An approximate version of Jackson's conjecture
Anita Liebenau, Yanitsa Pehova

TL;DR
This paper proves an approximate version of Jackson's conjecture, demonstrating that dense regular bipartite digraphs contain nearly a full set of edge-disjoint Hamilton cycles, extending understanding of Hamiltonian decompositions.
Contribution
It establishes that for sufficiently large dense bipartite digraphs, a near-complete Hamilton cycle decomposition exists, advancing the theory of Hamiltonian decompositions in directed graphs.
Findings
Dense bipartite digraphs contain almost all edges in Hamilton cycles.
The result applies to sufficiently large regular bipartite digraphs.
Nearly all edges can be covered by edge-disjoint Hamilton cycles.
Abstract
In 1981 Jackson showed that the diregular bipartite tournament (a complete bipartite graph whose edges are oriented so that every vertex has the same in- and outdegree) contains a Hamilton cycle, and conjectured that in fact the edge set of it can be partitioned into Hamilton cycles. We prove an approximate version of this conjecture: For every and there exists such that every -regular bipartite digraph on vertices contains edge-disjoint Hamilton cycles.
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An approximate version of Jackson’s conjecture
Anita Liebenau School of Mathematics and Statistics, UNSW Sydney, NSW 2052, Australia. Email: [email protected]. Supported by the Australian research council (ARC), DE170100789 and DP180103684.
Yanitsa Pehova Mathematics Institute, University of Warwick, Coventry CV4 7AL, UK. Email: [email protected]. This work has received funding from the European Research Council (ERC) under the European Union’s Horizon 2020 research and innovation programme (grant agreement No 648509). This publication reflects only its authors’ view; the European Research Council Executive Agency is not responsible for any use that may be made of the information it contains.
Abstract
A diregular bipartite tournament is a balanced complete bipartite graph whose edges are oriented so that every vertex has the same in- and outdegree. In 1981 Jackson showed that a diregular bipartite tournament contains a Hamilton cycle, and conjectured that in fact the edge set of it can be partitioned into Hamilton cycles. We prove an approximate version of this conjecture: for every there exists such that every diregular bipartite tournament on vertices contains a collection of cycles of length at least . Increasing the degree by a small proportion allows us to prove the existence of many Hamilton cycles: for every and there exists such that every -regular bipartite digraph on vertices contains edge-disjoint Hamilton cycles.
1 Introduction
Finding sufficient conditions for a graph to contain a Hamilton cycle, i.e. a cycle that contains every vertex of , is one of the classical problems in graph theory. Dirac’s theorem [6] states that every graph on vertices with minimum degree at least contains a Hamilton cycle. Later, Ore [21] showed that it is enough if every pair of non-adjacent vertices has the sum of their degrees totaling at least . A natural extension to the existence of one Hamilton cycle is then the existence of many edge-disjoint Hamilton cycles, or even of a decomposition into Hamilton cycles, i.e. a partition of the edges of a graph into Hamilton cycles. Clearly, if such a decomposition exists, say into Hamilton cycles, then the graph must be -regular. A construction by Walecki (see, e.g., [2, 11]) shows that the complete graph admits such a decomposition for every . More generally, the complete -partite graph on vertices admits a decomposition into Hamilton cycles whenever is even; and into Hamilton cycles and a perfect matching if is odd [10, 18]. Some further graph classes have been shown to admit Hamilton decompositions, we refer the reader to the survey article by Alspach, Bermond and Sotteau [3].
Nash-Williams [4] extended Dirac’s theorem by showing that every -vertex graph with minimum degree at least contains at least edge-disjoint Hamilton cycles, and conjectured that the minimum degree condition is sufficient to prove the existence of edge-disjoint Hamilton cycles. Babai (see [19]) provided a construction showing that this is false. However, Csaba, Kühn, Lo, Osthus and Treglown [5] proved that regular graphs satisfying the above minimum degree condition can be decomposed into Hamilton cycles and at most one perfect matching.
These problems naturally extend to the setting of oriented graphs that are obtained from simple graphs by endowing every edge with an orientation. We write for the (oriented) edge between the pair oriented from to . A Hamilton cycle in an oriented graph is an ordering of the vertices of such that for all the edge is present (where ). The outdegree of a vertex in an oriented graph , denoted by , is the number of edges , and the indegree of a vertex in an oriented graph , denoted by , is the number of edges . We suppress the subscript if the graph is clear from context. We set , , and . We refer to the latter one as the minimum semidegree of (the maximum semidegree is defined analogously).
Keevash, Kühn and Osthus [14] show that for large enough, every oriented graph on vertices with minimum semidegree at least contains a Hamilton cycle. A construction due to Häggkvist [12] shows that this is best possible. Kühn and Osthus [16] prove that every -regular oriented graph on vertices has a Hamilton cycle decomposition for every , where is a constant and is large enough. In particular, this establishes Kelly’s conjecture which states that every regular tournament has a Hamilton cycle decomposition. The result in [16] builds on earlier work by Kühn, Osthus and Treglown [15] which includes a first approximate version of Kelly’s conjecture.
How many disjoint Hamilton cycles can one guarantee when the (oriented) graph is not regular? As the union of disjoint Hamilton cycles forms a regular spanning subgraph, the maximal for which contains an -regular spanning subgraph is an upper bound for this quantity. Ferber, Long and Sudakov [7] show that this upper bound is asymptotically correct for oriented graphs of large enough minimum semidegree.
Theorem 1.1** (Ferber, Long, Sudakov [7]).**
Let , and let be sufficiently large. Let be an oriented graph on vertices with . Then contains edge-disjoint Hamilton cycles, where is the maximum integer such that contains an -regular spanning subgraph.
In this paper, we consider the corresponding degree conditions for regular bipartite oriented graphs. An obvious necessary condition for a bipartite (oriented) graph to contain a Hamilton cycle is that both parts of the bipartition have equal size, in which case the graph is called balanced. Note that the minimum semidegree of a bipartite oriented graph can be at most , where denotes the number of vertices of . Graphs that attain this bound satisfy , and are necessarily balanced and -regular. Such graphs are called diregular bipartite tournaments. Jackson [13] showed that diregular bipartite tournaments are Hamiltonian, and he conjectured the following.
Conjecture 1.2** (Jackson [13]).**
Every diregular bipartite tournament is decomposable into Hamilton cycles.
In this paper we adjust the methods of [7] to the bipartite setting and prove the following relaxation of Jackson’s conjecture. A directed graph (or digraph, for short) consists of a set of vertices and a set of ordered pairs of , called directed edges (or just edges). That is, directed graphs may contain edges and for two vertices , but no loops and no multiple edges. The notions of Hamilton cycles, minimum semidegree, etc., introduced earlier for oriented graphs generalise in the natural way to directed graphs.
Theorem 1.3**.**
Let , , and let be sufficiently large. Then every -regular bipartite digraph on vertices contains at least edge-disjoint Hamilton cycles.
To the best of our knowledge no other intermediate results towards Conjecture 1.2 are known. Our result constitutes an approximate version of Conjecture 1.2 in the following sense. Let be a diregular bipartite tournament and add in- and out-neighbours to every vertex (this can be realised by adding an edge-disjoint -regular spanning subgraph using Hall’s theorem on the complement). We obtain an almost decomposition of the resulting graph into Hamilton cycles. Of course, none of these Hamilton cycles need to be cycles of the original bipartite tournament. For bipartite oriented graphs we prove the following.
Theorem 1.4**.**
Let , , and let be sufficiently large. Then every -regular bipartite oriented graph on vertices contains at least edge-disjoint cycles of length at least
In particular, we can almost decompose the edge set of every bipartite regular tournament into almost spanning cycles.
We note that the constants and in Theorems 1.3 and 1.4 are optimal for such statements. Indeed, a -regular digraph may be disconnected if , as may be a -regular oriented graph if
2 Preliminaries
In this section we introduce notation and present lemmas that we later use in the proof of our main result.
All graphs and digraphs are finite and simple, that is, they do not contain loops or double edges (in the case of graphs) or double oriented edges (in the case of digraphs). Let be a graph or a digraph. We denote by the vertex set of and by the edge set of . For subsets we write for the set of edges if is a graph, and the set of directed edges if is a digraph. Let denote the graph or digraph induced on . When is a graph let denote the set of vertices such that for some . When is digraph, we denote by () the set of vertices such that ( for some . When we also write (and in the digraph case), , , and for the above sets, where the latter three we call the neighbourhood, the in-neighbourhood, and the out-neighbourhood of , respectively. The sizes of these sets are denoted by , , , , , . We also write for when is a graph, and and when is a digraph. Throughout the paper, expressions of the form are used as short-hand for ” and ”, and all other uses of carry the analogous meaning. We omit the subscript when there is no danger of ambiguity.
We say a graph or digraph has bipartition if where and are disjoint and all edges have one endpoint in and one in . A digraph is a balanced bipartite digraph if it has a bipartition such that .
For a graph or digraph with bipartition and a subset we write and for and , respectively.
For real numbers we write if . For two functions and we write if as . We omit floor and ceiling signs for clarity of presentation.
We need the following standard concentration result for binomial random variables (see [1, Theorem A.1.1]).
Lemma 2.1** (Chernoff’s inequality).**
Let be a binomial random variable with parameters , and let . Then
[TABLE]
Remark 2.2*.*
Let be a hypergeometric random variable with parameters , that is, given an underlying set of size and a subset of size , where is a subset of of size chosen uniformly at random. The same inequality as in Lemma 2.1 holds for , where now For details see [8, Section 21.5]).
The following provides a sufficient minimum semidegree condition for a digraph to contain a Hamilton cycle.
Theorem 2.3** (Ghouila-Houri [9]).**
Every strongly connected digraph on vertices with contains a Hamilton cycle. In particular, if , then contains a Hamilton cycle.
Let denote the complete bipartite balanced digraph in which both vertex classes have size and every vertex has in- and outdegree . A result by Ng [20] implies that the edge set of can be decomposed into Hamilton cycles. We use this to prove the following.
Lemma 2.4**.**
There exists such that for all the complete bipartite digraph contains disjoint Hamilton paths starting in the same vertex class of the bipartition. Moreover, every vertex of is an endpoint of at most of these paths.
Proof.
Let and denote the vertex classes of . It follows from Ng [20] that there is a decomposition of into Hamilton cycles, say . For every choose an edge of with uniformly at random among all such edges, all choices being independent. Denote their union by . We claim that with positive probability is at most .
Fix a vertex . Then for each vertex , the edge is in with probability . Moreover, the events are independent since for any two distinct vertices the edges and are in different cycles of the decomposition. Therefore, the out-degree of in has a binomial distribution with parameters and . Similarly, the in-degree of in has a binomial distribution with parameters and for every . Therefore, the probability that there exists with or with is at most , by Chernoff’s inequality (Lemma 2.1) and the union bound. It follows that with positive probability has maximum semidegree at most . The claim follows by taking , as the collection of Hamilton paths. By the choice of ’s all these paths start in . ∎
Finally, we use the following from [7].
Lemma 2.5** (Lemma 24 in [7]).**
Let and with sufficiently large and . Suppose that is a bipartite graph with and . Then contains a collection of edge-disjoint matchings, each of which has size at least , and whose union has minimum degree at least .
Remark 2.6*.*
Note that practically the same assertion holds when , up to an additive constant of 1 which we neglect due to the asymptotic nature of the statement. To see this, apply the lemma to the graph obtained by adding an auxiliary vertex to and edges between and .
3 Proof of Theorems 1.3 and 1.4
In this section we prove our main theorems. The two proofs are very similar and we treat them together for a large part of this section. We state lemmas along the way that we either prove in the appendix (Lemma 3.1) or at the end of the section (Lemmas 3.2, 3.3 and 3.4). We introduce some notation specific to the proof.
A path cover of size of a directed graph is a set of directed paths in such that every vertex is contained in exactly one path of . Every digraph contains a trivial path cover in which every path consists of exactly one vertex of , whereas a Hamilton path, if existent, is a path cover of size one. We call two path covers and edge-disjoint if any two paths and are edge-disjoint. Given a set of path covers of a digraph , we denote by the graph whose edge set is formed by taking the union of all sets , for all paths , for all path covers .
Let where we may assume for the proof that is sufficiently small. Let be a sufficiently large integer. Let and assume that is a balanced -regular bipartite digraph on vertices.
The next lemma asserts that we can split into roughly spanning subgraphs, each with good degree conditions into certain subsets.
Lemma 3.1**.**
Let be constants, let be sufficiently large. Let be a -regular bipartite digraph with bipartition such that , where . Then for there are edge-disjoint spanning subdigraphs of with the following properties.
- (P1)
For each there is a partition with ; 2. (P2)
For some and all , the induced subgraph satisfies
[TABLE] 3. (P3)
For all and all we have that ; 4. (P4)
Each induced subgraph has minimum semidegree at least .
The proof of the lemma is a straight-forward adaptation of Lemma 27 in [7] to the bipartite setting. We include it in the appendix for completeness.
We now claim that each as given by the previous lemma has many edge-disjoint path covers. Precisely, we prove the following.
Lemma 3.2**.**
There exists a positive integer , such that for and the following is true. Let be a balanced bipartite digraph on vertices such that for every vertex of . Then contains a collection of at least edge-disjoint path covers, each of size at most . Moreover, .
In the proofs of Theorems 1.3 and 1.4, respectively, we will apply Lemma 3.2 to each . The strategy is then to connect the paths of each path cover in to a Hamilton cycle (Theorem 1.3) or to a long cycle (Theorem 1.4) using the vertices in in such a way that the cycles corresponding to distinct path covers are edge disjoint. We make this precise using the following two lemmas. A subset of the vertices of a bipartite digraph with bipartition is called balanced if .
Lemma 3.3**.**
Let , and let be positive integers such that, . Let be a balanced bipartite digraph on vertices such that . Then, given a balanced set of distinct vertices with respect to a balanced bipartition of , there exists a path cover of such that each path starts at and ends at .
Lemma 3.4**.**
Let , and let be positive integers such that, . Let be a balanced bipartite oriented graph on vertices such that . Then, given a set of distinct vertices , there exists a collection of pairwise vertex disjoint paths of such that each path starts at and ends at .
We are ready to prove our main theorems.
Proof of Theorem 1.3.
Let , where we may assume for the proof that is sufficiently small. Let be a sufficiently large integer. Let and assume that is a balanced -regular bipartite digraph on vertices. Let and let be the subdigraphs given by Lemma 3.1 satisfying the properties (P1)–(P4).
For each we apply Lemma 3.2 with and given by (P2). Note that and is balanced so that the assumptions of Lemma 3.2 are satisfied for . Therefore, for every , we obtain a collection of at least edge-disjoint path covers of , each of size at most , and such that
[TABLE]
Now fix and let be path covers of as above. We iteratively find edge-disjoint Hamilton cycles in such that consists exactly of the edges in , for all . In other words, the paths in are connected to a cycle via edges in . For suppose that we have obtained such edge disjoint Hamilton cycles . Let be the graph obtained from by removing the edges of those cycles. Let be the pairs of start and end points of the paths in , and note that . We now greedily pick pairwise distinct vertices such that
[TABLE]
We verify briefly that this is indeed possible. For a vertex we have that , by (P3) and since An edge in (or , respectively) is removed from only if is the endpoint (or startpoint, respectively) of a path in (and in this case, at most one edge is removed from ). Since by (1), it follows that every is the start (or end) point of at most paths in . Thus,
[TABLE]
at each step, and we can indeed pick greedily in such that (2) holds.
We verify that , together with the set satisfies the assumptions of Lemma 3.3. Note that . Furthermore, the path cover has size at most , hence Now, by (P4) and since the only edges incident to vertices in that were removed from are those belonging to the Hamilton cycles . This implies that for some , since , is small enough, and . Finally, the set of vertices is balanced because the set of endpoints of paths in is also balanced.
Therefore, by Lemma 3.3, contains a path cover such that is an --path for . These paths, together with the paths in and the edges in (2) form a Hamilton cycle in that is edge-disjoint from and from the paths in .
Thus, after iterations, we obtain the desired edge-disjoint Hamilton cycles of . Treating all subgraphs in parallel (recall that they were edge-disjoint), we obtain edge-disjoint Hamilton cycles of . ∎
Proof of Theorem 1.4.
The proof is similar to the proof of Theorem 1.3 and so we merely sketch it and point out the differences.
Let , where we may assume for the proof that is sufficiently small. Let be a sufficiently large integer. Let and assume that is a balanced -regular bipartite oriented graph on vertices. Obviously, an oriented graph is a digraph, and so Lemmas 3.1 and 3.2 apply to this case just as above. Thus we obtain oriented subgraphs satisfying the properties (P1)–(P4) as in the previous proof. Furthermore, for every , we obtain a collection of at least edge-disjoint path covers of , each of size at most , and such that (1) holds.
Now fix and let be of those path covers of We iteratively find edge-disjoint cycles in such that consists exactly of the edges in , for all . That is, again, the paths in are connected to a cycle via edges in . For suppose that we have obtained such edge disjoint cycles . Let be the graph obtained from by removing the edges of those cycles. The argument why we can greedily pick pairwise distinct vertices satisfying (2) only differs in the constant factor in the lower bound , but the rest of the argument is essentially the same.
Similarly, we obtain analogously to above that for some .
Now instead of Lemma 3.3 we use Lemma 3.4 to find a collection of pairwise vertex disjoint paths in such that is an --path for . These paths, together with the paths in and the edges in (2) form a cycle in that is edge-disjoint from and from the paths in . Since covers all the vertices of this implies that the length of is at least The rest is analogous to the proof above. ∎
It remains to prove Lemmas 3.1, 3.2, 3.3, and 3.4. As noted earlier, we move the proof of Lemma 3.1 to the appendix due to its similarity with its counterpart in [7].
Proof of Lemma 3.2.
Let be a bipartition of such that , and let . Let and be partitions of and respectively, chosen independently and uniformly at random among all partitions such that for all . For a fixed and a fixed vertex , the random variable has a hypergeometric distribution with parameters . Therefore, the probability that is at most , by Remark 2.2 and since by assumption. A similar concentration argument applies to as well as to for every vertex and . It follows by the union bound that with probability at least we have that
[TABLE]
Fix partitions of and that satisfy (3) and (4).
Let denote a bipartition of the complete bipartite digraph , where the elements of the two sets are labelled and . Then contains edge-disjoint Hamilton paths, say , all of which have their start vertex in , and such that no vertex in is the endpoint of more than of these paths, by Lemma 2.4.
Let and let be the corresponding bipartite subgraphs of having edge sets
[TABLE]
respectively (recall that denotes the set of all edges of a digraph that are oriented from to ).
For each , we apply Lemma 2.5 to the digraph (and keep Remark 2.6 in mind in case and , say, differ by 1). Note that the assumptions are satisfied with slack for and , by (3) and (4). We conclude that contains at least
[TABLE]
edge-disjoint matchings, each of size at least . Moreover, every vertex in (or , respectively) is contained in at least
[TABLE]
of these matchings.
Note that, for each , all edges of are oriented from to if is odd, and from to if is even. Therefore, we may pick an arbitrary such matching from for every and concatenate those matchings to form a path cover of .
Then contains at least edges and so it must be of size at most , since each of the vertices of is in exactly one of the paths of .
Iteratively picking distinct matchings for each , we obtain such path covers for . We do the same for all Hamilton paths of Denote the union of all path covers obtained this way by , and note that contains at least path covers since is large enough. Since the paths are pairwise edge-disjoint it follows that the path covers in are pairwise edge-disjoint.
It remains to show that the graph has minimum semidegree at least . As noted above, for every bipartite graph of , , every vertex in is in at least matchings. That is, every such has at least in the graph formed by the union of those matchings. The same lower bound holds for every path and every that is not in the vertex class of the endpoint of . Since a particular is the “endpoint” of at most of the paths we get that for all
[TABLE]
in the graph formed by the union of all path covers. A similar argument applies to in , which finishes the proof the lemma. ∎
Proof of Lemma 3.3.
Let be a bipartition of such that . Choose a partition of uniformly at random from all partitions that satisfy
- (a)
for all , 2. (b)
for all , 3. (c)
.
To see that such a partition exists let , let be the set of indices such that , let be the set of indices such that , and let Since is balanced, which we denote by . Let , and assume first that is an integer. Let be a partition of such that if , if , and similarly, if , if . Note that this is possible by choice of and since . Then the partition is a partition as desired if we let for all . In this case the bound in is even 1. When is not an integer then a similar construction works (some occurrences of replaced by and some by ), in which case the set sizes may differ by 2.
Fix and . Note that has a hypergeometric distribution with parameters , where and . Therefore, for all the probability that is at most , since and by Remark 2.2. A similar bound holds for . Taking the union bound we deduce that with probability
[TABLE]
where , satisfies , and we use that .
Fix a partition that satisfies (5). We claim that this is sufficient to find a Hamilton --path in , for every . The following implies this already when , (or vice versa), when, by c, we have .
Claim 3.5**.**
Let be a non-negative integer and let be a bipartite digraph such that . Let , . If then contains a Hamilton path from to .
Proof of claim.
Let and , and let be the (undirected) bipartite graph with vertex set and edge set .
We claim that contains a perfect matching. Note that for all and for all . Let now be non-empty and assume that . Since every vertex in has at least neighbours in it follows that . Moreover, the set is non-empty, so for any vertex we have . This, however, implies that , a contradiction. Thus, for all , which implies that contains a perfect matching, by Hall’s Theorem.
Let denote the corresponding matching of directed edges in such that and for all , and let and . Consider now the following auxiliary digraph on vertex set . For each pair let be an edge of if is an edge of . Note that satisfies . Therefore, contains a Hamilton cycle, say with edge set , by Theorem 2.3. Now, this Hamilton cycle corresponds to a Hamilton path from to in which can be obtained by replacing each edge in by the edges and (the latter only if ) in . ∎
Clearly this implies that every has a Hamilton --path in the case when and , or vice versa. Assume now that both and are on the same side of the bipartition, say without loss of generality in . In that case by c. The balanced bipartite digraph satisfies the assumptions of the claim and thus contains a Hamilton path from to for any out-neighbour of . Adding the edge to that path yields a Hamilton path from to in , as required. ∎
Proof of Lemma 3.4.
Let be a bipartition of such that . Similarly to the proof of Lemma 3.3 we choose a partition of uniformly at random from all partitions that satisfy
- (a)
for all , 2. (b)
for all , 3. (c)
Analogously to (5) we deduce that with probability
[TABLE]
where Fix a partition such that (6) is satisfied. We now find an --path in using the following.
Claim 3.6**.**
Let be a balanced bipartite oriented graph on vertices. Assume that the minimum semidegree of satisfies . Then is strongly connected.
Proof.
Let be an arbitrary vertex in and let be the set of vertices such that there is a --path in . We first show that .
Suppose not. Let . Then as all out-neighbours of all are elements of , by definition. Since is bipartite, so is . Let be some bipartition of . By the minimum degree assumption, the set has size greater than , and so there is a vertex in of in-degree greater than . As the in- and out-neighbours of are distinct elements of (since is an oriented graph) we obtain that
[TABLE]
Counting the edges in gives analogously that
[TABLE]
Combining the two inequalities implies that
[TABLE]
where the last step follows from the AM-GM inequality.
Analogously one can show that the set of vertices such that there is a --path in has size greater than . Since this is true for any , it follows that for any two vertices and of , the sets and intersect, that is, there is a path from to . ∎
This finishes the proof of the lemma since all graphs are balanced bipartite oriented graphs and satisfy the degree condition (6). ∎
4 Conclusion
In this paper we prove that for every every -regular bipartite digraph on vertices admits an almost decomposition of its edge set into Hamilton cycles, as long as is large enough. We also prove that for every every -regular bipartite oriented graph on vertices admits an almost decomposition of its edge set into nearly Hamilton cycles, as long as is large enough. This gives a first approximate version of Conjecture 1.2. The following two would each constitute a strengthening towards Conjecture 1.2.
Conjecture 4.1**.**
Let and let be sufficiently large. Then every -regular bipartite digraph on vertices has a Hamilton cycle decomposition.
Note that this is a bipartite analogue of [16, Theorem 1.4]: a digraph on vertices with minimum semidegree for has a Hamilton decomposition, provided that .
Conjecture 4.2**.**
Let , let be sufficiently large, and let be an integer. Then every -regular bipartite oriented graph on vertices contains at least edge-disjoint Hamilton cycles.
The condition would be best possible since the oriented graph may be disconnected otherwise. Furthermore, the assumption of being regular is necessary for such a statement. To see this consider, for example, a blow up of a with slightly uneven vertex classes. This oriented graph has minimum semidegree slightly below , yet fails to be Hamiltonian.
A further direction for exploration may be multi-partite tournaments. Let a regular -partite tournament be a regular orientation of the complete -partite graph with equal size vertex classes. In [16], Kühn and Osthus not only prove Kelly’s conjecture, but more generally, that every sufficiently large regular digraph on vertices whose degree is linear in and which is a robust outexpander contains a Hamilton cycle decomposition. In [17, Section 1.6] they then argue that, for , every sufficiently large -partite tournament is a robust outexpander, and thus, has a Hamilton cycle decomposition. The approach via robust outexpanders does not cover the bipartite nor the tripartite case. Yet it is conjectured in [17], additionally to Jackson’s conjecture, that every regular tripartite tournament has a Hamilton cycle decomposition.
A possible approximate version of the conjecture for tripartite tournaments could be the following.
Conjecture 4.3**.**
Let , and let be sufficiently large. Let be a -regular tripartite digraph with vertex classes each of size . Then contains at least edge-disjoint Hamilton cycles.
Parts of our arguments do work for such an approximate version. The equivalent of Claim 3.5, however, does not seem to easily transfer. In fact, assuming just a lower bound of roughly on the minimum semidegree of a balanced tripartite digraph on vertices does not necessarily imply that the graph is Hamiltonian.
Acknowledgement. The authors would like to thank Asaf Ferber for helpful discussions during the early stages of this project. Furthermore, we would like to thank the referee for many helpful comments that improved the paper. In particular we are grateful for suggesting to add a version of Theorem 1.4.
Appendix A Proof of 3.1
Select at random equipartitions of and equipartitions of , each into sets: for each let be the partition of and let be the partition of . Note that all parts of all partitions have size either or , and for each index and each vertex (respectively ) there exists a unique index such that (respectively ). Denote by the union of and .
Consider the following random sets. For , , let be the set of vertices such that for some and some . Further, let be the set of vertices such that both and are in the same set for some . In other words, if we colour the edges of all induced subgraphs in colour (allowing multiple colours), is the set of all vertices such that the edge (or , respectively) received colour and at least one other colour, and is the set of vertices such that the edge (or , respectively) received at least one colour. Set and where we note that is independent of since all degrees in are equal and since the partitions were chosen uniformly. We claim that all of the following properties hold with high probability:
- (a)
For all and all sets : ; 2. (b)
for all and : 3. (c)
for all ,
For Property (a) note that for fixed , , and , both and are hypergeometric random variables, each with parameters . Hence, it follows that (a) holds with probability at least , by Remark 2.2 and the union bound.
For fixed and , the random variable is dominated by a binomial random variable with parameters . Thus and (b) follows from a straightforward application of Chernoff’s inequality (Lemma 2.1).
For Property (c) fix a vertex and note that
[TABLE]
For every and every , the probability that is . Thus, the probability that such a vertex is in is . It follows that . For each , let be a random subset of , where every is an element of with probability , all choices being independent. Let and let be the event that for all . Then the random variable is binomially distributed with parameters , and thus, Furthermore, the random variable has the same distribution as conditioned on . Hence,
[TABLE]
for all . Now, each has a binomial distribution with mean , thus is maximised when . Thus, by independence,
[TABLE]
Hence, we deduce from (7) that
[TABLE]
by Chernoff’s inequality (Lemma 2.1). If then the expression on the right hand side is of order , where we use that . The same inequality holds for all vertices , so (c) follows by taking the union bound over all .
Now fix partitions of , and partitions of , such that (a), (b) and (c) are satisfied.
Let be the digraph consisting of all edges of which are not contained in any . It follows directly from (c) that
[TABLE]
for every .
Relabel the sets as and define the digraphs on vertex sets to be the edges of that are not in for any . Finally, let .
Property of the lemma statement is trivially satisfied by definition. Furthermore, for every and every we have that
[TABLE]
by (a) and (b). Hence, Property follows since and
It remains to choose edge sets , and such that properties and are satisfied. For a vertex , let denote the set of indices such that , and note that by construction . Furthermore, for an edge we have by definition of . Define random edge sets and as follows. For every edge , add to exactly one of with the following probabilities. For each
- •
add to with probability if ;
- •
add to with probability if ,
choices being independent for distinct edges. Note that the probabilities indeed add up to 1. Now for all and all ,
[TABLE]
and
[TABLE]
Hence by (8), Chernoff’s inequality (Lemma 2.1) and the union bound, with probability at least we have that for all and all , for some suitable . Similarly we obtain that with probability at least , we have that for all and all ,
[TABLE]
by (a), Chernoff’s inequality 2.1, the union bound, and where we use in the last inequality that and .
Finally, fix choices of and that satisfy and for all and all , and set .
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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