Existence of nonradial positive and nodal solutions to a critical Neumann problem in a cone
M\'onica Clapp, Filomena Pacella

TL;DR
This paper proves the existence of nonradial positive and sign-changing solutions to a critical Neumann problem in unbounded cones under certain geometric conditions, expanding understanding of solutions in non-spherical domains.
Contribution
It establishes the existence of nonradial solutions to a critical Neumann problem in cones, including sign-changing and positive solutions, under convexity and volume conditions.
Findings
Existence of nonradial sign-changing solutions under symmetry.
Existence of positive nonradial solutions when cone volume is large.
Solutions are found in unbounded cone domains with Neumann boundary conditions.
Abstract
We study the critical Neumann problem \begin{equation*} \begin{cases} -\Delta u = |u|^{2^*-2}u &\text{in }\Sigma_\omega,\\ \quad\frac{\partial u}{\partial\nu}=0 &\text{on }\partial\Sigma_\omega, \end{cases} \end{equation*} in the unbounded cone , where is an open connected subset of the unit sphere in with smooth boundary, and . We assume that some local convexity condition at the boundary of the cone is satisfied. If is symmetric with respect to the north pole of , we establish the existence of a nonradial sign-changing solution. On the other hand, if the volume of the unitary bounded cone is large enough (but possibly smaller than half the volume of the unit ball in ), we establish…
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Existence of nonradial positive and nodal solutions to a critical Neumann problem in a cone
Mónica Clapp111M. Clapp was partially supported by UNAM-DGAPA-PAPIIT grant IN100718 (Mexico) and CONACYT grant A1-S-10457 (Mexico). and Filomena Pacella222F. Pacella was partially supported by PRIN 2015 (Italy) and INDAM-GNAMPA (Italy).
Abstract
We study the critical Neumann problem
[TABLE]
in the unbounded cone , where is an open connected subset of the unit sphere in with smooth boundary, and . We assume that some local convexity condition at the boundary of the cone is satisfied.
If is symmetric with respect to the north pole of , we establish the existence of a nonradial sign-changing solution.
On the other hand, if the volume of the unitary bounded cone is large enough (but possibly smaller than half the volume of the unit ball in ), we establish the existence of a positive nonradial solution.
Keywords: Semilinear elliptic equation, critical nonlinearity, conical domain, Neumann boundary condition, nonradial solution.
MSC2010: 35J61, 35B33, 35B44, 35B09.
1 Introduction
We consider the Neumann problem
[TABLE]
in the unbounded cone , where is an open connected subset of the unit sphere in with smooth boundary, , and is the critical Sobolev exponent.
It is well known that, if , i.e., if is the whole space , then the only positive solutions to the critical problem
[TABLE]
are the rescalings and translations of the standard bubble defined in (2.3). Moreover, they are the only nontrivial radial solutions to (1.2), up to sign. It is immediately deduced that, up to sign, the restriction of the bubbles (3.1) to are the only nontrivial radial solutions of (1.1) in any cone; see Proposition 3.4. In addition, if the cone is convex, it was shown in [8, Theorem 2.4] that these are the only positive solutions to (1.1). The convexity property of the cone is crucial in the proof of this result, and it is strongly related to a relative isoperimetric inequality obtained in [7].
The aim of this paper is to establish the existence of nonradial solutions to (1.1), both positive and sign-changing. As mentioned above, the positive ones can only exist in nonconvex cones. On the other hand, nodal radial solutions to (1.1) do not exist, as this would imply the existence of a nontrivial solution to problem (2.5) in the bounded cone , which is impossible because of the Pohozhaev identity (2.6) and the unique continuation principle.
For the problem (1.2) in various types of sign-changing solutions are known to exist; see [4, 3, 2, 5]. In particular, a family of entire nodal solutions, which are invariant under certain groups of linear isometries of , were exhibited in [2]. These solutions arise as blow-up profiles of symmetric minimizing sequences for the critical equation in a ball, and are obtained through a fine analysis of the concentration behavior of such sequences.
Here we use some ideas from [2] to produce sign-changing solutions to (1.1), but we exploit a different kind of symmetry. Our main result shows that, if is symmetric with respect to the north pole of and if the cone has a point of convexity in the sense of Definition 2.6, then the problem (1.1) has an axially antisymmetric least energy solution, which is nonradial and changes sign; see Theorem 2.8. As far as we know, this is the first existence result of a nodal solution to (1.1).
Next, we investigate the existence of positive nonradial solutions. In this case we do not require the cone to have any particular symmetry. We establish the existence of a positive nonradial solution to (1.1) under some conditions involving the local convexity of at a boundary point and the measure of the bounded cone ; see Corollary 3.5 and Theorem 3.6. We refer to Section 3 for the precise statements and further remarks.
2 A nonradial sign-changing solution
If is a domain in we consider the Sobolev space
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with the norm
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We denote by the functional given by
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and its Nehari manifold by
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For let be such that . Then,
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Hence,
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We set . It is well known that this infimum is attained at the function
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which is called the standard bubble, and at every rescaling and translation of it, and that
[TABLE]
where is the best constant for the Sobolev embedding .
Let be the unit sphere in and let be a smooth domain in with nonempty boundary, i.e., is connected and open in and its boundary is a smooth -dimensional submanifold of . The nontrivial solutions to the Neumann problem (1.1) in the unbounded cone
[TABLE]
are the critical points of on .
To produce a nonradial sign-changing solution for (1.1) we introduce some symmetries. We write a point in as , and consider the reflection . Then, a subset of will be called -invariant if for every , and a function will be called -equivariant if
[TABLE]
Note that every nontrivial -equivariant function is nonradial and changes sign.
Throughout this section we will assume that is -invariant. Note that because is smooth. Hence, for every . Our aim is to show that (1.1) has a -equivariant solution. We set
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[TABLE]
and
[TABLE]
Define
[TABLE]
and set . In we consider the mixed boundary value problem
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We point out that (2.5) does not have a nontrivial solution. Indeed, by the well known Pohozhaev identity, a solution to (2.5) must satisfy
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As for every and for every , we conclude that vanishes on . Therefore, the trivial extension of to the infinite cone solves (1.1), contradicting the unique continuation principle.
Let be the space of functions in whose trace vanishes on . Note that via trivial extension. Let be the restriction of to and set
[TABLE]
To produce a sign-changing solution for the problem (1.1) we will study the concentration behavior of -equivariant minimizing sequences for (2.5). We start with the following lemmas.
Lemma 2.1**.**
**
Proof.
It is shown in [8, Theorem 2.1] that .
Since , we have that . To prove the opposite inequality, let be such that has compact support and as . Then, we may choose such that the support of is contained in . Thus, and, hence,
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Letting we conclude that .
To prove that we fix a point and a sequence of positive numbers , and we set . Since is smooth, the limit of the sequence of sets is the half-space
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where is the exterior unit normal to at . Let , where is the standard bubble (2.3). Then,
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The function
[TABLE]
is -equivariant, and from (2.4), (2.8) and (2.9) we obtain
[TABLE]
This concludes the proof. ∎
Lemma 2.2**.**
Given a domain in and , we set . If is Lipschitz continuous, then there exist linear extension operators and a positive constant , independent of , such that
* for every .* 2.
. 3.
** 4.
If is -invariant, then is -equivariant if is -equivariant.
Proof.
The existence of an extension operator satisfying is well known, and the fact that the constant does not depend on was proved in [6, Lemma 2.1]. To obtain we replace by the function . ∎
The following proposition describes the behavior of minimizing sequences for on .
Proposition 2.3**.**
Let be such that
[TABLE]
Then, after passing to a subsequence, one of the following statements holds true:
There exist a sequence of positive numbers , a sequence of points in and a function such that , solves the Neumann problem
[TABLE]
in some half-space , ,
[TABLE]
and .
There exist a sequence of positive numbers with , and a -equivariant solution to the problem (1.1) such that
[TABLE]
and .
Proof.
Since
[TABLE]
the sequence is bounded and, after passing to a subsequence, weakly in . Then, . Since the problem (2.5) does not have a nontrivial solution, we conclude that .
Fix . As
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there are bounded sequences in and in such that, after passing to a subsequence,
[TABLE]
where . Note that, as , we have that . We claim that, after passing to a subsequence, there exist and such that
[TABLE]
and one of the following statements holds true:
for all .
for all .
for all and .
for all and .
for all , and, either , or for all .
This can be seen as follows: If the sequence is bounded, we set . Then, (2.12) and hold true. If is bounded, we take such that . Then, (2.12) and hold true. If both and are unbounded and is bounded, we take with . Then, (2.12) and hold true. If is unbounded and is bounded, we take with . Then, (2.12) and hold true. Finally, if is unbounded, we set if is bounded and if is unbounded. Then, (2.12) and hold true.
Set . Inequality (2.12) yields
[TABLE]
We consider as a function in via trivial extension, and we define as . Since is -equivariant, so is its extension given by Lemma 2.2. Let
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Then,
[TABLE]
[TABLE]
and is bounded in . Hence, a subsequence satisfies that weakly in , a.e. in and strongly in . Choosing sufficiently small and using (2.16), a standard argument shows that ; see, e.g., [10, Section 8.3]. Moreover, we have that and , because weakly in and .
Let be the limit of the domains . Since is bounded in , using Hölder’s inequality we obtain
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for every , and similarly for the integrals over . Therefore, as weakly in , rescaling and using (2.14) we conclude that
[TABLE]
where . Next, we analyze all possibilities, according to the location of .
If for all , then and is -equivariant. Hence, is -equivariant. Let . Then, for large enough , and from (2.17) we obtain
[TABLE]
This shows that solves (1.1). Therefore,
[TABLE]
Together with Lemma 2.1, this implies that and
[TABLE]
So, in this case, we obtain statement . 2.
If for all , then , where , is the exterior unit normal to at , and and are half-spaces defined as in (2.7). If , then for large enough , and using (2.17) we conclude that solves the mixed boundary value problem
[TABLE]
Since and are orthogonal, extending by reflection on , yields a nontrivial solution to the Dirichlet problem
[TABLE]
It is well known that this problem does not have a nontrivial solution, so cannot occur. 3.
If for all and , then , where is the exterior unit normal to at . Using (2.17) we conclude that solves the Neumann problem (2.10) in . Since , we have that . Therefore,
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Note also that weakly in . Using these facts and performing suitable rescalings and translations we obtain
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Since , applying Lemma 2.1 we conclude that , , and
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So, in this case we obtain statement . 4.
If for all and , then and using (2.17) we conclude that solves the Dirichlet problem (2.18). So this case does not occur. 5.
If for all and , then and solves the problem (1.2). If for every , then is -equivariant, and so is . Since is a sign-changing solution to (1.2) we have that
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contradicting Lemma 2.1. On the other hand, if , then, arguing as in case , we conclude that
[TABLE]
contradicting Lemma 2.1 again. So cannot occur.
We are left with and . This concludes the proof. ∎
Proposition 2.3 immediately yields the following result.
Corollary 2.4**.**
If , then the problem (1.1) has a -equivariant least energy solution in .
Equality is not enough, as the following example shows. Set
[TABLE]
Example 2.5**.**
If , then problem (1.1) does not have a -equivariant least energy solution in .
Proof.
is the upper half-space . If were a -equivariant least energy solution to (1.1) in then, extending by reflection on , would yield a sign-changing solution to the problem (1.2) in with . But the energy of any sign-changing solution to (1.2) is ; see [9]. ∎
The following local geometric condition guarantees the existence of a minimizer. It was introduced by Adimurthi and Mancini in [1].
Definition 2.6**.**
A point is a point of convexity of of radius if and the mean curvature of at with respect to the exterior unit normal at is positive.
As in [1] we make the convention that the curvature of a geodesic in is positive at if it curves away from the exterior unit normal . The half-space is defined as in (2.7). Examples of cones having a point of convexity are given as follows.
Proposition 2.7**.**
If , then has a point of convexity.
Proof.
Let be the smallest geodesic ball in , centered at the north pole , which contains . Then, and . Hence, every point on is a point of convexity of . As , we have that any point is a point of convexity of . ∎
Theorem 2.8**.**
If has a point of convexity, then . Consequently, the problem (1.1) has a -equivariant least energy solution in . This solution is nonradial and changes sign.
Proof.
Let be a point of convexity of of radius . It is shown in [1, Lemma 2.2] that, after fixing small enough and a radial cut-off function with if and if , the function , with as in (2.3), satisfies
[TABLE]
where is a positive constant depending only on and is the mean curvature of at . Hence, for small enough,
[TABLE]
where is such that ; see (2.1). Choosing so that we conclude that and
[TABLE]
The existence of a -equivariant least energy solution to (1.1) follows from Corollary 2.4. ∎
3 A positive nonradial solution
In this section is not assumed to have any symmetries.
We are interested in positive solutions to the problem (1.1). Note that this problem has always a positive radial solution given by the restriction to of the standard bubble defined in (2.3). The question we wish to address in this section is whether problem (1.1) has a positive nonradial solution.
Recall the notation introduced in Section 2 and set
[TABLE]
[TABLE]
It is shown in [8, Theorem 2.1] that . As in Lemma 2.1 one shows that . We start by describing the behavior of minimizing sequences for on .
Proposition 3.1**.**
Let be such that
[TABLE]
Then, after passing to a subsequence, one of the following statements holds true:
There exist a sequence of positive numbers , a sequence of points in and a function such that , solves the Neumann problem
[TABLE]
in some half-space , ,
[TABLE]
and .
There exist a sequence of positive numbers with and a solution to the problem (1.1) such that
[TABLE]
and .
Proof.
The proof is similar, but simpler than that of Proposition 2.3. ∎
The following statement is an immediate consequence of this proposition.
Corollary 3.2**.**
If , then the problem (1.1) has a positive least energy solution in .
Theorem 3.3**.**
If has a point of convexity, then . Consequently, the problem (1.1) has a positive least energy solution in .
Proof.
The proof is similar to that of Theorem 2.8. ∎
Let be the subspace of radial functions in , and define and
[TABLE]
It was shown in [8, Theorem 2.4] that, if is convex, then and the only positive minimizers are the restrictions of the rescalings
[TABLE]
of the standard bubble to . In fact, the proof of [8, Theorem 2.4] shows that these are the only positive solutions of (1.1) in a convex cone. Moreover, the following statement holds true.
Proposition 3.4**.**
For any cone , the restrictions to of the functions defined in (3.1) are minimizers of on . These are the only nontrivial radial solutions to (1.1), up to sign. Moreover,
[TABLE]
and is the Lebesgue measure of . In particular, increases with .
Proof.
A radial function solves (1.1) in if and only if the function given by with solves
[TABLE]
This last problem does not depend on . It is well known that, up to sign, the functions are the only nontrivial radial solutions to the problem (1.2) in . Hence, their restrictions to are the only nontrivial radial solutions to (1.1).
As in Lemma 2.1 one shows that . For , we have that
[TABLE]
Therefore,
[TABLE]
The same formula holds true when we replace by . In this case, the left-hand side is . Hence, , as claimed. ∎
Corollary 3.5**.**
If has a point of convexity and , then
the problem (1.1) has a positive least energy solution in ,
every least energy solution of (1.1) is nonradial.
Proof.
From Theorem 3.3 and Proposition 3.4 we get that is attained and
[TABLE]
where . So every least energy solution is nonradial. ∎
Note that the hypothesis that implies that is not convex.
A closer look at the estimate (2.19) allows to refine Corollary 3.5 and to produce examples of cones with for which the problem (1.1) has a positive nonradial solution.
To this end, we fix a smooth domain in for which has a point of convexity of radius , and we define
[TABLE]
Then, we have the following result.
Theorem 3.6**.**
There exists , depending only on , such that, for every with , the following statements hold true:
the problem (1.1) has a positive least energy solution in ,
every least energy solution of (1.1) is nonradial,
* is not convex.*
Proof.
Recall that the functions , introduced in the proof of Theorem 2.8, vanish outside the ball . Moreover, the value and the estimate (2.19) depend only on the value of in . We fix small enough so that
[TABLE]
and we set with as in Proposition 3.4. Then,
[TABLE]
Given , we fix a function such that if and if . So, if , we have that
[TABLE]
Note that is a point of convexity of . Hence, by Theorem 3.3 and the previous inequality, is attained at a nonradial solution of (1.1). Finally, recall that, if were convex, then ; see [8, Theorem 2.4]. This completes the proof. ∎
Corollary 3.7**.**
There exists a smooth domain such that the problem (1.1) has a positive nonradial solution in .
Proof.
Let be the geodesic ball in of radius centered at the north pole and let be any point on . Fix such that . Clearly, is a point of convexity of of radius , so we may fix as in Theorem 3.6. As , there exists with and . Now, Theorem 3.6 yields a positive nonradial solution to problem (1.1) in . ∎
Remark 3.8**.**
Let be such that is convex. Then, every point is a point of convexity of radius for any . Fix , and fix such that
[TABLE]
Now, define , as in Theorem 3.6. Since is convex, we must have that
[TABLE]
where the equality follows from the definition of ; see Proposition 3.4. Hence, for any convex cone , we obtain the upper bound
[TABLE]
for the measure of , which is given in terms of the Sobolev constant and the local energy of the standard bubbles.
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