Involutions on algebraic surfaces and the Generalised Bloch's conjecture
Kalyan Banerjee

TL;DR
This paper investigates how involutions on smooth projective surfaces influence the Chow group of zero cycles, aiming to shed light on aspects related to the Generalised Bloch's conjecture.
Contribution
It provides new insights into the action of involutions on algebraic surfaces and their Chow groups, contributing to the understanding of the Generalised Bloch's conjecture.
Findings
Analysis of involution actions on zero cycles
Results supporting the conjecture in specific cases
New techniques for studying algebraic surface symmetries
Abstract
In this note we are going to consider a smooth projective surface equipped with an involution and study the action of the involution at the level of Chow group of zero cycles.
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Taxonomy
TopicsAlgebraic Geometry and Number Theory · Advanced Algebra and Geometry · Advanced Differential Equations and Dynamical Systems
Involutions on algebraic surfaces and the Generalised Bloch’s conjecture
Kalyan Banerjee
HRI, India
Abstract.
In this note we are going to consider a smooth projective surface equipped with an involution and study the action of the involution at the level of Chow group of zero cycles.
1. Introduction
In this note we want to consider the generalised Bloch conjecture [Vo] [conjecture 11.19], which says that the action of a degree two correspondence on the Chow group of zero cycles on a smooth projective surface is determined by its cohomology class in . This is equivalent to the following: let be a correspondence of codimension on where are smooth projective surfaces over the field of complex numbers. Suppose that vanishes on then the homomorphism from to vanishes on the kernel of the albanese map .
In [Voi], the conjecture was proved for a symplectic involution on a surface. In this paper the author consider an automorphism of order two of the given K3 surface, such that acts as identity on globally holomorphic -forms, then acts as identity on of the K3 surface. Also the similar question was considered in [G] for intersection of quadrics and cubics in which are examples of K3 surfaces. Also in [HK] the question was considered and proved for certain examples of K3 surfaces equipped with a symplectomorphism.
In this note we prove the following theorem:
Let be a smooth surface admitting a map to a surface admitting an elliptic pencil such that the corresponding Jacobian fibration admits an ample line bundle such that the genus of the curves in are bounded by some positive integer . Let be the involution on arising from the map. Then the group of invariants of , given by
[TABLE]
is finite dimensional.
Our method of proof goes in the line of the proof of Bloch’s conjecture for surfaces not of general type with as in [BKL] and of the arguments present in [Voi].
Acknowledgements: The author would like to thank the ISF-UGC project for funding this project and also thanks the hospitality of Indian Statistical Institute, Bangalore Center for hosting this project. The author is indebted to Ramesh Sreekantan for suggesting this problem to the author and for many helpful discussions on the theme of the paper. Lastly the author is grateful to Chuck Weibel for constructive criticism on improving the exposition of the paper and for his advice to improve 2.1.
We assume that the ground field is algebraically closed and of characteristic zero.
2. The Bloch-Kas-Liebarman technique
In this section we prove the following theorem:
Theorem 2.1**.**
Let be a smooth surface admitting a map to a surface admitting an elliptic pencil such that the corresponding Jacobian fibration admits an ample line bundle such that the genus of the curves in are bounded by some positive integer . Let be the involution on arising from the map. Then the group of invariants of , given by
[TABLE]
is finite dimensional.
Proof.
To prove that the group of -invariants of the Chow group of degree zero cycles of , we follow the Bloch-Kas-Lieberman technique as presented in [BKL]. First consider the pencil of elliptic curves on the surface . That is a map from , where is isomorphic to .
Suppose that a pencil of curves on a surface can be given by choosing a projective line in , where is a line bundle on . So every element of this projective line gives rise to a global section of , which is non-zero and well-defined upto scalar multiplication. Let be the curve in defined by the zero locus of . Now let be two linearly independent global sections spanning the two dimensional vector subspace of , underlying the line . Then any element in this vector space look like . Now the rational map is defined by
[TABLE]
and it is not defined along the common zero locus of . Consider the surface
[TABLE]
this is nothing but the blow-up of along the base locus of the above rational map. Then sending to defines a regular map from to . That is we blow up the base locus of the rational map . Now consider the pull-back of to , call it . Then is nothing but the blow up of along the base locus of the rational map . Observe that fixing a point [math] in on , which is in the base locus of the pencil, we have a section of given by . Let us continue to denote the map from to by .
Consider the Jacobian fibration corresponding to . Now fix a smooth hyperplane section of under the embedding of in some . Let be the morphism from and is from . Let us have
[TABLE]
Then we have a map from to
[TABLE]
where is the Albanese map from to , . It is defined because the pencil has a section. This map is dominant as it is dominant on fibers.
Now we recall the notion of finite dimensionality in the sense of Roitman [Ro2]: Consider a correspondence on , then the image of from to is said to be finite dimensional if there exists a smooth projective variety and a correspondence on such that the image of is contained in the set:
[TABLE]
Lemma 2.2**.**
Let the image of be finite dimensional in the above mentioned sense. Then the group of invariants under the action of , in is finite dimensional.
Proof.
The proof of this lemma follows by arguing as in [BKL][proposition 4]. To prove the claim we have to understand the quasi-inverse of given by a correspondence on . Let belong to that lies over . View as a zero cycle on , that is it is an element in (by using the section for the Jacobian fibration). Since is isomorphic to , there is a unique point in on such that is rationally equivalent to . Now . So we can define to be
[TABLE]
Let be a zero cycle where are closed points on . Then we compute . We have by definition
[TABLE]
let . Then
[TABLE]
which can be re-written as
[TABLE]
Now . Therefore is equal to
[TABLE]
where is a zero cycle supported on . So for general hyperplane section of , we have a smooth projective curve. Therefore by Chow moving lemma, for any zero cycle of degree zero on , we have
[TABLE]
is supported on the Jacobian of . Suppose that we can prove that the image of is finite dimensional in the sense that there exists a smooth projective variety and a correspondence on , such that the image of is contained in the set
[TABLE]
Then we get that is supported on for a smooth projective curve . Tensoring with we get that is supported on . So it means that the group of -invariant elements in , is finite dimensional (rationally): in the sense that there exists a smooth projective curve , and a correspondence on such that from to is surjective. Then by lemma 3.1 in [GG] it follows that the group of -invariant elements of is finite dimensional. Since is a blow-up of and finite dimensionality is a birational invariant, we have the group of -invariant elements of is finite dimensional. ∎
Now we prove the following:
Lemma 2.3**.**
Let be as above and is equipped with an elliptic pencil on it. Suppose there exists on ample and the genus of the curves in are bounded by some integer . Let be as above. Then the image of is finite dimensional.
Proof.
Consider the symmetric power . Now given a zero cycle of the form on , we have each of belongs to a unique fiber for a general . Let us fix a point which belongs to the exceptional locus of the blow up . Then belongs to all the fibers of the fibration . Then write . Now consider the map from to , given by
[TABLE]
Now by the above we have that
[TABLE]
belongs to the Jacobian , such that belongs to . Actually
[TABLE]
lands inside the -invariant part of the involution on , denote it by . Here has dimension as it is complementary to the -anti-invariant part in . Indeed has dimension
[TABLE]
by the Riemann-Hurwitz formula ( is the ramification locus). Therefore the dimension of -antiinvariant part is
[TABLE]
hence the dimension of is .
Therefore we have that the map from to factoring through the fibration , here is the abelian fibration of the abelian varieties over . So the dimension of
[TABLE]
is . Therefore the map from to is generically finite.
Since the fibers of are of dimension , we have that the fibers are elliptic curves. So we have
[TABLE]
is a product of surfaces with elliptic fibrations. Note that is isomorphic to . Hence . Therefore the group is dominated by
[TABLE]
or by
[TABLE]
where varies over natural numbers. Now consider the following commutative diagram:
[TABLE]
Then the fibers of the right hand side vertical map contains the image of the fibers of the left-hand side vertical map, which are by the Riemann-Roch theorem (when ). Therefore the fiber of the map
[TABLE]
contains a projective space , as the map from is surjective. Actually the family of such that is supported on contains a projective bundle over . Now we choose an ample smooth projective curve in . Since is bounded, by adjunction formula, we have that the genus of is bounded and less than . We choose to be much bigger than the genus of , then the divisor on intersects the fibers of the map
[TABLE]
Therefore the image of the above map is actually the image of . Consider the map
[TABLE]
Then again by the previous process the fibers of the above map are supported on
[TABLE]
By continuing this process, the fibers of the map
[TABLE]
are supported on
[TABLE]
Here is the number of iterations such that is less than the dimension of the fiber of the map
[TABLE]
which is by Riemann-Roch theorem, equal to . Therefore, when , the image of under is same as , which is same as . Therefore we have that
[TABLE]
So the image of under is same as the image of under for . Hence the image of is finite dimensional by [Voi][lemma 3.1].
∎
∎
Corollary 2.4**.**
Let be the branched double cover of an elliptic K3 surface , let be the involution on involution . Then the corresponding Jacobian fibration associated to the elliptic pencil does not have an ample line bundle on it, such that it satisfies the following property:
Given any positive integer as in the above theorem, the number of iterations is greater than .
Proof.
If there exists such line bundles then it will follow from the previous theorem 2.1 that is finite dimensional, which is not true because geometric genus of is greater than zero. ∎
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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