On syntomic complex with modulus for semi-stable reduction case
Kento Yamamoto

TL;DR
This paper introduces a syntomic complex for modulus pairs involving semi-stable families and computes its cohomology sheaves, advancing the understanding of p-adic cohomology in algebraic geometry.
Contribution
It defines a new syntomic complex for modulus pairs with semi-stable reduction and calculates its cohomology sheaves, extending existing theories.
Findings
Cohomology sheaves of the syntomic complex are explicitly computed.
The syntomic complex is defined for semi-stable families with divisors.
The work advances p-adic cohomology theories for algebraic varieties.
Abstract
In this paper, we define syntomic complex for modulus pair (X,D), where X is regular semi-stable family and D is an effective Cartier divisor on X. We compute its cohomology sheaves.
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Taxonomy
TopicsAlgebraic Geometry and Number Theory · Advanced Algebra and Geometry · Algebraic structures and combinatorial models
On syntomic complex with modulus for semi-stable reduction case
Kento Yamamoto
Department of Mathematics,Chuo University 1-13-27 Kasuga, Bunkyo-Ku, Tokyo 112-8551, Japan
Abstract.
In this paper, we define syntomic complex for modulus pair , where is regular semi-stable family and is an effective Cartier divisor on . We compute its cohomology sheaves.
Key words and phrases:
syntomic complex with modulus
2010 Mathematics Subject Classification:
14F30
Contents
1. Introduction
In their paper [KMSY], Bruno Kahn, Hiroyasu Miyazaki, Shuji Saito and Takao Yamazaki study to construct a triangulated category of motives with modulus over a field that extends Voevodsky’s category with non -homotopy invariant property. While the Voevodsky’s category is constructed from smooth -varieties, the category of motives with modulus is expected to be constructed from proper modulus pairs , that is, pairs of a proper -variety and an effective divisor on such that is smooth.
Let be a -adic field, and let be its valuation ring with the residue field. Let be a regular semistable family over and put . Let be an effective Cartier divisor which is flat over and such that has normal crossings on . The first aim of this paper is to define the syntomic complex with modulus for such pairs () for and , which is a generalization of Tsuji’s syntomic complex (cf. [Ka1], [Ka2], [Ku], [Tsu1], [Tsu2], [Tsu3] etc.). More explicitly, we have . In [Tsu1], [Tsu2] and [Tsu3], Tsuji constructed the symbol map
[TABLE]
and proved the surjectivity of this map. The second aim of this paper is to construct a symbol map for and to investigate its surjectivity. We will prove the following main result:
Theorem 1.1**.**
(Theorem 3.7)* Let be an integer. If , , the cokernel of the symbol map*
[TABLE]
is Mittag-Leffler zero with respect to the multiplicities of the prime components of . Here , and is the definition ideal of ; denotes the log structure on associated with , and is the inverse image of onto .
In fact, the cokernel of is non-zero unless is zero or reduced, and deeply depends on the multiplicities of the prime components of . Nevertheless our main result asserts that those cokernels are Mittag-Leffler zero as a projective system. A key fact to understand this phenomenon is a Cartier inverse isomorphism in a modulus situation (see Lemma 3.3 below). From this key lemma, we will obtain an explicit description of the cokernel of the symbol map in a sufficiently local situation.
As an application of the subject of this paper, we will consider a -adic étale Tate twists for a modulus pair in a forthcoming paper [Y], which is a generalization of Sato’s -adic étale Tate twists ([Sat]). We will show that our new object is a “dual” of the usual -adic étale Tate twists of .
Notation and conventions.
- (i)
Throughout this paper, denotes a prime number and denotes a henselian discrete valuation field of characteristic [math] whose residue field is a perfect field of characteristic . We write for the integer ring of , and denotes a prime element of . We denote by the completion of with respect to the discrete valuation and by its ring of integers. 2. (ii)
Throughout this paper, we assume that a scheme is always separated over . 3. (iii)
For a scheme , we put . 4. (iv)
Let be a pure-dimensional scheme which is flat of finite type over . We call X a over , if it is regular and evrywhere étale locally isomorphic to
[TABLE]
for some such that .
2. syntomic complex with modulus
In this section, we will define syntomic complex with modulus for .
Setting:
- •
Let be a over . We set and . Let be an effective Cartier divisor on which is flat over and has normal crossings on .
- •
Let be a logarithmic structure on associated with . Let be a logarithmic structure on defined as the restriction of . For , we write for the inverse image of log structure of onto . Let be the reduction mod of .
2.1. Local construction
To define the syntomic complex with modulus in a sufficiently local situation, we assume the existence of the following data:
Assumption 2.1**.**
**
- •
There exist exact closed immersions
[TABLE]
of log schemes for such that and are smooth over , and such that the following diagram is commutative:
[TABLE]
- •
There exist a compatible system of liftings of Frobenius endomorphisms and for each ([Tsu1, p.71, (2.1.1)–(2.1.3)]).
- •
The systems and fit into the following commutative diagram for for each :
[TABLE]
Let be the PD-envelope of in which is compatible with the canonical PD-structure on the ideal (). Let be the PD-envelope of in . By the assumption that is flat over , we have . The morphism induces a lifting of Frobenius of . For , let be the -th devided power of the ideal J_{\mathscr{E}_{n}}:={\rm{Ker}}\Big{(}\mathscr{O}_{\mathscr{E}_{n}}\rightarrow\mathscr{O}_{X_{n}}\Big{)}. For , we put . We put
[TABLE]
which are locally free -modules.
Let us recall that the syntomic complex is defined as follows:
[TABLE]
for (cf. [Tsu1], [Tsu2], [Tsu3]).
Proposition 2.2**.**
([AS, Proposition 2.2.10])* For , there is a short exact sequence of complexes on *
[TABLE]
where we abbreviate to .
Definition 2.3**.**
(syntomic complex with modulus, sufficiently local case)
We assume . We define
[TABLE]
under the Assumption 2.1.
Remark 2.4**.**
If we define the syntomic complex , we do not need the assumption that is an effective Cartier divisor on for the global construction of the syntomic complex below. If we calculate the syntomic complex in the local situation, we need the assumption that is an effective Cartier divisor on .
Lemma 2.5**.**
The syntomic complex with modulus is independent of the choice of and .
Proof.
Choose another and , and consider the following commutative diagrams:
[TABLE]
where , , and are exact closed immersions. Let , (resp. , ) denote the PD-envelopes of and (resp. and ). From [Tsu3, Corollary 1.11], we have quasi-isomorphisms
[TABLE]
[TABLE]
We put , , and and morphisms and . Then we have the following commutative diagram of the long exact sequences
[TABLE]
Thus we have an isomorphism i.e., a quasi-isomorphism
[TABLE]
This completes the proof. ∎
2.2. Construction in the general case
We keep the Assumption 2.1. In the general case, we define \mathscr{S}_{n}(q)_{X|D}\in D^{+}\big{(}X_{1,\acute{e}t},\mathbb{Z}/p^{n}\mathbb{Z}\big{)} by gluing the local complexes: We choose a hyper-covering of (resp. of ) in the étale topology and a closed immersions (resp. ), with the property that, for each integer , (resp.
) is an immersion of log schemes and (resp ) is a smooth log scheme over , in such a way that there exists a compatible system of liftings of frobenius (resp. ).
Lemma 2.6**.**
(The functoriality of )* Suppose that we are given two data*
[TABLE]
in Assumption 2.1 which fit into the following commutative squares and a cartesian square:
[TABLE]
[TABLE]
where we assume that and are étale, and that . Then the natural homomorphism of complexes:
[TABLE]
is a quasi-isomorphism for any .
Proof.
We have the following quasi-isomorphisms by using [Tsu3, Corollary 1.11]:
[TABLE]
[TABLE]
Hence we obtain the quasi-isomorphism . ∎
We obtain the complex on by the functoriality of the local syntomic complex with modulus from the above Lemma 2.6.
Definition 2.7**.**
(syntomic complex with modulus, the general case; cf. [Tsu3, p. 540] ) We define the syntomic complex with modulus to be the object
[TABLE]
of , where denotes the canonical morphism of topoi .
Proposition 2.8**.**
The syntomic complex with modulus is independent of the choice of hyper coverings and up to a canonical isomorphism.
Proof.
If we choose another , , , and , then by taking the fiber products
[TABLE]
[TABLE]
[TABLE]
We put , , , the canonical morphism of topoi
[TABLE]
[TABLE]
By using [Tsu3, Corollary1.11], we obtain canonical quasi-isomorphisms
[TABLE]
[TABLE]
[TABLE]
[TABLE]
and a canonical quasi-isomorphisms
[TABLE]
[TABLE]
Hence we obtain
[TABLE]
This quasi-isomorphism satisfies the transitivity because the quasi-isomorphisms and satisfy the transitivity ([Tsu3, p.542, l.7]). This completes the proof. ∎
Lemma 2.9**.**
(cf. Proposition 2.2)* Let be an integer. We have a distinguished triangle*
[TABLE]
Proof.
It is enough to show the existence of the following distinguished triangle
[TABLE]
For in Proposition 2.2, we have the following distinguished triangles:
[TABLE]
[TABLE]
where we abbreviate to and to . Here we put and for simplicity. We put . We have
[TABLE]
Then we have the distinguished triangle
[TABLE]
This completes the proof. ∎
2.3. Definition of another syntomic complex with modulus
We assume the following assumption when we use another syntomic complex with modulus , which is defined below.
Assumption 2.10**.**
**
- •
There exist exact closed immersions
[TABLE]
of log schemes for such that and are smooth over , and such that the following diagram is cartesian :
[TABLE]
- •
There exist a compatible system of liftings of Frobenius endomorphisms and for each ([Tsu1, p.71, (2.1.1)–(2.1.3)]).
- •
*The systems and *fit into the following commutative diagram for for each :
[TABLE]
- •
* is an effective Cartier divisor on such that and which induces a morphism .*
For an effective Cartier divisor , we define , where .
We denote , where the homomorphism induced by . We will define the Frobenius morphism “devided by ” (or ) :J_{\mathscr{E}_{n}}^{[r-\text{\large\cdot}]}\otimes_{\mathscr{O}_{Z_{n}}}\mathscr{O}_{Z_{n}}(-\mathscr{D}_{n}))\rightarrow\mathscr{O}_{\mathscr{E}_{n}}\otimes_{\mathscr{O}_{Z_{n}}}\mathscr{O}_{Z_{n}}(-\mathscr{D}_{n}) in the following:
We have
[TABLE]
(cf. [Ka1, I, Lemma 1.3 (1)]). On the other hand, is flat over and
[TABLE]
for every and . Hence, for , there exists a unique homomorphism
[TABLE]
which makes the following diagram commute:
[TABLE]
From the fact that
[TABLE]
we can define a frobenius “divided by ”
[TABLE]
Definition 2.11**.**
(another syntomic complex with modulus, sufficiently local case)
We assume . We define
[TABLE]
where in degree . We denote this complex by for simplicity.
Lemma 2.12**.**
Under Assumption 2.10, and are naturally quasi-isomorphic.
Proof.
By the definition of , we have a quasi-isomorphism
[TABLE]
We will show that there exists an isomorphism of complexes
[TABLE]
To show this isomorphism, we will show the isomorphism
[TABLE]
for each degree . It sufficies to show an isomorphism
[TABLE]
where . By tensoring to the short exact sequence
[TABLE]
we have the exact sequence
[TABLE]
Thus we have the surjectivity of the morphism (2.4). We will prove the injectivity of this morphism. By the smoothness of , is locally free sheaf on . Hence it suffices to show that the morphism
[TABLE]
is injective. It suffices to show that the injectivity of the morphism locally, so we assume that is defined by the one equation . Then the inclusion map is identified with the map . So, we can identify with the map
[TABLE]
Since is the subsheaf of , it suffices to show that is injective. The problem is reduced to the case
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
In this case, , and the kernel of the ring homomorphism is
[TABLE]
We put and . The affine ring of is generated by as a -module. Then any element of can be written as , where . The generators of are linearly independent on . Thus are basis for as a -module ([Ber, p.31, 1.4.2 and Corollarie 2.3.2 (ii)]). Since the polynomial is a non-zero divisor on , is a non-zero divisor on . This completes the proof. ∎
In what follows, we will use the complex when we compute the cohomology sheaf of the syntomic complex with modulus in sufficiently local situation. By definition, is concentrated in []. Note that , the syntomic complex defined in [Tsu2], [Tsu3].
Lemma 2.13**.**
(cf. [Tsu2], [Tsu3])* For , there is a morphism in :*
[TABLE]
by
[TABLE]
[TABLE]
[TABLE]
Proof.
There is a product morphism (cf. [Tsu2 2.2] )
[TABLE]
This morphism induces
[TABLE]
Thus we can define the above product morphism . ∎
2.4. Construction of the symbol map in local case
In this subsection, we assume Assumption 2.10. Let us define a symbol map
[TABLE]
for . Here is the definition ideal of and
[TABLE]
We construct a symbol map in the local situation in the following. By taking , we immediately obtain its global case.
Recall that denotes the reduction mod of . Let be the complex
[TABLE]
[TABLE]
We define the morphism of complexes by
[TABLE]
[TABLE]
at degree [math] and
[TABLE]
[TABLE]
at degree , where denotes the Frobenius operator induced by and we have used the fact that is contained in
[TABLE]
since . We will show the isomorphism below:
Lemma 2.14**.**
We have the following exact sequence
[TABLE]
Proof.
We have the following exact sequence ([Tsu2])
[TABLE]
The module is a flat -module. Then we have the following exact sequence
[TABLE]
Here we have . This completes the proof. ∎
Corollary 2.15**.**
We have an isomorphism
[TABLE]
Proof.
If in Lemma 2.14, we have the exact sequence
[TABLE]
Then we have On the other hand, if in Lemma 2.14, we have the exact sequence
[TABLE]
Then we have . We obtain the isomorphism . ∎
Taking , we obtain
[TABLE]
We obtain the symbol map (2.5) as the following composite maps:
[TABLE]
[TABLE]
Here is symbol map defined by [Tsu2, §2]. The second morphism is product structure .
2.5. Global construction of the symbol map
We will construct the symbol map in global. First we show that the local symbol map is independent of the choice of the embedding system below. We consider the following three diagrams:
[TABLE]
[TABLE]
Note that is not effective Cartier divisor on . We put the projections
[TABLE]
[TABLE]
We denote by
[TABLE]
the ideal , where is the PD-envelope of
[TABLE]
in respectively. We put
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Lemma 2.16**.**
The following diagram is commutative:
[TABLE]
*where we define and .
Here the isomorphisms*
[TABLE]
are defined from an exact sequences
[TABLE]
[TABLE]
For is defined by the morphism . In degree [math], the morphism of complexes is
[TABLE]
and in degree , the morphism is
[TABLE]
The map is similar.
Proof.
We show the commutativity of – below:
The diagrams and are commutative by the definition of and .
The commutativity of and : The proofs of and are the same, we only show the case . It is enough to show that the commutativity of the following diagram of complexes:
[TABLE]
In degree [math], the above diagram is
[TABLE]
Here the upper and lower horizontal morphisms are defined by , is the projection . In degree , we have the diagram:
[TABLE]
Here the upper (resp. lower) horizontal morphisms are defined by
[TABLE]
[TABLE]
In degree , we have the diagram
[TABLE]
Here the right and left vertical morphisms are projections . This commutativity is obvious.
Then we have the commutativity of the above diagrams .
The commutativity of and : The proofs of and are the same, we only show the case . It is enough to show the commutativity of the following diagram of complexes:
[TABLE]
First we define the left vertical arrow .
[TABLE]
Here the upper horizontal arrows are the inclusion map and the lower horizontal arrow is . The morphism is the inclusion map and the morphism is . Then the above diagram is commutative. Hence we obtain the morphism of complex .
In degree [math],
[TABLE]
Here the upper and the lower horizontal arrow is . The right and the left vertical arrows are the inclusion map. Then the diagram is commutative.
In degree , the above diagram is
[TABLE]
The left vertical arrow is , the upper horizontal arrow is
[TABLE]
the lower horizontal arrow is , and the right vertical arrow is the inclusion to the first component . Then we obtain the commutativity of this diagram .
The commutativity of : We consider the diagram
[TABLE]
By the isomorphisms , and , the above diagram is commutative. This completes the proof. ∎
Take in the above construction, we have the morphism
[TABLE]
Since , we obtain a morphism
[TABLE]
Taking , we obtain a morphism
[TABLE]
The local symbol map has functorial property for and , hence we get the symbol map
[TABLE]
3. Main Rsults
In this and the next section, for and , we calculate the cohomology sheaf
[TABLE]
We first define two filtrations on the sheaf using symbols and state our main results on the associated graded pieces.
Definition 3.1**.**
We define the filtrations and on () by
[TABLE]
[TABLE]
if , and
[TABLE]
[TABLE]
[TABLE]
if . Here for .
Here we denote by the same notation the image of under the map and its images in . We define the filtration and on () to be the images of these filtrations under the symbol map 2.5. There are natural inclusions and . Put
[TABLE]
To describe these graded pieces, we introduce some differential sheaves on . We define
[TABLE]
where , \omega_{Y}^{q}:=\Omega^{q}_{Y/s}\big{(}\log(M_{Y}/N_{s})\big{)}, and denotes the log point over . We define the subsheaves and of by
[TABLE]
[TABLE]
Let be the subsheaf of abelian groups of generated by local sections of the form
[TABLE]
where x\in\Big{(}1+\mathscr{O}_{Y}\big{(}-D_{s}\big{)}\Big{)}^{\times} and .
If , we denote . Here . We put . We define a map by the local assignment
[TABLE]
where denotes a local uniformizer of , for each .
Lemma 3.2**.**
* is a complex.*
Proof.
It is enough to show that . We have
[TABLE]
This completes the proof.∎
We have the following Lemma:
Lemma 3.3**.**
(cf. [SS, Theorem 3.2] )* For each integer , there exists an isomorphism*
[TABLE]
[TABLE]
where and .
Proof.
We use a similar argument as in [SS, Theorem 3.2]. If divides for any , then the map sends
[TABLE]
Then we have \mathcal{H}^{q}(\omega_{Y|D_{s}}^{\text{\large\cdot}})\cong\mathcal{H}^{q}(\omega_{Y}^{\cdot})\otimes\mathscr{O}_{Y}(-D_{s}). By the fact that Theorem A3 in Appendix [Tsu3], we have an isomorphism: . Thus C^{-1}:\omega_{Y|D_{s}^{\prime}}^{q}\rightarrow\mathcal{H}^{q}(\omega_{Y|D_{s}}^{\text{\large\cdot}}) is injective. By the assumption divides for any , the surjectivity of the map in the statement of Proposition 3.3 is obvious. Thus we have the isomorphism
[TABLE]
We next show the general case. We see that the natural inclusion
[TABLE]
is a quasi-isomorphism. We define where . We can consider a filtration
[TABLE]
such that
[TABLE]
where , and , . We have an short exact sequence by definitions, which gives short exact sequence
[TABLE]
Then the graded pieces of the above filtration are of the form is isomorphic to . Here is the unique element such that and .
Lemma 3.4**.**
(cf. [SS, Lemma 3.4]) If , the complex of sheaves are acyclic for each .
Proof.
The proof is the same as the proof of [SS, Lemma 3.4]. It suffices to show that is acyclic if . Note that is generated by and the form with and (cf. [Tsu3, Corollary 1.9]). There is a residue homomorphism which is characterized by the following properties for (cf. see [SS, Lemma 3.4]):
[TABLE]
We define a residue homomorphism
[TABLE]
by for and . We have
[TABLE]
by the same computation as the proof of [SS, Lemma 3.4]. This implies that is acyclic if . ∎
Using above Lemma 3.4, we obtain the isomorphism
[TABLE]
Here the first isomorphism comes from the first case. This completes the proof of Lemma 3.3. ∎
For each integer , we have the following morphism which restricts a morphism (3.11) to :
[TABLE]
[TABLE]
where , and .
Lemma 3.5**.**
(cf. [JSZ, Theorem 1.2.1, Proposition 1.2.3])* We keep the notations and the assumptions as in §3. Then, for each integer , we have the following exact sequence.*
[TABLE]
Proof.
The surjectivity of : It suffices to show the surjectivity of on sections over the strict henselisation of a local ring of . This follows form the following fact:
Fact ([JSZ, Lemma 1.2.2].): *Let be a strictly henselian regular local ring of equi-characteristic and be the maximal ideal. Let and . If , then there exists , such that and .
*The exactness of the middle term : It suffices to show that the exactness of the sequence
[TABLE]
If we have this short exact sequence, we have (3.15) because . We have the following commutative diagram:
[TABLE]
Here the upper horizontal row is proved by [Tsu1, Theorem 6.1.1] and [Tsu3, Theorem A4]. Then it suffices to show that . This is an étale local problem and a consequence of Proposition 3.6 below. Let be the henselization of a local ring of . We put and
[TABLE]
where we choose a system of regular parameters of such that
[TABLE]
for some .
Proposition 3.6**.**
(cf. [JSZ, Proposition 1.2.3]) is generated by elements of the form
[TABLE]
The proof of Proposition 3.6 is the same computations as the proof of [JSZ, Proposition 1.2.3]. This completes the proof. ∎
We have the following main results.
Theorem 3.7**.**
Let be an integer. If and , the cokernel of the symbol map
[TABLE]
is Mittag-Leffler zero with respect to the multiplicities of the prime components of .
Theorem 3.8**.**
We assume that . Let be the absolute ramification index of . Then the sheaf \mathcal{H}^{q}\big{(}s_{1}(q)_{X|D}\big{)} has the folllowing structure:
- (1)
For , we have short exact sequences:
[TABLE]
[TABLE]
Here , and . We denote by (resp. ) the image of (resp. ) in , and we denote by the image of in .
[TABLE]
[TABLE]
where
[TABLE] 2. (2)
If and , then we have
[TABLE]
[TABLE]
[TABLE]
[TABLE] 3. (3)
If and , then we have short exact sequences
[TABLE]
[TABLE]
[TABLE]
[TABLE]
where is a certain subsheaf of {\rm{gr}}_{U}^{m}\mathcal{H}^{q}\big{(}s_{1}(q)_{X|D}\big{)} which is given more explicitly in a sufficientlly local situation (see (4.42) in Lemma 4.12 below). 4. (4)
If , then U^{m}\mathcal{H}^{q}\big{(}s_{1}(q)_{X|D}\big{)}=0.
4. ** Proof of Main Results**
4.1. Proof of Theorem 3.7
We put . We consider the diagram
[TABLE]
where the lower horizontal line is the long exact sequence which is obtained by Lemma 2.9. By this diagram, the assertion is reduced to the case . Then we show the claim in the case . By Lemma 4.14 and Lemma 4.15 below, the cokernel of the morphism
[TABLE]
will be Mittag-Leffler zero with respect to the multiplicities of the prime components of . Then we will obtain that is Mittag-Leffler zero by the finiteness of the filtration in Theorem 3.8 .
4.2. Proof of Theorem 3.8
If , by (4.11) in Lemma 4.3 and Lemma 4.12 below, we have the following diagram of the short exact sequences:
[TABLE]
where the surjectivity of the left and middle vertical arrows are form Lemma 4.12 and Lemma 4.3 (3) below. Here we put
[TABLE]
By the snake lemma, we have two short exact sequences in the assertion . If and , we consider the following diagram
[TABLE]
where the surjectivity of the left vertical arrow and the isomorphism of the middle vertical arrow are form Lemma 4.12 and Lemma 4.3 (1) below. By the snake lemma, we obtain the isomorphisms in the assertion . If and , by (4.11) in Lemma 4.3 and Lemma 4.12 below, we have the following diagram
[TABLE]
Here the surjectivity of the left and middle vertical arrows are form Lemma 4.12 and Lemma 4.3 (2) below. By the snake lemma, we obtain the assertion . From Lemma 4.7 () below, we will obtain for . Since by Lemma 4.6 and Corollary 4.8 below, this implies (). This completes the proof of Theorem 3.8.
In the rest of this section we prove the lemmas that have been mentioned in the above proof of Theorem 3.7 and Theorem 3.8. We will work with the following local situation. We keep the Assumption 2.10 in the following sections.
4.3. Local computation
We denote by the scheme with log sturcture defined by the closed point. Let be the scheme with the log structure defined by the divisor , and let be the exact closed immersion defined by . We assume that there exists a factorization such that is smooth and compatible with the liftings of frobenii, and such that the following diagram is cartesian (the left cartesian diagram is mentioned in Assumption 2.10):
[TABLE]
We define the liftings of Frobenius by the Frobenius of and . These assumptions are étale locally: We have the following diagram
[TABLE]
Here is defined by . The lower horizontal map is defined by . Then this diagram is commutative and the morphism is smooth and compatible with the liftings of frobenii.
Lemma 4.1**.**
Let be a non-negative integer.
- (1)
From the reduction* of the short exact sequence*
[TABLE]
and the -linear isomorphism
[TABLE]
induced by the multiplication by on for each integer , we obtain a short exact sequence of complexes:
[TABLE]
* Furthermore, for each integer , the connecting homomorphism*
[TABLE]
of the long exact sequence associated to (4.3) is the multiplication by . In particular, it is the zero map if . 2. (2)
*If , *\mathcal{H}^{q}(\big{(}T^{m}\mathscr{O}_{Z_{1}}/T^{m+1}\mathscr{O}_{Z_{1}}\big{)}\otimes\omega_{Z_{1}|\mathscr{D}_{1}}^{\cdot})=0. 3. (3)
If , there is an isomorphism:
[TABLE]
Proof.
The assertions 4.1, 4.2 and 4.3 are easily follows from [Tsu2, Lemma 2.4.2] and follows from . We prove and (). There is a commutative diagram of complexes with exact rows which comes from (4.3):
[TABLE]
and taking cohomology, we get the following commutative diagram:
[TABLE]
where is the inverse Cartier morphism. We have the following lemma:
Lemma 4.2**.**
(cf.[Tsu1, Lemma 7.1.4]) For the map of , we have
[TABLE]
for .
Proof.
This proof is the same argument as [Tsu1, Lemma 7.1.4]. It suffices to show that . Let be the image of and be the image of . If we have , there exists such that
[TABLE]
Then we have
[TABLE]
Thus we obtain . ∎
The commutativity of the above two diagram follows from this Lemma, the fact and the characterization of Cartier isomorphism. Then we have (3) from Lemma 3.3. We prove the claim by the same argument as in the proof of [Tsu1, Lemma 7.4.3 (2)]. We note that is a lifting of . Thus we have
[TABLE]
The image of in is Then there exists such that . Hence we have
[TABLE]
Then maps the class of to the class of . If , we have by the above proof of so that the class of is [math]. We obtain the claim . This completes the proof. ∎
Lemma 4.3**.**
Let be a non-negative integer.
- (1)
If , there is a short exact sequence
[TABLE]
which is characterized by the following properties. For and , the image of
[TABLE]
in is , and
[TABLE]
is the image of , where denote the images of in . 2. (2)
If , there is a short exact sequence
[TABLE]
which is characterized in the same way as (1). 3. (3)
The homomorphism
[TABLE]
is surjective. Its kernel is the subsheaf of abelian groups of Z^{q}\big{(}\mathscr{O}_{Y}\otimes\omega_{Z_{1}|\mathscr{D}_{1}}^{\cdot}\big{)} generated by local sections of the form
[TABLE]
and there is a short exact sequence
[TABLE]
*which is characterized by the following properties: *
For , the image of
[TABLE]
in is , and
[TABLE]
is the image of , where denote the images of in .
Proof.
If , Z^{q-1}\Big{(}\big{(}T^{m}\mathscr{O}_{Z_{1}}/T^{m+1}\mathscr{O}_{Z_{1}}\big{)}\otimes\omega_{Z_{1}|\mathscr{D}_{1}}^{\cdot}\Big{)}=B^{q-1}\Big{(}\big{(}T^{m}\mathscr{O}_{Z_{1}}/T^{m+1}\mathscr{O}_{Z_{1}}\big{)}\otimes\omega_{Z_{1}|\mathscr{D}_{1}}^{\cdot}\Big{)} by Lemma 4.1 (). Then we have from (4.3) the following exact sequence:
[TABLE]
If , the homomorphism
[TABLE]
is surjective by Lemma 4.1 (). Hence the homomorphism
[TABLE]
is surjective and 4.3 induces a short exact sequence:
[TABLE]
(1) and (2) follows from these two short exact sequences and (4.3). We will prove . We have a commutative diagram
[TABLE]
where the upper horizontal short exact sequence is the case of (4.17). The second and fourth morphism is surjective by Lemma 3.5. Then the middle morphism is surjective. By the snake lemma in the above commutative diagram, we have the short exact sequence (4.11). Hence we obtain the claim . This completes the proof. ∎
Let (resp. ) be the subcomplex of (resp. ) which coincides with (resp. ) in degree , , and (resp. degree , , and ), and is [math] in other degree.
Lemma 4.4**.**
The inclusion map (resp. ) and the identity map (resp. ) give a morphism of complexes (resp. ) : .
Proof.
It is obvious that the morphism is a morphism of complex. We consider the case . It suffices to show that the following diagram commutative
[TABLE]
By (2.2) and by the definition of , we have the commutativity of the above diagram. This completes the proof. ∎
We put the mapping fiber of the morphism . Then we have .
We define the descending filtration () on (resp. ) as follows:
[TABLE]
[TABLE]
[TABLE]
[TABLE]
where denotes the smallest integer which is . The morphism is compatible with the filtrations . By the assumpution , we have . Then the morphism is also compatible with the filtrations .
We define the filtration () on to be the mapping fiber of and define the filtration on to be the image of . We will show that () (see Corollary 4.11).
Next we calculate the image of under the symbol map 2.5.
Lemma 4.5**.**
For x\in\big{(}1+\mathscr{O}_{Z_{2}}(-\mathscr{D}_{2})\big{)}^{\times}, , the image of in under the symbol map 2.5, is the class of the cocycle
[TABLE]
[TABLE]
[TABLE]
where denote the image of in and denote the images of in .
Proof.
This is a straightforward calculation by (2.5). We only show that the case for simplicity. By the construction of the symbol map, we consider the image of the class of cocycle under product structure
[TABLE]
Its image in under product structure (see Lemma 2.13 ) is the class of cocycle
[TABLE]
This completes the proof of the case . ∎
Lemma 4.6**.**
For , we have .
Proof.
We use a similar argument as in [Tsu2, Lemma 2.5.2]. By Lemma 4.5, by , and by the definition of , it suffices to show that the following two assertions:
[TABLE]
[TABLE]
for and . Here we denote by a lifting of . We have
[TABLE]
Then we obtain (4.21). We show that (4.22). There exists such that . We put . Then we have
[TABLE]
We can write for some . Thus we obtain
[TABLE]
This completes the proof. ∎
Next we calculate for . By definition, we have a long exact sequence:
[TABLE]
[TABLE]
Since (resp. )\Longleftrightarrow$$m\geq pe/(p-1) (resp. ) and the differential
[TABLE]
vanishes when , we have the following:
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Lemma 4.7**.**
Let be an integer such that . Then :
- (1)
If , we have a short exact sequence
[TABLE] 2. (2)
We have an isomorphism
[TABLE] 3. (3)
If and , we have a map
[TABLE]
its kernel is .
If and , the map is an isomorphism. 4. (4)
If ,
[TABLE]
Proof.
We describe the homomorphism as follows:
(i)
[TABLE]
(ii)
[TABLE]
[TABLE]
(iii)
[TABLE]
[TABLE]
(iv)
[TABLE]
[TABLE]
The first homomorphism (i) is an isomorphism by Lemma 4.1 (2). We consider the following commutative diagram
[TABLE]
This commutativity is from Lemma 7.4.2 (4), p. 120 in [Tsu1]. Here we use (4.2) for the left vertical isomorphism and Lemma 4.1 (3) for the right vertcal isomorphism. Hence the second homomorphism is injective.
The third homomorphism (iii) is surjective by Lemma 4.3 (3). In the case (iv), we have . Then this map is because . It is trivial that (iv) is surjective. If , by the long exact sequence (4.23), we have the short exact sequence
[TABLE]
By the above commutative diagram , we take , we have
[TABLE]
By the isomorphisms (4.27), (4.26) and (4.2), we have the following isomorphism:
[TABLE]
Then we obtain the short exact sequence in . By the long exact sequence (4.23), we have
[TABLE]
Since all homomorphisms (i)–(iv) are injective, we have Thus we obtain . We have the surjective homomorphism
[TABLE]
by the long exact sequence (4.23), (4.24) and (4.25). If , we have
[TABLE]
If and , this homomorphism is surjective as it is. If and , this homomorphism is an isomorphism by the surjectivity of (i), (iii) and (iv). Therefore we obtain the claim . Finally, if , the above homomorphism (4.32) is an isomorphism and by (4.26) and (4.27). Thus we obtain the claim . This completes the proof. ∎
Lemma 4.8**.**
We have for
Proof.
If , we have
[TABLE]
[TABLE]
since ( ). We have
[TABLE]
for . Here we use ().
Hence (resp. ) is nilpotent on \big{(}T^{m}\mathscr{O}_{\mathscr{E}_{1}}+J_{\mathscr{E}_{1}}^{[p]}\big{)}\otimes\omega_{Z_{1}|\mathscr{D}_{1}}^{q-1} (resp. \big{(}T^{m}\mathscr{O}_{\mathscr{E}_{1}}+J_{\mathscr{E}_{1}}^{[p]}\big{)}\otimes\omega_{Z_{1}|\mathscr{D}_{1}}^{q}\Big{)}). Then are bijective in degree and degree . ∎
Corollary 4.9**.**
We have for .
Lemma 4.10**.**
The homomorphism is injective for .
Proof.
By Lemma 4.8, we may assume that . It is enough to show that
[TABLE]
is surjective. From the argument before Lemma 4.7 (i), we obtain an isomorphism
[TABLE]
Then it suffices to prove that the natural homomorphism
[TABLE]
[TABLE]
is surjective or equivalently that the homomorphism
[TABLE]
is surjective. When , this is obvious by Lemma 4.1 (2). In the case of , this follows from the following commutative diagram in which the lower horizontal arrow is surjective and the right vertical arrow is an isomorphism by Lemma 4.1 (3).
[TABLE]
∎
Corollary 4.11**.**
* for .*
From lemma 4.6 and 4.11, we have homomorphisms
[TABLE]
and injective homomorphisms
[TABLE]
for .
Lemma 4.12**.**
Let be a non-negative integer. Let , let and let . Let denote the image of in , let denote the image of in and let denote the image of in . Then we have:
- (1)
If , the image of
[TABLE]
under the composite
[TABLE]
is .
The image of
[TABLE]
under the map is . 2. (2)
The image of
[TABLE]
under the composite
[TABLE]
[TABLE]
is d\big{(}T^{m}y\otimes d\log a_{1}\land\cdots\land d\log a_{q-1}\big{)}. If and , the map is isomorphism. If and , the map is surjective.
The image of
[TABLE]
under the map is d\big{(}T^{m}y\otimes d\log a_{1}\land\cdots\land d\log a_{q-2}\land d\log T\big{)}.
We put
[TABLE]
Proof.
We note that is a lifting of . If , the image of by the symbol map (2.5) is the class of a cocycle of the form
[TABLE]
by Lemma 4.5. Its image in {\rm{Ker}}\left(Z^{q}\big{(}\mathscr{O}_{Y}\otimes_{\mathscr{O}_{Z_{1}}}\omega_{Z_{1}|\mathscr{D}_{1}}^{\cdot}\big{)}\xrightarrow{1-\varphi\otimes\land^{q}d\varphi/p}\mathcal{H}^{q}\big{(}\mathscr{O}_{Y}\otimes_{\mathscr{O}_{Z_{1}}}\omega_{Z_{1}|\mathscr{D}_{1}}^{\cdot}\big{)}\right) is
[TABLE]
by the construction of the homomorphism . Thus we obtain the claim . If , the image of (1+\pi^{m}\overline{y})\otimes\overline{a_{1}}\otimes\cdots\otimes\overline{a_{q-1}}\in U^{m}\Big{(}(1+I_{D_{2}})^{\times}\otimes(M_{X_{2}}^{gp})^{\otimes(q-1)}\Big{)}\;(\mbox{resp.}\;\;(1+\pi^{m}\overline{y})\otimes\overline{a_{1}}\otimes\cdots\otimes\overline{a_{q-2}}\otimes\pi\in V^{m}) by the symbol map (2.5) is the class of a cocycle of the form
[TABLE]
We have
[TABLE]
Then the image of in B^{q}\Big{(}\big{(}T^{m}\mathscr{O}_{Z_{1}}/T^{m+1}\mathscr{O}_{Z_{1}}\big{)}\otimes\omega_{Z_{1}|\mathscr{D}_{1}}^{\cdot}\Big{)} is
[TABLE]
by the construction of the homomorphism . Then we obtain the claim . ∎
Remark 4.13**.**
By the above Lemma 4.12 (2), the map and are isomorphism in the case . Then we obtain an isomorphism in this case.
Lemma 4.14**.**
The cokernel of the morphism
[TABLE]
is Mittag-Leffler zero with respect to the multiplicities of the prime components of .
Proof.
We have the following commutative diagram:
[TABLE]
where the vertical and horizontal sequences is exact. Here we put
[TABLE]
[TABLE]
[TABLE]
The morphism is constructed in Lemma 4.12. They are surjective by the explicit assignments in Lemma 4.12. We have
[TABLE]
by Lemma 4.7 and .
Thus is Mittag-Leffler zero with respect to the multiplicities of the prime components of . Since is surjective, is also surjective. Then is Mittag-Leffler zero. Hence is also Mittag-Leffler zero. This completes the proof. ∎
Lemma 4.15**.**
The kernel and the cokernel of the morphisms
[TABLE]
and the cokernel of
[TABLE]
are Mittag-Leffler zero with respect to the multiplicities of the prime components of .
Proof.
We consider the following commutative diagram:
[TABLE]
The left and central vertical morphism is injective by Lemma 4.6. If , the claim is trivial. We assume that . If , the right vertical morphism is injective by Corollaly 4.9 and the cokernel of is Mittag-Leffler zero from Lemma 4.14. We can easily show the assertion by induction on . ∎
5. Calculation of for
In this section, for , we will calculate the cohomology sheaf by a similar computations as in [Tsu3, Appendix]. The setting remains as in §4.3. We keep the assumption in the following sections.
We define a descending filtration on for an integer as follows: we define the filtration on (resp. ()) by
[TABLE]
Here for denotes the smallest integer . We can easy to see that the morphism are compatible with . We define the filtration on to be the mapping fiber of .
Lemma 5.1**.**
(cf. [Tsu3, Lemma A.8]) Let be a non-negative integer. For , the homomorphism
[TABLE]
is surjective. Its kernel is the subsheaf of abelian groups of Z^{q}\big{(}\mathscr{O}_{Y}\otimes\omega_{Z_{1}|\mathscr{D}_{1}}^{\cdot}\big{)} generated by local sections of the form
[TABLE]
[TABLE]
and there is a short exact sequence
[TABLE]
*which is characterized by the following properties:
For and , the image of*
[TABLE]
in the right term is , and
[TABLE]
is the image of in the left term, where denote the images of in .
Proof.
We can obtain this Lemma in the same way as Lemma 4.3 . We can reduce to the case by the commutative diagrams (cf. [Tsu3, Lemma A8]):
[TABLE]
where we put which exists étale locally on . The short exact sequence (5.3) is obtained by the same argument as the proof of the exactness of (4.11) in Lemma 4.3 .∎
Lemma 5.2**.**
(cf. Lemma 4.7, [Tsu3, Lemma A9]) Let and be integers such that . The map
[TABLE]
is surjective without the case and its kernels are follows:
- (1)
If or , then is an isomorphism. 2. (2)
If , then the kernel of is isomorphic to the kernel of
[TABLE]
where . 3. (3)
Suppose , then the kernel of is isomorphic to B^{q}\big{(}(\frac{T^{m}\mathscr{O}_{Z_{1}}}{T^{m+1}\mathscr{O}_{Z_{1}}})\otimes\omega_{Z_{1}|\mathscr{D}_{1}}\big{)}.
Proof.
The following argument is the similar computations as the proof of Lemma 4.7. We note that
[TABLE]
We have the following facts:
[TABLE]
[TABLE]
Here denotes the Eisenstein polynomial of over .
The proof of : If , we obtain
[TABLE]
Then the morphism is the identity. Next if , we have the following two cases:
- •
case : By Lemma 4.1 , we have
[TABLE]
- •
case : We have by the fact . By using and Lemma 4.1 , the kernel of the morphism vanishes.
The proof of : If , we have
[TABLE]
If , we have
[TABLE]
Then the kernel of the morphism is B^{q}\big{(}(T^{m}\mathscr{O}_{Z_{1}}/T^{m+1}\mathscr{O}_{Z_{1}})\otimes\omega_{Z_{1}|\mathscr{D}_{1}}\big{)}.
The proof of : If , we have from Lemma 4.1 and Lemma 5.1 and the fact . This completes the proof. ∎
If contains a primitive -th root of unity, then we have (See [Tsu3, the proof of Proposition A17]). Choose a -th root of . Then, by Lemma 3.3, for integers , we have
[TABLE]
Proposition 5.3**.**
Let the notation and assumption be as above. Let and be an integers such that . Then, for every integer , we have the structure of \mathcal{H}^{q}\big{(}{\rm{gr}}_{\tilde{\mathfrak{U}}}^{m}(s_{1}(r)_{X|D})\big{)} as follows:
- (1)
If or , then
[TABLE] 2. (2)
If , then there exists an exact sequence
[TABLE]
where . 3. (3)
Suppose . Then
- (a)
If , there exists an exact sequence
[TABLE] 2. (b)
If , there exists an exact sequence
[TABLE]
Proof.
We have the long exact sequence
[TABLE]
If or , the morphism is an isomorphism by Lemma 5.2 . Then we have \mathcal{H}^{q}\big{(}{\rm{gr}}_{\tilde{\mathfrak{U}}}^{m}(s_{1}(r)_{X|D})\big{)}=0 by the above long exact sequence . If , the kernel of is isomorphic to
[TABLE]
by the Lemma 5.2 . By the same argument as Lemma 4.7, the cokernel of is isomorphic to . Then we have (\mathfrak{Z}):\;\;\mathcal{K}\cong\frac{\mathcal{H}^{q}\big{(}{\rm{gr}}_{\tilde{\mathfrak{U}}}^{m}(s_{1}(r)_{X|D})\big{)}}{\mathfrak{K}^{q}} by . Hence we obtain the short exact sequence in the claim by the isomorphism and (5.3) of Lemma 5.1.
Finally, we prove the case . If , there is a short exact sequence
[TABLE]
by Lemma 4.3 . Then we have the claim by Lemma 5.2 and . If , we can obtain the claim by Lemma 5.2 and . This completes the proof. ∎
For integers , we define the filtration on to be the image of \mathcal{H}^{q}\big{(}{\rm{gr}}_{\tilde{\mathfrak{U}}}^{m}(s_{1}(r)_{X|D}\big{)}. By the same argument as in [Tsu3, Proposition A6], we have
[TABLE]
For and , where and , the product is contained in . By Proposition 5.3 and , for each integer , we have an isomorphism
[TABLE]
Here to obtain the last isomorphism, we use with .
Definition 5.4**.**
We define a filtrations on \mathcal{H}^{q}\big{(}s_{1}(r)_{X|D}\big{)} as follows:
[TABLE]
[TABLE]
[TABLE]
[TABLE]
As in Lemma 4.6, we see that the image of under the symbol map is contained in , i.e.
[TABLE]
Hence we have a homomorphism
[TABLE]
by using . Put
[TABLE]
Proposition 5.5**.**
(cf. Lemma 4.12) Let be a non-negative integer. Let , let and let . Let denote the image of in , let denote the image of in and let denote the image of in . Then we have:
- (1)
If , the image of
[TABLE]
under the composite
[TABLE]
is .
By Proposition 5.3, and , we get an exact sequence :
[TABLE] 2. (2)
Suppose . If , the image of
[TABLE]
under the composite
[TABLE]
is d\Big{(}T^{ep(r-q)/(p-1)+m}b_{0}^{-p(r-q)}y\cdot d\log(a_{1})\land\cdots\land d\log(a_{q-1})\Big{)}.
If (resp. ), by Proposition 5.3 and , we get an exact sequence:
[TABLE]
[TABLE]
Proof.
We prove by the same argument as the proof of Lemma 4.12. First, we explain the maps and . By the isomorphism , we have
[TABLE]
From the long exact sequence , we obtain the surjective map
[TABLE]
The right hand side is isomorphic to
[TABLE]
by Lemma 5.2 (2). Then we have the map . The map is the same argument and by using Lemma 5.2 (3).
We put and denote by the image of in
[TABLE]
under . Then we have . The image of under the map is the class of a cocycle of the form
[TABLE]
by using Lemma 4.5. Its image in
[TABLE]
is
[TABLE]
If and , the image of (1+\pi^{m}\overline{y})\otimes\overline{a_{1}}\otimes\cdots\otimes\overline{a_{q-1}}\in U^{m}\Big{(}(1+I_{D_{2}})^{\times}\otimes(M_{X_{2}}^{gp})^{\otimes(q-1)}\Big{)} by the map is the class of a cocycle of the form
[TABLE]
Then its image in B^{q}\Big{(}\big{(}T^{m_{0}+m}\mathscr{O}_{Z_{1}}/T^{m_{0}+m+1}\mathscr{O}_{Z_{1}}\big{)}\otimes\omega_{Z_{1}|\mathscr{D}_{1}}^{\cdot}\Big{)} is
[TABLE]
This completes the proof. ∎
Corollary 5.6**.**
If contains a primitive -th roots of unity, for any integer and such that , the homomorphism
[TABLE]
induced by the product structure is an isomorphism.
Proof.
We will prove that the morphism is an isomorphism. The morphism induces a morphism
[TABLE]
for every non-negative integer . It suffices to show that the morphism is an isomorphism. We consider the following diagrams of exact sequences:
If :
[TABLE]
If and :
[TABLE]
If and :
[TABLE]
Here the upper horizontal exact rows are obtained by Proposition 5.3 and the lower horizontal exact rows are obtained by Proposition 5.5. By the snake lemma, we have the isomorphisms
[TABLE]
[TABLE]
By the second isomorphism and the commutative diagram
[TABLE]
we obtain the isomorphism for .
If the case , the claim is trivial by Proposition 5.3 (1). This completes the proof. ∎
Corollary 5.7**.**
(cf. Theorem 3.8) Let be the absolute ramification index of . Then the sheaf \mathcal{H}^{q}\big{(}s_{1}(r)_{X|D}\big{)} has the folllowing structure:
- (1)
For , we have short exact sequences:
[TABLE]
[TABLE]
Here , and . We denote by (resp. ) the image of (resp. ) in , and we denote by the image of in .
[TABLE]
[TABLE]
where
[TABLE] 2. (2)
If and , then we have
[TABLE]
[TABLE]
[TABLE]
[TABLE] 3. (3)
If and , then we have short exact sequences
[TABLE]
[TABLE]
[TABLE]
[TABLE]
where \mathfrak{L}:={\rm{Ker}}\Big{(}{\rm{gr}}_{\mathcal{U}}^{m}\big{(}\mathcal{H}^{q}(s_{1}(r)_{X|D})\big{)}\longrightarrow B^{q}\left(\frac{T^{ep(r-q)/(p-1)+m}\mathscr{O}_{Z_{1}}}{T^{ep(r-q)/(p-1)+m+1}\mathscr{O}_{Z_{1}}}\otimes\omega_{Z_{1}|\mathscr{D}_{1}}\right)\Big{)}. 4. (4)
If , \mathcal{U}^{m}\mathcal{H}^{q}\big{(}s_{1}(r)_{X|D}\big{)}=0.
Proof.
We put for simplicity.
If , by Proposition 5.3 , we have the following diagram of the short exact sequences:
[TABLE]
where the surjectivity of the left and middle vertical arrows are from Proposition 5.5 . Here we put
[TABLE]
By the snake lemma, we have two short exact sequences in the assertion . If and , by Proposition 5.3 (a), we obtain the following diagram
[TABLE]
where the left vertical arrow is surjective and the middle vertical arrow is an isomorphism by Proposition 5.5 . By the snake lemma, we obtain the isomorphisms in the assertion . If and , Proposition 5.3 (b), we have the following diagram
[TABLE]
Here the surjectivity of the left and middle vertical arrows are from Lemma Proposition 5.5 . The lower exact sequence, we use the identification in the proof of Proposition 5.3 (3) . By the snake lemma, we obtain the assertion . Since U^{pe}\mathcal{H}^{q}(s_{1}(q)_{X|D})\big{)}=0 by Lemma 4.6 and Corollary 4.8, this implies (). This completes the proof of this Proposition. ∎
Next we do not assume that contains a primitive -th root of unity. Let be a totally ramified extension of of degree . We denote the scheme with the log structure defined by the closed point. Assume that there exists a prime of such that . We choose such a prime . Let be the scheme endowed with the log structure associated to the inclusion . We define the exact closed immersion in the same way as , by using (see the argument before Lemma 4.1). We have a cartesian diagram:
[TABLE]
where the morphism is defined by the multiplication by on . We define , , and denote , and the base changes of , and under the morphism above. Then one can apply the above arguments to , , , and . We denote by ′ the corresponding things. Since , and , then we have . Thus we obtain the following relations of the filtrations on and from Proposition 5.3 and :
Lemma 5.8**.**
(cf. [Tsu3, Lemma A18]) Let and be integers such that . Then there exists a canonical morphism
[TABLE]
which sends into for . If , then we have the following commutative diagram:
[TABLE]
where the horizontal rows and are exact sequence. Here
[TABLE]
[TABLE]
if**
[TABLE]
[TABLE]
and otherwise,
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Here , . We denote by the canoical projection or the identity. If is tamely ramified filed over , we have an isomorphism:
[TABLE]
Proof.
The horizontal rows of the diagram and are obtained by Proposition 5.3 for each cases. The first claim is trivial by . We show the second claim. The horizontal rows of diagrams of the second claim are obtained by (5.3) in Lemma 5.1, by in Lemma 5.3 and by . We prove the commutativity of these diagrams below.
case: We have the following diagram
[TABLE]
The image of xd\log(\overline{y})\land d\log(\overline{a_{2}})\land\cdots\land d\log(\overline{a_{q-1}})\in{\rm{Ker}}\big{(}1-a_{0}^{p(r-q)}C^{-1}\big{)} in \frac{{\rm{gr}}_{\tilde{\mathfrak{U}}}^{dm}\mathcal{H}^{q}\big{(}s_{1}(r)^{\prime}_{X|D}\big{)}}{\mathfrak{K}} is
[TABLE]
where we use that . On the other hand, the image of w\cdot xd\log(\overline{y})\land d\log(\overline{a_{2}})\land\cdots\land d\log(\overline{a_{q-1}})\in{\rm{Ker}}\big{(}1-a_{0}^{p(r-q)}C^{-1}\big{)} in \frac{{\rm{gr}}_{\tilde{\mathfrak{U}}}^{dm}\mathcal{H}^{q}\big{(}s_{1}(r)^{\prime}_{X|D}\big{)}}{\mathfrak{K}} is
[TABLE]
by calculating counterclockwise. Thus the left square is commutative. The commutativity of the right square is obvious.
case: We have the following diagram:
[TABLE]
The image of in \frac{{\rm{gr}}_{\tilde{\mathfrak{U}}}^{dm}\mathcal{H}^{q}\big{(}s_{1}(r)^{\prime}_{X|D}\big{)}}{\mathfrak{K}^{\prime}} is
[TABLE]
where we use that . On the other hand, the image of in \frac{{\rm{gr}}_{\tilde{\mathfrak{U}}}^{dm}\mathcal{H}^{q}\big{(}s_{1}(r)^{\prime}_{X|D}\big{)}}{\mathfrak{K}^{\prime}} is
[TABLE]
Hence the left square is commutative. The commutativity of the right square is obvious. Finally, if is tamely ramified filed over , we have . Then the above all cases, the morphisms and are an isomorphism. Thus we have the isomorphism
[TABLE]
by using snake lemma. This completes the proof. ∎
Corollary 5.9**.**
If and is tamely ramified filed over , the kenel and the cokernel of
[TABLE]
are Mittag-Leffler zero with respect to the multiplicities of the prime components of .
Proof.
We consider a commutative diagram
[TABLE]
From Lemma 5.8, the right vertical arrow is an isomorphism. The kernel and the cokernel of the left vertical arrow are Mittag-Leffler zero because and are Mittag-Leffler zero. Thus we obtain the claim by the snake lemma. ∎
By the same arguments as in Lemma 4.14 and Lemma 4.15, we have the following Proposition:
Proposition 5.10**.**
(cf. Lemma 4.15) The kernel and the cokernel of the morphism
[TABLE]
are Mittag-Leffler zero with respect to the multiplicities of the prime components of .
To prove the above Proposition, we need the following Lemma:
Lemma 5.11**.**
(cf. Lemma 4.14) The cokernel of the morphism
[TABLE]
is Mittag-Leffler zero with respect to the multiplicities of the prime components of .
Proof.
This proof is the same as the proof of Lemma 4.14. We have the following commutative diagram:
[TABLE]
where the vertical and horizontal sequences is exact. Here we put
[TABLE]
[TABLE]
[TABLE]
The morphism is constructed in Proposition 5.5. It is surjective by the explicit assignments in Proposition 5.5. We have
[TABLE]
by the similar argument as the proof of Lemma 4.7 and . Thus is Mittag-Leffler zero with respect to the multiplicities of the prime components of . Since is surjective, is also surjective. Since is Mittag-Leffler zero, so is . ∎
Proof of Proposition 5.10 : We put for simplicity. We consider the following commutative diagram:
[TABLE]
The left and central vertical morphism is injective. If , the claim is trivial. We assume that . If , the right vertical morphism is injective by the same argument as Lemma 4.8 and the cokernel of is Mittag-Leffler zero from Lemma 5.11. We can easily show the assertion by induction on .
6. Acknowledgements
I am thankful to Professor Kanetomo Sato for his great help and discussion. This problem was suggested to me by him. I thank Takashi Suzuki for his advice and comment, especially on the proof of the existence of a nice hyper covering. I would like to thank the referee for his/her numerous valuable comments and suggestions to improve the quality of this paper.
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