Harmonic measure and quantitative connectivity: geometric characterization of the $L^p$-solvability of the Dirichlet problem
Jonas Azzam, Steve Hofmann, Jos\'e Mar\'ia Martell, Mihalis, Mourgoglou, Xavier Tolsa

TL;DR
This paper provides a geometric characterization of the conditions under which harmonic measure is absolutely continuous with respect to surface measure, linking it to the solvability of the $L^p$ Dirichlet problem for domains with Ahlfors-David regular boundaries.
Contribution
It offers a geometric criterion for the weak-$A_ Infty$ property of harmonic measure, connecting it to $L^p$ solvability of the Dirichlet problem under natural geometric conditions.
Findings
Characterizes weak-$A_ Infty$ property geometrically.
Establishes equivalence between harmonic measure properties and $L^p$ solvability.
Provides counterexamples showing sharpness of conditions.
Abstract
It is well-known that quantitative, scale invariant absolute continuity (more precisely, the weak- property) of harmonic measure with respect to surface measure, on the boundary of an open set with Ahlfors-David regular boundary, is equivalent to the solvability of the Dirichlet problem in , with data in for some . In this paper, we give a geometric characterization of the weak- property, of harmonic measure, and hence of solvability of the Dirichlet problem for some finite . This characterization is obtained under background hypotheses (an interior corkscrew condition, along with Ahlfors-David regularity of the boundary) that are natural, and in a certain sense optimal: we provide counter-examples in the absence of either of them (or even one of the two, upper or lower, Ahlfors-David…
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Harmonic measure and quantitative connectivity: geometric characterization of the -solvability of the Dirichlet problem
Jonas Azzam
Jonas Azzam
School of Mathematics
University of Edinburgh
JCMB, Kings Buildings
Mayfield Road, Edinburgh, EH9 3JZ, Scotland
,
Steve Hofmann
Steve Hofmann
Department of Mathematics
University of Missouri
Columbia, MO 65211, USA
,
José María Martell
José María Martell
Instituto de Ciencias Matemáticas CSIC-UAM-UC3M-UCM
Consejo Superior de Investigaciones Científicas
C/ Nicolás Cabrera, 13-15
E-28049 Madrid, Spain
,
Mihalis Mourgoglou
Mihalis Mourgoglou
Departamento de Matemáticas, Universidad del País Vasco, Barrio Sarriena s/n 48940 Leioa, Spain and
Ikerbasque, Basque Foundation for Science, Bilbao, Spain
and
Xavier Tolsa
Xavier Tolsa
ICREA, Passeig Lluís Companys 23 08010 Barcelona, Catalonia, and
Departament de Matemàtiques and BGSMath
Universitat Autònoma de Barcelona
08193 Bellaterra (Barcelona), Catalonia
(Date: July 4, 2019. Revised: )
Abstract.
It is well-known that quantitative, scale invariant absolute continuity (more precisely, the weak- property) of harmonic measure with respect to surface measure, on the boundary of an open set with Ahlfors-David regular boundary, is equivalent to the solvability of the Dirichlet problem in , with data in for some . In this paper, we give a geometric characterization of the weak- property, of harmonic measure, and hence of solvability of the Dirichlet problem for some finite . This characterization is obtained under background hypotheses (an interior corkscrew condition, along with Ahlfors-David regularity of the boundary) that are natural, and in a certain sense optimal: we provide counter-examples in the absence of either of them (or even one of the two, upper or lower, Ahlfors-David bounds); moreover, the examples show that the upper and lower Ahlfors-David bounds are each quantitatively sharp.
Key words and phrases:
Harmonic measure, Poisson kernel, uniform rectifiability, weak local John condition, big pieces of Chord-arc domains, Carleson measures.
2000 Mathematics Subject Classification:
31B05, 35J25, 42B25, 42B37
S.H. was supported by NSF grant DMS-1664047. J.M.M. acknowledges financial support from the Spanish Ministry of Economy and Competitiveness, through the “Severo Ochoa” Programme for Centres of Excellence in R&D (SEV-2015- 0554). He also acknowledges that the research leading to these results has received funding from the European Research Council under the European Union’s Seventh Framework Programme (FP7/2007-2013)/ ERC agreement no. 615112 HAPDEGMT. In addition, S.H. and J.M.M. were supported by NSF Grant DMS-1440140 while in residence at the MSRI in Berkeley, California, during Spring semester 2017. M.M. was supported by IKERBASQUE and partially supported by the grant MTM-2017-82160-C2-2-P of the Ministerio de Economía y Competitividad (Spain), and by IT-641-13 (Basque Government). X.T. was supported by the ERC grant 320501 of the European Research Council (FP7/2007-2013) and partially supported by MTM-2016-77635-P, MDM-2014-044 (MICINN, Spain), 2017-SGR-395 (Catalonia), and by Marie Curie ITN MAnET (FP7-607647).
Contents
- 1 Introduction
- 2 Notation and definitions
- 3 Preliminaries for the Proof of Theorem 1.5
- 4 Step 1: the set-up
- 5 Some geometric observations
- 6 Construction of chord-arc subdomains
- 7 Step 2: Proof of
- 8 Step 3: bootstrapping
- 9 Preliminaries for the Proof of Theorem 1.6
- 10 The Main Lemma for the proof of Theorem 1.6
- 11 The Alt-Caffarelli-Friedman formula and the existence of short paths
- 12 Types of cubes
- 13 The corona decomposition and the Key Lemma
- 14 The geometric lemma
- 15 Proof of the Key Lemma
- 16 Proof of the Main Lemma 10.2
- A Some counter-examples
1. Introduction
A classical criterion of Wiener characterizes the domains in which one can solve the Dirichlet problem for Laplace’s equation with continuous boundary data, and with continuity of the solution up to the boundary. In this paper, we address the analogous issue in the case of singular data. To be more precise, the present work provides a purely geometric characterization of the open sets for which solvability holds, for some , and with non-tangential convergence to the data a.e., thus allowing for singular boundary data. We establish this characterization in the presence of background hypotheses (an interior corkscrew condition [see Definition 2.5 below], and Ahlfors-David regularity of the boundary [Definition 2.1]) that are in the nature of best possible, in the sense that there are counter-examples in the absence of either of them (or of even one of the two, upper or lower, Ahlfors-David bounds); moreover, the examples show that the upper and lower Ahlfors-David bounds are each quantitatively sharp (see the discussion following Theorem 1.5, as well as Appendix A, for more details.
Solvability of the Dirichlet problem is fundamentally tied to quantitative absolute continuity of harmonic measure with respect to surface measure on the boundary: indeed, it is equivalent to the so-called “weak-” property of the harmonic measure (see Definition 2.16). It is through this connection to quantitative absolute continuity of harmonic measure that we shall obtain our geometric characterization of solvability.
The study of the relationship between the geometry of a domain, and absolute continuity properties of its harmonic measure, has a long history. A classical result of F. and M. Riesz [RR] states that for a simply connected domain in the complex plane, rectifiability of implies that harmonic measure for is absolutely continuous with respect to arclength measure on the boundary. A quantitative version of this theorem was later proved by Lavrentiev [Lav]. More generally, if only a portion of the boundary is rectifiable, Bishop and Jones [BJ] have shown that harmonic measure is absolutely continuous with respect to arclength on that portion. They also present a counter-example to show that the result of [RR] may fail in the absence of some connectivity hypothesis (e.g., simple connectedness).
In dimensions greater than 2, a fundamental result of Dahlberg [Dah] establishes a quantitative version of absolute continuity, namely that harmonic measure belongs to the class in an appropriate local sense (see Definitions 2.16 and 2.20 below), with respect to surface measure on the boundary of a Lipschitz domain.
The result of Dahlberg was extended to the class of Chord-arc domains (see Definition 2.8) by David and Jerison [DJ], and independently by Semmes [Sem]. The Chord-arc hypothesis was weakened to that of a two-sided corkscrew condition (Definition 2.5) by Bennewitz and Lewis [BL], who then drew the conclusion that harmonic measure is weak- (in an appropriate local sense, see Definitions 2.16 and 2.20) with respect to surface measure on the boundary; the latter condition is similar to the condition, but without the doubling property, and is the best conclusion that can be obtained under the weakened geometric conditions considered in [BL]. We note that weak- is still a quantitative, scale invariant version of absolute continuity.
More recently, one of us (Azzam) has given in [Azz] a geometric characterization of the property of harmonic measure with respect to surface measure for domains with -dimensional Ahlfors-David regular (-ADR) boundary (see Definition 2.1). Azzam’s results are related to those of the present paper, so let us describe them in a bit more detail. Specifically, he shows that for a domain with -ADR boundary, harmonic measure is in with respect to surface measure, if and only if 1) is uniformly rectifiable (-UR)111This is a quantitative, scale-invariant version of rectifiability, see Definition 2.3 and the ensuing comments., and 2) is semi-uniform in the sense of Aikawa and Hirata [AH]. The semi-uniform condition is a connectivity condition which states that for some uniform constant , every pair of points and may be connected by a rectifiable curve , with , with length , and which satisfies the “cigar path” condition
[TABLE]
Semi-uniformity is a weak version of the well known uniform condition, whose definition is similar, except that it applies to all pairs of points . For example, the unit disk centered at the origin, with the slit removed, is semi-uniform, but not uniform. It was shown in [AH] that for a domain satisfying a John condition and the Capacity Density Condition (in particular, for a domain with an -ADR boundary), semi-uniformity characterizes the doubling property of harmonic measure. The method of [Azz] is, broadly speaking, related to that of [DJ], and of [BL]. In [DJ], the authors show that a Chord-arc domain may be approximated in a “Big Pieces” sense (see [DJ] or [BL] for a precise statement; also cf. Definition 2.13 below) by Lipschitz subdomains ; this fact allows one to reduce matters to the result of Dahlberg via the maximum principle (a method which, to the present authors’ knowledge, first appears in [JK] in the context of domains). The same strategy, i.e., Big Piece approximation by Lipschitz subdomains, is employed in [BL]. Similarly, in [Azz], matters are reduced to the result of [DJ], by showing that for a domain with an -ADR boundary, is semi-uniform with a uniformly rectifiable boundary if and only if it has “Very Big Pieces” of Chord-arc subdomains (see [Azz] for a precise statement of the latter condition). As mentioned above, the converse direction is also treated in [Azz]. In that case, given an interior corkscrew condition (which holds automatically in the presence of the doubling property of harmonic measure), and provided that is -ADR, the (or even weak-) property of harmonic measure was already known to imply uniform rectifiability of the boundary [HM3] (although the published version appears in [HLMN]; see also [MT] for an alternative proof, and a somewhat more general result); as in [AH], semi-uniformity follows from the doubling property, although in [Azz], the author manages to show this while dispensing with the John domain background assumption (given a harmlessly strengthened version of the doubling property).
Thus, in [Azz], the connectivity condition (semi-uniformity), is tied to the doubling property of harmonic measure, and not to absolute continuity. On the other hand, in light of the example of [BJ], and on account of the aforementioned connection to solvability of the Dirichlet problem, it has been an important open problem to determine the minimal connectivity assumption which, in conjunction with uniform rectifiability of the boundary, yields quantitative absolute continuity of harmonic measure with respect to surface measure. In the present work, we present a connectivity condition, significantly milder than semi-uniformity, which we call the weak local John condition (see Definition 2.13 below), and which solves this problem. Thus, we obtain a geometric characterization of the domains for which one has quantitative absolute continuity of harmonic measure; equivalently, for which one has solvability of the Dirichlet problem with singular () data (see Theorem 1.3 below). In fact, we provide two geometric characterizations of such domains, one in terms of uniform rectifiability combined with the weak local John condition, the other in terms of approximation of the boundary in a big pieces sense, by boundaries of Chord-arc subdomains.
Let us now describe the weak local John condition, which says, roughly speaking, that from each point , there is local non-tangential access to an ample portion of a surface ball at a scale on the order of . Let us make this a bit more precise. A “carrot path” (aka non-tangential path) joining a point , and a point , is a connected rectifiable path , with endpoints and , such that for some and for all ,
[TABLE]
where \ell\big{(}\gamma(y,z)\big{)} denotes the arc-length of the portion of the original path with endpoints and . For , and , set
[TABLE]
We assume that every point may be joined by a carrot path to each in a “Big Piece” of , i.e., to each in a Borel subset , with , where denotes surface measure on , and where the parameters , , and are uniformly controlled. We refer to this condition as a “weak local John condition”, although “weak local semi-uniformity” would be equally appropriate. See Definitions 2.9, 2.11 and 2.13 for more details. We remark that a strong version of the local John condition (i.e., with ) has appeared in [HMT], in connection with boundary Poincaré inequalities for non-smooth domains.
Let us observe that the weak local John condition is strictly weaker than semi-uniformity: for example, the unit disk centered a the origin, with either the cross removed, or with the slit removed, satisfies the weak local John condition, although semi-uniformity fails in each case.
The main result in the present work is the following geometric characterization of quantitative absolute continuity of harmonic measure, and of the solvability of the Dirichlet problem. The terminology used here will be defined in the sequel.
Theorem 1.3**.**
Let , , be an open set satisfying an interior corkscrew condition (see Definition 2.5 below), and suppose that is -dimensional Ahlfors-David regular (-ADR; see Definition 2.1 below). Then the following are equivalent:
- (1)
* is Uniformly Rectifiable (-UR; see Definition 2.3 below) and satisfies the weak local John condition (see Definition 2.13 below).* 2. (2)
* satisfies an Interior Big Pieces of Chord-Arc Domains (IBPCAD) condition (see Definition 2.14 below).* 3. (3)
Harmonic measure is locally in weak-* (see Definition 2.20 below) with respect to surface measure on .* 4. (4)
The Dirichlet problem is solvable for some , i.e., for some , there is a constant such that if , then the solution to the Dirichlet problem with data , is well defined as for each , converges to non-tangentially, and enjoys the estimate
[TABLE]
where is a suitable version of the non-tangential maximal function of .
Some explanatory comments are in order. The proof has two main new ingredients: the implication (1) implies (2), and the fact that the weak- property of harmonic measure implies the weak local John condition (this is the new part of (3) implies (1)). In turn, we split these main new results into two theorems: the first implication is the content of Theorem 1.5 below, and the second is the content of Theorem 1.6. We remark that the interior corkscrew condition is not needed for (1) implies (2) (nor for (2) implies (3) if and only if (4)). Rather, it is crucial for (3) implies (1) (see Appendix A).
As regards the other implications, the fact that (2) implies (3) follows by a well-known argument using the maximum principle and the result of [DJ] and [Sem] for Chord-arc domains222See, e.g., [H, Proposition 13] for the details in this context, but the proof originates in [JK]., along with the criterion for weak- obtained in [BL]; the equivalence of (3) and (4) is well known, and we refer the reader to, e.g., [HLe, Section 4], and to [H] for details. The implication (3) implies (1) has two parts. As mentioned above, the fact that weak- implies weak local John is new, and is the content of Theorem 1.6. The remaining implication, namely that weak- implies -UR, is the main result of [HM3]; an alternative proof, with a more general result, appears in [MT], and see also [HLMN] for the final published version of the results of [HM3], along with an extension to the -harmonic setting.
We note that our background hypotheses (upper and lower -ADR, and interior corkscrew) are in the nature of best possible: one may construct a counter-example in the absence of any one of them, for at least one direction of this chain of implications, as we shall discuss in Appendix A. In addition, in the case of the -ADR condition, given any , the counter-examples for the upper (respectively, lower) -ADR property can be constructed in such a way as to show that no weaker condition of the form (resp., ), with , may be substituted for a true -ADR upper or lower bound. Moreover, the first example shows that one cannot substitute the Capacity Density Condition (CDC)333The CDC is a scale invariant potential theoretic “thickness” condition, i.e., a quantitative version of Weiner regularity; see, e.g., [AH]. in place of the -ADR condition: indeed, the example is an NTA domain, in particular, it satisfies an exterior corkscrew condition, and thus also the CDC.
As regards our assumption of the interior corkscrew condition, we point out that, as is well known, the -ADR condition implies that the open set satisfies a corkscrew condition, with constants depending only on and ADR, i.e., at every scale , and for every point , there is at least one component of containing a corkscrew point relative to the ball . Our last example shows that such a component should lie inside itself, for each and ; i.e., that should enjoy an interior corkscrew condition.
As explained above, the main new contributions of the present work are contained in the following pair of theorems,
Theorem 1.5**.**
Let , , be an open set, not necessarily connected, with an -dimensional Ahlfors-David regular (-ADR) boundary. Then the following are equivalent:
- (i)
* is uniformly rectifiable (-UR), and satisfies the weak local John condition.*
- (ii)
* satisfies an Interior Big Pieces of Chord-Arc Domains (IBPCAD) condition.*
Only the direction (i) implies (ii) is new. For the converse, the fact that IBPCAD implies the weak local John condition is immediate from the definitions. Moreover, the boundary of a Chord-arc domain is -UR, and an -ADR set with big pieces of -UR is also -UR (see [DS2]). As noted above, that (ii) implies the weak- property follows by well known arguments.
Theorem 1.6**.**
Let , , be an open set satisfying an interior corkscrew condition and suppose that is -dimensional Ahlfors-David regular (-ADR). If the harmonic measure for satisfies the weak- condition, then satisfies the weak local John condition.
Let us mention that the present paper is a combination of unpublished work of two different subsets of the present authors: Theorem 1.5 is due to the second and third authors, and was first posted in the draft manuscript [HM5]444An earlier version of this work [HM4] gave a direct proof of the fact that (1) implies (3) in Theorem 1.3, without passing through condition (2).; Theorem 1.6 is due to the first, fourth and fifth authors, and appeared first in the draft manuscript [AMT2].
The paper is organized as follows. In the next section, we set notation and give some definitions. In Part 2 of the paper (Sections 3-8), we give the proof of Theorem 1.5. In Part 8 of the paper (Sections 9-16) we give the proof of Theorem 1.6. Finally, in Appendix A, we discuss some counter-examples which show that our background hypotheses are in the nature of best possible.
We thank the referee for a careful reading of the paper, and for several helpful suggestions that have led us to clarify certain matters, and to make improvements in the presentation.
2. Notation and definitions
Unless otherwise stated, we use the letters to denote harmless positive constants, not necessarily the same at each occurrence, which depend only on dimension and the constants appearing in the hypotheses of the theorems (which we refer to as the “allowable parameters”). We shall also sometimes write , , and to mean, respectively, that , , and , where the constants and are as above, unless explicitly noted to the contrary. In some occasions we will employ the notation , and to emphasize that the previous implicit constants and/or may depend on some relevant parameter . At times, we shall designate by a particular constant whose value will remain unchanged throughout the proof of a given lemma or proposition, but which may have a different value during the proof of a different lemma or proposition.
Our ambient space is , .
will always denote an open set in , not necessarily connected unless otherwise specified.
We use the notation to denote a rectifiable path with endpoints and , and its arc-length will be denoted . Given such a path, if , we use the notation to denote the portion of the original path with endpoints and .
We let , denote the standard unit basis vectors in .
The open -dimensional Euclidean ball of radius will be denoted . For , a surface ball is denoted
Given a Euclidean ball or surface ball , its radius will be denoted or , respectively.
Given a Euclidean or surface ball or , its concentric dilate by a factor of will be denoted or
Given an open set , for , we set .
We let denote -dimensional Hausdorff measure, and let \sigma:=H^{n}\big{\lfloor}_{\,\partial\Omega} denote the surface measure on .
For a Borel set , we let denote the usual indicator function of , i.e. if , and if .
For a Borel set , we let denote the interior of .
Given a Borel measure , and a Borel set , with positive and finite measure, we set .
We shall use the letter (and sometimes ) to denote a closed -dimensional Euclidean dyadic cube with sides parallel to the co-ordinate axes, and we let denote the side length of . If , then we set . Given an -ADR set , we use (or sometimes or ) to denote a dyadic “cube” on . The latter exist (see [DS1], [Chr], [HK]), and enjoy certain properties which we enumerate in Lemma 2.23 below.
Definition 2.1**.**
(-ADR) (aka -Ahlfors-David regular). We say that a set , of Hausdorff dimension , is -ADR if it is closed, and if there is some uniform constant such that
[TABLE]
where may be infinite. Here, is the surface ball of radius , and as above, is the “surface measure” on .
Definition 2.3**.**
(-UR) (aka -uniformly rectifiable). An -ADR (hence closed) set is -UR if and only if it contains “Big Pieces of Lipschitz Images” of (“BPLI”). This means that there are positive constants and , such that for each and each , there is a Lipschitz mapping , with Lipschitz constant no larger than , such that
[TABLE]
We recall that -dimensional rectifiable sets are characterized by the property that they can be covered, up to a set of measure 0, by a countable union of Lipschitz images of ; we observe that BPLI is a quantitative version of this fact.
We remark that, at least among the class of -ADR sets, the -UR sets are precisely those for which all “sufficiently nice” singular integrals are -bounded [DS1]. In fact, for -ADR sets in , the boundedness of certain special singular integral operators (the “Riesz Transforms”), suffices to characterize uniform rectifiability (see [MMV] for the case , and [NTV] in general). We further remark that there exist sets that are -ADR (and that even form the boundary of a domain satisfying interior corkscrew and Harnack Chain conditions), but that are totally non-rectifiable (e.g., see the construction of Garnett’s “4-corners Cantor set” in [DS2, Chapter 1]). Finally, we mention that there are numerous other characterizations of -UR sets (many of which remain valid in higher co-dimensions); cf. [DS1, DS2].
Definition 2.4**.**
(“UR character”). Given an -UR set , its “UR character” is just the pair of constants involved in the definition of uniform rectifiability, along with the ADR constant; or equivalently, the quantitative bounds involved in any particular characterization of uniform rectifiability.
Definition 2.5**.**
(Corkscrew condition). Following [JK], we say that an open set satisfies the corkscrew condition if for some uniform constant and for every surface ball with and , there is a ball . The point is called a corkscrew point relative to We note that we may allow for any fixed , simply by adjusting the constant . In order to emphasize that , we shall sometimes refer to this property as the interior corkscrew condition.
Definition 2.6**.**
(Harnack Chains, and the Harnack Chain condition [JK]). Given two points , and a pair of numbers , an -Harnack Chain connecting to , is a chain of open balls , with and We say that satisfies the Harnack Chain condition if there is a uniform constant such that for any two points , there is an -Harnack Chain connecting them, with depending only on and the ratio |x-x^{\prime}|/\left(\min\big{(}\delta_{\Omega}(x),\delta_{\Omega}(x^{\prime})\big{)}\right).
Definition 2.7**.**
(NTA). Again following [JK], we say that a domain is NTA (Non-tangentially accessible) if it satisfies the Harnack Chain condition, and if both and satisfy the corkscrew condition.
Definition 2.8**.**
(CAD). We say that a connected open set is a CAD (Chord-arc domain), if it is NTA, and if is -ADR.
Definition 2.9**.**
(Carrot path). Let be an open set. Given a point , and a point , we say that a connected rectifiable path , with endpoints and , is a carrot path (more precisely, a -carrot path) connecting to , if , and if for some and for all ,
[TABLE]
With a slight abuse of terminology, we shall sometimes refer to such a path as a -carrot path in , although of course the endpoint lies on .
A carrot path is sometimes referred to as a non-tangential path.
Definition 2.11**.**
(-weak local John point). Let , and for constants , , and , set
[TABLE]
We say that a point is a -weak local John point if there is a Borel set , with , such that for every , there is a -carrot path connecting to .
Thus, a weak local John point is non-tangentially connected to an ample portion of the boundary, locally. We observe that one can always choose smaller, for possibly different values of and , by moving from to a point on a line segment joining to the boundary.
Remark 2.12*.*
We observe that it is a slight abuse of notation to write , since the latter is not centered on , and thus it is not a true surface ball; on the other hand, there are true surface balls, and , centered at a “touching point” with , which, respectively, are contained in, and contain, .
Definition 2.13**.**
(Weak local John condition). We say that satisfies a weak local John condition if there are constants , , and , such that every is a -weak local John point.
Definition 2.14**.**
(IBPCAD). We say that a connected open set has Interior Big Pieces of Chord-Arc Domains (IBPCAD) if there exist positive constants and , and , such that for every , with , there is a Chord-arc domain satisfying
- •
.
- •
.
- •
.
- •
.
- •
The Chord-arc constants of the domains are uniform in .
Remark 2.15*.*
In the presence of an interior corkscrew condition, Definition 2.14 is easily seen to be essentially equivalent to the following more standard “Big Pieces” condition: there are positive constants and (perhaps slightly different to that in Definition 2.14), such that for each surface ball , and , and for any corkscrew point relative to there is a Chord-arc domain satisfying
- •
- •
.
- •
.
- •
.
- •
The Chord-arc constants of the domains are uniform in .
Definition 2.16**.**
(, weak-, and weak-). Given an -ADR set , and a surface ball centered on , we say that a Borel measure defined on belongs to if there are positive constants and such that for each surface ball centered on , with , we have
[TABLE]
Similarly, we say that weak- if for each surface ball centered on , with ,
[TABLE]
We recall that, as is well known, the condition weak- is equivalent to the property that in , and that for some , the Radon-Nikodym derivative satisfies the weak reverse Hölder estimate
[TABLE]
with centered on . We shall refer to the inequality in (2.19) as a “weak-” estimate, and we shall say that weak- if satisfies (2.19).
Definition 2.20**.**
(Local and local weak-). We say that harmonic measure is locally in (resp., locally in weak-) on , if there are uniform positive constants and such that for every ball centered on , with radius , and associated surface ball ,
[TABLE]
or, respectively, that
[TABLE]
equivalently, if for every ball and surface ball as above, and for each point , (resp., weak-) with uniformly controlled (resp., weak-) constants.
Lemma 2.23**.**
(Existence and properties of the “dyadic grid”) [DS1, DS2, Chr].* Suppose that is an -ADR set. Then there exist constants and , depending only on and the ADR constant, such that for each there is a collection of Borel sets (“cubes”)*
[TABLE]
where denotes some (possibly finite) index set depending on , satisfying
* for each .*
If then either or .
For each and each , there is a unique such that .
\operatorname{diam}\big{(}Q_{j}^{k}\big{)}\leq C_{1}2^{-k}.
Each contains some “surface ball” \Delta\big{(}x^{k}_{j},a_{0}2^{-k}\big{)}:=B\big{(}x^{k}_{j},a_{0}2^{-k}\big{)}\cap E.
H^{n}\big{(}\big{\{}x\in Q^{k}_{j}:{\rm dist}(x,E\setminus Q^{k}_{j})\leq\vartheta\,2^{-k}\big{\}}\big{)}\leq C_{1}\,\vartheta^{s}\,H^{n}\big{(}Q^{k}_{j}\big{)},* for all and for all .*
A few remarks are in order concerning this lemma.
In the setting of a general space of homogeneous type, this lemma has been proved by Christ [Chr] (see also [HK]), with the dyadic parameter replaced by some constant . In fact, one may always take (see [HMMM, Proof of Proposition 2.12]). In the presence of the Ahlfors-David property (2.2), the result already appears in [DS1, DS2]. Some predecessors of this construction have appeared in [Da1] and [Da2].
For our purposes, we may ignore those such that , in the case that the latter is finite.
We shall denote by the collection of all relevant , i.e.,
[TABLE]
where, if is finite, the union runs over those such that .
Properties and imply that for each cube , there is a point , a Euclidean ball and a surface ball such that and
[TABLE]
for some uniform constant . We shall refer to the point as the “center” of .
For a dyadic cube , we shall set , and we shall refer to this quantity as the “length” of . Evidently, by adjusting if necessary some parameters, we can assume that
[TABLE]
We shall denote
[TABLE]
Notice that .
For a dyadic cube , we let denote the dyadic generation to which belongs, i.e., we set if ; thus, .
Given , we set
[TABLE]
For , we also let
[TABLE]
For a pair of cubes , if is a dyadic child of , i.e., if , and , then we write .
For , we write
[TABLE]
With the dyadic cubes in hand, we may now define the notion of a corkscrew point relative to a cube .
Definition 2.28**.**
(Corkscrew point relative to ). Let satisfy the corkscrew condition (Definition 2.5), suppose that is -ADR, and let . A corkscrew point relative to is simply a corkscrew point relative to the surface ball defined in (2.24).
Definition 2.29**.**
(Coherency and Semi-coherency). [DS2].
Let be an -ADR set. Let . We say that is coherent if the following conditions hold:
contains a unique maximal element which contains all other elements of as subsets.
If belongs to , and if , then .
Given a cube , either all of its children belong to , or none of them do.
We say that is semi-coherent if conditions and hold. We shall refer to a coherent or semi-coherent collection as a tree.
Part 1: Proof of Theorem 1.5
3. Preliminaries for the Proof of Theorem 1.5
We begin by recalling a bilateral version of the David-Semmes “Corona decomposition” of an -UR set. We refer the reader to [HMM] for the proof.
Lemma 3.1**.**
([HMM, Lemma 2.2])* Let be an -UR set. Then given any positive constants and , there is a disjoint decomposition , satisfying the following properties.*
- (1)
The “Good” collection is further subdivided into disjoint trees, such that each such tree is coherent (Definition 2.29). 2. (2)
The “Bad” cubes, as well as the maximal cubes , , satisfy a Carleson packing condition:
[TABLE] 3. (3)
For each , there is a Lipschitz graph , with Lipschitz constant at most , such that, for every ,
[TABLE]
where and , and is the “center” of as in (2.24)-(2.25).
We remark that in [HMM], the trees were denoted by , and were called “stopping time regimes” rather than trees.
We mention that David and Semmes, in [DS1], had previously proved a unilateral version of Lemma 3.1, in which the bilateral estimate (3.2) is replaced by the unilateral bound
[TABLE]
Next, we make a standard Whitney decomposition of , for a given -UR set (in particular, is open, since -UR sets are closed by definition). Let denote a collection of (closed) dyadic Whitney cubes of , so that the cubes in form a pairwise non-overlapping covering of , which satisfy
[TABLE]
(just dyadically divide the standard Whitney cubes, as constructed in [Ste, Chapter VI], into cubes with side length 1/8 as large) and also
[TABLE]
whenever and touch.
We fix a small parameter , so that for any , and any , the concentric dilate
[TABLE]
still satisfies the Whitney property
[TABLE]
Moreover, for small enough, and for any , we have that meets if and only if and have a boundary point in common, and that, if , then misses .
Pick two parameters and (eventually, we shall take ). For , define
[TABLE]
Remark 3.8*.*
We note that is non-empty, provided that we choose small enough, and large enough, depending only on dimension and ADR, since the -ADR condition implies that satisfies a corkscrew condition. In the sequel, we shall always assume that and have been so chosen.
Next, we recall a construction in [HMM, Section 3], leading up to and including in particular [HMM, Lemma 3.24]. We summarize this construction as follows.
Lemma 3.9**.**
Let be -UR, and set . Given positive constants and , as in (3.7) and Remark 3.8, let , be the corresponding bilateral Corona decomposition of Lemma 3.1. Then for each , and for each , the collection in (3.7) has an augmentation satisfying the following properties.
- (1)
, where (after a suitable rotation of coordinates) each lies above the Lipschitz graph of Lemma 3.1, each lies below . Moreover, if is a child of , also belonging to , then (resp. ) belongs to the same connected component of as does (resp. ) and (resp., ). 2. (2)
There are uniform constants and such that
[TABLE]
Moreover, given , set
[TABLE]
and given , a semi-coherent subtree of , define
[TABLE]
Then each of is a CAD, with Chord-arc constants depending only on , and the ADR/UR constants for (see Figure 3.1).
Remark 3.13*.*
In particular, for each , if and belong to , and if is a dyadic child of , then is Harnack Chain connected, and every pair of points may be connected by a Harnack Chain in of length at most . The same is true for .
Remark 3.14*.*
Let . Given any , and any semi-coherent subtree , define as in (3.12), and similarly set . Then by construction, for any ,
[TABLE]
where of course the implicit constants depend on .
As in [HMM], it will be useful for us to extend the definition of the Whitney region to the case that , the “bad” collection of Lemma 3.1. Let be the augmentation of as constructed in Lemma 3.9, and set
[TABLE]
For we shall henceforth simply write in place of . For arbitrary , good or bad, we may then define
[TABLE]
Let us note that for , the latter definition agrees with that in (3.11). Note that by construction
[TABLE]
for some uniform constants and (see (3.4), (3.7), and (3.10)). In particular, for every if follows that
[TABLE]
where we recall that is defined in (2.26).
For future reference, we introduce dyadic sawtooth regions as follows. Given a family of disjoint cubes , we define the global discretized sawtooth relative to by
[TABLE]
i.e., is the collection of all that are not contained in any . We may allow to be empty, in which case . Given some fixed cube , we also define the local discretized sawtooth relative to by
[TABLE]
Note that with this convention, (i.e., if one takes in (3.20)).
4. Step 1: the set-up
In the proof of Theorem 1.5, we shall employ a two-parameter induction argument, which is a refinement of the method of “extrapolation” of Carleson measures. The latter is a bootstrapping scheme for lifting the Carleson measure constant, developed by J. L. Lewis [LM], and based on the corona construction of Carleson [Car] and Carleson and Garnett [CG] (see also [HLw], [AHLT], [AHMTT], [HM1], [HM2],[HMM]).
4.1. Reduction to a dyadic setting
To set the stage for the induction procedure, let us begin by making a preliminary reduction. It will be convenient to work with a certain dyadic version of Definition 2.14. To this end, let , with , and set , for some fixed as in Definition 2.11. Let be a touching point for , i.e., . Choose on the line segment joining to , with , and set . Note that , and furthermore,
[TABLE]
We may therefore cover by a disjoint collection , of equal length , such that each , and such that the implicit constants depend only on and ADR, and thus the cardinality of the collection depends on , ADR, and . With , we make the Whitney decomposition of the set as in Section 3 (thus, ). Moreover, for sufficiently small and sufficiently large in (3.7), we then have that for each . By hypothesis, there are constants , and as above, such that every is a -weak local John point (Definition 2.11). In particular, this is true for , hence there is a Borel set , with , such that every may be connected to via a -carrot path. By -ADR, and thus by pigeon-holing, there is at least one such that , with depending only on , and ADR. Moreover, the -carrot path connecting each to may be extended to a -carrot path connecting to , where depends only on .
We have thus reduced matters to the following dyadic scenario: let , let be the associated Whitney region as in (3.16), with fixed, and suppose that meets (recall that by construction , with ). For , and for a constant , let
[TABLE]
denote the set of which may be joined to by a -carrot path , and for , set
[TABLE]
Remark 4.3*.*
Our goal is to prove that, given and , there are positive constants and , depending on , and the allowable parameters, such that for each , and for each , there is a Chord-arc domain , with uniformly controlled Chord-arc constants, constructed as a union of fattened Whitney boxes , such that
[TABLE]
where is the particular connected component of containing , and
[TABLE]
For some , it may be that is empty. On the other hand, by the preceding discussion, each belongs to for suitable and , so that (4.4) (with ) implies
[TABLE]
with , where is the particular selected in the previous paragraph. Moreover, since , we can modify if necessary, by adjoining to it one or more fattened Whitney boxes with , to ensure that for the modified , it holds in addition that , and therefore verifies all the conditions in Definition 2.14.
The rest of this section is therefore devoted to proving that there exists, for a given and for each , a Chord-arc domain satisfying the stated properties (when the set is not vacuous). To this end, we let (by Remark 4.3, any fixed will suffice). We also fix positive numbers , and , and for these values of and , we make the bilateral Corona decomposition of Lemma 3.1, so that . We also construct the Whitney collections in (3.7), and of Lemma 3.9 for this same choice of and .
Given a cube , we set
[TABLE]
Thus, consists of the cube itself, along with its dyadic children and grandchildren. Let
[TABLE]
denote the collection of cubes which are the maximal elements of the trees in . We define
[TABLE]
Given any collection , we set
[TABLE]
Then is a discrete Carleson measure, i.e., recalling that is the discrete Carleson region relative to defined in (2.26), we claim that there is a uniform constant such that
[TABLE]
Indeed, note that for any , there are at most 3 cubes such that (namely, itself, its dyadic parent, and its dyadic grandparent), and that by -ADR, , if . Thus, given any ,
[TABLE]
by Lemma 3.1 part (2). Here, and throughout the remainder of this section, a generic constant , and implicit constants, are allowed to depend upon the choice of the parameters and that we have fixed, along with the usual allowable parameters.
With (4.8) in hand, we therefore have
[TABLE]
4.2. Induction Hypothesis and Outline of Proof
As mentioned above, our proof will be based on a two parameter induction scheme. Given fixed as above, we recall that the set is defined in (4.1). The induction hypothesis, which we formulate for any , and any is as follows:
There is a positive constant such that for any given , if
(4.10)
and if there is a subset for which
(4.11)
then there is a subset , such that for each connected component of which meets , there is a Chord-arc domain which is the interior of the union of a collection of fattened Whitney cubes , and whose Chord-arc constants depend only on dimension, , , , and the ADR constants for . Moreover, , and , where the sum runs over those such that meets .
Let us briefly sketch the strategy of the proof. We first fix , and by induction on , establish . We then show that there is a fixed such that implies , for every . Iterating, we then obtain for any . Now, by (4.9), we have (4.10) with , for every . Thus, may be applied in every cube such that (see (4.2)) is non-empty, with , for any . For , and an appropriate choice of , by Remark 4.3, we obtain the existence of a Chord-arc domain verifying the conditions of Definition 2.14, and thus that Theorem 1.5 holds, as desired.
5. Some geometric observations
We begin with some preliminary observations. In what follows we have fixed and two positive numbers , and , for which the bilateral Corona decomposition of in Lemma 3.1 is applied. We now fix , , such that
[TABLE]
Lemma 5.2**.**
Let , and suppose that , with . Suppose that there are points and , that are connected by a -carrot path in . Then meets .
Proof.
By construction (see (3.7), Lemma 3.9, (3.15) and (3.16)), implies that
[TABLE]
Since , and , we then have that x\in\Omega\setminus B\big{(}y,2\ell(Q^{\prime})\big{)}, so meets B\big{(}y,2\ell(Q^{\prime})\big{)}\setminus B\big{(}y,\ell(Q^{\prime})\big{)}, say at a point . Since is a -carrot path, and since we have previously specified that ,
[TABLE]
On the other hand
[TABLE]
In particular then, the Whitney box containing must belong to (see (3.7)), so . Note that since . ∎
We shall also require the following. We recall that by Lemma 3.9, for , the Whitney region has the splitting , with (resp. ) lying above (resp., below) the Lipschitz graph of Lemma 3.1.
Lemma 5.3**.**
Let , and suppose that and both belong to , and moreover that both and belong to the same tree . Suppose that and are connected via a -carrot path in , and assume that there is a point (by Lemma 5.2 we know that such a exists provided ). Then if and only if (thus, if and only if ).
Proof.
We suppose for the sake of contradiction that, e.g., , and that . Thus, in traveling from to and then to along the path , one must cross the Lipschitz graph at least once between and . Let be the first point on that one encounters after , when traveling toward . By Lemma 3.9,
[TABLE]
where we recall that we have fixed . Consequently, \ell\big{(}\gamma(y,x)\big{)}\ll K^{3/4}\ell(Q), so in particular, \gamma(y,x)\subset B_{Q}^{*}:=B\big{(}x_{Q},K\ell(Q)\big{)}, as in Lemma 3.1. On the other hand, . Indeed, , so if , then by (3.2), . However,
[TABLE]
where in the last step we have used Lemma 3.9. This contradicts our choice of .
We now form a chain of consecutive dyadic cubes , connecting to , i.e.,
[TABLE]
where the introduced notation means that is the dyadic child of , that is, and . Let , , be the smallest of the cubes such that . Setting , we then have that , and . By the coherency of , it follows that , so by (3.2),
[TABLE]
On the other hand,
[TABLE]
and therefore, since ,
[TABLE]
Combining (5.4) and (5.5), we see that , which contradicts that we have fixed , and . ∎
Lemma 5.6**.**
Fix . Given and a non-empty set , such that each may be connected by a -carrot path to some , set
[TABLE]
where we recall that is the set of that are connected via a -carrot path to (see (4.1)). Let be such that and . Then, there exists a non-empty set such that if we define as in (5.7) with replacing , then . Moreover, for every , there exist , (indeed ) and a -carrot path such that .
Proof.
For every , by definition of , there exist and a -carrot path . By Lemma 5.2, there is a point (there can be more than one , but we just pick one). Note that the sub-path is also a -carrot path, for the same constant . All the conclusions in the lemma follow easily from the construction by letting . ∎
Remark 5.8*.*
It follows easily from the previous proof that under the same assumptions, if one further assumes that , we can then repeat the argument with both and (the dyadic parent of ) to obtain respectively and . Moreover, this can be done in such a way that every point in (resp. ) belongs to a -carrot path which also meets (resp. ), connecting and .
Given a family of pairwise disjoint cubes, we recall that the “discrete sawtooth” is the collection of all cubes in that are not contained in any (see (3.19)), and we define the restriction of (cf. (4.6), (4.7)) to the sawtooth by
[TABLE]
We then set
[TABLE]
Let us note that we may allow to be empty, in which case and is simply . We note that the following claim, and others in the sequel, remain true when is empty; sometimes trivially so, and sometimes with some straightforward changes that are left to the interested reader.
Claim 5.10**.**
Given , and a family of pairwise disjoint sub-cubes of , if , then each , each , and every dyadic child of any , belong to the good collection , and moreover, every such cube belongs to the same tree . In particular, is a semi-coherent subtree of , and so is , where denotes the collection of all dyadic children of cubes in .
Indeed, if any were in (recall that is the collection of cubes which are the maximal elements of the trees in ), then by construction for that cube (see (4.6)), so by definition of and , we would have
[TABLE]
a contradiction. Similarly, if some (respectively, ) were in , then its dyadic parent (respectively, dyadic grandparent) would belong to , and by definition , so again we reach a contradiction. Consequently, does not meet , and the claim follows.
6. Construction of chord-arc subdomains
For future reference, we now prove the following. Recall that for , has precisely two connected components in .
Lemma 6.1**.**
*Let , let be such that , see (5.1), and suppose that there is a family of pairwise disjoint sub-cubes of , with (hence by Claim 5.10, there is some with ), and a non-empty subcollection , such that: *
- (i)
, for each cube ;
- (ii)
the collection of balls \big{\{}\kappa B^{*}_{Q_{j}}:=B\big{(}x_{Q_{j}},\kappa K\ell(Q_{j})\big{)}:\,Q_{j}\in\mathcal{F}^{*}\big{\}} is pairwise disjoint, where is a sufficiently large positive constant; and
- (iii)
* has a disjoint decomposition , where for each , there is a Chord-arc subdomain , consisting of a union of fattened Whitney cubes , with , and with uniform control of the Chord-arc constants.*
Define a semi-coherent subtree by
[TABLE]
and for each choice of for which is non-empty, set
[TABLE]
Then for large enough, depending only on allowable parameters, is a Chord-arc domain, with chord arc constants depending only on the uniformly controlled Chord-arc constants of and on the other allowable parameters. Moreover, , and is a union of fattened Whitney cubes.
Remark 6.3*.*
Note that we define if and only if is non-empty. It may be that one of is empty, but and cannot both be empty, since is non-empty by assumption.
Proof of Lemma 6.1.
Without loss of generality we may assume that is not contained in for all (otherwise we can drop those cubes from ). On the other hand, we notice that is a union of (open) fattened Whitney cubes (assuming that it is non-empty): each has this property by assumption, as does by construction.
We next observe that if (resp. ) is non-empty, then it is contained in . Indeed, by construction, is non-empty if and only if is non-empty. In turn, is non-empty if and only if there is some such that , and moreover, the latter is true for every , by definition. But each such belongs to , hence , again by construction (see (3.12)). Thus, meets , and since , therefore . Combining these observations, we see that . Of course, the same reasoning applies to , provided it is non-empty.
In addition, since , and since , by Lemma 3.9 we have . Furthermore, , and since , we obtain
[TABLE]
Thus, in particular, , and therefore also .
It therefore remains to establish the Chord-arc properties. It is straightforward to prove the interior corkscrew condition and the upper -ADR bound, and we omit the details. Thus, we must verify the Harnack Chain condition, the lower -ADR bound, and the exterior corkscrew condition.
6.1. Harnack Chains
Suppose, without loss of generality, that is non-empty, and let , with . If and both lie in , or in the same , then we can connect and by a suitable Harnack path, since each of these domains is Chord-arc. Thus, we may suppose either that 1) and lies in some , or that 2) and lie in two distinct and . We may reduce the latter case to the former case: by the separation property (ii) in Lemma 6.1, we must have r\gtrsim\kappa\max\big{(}\operatorname{diam}(\Omega_{Q_{j_{1}}}^{+}),\operatorname{diam}(\Omega_{Q_{j_{2}}}^{+})\big{)}, so given case 1), we can connect to the center of some , and to the center of some , where , with , and , . Finally, we can connect and using that is Chord-arc.
Hence, we need only construct a suitable Harnack Chain in Case 1). We note that by assumption and construction, .
Suppose first that
[TABLE]
where is a sufficiently small positive constant to be chosen. Since , we then have that , so by the construction of and the separation property (ii), it follows that , where is a uniform constant depending only on the allowable parameters (in particular, this fact is true for all , so it does not depend on the choice of ). Now choosing (eventually, it may be even smaller), we find that . Moreover, implies that . Also, since we have that . Since and are each the interior of a union of fattened Whitney cubes, it follows that there are Whitney cubes and , with , , and
[TABLE]
where the implicit constants depend on . For small enough in (6.4), depending on the implicit constants in the last display, and on the parameter in (3.5), this can happen only if and overlap (recall that we have fixed small enough that and overlap if and only if and have a boundary point in common), in which case we may trivially connect and by a suitable Harnack Chain.
On the other hand, suppose that
[TABLE]
Let , with (we may find such a , since is a union of fattened Whitney cubes, all of length ; just take to be the center of such an ). We may then construct an appropriate Harnack Chain from to by connecting to via a Harnack Chain in the Chord-arc domain , and to via a Harnack Chain in the Chord-arc domain .
6.2. Lower -ADR and exterior corkscrews
We will establish these two properties essentially simultaneously. Again suppose that, e.g., is non-empty. Let , and consider , with . Our main goal at this stage is to prove the following:
[TABLE]
with a uniform positive constant depending only upon allowable parameters (including ). Indeed, momentarily taking this estimate for granted, we may combine (6.5) with the interior corkscrew condition to deduce the lower -ADR bound via the relative isoperimetric inequality [EG, p. 190]. In turn, with both the lower and upper -ADR bounds in hand, (6.5) implies the existence of exterior corkscrews (see, e.g., [HM2, Lemma 5.7]).
Thus, it is enough to prove (6.5). We consider the following cases.
Case 1: does not meet for any . In this case, the exterior corkscrew for associated with easily implies (6.5).
Case 2: meets for at least one , and , where is chosen to have the largest length among those such that meets . We now further split the present case into subcases.
Subcase 2a: meets at a point with , where is a large number to be chosen. Then , for large enough. In addition, we claim that misses \Omega_{{\mathsf{T}}^{*}}^{+}\cup\big{(}\cup_{j\neq j_{0}}\Omega_{Q_{j}}^{+}\big{)}. The fact that misses every other , follows immediately from the restriction , and the separation property (ii). To see that misses , note that if , then
[TABLE]
for large. On the other hand,
[TABLE]
by the construction of and the separation property (ii). Thus, the claim follows, for a sufficiently large (fixed) choice of . Since misses and all other , we inherit an exterior corkscrew point in the present case (depending on and ) from the Chord-arc domain . Again (6.5) follows.
Subcase 2b: , for every (hence , since ). We claim that consequently, , for some with , such that . To see this, observe that it is clear if (just take ). Otherwise, by the separation property (ii), the remaining possibility in the present scenario is that , for some with , in which case . Since also , for any , the claim follows.
On the other hand, since , there is a with , such that is not contained in . We then have an exterior corkscrew point in , and (6.5) follows in this case.
Case 3: meets for at least one , and , where as above has the largest length among those such that meets . In particular then, , since we assume .
We next claim that contains some . This is clear if by taking . Otherwise, for some . Note that . Also, , by construction. On the other hand we note that if we have by (3.17)
[TABLE]
by our choice of . By this fact, and the definition of , we have
[TABLE]
Using then that is connected, we see that a path within joining with must meet . Hence we can find . By Lemma 3.9, and are disjoint (they live respectively above and below the graph ), so a path joining and within meets some . On the other hand, , since . Furthermore, , so by assumption (ii), we necessarily have that for . Thus, , and moreover, since meets (at ) we have . Therefore, is the claimed point, since in the current case .
With the point in hand, we note that
[TABLE]
By the exterior corkscrew condition for ,
[TABLE]
for some constant depending only on and the ADR/UR constants for , by Lemma 3.9. Also, for each whose boundary meets (and thus meets ),
[TABLE]
in the present scenario. Consequently, , for all such .
We now make the following claim.
Claim 6.9**.**
On has
[TABLE]
for some depending only on allowable parameters.
Observe that by the second containment in (6.6), we obtain (6.5) as an immediate consequence of (6.10), and thus the proof will be complete once we have established Claim 6.9.
Proof of Claim 6.9.
To prove the claim, we suppose first that
[TABLE]
where the sum runs over those such that meets , and is the constant in (6.7). In that case, (6.10) holds with (and even with ), by definition of (see (6.2)), and the fact that . On the other hand, if (6.11) fails, then summing over the same subset of indices , we have
[TABLE]
We now make a second claim:
Claim 6.13**.**
For appearing in the previous sum, we have
[TABLE]
for some uniform .
Taking the latter claim for granted momentarily, we insert estimate (6.14) into (6.12) and sum, to obtain
[TABLE]
By the separation property (ii), the balls are pairwise disjoint, and by assumption . Thus, for any given , misses . Moreover, as noted above (see (6.8) and the ensuing comment), for each under consideration in (6.11)-(6.15). Claim 6.9 now follows. ∎
Proof of Claim 6.13.
There are two cases: if , then (6.14) is trivial, since . Otherwise, contains a point . In the latter case, by the exterior corkscrew condition for ,
[TABLE]
since . On the other hand, B\big{(}z,2^{-1}\kappa^{1/4}K\ell(Q_{j})\big{)}\subset\kappa^{1/4}B_{Q_{j}}^{*}, and (6.14) follows, finishing the proof of Claim 6.13. ∎
Next, (6.6) and (6.10) yield (6.5) in the present case and hence the proof of Lemma 6.1 is complete. ∎
7. Step 2: Proof of
We shall deduce (see Section 4.2) from the following pair of claims.
Claim 7.1**.**
* holds for every .*
Proof of Claim 7.1.
If in (4.10), then , whence it follows by Claim 5.10, with , that there is a tree , with . Hence is a coherent subtree of , so by Lemma 3.9, each of is a CAD, containing , respectively, with by (3.18). Moreover, by [HMM, Proposition A.14]
[TABLE]
so that Thus, holds trivially. ∎
Claim 7.2**.**
There is a uniform constant such that , for all .
Combining Claims 7.1 and 7.2, we find that holds.
To prove Claim 7.2, we shall require the following.
Lemma 7.3** ([HM2, Lemma 7.2]).**
Suppose that is an -ADR set, and let be a discrete Carleson measure, as in (4.7)-(4.9) above. Fix . Let and , and suppose that \mathfrak{m}\big{(}\mathcal{D}(Q)\big{)}\leq(a+b)\,\sigma(Q). Then there is a family of pairwise disjoint cubes, and a constant depending only on and the ADR constant such that
[TABLE]
[TABLE]
where \mathcal{F}_{bad}:=\{Q_{j}\in\mathcal{F}:\,\mathfrak{m}\big{(}\mathcal{D}(Q_{j})\setminus\{Q_{j}\}\big{)}>\,a\sigma(Q_{j})\}.
We refer the reader to [HM2, Lemma 7.2] for the proof. We remark that the lemma is stated in [HM2] in the case that is the boundary of a connected domain, but the proof actually requires only that have a dyadic cube structure, and that be a non-negative, dyadically doubling Borel measure on . In our case, we shall of course apply the lemma with , where is open, but not necessarily connected.
Proof of Claim 7.2.
We assume that holds, for some . Let us set , where is the constant in (7.4). Consider a cube with . Suppose that there is a set such that (4.11) holds with . We fix (see (5.1)) large enough so that .
Case 1: There exists (see (2.27)) with \mathfrak{m}\big{(}\mathcal{D}(Q^{\prime})\big{)}\leq a\sigma(Q^{\prime}).
In the present scenario , that is, (see (4.11) and (5.7)), which implies . We apply Lemma 5.6 to obtain and the corresponding which satisfies . That is, (4.11) holds for , with . Consequently, we may apply the induction hypothesis to , to find , such that for each meeting , there is a Chord-arc domain formed by a union of fattened Whitney cubes with , and
[TABLE]
By Lemma 5.6, and since , each lies on a -carrot path connecting some to some ; let denote the set of all such , and let (respectively, ) denote the collection of connected components of (resp., of ) which meet (resp., ). By construction, each component may be joined to some corresponding component in , via one of the carrot paths. After possible renumbering, we designate this component as , we let denote the points in and in , respectively, that are joined by this carrot path, and we let be the portion of the carrot path joining to (if there is more than one such path or component, we just pick one). We also let be the collection of all of the selected points . We let be the collection of Whitney cubes meeting , and we then define
[TABLE]
By the definition of a -carrot path, since , and since is a CAD, one may readily verify that is also a CAD consisting of a union of fattened Whitney cubes . We omit the details. Moreover, by construction,
[TABLE]
so that the analogue of (7.6) holds with replaced by , and with replaced by .
It remains to verify that . By the induction hypothesis, and our choice of , since we have
[TABLE]
Moreover, , by (3.18). We therefore need only to consider with . For such an , by definition there is a point and , so that and thus,
[TABLE]
where in the last inequality we have used (3.17) and the fact that . Hence, for every by (3.4)
[TABLE]
by our choice of the parameters and .
We then obtain the conclusion of in the present case.
Case 2: \mathfrak{m}\big{(}\mathcal{D}(Q^{\prime})\big{)}>a\sigma(Q^{\prime}) for every .
In this case, we apply Lemma 7.3 to obtain a pairwise disjoint family such that (7.4) and (7.5) hold. In particular, by our choice of ,
[TABLE]
so that the conclusions of Claim 5.10 hold.
We set
[TABLE]
define
[TABLE]
and let
[TABLE]
Then by (7.5)
[TABLE]
where is defined by
[TABLE]
We claim that
[TABLE]
Indeed, were this not true for some , then by definition of and pigeon-holing there will be with such that \mathfrak{m}\big{(}\mathcal{D}(Q_{j}^{\prime})\big{)}\leq a\,\sigma(Q_{j}^{\prime}). This contradicts the assumptions of the current case.
Note also that by (7.12) and by (7.5), hence . By (7.7) and Claim 5.10, there is some tree so that is a semi-coherent subtree of , where denotes the collection of all dyadic children of cubes in .
Case 2a: .
In this case, has an ample overlap with the boundary of a Chord-arc domain with controlled Chord-arc constants. Indeed, let which, by (7.7) and Claim 5.10, is a semi-coherent subtree of some . Hence, by Lemma 3.9, each of is a CAD with constants depending on the allowable parameters, formed by the union of fattened Whitney boxes, which satisfies (see (3.11), (3.12), and (3.18)). Moreover, by [HMM, Proposition A.14] and [HM2, Proposition 6.3] and our current assumptions,
[TABLE]
Recall that in establishing , we assume that there is a set for which (4.11) holds with . Pick then and set . Note that since it follows that belongs to either or . For the sake of specificity assume that hence, in particular, . Note also that is the only component of meeting . All these together give at once that the conclusion of holds in the present case.
Case 2b: .
In this case by (7.10)
[TABLE]
In addition, by the definition of (7.9), and pigeon-holing, every has a dyadic child (there could be more children satisfying this, but we just pick one) so that
[TABLE]
Under the present assumptions , that is, (see (4.11) and (5.7)), hence . We apply Lemma 5.6 (recall (7.12)) to obtain and which satisfies . That is, (4.11) holds for , with . Consequently, recalling that (see Claim 5.10), and applying the induction hypothesis to , we find , such that for each meeting , there is a Chord-arc domain formed by a union of fattened Whitney cubes with . Moreover, since in particular, the cubes in along with all of their children belong to the same tree (see Claim 5.10), the connected component overlaps with the corresponding component for its child, so we may augment by adjoining to it the appropriate component , to form a chord arc domain
[TABLE]
Moreover, since , and since , we have that , hence by construction.
By a covering lemma argument, for a sufficiently large constant , we may extract a subcollection so that is a pairwise disjoint family, and
[TABLE]
In particular, by (7.13),
[TABLE]
where the implicit constants depend on ADR, , and the dilation factor .
By the induction hypothesis, and by construction (7.15) and -ADR,
[TABLE]
where is equal either to or to (if (7.17) holds for both choices, we arbitrarily set ).
Combining (7.17) with (7.16), we obtain
[TABLE]
We now assign each either to or to , depending on whether we chose satisfying (7.17) to be , or . We note that at least one of the sub-collections is non-empty, since for each , there was at least one choice of “+’ or “-” such that (7.17) holds for the corresponding choice of . Moreover, the two collections are disjoint, since we have arbitrarily designated in the case that there were two choices for a particular .
To proceed, as in Lemma 6.1 we set
[TABLE]
which is semi-coherent by construction. For non-empty, we now define
[TABLE]
Observe that by the induction hypothesis, and our construction (see (7.15) and the ensuing comment), for an appropriate choice of , , and since , by (7.18) and Lemma 6.1, with , each (non-empty) choice of defines a Chord-arc domain with the requisite properties.
Thus, we have proved Claim 7.2 and therefore, as noted above, it follows that holds. ∎
8. Step 3: bootstrapping
In this last step, we shall prove that there is a uniform constant such that for each , . Since we have already established , we then conclude that holds for any given . As noted above, it then follows that Theorem 1.5 holds, as desired.
In turn, it will be enough to verify the following.
Claim 8.1**.**
There is a uniform constant such that for every , , , and as in Step 2/Proof of Claim 7.2, if holds, then
[TABLE]
Let us momentarily take Claim 8.1 for granted. Recall that by Claim 7.1, holds for all . In particular, given fixed, for which holds, we have that holds. Combining the latter fact with Claim 8.1, and iterating, we obtain that holds. We eventually reach , with . The conclusion of Step 3 now follows, with .
Proof of Claim 8.1.
The proof will be a refinement of that of Claim 7.2. We are given some such that holds, and we assume that holds, for some and . Set , where as before is the constant in (7.4). Consider a cube with . Suppose that there is a set such that (4.11) holds with replaced by , for some to be determined. Our goal is to show that for a sufficiently small, but uniform choice of , we may deduce the conclusion of the induction hypothesis, with in place of .
By assumption, and recalling the definition of in (5.7), we have that (4.11) holds with constant , i.e.,
[TABLE]
As in the proof of Claim 7.2, we fix (see (5.1)) large enough so that . There are two principal cases. The first is as follows.
Case 1: There exists (see (2.27)) with \mathfrak{m}\big{(}\mathcal{D}(Q^{\prime})\big{)}\leq a\sigma(Q^{\prime}).
We split Case 1 into two subcases.
Case 1a: .
In this case, we follow the Case 1 argument for in Section 7 mutatis mutandis, so we merely sketch the proof. By Lemma 5.6, we may construct and so that and hence . We may then apply the induction hypothesis in , and then proceed exactly as in Case 1 in Section 7 to construct a subset and a family of Chord-arc domains satisfying the various desired properties, and such that
[TABLE]
The conclusion of then holds in the present scenario.
Case 1b: .
By (8.2)
[TABLE]
In the scenario of Case 1b, this leads to
[TABLE]
that is,
[TABLE]
Note that we have the dyadic doubling estimate
[TABLE]
where . Combining this estimate with (8.3), we obtain
[TABLE]
We now choose , so that , and therefore the expression in square brackets is at least 1. Consequently, by pigeon-holing, there exists a particular such that
[TABLE]
By Lemma 5.6, we can find such that , where the latter is defined as in (5.7), with in place of . By assumption, holds, so combining (8.4) with the fact that (4.10) holds with for every , we find that there exists a subset , along with a family of Chord-arc domains enjoying all the appropriate properties relative to . Using that , we may now proceed exactly as in Case 1a above, and also Case 1 in Section 7, to construct and such that the conclusion of holds in the present case also.
Case 2: \mathfrak{m}\big{(}\mathcal{D}(Q^{\prime})\big{)}>a\sigma(Q^{\prime}) for every .
In this case, we apply Lemma 7.3 to obtain a pairwise disjoint family such that (7.4) and (7.5) hold. In particular, by our choice of , .
Recall that is defined in (5.7), and satisfies (8.2). We define as in (7.8), and as in (7.9). Let . Then as above (see (7.10)),
[TABLE]
where again is defined as in (7.11). Just as in Case 2 for in Section 7, we have that
[TABLE]
(see (7.12)). Hence, the conclusions of Claim 5.10 hold.
We first observe that if , for some to be chosen (depending on allowable parameters), then the desired conclusion holds. Indeed, in this case, we may proceed exactly as in the analogous scenario in Case 2a in Section 7: the promised Chord-arc domain is again simply one of , since at least one of these contains a point in and hence in particular is a subdomain of . The constant in our conclusion will depend on , but in the end this will be harmless, since will be chosen to depend only on allowable parameters.
We may therefore suppose that
[TABLE]
Next, we refine the decomposition . With as in (7.11) and (8.5), we choose . Set
[TABLE]
and define . Let
[TABLE]
and define .
We split the remaining part of Case 2 into two subcases. The first of these will be easy, based on our previous arguments.
Case 2a: There is such that .
By definition of , one has . By pigeon-holing, has a descendant with , such that . We may then apply in , and proceed exactly as we did in Case 1b above with the cube , which enjoyed precisely the same properties as does our current . Thus, we draw the desired conclusion in the present case.
The main case is the following.
Case 2b: Every satisfies .
Observe that by definition,
[TABLE]
and also
[TABLE]
Set . For future reference, we shall derive a certain ampleness estimate for the cubes in . By (8.2),
[TABLE]
where in the last step have used (8.7) and (8.8). Observe that
[TABLE]
Using (8.10) and (8.11), for \varepsilon\ll\big{(}4\rho^{-1}-1\big{)}\vartheta\beta\theta, we obtain
[TABLE]
and thus
[TABLE]
We now make the following claim.
Claim 8.13**.**
For chosen sufficiently small,
[TABLE]
Proof of Claim 8.13.
If , then we are done. Therefore, suppose that
[TABLE]
We have made the decomposition
[TABLE]
Consequently
[TABLE]
where we have used (8.7), and (8.14) to estimate the contributions of , and of , respectively. This, (8.2), (8.8), and (8.9) yield
[TABLE]
In turn, applying (8.11) in the latter estimate, and rearranging terms, we obtain
[TABLE]
Recalling that , and that , we further note that by (8.5), choosing , and using (8.7) and (8.14), we find in particular that
[TABLE]
Applying (8.17) and the trivial estimate in (8.16), we then have
[TABLE]
Since , we conclude, for , that
[TABLE]
and Claim 8.13 follows. ∎
With Claim 8.13 in hand, let us return to the proof of Case 2b of Claim 8.1. We begin by noting that by definition of , and Lemma 5.6, we can apply to any , hence for each such there is a family of Chord-arc domains satisfying the desired properties.
Now consider . Since , by pigeon-holing has a dyadic child satisfying
[TABLE]
(there may be more than one such child, but we just pick one). Our immediate goal is to find a child of , which may or may not equal , for which we may construct a family of Chord-arc domains satisfying the desired properties. To this end, we assume first that satisfies
[TABLE]
In this case, we set , and using Lemma 5.6, by the induction hypothesis , we obtain the desired family of Chord-arc domains.
We therefore consider the case
[TABLE]
In this case, we shall select . Recall that we use the notation to mean that is a dyadic child of . Set
[TABLE]
Note that we have the dyadic doubling estimate
[TABLE]
where . We also note that
[TABLE]
By definition of ,
[TABLE]
By (8.20), it follows that
[TABLE]
In turn, using (8.22), we obtain
[TABLE]
By the dyadic doubling estimate (8.21), this leads to
[TABLE]
Choosing , we find that the expression in square brackets is at least 1, and therefore, by pigeon holing, we can pick satisfying
[TABLE]
Hence, using Lemma 5.6, we see that the induction hypothesis holds for , and once again we obtain the desired family of Chord-arc domains.
Recall that we have constructed our packing measure in such a way that each , as well as all of its children, along with the cubes in , belong to the same tree ; see Claim 5.10. This means in particular that for each such , the Whitney region has exactly two components , and the analogous statement is true for each child of . This fact has the following consequences:
Remark 8.24*.*
For each , and for the selected child of each , the conclusion of the induction hypothesis produces at most two Chord-arc domains (resp. ), which we enumerate as (resp. , , with corresponding “+”, and corresponding to “-”, respectively.
Remark 8.25*.*
For each , the connected component overlaps with the corresponding component for its child, so we may augment by adjoining to it the appropriate component , to form a chord arc domain
[TABLE]
By the induction hypothesis, for each (and by -ADR, in the case of ), the Chord-arc domains that we have constructed satisfy
[TABLE]
where the sum has either one or two terms, and where the implicit constant depends either on and , or on and , depending on which part of the induction hypothesis we have used. In particular, for each such , there is at least one choice of index such that satisfies
[TABLE]
(if the latter is true for both choices , we arbitrarily choose , which we recall corresponds to “+”). Combining the latter bound with Claim 8.13, and recalling that has now been fixed depending only on allowable parameters, we see that
[TABLE]
For , as above set . By a covering lemma argument, we may extract a subfamily such that is pairwise disjoint, where again is a large dilation factor, and such that
[TABLE]
Let us now build (at most two) Chord-arc domains satisfying the desired properties. Recall that for each , we defined the corresponding Chord-arc domain , where the choice of index (if there was a choice), was made so that (8.26) holds. We then assign each either to or to , depending on whether we chose satisfying (8.26) to be , or . We note that at least one of the sub-collections is non-empty, since for each , there was at least one choice of index such that (8.26) holds with . Moreover, the two collections are disjoint, since we have arbitrarily designated (corresponding to “+”) in the case that there were two choices for a particular . We further note that if , then .
We are now in position to apply Lemma 6.1. Set
[TABLE]
which is a semi-coherent subtree of , with maximal cube . Without loss of generality, we may suppose that is non-empty, and we then define
[TABLE]
and similarly with “+” replaced by “-”, provided that is also non-empty. Observe that by the induction hypothesis, and our construction (see Remarks 8.24 and 8.25, and Lemma 3.9), for an appropriate choice of “”, , and since , by (8.27) and Lemma 6.1, each (non-empty) choice defines a Chord-arc domain with the requisite properties. This completes the proof of Case 2b of Claim 8.1 and hence that of Theorem 1.5. ∎
Part 2: Proof of Theorem 1.6
9. Preliminaries for the Proof of Theorem 1.6
9.1. Uniform rectifiability
Recall the definition of -uniform rectifiable (-UR) sets in Definition 2.3. Given a ball , we denote
[TABLE]
where the infimum is taken over all the affine -planes that intersect . The following result is due to David and Semmes:
Theorem 9.2**.**
Let be -ADR. Denote and let be the associated dyadic lattice. Then, is -UR if and only if, for any ,
[TABLE]
For the proof, see [DS2, Theorem 2.4, p.32] (this provides a slight variant of Theorem 9.2, and it is straightforward to check that both formulations are equivalent). Remark that the constant multiplying in the estimate above can be replaced by any number larger than .
Recall also the following result (see [HLMN] or [MT]).
Theorem 9.3**.**
Let , , be an open set satisfying an interior corkscrew condition, with -ADR boundary, such that the harmonic measure in belongs to weak-. Then is -UR.
9.2. Harmonic measure
From now on we assume that is an open set with -ADR boundary such that the harmonic measure in belongs to weak-. We denote by the surface measure in , that is, . We also consider the dyadic lattice associated with as in Lemma 2.23. The AD-regularity constant of is denoted by .
We denote by the harmonic measure with pole at of , and by the Green function. Much as before we write .
The following well known result is sometimes called “Bourgain’s estimate”:
Lemma 9.4**.**
[Bou]**. Let be open with -ADR boundary, , and . Then
[TABLE]
where depends on and the -ADRity constant of .
The following is also well known.
Lemma 9.6**.**
Let be open with -ADR boundary. Let be such . Then,
[TABLE]
We remark that the previous lemma is also valid in the case without the -ADR assumption. In the case this holds under the -ADR assumption, and also in the more general situation where satisfies the CDC. This follows easily from [AH, Lemmas 3.4 and 3.5]. Notice that -ADR implies the CDC in (for any ), by standard arguments.
The following lemma is also known. See [HLMN, Lemma 3.14], for example.
Lemma 9.7**.**
Let be open with -ADR boundary and let . Let be a ball centered at such that . Then
[TABLE]
Lemma 9.8**.**
Let be open with -ADR boundary. Let and . Let be a non-negative harmonic function in and continuous in such that in . Then extending by [math] in , there exists a constant such that, for all ,
[TABLE]
where and depend on and the AD-regularity of . In particular,
[TABLE]
The next result provides a partial converse to Lemma 9.6.
Lemma 9.9**.**
Let be open with -ADR boundary. Let and let be such that . Suppose that . Then there exists some such that
[TABLE]
and
[TABLE]
Proof.
For a given to be fixed below, we can pick with such that
[TABLE]
Let be a function supported in , on , and such that . Then, choosing small enough so that , say, and applying Caccioppoli’s inequality,
[TABLE]
Applying now Lemmas 9.8 and 9.7 and taking small enough so that , for any we get
[TABLE]
From the estimates above we infer that
[TABLE]
Hence, for small enough, we derive
[TABLE]
which implies the existence of the point required in the lemma. ∎
9.3. Harnack chains and carrots
It will be more convenient for us to work with Harnack chains instead of curves. The existence of a carrot curve is equivalent to having what we call a good chain between points.
Let , be such that , and let . A -good chain (or -good Harnack chain) from to is a sequence of balls (finite or infinite) contained in such that and either
- •
if , or
- •
if , where is the number of elements of the sequence if this is finite,
and moreover the following hold:
- •
for all ,
- •
for all ,
- •
if ,
- •
for each there are at most balls such that .
Abusing language, sometimes we will omit the constant and we will just say “good chain” or “good Harnack chain”.
Observe that in the definitions of carrot curves and good chains, the order of and is important: having a carrot curve from to is not equivalent to having one from to , and similarly with good chains.
Lemma 9.10**.**
There is a carrot curve from to if and only if there is a good Harnack chain from to .
Proof.
Let be a carrot curve from to . We can assume , since if , we can obtain this case by taking a limit of points converging to . Let be a Vitali subcovering of the family and let stand for the radius and for the center of . So the balls are disjoint and cover . Note that for , if ,
[TABLE]
In particular, since the ’s are disjoint, by volume considerations, there can only be boundedly many of radius between and , say. Moreover, we may order the balls so that and is a ball such that and contains the point from which is maximal in the natural order induced by (so that is the minimal point in ). Then for ,
[TABLE]
This implies is a -good chain for a sufficiently big .
Now suppose that we can find a good chain from to , call it . Let be the path obtained by connecting their centers in order. Let . Then there is a such that , the segment joining and . Since is a good chain,
[TABLE]
We would like to note that the implicit constants do not depend on . Indeed, from the properties of the good chain it easily follows that
[TABLE]
Thus, is a carrot curve from to . ∎
10. The Main Lemma for the proof of Theorem 1.6
Because of the absence of doubling conditions on harmonic measure under the weak- assumption, to prove Theorem 1.6 we cannot use arguments similar to the ones in [AH] or [Azz]. Instead, we prove a local result which involves only one pole and one ball which has its own interest. This is the Main Lemma 10.2 below.
Let be a ball centered at and let . We restate Definition 2.20 in the following form: satisfies the weak- condition in if for every there exists such that the following holds: for any subset ,
[TABLE]
In the next sections we will prove the following.
Main Lemma 10.2**.**
Let have -uniformly rectifiable boundary. Let and let be a point such that
[TABLE]
and . Suppose that satisfies the weak- condition in . Then there exists a subset and a constant with such that each point can be joined to by a carrot curve. The constant and the constants involved in the carrot condition only depend on , the weak- condition, and the -UR character of .
The notation stands for “connectable”.
It is easy to check that Theorem 1.6 follows from this result. First notice that the assumptions of the theorem imply that is -uniformly rectifiable by Theorem 9.3. Consider now any and take a point such that . Then we consider the point in the segment such that . By Lemma 9.4, we have
[TABLE]
because . Hence, by covering with cubes contained in with side length comparable to we deduce that at least one these cubes, call it , satisfies . Further, by taking the side length small enough, we may also assume that . Since satisfies the weak- property in (by the assumptions in Theorem 1.6), we can apply the Main Lemma 10.2 above and infer that there exists a subset with such that all can be joined to by a carrot curve, which proves that satisfies the weak local John condition and concludes the proof of Theorem 1.6.
Two essential ingredients of the proof of the Main Lemma 10.2 are a corona type decomposition (whose existence is ensured by the -uniform rectifiability of the boundary) and the Alt-Caffarelli-Friedman monotonicity formula [ACF]. This formula is used in some of the connectivity arguments below. This allows to connect by carrot curves corkscrew points where the Green function is not too small to other corkscrew points at a larger distance from the boundary where the Green function is still not too small (see Lemma 11.11 for the precise statement). The use of the Alt-Caffarelli-Friedman formula is not new to problems involving harmonic measure and connectivity (see, for example, [AGMT]). However, the way it is applied here is new, as far as we know.
Two important steps of the proof of the Main Lemma 10.2 (and so of Theorem 1.6) are the Geometric Lemma 14.5 and the Key Lemma 15.2. An essential idea consists of distinguishing cubes with “two well separated big corkscrews” (see Section 13.4 for the precise definition). In the Geometric Lemma 10.2 we construct two disjoint open sets satisfying a John condition associated to trees involving this type of cubes, so that the boundaries of the open sets are located in places where the Green function is very small. This construction is only possible because the associated tree involves only cubes with two well separated big corkscrews. The existence of these cubes is an obstacle for the construction of carrot curves. However, in a sense, in the Key Lemma 15.2 we take advantage of their existence to obtain some delicate estimates for the Green function on some corkscrew points.
We claim now that to prove he Main Lemma 10.2 we can assume that . To check this, let , , and satisfy the assumptions in the Main Lemma. Consider the open set . Then the harmonic measure in coincides with the harmonic measure in (the fact that is not connected does not disturb us). Thus , , and satisfy the assumptions in the Main Lemma, and moreover . Assuming the Main Lemma to be valid in this particular case, we deduce that there exists a subset and a constant with such that each point can be joined to by a carrot curve in . Now just observe that if is one of this carrot curves and it joints and , then is contained in except for its end-point . By connectivity, since , must be contained in , except for the end-point . Hence, is a carrot curve with respect to .
Sections 11-16 are devoted to the proof of Main Lemma 10.2. To this end, we will assume that .
11. The Alt-Caffarelli-Friedman formula and the existence of short paths
11.1. The Alt-Caffarelli-Friedman formula
Recall the following well known result of Alt-Caffarelli-Friedman (see [CS, Theorems 12.1 and 12.3]):
Theorem 11.1**.**
Let , and let be nonnegative subharmonic functions. Suppose that and that . Set
[TABLE]
and
[TABLE]
Then is a non-decreasing function of and for all . That is,
[TABLE]
Further,
[TABLE]
In the case of equality we have the following result (see [PSU, Theorem 2.9]).
Theorem 11.5**.**
Let and be as in Theorem 11.1. Suppose that for some . Then either one or the other of the following holds:
- (a)
* in or in ;*
- (b)
there exists a unit vector and constants such that
[TABLE]
We will also need the following auxiliary lemma.
Lemma 11.6**.**
Let , and let a sequence of functions which are nonnegative, subharmonic, such that each is harmonic in and . Suppose also that
[TABLE]
for all . Then, for every there exists a subsequence which converges uniformly in and weakly in to some function , and moreover,
[TABLE]
Proof.
The existence of a subsequence converging weakly in and uniformly in to some function is an immediate consequence of the Arzelà-Ascoli and the Banach-Alaoglu theorems. The identity (11.7) is clear when , and quite likely, for this is also well known. However, for completeness, we will show the details (for ).
Consider a non-negative subharmonic function which is harmonic in so that . For and , let be a radial function such that . Let be the fundamental solution of the Laplacian. For , denote . Then we have
[TABLE]
Using the fact that is harmonic in and that since is compactly supported in , on , and is far away from , it follows easily that . On the other hand, we have
[TABLE]
Thus,
[TABLE]
Taking into account that is far away from , letting , we obtain
[TABLE]
Using the preceding identity, it follows easily that
[TABLE]
Indeed, . Also, it is clear that
[TABLE]
Further,
[TABLE]
by the weak convergence of in and the uniform convergence in , since is far away from .
Let be a radial function such that . The same argument as above shows that
[TABLE]
Consequently,
[TABLE]
and also
[TABLE]
Since can be taken arbitrarily small, (11.7) follows. ∎
Lemma 11.8**.**
Let , and let be nonnegative subharmonic functions such that each is harmonic in . Suppose that and that . Assume also that
[TABLE]
For any , there exists some such that if
[TABLE]
with defined in (11.2), then either one or the other of the following holds:
- (a)
* or ;*
- (b)
there exists a unit vector and constants such that
[TABLE]
The constant depends only on .
Proof.
Suppose that the conclusion of the lemma fails. Then, by replacing by , we can assume that and . Let , and for each and , consider functions satisfying the assumptions of the lemma and such that neither (a) nor (b) holds for them. By Lemma 11.6, there exist subsequences (which we still denote by ) which converge uniformly in and weakly in to some functions , and moreover,
[TABLE]
both for and . Clearly, the functions are non-negative, subharmonic, and . Hence, by Theorem 11.5, one of the following holds:
- (a’)
in or in ;
- (b’)
there exists a unit vector and constants such that
[TABLE]
However, the fact that neither (a) nor (b) holds for any pair , , together with the uniform convergence of , implies that neither (a’) nor (b’) can hold, and thus we get a contradiction. ∎
11.2. Existence of short paths
Let and . For , we write if for all ,
[TABLE]
We will see in Section 12 that, under the assumptions of the Main Lemma 10.2, for some big enough,
[TABLE]
Lemma 11.10**.**
Let , , and . Then there exists such that, for some constant ,
- (a)
, and
- (b)
[TABLE]
The constant depends only on , , and , the AD-regularity constant of .
Proof.
This follows easily from Lemmas 9.6 and 9.9. ∎
Lemma 11.11** (Short paths).**
Let , , and for , , let be such that
[TABLE]
Then there exist constants and such that for every , there exists some point such that
[TABLE]
(with as in Lemma 11.10) and such that and can be joined by a curve such that
[TABLE]
The parameters depend only on and the ratio .
Proof.
All the parameters in the lemma will be fixed along the proof. We assume that . First note that we may assume that . Otherwise, we just take a point such that , which clearly satisfies the properties in (11.13). Further, both and belong to the open connected set
[TABLE]
for a sufficiently small . The fact that is connected is well known. This follows from the fact that, for any , any connected component of should contain . Otherwise there would be a connected component where is positive and harmonic with zero boundary values. So, by maximum principle, should equal in the whole component, which is a contradiction. So there is only one connected component.
We just let be a curve contained in . Note that
[TABLE]
for a sufficiently small because, by boundary Hölder continuity,
[TABLE]
if . Further, the fact that ensures that , for a sufficiently big constant depending on .
So from now on we assume that . By Lemma 11.10 we know there exists some point such that
[TABLE]
with depending on and .
Assume that and cannot be joined by a curve as in the statement of the lemma. Otherwise, we choose and we are done. For , consider the open set
[TABLE]
We fix small enough such that . Such exists by (11.12) and (11.14), and it may depend on .
Let and be the respective components of to which and belong. We have
[TABLE]
because otherwise there is a curve contained in which connects and , and further this is far away from . Indeed, we claim that
[TABLE]
To see this, note that by the Hölder continuity of in , for all , we have
[TABLE]
where in the last inequality we used Lemma 9.7 and that . This yields our claim.
Next we wish to apply the Alt-Caffarelli-Friedman formula with
[TABLE]
It is clear that both satisfy the hypotheses of Theorem 11.1. For and , we denote
[TABLE]
so that . We claim that:
- (i)
for and .
- (ii)
for .
The condition (i) follows from (11.4) and the fact that
[TABLE]
which holds by Lemma 9.7 and subharmonicity, since . Concerning (ii), note first that
[TABLE]
where we first used Cauchy estimates and then the pointwise bounds of in (11.16) with . Thus, using also that , we infer that in some ball with possibly depending on . Analogously, we deduce that in some ball . Let be the largest open ball centered at not intersecting and let . Then, by considering the convex hull of and and integrating in spherical coordinates (with the origin in ), one can check that
[TABLE]
An analogous estimate holds for , and then it easily follows that
[TABLE]
which implies (ii). We leave the details for the reader.
From the conditions (i) and (ii) and the fact that is non-decreasing we infer that
[TABLE]
and also
[TABLE]
Assume that for some big . Since is non-decreasing we infer that there exists some such that
[TABLE]
because otherwise, by iterating the reverse inequality, we get a contradiction. Now from Lemma 11.8 we deduce that, given any , for big enough, there are constant and a unit vector such that
[TABLE]
As a matter of fact, by (11.4), (11.17), and (11.16); by Lemma 9.8; and the option (a) in Lemma 11.8 cannot hold (since we have ).
In particular, for small, (11.18) implies that if , then one has , and also that
[TABLE]
Thus and so is at a distance at least from , and also
[TABLE]
Further, since and are both in by definition, there is a curve which joins and contained in satisfying
[TABLE]
by (11.15). So satisfies all the required properties in the lemma and we are done. ∎
12. Types of cubes
From now on we fix and and we assume that we are under the assumptions of the Main Lemma 10.2.
We need now to define two families and of high density and low density cubes, respectively. Let be some fixed constant. We denote by (high density) the family of maximal cubes which are contained in and satisfy
[TABLE]
We also denote by (low density) the family of maximal cubes which are contained in and satisfy
[TABLE]
(notice that by assumption). Observe that the definition of the family involves the density of , while the one of involves the density of .
We denote
[TABLE]
Lemma 12.1**.**
We have
[TABLE]
Proof.
By Vitali’s covering theorem, there exists a subfamily so that the cubes , , are pairwise disjoint and
[TABLE]
Then, since is doubling, we obtain
[TABLE]
Next we turn our attention to the low density cubes. Since the cubes from are pairwise disjoint, we have
[TABLE]
∎
From the above estimates and the fact that the harmonic measure belongs to weak- (cf. (10.1)), we infer that if is chosen big enough, then
[TABLE]
and thus
[TABLE]
As a consequence, denoting , we deduce that
[TABLE]
which implies that
[TABLE]
again using the fact that belongs to weak- in . So we have:
Lemma 12.2**.**
Assuming big enough, the set satisfies
[TABLE]
with the implicit constants depending on and the weak- condition in .
We denote by the family of those cubes which are not contained in . In particular, such cubes do not belong to and
[TABLE]
From this fact, it follows easily that is contained in the set defined in Section 11.2, assuming big enough, and so Lemma 12.2 ensures that (11.9) holds.
The following lemma is an immediate consequence of Lemma 11.10.
Lemma 12.4**.**
For every cube there exists some point such that and
[TABLE]
for some , which depend on and on the weak- constants in .
If and , we say that is -corkscrew for . If (12.5) holds, we say that is a -good corkscrew for . Abusing notation, quite often we will not write “for ”.
We will need the following auxiliary result:
Lemma 12.6**.**
Let and let be a -good -corkscrew, for some . Suppose that . Then there exists some -good Harnack chain that joins and , with depending on .
Proof.
Consider the open set . This is connected and thus there exists a curve that connects and . By Hölder continuity, any point such that , satisfies
[TABLE]
Since for all , we then deduce that for some depending on and . Thus,
[TABLE]
From the fact that for all , we infer that any satisfies
[TABLE]
Therefore,
[TABLE]
So for some depending on and . Next we consider a Besicovitch covering of with balls of radius . By volume considerations, it easily follows that the number of balls is bounded above by some constant depending on and , and thus this is a -good Harnack chain, with . ∎
Lemma 12.7**.**
There exists some constant with such that the following holds for all . Let , , and let be a -good -corkscrew. Then there exists some cube with and and a -good -corkscrew such that and can be joined by a -good Harnack chain, with and depending on .
The proof below yields a constant . On the other hand, the lemma ensures that is still a -corkscrew, which will be important for the arguments to come.
Proof.
This follows easily from Lemma 11.11. For completeness we will show the details.
By choosing big enough, and thus there exists some . We let
[TABLE]
where is defined in Lemma 12.4 and in Lemma 11.10 (and thus it depends only on and ). We apply Lemma 11.11 to , , with , , and . To this end, note that
[TABLE]
Hence there exists such that
[TABLE]
and such that and can be joined by a curve such that
[TABLE]
with depending on . Now let be the cube containing such that
[TABLE]
Observe that
[TABLE]
Also, we may assume that because otherwise we have and then the statement in the lemma follows from Lemma 12.6. So we have .
From (12.8) we get
[TABLE]
and
[TABLE]
Hence, is a -good -corkscrew, for .
From (12.9) and arguing as in the end of the proof of Lemma 12.6 we infer that and can be joined by a -good Harnack chain. ∎
From now on we will assume that all corkscrew points for cubes are -corkscrews, unless otherwise stated.
13. The corona decomposition and the Key Lemma
13.1. The corona decomposition
Recall that the coefficient of a ball was defined in (9.1). For each , we denote
[TABLE]
Now we fix a constant . Given , we denote by the maximal family of cubes satisfying that either or b\beta\bigl{(}{\widehat{Q}}\bigr{)}>\varepsilon, where is the parent of . Recall that the family was defined in (12.3). Note that, by maximality, is a family of pairwise disjoint cubes.
We define
[TABLE]
In particular, note that .
We now define the family of the top cubes with respect to as follows: first we define the families for inductively. We set
[TABLE]
Assuming that has been defined, we set
[TABLE]
and then we define
[TABLE]
Notice that the family of cubes with which are not contained in any cube is contained in , and this union is disjoint. Also, all the cubes in that union belong to .
The following lemma is an easy consequence of our construction. Its proof is left for the reader.
Lemma 13.1**.**
We have
[TABLE]
Also, for each ,
[TABLE]
Further, for all ,
[TABLE]
Remark that the last inequality holds for any cube because its parent belongs to and so is not contained in any cube from , which implies that
Using that is -UR (by the assumption in the Main Lemma 10.2), it is easy to prove that the cubes from satisfy a Carleson packing condition. This is shown in the next lemma.
Lemma 13.2**.**
We have
[TABLE]
Proof.
For each we have
[TABLE]
Then we get
[TABLE]
Note now that, because of the stopping conditions, for all , if , then the parent of satisfies . Hence, by Theorems 9.2 and 9.3,
[TABLE]
On the other hand, the cubes with do not contain any cube from , by construction. Hence, they are disjoint and thus
[TABLE]
By an analogous reason,
[TABLE]
Using (13.3) and the estimates above, the lemma follows. ∎
Given a constant , next we define
[TABLE]
By Chebyshev and the preceding lemma, we have
[TABLE]
Therefore, if is chosen big enough (depending on and the constants on the weak- condition), by Lemma 12.2 we get
[TABLE]
and thus
[TABLE]
We distinguish now two types of cubes from . We denote by the family of cubes such that , and we set . Notice that, by construction, if , then . On the other hand, this estimate may fail if .
13.2. The truncated corona decomposition
For technical reasons, we need now to define a truncated version of the previous corona decomposition. We fix a big natural number . Then we let be the family of the cubes from with side length larger than . Given we let be the subfamily of the cubes from with side length larger than , and we let be a maximal subfamily from , where is the subfamily of the cubes from with side length . We also denote and .
Observe that, since , we also have
[TABLE]
13.3. The Key Lemma
The main ingredient for the proof of the Main Lemma 10.2 is the following result.
Lemma 13.5** (Key Lemma).**
Given and (with as in (12.5)), there exists an exceptional family satisfying
[TABLE]
such that, for every , any -good corkscrew for can be joined to some -good corkscrew for by a -good Harnack chain, with depending on .
This lemma will be proved in the next Sections 14 and 15. Using this result, in Section 16 we will build the required carrot curves for the Main Lemma 10.2, which join the pole to points from a suitable big piece of . If the reader prefers to see how this is applied before its long proof, they may go directly to Section 16. A crucial point in the Key Lemma is that the constant in the definition of the stopping cubes of the corona decomposition does not depend on the constants or above.
To prove the Key Lemma 13.5 we will need first to introduce the notion of “cubes with well separated big corkscrews” and we will split into subtrees by introducing an additional stopping condition involving this type of cubes. Later on, in Section 14 we will prove the “Geometric Lemma”, which relies on a geometric construction which plays a fundamental role in the proof of the Key Lemma.
13.4. The cubes with well separated big corkscrews
Let be a cube such that . For example, might be a cube from , with (which in particular implies that ). We denote by a best approximating -plane for , and we choose and to be two fixed points in such that and lie in different components of . So and are corkscrews for . We will call them “big corkscrews”.
Since any corkscrew for satisfies and we have chosen , it turns out that
[TABLE]
As a consequence, can be joined either to or to by a -good Harnack chain, with depending only on , and thus only on , and the weak- constants in . The following lemma follows by the same reasoning:
Lemma 13.6**.**
Let be cubes such that and is the parent of . Let , for , be big corkscrews for and respectively. Then, after relabeling the corkscrews if necessary, can be joined to by a -good Harnack chain, with depending only on .
Given , we will write (or just , which stands for “well separated big corkscrews”) if and the big corkscrews , can not be joined by any -good Harnack chain. The parameter will be chosen below. For the moment, let us say that . The reader should think that in spite of , the possible existence of “holes of size in ” makes possible the connection of the big corkscrews by means of -Harnack chains passing through these holes. Note that if and , then any pair of corkscrews for can be connected by a -good Harnack chain, since any of these corkscrews can be joined by a good chain to one of the big corkscrews for , as mentioned above.
13.5. The tree of cubes of type and the subtrees
Given , denote by the maximal subfamily of cubes which satisfy that either
- •
, or
- •
.
Also, denote by the cubes from which are not contained in any cube from . So this tree is empty if . Notice also that .
Observe that if , it may happen that . However, unless , it holds that , with depending only on and (because the parent of belongs to ).
For each , we denote
[TABLE]
So we have
[TABLE]
and the union is disjoint. Observe also that we have the partition
[TABLE]
14. The geometric lemma
14.1. The geometric lemma for the tree of cubes of type
Let and suppose that . We need now to define a family of cubes from , which in a sense can be considered as a regularized version of . The first step consists of introducing the following auxiliary function:
[TABLE]
Observe that is -Lipschitz.
For each we take the largest cube such that and
[TABLE]
We consider the collection of the different cubes , , and we denote it by .
Lemma 14.2**.**
Given , the cubes from are pairwise disjoint and satisfy the following properties:
- (a)
If and , then .
- (b)
There exists some absolute constant such that if and , then
- (c)
For each , there at most cubes such that where is some absolute constant.
- (d)
*If and , then there exists some such that and . *
Proof.
The proof is a routine task. For the reader’s convenience we show the details. To show (a), consider . Since is -Lipschitz and, by definition, , we have
[TABLE]
To prove the converse inequality, by the definition of , there exists some , the parent of , such that
[TABLE]
Also, we have
[TABLE]
Thus,
[TABLE]
The statement (b) is an immediate consequence of (a), and (c) follows easily from (b). To show (d), observe that, for any ,
[TABLE]
Thus,
[TABLE]
In particular, choosing , we deduce
[TABLE]
and thus, using again that , it follows that . Let be such that , and let be the smallest cube such that and . Since and , we deduce that , implying that .
So it just remains to check that . To this end, consider a cube such that
[TABLE]
From the first inequality, it is clear that and then, by the definition of , we infer that . This inclusion and the second inequality above imply that
[TABLE]
By (a) we know that , and so we derive . ∎
Lemma 14.3**.**
Given , if and , then and , with , for some absolute constants .
Proof.
This immediate from the fact that, by (d) in the previous lemma, there exists some cube such that and , so that and . ∎
As in Section 3, we make a standard Whitney decomposition of the open set . With a harmless abuse of notation we let denote a collection of (closed) dyadic Whitney cubes of , so that the cubes in form a pairwise non-overlapping covering of , which satisfy for some and
- (i)
;
- (ii)
;
- (iii)
there are at most cubes such that . Further, for such cubes , we have , where stands for the side length of .
From the properties (i) and (ii) it is clear that . We assume that the Whitney cubes are small enough so that
[TABLE]
To construct this Whitney decomposition one just needs to replace each cube , as in [Ste, Chapter VI], by its descendants , for some fixed .
For each , as much as in Lemma 9.6, we denote by a ball concentric with and radius , where is a universal constant big enough so that
[TABLE]
and whenever . Obviously, the ball intersects , and the family does not have finite overlapping.
Given a bounded measurable set with , and a function , we denote by the mean of in with respect to Lebesgue measure. That is,
[TABLE]
To state the Geometric Lemma we need some additional notation. Given a cube , we denote by the family of cubes from with side length at most which are contained in and are not contained in any cube from . We also denote by the subfamily of the cubes from which are contained in some cube from . Note that is not a tree, in general, but a union of trees. Further, from Lemma 14.2(a), it follows easily that
[TABLE]
Lemma 14.5** (Geometric Lemma).**
Let , and assume that the constant in the definition of is big enough. Let and let be such that , with big enough. Then there are two open sets with disjoint closures which satisfy the following properties:
- (a)
There are subfamilies such that
- (b)
Each contains a ball with , and each corkscrew point for contained in can be joined to the center of by a good Harnack chain contained in . Further, any point can be joined to by a good Harnack chain (not necessarily contained in ).
- (c)
For each Q\in\big{(}{\mathsf{T}}_{{\mathsf{WSBC}}}(R)\cup{\mathsf{Stop}}_{{\mathsf{WSBC}}}(R)\big{)}\cap{\mathcal{D}}(R^{\prime}) there are big corkscrews and , and if is an ancestor of which also belongs to , then can be joined to by a good Harnack chain, for each .
- (d)
.
- (e)
For each such that , let be the family of Whitney cubes such that , so that
[TABLE]
Then
- (i)
[TABLE]
and
- (ii)
[TABLE]
for some universal constant .
The constants involved in the Harnack chain and corkscrew conditions may depend on , , and .555To guarantee the existence of the sets and the fact that they are contained in we use the assumption that .
14.2. Proof of the Geometric Lemma 14.5
In this whole subsection we fix and we assume , as in Lemma 14.5. We let be such that , with big enough, as in Lemma 14.5, and we consider the associated families and .
Remark 14.6*.*
By arguments analogous to the ones in Lemma 14.3, it follows easily that if , for such that , then there exists some cube such that and . This implies that and too.
In order to define the open sets , described in the lemma, first we need to associate some open sets , to each . We distinguish two cases:
- •
For , we let be the family of Whitney cubes which intersect
[TABLE]
and are contained in the same connected component of as , and then we set
[TABLE]
- •
For the definition of is more elaborated. First we consider an auxiliary ball , concentric with , such that and having thin boundaries for . This means that, for some absolute constant ,
[TABLE]
The existence of such ball follows by well known arguments (see for example [To, p.370]).
Next we denote by the family of Whitney cubes which intersect and satisfy for depending on (the reader should think that and that for some ), and we set
[TABLE]
For a fixed or , let be the connected components of which satisfy one of the following properties:
- –
either (recall that is a big corkscrew for ), or
- –
there exists some such that and there is a -good Harnack chain that joins to , for some constant to be chosen below.
Then we let . After reordering the sequence, we assume that . We let be the subfamily of cubes from contained in .
In the case , from the definitions, it is clear that the sets are open and connected and
[TABLE]
In the case , the sets may fail to be connected. However, (14.9) still holds if is chosen big enough (which will be the case). Indeed, if some component can be joined by -good Harnack chains both to and , then there is a -good Harnack chain that joins to , and thus does not belong to if is taken big enough, which cannot happen by Lemma 14.3. Note also that the two components of
[TABLE]
are contained in , because and we assume .
The following is immediate:
Lemma 14.10**.**
Assume that we relabel appropriately the sets and corkscrews for . Then for all such that is the parent of we have
[TABLE]
Further,
[TABLE]
where depends at most on and .
The labeling above can be chosen inductively. First we fix the sets and corkscrews for every maximal cube from (contained in and with side length equal to ). Further we assume that, for any maximal cube , the corkscrew is at the same side of as , for each (this property will be used below). Later we label the sons of each so that (14.11) holds for any son of . Then we proceed with the grandsons of , and so on. We leave the details for the reader.
The following result will be used later to prove the property (e)(i).
Lemma 14.12**.**
Suppose that the constant in Lemma 14.5 is big enough. Let and assume small enough and big enough in the definition of . If satisfies , then .
Recall is the ball with thin boundary appearing in (14.7).
Proof.
By the definition of , it suffices to show that belongs to some component and that there is a -good Harnack chain that joins to . To this end, observe that by the boundary Hölder continuity of ,
[TABLE]
where in the last inequality we used Lemma 9.7. Thus,
[TABLE]
and if is small enough, then belongs to some connected component of the set in (14.8). By Lemma 14.2(d) there is a cube such that and . In particular, and thus, by applying Lemma 11.11 with and (for a suitable ), it follows that there exists a -corkscrew , with say, such that can be joined to by a -good Harnack chain. Assuming that the constant in Lemma 14.5 is big enough, it turns out that for some such that . Since all the cubes such that satisfy , by applying Lemma 13.6 repeatedly, it follows that can be joined either to or by a -good Harnack chain. Then, joining both Harnack chains, it follows that can be joined either to or by a -good Harnack chain. So belongs to one of the components , assuming big enough. ∎
From now on we assume small enough and big enough so that the preceding lemma holds. Also, we assume . We define
[TABLE]
Next we will show that
[TABLE]
Since the number of cubes is finite (because of the truncation in the corona decomposition), this is a consequence of the following:
Lemma 14.13**.**
Suppose is big enough in the definition of (depending on ). For all , we have
[TABLE]
Proof.
We suppose that We also assume that and then we will get a contradiction. Notice first that if for some , then the corkscrews and are at the same side of for each . This follows easily by induction on .
Case 1. Suppose first that . Since the cubes from have side length at least , it follows that at least one of the cubes from has side length at least , which implies that , by the construction of .
Since , there exists some curve that joins and such that because all the cubes from have side length at least , and the ones from have side length .
Let be the ancestor of such that . From the fact that , we deduce that and thus , and so . This implies that is in the same connected component as and also that , because and they are at the same side of .
Consider now the chain , so that is the parent of . Form the curve with endpoints and by joining the segments . Since these segments satisfy
[TABLE]
it is clear that .
Next we form a curve which joins to by joining , , and . It follows easily that this is contained in and that . However, this is not possible because and are in different connected components of and (since we assume ).
Case 2. Suppose now that . The arguments are quite similar to the ones above. In this case, the cubes from have side length at least and thus at least one of the cubes from has side length at least , which implies that .
Now there exists a curve that joints and such that because all the cubes from have side length at least , and the ones from have side length .
We consider again cubes and defined exactly as above. By the same reasoning as above, . We also define the curve which joins to in the same way. In the present case we have
[TABLE]
Again construct a curve which joins to by gathering , , and . This is contained in (for some possibly depending on ) and satisfies . From this fact we deduce that and can be joined by -good Harnack chain. Taking big enough (depending on ), this implies that the big corkscrews for can be joined by a -good Harnack chain, which contradicts Lemma 14.3.
Case 3. Finally suppose that . We consider the same auxiliary cube and the same curve satisfying . By joining the segments , we construct a curve analogous to from the case 2, so that this joins to and satisfies .
We construct a curve that joins to by joining , , and . Again this is contained in and it holds . This implies that and can be joined by -good Harnack chain. Taking big enough, we deduce the big corkscrews for can be joined by a -good Harnack chain, which is a contradiction. ∎
By the definition of and it is clear that the properties (a), (b) and (c) in Lemma 14.5 hold. So to complete the proof of the lemma it just remains to prove (d) and (e).
Proof of Lemma 14.5(d).
Let . We have to show that there exists some such that . To this end we consider such that . Since , it follows that . Let be such that . Observe that
[TABLE]
We claim that . Indeed, if , taking also into account (14.14), there exists some ancestor of contained in such that and . From the fact that we deduce that . By the construction of the sets , it is immediate to check that the condition that implies that . Thus and so (for this identity we use that ), which is a contradiction. ∎
To show (e), first we need to prove the next result:
Lemma 14.15**.**
For each , we have
[TABLE]
Proof.
Clearly, we have
[TABLE]
So it suffices to show that
[TABLE]
Let , with , . From the definition of , it follows easily that
[TABLE]
On the other hand, by Lemma 14.5(d), there exists some such that . By the definition of , since , it also follows easily that
[TABLE]
Hence, and so
[TABLE]
We claim that . Indeed, from the fact that , we infer that
[TABLE]
Suppose that . This implies that . Consider now a cube belonging to . Since , by Lemma 14.2 (b) we have
[TABLE]
which proves our claim. Together with (14.17) and (14.18), this yields
[TABLE]
which is a contradiction for small enough. So there does not exist any , which proves (14.16). ∎
Proof of Lemma 14.5(e).
Let be such that . The statement (i) is an immediate consequence of Lemma 14.12. In fact, this lemma implies that any such that is contained in and thus in . In particular, . Thus, if , then
[TABLE]
It is easy to check that this implies the statement (i) in Lemma 14.5(e) (possibly after replacing by ).
Next we turn our attention to (ii). To this end, denote by the subfamily of the cubes such that . By Lemma 14.15,
[TABLE]
We will show that
[TABLE]
where is the family of Whitney cubes such that . To this end, observe that, by (14.19) and the construction of , for each there exists some such that and either or . Using the -ADRity of , it is immediate to check that for each ,
[TABLE]
Also,
[TABLE]
Since the number of cubes is uniformly bounded (by Lemma 14.2(b)) and , the above inequalities yield the first estimate in (14.20).
To prove the second one we also distinguish among the two types of cubes above. First, by the bounded overlap of the balls such that , we get
[TABLE]
since the balls in the sum are contained for a suitable universal constant . To deal with the cubes such that we intend to use the thin boundary property of in (14.7). To this end, we write
[TABLE]
where stands for the -neighborhood of . By (14.7) it follows that
[TABLE]
and thus
[TABLE]
for a suitable . Together with (14.21), this yields the second inequality in (14.20), which completes the proof of Lemma 14.5(e). ∎
15. Proof of the Key Lemma
We fix and a corkscrew point as in the preceding sections. We consider and we assume , as in Lemma 14.5. We let be such that , with big enough. Given and , we set
[TABLE]
so that by Lemma 12.4, . Here we are assuming that the corkscrews belong to the set from Lemma 14.5, that is small enough, and we are taking into account that, by the arguments in Section 13.4, any corkscrew for can be joined to one of the big corkscrews by some -good Harnack chain.
Lemma 15.2** (Baby Key Lemma).**
Let be as above. Given , define also as above. For a given , suppose that
[TABLE]
If is small enough in the definition of in Lemma 14.5 (depending on and ), then
[TABLE]
Remark that depends on (see Lemma 14.5), and thus the families , , also depend on . The reader should thing that as .
A key fact in this lemma is that the constants can be taken arbitrarily small, without requiring as . Instead, the lemma requires , which does not affect the packing condition in Lemma 13.2.
We denote
[TABLE]
with as in the Lemma 14.5. That is, is the family of Whitney cubes such that . So the family contains Whitney cubes which intersect the boundaries of or and are close to .
Let us introduce some extra piece of notation. Given and we let
[TABLE]
To prove Lemma 15.2, first we need the following auxiliary result.
Lemma 15.3**.**
Let be as above and, for or , let . Let be as in Lemma 14.5 and let be a corkscrew point for which belongs to . Denote and for set
[TABLE]
Then we have
[TABLE]
Let us note that the fact that is a corkscrew for contained in implies that , by the construction of the sets in Lemma 14.5.
Proof.
We fix , for definiteness. Recall that . For each , consider a smooth function such that with and
[TABLE]
It follows that and so and also
[TABLE]
Let be a smooth function such that , with . Then we set
[TABLE]
So is smooth, and it satisfies
[TABLE]
Observe that, in a sense, is a smooth version of the function .
Since and is a continuous function from , we have
[TABLE]
First we estimate . For with , we consider a smooth function such that , with . Since , we have
[TABLE]
To deal with we use the fact that for we have
[TABLE]
Then we get
[TABLE]
Let us turn our attention to . We denote . Integrating by parts, we get
[TABLE]
Observe now that the first integral vanishes because and vanishes at and at . Hence, since , we derive
[TABLE]
To estimate we take into account that , and then we derive
[TABLE]
Using now that, for in the domain of integration,
[TABLE]
we obtain
[TABLE]
From the above estimates we infer that
[TABLE]
Since neither nor depend on , letting we get
[TABLE]
We denote
[TABLE]
[TABLE]
and
[TABLE]
Next we split the last integral as follows:
[TABLE]
Concerning , we have
[TABLE]
Thus, using also that outside ,
[TABLE]
Regarding , using Cauchy-Schwarz, we get
[TABLE]
To estimate the integral , we take into account that, for all ,
[TABLE]
Then we deduce
[TABLE]
Next we estimate the integral . By covering by a finite family of balls of radius and applying Caccioppoli’s inequality to each one, it follows that
[TABLE]
Since
[TABLE]
we get
[TABLE]
So we obtain
[TABLE]
By interchanging, and , it is immediate to check that an analogous estimate holds for the second summand on the right hand side of (15.6). Thus we get
[TABLE]
Concerning , we just take into account that in , and then we obtain
[TABLE]
Together with (15.4), (15.5), and (15.7), this yields the lemma. ∎
Proof of Lemma 15.2.
We fix , for definiteness. By a Vitali type covering theorem, there exists a subfamily such that the balls are disjoint and
[TABLE]
By Lemma 15.3, for each we have
[TABLE]
with . Since , we derive
[TABLE]
Estimate of
We have
[TABLE]
Note now that
[TABLE]
where we used the fact that the cubes , with , are pairwise disjoint. Since , we derive
[TABLE]
Estimate of
First we estimate by applying Lemma 9.7:
[TABLE]
So we have
[TABLE]
Estimate of
Note first that, for each , since , using the subharmonicity of and in , and Caccioppoli’s inequality,
[TABLE]
By very similar estimates, we also get
[TABLE]
Recall now that, by Lemma 14.5(e)(i),
[TABLE]
for each , with such that .
We distinguish two types of Whitney cubes . We write if for some such that and , and we write otherwise (there may exist more than one such that , but if , then ). So we split
[TABLE]
Concerning the sum we have
[TABLE]
Next we take into account that
[TABLE]
where stands for the center of and is some absolute constant. This follows from Lemma 9.7 if is far from , and it can be deduced from Lemma 9.4 when is close to (in this case, ). Then we derive
[TABLE]
Since for each , we get
[TABLE]
By Lemma 14.5(e)(ii), we have , and so we deduce
[TABLE]
Next we turn our attention to the sum in (15). Recall that
[TABLE]
Let us remark that we assume the condition that for some such that to be part of the definition of . Using the estimate , we derive
[TABLE]
To estimate the term we take into account that if and , then and thus because . As a consequence, and also, by the Hölder continuity of , if we let be a ball concentric with with radius comparable to and such that , we obtain
[TABLE]
where is the exponent of Hölder continuity. Hence,
[TABLE]
By Lemma 14.5(e)(ii), we have , and using also that, for as above, for some absolute constant , we obtain
[TABLE]
Finally, we turn our attention to the term . We have
[TABLE]
We claim now that, in the last sum, if one assumes that , then . To check this, take such that . Then note that
[TABLE]
Using that , , and , we get
[TABLE]
which implies that
[TABLE]
and yields our claim.
Taking into account that the balls are disjoint and the Hölder continuity of , for all we get
[TABLE]
Thus,
[TABLE]
Recalling again that , we deduce
[TABLE]
Remark that for the second inequality we took into account that is contained in a cube of the form with and , by Lemma 14.2. This implies that .
Gathering the estimates above and recalling (15.8), we deduce
[TABLE]
So, if and are small enough (depending on ), we infer that
[TABLE]
That is, there exists some with such that
[TABLE]
with depending on . Since and can be joined by a -good Harnack chain (for some depending on and , and thus on ), we deduce that
[TABLE]
as wished. ∎
Lemma 15.10**.**
Let and . Choose small enough as in Lemma 15.2 with . Assume that the family is defined by choosing big enough depending on (and thus on and ) as in Lemma 14.5. Let and suppose that . Then, there exists an exceptional family satisfying
[TABLE]
such that, for every , any -good corkscrew for can be joined to some -good corkscrew for by a -good Harnack chain, with depending on .
Proof.
For any , with , we define as in (15.1), so that
[TABLE]
For each , we set
[TABLE]
That is, for fixed or , if , then all the cubes from belong to . In this way, it is clear that
[TABLE]
We claim that the -good corkscrews of cubes from can be joined to some -good corkscrew for by a -good Harnack chain, with depending on , and depending on and thus on too. Indeed, if and is -good corkscrew belonging to (we use the notation of Lemma 15.2 and 14.5), then by the definition above and thus Lemma 15.2 ensures that . So is a -good corkscrew, which by Lemma 14.5(c) can be joined to by a -good Harnack chain. In turn, this -good corkscrew for can be joined to some -good corkscrew for by a -good Harnack chain, by applying Lemma 13.6 times, with depending on and thus on and .
On the other hand, the cubes which are not contained in any cube satisfy , and then, arguing as above, their associated -good corkscrews can be joined to some -good corkscrew for by a -good Harnack chain, by applying Lemma 13.6 at most times. Hence, if we define
[TABLE]
taking into account (15.11), the lemma follows. ∎
Proof of the Key Lemma 13.5.
We choose as in Lemma 15.10 and we consider the associated family . In case that , we set . Otherwise, we consider the family from Lemma 15.10, and we define
[TABLE]
It may be useful for the reader to compare the definition above with the partition of in (13.7). By Lemma 15.10 we have
[TABLE]
Next we show that for every , any -good corkscrew for can be joined to some -good corkscrew for by a -good Harnack chain. In fact, if , then since such cube cannot belong to for any (recall the partition (13.7)), and thus the existence of such Harnack chain is ensured by Lemma 15.10. On the other hand, if , then is contained in some cube . Consider the chain , so that each is the parent of . For , choose inductively a big corkscrew for in such a way that is at the same side of as the good corkscrew for , and is at the same side of as for each . Using that for all , it easy to check that the line obtained by joining the segments , ,…, is a good carrot curve and so gives rise to a good Harnack chain that joins to . It may happen that is not a -good corkscrew. However, since , it turns out that can be joined to some -good corkscrew for by some -good Harnack chain, with given by (12.5) (and thus independent of and ), because . Note that since , is also a -good corkscrew. In turn, since , can be joined to some -good corkscrew for by another -good Harnack chain. Altogether, this shows that can be connected to some -good corkscrew for by a -good Harnack chain, which completes the proof of the lemma. ∎
Below we will write instead of to keep track of the dependence of this family on the parameters and .
16. Proof of the Main Lemma 10.2
16.1. Notation
Recall that by the definition of in (13.4), for all . For such , let be the smallest cube from that contains , and denote , so that . Next let be such that
[TABLE]
and denote
[TABLE]
Fix
[TABLE]
and set
[TABLE]
and also
[TABLE]
(recall that and were defined in Section 13.2). So if , then coincides the family of sons of , and it this will not be the case, in general. Next we denote by and the respective subfamilies of cubes from and which intersect .
For , we set
[TABLE]
We also denote
[TABLE]
and we let be the subfamily of cubes such that there exists some such that and is not contained in any cube from with .
16.2. Two auxiliary lemmas
Lemma 16.1**.**
The following properties hold for the family :
- (a)
The cubes from are pairwise disjoint and cover , assuming big enough.
- (b)
If , then .
- (c)
Given with (for example, ) and , if is a -good corkscrew point for , then there is a -good Harnack chain that joins to .
Proof.
Concerning the statement (a), the cubes from are pairwise disjoint by construction. Suppose that is not contained in any cube from . By the definition of the family , this implies that all the cubes with containing belong to . However, there are at most cubes of this type, which is not possible if is taken big enough. So the cubes from cover .
The proof of (b) is analogous. Given , all the cubes which contain and have side length smaller or equal that belong to . Hence there at most cubes of this type, because . Thus, .
The statement (c) is an immediate consequence of (b) and Lemma 12.6. ∎
Lemma 16.2**.**
Let for some and let be a -good corkscrew for , with . There exists some constant such if , then there exists some cube such that with a -good corkscrew for such that can be joined to by a -good Harnack chain, with depending on and .
Proof.
We assume small enough. Then we can apply Lemma 12.7 times to get cubes satisfying:
- •
and ,
- •
each has an associated -good corkscrew (with depending on ) and there exists a -good Harnack chain joining and .
Since , at least one of the cubes , say , does not belong to . This implies that for some . Let be the stopping cube that contains . Then Lemma 14.5 ensures that there is a good Harnack chain that connects to some corkscrew for . Notice that because . This implies that . Further, gathering the Harnack chain that joins to and the one that joins to , we obtain the good Harnack chain required by the lemma. ∎
16.3. The algorithm to construct good Harnack chains
We will construct good Harnack chains that join good corkscrews from “most” cubes from that intersect to good corkscrews from cubes belonging to , and then we will join these latter good corkscrews to using the fact that . To this end we choose such that
[TABLE]
and we denote
[TABLE]
(so that ) and we apply the following algorithm: we set , so that (12.5) ensures that for each there exists some good -good corkscrew . For , we perform the following procedure:
(1)
Join -good corkscrews of cubes from such that to -good corkscrews of cubes from by -good Harnack chains, with , so that is an ancestor of . This step can be performed because of Lemma 16.2, with in the lemma. The constants , , and depend on and .
(2)
Set
and join -good corkscrews for all cubes to -good corkscrews for cubes by -good Harnack chains, with , so that is an ancestor of . To this end, one applies Lemma 13.5, which ensures the existence of such Harnack chains connecting -good corkscrew points for cubes from to -good corkscrew points for cubes from . The constants and depend on and .
After iterating the procedure above for and joining some Harnack chains arisen in the different iterations, we will have constructed -good Harnack chains that join -good corkscrew points for all cubes not contained in to -good corkscrews of some ancestors belonging either or, more generally, such that . The constants , , , worsen at each step . However, this is not harmful because the number of iterations of the procedure is at most , and .
Denote by the cubes from which intersect and are not contained in any cube from . By the algorithm above we have constructed good Harnack chains that join -good corkscrew points for all cubes to some -good corkscrew for cubes with . Also, by applying Lemma 16.1 (c) we can connect the -good corkscrew for to by a good Harnack chain.
Consider now an arbitrary point , with . By the definition of and the choice , all the cubes containing with side length smaller or equal than satisfy . Then, by an easy geometric argument (see the proof of Lemma 13.5 for a related one) it is easy to check that there is a good Harnack chain joining any good corkscrew for to . Hence, for all the points there is a good Harnack chain that joins to .
Finally, observe that, for each , by Lemma 13.5,
[TABLE]
Therefore,
[TABLE]
and thus
[TABLE]
This finishes the proof of the Main Lemma 10.2. ∎
Appendix A Some counter-examples
We shall discuss some counter-examples which show that our background hypotheses in Theorem 1.3 (namely, -ADR and interior corkscrew condition) are natural, and in some sense in the nature of best possible. In the first two examples, is a domain satisfying an interior corkscrew condition, such that satisfies exactly one (but not both) of the upper or the lower -ADR bounds, and for which harmonic measure fails to be weak- with respect to surface measure on . In this setting, in which full -ADR fails, there is no established notion of uniform rectifiability, but in each case, the domain will enjoy some substitute property which would imply uniform rectifiability of the boundary in the presence of full -ADR. Moreover, these examples may be constructed in such a way that the failure of the condition (either upper or lower -ADR) can be expressed quantitatively, with a bound that may be taken arbitrarily close to a true -ADR bound; see (A.3) and (A.6) below.
In the last example, we construct an open set with -ADR boundary, and for which weak- with respect to surface measure, but for which the interior corkscrew condition fails, and is not -UR.
Example 1. Failure of the upper -ADR bound. In [AMT1], the authors construct an example of a Reifenberg flat domain for which surface measure is locally finite on , but for which the upper -ADR bound
[TABLE]
fails, and for which harmonic measure is not absolutely continuous with respect to . Note that the hypothesis of Reifenberg flatness implies in particular that and are both NTA domains, hence both enjoy the corkscrew condition, so by the relative isoperimetric inequality, the lower -ADR bound
[TABLE]
holds. Thus, it is the failure of (A.1) which causes the failure of absolute continuity: in the presence of (A.1), the results of [DJ] apply, and one has that , and that satisfies a “big pieces of Lipschitz graphs” condition (see [DJ] for a precise statement), and hence is -UR. We note that by a result of Badger [Bad], a version of the Lipschitz approximation result of [DJ] still holds for NTA domains with locally finite surface measure, even in the absence of the upper -ADR condition.
In addition, given any , the construction in [AMT1] can be made in such a way that (A.1) fails “within ”, i.e., so that
[TABLE]
Let us sketch an argument to explain why this is so; we refer the interested reader to [AMT1] for more details.
The domain in [AMT1] is obtained by enlarging a Wolff snowflake, that we will denote here by . Both and are -Reifenberg flat, with as small as wished in the construction (recall that Wolff snowflakes can be taken -Reifenberg flat, with as small as wished).
It is shown in [AMT1, Theorem 3.1] that for all and ,
[TABLE]
where is some measure supported on satisfying for all in some compact set , and some In the construction in [AMT1] , the authors take , the harmonic measure for . Further, from results of Kenig and Toro it follows that harmonic measure in a -Reifenberg flat domain satisfies
[TABLE]
with as (see [KT, Theorem 4.1]). As a consequence, the measure satisfies
[TABLE]
with as small as wished depending on . From (A.4), it follows that
[TABLE]
Example 2. Failure of the lower -ADR bound. In [ABHM, Example 5.5], the authors give an example of a domain satisfying the interior corkscrew condition, whose boundary is rectifiable (indeed, it is contained in a countable union of hyperplanes), and satisfies the upper -ADR condition (A.1), but not the lower -ADR condition (A.2), but for which surface measure fails to be absolutely continuous with respect to harmonic measure, and in fact, for which the non-degeneracy condition
[TABLE]
fails to hold uniformly for , for any fixed positive and , and therefore cannot be weak- with respect to . We note that in the presence of the full -ADR condition, if were contained in a countable union of hyperplanes (as it is in the example), then in particular it would satisfy the “BAUP” condition of [DS2], and thus would be -UR [DS2, Theorem I.2.18, p. 36].
Moreover, given any , the parameters in the example of [ABHM] can be chosen in such a way that the lower ADR bound fails “within ”, i.e., so that
[TABLE]
To see this, we proceed as follows. We follow closely the construction in [ABHM, Example 5.5], with some modification of the parameters. Fix , and set
[TABLE]
For , and , set
[TABLE]
where for , is the usual -disk of radius centered at . Define
[TABLE]
each of which is clearly open and connected. Notice that satisfies the interior Corkscrew condition (since the sets are located at heights which are sufficently separated). Moreover, it is easy to see that satisfies the upper ADR condition and that .
On the other hand, the lower ADR bound fails. To see this, let , and choose and such that . Set , and observe that as , or equivalently
[TABLE]
where has radius , and . We shall show that this behavior is in fact typical, and that (A.6) holds, with in place of .
Let and denote harmonic measure for the domains and respectively.
Claim. , with . Thus, in particular (A.5) fails.
It remains to verify (A.6), and the claim. As regards the former, note that for , we have the trivial standard lower -ADR bound , whereas for , we have
[TABLE]
The first and fourth of these estimates are of course the standard lower -ADR bound. For , the second estimate is bounded below by , and in turn, with , the second and third estimates are therefore bounded below by
[TABLE]
which yields (A.6) with in place of .
Let us now prove the claim. We first recall some definitions. Given an open set , and a compact set , we define the capacity of relative to as
[TABLE]
Also, the inhomogeneous capacity of is defined as
[TABLE]
Combining [HKM, Theorem 2.38], [AH, Theorem 2.2.7] and [AH, Theorem 4.5.2] we have that if is a compact subset of , where is a ball with radius smaller than , then
[TABLE]
where the implicit constants depend only on , the sup runs over all Radon positive measures supported on , for which
[TABLE]
Fix , and set
[TABLE]
by definition of . Our next goal is to show that
[TABLE]
For a fixed and , write , set and note that for , similarly to (A.7), we have
[TABLE]
To compute for write
[TABLE]
Then, since ,
[TABLE]
Furthermore, the last two estimates in (A.10) easily imply that and hence for every . This, (A.8), and (A.10) imply as desired (A.9):
[TABLE]
Set
[TABLE]
and observe that for ,
[TABLE]
Recall that , and define
[TABLE]
Observe that since is ADR (constants depend on but we just use this qualitatively) and is a Lipschitz function on . Fix and let be such that . Let , which is an open connected bounded set. We can now apply the usual capacitary estimates (see, e.g., [HKM, Theorem 6.18]) to find a constant such that
[TABLE]
where we have used (A.9), the definition of , and the fact that on . Note that the last estimate holds for any and therefore, by the maximum principle,
[TABLE]
In particular, if we set , then by another application of the maximum principle,
[TABLE]
as , and the claim is established.
Example 3. Failure of the interior corkscrew condition. The example is based on the construction of Garnett’s 4-corners Cantor set (see, e.g., [DS2, Chapter 1]). Let be a unit square positioned with lower left corner at the origin in the plane, and in general for each , we let be the unit square positioned with lower left corner at the point on the -axis. Set . Let be the first stage of the 4-corners construction, i.e., a union of four squares of side length 1/4, positioned in the corners of the unit square , and similarly, for each , let be the -th stage of the 4-corners construction, positioned inside . Note that for every . Set . It is easy to check that is -ADR, and that the non-degeneracy condition (A.5) holds in for some uniform positive and , and thus by the criterion of [BL], weak-. On the other hand, the interior corkscrew condition clearly fails to hold in (it holds only for decreasingly small scales as increases), and certainly cannot be -UR: indeed, if it were, then would be -UR, with uniform constants, for each , and this would imply that itself was -UR, whereas in fact, as is well known, it is totally non-rectifiable. One can produce a similar set in 3 dimensions by simply taking the cylinder . Details are left to the interested reader.
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