Random Hamiltonians with Arbitrary Point Interactions
David Damanik (Rice University), Jake Fillman (Texas State, University), Mark Helman (Rice University), Jacob Kesten (Rice University),, Selim Sukhtaiev (Rice University)

TL;DR
This paper studies disordered Hamiltonians with random singular point interactions, establishing a dichotomy between purely absolutely continuous spectrum and localization, including Anderson localization for Bernoulli-type potentials.
Contribution
It introduces a general framework for Hamiltonians with arbitrary singular point interactions and proves a spectral localization dichotomy under minimal assumptions.
Findings
Spectral and dynamical localization can occur in these models.
Purely absolutely continuous spectrum is also possible in the same setting.
Anderson localization is established for Bernoulli-type singular potentials.
Abstract
We consider disordered Hamiltonians given by the Laplace operator subject to arbitrary random self-adjoint singular perturbations supported on random discrete subsets of the real line. Under minimal assumptions on the type of disorder, we prove the following dichotomy: Either every realization of the random operator has purely absolutely continuous spectrum or spectral and exponential dynamical localization hold. In particular, we establish Anderson localization for Schr\"odinger operators with Bernoulli-type random singular potential and singular density.
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Taxonomy
TopicsSpectral Theory in Mathematical Physics · Numerical methods in inverse problems · Quantum chaos and dynamical systems
Random Hamiltonians with Arbitrary Point Interactions
David Damanik
Department of Mathematics, Rice University, Houston, TX 77005, USA
,
Jake Fillman
Department of Mathematics, Texas State University, San Marcos, TX 78666, USA
,
Mark Helman
Department of Mathematics, Rice University, Houston, TX 77005, USA
,
Jacob Kesten
Department of Mathematics, Rice University, Houston, TX 77005, USA
and
Selim Sukhtaiev
Department of Mathematics, Rice University, Houston, TX 77005, USA
Abstract.
We consider disordered Hamiltonians given by the Laplace operator subject to arbitrary random self-adjoint singular perturbations supported on random discrete subsets of the real line. Under minimal assumptions on the type of disorder, we prove the following dichotomy: Either every realization of the random operator has purely absolutely continuous spectrum or spectral and exponential dynamical localization hold. In particular, we establish Anderson localization for Schrödinger operators with Bernoulli-type random singular potential and singular density.
Key words and phrases:
Anderson localization, Laplace operator
D. D. was supported in part by NSF grant DMS–1700131 and by an Alexander von Humboldt Foundation research award.
S.S. was supported in part by an AMS-Simons travel grant, 2017-2019
Contents
1. Introduction
1.1. Overview
The spectral theory of Schrödinger operators with singular potentials, originally motivated by the Kronig–Penney model from solid state physics, has been of interest since at least 1961 when Berezin and Faddeev [4] gave a mathematically rigorous treatment of , where is a real parameter and denotes a Dirac delta distribution. An illuminating discussion of this subject together with historical remarks and relevant references can be found in the classical monograph [2].
The main focus of this paper is on Anderson localization for random Hamiltonians with arbitrary point interactions under minimal assumptions on the randomness. The first relevant work in this direction is due to Delyon, Simon, and Souillard [11]. They established spectral localization for , where is a sequence of independent identically distributed random variables whose common distribution has a sufficiently regular nontrivial absolutely continuous part. More recently, Hislop, Kirsch, and Krishna [16], [17] proved Anderson localization (in suitable energy regions) and studied eigenvalue statistics for the same model in dimensions . Localization and zero-measure spectrum for closely related quantum graph models were established in [9, 10].
The principal achievement of this paper is twofold. First, we cover arbitrary (as discussed in [22, Section 3.4]) self-adjoint second order differential operators with coefficients supported on a discrete set . Similar to the Kronig–Penney model, these operators are realized via self-adjoint vertex conditions imposed at every . Second, we make no assumptions on the regularity of the common probability distribution of i.i.d. random variables in question, contrary to all previously considered Kronig–Penney type random models. Such a level of generality is essential in several random quantum graph models where the random variables take integer values representing geometric characteristics of graphs, e.g., the number of edges, cf. [10].
The main ingredient of the proof is the fact that the Lyapunov exponent is positive away from a discrete set of exceptional energies, which we establish in Theorem 2.2. It is worth noting that the underlying one-step transfer matrix takes a rather general form given by a product of the monodromy matrix of the free Hamiltonian and an arbitrary matrix, see (2.3). The latter describes the general self-adjoint vertex condition mentioned above, which takes the form
[TABLE]
Having established positivity of Lyapunov exponents, we proceed with the proof of localization following [5] and its continuum versions [6, 10]; see Theorem 3.1.
1.2. Main result
To begin, we discuss self-adjoint realizations of the Laplace operator subject to singular perturbations supported on a uniformly discrete set of vertices
[TABLE]
Let be the operator acting in and given by
[TABLE]
where denotes the direct sum of Sobolev spaces. This operator is symmetric and has infinite deficiency indices. Its adjoint is given by
[TABLE]
see [2, Section III.2.1]. All self-adjoint extensions of (automatically satisfying ) can be described by means of vertex conditions imposed at every . Define
[TABLE]
Then by [1, Theorem 1] (see also [3, 8, 22, 23]) the operator is a self-adjoint extension of if and only if there exists a sequence
[TABLE]
such that
[TABLE]
The main goal of this paper is to show that a random choice of vertex conditions (1.9), (1.10) leads to Anderson localization unless the vertex matrices are drawn in such a way that the resulting Hamiltonians are all unitarily equivalent to an operator with periodic coefficients, in which case the resultant operators all have purely absolutely continuous spectrum.
The location of vertices supplies another source of randomness in our model. We assume that the distance between and is random. To facilitate this, for a sequence , we denote and
[TABLE]
Hypothesis 1.1**.**
Fix . Suppose that is a bounded set. Let be an arbitrary probability measure on and let .
For a sequence
[TABLE]
let denote the self-adjoint extension of corresponding to the discrete set of vertices given by (1.11) and the boundary conditions (1.10).
Theorem 1.2**.**
Assume Hypothesis 1.1. (i) Suppose that there exist
[TABLE]
such one of the following holds
- •
**
- •
**
- •
.
Then possesses a basis of exponentially decaying eigenfunctions for -almost every . Furthermore, there exist a set with and a discrete set such that for every compact interval , every and every compact set ,
[TABLE]
where denotes the spectral projection corresponding to , and denotes the operator of multiplication by the function .
(ii)* If the assumptions of part (i) are not satisfied then has purely absolutely continuous spectrum for every .*
Remark 1.3*.*
- (1)
Part (ii) of Theorem 1.2 follows from general arguments. For example, if every satisfies , for some , then all realizations of will be unitarily equivalent to the free Laplacian, and hence will exhibit purely absolutely continuous spectrum. Similarly, if there exist and such that all elements of are of the form for some , then every realization of will be unitarily equivalent to an operator with periodic point interactions and again the desired localization fails.
In particular, we want to point out that Part (i) is optimal in the sense that any amount of randomness that pushes one outside the periodic case will produce spectral and dynamical localization. 2. (2)
In the third case of Theorem 1.2.(i) (that is, when ), decouples into an infinite direct sum of operators on finite intervals (-almost surely). These operators have compact resolvents by general arguments, so the associated spectra are pure point with compactly supported (hence exponentially decaying) eigenfunctions. Moreover, in this case one has .
Let us point out that this result yields localization for several physically relevant Hamiltonians. Let be a sequence of independent identically distributed random variables taking at least two distinct values in a bounded subset of . Define and introduce formally self-adjoint differential expressions
[TABLE]
As was shown in [22] these differential expressions may be realized as self-adjoint extensions of corresponding to (i.e. ) and the following vertex matrices
[TABLE]
The first and the second cases satisfy the assumptions of Theorem 1.2 part (i), the third case satisfies the assumptions of Theorem 1.2 part (ii). Hence, the first two operators exhibit Anderson localization, while the third operator has purely absolutely continuous spectrum.
Another relevant application is to Anderson localization for the Kirchhoff Laplacian on random radial trees discussed in [10], [18]. In this case the Hamiltonian is determined by the following matrices,
[TABLE]
where , are sequences of i.i.d. random variables taking at least two distinct values in a bounded subset of . Anderson localization for this model was proved in [10] and also follows from Theorem 1.2.
2. Ergodic Setup and Positive Lyapunov Exponents
In this section we assume Hypothesis 1.1 with the additional restriction
[TABLE]
We will explain in the beginning of Section 3 that it is enough to prove Theorem 1.2 assuming (2.1).
2.1. Ergodic Setup
Let us discuss the eigenvalue problem , where is a self-adjoint extension of corresponding to a fixed set of vertices (1.2) and vertex conditions (1.10) with satisfying
[TABLE]
Consider the differential equation subject to , and vertex conditions (1.1). The solution satisfies
[TABLE]
where the mapping 111By (2.1) the second component of all elements of is . Consequently, slightly abusing notation, we may view as a function of two variables . is defined by
[TABLE]
We note that the entries of are well-defined analytic functions of .
Define by . Let denote the left shift acting on and define the skew product
[TABLE]
We denote the -step transfer matrix by
[TABLE]
and note that the iterates over the skew product are given by . One has
[TABLE]
whenever satisfies and the vertex conditions from (1.1) corresponding to . The Lyapunov exponent is defined by
[TABLE]
By Kingman’s Subadditive Ergodic Theorem we have
[TABLE]
for -almost every , where . Let us point out that there is also a natural continuum cocycle which satisfies
[TABLE]
in the event that solves and satisfies the vertex conditions corresponding to . By a simple application of Birkhoff’s ergodic theorem, the Lyapunov exponent for this cocycle is related to that of the discrete cocycle via
[TABLE]
where denotes the -expected value of the length.
2.2. Positivity of Lyapunov Exponents
Hypothesis 2.1**.**
Assume Hypothesis 1.1 with
[TABLE]
Suppose that there exist , such that
[TABLE]
[TABLE]
The main assertion of this subsection is that the Lyapunov exponent is positive away from a discrete set of exceptional energies.
Theorem 2.2**.**
Assume Hypothesis 2.1. Then there is a discrete set with the property that for every .
To begin, we address the key technical fact that will be utilized in the proof of Theorem 2.2. Given , , and , define
[TABLE]
to be the commutator of the two matrices , . In view of [6], the key obstruction to positive exponents away from a discrete set of energies is everywhere vanishing of .
Theorem 2.3**.**
Given , one has for all if and only if at least one of the following statements is true:
[TABLE]
The following lemma will be helpful in the proof of Theorem 2.3.
Lemma 2.4**.**
If with and
[TABLE]
then either or (and ). In particular, if (2.12) holds true, then
[TABLE]
Proof.
Since is an almost-periodic function of , if (2.12) holds, then vanishes identically. To see this, note that if for some and is a -almost period of , then for all .
Thus, we assume and that . Since , we arrive at
[TABLE]
Since , this yields , hence . Interchanging the roles of and implies as well. Since , this forces and hence as well. ∎
With Lemma 2.4 in hand, we prove Theorem 2.3.
Proof of Theorem 2.3.
Given , , , , and , introduce , and define the matrices
[TABLE]
and
[TABLE]
Consider the matrix given by
[TABLE]
For brevity, we introduce
[TABLE]
for the parameter space; given , we abuse notation a bit and write for . Since , the Iwasawa decomposition (see, e.g. [21]) implies there exist , , and such that and , and hence . It is enough to assume the representation and prove that one of
[TABLE]
holds.
If either (2.16) or (2.17) holds, then a straightforward calculation reveals that . Conversely, assume that ; in particular, .
Case 1**.**
. In this case, we denote .
Case 1.1**.**
.
Since , after making the substitutions and , we obtain
[TABLE]
where
[TABLE]
Since the set of functions is linearly independent over , we have , and thus we arrive at
[TABLE]
From (2.20), we obtain , which implies , since . Plugging this into (2.18) and (2.19), we have that and . Subtracting these two equations gives . Since , we obtain that , and hence since . Plugging these relations into (2.21) and using , we obtain
[TABLE]
implying . Thus, we have shown that , as desired.
Case 1.2**.**
Exactly one vanishes.
Without loss of generality, assume and ; in particular and . Since the assumption , implies and , we aim to show that is impossible in this case. Using the same substitutions as before, we get
[TABLE]
where
[TABLE]
Since is clearly impossible, we see that cannot vanish identically in this case.
Case 1.3**.**
.
Substituting , we get
[TABLE]
where and . Thus, if , we obtain , implying and as before.
Case 2**.**
**
Case 2.1**.**
.
Substituting , we have
[TABLE]
where
[TABLE]
Since and are bounded functions, (2.22) implies . Applying Lemma 2.4 and recalling that , we must have , , and hence . Thus, appealing to boundedness of as before and using (2.22) again, we arrive at . Since , this implies
[TABLE]
so (since both are positive). Since and vanish identically, appealing to (2.22) one more time gives us . Consequently,
[TABLE]
From Lemma 2.4 (using again), we have .
At this point, we have , , . Substituting all of this into the relation , we see that the expression vanishes for all , which contradicts .
Case 2.2**.**
Exactly one vanishes.
Substituting and , we get
[TABLE]
where
[TABLE]
As before, if vanishes identically, then, since the functions and are bounded, we get , hence vanishes identically (by Lemma 2.4), a contradiction.
Case 2.3**.**
.
Substituting , we get
[TABLE]
where
[TABLE]
As before, is a bounded function, so . Arguing as in previous cases, we have and . Consquently, , so Lemma 2.4 yields .
Substituting , , and into , we arrive at
[TABLE]
Since , we must have . Therefore , which implies , just like we wanted. ∎
We are now in a position to prove the Theorem 2.2.
Proof of Theorem 2.2.
It is enough to check the conditions of [6, Theorem 2.1] with and . First, both functions are real analytic, are non-constant, and whenever . Then we need to show that for some one has
[TABLE]
By Assumption (2.8), neither (2.16) nor (2.17) holds and hence Theorem 2.3 implies the desired result. ∎
3. Proof of Theorem 1.2
First, we note that the boundary conditions corresponding to the elements of decouple the operator and hence lead to localization for somewhat trivial reasons. Specifically, assume that the sequence in (1.9) contains a subsequence
[TABLE]
Then
[TABLE]
where the operator is given by
[TABLE]
Since has compact resolvent, the operator possesses a basis of compactly supported (hence, exponentially decaying) eigenfunctions and has pure point spectrum.
By Remark 1.3 (ii) it is enough to prove Theorem 1.2 (i) assuming (2.1), that is, and in (1.6). This is accomplished in the following theorem.
Theorem 3.1**.**
Assume Hypothesis 2.1 and recall from Theorem 2.2. Then there exists a set with such that for every compact interval and every the following assertions hold:
- (i)
For every generalized eigenvalue222A generalized eigenvalue is an energy admitting a linearly bounded solution, that is, a solution, , satisfying (3.15).* of the operator , one has*
[TABLE] 2. (ii)
The spectral subspace admits a basis of exponentially decaying eigenfunctions. 3. (iii)
Given and a normalized eigenfunction
[TABLE]
there exist , , such that
[TABLE] 4. (iv)
For every and every compact set one has
[TABLE]
Proof.
Our argument closely follows the proof of [10, Theorem 3.11] which in turn stems from that of [5, Theorem 1.2]. Throughout the the rest of the proof, denotes with some constant depending only on and .
*Proof of Part *(i). As was discussed in [10, Section 3.3], Theorem 2.1 yields a Large Deviation Theorem, [5, Theorem 3.1], which in turn implies the following two facts:
For every , there exists a full-measure set with the following property: For every , there is such that
[TABLE]
for all , , and , see [5, Proposition 5.2].
For every , there exists a full measure set such that for every , there is such that
[TABLE]
for any and , see [5, Corollary 5.3]. In particular, this yields
[TABLE]
Our objective is to show that
[TABLE]
To that end, we first note a version of [10, Theorem 3.10]333The proof of this fact for the model in question is almost identical to that of [10, Theorem 3.10]. concerning the elimination of double resonances. Denote the Neumann restriction of to by 444cf. (LABEL:2.13) with , . For and , define
[TABLE]
and ; then one has Define the full measure set
[TABLE]
where
[TABLE]
Fix and a generalized eigenvalue . Then in order to establish (3.11) it is enough to check
[TABLE]
Now, let denote a generalized eigenfunction corresponding to the generalized eigenvalue and the operator . That is,
[TABLE]
We now follow the blueprint of [10]. Given , the primary goal is to show that
[TABLE]
for all sufficiently large . The intervals so described cover a half-line, and hence (3.16) implies (3.14).
Given , define555In the arguments that follow, will correspond to the center of localization.
[TABLE]
where will be determined later666Specifically, will depend solely on , so, if all generalized eigenfunctions are bounded, then may be chosen independently of ., and are as discussed near (3.8) and (3.9) (respectively), and is the minimal integer such that
[TABLE]
Step 1**.**
There exists such that for all , there exist integers such that
[TABLE]
for
Proof.
Using (3.8) with and we get
[TABLE]
for some . Thus,
[TABLE]
Likewise, using (3.8) with , we obtain (3.21) for some . Fixing such an , we introduce and via
[TABLE]
We will show that this choice of gives (3.19) with . The proof for relies on (3.21) with and is completely analogous. Our argument is based on a representation of in terms of its boundary values , and special solutions satisfying specific boundary conditions chosen based on which entry of the matrix
[TABLE]
dominates its norm.
Thus, there are four cases; we will consider one case and note that the other cases are completely similar. The reader may also consult [10] to see what modifications one should make in the other three cases.
To that end, let denote the entry of (3.23), and suppose . In this case, we choose to satisfy the interior vertex conditions as well as the boundary conditions
[TABLE]
and observe that
[TABLE]
By (3.25), and are linearly independent, so we may write
[TABLE]
Next, we estimate the right-hand side of (3.26). Putting together (3.21) and (3.25), we obtain
[TABLE]
Next, (3.15) implies
[TABLE]
Next, apply (3.9) with and , and select so that to get
[TABLE]
Similarly, for sufficiently large, we get
[TABLE]
Putting together (3.26), (3.27), (3.29), and (3.30), we have
[TABLE]
where the final inequality holds for sufficiently large. Similarly,
[TABLE]
follows by replacing (respectively, ) by (respectively, ) in (3.26), and by in both (3.29) and (3.30). ∎
Step 2**.**
If for some , let be the largest integer for which . If for some , let be the largest integer for which . Let be as in Step 1. Then
[TABLE]
Proof.
There exists a -independent interval such that
[TABLE]
Suppose that satisfies in , the interior vertex conditions in the interval and
[TABLE]
Then one has
[TABLE]
Integrating over , using (3.34) and (3.19) we infer
[TABLE]
Thus, without loss we may assume
[TABLE]
Since , we have
[TABLE]
for a suitable -independent constant which is sufficiently small. Combining the previous two inequalities we get
[TABLE]
Let denote the Green function of , then
[TABLE]
Denoting
[TABLE]
we get
[TABLE]
for sufficiently large in (3.17). ∎
Step 3**.**
Choose as in the previous step. For a suitable , we have
[TABLE]
for every and every .
Proof.
[TABLE]
This input suffices to apply the Avalanche Principle [15] to deduce (3.44). Consult [5, (6.17)–(6.18)] for details. ∎
Since the intervals in Step 3 cover a half-line, (3.14) and (3.4) follow immediately.
Proof of Part (ii). By Part (i) and Osceledets’ Theorem, every generalized eigenvalue of is an eigenvalue whose corresponding eigenfunctions decay exponentially at the rate dictated by the Lyapunov exponent.
Next, we note that
[TABLE]
Indeed, assume that , . Then by Sobolev inequalities (see, e.g, [7, Corollary 4.2.10], [19, IV.1.2]) we get
[TABLE]
Therefore [18, Assumption B.1] is satisfied and by [18, Theorem B.9] the spectral measure of is supported by the generalized eigenvalues. Thus the eigenfunctions corresponding to generalized eigenvalues in span the spectral subspace .
Proof of Part (iii). First, using and the one-dimensional Sobolev inequalities (see, e.g, [7, Corollary 4.2.10], [19, IV.1.2]), we have
[TABLE]
and
[TABLE]
Therefore, after taking
[TABLE]
we may repeat the arguments from Part (i). We pick any value of with desired property and note that its existence is guaranteed because
[TABLE]
So, given , we may choose (independent of ) so that
[TABLE]
for all and all . Our next objective is to show that
[TABLE]
for all and . As before, the proof relies on a representation of in terms of its boundary values at and , and the choice of representation, depends on which entry of
[TABLE]
dominates its norm. We will argue under the assumption that the upper left entry dominates the norm; the other three cases are almost identical.
Choose as follows: they satisfy the interior vertex conditions in , solve , and satisfy the boundary conditions
[TABLE]
Notice that
[TABLE]
One has
[TABLE]
where . In order to estimate , we rewrite it in terms of the transfer matrices and use (3.9) as follows
[TABLE]
Similarly one can estimate . Put this together with (LABEL:464n)–(3.57) to obtain
[TABLE]
In the final inequality, pick sufficiently small (which only depends on ). Thus
[TABLE]
for all and . So, for sufficiently large , the inequality in (3.60) holds for all
[TABLE]
Trivially estimating for (that is, using ) we obtain
[TABLE]
Using the representation
[TABLE]
we may prove a version of (3.62) with replaced by by repeating (3.56)–(3.62). Lastly, we infer (3.6) for all by interpolation. The same argument applies to the negative half-axis.
Proof of Part (iv). The argument is essentially identical to the proof of [10, Theorem 1.1], which in turn stems from [14], with natural substitution of one-sided intervals by their symmetric two-sided versions. ∎
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