Regularity results for a class of non-autonomous obstacle problems with $(p,q)$-growth
Cristiana De Filippis

TL;DR
This paper investigates regularity properties of solutions to non-autonomous obstacle problems involving $(p,q)$-growth conditions, providing a comprehensive analysis that encompasses key models in the existing literature.
Contribution
It offers new regularity results for a broad class of non-autonomous obstacle problems with $(p,q)$-growth, extending previous models and assumptions.
Findings
Established regularity results under suitable assumptions
Unified analysis covering main models in literature
Extended understanding of obstacle problems with variable growth conditions
Abstract
We study some regularity issues for solutions of non-autonomous obstacle problems with -growth. Under suitable assumptions, our analysis covers the main models available in the literature.
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Regularity results for a class of non-autonomous obstacle problems with -growth
Cristiana De Filippis
Cristiana De Filippis
Mathematical Institute, University of Oxford
Andrew Wiles Building, Radcliffe Observatory Quarter, Woodstock Road, Oxford, OX26GG, Oxford, United Kingdom
Abstract.
We study some regularity issues for solutions of non-autonomous obstacle problems with -growth. Under suitable assumptions, our analysis covers the main models available in the literature.
Key words and phrases:
Regularity, non-autonomous functionals, obstacle problems, -growth
2010 Mathematics Subject Classification:
35J60, 35J70
Acknowledgements. This work is supported by the Engineering and Physical Sciences Research Council (EPSRC): CDT Grant Ref. EP/L015811/1.
Contents
1. Introduction
Regularity for local minimizers of the functional
[TABLE]
where the integrand has power growth
[TABLE]
has been investigated in the fundamental works [2, 28, 29, 34, 31, 32, 33, 44, 45]. The outcome is -regularity for the gradient of solutions with , and such result is optimal, in the light of the counterexample contained in [45]. Later on, in the seminal papers [38, 39, 40, 41], was introduced the so-called -growth condition, i.e.:
[TABLE]
which is more flexible than (1.2) and allows dealing with models coming from fluid mechanics and material science, [46, 47, 48], such as
[TABLE]
This new framework has been object of intense investigation over the last two decades, see [3, 5, 6, 9, 16, 17, 21, 22, 23, 27, 36] for an incomplete list of relatively recent contributions and [42] for a reasonable survey. In these works is studied the regularity for minimizers of variational integrals like the one in (1.1) with (1.3) in force, which are "free", in the sense that no additional constraint is imposed on solutions and competitors. Classical examples of constrained variational problems are those involving manifold valued maps, see [13, 14, 15] for the -growth case, and obstacle problems. The latter were treated at length in the literature, see [11, 12, 19, 25, 26, 37, 43] for variational inequalities modelled upon the -laplacean energy and [7, 8, 10, 20, 24, 27] for more general structures. The underlying principle is that solutions of the obstacle problem should reflect the regularity of the obstacle itself. This holds verbatim for linear problems, in which solutions are as regular as the obstacle and for certain nonlinear models with Harnack inequalities and full regularity available for unconstrained minimizers. However, this is no longer the case in the nonlinear setting for general integrands without any specific structure. In this situation, extra regularity must be imposed on the obstacle to balance, in some sense, both the nonlinearity and the non-standard growth. The increasing interest towards the regularity for solutions of obstacle problems is also justified by the fact that they can be employed as comparison maps in the investigation of fine properties of solutions of some PDE, see [10, 24, 37, 30] and references therein.
In this paper we provide some regularity results for solutions of non-autonomous obstacle problems with -growth. In dealing with this, the first big problem arising is the possible occurrence of the Lavrentiev phenomenon, i.e.:
[TABLE]
This is a clear obstruction to regularity, since (1.4) prevents minimizers to belong to . Notice that (1.4) cannot happen if or if is autonomous and convex. Moreover, as pointed out in [22, Section 3], the appearance of (1.4) has geometrical reasons and cannot be spotted via standard techniques. Therefore, the basic strategy consists in excluding the occurrence of (1.4) by imposing that the Lavrentiev gap functional vanishes on solutions: at this stage, the closeness condition formulated in (4.2) below assures the validity of certain a priori estimates, then, a convergence argument renders
Theorem 1**.**
Under assumptions (2.8), (4.1) and (4.2), let be as in (4.3) and as in (2.4). If the solution of problem (2.5) satisfies (3.8), then it has the following regularity features:
* for all ;*
- -
* for all .*
In particular, if is any ball, there holds that
[TABLE]
where and .
It is reasonable to expect that, strengthening the regularity assumptions on both, integrand and obstacle, we can actually show better regularity properties than those obtained in Theorem 1. In fact,
Theorem 2**.**
Under assumptions (2.8), (5.1), (5.2) and (5.3), let be as in (5.4)-(5.5) and as in (2.4). If the solution of problem (2.5) satisfies (3.8), then
[TABLE]
Moreover, if are concentric balls, the following local Lipschitz estimate holds
[TABLE]
with , and .
The Lipschitz bound in Theorem 2 is essentially realized in three steps: first, the problem is linearized via the identification of a non-negative Radon measure which turns the variational inequality naturally associated to a regularized version of (2.5) into an integral identity. Then, the revisited Moser’s iteration introduced in [16] leads to a uniform bound on the sup-norm of the gradient of a suitable sequence of maps approximating the original solution. Finally, careful convergence arguments give the conclusion.
The paper is organized as follows: in Section 2 we list some basic assumptions which will always be in force and strengthened when needed; well-known results on fractional Sobolev spaces and some useful miscellanea. We also briefly discuss existence and uniqueness for solutions of problem (2.5). In Section 3 we tackle the question of relaxation of functionals with -growth with obstacle constraint. Sections 4-5 are devoted to the proof of Theorems 1-2 respectively, while in Section 6 we provide a higher weak differentiability result for local minimizers of variational integrals with standard -growth and obstacle constraint.
2. Preliminaries
2.1. Main assumptions
In this section we shall collect some minimal hypotheses which will be eventually strengthened throughout the paper. We assume that , , is an open, bounded domain with boundary and is a Carathéodory integrand satisfying, for all and
[TABLE]
where are absolute constants and the exponents are so that
[TABLE]
Let us consider also two measurable functions: so that
[TABLE]
and
[TABLE]
We are interested in some regularity properties of solutions of the obstacle problem
[TABLE]
where
[TABLE]
and
[TABLE]
In the following, we shall always assume that
[TABLE]
Notice that if is a solution of problem (2.5), then it is a local minimizer of the variational integral in (2.6) with the obstacle constraint, in the sense of the following definition.
Definition 1**.**
By local minimizer of (2.6) with obstacle constraint we mean a map such that
[TABLE]
and whenever is an open set there holds that
[TABLE]
In fact, if is any open subset and is such that for a.e. , then the map
[TABLE]
belongs to since and by construction, a.e. in . Thus and
[TABLE]
In particular, this argument shows that if is a solution of problem (2.5) and is any open subset with boundary regular enough to allow for the concept of traces, then is a solution of the obstacle problem
[TABLE]
where is defined as in (2.7) with replaced by , instead of and it is obviously non-empty, since .
Remark 2.1**.**
Being the outcomes of Theorems 1-2 local in nature, we do not assume more than (2.4) for the regularity of the boundary datum . Anyway, by and [1, Lemma 2.1], hypotheses (2.4) makes problem (2.5) well posed.**
2.2. Notation
In this paper we denote by a general constant larger than one. Different occurences from line to line will be still denoted by , while special occurrences will be denoted by and so on. Relevant dependencies on parameters will be emphasised using parentheses, i.e., means that depends on . In a similar fashion, by we denote a quantity depending on the parameter such that when goes to a relevant limit (typically or ); also in this case the expression of might vary from line to line and relevant dependencies are emphasized. We denote by the open ball with center and radius ; when no ambiguity arises, we omit denoting the center as follows: . Very often, when not otherwise stated, different balls in the same context will share the same center. When considering function spaces of vector valued maps, such as , etc, we often abbreviate as , and so on; the meaning will be clear from the context. Given any differentiable map , with we mean the derivative of with respect to the variable and by the derivative of in the -variable, while, by we denote the second derivative in of and by the mixed one. For the sake of clarity, we shall adopt the shorthand notation
[TABLE]
see Sections 4-5 for more details on all the quantities involved.
2.3. Auxiliary results
We start with some elementary facts on Sobolev functions. For a map , and a vector , we denote by the standard finite difference operator pointwise defined as
[TABLE]
where . It is clear that the finite difference operator is strictly connected with the weak differentiability of a function.
Lemma 2.1**.**
Let be two balls, be a vector with and for some . Then
[TABLE]
Controlling a suitable Lebesgue norm of the finite difference of a function implies weak differentiability.
Lemma 2.2**.**
Let be two balls. If , , is a map such that
[TABLE]
for all vectors with , then
[TABLE]
The next result explains how to control translations.
Lemma 2.3**.**
Let be two balls, be a vector so that and for some . Then
[TABLE]
We now recall a few basic facts concerning fractional Sobolev spaces.
Definition 2**.**
Let , , , and let be an open subset with (we allow for the case ). The fractional Sobolev space is defined prescribing that belongs to iff the following Gagliardo type norm is finite:
[TABLE]
Accordingly, in the case , we say that iff the following quantity is finite
[TABLE]
The local variant is defined by requiring that iff for every open subset .
Definition 3**.**
Let , , , and let be an open subset with . The Nikol’skii space is defined prescribing that iff
[TABLE]
The local variant is defined by requiring that iff for every open subset .
Moreover we have that
[TABLE]
holds for sufficiently regular domains . Notice that, given any ball such that , a function and a vector with , than Definition 3 and immediately imply that
[TABLE]
A local, quantified version of (2.9) in the next lemma.
Lemma 2.4**.**
[4]* Let be a ball with , , and assume that, for , and concentric balls , there holds*
[TABLE]
Then whenever and
[TABLE]
holds, where .
The next is the embedding theorem for fractional Sobolev spaces.
Lemma 2.5**.**
[18]* Let , with , such that and let be a bounded, Lipschitz domain. Then*
* with ;*
- -
* for all , with ;*
- -
* with ;*
with depending at the most from .
We refer to [18] for a survey on this matter. We close this section by reporting some informations on well-known tools in the Calculus of Variations. For constant and we introduce the auxiliary vector field
[TABLE]
which turns out to be very convenient in handling the monotonicity properties of certain operators.
Lemma 2.6**.**
[34]* For any given , there holds that*
[TABLE]
where the constants implicit in "" depend only from .
Another useful result is the following
Lemma 2.7**.**
[2]* Let , and be so that . Then*
[TABLE]
with constants implicit in "" depending only from .
Finally, the iteration lemma.
Lemma 2.8**.**
Let be a non-negative and bounded function, and let , be numbers. Assume that
[TABLE]
holds for all . Then the following inequality holds
[TABLE]
2.4. Existence and uniqueness
The existence of a solution of problem (2.5) easily follows from direct methods, we briefly report a sketch for completeness. Let be a minimizing sequence. Therefore,
[TABLE]
This means that, for sufficiently large there holds that
[TABLE]
Combining , (2.12) and Poincaré inequality we directly have
[TABLE]
thus, up to extract a (non-relabelled) subsequence, we get
[TABLE]
By we have that a.e. in and , thus . Using , , weak lower semicontinuity and (2.11) we can conclude that
[TABLE]
so solves (2.5). In case we ask for strict convexity rather than just , we can guarantee that is actually the unique solution of our problem: in fact, if are both solutions of problem (2.5), we can define and get
[TABLE]
which is clearly a nonsense, since .
3. Relaxation
In this section we shall provide a meaningful definition of relaxation for problem (2.5) in the spirit of [1, 22, 38]. Given the local nature of our main theorems, in the following we will not consider boundary conditions. Let be an open subset and define
[TABLE]
Being convex and closed, is a Banach subspace of and is a Banach subspace of .
Lemma 3.1**.**
Class is dense in with respect to the -norm.
Proof.
Let be a family of standard, non-negative, radially symmetric mollifiers so that
[TABLE]
and set and , where . By the properties of convolution and (2.3) we have that
[TABLE]
Furthermore, there holds
[TABLE]
Now set . From , (3.2), (2.3) and (3.3), it directly follows that and
[TABLE]
∎
Once established this density result, we can consider the relaxed functional
[TABLE]
where
[TABLE]
Notice that is non-empty, given that the sequence , where and are as in (3.2), belongs to , (recall (3.3)). Let us connect functional with the original one appearing in problem (2.5). By and weak-lower semicontinuity, we have
[TABLE]
Moreover, if , we get in addition that the regularized sequence in , strongly converges to in , therefore, using a well-known variant of Lebesgue dominated convergence theorem, we end up with
[TABLE]
From (3.4) and (3.5) we can conclude that if , then . As in [22], we then define the gap functional
[TABLE]
If is so that , then there exists a sequence so that
[TABLE]
see [1, Section 4]. This is actually the key to show that the vanishing of the Lavrentiev gap functional assures that
[TABLE]
Indeed, since , we have
[TABLE]
and if we assume that , where is so that
[TABLE]
then we can find a sequence as in (3.6) which realizes (3.7).
Remark 3.1**.**
We saw before that for any given map , condition
[TABLE]
yields (3.6), which is a crucial tool in the proof of Theorems 1-2. In particular, if we do not assume any specific underlying structure for the integrand , (3.8) needs to be taken as an assumption. On the other hand, by [22, Section 5] and [35, Section 3.5], under suitable assumptions, we know that there are several models, such as**
[TABLE]
just to quote the most popular, realizing (3.8). In fact, whenever is so that and is an open subset, then we can regularize via a family of mollifiers as in (3.1), thus obtaining a sequence satisfying**
[TABLE]
for all . We can then apply the trick presented in the proof of Lemma 3.1 and make minor changes to the techniques in [22, Section 5] and [35, Section 3.5] to build a sequence matching (3.6). Given that (3.6) and (3.8) are equivalent, under the appropriate set of assumptions on exponents or coefficients, our results cover models -, see Sections 4-5 for more details.**
4. Proof of Theorem 1
To prove Theorem 1, we need to assume something more on both the integrand and on the obstacle . Precisely, we ask that the Carathéodory integrand verifies
[TABLE]
for all and all with and absolute constants. The exponents are such that
[TABLE]
and the obstacle satisfies
[TABLE]
Some comments are in order. First, notice that (2.2) holds also in this case. Moreover, implies that
[TABLE]
and, as a consequence of and (4.4), we get that
[TABLE]
see [41, Lemma 2.1]. Furthermore, by Lemma 2.5,
[TABLE]
so in any case and also (2.3) still holds true. This legalizes our final assumption: condition (3.8) is verified by the solution of problem (2.5), (recall the content of Section 2.4 and (4.4)). Finally, by (4.3) and (2.3) we can conclude that if is a ball and is any vector with , then
[TABLE]
for . For the ease of exposition, we shall split the proof into two moments: first we are going to show the higher integrability result and then derive extra fractional differentiability.
4.1. Higher integrability
Let be the solution of problem (2.5). Let us fix a ball with . Since satisfies (3.8), by (3.6), this means that there exists a sequence such that
[TABLE]
We introduce a suitable family of regularized problems. To do so, we set
[TABLE]
and consider the obstacle problem
[TABLE]
where
[TABLE]
and
[TABLE]
Notice that since by (4.7), . Recalling assumptions (4.1), it is easy to see that the integrand in (4.8) satisfies
[TABLE]
whenever and for absolute constants and . Notice that yields that is strictly convex so, again by it follows that
[TABLE]
Using the content of Section 2.4, we see that there exists a unique solution of problem (4.9) and the following variational inequality holds
[TABLE]
To recover (4.14), we pick any and notice that, for , the function belongs to , thus it is an admissible competitor in problem (4.9). By the minimality of we have
[TABLE]
Now we can use (4.13) to legalize an application of the dominated convergence theorem and send in (4.1), the outcome being precisely (4.14). At this point we fix parameters , take a cut-off function with the following specifics:
[TABLE]
and a vector with . We look at the map . By construction, , condition guarantees that and
[TABLE]
therefore is an admissible test function in (4.14). Using the integration by part rule for finite difference operators we obtain
[TABLE]
From and Lemma 2.6, we readily have
[TABLE]
Combining , Hölder and Young inequalities, , Lemma 2.3 and (4.6) we obtain
[TABLE]
where . By (4.13), Hölder and Young inequalities, (4.16), Lemmas 2.1 and 2.3 we get
[TABLE]
with . Using , Hölder and Young inequalities, and Lemma 2.3 we see that
[TABLE]
for . Finally, exploiting , Hölder and Young inequalities, (4.16), Lemmas 2.3 and 2.1 we obtain
[TABLE]
where . Merging the content of all the above displays and recalling , we can conclude that
[TABLE]
with . Now we can invoke Lemma 2.4 to get, with (4.17),
[TABLE]
with , so, by Lemma 2.5 we obtain
[TABLE]
for all . In (4.18), . We manipulate (4.18) in a more convenient way:
[TABLE]
set . Notice that, by (4.2), for , there holds that , thus we can apply the interpolation inequality
[TABLE]
where is derived via the equation
[TABLE]
Inserting (4.20) in (4.19) we get
[TABLE]
so, for and (4.2) we see that . This allows using Young inequality with conjugate exponents and to obtain
[TABLE]
where we set and . Since inequality (4.21) holds true for all , we can use Lemma 2.8 to end up with
[TABLE]
with and as in (4.21). At this stage, we jump back to problem (4.9) and notice that by , . Thus, using the minimality of in class we get
[TABLE]
thus
[TABLE]
Merging (4.23), and (4.22) we get
[TABLE]
thus, by , (4.25) and weak lower semicontinuity, we can conclude that
[TABLE]
At this point we only need to show that for a.e. . To do so, we notice that by , and the weak continuity of the trace operator, there holds that
[TABLE]
Moreover, by , (4.10), , weak lover semicontinuity and the minimality of the ’s we have
[TABLE]
Collecting estimates (4.25) and (4.1) and keeping in mind (4.4) and (4.26) we can conclude that a.e. in and
[TABLE]
with and . Recalling that is arbitrary, using Hölder inequality in (4.28) we obtain (1.5), where is arbitrary. Finally, a standard covering argument renders that and we are done.
Remark 4.1**.**
For transforming (4.18) into (4.19), we implicitely used that, for any map , such that for some there holds**
[TABLE]
Inequality (4.29) is trivial when , while for we have**
[TABLE]
therefore**
[TABLE]
where we also used that .**
Remark 4.2**.**
The arbitrariety of allows a corresponding choice of , therefore we will translate any dependency of the constants from into the one from , i.e.: becomes . This justifies the final dependencies of the constant appearing in (1.5).**
4.2. Fractional differentiability
Let be the solution of problem (2.5). Combining assumption (4.2) and the outcome of Theorem 1, we see that , so, in particular, . This means that we no longer need the approximating problems to study the fractional differentiability of . In fact, let be any ball with and notice that, as in Section 2.4, it follows that is the solution of
[TABLE]
where is defined as in (4.11), with instead of . As for (4.14), we see that the variational inequality
[TABLE]
holds for all and the map is an admissible test function. Here, is such that
[TABLE]
and . We can repeat exactly the same procedure outlined in Section 4 with , both replaced by , to end up with
[TABLE]
for all , with . Via a standard covering argument, we can conclude that for all and the proof is complete.
5. Proof of Theorem 2
The proof of Theorem 2 requires certain assumptions which are stronger that (2.1)-(4.1). Precisely, we need a Carathéodery integrand satisfying
[TABLE]
for all and . In (5.1), are absolute constants, and
[TABLE]
the exponents match condition
[TABLE]
Concerning the obstacle, we shall assume that
[TABLE]
When or , we also ask that
[TABLE]
where is the same as in (5.2). Notice that the hypotheses considered in Section 3 are trivially satisfied. Moreover, as before, assumption implies that
[TABLE]
We just spend a few lines commenting on the relation between (4.2) and (5.3). First, notice that as in [16, Remark 1.4], we directly see that, whenever and , there holds
[TABLE]
for , which is with and such value of turns (5.3) in (4.2). Therefore, if assumptions (5.1)-(5.4) are satisfied and if the solution of problem (2.5) satisfies (3.8) for all open subsets , then
[TABLE]
by Theorem 1. Finally, integrating (5.7) and using that, by , , we can conclude with
[TABLE]
with .
Remark 5.1**.**
Assumption comes essentially for free. In fact, if is any integrand as in (5.1) with not constant for all , then we can consider the shifted function . It is then straightforward to check that matches (5.1) (with instead of ) and, by construction, is constantly equal to .**
Remark 5.2**.**
Assumption (5.5) has a significant role only to treat the degenerate case when
[TABLE]
If and (5.9) holds, we can neglect it up to accept a dependency from of the constants appearing in the forthcoming estimates.**
5.1. Approximating problems
As in [16, Section 4], we regularize the integrand in (5.1) and correct its non-standard growth behavior in the following way. Let be two concentric balls with . We consider a standard family of symmetric mollifiers for such that , that is
[TABLE]
We then define
[TABLE]
for all . By the very definition in (5.11) and (5.8), we have
[TABLE]
We further define
[TABLE]
for and . Next, we use that satisfies (3.8) which, by the results in Section 3, renders a sequence such that
[TABLE]
For simplicity, define
[TABLE]
Recalling also (5.5), we trivially observe that
[TABLE]
We then set, for ,
[TABLE]
with
[TABLE]
Finally, we define . From (5.1), (5.10), (5.11) and some convolution arguments, see [16, Section 4], we see that the integrand satisfies
[TABLE]
for all and with . We stress that in particular implies strict convexity and the monotonicity inequality
[TABLE]
see also Lemma 2.6. Let us consider the obstacle problem
[TABLE]
where is the same as in (4.11). By direct methods (cf. Section 2.4) we know that there exists a unique solution of problem (5.19), satisfying the variational inequality
[TABLE]
Moreover, recalling the discussion in Section 2.1, is a local minimizer of the variational integral with obstacle constraint, thus assumptions (5.17), (5.4), (5.14) together with Proposition 6.1 assure that
[TABLE]
5.2. Linearization
We aim to recover an integral identity from the variational inequality (5.20). To do so, we follow the arguments in [26, 27] and pick a cut-off function so that for all and, for , we take a function satisfying
[TABLE]
The map clearly belongs to , thus it is an admissible test in (5.20). We then get
[TABLE]
so, by Riesz representation theorem there exists a non-negative Radon measure such that
[TABLE]
Notice that, as shown in [26, Section 3], does not depend on . Let us find a suitable representative for the measure . From (5.23), (5.1) and we estimate
[TABLE]
Set . Using the position in (5.22), we get that
[TABLE]
since on . Concerning term (II), by (5.4) and (5.21) we can integrate by parts, thus getting
[TABLE]
Merging (5.23), (5.24) and (5.2) we obtain
[TABLE]
for all such that . This implies that
[TABLE]
and that there exists a density function such that
[TABLE]
Set . Notice that by (5.4), exists almost everywhere in , thus we can compute
[TABLE]
so by there holds that
[TABLE]
where , while, by , we have
[TABLE]
with . Estimate (5.2) implies that
[TABLE]
and, by (5.2), (5.2), (5.5), , and (5.15) we see that
[TABLE]
This means that the ’s have uniformly bounded -norm. Once identified we turn back to (5.23), which, as in [25], implies that
[TABLE]
for all such that on . Now (5.31), (5.26), (5.29) and standard density arguments lead to
[TABLE]
5.3. Caccioppoli inequality
By virtue of (5.21), we can differentiate equation (5.32) and sum over to obtain
[TABLE]
which holds for all with . We let be any non-negative map, a fixed number and set . A straightforward computation shows that
[TABLE]
so, again by (5.21), is admissible in (5.33). We can rewrite (5.33) as
[TABLE]
where the terms indexed with (resp. ) denote the ones stemming from those in (5.33) containing (resp. ). Since
[TABLE]
with we estimate
[TABLE]
From , Hölder and Young inequalities we have
[TABLE]
with . By , Hölder and Young inequalities we see that
[TABLE]
where . In an analogous fashion we also bound
[TABLE]
and
[TABLE]
In the previous two displays, . Finally, by means of (5.30), (5.3), Hölder and Young inequalities we control
[TABLE]
Similarly we have
[TABLE]
and
[TABLE]
where we also used that , being . In the above three displays, . All in all, we got
[TABLE]
By (5.3), Sobolev embedding theorem combined with the elementary inequality for and , we obtain
[TABLE]
where we set
[TABLE]
5.4. Moser’s iteration
We shall use the modified Moser’s iteration developed in [16]. For every integer , we define by induction the exponents
[TABLE]
It follows that
[TABLE]
where
[TABLE]
From (5.38) we have that for all integers , there holds
[TABLE]
and, being , then . Moreover, it is easy to see that
[TABLE]
From now on, all the balls considered will be concentric to . We abbreviate
[TABLE]
and notice that, by (5.21), is bounded on any interval with . For , we consider a sequence of shrinking balls, where . Notice that is a decreasing sequence such that and ; therefore it is and . Accordingly, we fix corresponding cut-off functions with
[TABLE]
We fix in (5.3) and rearrange it as to obtain
[TABLE]
where we set , since and . For we set
[TABLE]
thus (5.4) reads as
[TABLE]
with . Iterating the inequality in (5.43) we obtain
[TABLE]
for all . By (5.40) and simple comparison arguments
[TABLE]
we get that
[TABLE]
with and , see [16, Section 4.3] for more details. With (5.45) at hand we can further bound (5.44) to obtain
[TABLE]
Finally, notice that
[TABLE]
so we can send in (5.46) and conclude with
[TABLE]
Since
[TABLE]
which is the case by (5.3) and (5.37). Hence, we can apply Young inequality to (5.47) with conjugate exponents and to get
[TABLE]
where we set and , thus and . Finally, Lemma 2.8 and (5.4) render that
[TABLE]
for , and .
5.5. Convergence
Looking at the very definition of problem (5.19), we fix an arbitrary and using , and (5.16) we get
[TABLE]
Since is fixed and , by (5.12) we have
[TABLE]
therefore the sequence is bounded in uniformly in . Hence, up to extract a (non-relabelled) subsequence (depending on the chosen index ), we find that
[TABLE]
From (5.47), (5.5), (5.51) and it follows that
[TABLE]
with , and . This implies that, again up to subsequences, in , so by weak*∗*-lower semincontinuity we can send in (5.53) to end up with
[TABLE]
for , and . Notice that (5.54) actually holds for all concentric balls with . Now, by (5.12) and (5.53) we have
[TABLE]
and, by weak lower semicontinuity there holds that
[TABLE]
Merging all the above informations we obtain
[TABLE]
where for the last inequality we also used (5.5) and (5.51). Letting in the previous display we see that
[TABLE]
By , (5.55) and the arbitrariety of , we deduce that the sequence is uniformly bounded in , therefore, recalling also and , we get that
[TABLE]
thus . Moreover, combining (5.54) and we also obtain that
[TABLE]
for all balls concentric to with . Weak*∗*-lower semicontinuity, (5.57) and (5.54) render that
[TABLE]
with , and . Now we can exploit and weak-lower semicontinuity to pass to the limit in (5.55) and obtain
[TABLE]
Combining (5.59), , the minimality of in class and (5.6) we can conclude that a.e. on thus estimate (5.58) holds for as well. Finally, via a standard covering argument we get that and the proof is complete.
6. Weak differentiability for obstacle problems with standard -growth
In this section we prove a higher regularity result for solutions of non-autonomous obstacle problems with standard polynomial growth. Precisely, we shall consider an integrand satisfying
[TABLE]
for all and . Here, are absolute constants and we set with . For the obstacle function , we shall retain (5.4). We study regularity for local minimizers of the variational integral with obstacle constraint
[TABLE]
where this time
[TABLE]
Of course we are supposing that
[TABLE]
Our main result in this perspective is the following
Proposition 6.1**.**
Let be a solution of problem (6.2) under assumptions (6.1), (5.4) and (6.3). Then
[TABLE]
for some . Moreover, there holds that
[TABLE]
Proof.
First notice that, by we can compute the variational inequality associated to problem (6.2): we have that
[TABLE]
The local -regularity follows from the results in [11, 12, 43], but for our ends will be enough. To prove the weak higher differentiability of , as in Section 4.2, we fix a ball , , pick a cut-off function so that
[TABLE]
a vector with and test (6.5) against the map . We obtain
[TABLE]
The decomposition into terms (I)-(VI) is the same appearing in Section 4.1, but the resulting estimates will be slightly different from what we did before, owing to the higher regularity we are assuming now for both integrand, obstacle and solution. For simplicity we shall separate the three cases , and .
Case 1: . By and Lemma 2.6 we have
[TABLE]
for . Using , the mean value theorem, Lemmas 2.6, 2.3, 2.1 and 2.7, (5.4), Hölder and Young inequalities we get
[TABLE]
for . From , Lemmas 2.1, 2.6 and 2.7, , Hölder and Young inequalities we obtain
[TABLE]
where . By , Lemmas 2.6, 2.3 and 2.1, , Hölder and Young inequalities we have
[TABLE]
with . Finally, exploiting , Lemmas 2.3 and 2.1, , Hölder and Young inequality we end up with
[TABLE]
for .
Case 2: . Only terms (II)-(III) need a different treatment. By , the mean value theorem, Lemmas 2.6, 2.3, 2.1 and 2.7, (5.4), Hölder and Young inequalities we have
[TABLE]
where . Using the mean value theorem, , Lemma 2.1, Hölder and Young inequalities we get
[TABLE]
with .
Case 3: . As for the previous case we bound
[TABLE]
and
[TABLE]
In both the previous displays, .
Merging all the previous estimates and choosing sufficiently small, we obtain
[TABLE]
for . Combining (6.6) with Lemma 2.2 and recalling the specifics of the cut-off , we obtain, that and, after a standard covering argument we reach the conclusion that . An easy computation than shows that
[TABLE]
thus, for any given open subset , there holds that
[TABLE]
Hence, after a standard covering argument, we can conclude that and, since
[TABLE]
with , it also follows that and we are done. ∎
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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