Dehn functions of mapping tori of right-angled Artin groups
Kristen Pueschel, Timothy Riley

TL;DR
This paper classifies the Dehn functions of algebraic mapping tori of certain right-angled Artin groups based on their automorphisms, revealing how these functions depend on the automorphism structure.
Contribution
It provides a complete classification of Dehn functions for mapping tori of specific right-angled Artin groups, including all 3-generator cases and products of free groups.
Findings
Dehn functions depend on the automorphism ta; classification achieved for key classes of right-angled Artin groups.
Explicit descriptions of Dehn functions for all 3-generator right-angled Artin groups.
Results extend understanding of geometric properties of automorphism-induced group extensions.
Abstract
The algebraic mapping torus of a group with an automorphism is the HNN-extension of in which conjugation by the stable letter performs . We classify the Dehn functions of in terms of for a number of right-angled Artin groups , including all -generator right-angled Artin groups and for all .
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Taxonomy
TopicsGeometric and Algebraic Topology · Algebraic Geometry and Number Theory · Advanced Combinatorial Mathematics
Dehn functions of mapping tori of right-angled Artin groups
Kristen Pueschel and Timothy Riley
Abstract.
The algebraic mapping torus of a group with an automorphism is the HNN-extension of in which conjugation by the stable letter performs . We classify the Dehn functions of in terms of for a number of right-angled Artin groups , including all -generator right-angled Artin groups and for all .
2010 Mathematics Subject Classification: 20F65, 20F36
Key words and phrases: Dehn function, right-angled Artin group, mapping torus
1. Our results
When studying mapping tori, a natural question is how the maps used to define them determine their geometry. The paradigm is the Nielsen–Thurston classification of topological mapping tori. When is a compact orientable surface of genus at least and is a homeomorphism, the mapping torus is , with defined so that for all . The classification is that, up to isotopy, is of one of three types: (1) reducible, in which case the mapping torus contains an incompressible torus, (2) periodic, in which case the mapping torus admits an structure, and (3) psuedo-Anosov, in which case the mapping torus admits a hyperbolic structure.
Here, we study algebraic mapping tori of right-angled Artin groups. For a finitely presented group and an injective endomorphism , the algebraic mapping torus is the group
[TABLE]
In this article, will always be an automorphism, so , and will always be a right-angled Artin group (‘RAAG’)—that is, is encoded by a finite graph with vertex set in that is presented by
[TABLE]
Algebraic mapping tori arise naturally as fundamental groups of topological mapping tori of surfaces or complexes.
The lens through which we will study the geometry of will be the Dehn function (which we will always consider qualitatively—that is, up to an equivalence relation : for , write when there exists such that for all , and write when and ). The Dehn function is an invariant of finitely presentable groups which can be framed either as an algorithmic complexity measure for the word problem or as an isoperimetric function recording the minimal area of discs spanning loops as a function of the lengths of the loops. (More details are in Section 3.1.)
Our study of Dehn functions for mapping tori of RAAGs is motivated by the following two classifications. The first concerns , the RAAG associated to the complete graph with vertices.
Theorem** (Bridson–Gersten [6], Bridson–Pittet [9]).**
Suppose . If has an eigenvalue with , then the Dehn function of the mapping torus is exponential. Else, the Dehn function of is polynomial of degree , where is the size of the largest Jordan block in the Jordan Canonical form of the matrix associated to .
The second concerns , the rank- free group, i.e. the RAAG associated to the graph with vertices and no edges. An automorphism of is atoroidal when there are no periodic conjugacy classes—that is, for all and , if and are conjugate, then or .
Theorem** (Bestvina–Handel [3], Brinkmann [10], Bridson–Groves [7]).**
Suppose . The mapping torus is hyperbolic (that is, has linear Dehn function) if and only if is atoroidal. All other have quadratic Dehn functions.
RAAGs can be viewed as interpolating between free abelian and free groups, so it is natural to look to extend the above theorems to other RAAGs. We thank Karen Vogtmann for suggesting this problem.
A classification of the Dehn functions of all RAAGs remains out of reach. Here we complete the classification for three-generator RAAGs and all groups where .
For , , , , and , the theorems above classify the Dehn functions of . The remaining three-generator RAAGs are and . Here are our results.
Theorem 1.1**.**
Suppose . Let be the map induced by via the map killing the factor. Let be the map induced via the abelianization map , .
Let be projection to the second factor. Exactly one of the following holds:
- (1)
There exists and such that and , in which case has cubic Dehn function. 2. (2)
* has quadratic Dehn function.*
Theorem 1.2**.**
Suppose . Suppose restricts to an automorphism on the factor and satisfies . Let be the restriction of to the -factor. Exactly one of the following holds:
- (1)
* is finite order, in which case has quadratic Dehn function.* 2. (2)
* has an eigenvalue such that , in which case has exponential Dehn function.* 3. (3)
* has cubic Dehn function.*
Theorem 1.2 is effective in that given a , a as per the statement is easy to produce: see Lemma 6.1.
Suppose is a free group with a finite basis . For , denotes the length of the reduced word on representing . The growth of an automorphism is defined by . While the growth type of does not depend on the choice of , it is not invariant under inner automorphisms. For example, the automorphism has linear growth, whereas has constant growth. The cyclic growth of an automorphism accounts for this issue; it describes the growth of (all) conjugacy classes under iteration of automorphisms, and is invariant under inner automorphisms. (Details are in Section 7.2.)
We classify the Dehn functions of mapping tori of products of free groups with as follows.
Theorem 1.3**.**
If where , and , then we can find and such that satisfies in . The Dehn functions of the associated mapping tori satisfy and their asymptotics can be read off and in that:
- (1)
If for some , and either 1 or 2, then . 2. (2)
If for some , then , and likewise with the indices and interchanged. 3. (3)
If , then grows exponentially.
As we will explain in Section 7.2, the three cases in this theorem are exhaustive and mutually exclusive.
Since all automorphisms of are periodic or have cyclic growth that is linear or exponential, this implies:
Corollary 1.4**.**
If and , then has quadratic, cubic, or exponential Dehn function.
The case when , stands in the way of a full classification of Dehn functions of mapping tori over . It differs from with because has non-trivial center, which results in additional transvections. What we can say about the Dehn functions of mapping tori of is that they satisfy . The cubic upper bound comes by recognizing as a central extension of and then applying Corollary 4.4. The quadratic lower bound comes from the presence of a -subgroup: the square of the stable letter commutes with the -factor. In special cases we can determine the Dehn function.
For all , there exists with the form such that in .
- (1)
If is atoroidal, then has quadratic Dehn function by Theorem 4.4, because the base of the central extension is hyperbolic and maximal trees have linear diameter. 2. (2)
If there is such that , then has cubic Dehn function by Theorem 3.5.
Our techniques for do not apply to for . We heavily use the isomorphism and the fact that for any given some iterate fixes the conjugacy class . These fail in higher rank.
Another example to investigate next is the RAAG whose graph is the path with four vertices and three edges.
2. Overview
This article is organized as follows. In Section 3, we give background on Dehn functions and on corridors in van Kampen diagrams. In Section 4 we review the electrostatic model of Gersten and Riley from [15]. We prove Theorems 1.1, 1.2, and 1.3 in Sections 5, 6 and 7, respectively.
Here is an overview of our strategy. Given a RAAG , we organize its automorphisms into cases, chosen so that within each case we can present in a manner which facilitates analysis of its Dehn function. In some cases we find it convenient to replace by a power; this, in turn, replaces by a finite index subgroup, which does not qualitatively change the Dehn function.
In the setting of Theorem 1.1, our presentation expresses as a central extension of another mapping torus . Then we use what Gersten and Riley called an electrostatic model in [15] to get upper bounds on the the Dehn function of . The idea is that a van Kampen diagram over can be ‘charged’ by elements of the kernel of the extension (elements of the center of ). The diagram is then ‘inflated’ by adding in suitable corridors to connect up these charges and get a van Kampen diagram over . This leads to diagrams of cubic area (as a function of their boundary length) and so a cubic upper bound on the Dehn function. For certain , we improve this estimate to quadratic by noticing that is hyperbolic relative to a subgroup that receives no charges. This implies that only linearly many charges appear in the diagram, and thereby that the resulting van Kampen diagram over has quadratic area. For other we define partial corridors in van Kampen diagrams and then use Hall’s Marriage Theorem to give a special pattern for discharging the diagrams, which again improves the Dehn function upper bound to quadratic.
As for obtaining the matching lower bounds, the Dehn function of is always at least quadratic because is not hyperbolic. For certain , a result of Bridson and Gersten (see Lemma 3.5) improves this to a cubic lower bound by identifying a suitable quasi-isometrically embedded abelian subgroup of to which the action of restricts.
For Theorem 1.2 the main innovation is for a case where even though the are not central extensions, is such that one generator commutes with all but a particular generator that forms corridors. By specifying how -corridors have to join in van Kampen diagrams over the quotient of in which is killed, we are able to apply the electrostatic model to regions complementary to the -corridors. We then define alternating corridors which string together two types of partial corridors. We show that these alternating corridors can intersect themselves and each other at most once, and that every 2-cell in the diagram is contained in some alternating corridor. This lets us show that the area of the van Kampen diagram in the quotient is at most quadratic in the length of the boundary word. The electrostatic model then produces a van Kampen diagram with at most cubic area.
For the lower bounds of Theorem 1.3 we exhibit a family of words such that any van Kampen diagram for one of these words has area we can bound below on account of having a belt of corridors of controlled length. For the upper bound we estimate the number of relators that need to be applied to convert a word representing the identity over the mapping torus of to a word with that represents the identity in , and then we use the fact that the Dehn function of is at most quadratic. The upper and lower bounds on the Dehn function are derived from two different notions of free group automorphism growth, which we reconcile by appealing to a number of results in the literature.
3. Preliminaries
We write to denote the length of a word . Our conventions are and .
3.1. Van Kampen diagrams, corridors, and Dehn functions
These topics feature in many surveys, for instance [8]. Here are the essentials.
Suppose is a finitely presented group (so and are finite). Suppose is a word on such that in . A van Kampen diagram for is a simply-connected planar 2-complex with edges labeled by elements of and directed so that the following holds. When traversing counterclockwise from some base vertex, we read off , and around the boundary of each 2-cell in one direction or the other and from a suitable base vertex, we read an element of . (If an edge is traversed in the direction of its orientation, the positive generator is implied, and if against its orientation, the inverse of the generator.) The 1-skeleton of has the path metric in which every edge has length 1. The area of is the number of 2-cells it has. denotes the minimum area among all van Kampen diagrams with boundary word .
The Dehn function of is .
Up to the equivalence relation defined in Section 1, the Dehn function does not depend on the choice of finite presentation for , and, moreover, is a quasi-isometry invariant among finitely presented groups. In particular, we will need:
Proposition 3.1**.**
If is finitely presented and is a finite index subgroup, then is also finitely presentable and and have equivalent Dehn functions.
Corridors appear in van Kampen diagrams over a presentation when there is some such that all relators in which appears can be expressed as where , , and are words not containing . Such presentations naturally arise for HNN-extensions, with being the stable letter. Suppose is a van Kampen diagram for a word over such a presentation and that contains an . This edge is either in the thin part of that diagram—that is, this edge is not in the boundary of any 2-cell (as in Figure 1a)—or it is in the thick part and there is a 2-cell in with that edge in its boundary, as in Figure 1b. This 2-cell will have exactly one other -edge. In turn, this other -edge either is in or is common with another 2-cell. This continues likewise and eventually must end elsewhere in the boundary. The resulting collection of 2-cells is an -corridor. The number of 2-cells involved is the length of the corridor. An -corridor is reduced if it contains no two 2-cells sharing an -edge for which the word around the boundary of their union is freely reducible to the identity in the group.
Remark 3.2**.**
Many of the presentations we will work with will have the form where is some alphabet (not containing ), and and are sets of words on . An -corridor in a diagram over such a presentation is reduced exactly when the word along the bottom is reduced.
Suppose is a van Kampen diagram with -corridors. Then is at most half the length of the boundary (at most half the number of in ). Since -corridors cannot cross, removing all the -corridors leaves connected subdiagrams called -complementary regions. The words around the perimeters of each of these regions contain no . So analysis of the lengths of the -corridors and of the areas of the -complementary regions can lead to estimates on the area of .
The dual tree to the set of -corridors has vertices corresponding to -complementary regions, and has an edge between two vertices when an -corridor borders the two corresponding -complementary regions. (There is no vertex corresponding to the outside of the van Kampen diagram.)
Definition 3.3**.**
A letter forms partial corridors when all the defining relations which contain both and have the form of a corridor relation, for some and without . A partial corridor is a maximal set of 2-cells joined by corridor relations as above. We refer to such 2-cells which contain one or more or (but not both) in their boundary words as capping faces, since they cap off partial corridors.
An in the boundary of a van Kampen diagram will either be connected by a full -corridor to another edge labeled by in the boundary, or begins a partial -corridor ending at one of the capping faces. An -edge on a capping face is either connected to the boundary via a partial -corridor (possibly of length zero), or is connected to an -edge of another capping face via a partial -corridor.
Like standard corridors, partial corridors cannot cross. However, there is no immediate control on the number of partial corridors in terms of , since they may begin and end within the diagram.
3.2. General bounds on Dehn functions of mapping tori of RAAGs
RAAGs are (bi)automatic [16] and so have either linear or quadratic Dehn functions. A finitely presented group is hyperbolic if and only if it has linear Dehn function. Finite-rank free groups are hyperbolic. Non-free RAAGs have subgroups and so are not hyperbolic (e.g. [8] and references therein). So RAAGs have either linear or quadratic Dehn functions, the former case only occurring for free RAAGs. This will be useful for the following lemma.
Lemma 3.4**.**
If is a non-free RAAG and , then the Dehn function of satisfies .
Proof.
Suppose is a non-free RAAG. So has a finite presentation derived from a graph with at least one edge. Then and hence will contain a subgroup. This implies that is not hyperbolic and therefore (again, [8] and references therein).
A word on the generators of
[TABLE]
can be expressed as for some and some . Suppose represents the identity in . Then shuffling all the to the right, replacing each by the freely reduced word representing does not change the element of represented. Eventually we arrive at where is a word on that represents in and . Applying in this way to a word on increases its length by at most a constant factor, specifically by at most . So is an upper bound on both and on the number of relation applications needed to convert to .
The Dehn function of is at most quadratic, so can be reduced to the empty word using at most a constant times defining relations. Thus is at most a constant times , and therefore . ∎
Our next lemma is the special case of Theorem 4.1 of [6] in which (in the notation of [6]) and is quasi-isometrically embedded. We will call on this repeatedly to establish lower bounds on the Dehn functions.
Lemma 3.5** (adapted from Bridson–Gersten [6]).**
Suppose is a quasi-isometrically embedded infinite abelian subgroup of a finitely presented group . If and , then the Dehn function of satisfies
[TABLE]
Equivalently, if is associated to the matrix , and if
- (1)
* has an eigenvalue such that , then has exponential Dehn function.* 2. (2)
* only has eigenvalues such that , then if the largest Jordan block for is , then .*
The following lemma allows us to specialize to convenient when analyzing the Dehn functions of mapping tori. We include the proof because it is brief and the result is vital to this paper.
Lemma 3.6** (Bogopolski [4]).**
The following mapping tori have equivalent Dehn functions:
- (1)
* and , for any .* 2. (2)
* and .* 3. (3)
* and when and are conjugate in .*
Proof, following [4].
Map onto by killing and then onto by the natural quotient map. The kernel of this composition is the index- subgroup . By Proposition 3.1, and have equivalent Dehn functions.
As for all , it follows that , so mapping and fixing gives an isomorphism . Thus and have equivalent Dehn functions.
If and are conjugate in , there exists and such that for all . We will show that and are isomorphic. Consider given by for and , where . It is a homomorphism because the relators for are mapped to the identity in . Indeed,
[TABLE]
It is certainly onto. This homomorphism has inverse given by for and , so it is an isomorphism. ∎
3.3. Growth and automorphims of
For a matrix , let denote the maximum of the absolute values of the entries in . We say has linear growth when the function mapping is -equivalent to .
The following lemmas will allow us to specialize to convenient cases of when analyzing Dehn functions of mapping tori of and .
Lemma 3.7**.**
If has linear growth, then there are integers and such that and is conjugate to in .
Proof.
As has linear growth, Theorem 2.1 of [6] tells us that there exists an integer such that is for some non-zero matrix such that . As , the trace of is zero, and for some integers not all zero such that . If , then the result holds with . So assume they are not both zero. Notice that . So there are coprime integers and (in particular not both zero) with . By Bezout, there are such that , and so is in . And then where , and the result follows. ∎
Lemma 3.8**.**
Suppose has eigenvalues with , then either or has finite order dividing six.
Proof.
As , . So if is not real, then the discriminant , and as has only integer entries, . Suppose then that and . Then, as , we find . It follows that is conjugate in to where is , , or , and so has order dividing . ∎
4. The electrostatic model for central extensions
Gersten and Riley’s electrostatic model of [15] is a method of constructing van Kampen diagrams for central extensions. We will use it and variants to obtain upper bounds on the Dehn functions of some mapping tori.
Suppose a group is a central extension with kernel . If has presentation
[TABLE]
then for some , has presentation
[TABLE]
Suppose . Since is central, in , for some and is with all removed. If represents the identity in , the word represents the identity in . We will describe how to construct a van Kampen diagram for over from a diagram for over .
We read a defining relator clockwise or counterclockwise from an appropriate vertex around the boundary of each 2-cell in . Now ‘charge’ every 2-cell: insert loops at each labeled with ’s and oriented in such a way that around the interior of the 2-cell we now read (to reflect the relation ), as in Figure 2. If , then at most such loops labeled by are introduced by charging.
To discharge, pick a geodesic spanning tree in —that is, a maximal tree such that the distance in the tree from any vertex to the base vertex of is the same as its distance in . In [15], for each introduced -edge, a -corridor is added which follows to the root of the tree. (Figures 4–7 in [15] show how these corridors appear.) Each -corridor has length bounded above by . This produces a diagram for in with area at most .
As in , there is a van Kampen diagram for over . Since the arrangement of generators other than is the same in and in , can be filled with -corridors and . To get a diagram for we wrap the diagram around as in Figure 3.
This leads to the following theorem.
Theorem 4.1** (Gersten–Riley [15]).**
Suppose we have a central extension of a finitely presented group , and are functions such that for every word representing the identity in , there exists a van Kampen diagram such that and the diameter of the 1-skeleton of is at most . Then the Dehn function of is bounded above by a constant times .
To use Theorem 4.1, we need simultaneous control on both area and diameter of diagrams. This is available in the setting we will be concerned with thanks to the following theorem of Papasoglu. The radius of a van Kampen diagram is the minimal such that for every vertex in there is a path of length at most in the 1-skeleton of from that vertex to . Since one can travel between any two vertices by concatenating shortest paths to the boundary with a path part way around the boundary,
[TABLE]
Theorem 4.2** (Papasoglu [21]).**
For a group given by a finite presentation in which every relator has length at most three, if is a minimal area van Kampen diagram such that and , then .
Every finitely presentable group has such a presentation, and changing between two finite presentations of a group alters diameter and area by at most a multiplicative constant, so, in the light of (1), Theorem 4.2 gives us:
Corollary 4.3**.**
If a finitely presented group has Dehn function bounded above by a quadratic function, then there exists such that for every word of length representing the identity, there is a van Kampen diagram whose area is at most and whose diameter is at most .
We are now ready to deduce:
Corollary 4.4**.**
All mapping tori of have at most a cubic Dehn function.
Proof.
Bridson and Groves [7] prove that for all , has a quadratic Dehn function, so Corollary 4.3 applies and allows us to use Theorem 4.1 to deduce that every central extension of has at most cubic Dehn function. Lemmas 5.2 and 3.6 together imply that has at most a cubic Dehn function. ∎
In Sections 5.2 and 5.3 we will refine this method to improve the upper bound from cubic to quadratic in special cases. In Section 6 we will adapt the arguments to certain related situations which fail to be central extensions.
5. Mapping tori of
5.1. Automorphisms of
Recall the notation of Theorem 1.1: induces via the map killing the factor, and induces via the abelianization map , ; and is projection onto the second factor. Let be the (complex) eigenvalues of . We will prove Theorem 1.1 by separately addressing three comprehensive and mutually exclusive cases.
- (i)
, 2. (ii)
and there exists and such that and , 3. (iii)
all other cases—that is, and for every and every , if then .
In Section 5.2 we will prove that the Dehn function of the mapping torus of is quadratic in case (i). In Section 5.3 we will prove that it is cubic in case (ii) and is quadratic in case (iii). First we narrow the family of automorphisms that must be explored.
Lemma 5.1**.**
[19, Proposition 5.1 (Nielsen)]** For all , there is such that .
Proof.
is generated by the following five elementary Nielsen transformations: maps to , , , , or . Each of these automorphisms sends to a conjugate of . ∎
To prove Theorem 1.1 it will suffice to focus only on the mapping tori of the form described in the next lemma.
Lemma 5.2**.**
Let . Given , there exists satisfying the following properties:
- •
there is such that in ,
- •
the Dehn functions of and are equivalent,
- •
,
- •
* has determinant and so is in ,*
- •
the eigenvalues of are real and positive, and
- •
* is a central extension of by ,*
where is the map induced from by killing , and is the map induced by the abelianization of to . Thus there exist such that
[TABLE]
Moreover, conditions (i), (ii), and (iii) above hold for exactly when they hold for .
Proof.
The center of , being characteristic, is preserved by , so maps to or , and maps to . On killing , induces some . Therefore, the mapping torus is
[TABLE]
for some . By Lemma 5.1, for some . In case (i), define to be composed with conjugation by . This new automorphism satisfies the properties above by definition and by Lemma 3.6. Lemma 3.8 tells us that in cases (ii) and (iii), either has a real unit eigenvalue or it has finite order dividing six. Define to be composed with an appropriate inner automorphism so that . Then and satisfy all the required properties.
Conditions (i), (ii), and (iii) hold for exactly when they hold for : Suppose that satisfies condition (i): Then for some . The map has a non-unit eigenvalue if and only if has a non-unit eigenvalue. Suppose that satisfies condition (ii): Then for some . If for some , we have that is a fixed point of , then it is also a fixed point of . If there is so that has a fixed point, then will also have a fixed point. Moreover, , so if and only if . ∎
5.2. Theorem 1.1 when has non-unit eigenvalues
The primary tool for this section is relative hyperbolicity, a concept introduced by Gromov, and then developed by Bowditch, Farb, Osin, and others [5, 13, 20].
Suppose is a group presented by
[TABLE]
where such that .
Lemma 5.3**.**
If has non-unit eigenvalues, is strongly hyperbolic relative to the subgroup .
Proof.
is the fundamental group of a finite-volume hyperbolic once-punctured torus bundle. In Theorem 4.11 of [13], Farb showed that such groups are strongly hyperbolic relative to their cusp subgroups. In our case, that is the subgroup . (See also Section 4 of [11] for a survey of when mapping tori of free groups are relatively hyperbolic and acylindrically hyperbolic.) ∎
Consider the presentation
[TABLE]
for obtained from by adding an extra generator , an extra relation which declares that equals in the group, and a further extra relation which declares that commutes with (which is, a consequence of the other defining relations since ). Then is the subgroup of Lemma 5.3. Refer to faces of a van Kampen diagram over as -faces when they correspond to the relation , and refer to the remaining faces as -faces.
Lemma 5.4**.**
There exists such that every word on of length that represents the identity has a van Kampen diagram over with the following properties.
- (1)
The number of -faces is at most . 2. (2)
The number of -faces in is at most . 3. (3)
From every vertex of on the perimeter of an -face, there is a path to of length at most in the 1-skeleton of the union of the -faces.
Proof.
Let be an alphabet, with a letter for each non-identity element of the subgroup of . Here corresponds to the element represented by . Let denote the set of words in that represent the identity in . For example, includes the word and for all .
The presentation
[TABLE]
again gives . Note that the elements and appear in , and the defining relation appears in . Again, we will refer to van Kampen diagram faces that correspond to elements of as -faces.
Then is a finite relative presentation for with respect to , as per Definition 2.2 of Osin in [20]. Theorem 1.5 in [20] says (in particular) that a finitely generated group which is hyperbolic relative to a subgroup in the sense of Farb, as is the case for relative to by Lemma 5.3, has a linear relative Dehn function. This implies that there exists such that for every word on representing the identity, there is a van Kampen diagram over whose number of -faces is at most .
Osin proves further facts that we will need concerning the geometry of . A diagram for the word is of minimal type over all diagrams for if under lexicographic ordering it minimizes
( # of -faces, # of -faces, total # of edges).
Choose be of minimal type.
Let be the maximum length of the relators , , , and . Call an edge of internal to the -faces when it has -faces (or a -face) on both sides. Osin (Lemma 2.15 of [20]) tells us that if is of minimal type then it has no edges which are internal to the -faces and deduces (Corollary 2.16) that the sum of the lengths of the perimeters of -faces in is at most .
Suppose that is a word on and take to be a diagram of minimal type for over .
The words around -faces only include the letters and , so they can overlap -faces only in edges labeled by and . Therefore the word around each -face is a word on since every edge in the boundary of a -face is either in or is also in the boundary of an -face. Let be a diagram obtained from by excising all -faces and replacing each -face with the appropriate minimal area diagram over . So is a van Kampen diagram over . By Osin’s Theorem 1.5, as discussed above, satisfies (1). As the Dehn function of enjoys a quadratic upper bound, and, given the bound on the lengths of the boundaries of -faces explained in the previous paragraph, also satisfies (2).
Because of the minimality assumption on the number of -faces, no two -faces will have a vertex in common in : two -faces with a vertex in common could be replaced by a single -face. Also the boundary circuit of any -face in will be a simple loop. This is because is minimal: a -face with a non-simple loop as its boundary circuit could be excised and a -face with a shorter and simple boundary loop inserted in its place. Thus the -faces form disjoint islands in and there are no -faces enclosed within these islands. In the light of this, (3) follows from (2). ∎
Proof of Theorem 1.1 in Case (i).
We suppose . By Lemma 5.2 there exists so that and have equivalent Dehn function, and has presentation
[TABLE]
which is a central extension of
[TABLE]
where has the property that . If , then in
[TABLE]
We change presentations, and work with the central extension
[TABLE]
of
[TABLE]
Suppose is a word of length representing the identity in . Let be with all deleted.
Let be a van Kampen diagram for as per Lemma 5.4. Given (3) of that lemma, there is a forest in the 1-skeleton of the union of the -faces in joining every vertex of an -face to by a path of length at most through the 1-skeleton of the -faces.
Charge . Given that the defining relation is unchanged on lifting to the central extension, the -faces of Lemma 5.4(2), are unchanged. There are such faces. Let . The remaining -faces of Lemma 5.4(1), each acquire at most charges. These are discharged by adding partial -corridors that follow the forest to the boundary and then around the boundary to a base vertex. Each partial -corridor has length at most : the length of the path to the boundary is at most by Lemma 5.4 (3) and the length of the path to the base vertex is at most . In total then, -partial corridors contribute at most 2-cells to the new diagram. The result is a diagram over of area at most for a word , which has length less than . By adding in an annular region to rearrange to , as per the electrostatic model of Section 4, it follows that has a diagram over of area at most . ∎
5.3. Theorem 1.1 in the case where all eigenvalues of are unit
We begin by arguing that for the purpose of determining Dehn functions we can further specialize the family of presentations to examine:
Lemma 5.5**.**
Suppose that is as per Lemma 5.2 and that the eigenvalues of are . Then there exists such that the eigenvalues of are also , the Dehn functions of and are equivalent, and
[TABLE]
for some . Moreover, conditions (ii) and (iii) of Section 5.1 hold for exactly when they hold for , and they are characterized by and , respectively.
Proof.
Let be as per Lemma 5.2: , for some and some such that has determinant . We assume its only eigenvalue is 1, and thus there is some such that .
We will now show that there is such that and are conjugate in and maps .
As has only eigenvalue 1, it is either the identity or it has linear growth. So (by Lemma 3.7 in the latter case) is conjugate in to for some . On account of the standard isomorphism between and , is conjugate in to where and . So for some and some . We lift to by defining for and , by taking to be conjugation by , and by defining . Because is central, . In particular,
[TABLE]
for some . (Note that and may not be equal, as and will not generally have the same index sum of .)
Therefore has the presentation claimed and has only as an eigenvalue, as required. And, by Lemma 3.6, the mapping tori and have equivalent Dehn functions.
Next we will show that
- (1)
If , then if and only if . 2. (2)
If , then exactly one of the following hold:
- (a)
for all , in which case and , 2. (b)
for some , in which case or is non-zero.
We wish to compare and . Let . The following calculation shows that is another fixed point of and that :
[TABLE]
Now we prove 1. If , then since and are both fixed by , for some , and therefore . So if and only if .
Next we prove 2. If , then maps , , and for some , and so also.
Lemma 5.2 shows that and either both satisfy condition (ii) or both satisfy condition (iii).
Under case 1, it is immediately evident that, as required, and either both satisfy condition (ii) or both satisfy condition (iii), and so this holds for and also.
Finally consider case 2. When , condition (ii) ‘there exists and such that and ’ amounts to ‘there exists such that .’ Observations 2a and 2b show that this holds for if and only if it holds for . Again and either both satisfy condition (ii) or both satisfy condition (iii), and so this holds for and also. ∎
Proof of Theorem 1.1 in Case (ii)..
By Lemmas 5.2 and 5.5, for the purpose of calculating the Dehn function we may work with
[TABLE]
where . The subgroup quasi-isometrically embeds in and . So, by Lemma 3.5, is a lower bound for the Dehn function of . This lower bound is cubic (as ), matching our upper bound from Corollary 4.4, so the claim is established. ∎
We now turn to Case (iii). This time, Lemmas 5.2 and 5.5 allow us to work with which has the form
[TABLE]
where, is non-zero. (The case and is covered by Theorem 1.1 in Case (ii)—the Dehn function of this mapping torus is cubic.)
The methods of Case (i) cannot be used here. Indeed, Button and R. Kropholler [11] have shown that for with this form, is not strongly hyperbolic relative to any finitely generated proper subgroup, so van Kampen diagrams over do not decompose into uncharged islands with linear-area complement. Instead will use a variant of the electrostatic model whereby the diagram will be discharged along partial corridors (see Section 3.1) in a manner controlled by an application of Hall’s Marriage Theorem, which we now review.
A subgraph of a graph is a 1-factor for if it contains all vertices of and each vertex meets precisely one edge of . In other words, a 1-factor pairs every vertex with a neighbor. We will be interested in the following special case:
Lemma 5.6**.**
A -regular bipartite graph with has a 1-factor.
This is a consequence of Hall’s Marriage Theorem. See [12] for a proof.
Proof of Theorem 1.1 in Case (iii)..
By Lemma 5.5, it suffices to prove that , presented by
[TABLE]
has quadratic Dehn function. If , then and so the Dehn functions of and agree and will be quadratic. Therefore we may restrict our attention to the case where and are both non-zero.
Van Kampen diagrams over have both partial -corridors and partial -corridors. is a central extension of by , where is presented by
[TABLE]
Van Kampen diagrams over may have partial -corridors.
Suppose is a word of length representing the identity in . Let be with all removed. Then in for some and . Since has a quadratic Dehn function, there exists a minimal area diagram for over such that . We charge by replacing 2-cells in with 2-cells labeled by the defining relators from , as in the first steps of the Electrostatic Model (see Section 4). What follows is a scheme for adding in 2-cells to ‘discharge’ so as to create a diagram for over .
The idea is that if we can pair off oppositely-oriented capping faces that are joined by partial -corridors, then we can add in partial -corridors following the -corridors, as in Figure 4, in order to discharge the -edges in our diagram. As is central in , partial -corridors can be run alongside this partial -corridor, and the word one reads along both the top and bottom of the -corridor will be the same as that word along the top and bottom of the -corridor, namely some power of . We wish to find a consistent way of partnering vertices so that we can replicate the picture in Figure 4, adding in partial -corridors to discharge between partners throughout the van Kampen diagram, with no leftover charges to consider.
I. Modeling with a graph. Construct a planar graph with multi-edges, , from as illustrated in Figure 5: has a black vertex for each capping face in ; whenever two capping faces are connected by a partial -corridor, possibly of length zero, an edge connects the corresponding vertices (two vertices may share multiple edges); we also add an edge and a white vertex to for each partial -corridor that goes to the boundary. Every black vertex in the graph is degree and every white vertex has degree 1.
The graph is naturally bipartite (but not generally black-white bipartite, as you can see in Figure 5): partition the black vertices according to whether they correspond to capping faces with clockwise or anticlockwise oriented -edges, and extend this partition to the white vertices.
II. Building a regular bipartite graph. We would like to apply Corollary 5.6, but may not be regular: black vertices have degree , but white vertices have degree . So, as illustrated in Figure 6a, we construct a regular graph which has as a subgraph. Take many copies of , and identify the white vertices in each of the copies. That is,
[TABLE]
where for all when is a white vertex. White vertices are degree one, so the identification of copies of forces to be a -regular graph. If is bipartite with respect to a partition of its vertices, then is bipartite with respect to
[TABLE]
III. Finding pairing partners for - and -corridors. Corollary 5.6 tells us that has a 1-factor. This partners each vertex with an adjacent vertex . View the image of in as , sitting as a subgraph in . In the example of Figure 6c, is the grey subgraph at the back. If is a black vertex, its partner is also a vertex of , but this may fail for white vertices.
IV. Completing to a van Kampen diagram. If and are partnered black vertices in then the corresponding capping faces are connected by at least one partial -corridor (possibly of length zero). In , the capping faces and corresponding to and have many oppositely oriented charges. We will connect these charges with partial -corridors, as in Figure 4. Choose one of the partial -corridors joining to (there is at least one). Run all of the partial -corridors for one capping face alongside the partial -corridor. If a black vertex is paired with a white vertex in , run all of the partial -corridors alongside the partial -corridor to the boundary. Two white vertices will never be paired. At the ends of partial -corridors on capping faces, it may be necessary to insert rectangles in which the -and -corridors cross, as in Figure 7, but this requires no more than additional 2-cells. The total number of 2-cells added to in this process is no more than .
V. Correcting the boundary. Partial -corridors follow partial -corridors to the boundary in groups of . The new diagram has boundary length between and and is a van Kampen diagram over for some word in the pre-image of . Deleting all from produces , but the arrangement of the letters in may differ from that in . As was described in Section 4 we glue around the outside of this diagram an annular diagram with the word along the inner boundary component and the word along the outer boundary component. Together, they form , a van Kampen diagram for over . This annular diagram has area at most , and summing our area estimates, has area no more than . Since , it follows that there is constant such that for any given word in the generators of that represents the identity, this construction produces a van Kampen diagram of area at most . ∎
6. Mapping tori of
6.1. Automorphisms of
Servatius [23] and Laurence [17] found a generating set for the automorphism group of a RAAG based on the underlying graph . In the instance of
[TABLE]
their generating set for the automorphism group consists of the inner automorphisms, inversions, the one non-trivial graph isomorphism (, , and ), and the four transvections
[TABLE]
The following lemma and then proposition are steps towards Theorem 1.2 in that they let us focus on particular presentations for the purposes of classifying Dehn functions of mapping tori of . Recall that denotes the inner automorphism .
Lemma 6.1**.**
For all , there exists such that
[TABLE]
where , and are words on and , and in . Explicitly, suppose that , where and each for all , and . Then is even and for , we find is an example of a map satisfying the properties given for .
Moreover, for any of the given form, and have equivalent Dehn functions.
Proof.
Since , all automorphisms can be written as where denotes conjugation by some and is some product of the inversions, transvections, and graph isomorphisms in the generating set above. All inversions, transvections, and graph isomorphisms restrict to automorphisms of the subgroup , and they all map the subset to itself. So
[TABLE]
for some and some words and on and . This proves the existence of a with the required properties. We turn next to how to find such an automorphism.
Now suppose is as per the statement. For as above we have that . So
[TABLE]
But, given the free product structure of , that implies that is even and
[TABLE]
where is some element of and is as defined in the statement.
It follows then that . So maps for some and some words and on and .
By Lemma 3.6, and have equivalent Dehn functions. ∎
Proposition 6.2**.**
Given as per Lemma 6.1, there exists of the form
[TABLE]
where , , and and have equivalent Dehn functions. Moreover, conditions (1), (2), and (3) of Theorem 1.2 apply to exactly when they apply to .
Additionally,
- •
when has finite order (Condition (1) of Theorem 1.2), we may further assume , so that
[TABLE]
- •
when is of infinite order and has only unit eigenvalues (Condition (3) of Theorem 1.2), we may further assume for some , so that for some ,
[TABLE]
Proof.
Recall as per Lemma 6.1. Define and . So if , then where . If , then where .
For , let , the restriction of to the factor.
Suppose has exponential growth. Define . Then has the general form claimed in the proposition, and since and , Lemma 3.6 implies that and have equivalent Dehn functions.
Suppose has finite order (i.e. has trivial growth). Define . This has the promised form: its restriction to is the identity and for some . Lemma 3.6 implies that and have equivalent Dehn functions.
Finally, suppose is of infinite order and has only unit eigenvalues. Lemma 3.7 implies that is conjugate in to the automorphism , , for some . Therefore, for some , . Define , where restricts to on and maps . By Lemma 3.6, and have equivalent Dehn functions. Let . The map has the desired form:
[TABLE]
In every case, conditions (1), (2), and (3) of Theorem 1.2 apply to exactly when they apply to . After all, in each case, the restriction of to the factor is a conjugate of a power of the restriction of . Let be the Jordan Canonical Form (JCF) of . For all , is finite order if and only if is finite order, and has a non-unit eigenvalue if and only if has one too. The JCF is invariant under conjugation. ∎
6.2. Corridors
In every instance of Proposition 6.2,
[TABLE]
for some and some . In this section we prove some preliminary results about van Kampen diagrams over this presentation. Such diagrams can have both - and -corridors.
Definition 6.3**.**
Suppose that is a -corridor and is a -corridor. Suppose and are subcorridors. We say and form a bigon when they have exactly two common 2-cells, specifically their first and last ones.
We leave the proof of our next lemma as an exercise—the essential points are (1) neither a -corridor nor a -corridor self-intersects, and (2) look at an innermost pair of crossings.
Lemma 6.4**.**
Suppose is a -corridor and is a -corridor. If and intersect more than once, then there are subcorridors and forming a bigon.
Recall that a -corridor is called reduced if it contains no two 2-cells sharing a -edge for which the word around the boundary of their union is freely reducible to the identity in the group.
Lemma 6.5**.**
In a van Kampen diagram where -corridors are reduced, if a -corridor intersects a -corridor , it will do so only once.
Proof.
Since -corridors are made up of a single kind of 2-cell (arising from the defining relation ), all 2-cells in a reduced -corridor have the same labels and are oriented the same way along the corridor. Let us assume for the contradiction that is reduced and that and intersect at least twice.
By Proposition 6.4, there exist subcorridors and that form a bigon, with precisely the first and final 2-cells, and , in common, as in Figure 8. The orientation of the edges labeled by in fixes an orientation for all the -labeled 1-cells along the bottom of (see Remark 3.2) since is reduced. It also fixes an orientation for -labeled 1-cells in . But these two specifications are inconsistent for the -labeled 1-cells in . ∎
We will use the same argument for alternating corridors and -corridors in Lemma 6.10(1) and for - and - partial corridors in Lemma 6.10(4).
Corollary 6.6**.**
In a van Kampen diagram with reduced -corridors, there are no -annuli, and -annuli do not intersect -corridors.
Proof.
The word around the outside of a -annulus contains ’s, so it would have to intersect once (and therefore intersect at least twice) with a -corridor, which is impossible by Lemma 6.5. Similarly, if a -corridor has common 2-cells with a -annulus, it must have at least two in common—again impossible by Lemma 6.5. ∎
The following corollary allows us to determine the lengths of -corridors in a diagram in terms of the word around its boundary and the way -edges are paired up by -corridors—the so-called -corridor pairing (see Definition 6.11).
Corollary 6.7**.**
Suppose is a van Kampen diagram with reduced -corridors. Suppose further that its boundary word is for some words and and that is a -corridor beginning and ending on the edges labelled by these distinguished . Then the length of is the absolute value of the index sum of the in (or, equivalently, in ).
Proof.
All -corridors intersecting have the same orientation with respect to . In particular, the word along one side of is for some , without any free reductions. Thus the -corridors starting at -edges in that are oppositely oriented to the ’s in cannot cross it, and so must have oppositely oriented partners on the same side of , as shown in Figure 9. This leaves exactly the absolute value of the index-sum of in many -corridors which have no partners on the same side of , and so must cross it. By Lemma 6.5, each of these -corridors can cross exactly once. ∎
Since -corridors cannot cross, removing all the -corridors leaves a set of connected subdiagrams called -complementary regions. The words around the perimeters of each of these regions contain no . See Figure 10.
Corollary 6.8**.**
Let be a -complementary region in a van Kampen diagram for the word . If the word around the perimeter of is called , then .
Proof.
Suppose that after cyclic conjugation has the form . Then the perimeter of can be labeled by the word where are part of and label the -corridors, with . By Corollary 6.7, , and so . ∎
6.3. Alternating corridors
When
[TABLE]
for some , killing maps onto
[TABLE]
The elements and do not commute in , so is not a central extension of . Nevertheless, we will use a variant of the electrostatic model to establish upper bounds on area in . The purpose of this section is to provide necessary information about van Kampen diagrams over . We begin with the case . Setting , we see that
[TABLE]
and are the same group.
Definition 6.9**.**
A -face is a 2-cell in a van Kampen diagram over corresponding to the defining relation . Partial - and -corridors in fit together in an alternating way: where a partial -corridor ends at a -face in the interior of a diagram, a partial -corridor begins, and where this ends, another partial -corridor begins. An alternating corridor in is a maximal union of -partial corridors, -partial corridors and the -faces between them, fitting together in this way—see Figure 11.
Like a standard corridor, an alternating corridor either closes up on itself or it connects two boundary edges. It is possible for alternating corridors to self-intersect, but, as we will see shortly, in a reduced diagram, alternating corridors do not self-intersect or form annuli. Every face in is part of some alternating corridor. Like standard and partial corridors, an alternating corridor has a top and a bottom: the internal - and -edges are directed from the bottom to the top (again, see the figure).
Lemma 6.10**.**
Suppose is a van Kampen diagram over in which all -corridors and all - and -partial corridors are reduced. (See Figures 12 and 13.) Then in :
- (1)
A -corridor and an alternating corridor can cross at most once. 2. (2)
Alternating corridors do not form annuli. 3. (3)
A single alternating corridor can never cross itself. 4. (4)
Two alternating corridors cannot cross more than once.
Proof.
For (1) it suffices (see Lemma 6.4) to prove that it is impossible to have a bigon of an alternating corridor and a -corridor in . Since -corridors in are reduced, the top of the -corridor is labeled by a power of without any free reduction. As in our proof of Lemma 6.5, and specify inconsistent orientations for the edge in the second common 2-cell, as in Figure 14a.
For (2), suppose for a contradiction, that there is such an annulus. It cannot contain any -faces, as this would force a -corridor to cross the alternating annulus twice. If our annulus contains no -faces, then it is either a - or -annulus. The word along the top of the annulus is a power of or , respectively. Such an annulus would imply that or have finite order, but both are infinite order elements of .
For (3), suppose for a contradiction that an alternating corridor has a self-intersection. An alternating corridor can only have a self-intersection at a 2-cell corresponding to the relation . Let be a subcorridor of that begins and ends at the self-intersection. Call this first and final 2-cell .
The 2-cell is part of both - and - partial corridors in ; therefore contains at least one -face (in particular, an odd number of -faces in order to get both an - and -segment at the intersection). Each -face in is part of a -corridor. By (1), -corridors can only cross once, but each -corridor must cross at least twice, since is an annulus.
For (4), assume for the contradiction that two alternating corridors cross at least twice. Again, we can find a bigon of alternating corridors. There are two cases. In one, no -corridors intersect the bigon. In this case, one of the alternating corridors is a partial -corridor, and the other is a partial -corridor. An argument like Lemma 6.5 shows that this kind of double intersection is impossible when - and - partial corridors are reduced (see Figure 14c). In the other case, at least one -corridor intersects the bigon. We look at the triangle formed by the two bigons and the first -corridor to cross them. Since it is the first such -corridor, we have an - and -partial corridor that both need to end on the same side of a -corridor. However, -corridors always have ’s along the bottom and ’s along the top — there cannot be both ’s and ’s on the same side of the -corridor. Figure 14d illustrates this contradiction. Therefore neither case happens.∎
6.4. Quadratic area diagrams over
Definition 6.11**.**
A -pairing for a word is any pairing off of the in with the in .
If represents the identity in , then a van Kampen diagram for induces a -pairing: a and a are paired when they are joined by a -corridor in . We say that a -pairing is valid if it is induced by a van Kampen diagram for . (Not all -pairings of a word need be valid. Valid -pairings need not be unique.)
The Dehn function of
[TABLE]
grows at most quadratically, as it is a free-by-cyclic group. The point of the following lemma is that this quadratic area bound can be realized on diagrams witnessing any prescribed valid -pairing.
Lemma 6.12**.**
There exists such that for any word representing the identity in (not necessarily freely reduced), and for any valid -pairing of , there is a van Kampen diagram for over that induces , has , and has reduced -corridors.
Proof.
Let be a van Kampen diagram for over that realizes the given -pairing.
Instead of we will work with
[TABLE]
which, recall, we can see presents the same group by setting .
Two finite presentations and of the same group have -equivalent Dehn functions [1, 14]. In outline, the proofs in [1, 14] go as follows. For each , pick a word representing the same group element. Suppose a word represents in . Let be the word obtained from by replacing all of its letters by . A van Kampen diagram over can be converted to a van Kampen diagram for over of comparable area by converting each edge labeled to a path labeled and then filling all the faces. Each relator in can be rewritten as a word representing the identity in , and each can then be filled with at most some constant number of relators in , so the area of the diagram over will be no more than a constant multiple of the area of the diagram over .
In the instance of and , the -pairings induced by the two diagrams agree, and so it suffices to prove the lemma for instead of .
Given , let be the word obtained from by cancelling away all and all (but not all ). Then . Construct a van Kampen diagram for over as follows. Begin with a planar polygon with edges directed and labeled so that one reads around the perimeter. Insert reduced -corridors of 2-cells (each with perimeter ) mimicking the pattern of -corridors in . Fill the complementary regions with minimal area sub-diagrams over . The words around their perimeters represent the identity in because the words around the corresponding loops in represent the identity in . Since the complementary regions are filled with minimal area subdiagrams, all - and - partial-corridors in are reduced.
Lemma 6.10 implies that the length of any alternating corridor in our diagram is bounded above by the total number of -corridors and alternating-corridors that intersect . Since there are in total no more than -corridors and alternating corridors, the length of is at most . Similarly, the length of each -corridor is at most by Lemma 6.7, and there are fewer than many -corridors. So altogether,
[TABLE]
∎
6.5. Quadratic area diagrams over
In the previous section we established that given a valid -pairing for a word representing the identity in , we can construct a quadratic area van Kampen diagram with that -pairing. In this section, we leverage Lemma 6.12 to the case where we have a valid -pairing for a word representing the identity in . Our main strategy is to rewrite words representing the identity in to words in , where we can apply Lemma 6.12 to build a van Kampen diagram. Then we convert it to a diagram over .
Recall that
[TABLE]
Define
[TABLE]
Identifying with gives an isomorphism of with the index subgroup of generated by and .
Proposition 6.13**.**
If is a (not necessarily freely reduced) word representing the identity in and is a valid -pairing of , there exists a van Kampen diagram for the corresponding word in with a corresponding -pairing.
Proof.
Suppose represents the identity in and is a van Kampen diagram over for inducing the -pairing . Define —that is, obtain by substituting a for every in . Then represents the identity in and induces a valid -pairing for (which we will also call ) since can be converted to a van Kampen diagram for over with the same pattern of -corridors as follows. First replace each -edge in by a concatenation of -edges. The resulting diagram has 2-cells of two types—those originating from the relation and those from the relation . The perimeter words of these 2-cells become and . These words are relators in : the first can be derived by applications of and the second by applications of and applications of . Accordingly, refine the diagram by replacing the 2-cells with an -corridor of 2-cells each labeled , and the 2-cells with a -corridor of 2-cells labeled together with of the 2-cells. The substitutions in the case are shown in Figure 15. This process maintains the -pairing during the change from to .
∎
After producing a quadratic area van Kampen diagram for in that has -pairing , we want to use it to build a quadratic area van Kampen diagram for in that also has -pairing . The following lemma tells us that we will be able to replace -corridors over with -corridors over , as they always occur in multiples of .
Lemma 6.14**.**
Suppose is van Kampen diagram for a word over , with reduced -corridors. Then every -corridor in has length a multiple of .
Proof.
Let be the tree dual to the -corridors in —that is, has a vertex dual to each -complementary region and an edge dual to each -corridor; the leaves of correspond to regions which have one single -corridor in their perimeter. (See Section 3.1.) Pick any leaf of to serve as the root. There is a bijection between vertices of and -corridors : take to be dual to the first edge of the geodesic in from to .
We will show by reverse induction on distance in from to (i.e. starting from the leaves and working towards ), that the length of is a multiple of . Indeed when is a leaf, the length of is the index-sum of the in the boundary between the paired -edges and only appears in multiples of in , so the result holds. For the induction step, suppose . The length of is the exponent sum of the lengths of (with appropriate signs) over every parent of (each a multiple of , by induction hypothesis) and of the in the boundary of that are also in the boundary of the subdiagram dual to . ∎
Next we examine how to build a filling for a -complementary region over from a filling for a -complementary region over when their boundaries are compatible.
Lemma 6.15**.**
Suppose has a van Kampen diagram over of area . Then has a van Kampen diagram over of area at most .
Proof.
Define a -segment to be consecutive -labeled edges in the boundary circuit of . Such segments have a natural orientation that agrees with the orientation of the constituent . We will find a van Kampen diagram for over for which the -segments are connected by blocks of parallel -corridors. (Call this a -pairing.)
The first edge in any -segment can only be paired by a -corridor in with the first edge of an oppositely oriented -segment. Indeed, suppose that an initial in a -segment is connected by a corridor to a in position on another segment, with . Let be the subword of between them, as in Figure 16a. Because corridors do not cross, the -index sum of must be zero. If , the -index sum of will not be a multiple of , as either includes an entire -segment or entirely misses it, except for the partial segment which contains the in position . In particular, the index-sum of in can only be 0 when .
Construct a new van Kampen diagram for over as follows. Begin with a planar loop with edges labeled so that we read around the perimeter. Add in all initial corridors from . If an initial -corridor connects -segments and , we will pair each in to the corresponding in using copies of , as in Figures 16b and 17c. The remaining regions that have to be filled have perimeters labeled by words on alone, as all edges have been paired. Moreover, the index-sum of is zero, so these can be folded together to complete the construction of without the addition of any further 2-cells.
The area of will be times the sum of the initial -corridor contributions, and so in particular, the area of the new diagram is at most . Let be the van Kampen diagram for over of area at most obtained by replacing each stack of -corridors in by a single -corridor and each -segment in the boundary by a single -edge, as in Figure 17d. ∎
We will promote Lemma 6.12 to the following result concerning
Proposition 6.16**.**
There exists such that if is a (not necessarily freely reduced) word representing the identity in and is a valid -pairing of , then there exists a van Kampen diagram for over which has reduced -corridors, induces , and has .
Proof.
Suppose represents the identity in and has a valid -pairing . Lemma 6.13 implies that is also a valid -pairing for the corresponding word in , which we get by substituting a for every in . Now we can use what we know about building diagrams over : by Lemma 6.12, there is a constant such that admits a new van Kampen diagram over that induces and has area at most . Guided by , we will construct a van Kampen diagram for over which has comparable area.
By Lemma 6.14, -corridors in all have length that is a multiple of . To build , we begin by inserting reduced -corridors into a polygonal path labeled by , mimicking the -corridors in . Corresponding -corridors in the two diagrams differ in length by exactly the factor : where a -corridor in has along one side and along the other, the corresponding -corridor in has along one side and along the other.
Next we fill the -complementary regions. We wish to use Lemma 6.15 to convert the filling in -complementary regions of to fillings in , but for any -complementary region, the word along the perimeter of the region will not generally have an appropriate form. Its perimeter has the form , where , , and is a subword of and therefore is a word in and . We add a collar of -cells to change the boundary of the -complemetary region to . In particular, if is a minimal area diagram for the word , copies of can be glued in to rewrite to . The result is a region with boundary that is a word in and .
Apply Lemma 6.15 to convert each of these diagrams, without increasing area, to diagrams over with boundary (as in Figure 19d), and use them to fill the -complementary regions of . This produces a van Kampen diagram for over .
Finally we come to area estimates for . First observe that the total number of 2-cells in the -corridors in is at most the area of , which we determined earlier to be at most . Correspondingly, there are at most 2-cells in the -corridors in . The number of copies of glued on to the -complementary regions is at most , since it is the sum of the lengths of the -corridors, divided by . Since has area bounded above by , the total area taken by copies of is at most . The total area of the -complementary regions in is also at most . They, along with the attached copies of , are converted to the -complementary regions in without an increase in their area, as per Lemma 6.15. Therefore the area of is at most , where . ∎
6.6. Completing our proof of Theorem 1.2
Proof of Theorem 1.2(1).
This is the case where has finite order. By Lemma 6.1 and Proposition 6.2, for the purposes of determining the Dehn function of , and thus , we can work with , which has the form
[TABLE]
for some . Let
[TABLE]
These groups are not hyperbolic, so their Dehn functions grow at least quadratically. We will show that these mapping tori have quadratic Dehn functions for all . All proofs of the quadratic upperbound for these groups can be reduced to the proof for , so we begin with this special case.
Suppose is a word representing the identity in . Let be a minimal area van Kampen diagram for over . Let be with all removed. Then in . The -pairing induced by in turn induces a valid -pairing for because collapsing each -corridor to the path along its bottom side gives a van Kampen diagram for over .
By Proposition 6.16, there is a constant and a van Kampen diagram for over which has reduced -corridors, induces , and has area at most .
The defining relations for are also defining relations for (as ), so is a fortiori a van Kampen diagram over . We aim to convert it from a van Kampen diagram for , which contains no letters , to a van Kampen diagram for the original , which may contain letters . We will do this without altering its -corridors. Rather, we will replace each -complementary region in with an inflated version so that the word around the boundary becomes .
In there are no partial -corridors and no -corridor can cross a -corridor. Therefore each word read around the boundary of a -complementary region in contains the same number of letters as letters. Since the layout of -corridors in agrees with that in (and so in ), for each -complementary region in , there is a corresponding -complementary region in . As in , each word read around the boundary of the -complementary region in contains the same number of letters as letters. Therefore can be inflated to put the necessary and in place by adding -corridors to the boundary of .
The total number of such -corridors that we must insert is at most . The length of each -corridor is at most the length of the boundary circuit of the relevant -complementary region in —at most a constant times —by an argument equivalent to Corollary 6.8. Thus the area of the resulting diagram is at most the area of (which is at most ) plus the number of 2-cells in -corridors, which is no more than a constant times . In total, the area of is at most a constant times , as required.
Now we consider the case of for . If and are relatively prime, by Bezout’s Lemma, there is a pair of integers such that . So there is a generating set of with and (generating since and ), for which our group has the presentation
[TABLE]
the same as . Therefore the Dehn function is quadratic. Finally, if and are not relatively prime, let . Then is a subgroup of index in . But then has a quadratic Dehn function and hence so does . ∎
Proof of Theorem 1.2(2).
This is the case where has a non-unit eigenvalue. As quasi-isometrically embeds in and is an automorphism of , Lemma 3.5 implies that the Dehn function of is bounded below by an exponential function. From Lemma 3.4, the Dehn functions of mapping tori of RAAGs are always bounded above by exponential functions. Thus and so has exponential Dehn function. ∎
Proof of Theorem 1.2(3).
This is the case where has infinite order and only unit eigenvalues. We will show that and thus has a cubic Dehn function. By Lemma 6.1 and Proposition 6.2, for the purposes of determining the Dehn function, we can work with which has the form
[TABLE]
for some with . Let
[TABLE]
Suppose is a freely reduced word representing the identity in . Let be a minimal area van Kampen diagram for over . Let be with all removed. Then in . As in Case (1) above, the -pairing induced by induces a valid -pairing for .
By Proposition 6.16 there is a constant dependent only on such that admits a van Kampen diagram over which also induces and has area at most . Again, as in Case (1) above, by Corollary 6.8, there exists a constant such that the boundary circuit of any -complementary region in has length at most . Each such region is a diagram over .
Each such has a maximal geodesic tree in its 1-skeleton—that is, a tree reaching all vertices and with the property that there is a root vertex on the boundary such that for every vertex in , the distance from in the tree is the same as in the 1-skeleton of .
The diameter of each -complementary region is linear in and so in . After all, every vertex in is contained in an -corridor that extends to the boundary of . The length of each -corridor is the number of -corridors that cross it, and there are at most many -corridors in . So the maximum distance to the boundary is and thus the diameter of the -complementary region is at most .
We now apply the electrostatic model from Section 4 to inflate to a van Kampen diagram for over .
Since induces a valid -pairing, this can be done by inserting -corridors within the -complementary regions.
First we charge the diagram with at most many -charges (in effect, replacing all of the 2-cells for defining relations from with the corresponding 2-cells for defining relations from ). Next connect each charge in by a -partial corridor of length no more than to the root . The total area of these -partial corridors is at most a constant times . Finally, insert -corridors (each of at most a constant times ) along the boundaries of the -complementary regions to rearrange the (at most a constant times many) and until the perimeter word is .
The resulting diagram for over has at most the area of (at most quadratic in ), plus the total area of the -partial corridors (at most cubic in ), plus the total area of the -corridors (at most cubic in )—in total, at most cubic in .
So the Dehn function of grows at most cubically.
As has infinite order and only unit eigenvalues, it has a Jordan block and so, by Lemma 3.5, the Dehn function of the mapping torus has a cubic lower bound. ∎
7. Mapping tori of RAAGs of the product of two free groups
Here we will prove Theorem 1.3 concerning Dehn functions of mapping tori of products of free groups.
7.1. Automorphisms of
Suppose and are disjoint finite sets with , , and . Let be the bipartite graph with vertex set and an edge between a pair of vertices if and only if one is in and the other is in . So is the RAAG .
Our first task is to explain the opening part of Theorem 1.3, which amounts to:
Lemma 7.1**.**
Given , we can find and such that has the property that in .
This lemma allows us to work with instead of when trying to find the Dehn function of , since by Lemma 3.6.
For a vertex in a graph, is the subgraph consisting of all edges incident with and is the set of vertices adjacent to . We will prove Lemma 7.1 with the help of:
Lemma 7.2** (Laurence [17], Servatius [23]).**
If is a RAAG, then the following is a generating set for :
- (1)
All inner automorphisms: for a vertex of , for all . 2. (2)
All inversions: maps that send for some vertex of and leave all other vertices fixed. 3. (3)
All partial conjugations: for a vertex in and a connected component of , map for all vertices in and fix all other vertices. 4. (4)
All transvections: for a pair of vertices of such that , maps and fixes all other vertices. 5. (5)
All graph symmetries: automorphisms induced by the restriction of a graph symmetry to the vertex set.
We can see how this generating set reflects the product structure in the instance of .
Corollary 7.3**.**
When , the inversions, partial conjugations, and transvections of the Laurence–Servatius generators of restrict to automorphisms of and . The same is true of the graph symmetries, except when , in which case there are automorphisms exchanging and .
Proof.
This is immediate for the inversions. It is true of the partial conjugations because if , then . As for the transvections, suppose , and so . If then , and so . So (and fixes all other elements of ), and restricts to automorphisms of and as claimed. If, on the other hand, , then since , if and only if , and so, as , there are no transvections . Likewise the result holds for transvections with . The result for graph symmetries is straight-forward. ∎
Proof of Lemma 7.1.
Every automorphism of is a product of the Laurence–Servatius generators. As , the inversions, partial conjugations, transvections, and graph symmetries in this product can be shuffled to the end as a suffix , so as to express as for some inner automorphism .
If is a graph symmetry and is an inversion, partial conjugation, or transvection, then is again an inversion, partial conjugation, or transvection (respectively). So where is the product of the graph symmetries in the product and, by Corollary 7.3, restricts to automorphisms of and .
Now the lemma concerns some . Take . In this case the product will have an even number of terms and so (whether or not ), Corollary 7.3 tells us that restricts to automorphisms of and . So taking we have that for some and and , as required. ∎
Here is a further lemma we will use to adapt a RAAG automorphism to one better suited to calculation of the Dehn function of the mapping torus.
Lemma 7.4**.**
Suppose and are such that in and in . Then .
Proof.
Suppose for and for . Then viewing and as elements of via the natural embeddings and , we have that , as commutes with all elements of and commutes with all elements of . So in and it follows from Lemma 3.6 that . ∎
7.2. Growth of free group automorphisms
Suppose is a finite-rank free group. The growth of an automorphism with respect to a free basis is defined by
[TABLE]
where denotes the length of a shortest word on representing . We write when are Lipschitz equivalent; that is, when there exist such that for all . Up to , free group growth does not depend on the choice of finite basis .
We say that is periodic when there is such that is an inner automorphism. We say that is polynomially growing when there is such that , and is called exponentially growing otherwise.
Levitt [18, Theorem 3] shows that in the polynomially growing case, for every , there exists such that , and in the exponentially growing case, there exists and such that for all . For , let denote the cyclically reduced length, that is, the length of the shortest word representing a conjugate of . The corresponding result holds for in place of (though possibly with different powers and exponential functions) [18, Theorem 6.2].
Definition 7.5**.**
If is polynomially growing, let be the largest degree so that for some , . In this case, define . Otherwise, define .
In contrast with growth, in general. That is, knowing what happens to generators is not enough to understand . Indeed, [18, Lemma 5.2] gives a family of automorphisms and bases () such that for all , but there exists such that .
To establish lower bounds for the Dehn function of , we will use cyclically reduced growth to find lower bounds for the growth of a family of words under repeated application of our automorphism. To establish upper bounds for the Dehn function of , we will use growth to provide upper bounds for the growth of words under our automorphism. Results of Levitt provide a way to bridge the gap between the two types of growth: in all cases where the cyclically reduced growth and traditional growth disagree, it is possible to exchange with a related automorphism for which for . The mapping tori and have equivalent Dehn functions. We expand on this below.
Here is a summary of results of Levitt [18] and Piggot [22] on properties of growth and cyclically reduced growth in free groups:
Lemma 7.6**.**
Suppose .
- (1)
* if .* 2. (2)
If is polynomially growing, for all . 3. (3)
(Theorem 0.4 of **[22]**) . 4. (4)
(Section 2 of **[18]**) . 5. (5)
(Theorem 3 of **[18]**, cf. Bestvina–Feighn–Handel **[2]**). Either , or for some . 6. (6)
(By Corollary 1.6 of **[18]**) If grows polynomially, then there exists and such that in and admits a non-trivial fixed point. 7. (7)
(By Lemma 2.3 of **[18]**) Suppose satisfies with and has a non-trivial fixed point set. Then . (There are two other possible behaviors for : either for some , , or has exponential growth.)
In building van Kampen diagrams and shuffling relators we will use both forward and backward iterates of our automorphism. Lemma 7.6 (3) and (4) imply that we can use the same functions to estimate both. (1) implies that cyclic growth can be defined for outer automorphisms. This can fail for growth.
Lemma 7.7**.**
Suppose has polynomial growth and is not periodic. Then there exists and with and . Moreover, for any , .
Proof.
We use Lemma 7.6: take as per (6) and then apply (7), (1), and (2). ∎
Lemma 7.8**.**
Suppose and . For , suppose is such that as in Lemma 7.7. Define . Then and have equivalently growing Dehn functions and .
Proof.
By Lemma 3.6, the Dehn functions of and are equivalent. By Lemma 7.4, we may also pick convenient representatives of the outer automorphism classes without changing the Dehn function, so will also have equivalent Dehn function to . ∎
7.3. Dehn function lower bounds
A result similar to Lemma 7.9 was proved by Brady and Soroko [24] in the context of Bieri doubles.
Lemma 7.9**.**
Suppose that has the form where and . Suppose that .
- (1)
If , for some , then 2. (2)
If , then the Dehn function .
Proof.
If then by Lemma 7.6 (4), . Let and be such that for all . If is polynomially growing, there is and such that , and if is exponentially growing, choose such that for some , .
Consider the word . We will show that . Since
[TABLE]
this lower bound on the area will imply that the Dehn function dominates the polynomial . Consider the following picture:
A -corridor beginning on side 1 can only end on sides 2 or 4. Since -corridors cannot cross, there is some value so that the first -corridors emanating from side 1 end on side 2 and the remainder end on side 4. This switching point determines the diagram, as seen in Figure 20b. If , then a stack of at least -corridors (emanating from the 1st, 2nd etc., edge of side 1) start on side 1 and end on side 2. If , then a stack of at least -corridors start on side 1 and end on side 4: in this case take to be that emanating from the final edge of side 1, to be that emanating from the penultimate edge, etc. Let be the area of corridor , that is, the number of 2-cells in the corridor.
The area of each corridor can be bounded from below by the length of the shortest side, and that can be bounded below by the cyclically reduced length of the shortest side. For and , , so we get
[TABLE]
Summing the areas of corridors , we find that
[TABLE]
∎
7.4. Dehn function upper bounds
Lemma 7.10**.**
Suppose has the form , where and . If , then . In the case that is periodic, .
Proof.
We have a finite presentation
[TABLE]
for . Suppose is a word
[TABLE]
in which the subwords are in . Let be the length of and suppose represents the identity in . To bound from above we will estimate how many defining relators need to be applied to to reduce it to the empty word. (We are also allowed to insert or remove inverse pairs of generators or , but only applications of defining relators will count towards the area.)
By applying fewer than commutators, convert each to for some reduced and , thereby rewriting as a word , which has length at most .
Next convert to a product of the word with a word in , by applying defining relators to shuffle all the in to the right. The word represents the identity in and represents the identity in . Indeed, the index sum of in is zero, so gathering all powers of together on the left would produce a word of the form with and which represents the identity in , and so and freely reduce to the identity—in particular, in .
This shuffling of into results in growth of slow-growth elements (the factor), but not in growth of fast-growth elements (the factor). We can (crudely) estimate its cost by giving an upper bound on the length to which a letter can grow in the process: it passes at most letters or , each time with the effect of applying or . We are given that , so , by Lemma 7.6 (3). Thus there is a constant such that can grow to length at most . The cost to shuffle (and in the process transform) all the (at most ) letters of the to the right past the letters of (of which there are at most ) is at most .
Next freely reduce to the empty word (at no cost to area), leaving the word , which represents the identity in and has length at most . By Bridson–Groves [7], can be reduced to the empty word using no more than a constant times defining relations.
In conclusion, we have an upper bound of , which gives that as required.
Finally, we address the periodic case: suppose is such that is an inner automorphism. By Lemmas 3.6 and 7.4, . We can estimate by the above argument in the special case that . In this case the cost of shuffling the through the word is at most (rather than ) since they do not grow in the process, and so . ∎
Proof of Theorem 1.3.
We have , where , and . Lemma 7.1 identified a with and which (by Lemma 3.6) has .
Provided is not periodic, Lemmas 7.7 and 7.8 imply that even if , there is such that with .
The theorem claims that
- (1)
If for some (that is, is periodic), then . 2. (2)
If , then , and likewise with the indices and interchanged. 3. (3)
If , then grows exponentially.
For (1), Lemma 7.10 gives , and we have by Lemma 3.4. For (2), Lemma 7.9 gives the required lower bound on the Dehn function and (since ) Lemma 7.10 gives the upper bound. For (3), Lemma 7.9 again gives the lower bound, and Lemma 3.4 gives the upper bound.∎
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