) once again yields
[TABLE]
from which we easily conclude that
[TABLE]
In a similar manner we obtain that
[TABLE]
This proves (5.36) in the case where .
It remains to prove (5.36) in the case . By (5.5) and the fact that is supported on , we have that
[TABLE]
The lemma is proved
A similar statement can be proved in the Dirichlet case.
Lemma 5.7**.**
For any and , there exist and such that, for all , and , and for any we have
[TABLE]
The proof is similar to the proof of Lemma 5.6 and is therefore skipped.
6 No-slip resolvent estimates
6.1 A no-slip Schrödinger operator
We begin by providing a short explanation of the difficulties arising when the no-slip boundary condition (3.10) is prescribed. Complete details will be given in Section 8.
In the zero-traction case, estimating satisfying for some , we may write, by (3.4),
[TABLE]
Since by (3.9), it holds that satisfies a Dirichlet condition at , one can now use, for instance, (5.8) and (5.21) to obtain
[TABLE]
Such an estimate is particularly useful in the case , but also in other cases (detailed in Section 8).
Similar estimates can be obtained for and .
If we now consider the same problem in the no-slip case the above approach is inapplicable. Thus, for satisfying , we can no longer use neither (5.8) nor (5.21), as does not satisfy a Dirichlet condition at . However, integration by parts easily yields that for all we have
[TABLE]
If we consider or instead of we can still obtain similar orthogonality conditions (see (8.22) and (8.32c)). These conditions read
[TABLE]
where and are linearly independent, dependent, and belong to .
With (3.4) in mind, we let be the differential operator with domain
[TABLE]
For convenience we require that satisfy
[TABLE]
Note that do not satisfy the above requirement, and we shall therefore need to replace them by a pair of proper linear combinations of them [44] (a more detailed explanation is brought in Section 8). We seek resolvent estimates for in the following. In the absence of a Dirichlet boundary condition, it seems reasonable to approximate the solution of
[TABLE]
by a sum of a solution in of the inhomogeneous equation and a linear combination of two independent approximate solutions of the homogeneous equation whose coefficients will be determined by the above integral conditions. Using affine approximations of in or extensions outside of , the approximate solutions can be described by a pair of dilated and translated Airy functions in and .
**The solution in .
** We now explain our construction of an approximate inverse in by defining first a natural -extension of outside of , satisfying (5.3), by
[TABLE]
We note that satisfies the conditions of Proposition 5.1. We also extend by
[TABLE]
and set
[TABLE]
where is defined by (5.1) and (5.2) and denotes the restriction to .
**Boundary terms.
**To obtain the boundaries effect, we replace by its affine approximation at and consider the solutions of the approximate problems
[TABLE]
and
[TABLE]
with
[TABLE]
Except, perhaps for some particular values of , the above solutions are unique, and rapidly decays as , but their existence (due to the additional integral condition) could depend on as is clarified below. We express using Airy functions. Having in mind the definition of the generalized Airy functions [47, eq. (39)] or [42, Lemma 2] (for more details see [17, Appendix] or our short review in Appendix A). These solutions are given, assuming that the denominator does not vanish, by
[TABLE]
where is the holomorphic extension to of
[TABLE]
Much of the properties of are recalled (mainly from Wasow’s paper [47]) in Appendix A. It has been established in [47] (see also Appendix A) that The zeroes of are located in the sector . Let
[TABLE]
and further define
[TABLE]
In addition, we prove in Appendix A.2 that and(relying on [47]) that It follows that the denominators in (6.8b) and (6.8a) do not vanish, if
[TABLE]
where is given by (2.30c).
The functions are not exact solutions of and hence we must introduce a correction term. We thus consider
[TABLE]
and then introduce
[TABLE]
This correction term can be estimated as follows
Lemma 6.1**.**
For any and , there exist and such that, for all , satisfying
[TABLE]
and , we have
[TABLE]
Proof.
A simple computation shows that:
[TABLE]
Let
[TABLE]
We note that
[TABLE]
where is defined in the appendix (see (A.42)).
Using translation, dilation, and (A.43a), we can conclude that, under the assumptions of Lemma 6.1, it holds, for , that
[TABLE]
Hence, as
[TABLE]
we have
[TABLE]
[TABLE]
establishing thereby (6.14).
We are now ready for introducing a solution of (6.4) in the form
[TABLE]
We observe that for any pair . Therefore, one can attempt to find two linear forms and such that belongs to the domain of , hence is the solution of (6.4). This is the object of the next lemma.
Lemma 6.2**.**
Let and , and suppose that satisfy the conditions (6.3),
[TABLE]
and
[TABLE]
Let further and . Then, there exist and such that for all , , and satisfying
[TABLE]
(6.4) and (6.20) hold true with and denoting a pair of linear forms . Furthermore, there exists such that, for all , and , we have
[TABLE]
Proof.
In view of the discussion preceding the statement of the lemma, it remains to show the existence of satisfying (6.24).
Taking the inner product of (6.20) in , first by and then by while having (6.1) in mind yields the following system
[TABLE]
We now write
[TABLE]
For the first term on the right-hand-side we have
[TABLE]
The integral on the other side can be estimated as follows: we first write
[TABLE]
Then, using (A.43b), (6.16) and dilation, we obtain for all ,
[TABLE]
The above estimate for yields,
[TABLE]
A similar estimate can be obtained for . Consequently we have
[TABLE]
For the second term on the right-hand-side of (6.26) we use the fact that, for all , we have by (6.3)
[TABLE]
We obtain, using (6.27) with and (6.22),
[TABLE]
Furthermore, by (4.37) and (6.19), we have
[TABLE]
By the above, (6.28), and (6.29), there exists and , such that, for any and any satisfying , we have
[TABLE]
As , we obtain as in (6.29)
[TABLE]
Furthermore, as in (6.30) we obtain that
[TABLE]
Substituting the above, together with (6.31) and (6.32) into (6.25) then yields, for small enough, and large enough, the invertibility of (6.25) together with the estimate
[TABLE]
By (5.36) we obtain that
[TABLE]
Substituting the above into (6.34) yields (6.24).
Remark 6.3**.**
We may replace in Lemma 6.2, by in (6.5) and (6.12), but under the condition . In this case, we have by (6.20) (with instead of ) and having in mind the Dirichlet condition at ,
[TABLE]
By (A.35) we have
[TABLE]
and by (A.43c)
[TABLE]
Combining the above with (6.24) yields that
[TABLE]
6.2 A no-slip Schrödinger in
In the previous subsection we have considered a space of functions satisfying the orthogonality condition (6.1). We have assumed that the functions spanning the orthogonal space and satisfy the bound
[TABLE]
where for some sufficiently small .
Of particular interest is the example (or a proper linear combination of them satisfying (6.3)). In this case, we have
[TABLE]
for sufficiently large .
Consequently, as long as , Lemma 6.2 is applicable in this case. We, however, need to consider also the case where , or even . These cases can, nevertheless, be treated using localization techniques as in [28, 4]. To this end we have to consider a localized version of near . This subsection is devoted therefore to the study of the ensuing linearized operator.
We begin by establishing a proper spectral formulation for the problem.
Proposition 6.4**.**
Let, for some ,
[TABLE]
*Then, is a closed operator with non empty resolvent set and compact resolvent.
Moreover has index [math].*
Before proceeding to the proof of the proposition we establish the following estimate of any in term of the -norm of and .
Lemma 6.5**.**
There exists some constant such that, for any and any , we have
[TABLE]
Proof.
Let and satisfy
[TABLE]
Taking the inner product with yields
[TABLE]
To obtain an estimate for the fourth term on the left-hand-side of (6.39) we need an effective bound on .
Integration by parts yields, with the aid of the fact that ,
[TABLE]
Taking the inner product of (6.38) with , we then obtain
[TABLE]
from which we conclude that
[TABLE]
As
[TABLE]
we obtain, using (6.41) that
[TABLE]
Combining the real part of (6.39) with (6.43) yields
[TABLE]
Consequently, we obtain (6.37).
Proof of Proposition 6.4.
Step1: We prove that is a closed operator.
Let converge, as , in to . We need to establish that . The orthogonality of with immediately follows from the convergence. From (6.37) (with ) we conclude that is a Cauchy sequence in and hence must converge to in the norm.
Let be supported on and satisfy for . Clearly,
[TABLE]
Since we can smoothly extend to , it follows from (5.4) and (5.5) (with and ) that and are Cauchy sequences in and in respectively. Hence, its limit satisfies and . By the convergence of it follows that is a weak solution of
[TABLE]
Since the right-hand-side is in , it follows that and hence is closed.
Step 2: We prove that has index [math].
Let be associated with the same differential operator as . Clearly, is a Fredholm operator of index . Indeed, it is clearly surjective (we can find a unique solution satisfying a Dirichlet condition at ) and it is easy to see that the kernel has dimension (. Consequently, for any , has index . We now observe that is obtained by imposing a single orthogonality condition in the domain. Hence the index of equals [math].
Step 3: We show that .
We prove that there exists such that for all the operator is injective. Combined with the above zero index property, it would yield that the resolvent set contains the half plane . The injectivity follows from (6.42) and (6.44), by which there exist and such that for all , we have
[TABLE]
Finally, the compactness of the resolvent follows from the fact that is compactly embedded in .
The previous proof has also shown to us that is semi-bounded. The next proposition provides a more explicit lower bound for the spectrum as a function of .
Proposition 6.6**.**
For all , we have
[TABLE]
Proof.
Suppose that for some positive there exist and such that
[TABLE]
Since is an solution of the complex Airy equation in it is expressible, up to a multiplicative constant, in the form
[TABLE]
Step 1: We prove that the set is open.
We use the implicit function theorem. If indeed , we get after integration by parts that
[TABLE]
Hence there exists a neighborhood of and a - solution in this neighborhood such that .
Step 2: Let . Consider the set
[TABLE]
which can be described as a countable (or finite) union of simple analytic curves denoted by , each with an interval of definition . Let further . We prove that for all and
[TABLE]
where
[TABLE]
Let . For convenience of notation we set
[TABLE]
By (6.48b,c) we have that
[TABLE]
Differentiating this identity with respect to yields
[TABLE]
Integration by parts yields, in conjunction with (6.50),
[TABLE]
We now write, with the aid of (6.50) and Airy’s equation
[TABLE]
Integration by parts and (6.52) then yield
[TABLE]
Substituting the above, together with (6.52) into (6.51) yields
[TABLE]
Taking the inner product of (6.47) with we obtain for the real part
[TABLE]
where .
Combining the above with (6.53) then yields
[TABLE]
We then have on the branch
[TABLE]
Solving in yields (6.49).
Step 3: We prove that along every curve in
[TABLE]
From (6.44) with , and (6.42) we obtain that
[TABLE]
The above, in conjunction with Young’s inequality yields which is precisely (6.54). In particular it implies that
[TABLE]
Step 4: We prove (6.46).
If then (6.46) readily follows. Hence, we can assume that there exists such that and .
We then look at inside where . By (6.55), all branches exit for sufficiently large .
We now observe that
[TABLE]
Indeed, as
[TABLE]
we can apply Corollary A.4. Hence, these branches must lie outside for for sufficiently small . Assume that is chosen small enough so that
[TABLE]
Consider any branch in with in some interval such that
We can then use (6.49) to obtain
[TABLE]
This completes the proof of (6.46).
Corollary 6.7**.**
It holds that
[TABLE]
The proof of (6.57) with the non strict inequality follows immediately from (6.46). Note now that by (6.56), taking into account that and that we can conclude the strict inequality in (6.57).
The adjoint operator
We note that is not dense in . We thus introduce , and then define
[TABLE]
and set to be the unique (by Riesz theorem) for which
[TABLE]
The standard definition is recovered when . Note that
[TABLE]
where is the projector on . We further note that is an unbounded operator on .
In the particular case , is the orthogonal complement in of . Hence, , where, for any ,
[TABLE]
We next provide a more explicit representation of .
Lemma 6.8**.**
We have
[TABLE]
Proof.
The proof is reminiscent of the analysis of selfadjointness for -problems in [41]. Let and then set . Let , where is defined by (6.58). From the definition we deduce that the distribution
[TABLE]
should extend as a continuous linear map on . We then observe that
[TABLE]
The second term on the right hand side defines a linear form on . Hence, from (6.58) we get that is a distribution in . Hence, it holds that . We can thus conclude that , .
We now compute using integration by parts to obtain
[TABLE]
To conform with (6.58) must be a continuous map on . This, however, is possible only if (consider the sequence with ), leading thereby to (6.59a). Consequently for any , we have
[TABLE]
Having in mind that
[TABLE]
leads to
[TABLE]
We can then extend (6.60) by density to any .
Proposition 6.9**.**
The eigenfunctions of are complete in .
Proof.
We take a similar approach to the one in [5].
Step 1: By the semi-boundedness of and (6.59a) there exists and such that for all
[TABLE]
Step 2: We now show that the resolvent of is in for every , where denotes the Schatten of order .
By the Max-Min principle the singular values of the operator satisfy for
[TABLE]
Let further
[TABLE]
By (6.61) we have, for ,
[TABLE]
Finally, let
[TABLE]
In view of the additional constraint embedded in we have
[TABLE]
By the Max-Min principle the are eigenvalues of
[TABLE]
defined on
[TABLE]
Let , where , denote an eigenvalue of . (Note that is an eigenvalue.) Let denote the corresponding eigenfunction. As
[TABLE]
we easily obtain that, up to a product by an arbitrary constant,
[TABLE]
where has to be determined from the requirement . It can now be easily verified that if and only if
[TABLE]
Let denote the zeroes of Airy’s function . By computation of its derivative is a monotone increasing for and tends to at the edges. Consequently, there is precisely one solution of (6.62) in .
As we may conclude from the foregoing discussion that as well. Consequently, there exists such that, for sufficiently large ,
[TABLE]
As a result, for all it holds that
[TABLE]
Step 3: We complete the proof of the proposition.
We take a similar approach to the one in [5]. By (6.42) and (6.44) we have, for sufficiently large ,
[TABLE]
Let for some . From the imaginary part of (6.39) we learn that
[TABLE]
With the aid of (6.37) and (6.43) we then obtain that
[TABLE]
Hence, there exists such that if , then
[TABLE]
From the foregoing discussion we may conclude that every direction where is a direction of minimal growth for . Following the arguments of the proof of [2, Theorem 16.4] (cf. also [21, Theorem X.3.1 ] or [18, Corollary XI.9.31])) we can conclude that the eigenspace of is given by .
Proposition 6.10**.**
Let . Then,
[TABLE]
where the left most eigenvalue of the Dirichlet realization of in .
Proof.
We begin the proof by applying Rouché’s Theorem, in the large limit, to the holomorphic functions and inside a disk of radius centered at and containing no other eigenvalue of . As has a unique zero in this disk, Rouché’s Theorem would show the same for the zeros of . It is therefore necessary to compare the two functions for . We thus write
[TABLE]
We bound the right-hand-side in the following manner
[TABLE]
From this, we obtain the existence of and such that, for any and any , we have
[TABLE]
It follows from Rouché’s Theorem that for sufficiently large , has a unique zero in .
At this stage we have obtained
[TABLE]
Using the arguments as above and supposing now that and , we can establish that
[TABLE]
Consequently, we obtain that, there exists such that, for all does not vanish in .
To complete the proof we need yet to establish that there exists , and such that for all we have that
[TABLE]
To this end we set as in (A.6)
[TABLE]
To bound the second term we use (A.14) and (A.17) (with ) together with Sobolev embeddings to obtain
[TABLE]
Hence,
[TABLE]
from which (6.67) easily follows.
6.3 No-slip operator on for large
Consider , defined in (6.2), with , where is the solution of
[TABLE]
An immediate computation gives
[TABLE]
and a similar formula for .
We attempt to obtain a resolvent estimate for in the case where . If we try to use the arguments of Subsection 6.1 we would encounter a problem while attempting to use (6.29). It can be verified from (6.70) that
[TABLE]
Then, one can deduce in the same manner that for some , , and sufficiently large ,
[TABLE]
Thus, the error introduced by (6.29) is not necessarily small and one needs an alternate route for the estimation of .
Since for we need to consider, in the next section, only the case , we focus attention here on the resolvent of in that case. Thus, we no longer approximate near by , as in Subsection 6.1, and use instead the approximation as observed in (6.71). Note that depends on through the orthogonality conditions appearing in the definition of its domain. Consequently, we need to renormalize from (6.8b) and (6.8a) in a manner that would suit the approximation used for .
For some , the renormalization factor will be defined by
[TABLE]
where, (see (6.15) for the definition of ),
[TABLE]
We now define
[TABLE]
where was introduced in (6.8b)- (6.8a).
The above normalization provides the approximation , in the limit , as in Subsection 6.1 (see below (6.85)).
We similarly introduce with the notation of (6.11) and (6.12)
[TABLE]
We can now state:
Proposition 6.11**.**
Let , and . Then, there exist and such that, for all , and ,
[TABLE]
where
[TABLE]
Remark 6.12**.**
In the sequel we apply Proposition 6.11 with where is defined in the statement of Lemma 6.2.
Proof.
The proof goes along similar lines to the proof of Lemma 6.2. Let satisfy
[TABLE]
Furthermore, let the pair in satisfy the relation
[TABLE]
We assume, as in (6.20),
[TABLE]
where is given by (6.5), and then estimate in the relevant regime of values.
We first estimate the renormalization factor. We note that
[TABLE]
and from (A.44) which reads,
[TABLE]
we obtain that there exist and , such that for all , , and we have
[TABLE]
We can now use (6.17), (6.18) and (6.19) to obtain that
[TABLE]
[TABLE]
and
[TABLE]
We note that (6.25) remain valid in the case , i.e.,
[TABLE]
We now write
[TABLE]
Since by (6.79) and (A.43b) we have that
[TABLE]
we can easily deduce using (6.71) that for sufficiently large
[TABLE]
Furthermore, as
[TABLE]
we have that
[TABLE]
Since by (6.84) we have
[TABLE]
and hence we obtain
[TABLE]
and a similar estimate can be obtained for .
We now write
[TABLE]
and then use (6.84), (6.79), and (A.43c) to obtain that
[TABLE]
Bounds for .
Set,
[TABLE]
As and , it can be verified that
[TABLE]
and hence
[TABLE]
We now verify that
[TABLE]
Indeed, we have
[TABLE]
which is non positive by (6.87).
Hence the maximum of is obtained at . A similar inequality can be established for . Combining (6.88) and (6.89) yields
[TABLE]
Note that the replacement of by avoids the burden of a vanishing denominator.
We now write
[TABLE]
To estimate in the right hand side of (6.91) , we first obtain a bound for . Thus, integration by parts yields for all
[TABLE]
From which we conclude, by integrating the above for and Cauchy-Schwarz inequalities, that
[TABLE]
By (5.4) and (5.5) we then have
[TABLE]
We now write
[TABLE]
By (5.4) we then have
[TABLE]
and hence, using(5.4) once again to estimate , we may conclude that
[TABLE]
Combining the above with (6.90) and (6.91) yields
[TABLE]
Bounds for .
The estimation of follows a similar path to that of . We begin by writing
[TABLE]
Since , given by (6.75) satisfies the same problem as with replaced by we may conclude as in (6.92) that
[TABLE]
Consequently, by (6.81) and (6.90)
[TABLE]
In a similar manner we can obtain that
[TABLE]
As in (6.31) we can now write, in view of (6.94) and
[TABLE]
Combining the above with (6.86), (6.94), and (6.95) yields
[TABLE]
The above, together with (6.93) yields
[TABLE]
As , we obtain for sufficiently large
[TABLE]
Combining the above with (6.78), (6.80), and (6.82) yields (6.76).
7 Zero traction Orr-Sommerfeld operator
7.1 A short reminder
We recall for the commodity of the reader that is defined by (3.4) and (3.10) i.e.
[TABLE]
with domain
[TABLE]
Here
[TABLE]
and is the Dirichlet realization of in .
Finally we recall that the inviscid operator associated with is defined by
[TABLE]
with domain .
7.2 The case .
We now prove
Proposition 7.1**.**
For all and there exist positive , , and such that, for any and satisfying (2.34), it holds that
[TABLE]
Proof.
Let . Let further and suppose . Let and satisfy
[TABLE]
and
[TABLE]
We note that and, defining by
[TABLE]
we have
[TABLE]
By (5.19), there exist and such that, for and we have
[TABLE]
As
[TABLE]
we easily obtain that
[TABLE]
We now write,
[TABLE]
With the aid of (5.8) and (5.21) we then obtain
[TABLE]
Substituting the above into (7.8) then yields
[TABLE]
To bound we first use the fact that
[TABLE]
Then, by (7.10) we obtain that
[TABLE]
and
[TABLE]
We continue the proof by considering in a few different regimes of values.
Case 1: Bounded
Suppose first that
[TABLE]
where . The value of to be selected above will be determined in a later stage.
Using (7.10) , (7.11), and (7.14), we obtain from (7.5) that
[TABLE]
or by Sobolev’s embedding
[TABLE]
(7.3), we may apply Proposition 4.14 to the pair to conclude, by (4.25), that for any there exists such that
[TABLE]
Similarly, by (4.26), for any there exists such that
[TABLE]
Hence,
[TABLE]
We may now use (7.6) to obtain, for ,
[TABLE]
Applying (7.6) (which is valid for as well) once again yields
[TABLE]
Finally, we apply (5.10) (with ) to the pair satisfying (7.4)) to conclude, for , that
[TABLE]
Combining the above we then obtain, for sufficiently small and ,
[TABLE]
From (5.10) and (7.19) we now get, for any ,
[TABLE]
From which we deduce, for sufficiently close to and sufficiently small , the existence of such that
[TABLE]
We now return to (7.17) to conclude that
[TABLE]
Hence (7.1) is proven in Case 1 for sufficiently small .
Case 2: unbounded negative
Next, consider the case where (7.15a) is kept in place but instead of (7.15b), is assumed. In this case we return to (7.7) and use the positivity of for the last term on its right hand side. In a similar manner to the one used to derive (7.8) we establish the existence of such that for all ,
[TABLE]
Since it can be easily verified that
[TABLE]
and hence for any , there exist and such that, for all and all
[TABLE]
establishing (7.1) in Case 2.
Remark 7.2**.**
Case 3: unbounded
Consider next the case, where instead of (7.15) we have
[TABLE]
In this case we write
[TABLE]
As we have that
[TABLE]
and hence, under (7.22),
[TABLE]
Selecting we then obtain
[TABLE]
We can now conclude from (7.21) that
[TABLE]
As (4.24)- (4.26) are not valid for , we need to establish (7.20) for the case . Let
[TABLE]
Then, we may write by (7.7) that
[TABLE]
Then, as
[TABLE]
we may conclude (7.1) from (7.20).
7.3 The nearly Couette case
We now proceed to consider the nearly Couette case addressed by both Theorems 2.15 and 2.16. Let satisfy (2.29) and recall the definition of from (2.31),
[TABLE]
We next recall from (2.33), for some ,
[TABLE]
We shall consider the case where is small. Unlike the Couette case, where , is no longer accretive when [15, Subsection 6.1]. Note that in contrast with the assumptions of Proposition 7.1, may change its sign.
Proposition 7.3**.**
For any and , there exist , and positive and , such that, for all satisfying and all ,
[TABLE]
Proof.
Note that by (2.33)
[TABLE]
As in the proof of Proposition 7.1 we separately consider different regimes of .
**Case 1: or
**
Let . Using the definitions (7.2)-(7.3) we further set
[TABLE]
Clearly
[TABLE]
We now write
[TABLE]
By (5.8) and (5.9) we then have
[TABLE]
Next, we turn to estimate . Clearly, by (7.25),
[TABLE]
where we have use that fact that
[TABLE]
For the third term in the right-hand-side of (7.27) we have
[TABLE]
We now turn to estimate the second term on the right-hand-side of (7.27). Here we write
[TABLE]
Then, we use (7.13) (which remains valid in the nearly-Couette case) to obtain
[TABLE]
Sobolev embedding then yields
[TABLE]
Finally, we turn to estimate the last term on the right-hand-side of (7.27).
Suppose first that for some we have . Clearly, as
[TABLE]
it holds by (7.24) that
[TABLE]
Hence, we obtain
[TABLE]
Substituting the above together with (7.29) and (7.28) into (7.27) yields with the aid of Sobolev embedding and Poincare inequality
[TABLE]
which for gives
[TABLE]
By (7.26) we then have
[TABLE]
The proof can now be completed, for or , by using (4.26) with . In the case where on , we may still apply the previous arguments by replacing (7.30) with
[TABLE]
where denotes for and for .
**Case 2: **
Let
[TABLE]
and then write
[TABLE]
Since we can use (7.23) to obtain that
[TABLE]
We now recall (7.9)
[TABLE]
and then use (5.8) and (5.21) to establish that
[TABLE]
Substituting the above into (7.35) yields
[TABLE]
Using Sobolev embedding yields (7.23) , for sufficiently small and .
8 No slip Orr-Sommerfeld operator
In contrast with the prescribed traction condition, the auxiliary function , does not satisfy, if a Dirichlet boundary condition. Consequently, special attention must be given to the behaviour of near the boundary through (6.20) for instance. Since satisfies a Dirichlet boundary condition, we expect that the rapidly decaying boundary terms in (6.20) should have a negligible contribution to compared with that of (i.e., ). The next subsection is dedicated to the establishment of such estimates.
8.1 Preliminaries
We recall that and that and are respectively defined by (6.10), (6.6) and (6.7). The next lemma holds true under the assumptions of either Proposition 4.10 or Proposition 4.14.
Lemma 8.1**.**
For any and , there exist positive constants and such that, for all , for which , and satisfying either (2.34) or (4.19), it holds that
[TABLE]
where
[TABLE]
Proof.
Let . We write
[TABLE]
As
[TABLE]
we may write
[TABLE]
It follows from (6.27) (with ) that for some positive
[TABLE]
In the case where (4.19) is satisfied, we may use (4.41) so that
[TABLE]
which, combined with (8.4) yields (8.1).
In the case where (2.34) is satisfied, we may use (4.89) for to obtain that
[TABLE]
Then, we apply (8.4) to obtain (8.1).
We shall also need the following
Lemma 8.2**.**
Let and . Let further satisfy , and are in and . Then, there exist positive and such that, for all , and all satisfying either (2.34) or (4.19), it holds that
[TABLE]
where
[TABLE]
Proof.
For later reference we note that the requirement set above that implies the existence of such that
[TABLE]
and
[TABLE]
where .
Step 1: We prove that there exist positive , and such that for all and
[TABLE]
For convenience of notation we prove (8.6) only for . The proof for can be obtained in a similar manner.
Let , for . For convenience we also set for all .
The case .
For , we observe from (5.4) and (6.17), that we have
[TABLE]
We note that (8.6) for does not follow from (8.7). Some additional estimates for large values should be obtained to this end. For , we now write:
[TABLE]
By (5.4) it holds that
[TABLE]
As
[TABLE]
we obtain, as , that
[TABLE]
Substituting the above into (8.9) yields, for ,
[TABLE]
Using (6.17) for and , which holds as , yields
[TABLE]
From (8.7) and (8.12) we then get
[TABLE]
Using (8.13) we can now complete the proof of (8.6) for . To this end we write
[TABLE]
From (5.5) and (6.17), we deduce that
[TABLE]
On the other hand, we have, by (8.13)
[TABLE]
Together with (8.7), we obtain
[TABLE]
which proves (6.11) for .
The case .
By (8.10) we may write, instead of (8.11),
[TABLE]
Hence, by (6.17), it holds that
[TABLE]
which, when substituted into (8.9) for , yields
[TABLE]
Substituting into (8.11) yields, for ,
[TABLE]
and hence, by (8.9) for ,
[TABLE]
As above we now write
[TABLE]
to obtain from (8.17), (8.16), (5.5), and (6.17) that
[TABLE]
The case
We briefly repeat the same argument as in the case . By (8.10) with we may write (instead of using (8.11))
[TABLE]
From which we obtain, with the aid of (8.19) and (8.15)
[TABLE]
Substituting (8.20) into (8.9) with then yields with the aid of (8.14)
[TABLE]
Substituting the above, (8.20), and (8.14) into (8.11), with yields
[TABLE]
From (8.9) with we then obtain
[TABLE]
As in (8.18) and (8.19) we can now obtain that
[TABLE]
Combining the above with (8.19) and (8.14) yields (8.12).
Step 2: We prove (8.5).
We first observe that by interpolation (8.6) holds for any . If the conditions of (4.10) are met, we may now obtain (8.5) from (4.19) as in the proof of (8.1).
Otherwise if the assumptions of Proposition 4.14 are met, we may conclude (8.1) from (4.89).
8.2 Nearly Couette flows
We begin by considering the case where the flow is nearly linear, as in Subsection 7.3.
8.2.1 The case
Let be defined by (3.4). We can now state and prove
Proposition 8.3**.**
For every and , there exist positive , , , and such that, for all satisfying (where is given by (2.31)) and , it holds that
[TABLE]
Proof.
Let and satisfy . Let . Let further be given by (7.3), and set . Without any loss of generality we select
[TABLE]
Step 1: We prove (8.21) for satisfying either or , and .
Let satisfy the problem
[TABLE]
Note that the differential operator on the left-hand-side is identical with that of given by (3.13). We now write
[TABLE]
in which , where is given by (5.14), and .
and estimates
We begin by establishing and estimates for . To this end we first write
[TABLE]
Note that since the derivatives of are supported on we have, since is bounded,
[TABLE]
Note further that, for all , we have
[TABLE]
and
[TABLE]
Consequently, for all , we have
[TABLE]
Observing that
[TABLE]
we deduce from Lemma 4.7 that, for sufficiently small there exist and such that, for any and any , (recall that in this step)
[TABLE]
Consequently, by (4.34) (which is applied with , and ) and (8.25), for any there exists such that
[TABLE]
(We use the fact that and Poincaré’s inequality to obtain the last inequality.) We may thus conclude that
[TABLE]
Hence, for , we get
[TABLE]
which finally implies
[TABLE]
By (8.26) we also have that
[TABLE]
and hence
[TABLE]
For we may thus conclude
[TABLE]
As (8.27) and (8.28) are unsatisfactory for large values of , we use the fact that
[TABLE]
Assuming , we first obtain, for any
[TABLE]
Poincaré’s inequalit then yields, for sufficiently small
[TABLE]
which implies, for sufficiently large
[TABLE]
We can now use (8.25a), (8.27) and (8.29) to obtain, for any ,
[TABLE]
Combining (8.29) with (8.27) implies, in addition, the following refinement of (8.27) to any
[TABLE]
Substituting (8.30) and (8.31) into (8.23) respectively yields
[TABLE]
Application of Lemma 6.2
It can be easily verified that
[TABLE]
We can thus consider the problem
[TABLE]
where satisfies (8.32c) and is given by (see (7.25))
[TABLE]
By (8.32) we may now use Lemma 6.2 to conclude from (6.20) (applied for )) that admits the decomposition
[TABLE]
where and respectively satisfy (6.24) and (6.14), and is given by
[TABLE]
where
[TABLE]
By (5.4) we then have
[TABLE]
Estimate of .
Since (7.27), (7.28), and (7.31) are still valid, we obtain
[TABLE]
which leads for to
[TABLE]
To bound the last term on the right-hand-side we write, recalling that in this step,
[TABLE]
Then, we use the fact that by (7.3) and (3.13)
[TABLE]
As in the proof of (7.31), we get
[TABLE]
We now obtain a bound for the norm of by estimating each term appearing in the right hand side of (8.33). By (6.14) we get for ,
[TABLE]
By (6.17) (for ) we get for ,
[TABLE]
and by (6.24) we get for
[TABLE]
Together with (8.35) for , we then have
[TABLE]
where is given by (6.15).
Since (7.12) remains valid for no-slip conditions we may conclude that
[TABLE]
Since is bounded in this step, we obtain
[TABLE]
Combining the above with (8.36) and (8.37) yields
[TABLE]
For later reference we note that by (7.31), (8.40) and (8.41) we have
[TABLE]
Estimates of
Next we set, with (8.33) in mind,
[TABLE]
where
[TABLE]
and
[TABLE]
Set further
[TABLE]
Clearly,
[TABLE]
To estimate we write
[TABLE]
For the first term in the right hand side, we use (8.1) to obtain
[TABLE]
Using (4.26) with and (6.14), yields for the second term
[TABLE]
Hence using (8.39), we obtain
[TABLE]
To estimate we first recall that by (8.34) and (8.44)
[TABLE]
By (5.4) and (5.5) we then have
[TABLE]
and hence by (8.41)
[TABLE]
By (4.26) (with ), and the definition of we obtain
[TABLE]
Substituting (8.49) and (8.47) into (8.45) yields,for sufficiently small
[TABLE]
which is precisely (8.21) established in this step for all such that , and either or .
Step 2: We prove (8.21) for sufficiently small and satisfying and .
Let be given by (6.69). Note that
[TABLE]
By (3.10), (6.69), and two integrations by parts, it holds that
[TABLE]
As (7.9) is still valid, and in view of (8.50) and (8.51), we can apply Lemma 6.2, assuming that is small enough, with replaced by , to obtain for
[TABLE]
that
[TABLE]
where
[TABLE]
and
[TABLE]
By (6.24) and the fact that in this nearly Couette case, it holds that
[TABLE]
By (6.14) together with (8.53), we have
[TABLE]
By (5.4) and (5.35) it holds that
[TABLE]
Combining the above with (8.52) and (8.54) then yields
[TABLE]
where
[TABLE]
As in the proof of Proposition 7.3, we use the result of the previous step by considering for a suitable value of . We choose such that
[TABLE]
We now write
[TABLE]
and introduce the following decomposition of
[TABLE]
where
[TABLE]
For convenience we set
[TABLE]
We may now apply (8.21) (with replaced by ) to obtain, with the aid of (8.55) that
[TABLE]
Estimate of .
We seek an estimate of . To this end we repeat the same procedure applied in step 1. For convenience of notation we consider only in the following. The same estimates for can be obtained in a similar manner. Let then
[TABLE]
and
[TABLE]
It can be easily verified that
[TABLE]
and that . Consequently, we can use Lemma 6.2 with replaced by . With the notation , ,and (as defined in (6.12)) Lemma 6.2 yields
[TABLE]
where and
[TABLE]
Moreover, we have that
[TABLE]
We now follow the arguments of the previous step with respectively replacing . We then reach by the equivalent of (8.42)
[TABLE]
from which, using (6.17), we get
[TABLE]
Hence, by (8.60) for , we get
[TABLE]
As above we set
[TABLE]
[TABLE]
Note here that as we have used that, for some ,
[TABLE]
Moreover, by (8.61), (6.14), and (4.26) (with ) it holds that
[TABLE]
Combining the above yields
[TABLE]
Next, we estimate . By (8.5) we have
[TABLE]
Furthermore, by (5.5), (5.4), and (4.26), we have
[TABLE]
By (8.42) with instead of and replacing , it holds that
[TABLE]
Combining the above with (8.65) leads to
[TABLE]
which, together with (8.64), yields
[TABLE]
Combining the above with (8.62) and (8.63) yields, for small enough,
[TABLE]
In a similar manner we obtain
[TABLE]
Substituting the above, (8.58), and (8.53) into (8.57) yields that (8.21) holds for .
Step 3: We prove (8.21) for satisfying .
As and
[TABLE]
we can conclude that
[TABLE]
Since it holds that
[TABLE]
and hence (recall that and ) we can conclude that there exists such that
[TABLE]
completing, thereby, the proof of (8.21) for .
Step 4: We prove (8.21) for satisfying .
An integration by parts yields
[TABLE]
and as
[TABLE]
we obtain that
[TABLE]
As
[TABLE]
we establish (8.66) whenever .
The proposition is proved.
8.2.2 The case
We separately treat the case and the case .
Proposition 8.4**.**
For any and any there exist , and such that for all and
[TABLE]
Proof.
Let be given by (6.69). By (6.76), (7.9), and (8.51), we have
[TABLE]
where .
Hence,
[TABLE]
As , we obtain that for sufficiently large and ,
[TABLE]
which implies
[TABLE]
Returning to (8.69), we get
[TABLE]
hence
[TABLE]
Remark 8.5**.**
Using the definition of from (6.77) yields that
[TABLE]
*where . Let .
Using the definition of from (6.57) we then conclude*
[TABLE]
Consequently we obtain that
[TABLE]
By the foregoing discussion, we may conclude from (8.67) that
[TABLE]
A similar estimate holds true also for .
Proposition 8.6**.**
For any and there exist positive , and such that for all and such that
[TABLE]
Proof.
To prove (8.71) we note that by (7.9) we have
[TABLE]
Consequently,
[TABLE]
from which (8.71) follows as in the - case.
8.3 Strictly convex/concave flows
8.3.1 Large or
If we assume large or we may obtain resolvent estimates for all , without the necessity to assume any further restrictions on as in the nearly Couette case or in the case .
Proposition 8.7**.**
Let , , and . Then, there exist , , , , and such that, for all and satisfying (4.24)-(4.26), it holds that
[TABLE]
and
[TABLE]
Proof.
Let , and satisfy
[TABLE]
**Proof of (8.73).
**Consider first the case . Here, following the same derivation as in (7.27)-(7.31) (for ) and (8.37)-(8.41) (for ) (the role of being replaced by , which is small too) we obtain
[TABLE]
For sufficiently large we can thus follow the same steps of either the proof of Proposition 7.3 starting from (7.32) now replaced by (8.74), or the proof of Proposition 8.3 starting from (8.41), now replaced by (8.74), to obtain (8.73).
**Proof of (8.72).
** Case 1: . To prove (8.72) for we repeat the same procedure used in the proof of Proposition 8.3 to establish (8.48) with (note that we always have and recall that is defined by (8.44))
[TABLE]
In the case we repeat the same steps as in the proof of Proposition 7.3 to establish (7.33) with . For convenience we use the notation instead of (which is defined by (7.3)).
We now estimate . To this end we rewrite (4.28) in the form
[TABLE]
The left-hand-side can be bounded by (4.39) (for ) to obtain
[TABLE]
Since by Lemma 4.9, we pick such that
[TABLE]
Then we write
[TABLE]
Consequently,
[TABLE]
and
[TABLE]
By (8.75) and (8.77), we deduce
[TABLE]
In the case we have and hence (8.72) immediately follows. In the case we continue as in the proof of Proposition 8.3 to establish (8.47) with , or explicitly,
[TABLE]
The above, combined with (8.78) and (8.45) yields for with large enough and with large enough
[TABLE]
from which (8.72) readily follows.
Case 2: .
For we use (7.36) for , i.e.,
[TABLE]
Then, as
[TABLE]
we may use (8.78), having in mind that , to obtain that
[TABLE]
Substituting (8.80) into the above yields (8.72).
For we first obtain (8.55) with , which implies
[TABLE]
where
[TABLE]
and
[TABLE]
As
[TABLE]
where satisfies (8.56), we can write as in (8.57) that
[TABLE]
where
[TABLE]
The estimation of can be done with the aid of (8.79) and (8.81), yielding
[TABLE]
To estimate (or ) we write
[TABLE]
where
[TABLE]
As
[TABLE]
we can conclude from (5.4), (5.5), and (8.77) that
[TABLE]
The estimation of in the proof of Proposition 8.3 does not involve at all, but only and hence we can conclude by (8.63) and (8.64) that
[TABLE]
Consequently we obtain that for sufficiently large
[TABLE]
A similar estimate holds for , and hence we can conclude (8.72) from (8.83), (8.82), and (8.53).
8.3.2 The case
Lemma 8.8**.**
Let and . Then, there exist , , and such that for all and satisfying (2.34), it holds that
[TABLE]
where is the same as in Proposition 8.7.
Proof.
Let , , and defined by
[TABLE]
where
[TABLE]
in which is defined in (6.8) and , with given by (5.14). We note that by (A.43d) we have that for some
[TABLE]
Note that and hence we may introduce
[TABLE]
We have
[TABLE]
wherein
[TABLE]
and
[TABLE]
We note that
[TABLE]
As in the proof of Proposition 7.1 (see in particular (7.7)) we can integrate by parts to obtain
[TABLE]
We begin the estimation by obtaining a bound for the last term on the right-hand-side.
**Estimate of .
** We first write
[TABLE]
Let
[TABLE]
By (A.43c) and (8.87) there exists such that , and hence
[TABLE]
Thus,
[TABLE]
Using (A.43b), (8.87), translation, and dilation (see also (6.17)), we may conclude that
[TABLE]
and hence
[TABLE]
We then obtain for , using the fact that ,
[TABLE]
Consequently, from (8.91) and (8.92), we thus get, as ,
[TABLE]
**Estimate of .
** Next we obtain from (8.90) and (8.93) that
[TABLE]
To estimate we first write, as in (7.9)
[TABLE]
where is given by (6.69). Then, in view of Remark 6.3, we may use (6.35) to obtain that with to obtain
[TABLE]
Furthermore, using the fact that , we may use (6.18) and (8.87) to obtain that
[TABLE]
which, when substituted into (8.94), yields, with the aid of Sobolev’s embeddings,
[TABLE]
**Estimate of .
** By (5.21) and (8.89) we have that
[TABLE]
Hence, by (8.96) and (8.95), we have that
[TABLE]
Substituting the above into (8.97) yields
[TABLE]
We now combine (8.88), (8.98), (8.97), (8.95), and (8.96) to obtain that
[TABLE]
**Proof of (8.84)
**We continue as in the proof of Proposition 8.3. We first write, in view of (8.85)
[TABLE]
where
[TABLE]
[TABLE]
and hence, by (8.100),
[TABLE]
Substituting the above into (8.99) yields, with the aid of (8.100)
[TABLE]
By (4.92b,c) we then have for any and (recall that )
[TABLE]
By (7.6) there exists such that for all (including ) it holds that
[TABLE]
Similarly, by (5.10), for all , there exists such that
[TABLE]
Substituting (8.103) and (8.104) into (8.102) yields, choosing small enough and large enough, the existence of such that for
[TABLE]
Using (4.92b,c) once again upon (8.103) and (8.104) and the above inequality readily verifies (8.84).
We can now conclude.
Proposition 8.9**.**
Let and . Then, there exist , , and , such that for all and satisfying (2.34), it holds that
[TABLE]
The proof follows immediately by combining (8.70), (8.72), and (8.84) for a sufficiently small value of .
9 Semigroup estimates
In this section we prove Theorems 2.15 and 2.16.
9.1 Preliminaries
For , let , , and satisfy
[TABLE]
Recall that by writing for some we have established in (3.1) that
[TABLE]
This gives, for ,
[TABLE]
To estimate we seek therefore a bound for , for in a suitable region of . We later derive the properties of the semi-group from these resolvent estimates.
We seek a bound for the norm of in the domain in for some . Recall that depends on through the periodicity condition appearing in the definition of its domain. As in Section 3 we can rewrite (3.11), which provides an bound for to the following estimate
[TABLE]
where,
[TABLE]
in which .
9.2 Proof of Theorem 2.15
9.2.1 estimates
Estimation of .
We begin by showing that for any , and , there exist , and , such that, for all and
[TABLE]
Let then
[TABLE]
By (7.1) we have that for sufficiently small there exists and such that
[TABLE]
for all .
On the other hand, it follows from (8.71) in a similar manner that for any there exist , , and , such that for all we have
[TABLE]
As a result, for all and such that (implying that ) it holds that
[TABLE]
Combining the above with (9.6) for yields that for any there exists , , and such that for all and satisfying and , we have
[TABLE]
We now observe that
[TABLE]
Hence we obtain that for any there exist , , and such that for all , satisfying it holds that
[TABLE]
In conclusion, we have established the following
Proposition 9.1**.**
For any there exist and , such that for all positive and for which , , and satisfying (2.34), it holds that
[TABLE]
9.2.2 Estimation of .
Proof of (2.35)
Let and be as in the statement of Proposition 9.1. We can now combine (9.2), (9.3), and (9.10), to obtain for all
[TABLE]
We now establish a bound on for . To this end we first recall Lemma 2.11 to obtain
[TABLE]
Using (2.14) with replaced by (note that, by Lemma 2.9 ) we obtain
[TABLE]
which implies
[TABLE]
Since by (2.13) we have
[TABLE]
we may use the resolvent-semigroup relation to obtain that
[TABLE]
We may therefore conclude that
[TABLE]
Consequently,
[TABLE]
To estimate the resolvent for satisfying , we introduce and use the resolvent identity, composed on the left by ,
[TABLE]
to obtain, with the aid of Lemma 2.11, that
[TABLE]
Using (9.11) and (9.15) we then obtain that for each there exist , , and such that for all , satisfying
[TABLE]
We can now use [27, Proposition 2.1] (cf. also [26, Proposition 13.31] or [45, Theorem 11.3.5]), which we repeat here for the benefit of the reader
Proposition 9.2**.**
Let be a strongly continuous semigroup, defined on a Hilbert space , which satisfies for some and ,
[TABLE]
Let denote the generator of . Suppose further that for some
[TABLE]
Then,
[TABLE]
By Remark 1.4 in [27] (or Remark 11.3.4 in [45]), we may conclude that
[TABLE]
Note that since is bounded by (9.19), we can obtain the above from its analyticity and the Phragmèn-Lindelöf Theorem. We now apply the proposition with . By (2.13) it follows that (9.18) holds for and . By (9.17) and (9.21), (9.19) holds for with .
Consequently by (9.20) , we obtain that for any , there exist , , and such that for all and satisfying we have
[TABLE]
This completes the proof of (2.35).
Remark 9.3**.**
Note that while (9.16) allows for an estimate in of , it contributes an additional factor to the coefficient of the exponent in (2.35). If we manage to obtain estimates for in the additional factor could be avoided. In fact, in [15], the initial conditions are assumed to be in , resulting in improved estimates for the semigroup.
Proof of Part 2.
The proof of part 2 is obtained in the same manner. We begin by replacing Proposition 9.1 by the following result
Proposition 9.4**.**
Let . For any there exist , , and such that for all positive and for which , and satisfying it holds that
[TABLE]
Proof.
We use (7.23) which gives
[TABLE]
Combining the above with (9.8) yields
[TABLE]
which together with (9.4) yields (9.22).
The proof of (2.36) proceeds from here in the same manner as in Part 1.
9.3 Proof of Theorem 2.16
Since the proof is similar to the proof of Theorem 2.15 we address here only it main ingredients.
Proof of Part 1
For the first part of the theorem we use (8.70) and (8.105) to establish that for any there exist , and such that for all positive and satisfying and we have
[TABLE]
This is similar to (9.9) in the case .
Combining (9.24) with (9.4) we may conclude that
Proposition 9.5**.**
For any there exist and , such that for all positive and for which , , and satisfying (2.34), it holds that
[TABLE]
We may now proceed as in the proof of (2.35) to establish (2.38).
Proof of Part 2
To establish (2.39) in Part 2 we use (8.21) and (8.70) to show that
[TABLE]
Then we can continue in the same manner as in the proof of (2.36) in the first part of the theorem.
Acknowledgments: Y. Almog was partially supported by NSF grant DMS-1613471. Both authors would like to thank Pierre Bolley and Nader Masmoudi for for some fruitful discussions with B. Helffer.
Appendix A Basic properties of the Airy function and Wasow’s results on
A.1 Airy function properties
In this subsection, we summarize some of the basic properties of Airy function , and the generalized Airy function , that are being used throughout this work (see [1] for details) and establish some new inequalities satisfied by these functions. We recall that Airy function is the unique solution of
[TABLE]
on the line such that tends to [math] as and Standard ODE theory shows that Airy function is entire and strictly decreasing on , but has an infinite number of zeros in .
Airy function satisfies different asymptotic expansions as depending on . We bring two of them here
[TABLE]
Moreover the estimate is, for any , uniform when in (A.1a) or in (A.1b) . In particular, is rapidly decreasing at if belongs to a sector , with .
The following moment estimates are needed in Subsection 6.1.
Proposition A.1**.**
Let . For every there exists such that, for any with , we have,
[TABLE]
and
[TABLE]
Proof.
If then, by (A.1a), all the estimates of the proposition are satisfied for some . Hence, we can consider from now on the case where Note that by interpolation, it is sufficient to consider .
**Proof of (A.2) for .
**Let
[TABLE]
which is well-defined for
[TABLE]
since the denominator can vanish only when .
It can be easily verified that
[TABLE]
Let further
[TABLE]
where is well-defined for as
[TABLE]
Note that for
[TABLE]
implying, for any , the existence of , such that, for all , it holds that
[TABLE]
Substituting into (A.5) yields
[TABLE]
where is associated with the differential operator and is defined on the domain
[TABLE]
It has been established in [25, §5] that, for any , there exist and such that
[TABLE]
In addition, we have
[TABLE]
Denote by the eigenvalues of , and recall that they are located on the ray (see [3, §2.2]). Observing that does not contain any eigenvalue (a consequence of the fact that ) and combining the above with (A.10)-(A.11) yield the existence of such that
[TABLE]
Hence, for ,
[TABLE]
Using (A.7), we obtain that
[TABLE]
and hence
[TABLE]
By the above, (A.6), and (A.8), we thus have
[TABLE]
To prove (A.2) for , we need to establish yet an upper bound for , for . This is an immediate consequence of (A.1a). We observe indeed that for any , as with . This implies that, for any , there exists such that for and , \arg\Big{(}\lambda\exp{\frac{2i\pi}{3}}\Big{)}\in(-\frac{5\pi}{6}-\epsilon,\frac{\pi}{6}+\epsilon).
Consequently, for any , there exists a constant , such that for all
[TABLE]
Together with (A.15), (A.16) yields (A.2) for and .
**Proof of (A.2) for .
**We begin by deriving an estimate of . To this end we observe that
[TABLE]
Following the same procedure applied in the previous proof, we need an estimate of . To achieve this end, we first observe that
[TABLE]
which leads to the estimate
[TABLE]
Implementing (A.13) and (A.14) leads to
[TABLE]
We observe in addition that
[TABLE]
Proceeding as in the proof of (A.2) for , we obtain (A.2) for .
**Proof of for .
**In this case the approximation of by is unsatisfactory. To improve it, in light of (A.9), we solve in the problem
[TABLE]
We look for in the form which means that must satisfy
[TABLE]
We search for a polynomial solution. A simple computation leads to
[TABLE]
We now write
[TABLE]
to obtain
[TABLE]
In order to prove (A.2) () we observe first that
[TABLE]
Hence, it remains necessary to obtain an estimate of in . Here we use the fact that (A.9) is similar to (A.21), the only difference being that the right-hand-side is given by instead of . Note that is much smaller than as .
By (A.12), (A.21) and (A.22) (for ), we then have
[TABLE]
which is significantly smaller than the bound provided by (A.14) for . We continue as in the case . We first use the identity
[TABLE]
to conclude with the aid of (A.21), (A.22), (A.23), and recalling that ,
[TABLE]
Then we write
[TABLE]
Combining (A.24), (A.21), and (A.12) yields
[TABLE]
From (A.26) and (A.23) we get in addition
[TABLE]
Next, we write
[TABLE]
to conclude from (A.25) and (A.26) that
[TABLE]
Upon writing
[TABLE]
we use (A.28), (A.21), and (A.12) to obtain
[TABLE]
which can be used, together with (A.20) and (A.6) to obtain (A.2) for .
In a similar manner we obtain the estimates for . We note in particular that
[TABLE]
and hence, by Sobolev embeddings,
[TABLE]
Combining the above with (A.6) and (A.20) yields, for ,
[TABLE]
**Weighted estimates.
** Recall that in deriving (A.2) we needed to establish that, for , it holds that
[TABLE]
By interpolation it is enough to treat the case when is an integer. Then we use Hölder inequality and (A.31) for and to obtain, for ,
[TABLE]
We then recover (A.3) by using (A.16).
A.2 Definition of and the locus of its zeroes.
Let be given (see (6.9)) by the holomorphic extension to of
[TABLE]
To use the results of Wasow [47] (see [47, Eq. (39)]) and justify this holomorphic extension we observe the following relation
Lemma A.2**.**
[TABLE]
where is the holomorphic extension of the real function
[TABLE]
It has been proved by Wasow in [47, Section 3] that the zeroes of are all located in the sector .
Proposition A.3**.**
The zeroes of belongs to . Moreover has no real zeroes.
Sketch of the proof.
To establish that result is a combination of the argument principle and Rouché’s. The change of is estimated along the path where, for some
[TABLE]
Since is real and positive for it follows that does not change along . Along one uses (A.1), with a bound on the remainder. Finally, to estimate along one uses the power series of , for , and (A.1) for . The tails of the ensuing power series of and are Leibniz series with terms of alternating sign and decreasing moduli. Thus, one may truncate the series into finite sums, and the remainders can be easily estimated. Once the above procedure is applied, one can establish that and hence that along . Since , the first statement of the proposition follows.
The second statement is proved in [47, p. 199].
Corollary A.4**.**
Let . Then, .
We continue with the following result stated in [47] (Eq. (35)) which allows us to obtain additional information on the location of the zeroes of . It is also serves as a useful tool in some of the proofs in Subsection 6.1.
Lemma A.5**.**
Let . For any there exists and such that for all in the sector it holds that
[TABLE]
The proof is a rather standard application of the method of steepest descent method [38, Chapter 4] and is therefore being skipped.
A.3 Asymptotic of the zeroes
In Subsection 6.1 we also need to establish the following lemma about the asymptotic behavior of the zeroes of . A similar statement for is made in [47, § 3] without a clear proof.
Proposition A.6**.**
Let denote the set of points satisfying . Then, for any , is finite and its cardinality tends to as tends to . In particular is non empty. Moreover, for any , there exists such that, for ,
[TABLE]
Proof.
We apply Jensen’s formula [35, Theorem 1.7] to .
[TABLE]
In the above is the Nevanlinna counting function,
[TABLE]
where we have used the fact that all zeroes of are simple. We recall from [47] that none of them is real, and all the zeroes of lie on the negative real axis. Note that if then for all . Recall from the definition that and hence if we show that the first term on the right-hand-side of (A.37) is unbounded as , we may conclude the first statement of the proposition.
It follows from (A.35) that for any there exist and such that for all we have
[TABLE]
Indeed, using Lemma A.5, we eastablish the existence for any of and such that, for all ,
[TABLE]
To estimate the integral for we write, owing to the concavity of ,
[TABLE]
Since by (A.34) we have, for any and ,
[TABLE]
where is fixed, but sufficiently large so that obeys (A.1b) for all . For the first term on the right-hand side there exists such that
[TABLE]
For the second term we use (A.1b) to obtain the rather crude estimate for
[TABLE]
Consequently, for every there exists , such that, for all ,
[TABLE]
This implies, by (A.39), the existence, for any , of , such that for
[TABLE]
Combining the above with (A.38) yields, by fixing small enough, the existence of and such that for all
[TABLE]
The proof shows that the above bound holds true for any for large enough. Hence, we get a lower bound for which implies the first statement of the proposition.
To prove (A.36) we notice that for any , it holds by (A.35) that there exists such that cannot have any zeroes, for in the sector . We then observe that
We can now immediately draw the following conclusion.
Corollary A.7**.**
[TABLE]
A.4 Normalized Airy functions
We complete the appendix with some corollaries of (A.2)-(A.3) and (A.35) needed in Subsection 6.1 and with other estimates needed in Subsection 6.3.
Proposition A.8**.**
Let be defined by
[TABLE]
Then, for any there exists such that for all
[TABLE]
Proof.
Let (the proof for follows by continuity as the denominator is bounded away from zero). As we obtain from (A.35) that there exists such that for any and
[TABLE]
which combined with (A.2) and (A.3) yields (A.43a,b), and with the aid of (A.1) gives (A.43d) . The proof of (A.43c) follows from (A.30).
We also need, in Subsection 6.3 the following estimate
Lemma A.9**.**
Let and, for , where
[TABLE]
Let be defined by (6.48c). There exists such that, for all ,
[TABLE]
Proof.
Let be determined later.
The case .
Let satisfy
[TABLE]
By the continuity of on , we have
[TABLE]
In the case we write, as in Subsection 6.3 (see (6.64)),
[TABLE]
and deduce (see (6.65)) that, for , we have
[TABLE]
We may now use the fact that to get the existence of and such that, for , and we have
[TABLE]
For , we use the continuity of to get a uniform lower bound for it. Consequently, we obtain that
[TABLE]
The case .
If we may use (6.68) which reads
[TABLE]
to obtain for large enough with the aid of (A.1), (A.33), and (A.35) that,
[TABLE]
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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