Extension property in the tridisc
Lukasz Kosinski, Wlodzimierz Zwonek

TL;DR
This paper introduces a new concept of Carathéodory sets in the tridisc, explores special two-dimensional submanifolds, and investigates universal sets for the Carathéodory extremal problem, advancing understanding of extension properties in complex domains.
Contribution
It proposes a refined notion of Carathéodory sets, identifies classes of submanifolds where Lempert's theorem applies, and studies the existence of finite universal sets in the tridisc.
Findings
Certain two-dimensional submanifolds are Carathéodory and satisfy Lempert's theorem.
New criteria for domains admitting finite universal sets are established.
The introduced notion improves the characterization of extension sets in the tridisc.
Abstract
Motivated by works on extension sets in standard domains we introduce a notion of the Carath\'eodory set that seems better suited for the methods used in proofs of results on characterization of extension sets. A special stress is put on a class of two dimensional submanifolds in the tridisc which not only turns out to be Carath\'eodory but also provides examples of two dimensional domains for which the celebrated Lempert Theorem holds. Additionally, a recently introduced notion of universal sets for the Carath\'eodory extremal problem is studied and new results on domains admitting (no) finite universal sets are given.
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Taxonomy
TopicsHolomorphic and Operator Theory · Analytic and geometric function theory · Algebraic and Geometric Analysis
Extension property and universal sets
Łukasz Kosiński
and
Włodzimierz Zwonek
Abstract.
Motivated by works on extension sets in standard domains we introduce a notion of the Carathéodory set that seems better suited for the methods used in proofs of results on characterization of extension sets. A special stress is put on a class of two dimensional submanifolds in the tridisc which not only turns out to be Carathéodory but also provides examples of two dimensional domains for which the celebrated Lempert Theorem holds. Additionally, a recently introduced notion of universal sets for the Carathéodory extremal problem is studied and new results on domains admitting (no) finite universal sets are given.
Key words and phrases:
Extension set, Carathéodory set, Lempert theorem, universal set for the Carathéodory extremal problem
2000 Mathematics Subject Classification:
32D15, 32F45
The first author is partially supported by NCN grant SONATA BIS no. 2017/26/E/ST1/00723. The second author is partially supported by the OPUS grant no. 2015/17/B/ST1/00996 of the National Science Centre, Poland
1. Extension property and Carathéodory sets
1.1. Introduction and state of affairs
For a set , where is a domain in we denote by the set of holomorphic functions defined on as the set of all such that for arbitrary there are an open neighborhood of in and a holomorphic such that coincides with on . By we mean the algebra of bounded holomorphic functions on . In what follows many results could be formulated and proven for any algebras of holomorphic functions on containing polynomials; however we restrict ourselves to the special case of the algebra of bounded holomorphic functions. Additionally, for the simplicity of formulations and clarity of presentation we always assume that the set has analytic structure in the sense that is always to be assumed to be an analytic set in the given domain . This means that is relatively closed in and for every point there exist an open set containing , and such that .
The analytic set has the extension property if for any there is an such that on and .
The origin of the problem of the existence of norm preserving extensions of bounded holomorphic functions goes back to Rudin’s book ([22], Theorem 7.5.5). The key step in that area of research can be found in [4] where the problem was solved for the bidisc. More precisely, the following result was proven.
Theorem 1**.**
(see [4])* Let be a relatively polynomially convex subset of . Then has the extension property if and only if it is a retract.*
Recall that is a retract if there is a holomorphic map such that its range is and is the identity. It is an obvious observation that any retract has the extension property.
Later Kosiński and McCarthy proved, relying on the Lempert theory, that the same statement as above holds for the class of two-dimensional strictly convex domains (see [15]). They also showed some necessary form of the sets with the extension property in sufficiently smooth strongly linearly convex domains in higher dimensions. Such sets must be totally geodesic.
On the other hand in the paper [2] the authors described the sets with the extension property in the symmetrized bidisc and they found out that in this case there are sets with the extension property that are not retracts.
Although the problem of the characterization of the extension sets in the simplest case of the polydisc has been studied it is very frustrating that only some partial results on that topic were obtained. In this context let us mention results in [10], [6], [20], [14].
The situation in the tridisc was studied in [14].
As one looks at the proofs of results describing the extension sets in a series of papers in quite different situations a weaker form of the extension property is more natural to work with. Namely, the existence of norm preserving extensions of some extremal functions is essential. And in principle the results on the description of extension sets just mentioned may be generalized to that new notion. This is formally done in Section 2 where the proofs are given in a detailed and partially novel way in the bidisc only; in other cases they are merely outlined.
Studying the tridisc the authors showed that one dimensional sets with the extension property are precisely retracts (that was later generalized to arbitrary polydiscs in [20]) and for two-dimensional sets with the extension property they found a necessary condition ([14], Theorem 6.1). The last form was, as indicated in [14], not sufficient for the set to have the extension property. Then authors considered a class of two-dimensional subsets that are uniqueness varieties for three dimensional and non-degenerate 3-point Pick interpolation problem in (see [14], Remark 7.4 and [13]). In our paper we shall show that these two-dimensional subsets do satisfy our new notion, but they are not retracts. This is surprising as such a phenomenon occurs neither in the bidisc nor in domains studied in the literature so far. Therefore, this class of two-dimensional algebraic subsets is one of the objects that attracts our attention. More precisely, we look at analytic submanifolds defined as the sets
[TABLE]
where are not all zeros.
Remark 2*.*
i) Recall that a characterization of retracts in the polydisc as the sets being graphs of holomorphic functions over lower dimensional polydiscs comes from [11]. Note that if , the surface can be written as a graph of a function given by the formula
[TABLE]
where , and . In particular, is a graph of a function over the first two variables from if and only if that is . Therefore, the above-mentioned result of Heath and Suffridge [11] implies that the variety is not a retract of the tridisc exactly when for all possible permutations of the set – we shall say that such a triple satisfies the triangle inequality.
ii) The family is stable under automorphisms of in the following sense: if and maps to [math], then for some . To prove this it is enough to consider the case (permute the coordinates, if necessary). Let us represent as in (1). Note that the function is inner in the following sense: for almost all in the unit circle. Trivial computations show that transforms to a surface of the form
[TABLE]
where . It can be assumed that . It is also simple to observe (properties of ) that is inner. This fact is crucial for the rest of our reasoning.
The following observation is trivial: if
[TABLE]
is inner (that is maps almost all points from the unit cirle to the unit circle), then and either or .
Let us apply this observation to , where is a unimodular constant (almost arbitrary). If appearing in (3) is unimodular, we get that and
[TABLE]
If, in turn, , then either is unimodular and or is unimodular and . Certainly the last two cases cannot occur (otherwise would be of the form for some ). In particular, is of the form (4) and consequently can be written as for , where .
Note also that satisfies the triangle inequality if and only if does. This is an immediate consequence of the fact that takes holomorphic retracts to holomorphic retracts and the previously mentioned description of such sets.
iii) All the results for presented below are non-trivial precisely when the triple satisfies the triangle inequality – otherwise the sets are biholomorphic to the bidisc.
The notion that is new and is basic in our paper is that of an (infinitesimally) Carathéodory set to be defined below. To define the objects we use notion of the Carathéodory pseudodistance (Carathéodory-Reiffen pseudometric) that is an example of a holomorphically invariant function. Since basic properties of holomorphically invariant functions are essential for us we ask the Reader to consult the book [12] on the fundamental properties of these functions.
By we denote the hyperbolic metric on the unit disc . We also denote .
We define the Carathéodory pseudodistance
[TABLE]
Its infinitesimal version, the Reiffen-Carathéodory pseudometric, is defined below
[TABLE]
where is a regular point () and is an arbitrary vector from the tangent space .
A function for which the supremum in the definition above is attained is called extremal (respectively, infinitesimally extremal) for the pair (respectively, ).
Note that if is an analytic set in then for any and for any , .
Definition 3**.**
Let be a set (an analytic variety) in a subdomain of .
We say that is a Carathéodory set if
[TABLE]
We say that is an infinitesimal Carathéodory set if
[TABLE]
for any regular point and .
As we have already announced the (infinitesimal) Carathéodory sets are the ones that admit the norm preserving extensions of (infinitesimally) extremal functions.
It is an elementary observation that if has the extension property then it is a Carathéodory set. Any Carathéodory set is an infinitesimal Carathéodory set. In Section 2 we briefly sketch how the known proofs on results describing extension sets presented above apply to the situation of the Carathéodory sets. At this place note that any Carathéodory set must be connected.
1.2. Link to the Lempert theory
While trying to characterize the sets having the extension property (or Carathéodory sets) the impact of the Lempert theory of holomorphically invariant functions in convex domains turns out to be essential. First recall that for the domain and points we define the Lempert function
[TABLE]
Note that the definition of the Lempert function may be easily extended to arbitrary subsets (with replaced by ) - in case there is no holomorphic mapping joining , lying entirely in we define . We may also define the infinitesimal version of the Lempert function. We define
[TABLE]
where and . The function is called the Kobayashi-Royden pseudometric.
We call a holomorphic mapping a complex geodesic if there is a holomorphic function such that is an automorphism of the unit disc. In particular, for any we have the equality , . We call the function to be *the left inverse of * the complex geodesic . We also say that the complex geodesic passes through (respectively, ) if (respectively, and is parallel to for some ).
The main result in the Lempert theory is the following.
Theorem 4**.**
(see [18], [19]).* Let be a convex domain in . Then . Moreover, if is also bounded, then for any two points (respectively, , ) we may find a complex geodesic passing through (respectively, ).*
Actually for taut domains (i.e. such that any sequence of holomorphic mappings is a normal family) the fact that coincides with is equivalent to the existence for any pair of points of a complex geodesic passing through them. It is quite natural to call any taut domain such that a Lempert domain. The Lempert theorem states that any bounded convex domain is a Lempert domain. Note that the complex geodesics in are proper holomorphic embeddings of the unit disc into the domain .
Definition 5**.**
Let be an analytic subset of a domain in .
We say that is totally geodesic in if for any , there exists a complex geodesic passing through and that lies entirely in .
We say that an analytic set in is infinitesimally totally geodesic if for any and any we find a complex geodesic such that , the vector is parallel to and the image of lies entirely in .
Proposition 6**.**
Any (infinitesimally) totally geodesic set in a Lempert domain is an (infinitesimally) Carathéodory set.
Proof.
Choose distinct points and a holomorphic function . Let be a complex geodesic passing through that lies in . Choose so that , . Then, by the Schwarz lemma,
[TABLE]
Consequently, which finishes the proof in the first case. The proof in the infinitesimal case goes along the same lines so we skip it. ∎
1.3. Main results
As we already announced the following theorem is one of the main results of our paper (see Theorem 14): the set is Carathéodory. Moreover,
[TABLE]
Although we do not know whether the sets are always extension sets the above result gives not only a new insight into the understanding of the extension property and extends results of [14] but also provides an interesting class of Lempert domains. To make the last statement clear we introduce a class of two dimensional subdomains in . For we define
[TABLE]
where
[TABLE]
Note that the function is the one which gives a solution of the equation defining for suitably chosen . Similarly as above the domain is interesting precisely when the triple satisfies the triangle inequality.
A direct consequence of the above result is the following (see Theorem 19): the domain is a Lempert domain.
As we shall see later the domains are, under some obvious assumptions on and , even not linearly convex (see Remark 20). The existence of such a class of domains is interesting from the point of view of the Lempert theory, as the only domain with all holomorphically invariant functions equal for which that equality could not be concluded from the Lempert theorem is the tetrablock (introduced in [1]) – see [8]. Recall that the symmetrized bidisc was, at the time of its discovery, the first example posessing such a phenomenon (see [7], [5]). It turned out later that this domain can be exhausted by strongly linearly convex domains - that made possible to deduce the equality of all holomorphically invariant functions on the symmetrized bidisc from the Lempert theorem (see [21]).
In Section 4 motivated by a recent paper [2] we consider the universal sets for the Carathéodory problem, i.e. the sets which can replace the set in the definition of the Carathéodory pseudodistance of the domain . We remark that in dimension one under very mild and natural assumptions the existence of a finite universal set for the Carathéodory problem implies that the domain is the disc (Theorem 25).
It is noted in [2] that in dimension two the existence of a universal set with two elements requires the domain to be the bidisc. We generalize this result showing that the existence of a finite universal set lets the domain embed in the polydisc (possible of higher dimension) – see Theorem 26. Additionally, the domains turn out to be examples of the ones admitting three and not two elements in the universal set. Therefore, the situation in dimension two differs from that in dimension one and there are other than the bidisc nice and non-trivial domains admitting a finite number of elements in the universal set - see Example 27.
In Section 2 the main stress is put on extension and simplification of the situation in the bidisc, i.e. Theorem 1, which is the content of Theorem 9 and Corollary 10. The characterization of Carathéodory sets in the situation of strictly convex, strongly linearly convex and the symmetrized bidisc is sketched only as the methods from [3], [15] and [14] apply in the general case word by word.
In Section 5 we briefly discuss the problem of a possible structure of universal sets for the Carathéodory extremal problem in the Euclidean ball and we show how to produce universal sets that are ’smaller’ than the ones obtained by the most evident way.
2. Carathéodory sets replace extension sets
This section studies connection between Carathéodory and extension sets. Its first aim is to describe Carathéodory sets in the bidisc showing that they are holomorphic retracts. It is thus trivial that both notions coincide there which, in particular, proves and extends [4]. After a more detailed study of the case of the bidisc we sketch how the proofs in [3], [15] and [14] may be applied to get the results describing Carathéodory sets in the cases of strictly convex, strongly linearly convex domains and the symmetrized bidisc — the proofs of (formally stronger) results follow exactly the same lines as in appropriate papers.
Proposition 7**.**
Let be a domain in and an analytic set. Assume that for some (respectively, , for some and ). If the function is extremal for (resp. for ), then is dense in .
Proof.
Suppose that is not dense in . Let , , be a closed disc. In the first case the result follows from Lemma 9.3 in [3] which gives the existence of a holomorphic function such that
[TABLE]
which contradicts the extremality of . The infinitesimal case follows the same idea (and makes use of the same Lemma 9.3 from [3]). ∎
Below we use the notion of balanced points introduced in [4]. A pair , (respectively, , ) is called balanced (respectively, infinitesimally balanced) if it satisfies the equality (respectively, ). Note that being (infinitesimally) balanced is invariant under holomorphic automorphisms of in the sense that if the pair (respectively, ) is (infinitesimally) balanced then so is (respectively, ) for any automorphism of . It follows from the Schwarz lemma that the (infinitesimally) balanced pair determines uniquely a complex geodesic passing through them – in this case both components of the geodesic are automorphisms of the unit disc).
Lemma 8**.**
Let be polynomially convex analytic subvariety. If there is a balanced pair such that and (respectively, infinitesimally balanced pair and ) then contains the unique complex geodesic passing through them.
Proof.
The proof is standard, we are recalling it for the sake of completeness. Losing no generality we can assume that . Since (respectively, ) forms a balanced (respectively, infinitesimally balanced) pair we get that (respectively, ) , . Then making use of the fact that the function is (infinitesimally) extremal for (respectively, ), due to Proposition 7 we get that the set is dense in , so the polynomial convexity of implies that , which finishes the proof. ∎
Theorem 9**.**
Let be an analytic subvariety of that is polynomially convex. Then is an infinitesimal Carathéodory set if and only if it is a union of a discrete set and complex geodesics.
Proof.
The only difficult part is to show that any one-dimensional irreducible component of an infinitesimal Carathéodory set is (equivalently, contains) a complex geodesic.
The case when there is a point that is infinitesimally balanced follows from Lemma 8.
Suppose that no pair is balanced. Then without loss of generality we may assume that
[TABLE]
In particular, near every such the variety is a graph of a holomorphic function over the first coordinate. Moreover,
[TABLE]
if are close enough to each other.
We shall prove that contains a graph of a holomorphic function with the property , which would finish the proof.
First note that near we get the existence of a holomorphic with the property , and . Below we show how we may extend the function to the whole unit disc. Denote which is a discrete subset of .
Define as the family of all pairs where , is star-shaped (with respect to [math]), is holomorphic with , and . The identity principle shows that for any two pairs we have on . Consequently, the relation if is a partial order on .
We define the extension as follows and the function with the formula if and . Note that the function is well-defined, holomorphic, coincides with on and , . The element is a maximal element of . It is sufficient to show that . Suppose the opposite. Take a point such that the ray . First note that exists and , as otherwise would contain over uncountably many points so the disc would be contained in which contradicts the irreducibility of . Note also that . To see it divide into sufficiently small intervals Using (9) we get
[TABLE]
We claim that . Suppose the opposite. Then . The set is near the point the graph of a holomorphic function which easily gives a strictly bigger element than , which contradicts its maximality.
Now we extend the function as follows. We already know that is . And now proceeding similarly as earlier assuming that cannot be extended continuously to we get that at some point from the cluster set of would contain uncountably many points from which would force to contain – a contradiction. The continuous extension of is then trivially holomorphic.
∎
Corollary 10**.**
Let be as in Theorem 9. Then is a Carathéodory set if and only if it is a holomorphic retract.
Proof.
We already know that the Carathéodory set is connected. If is not a single point, then, by Theorem 9, contains the graph of a complex geodesic which is, up to a permutation of variables, of the form , where . If is not equal to , we can assume that and . Note that for implies that which contradicts our assumption, while for is impossible. Therefore, there is at least one (and thus uncountable many) such that . For every such the pair and is balanced. Therefore these the variety contains a geodesic , where satisfies . It is also elementary that the set of all these is uncountable. From this we simply get that is the whole bidisc. ∎
The equivalence of the notions of the Carathéodory set and infinitesimal Carathéodory set should hold for varieties without singular points for a reasonable class of .
In the remaining part of the section we shall describe relation between Carathédory and extension sets in some classes of domains. Roughly speaking both notions can be replaced by each other in statements of all the results that have been obtained so far. We shall explain this briefly below.
Recall that a domain is linearly convex if its complement is the union of complex affine hyperplanes. A domain with the smooth defining function satisfying the inequality
[TABLE]
for any , lying in the complex tangent hyperplane to at is called strongly linearly convex.
Remark 11*.*
Using methods from the present paper and the ones used in [15] we can get the following result: Let a domain in be strictly convex or strongly linearly convex. Let be a relatively polynomially convex analytic subset of . Then is a Carathéodory set if and only if it is totally geodesic.
In particular, if is the Euclidean ball or if , then any Carathéodory set is a holomorphic retract.
Remark 12*.*
Except for examples described above the extension property problem was solved fully only in a particular example of the domain
[TABLE]
called the symmetrized bidisc. It turns out that both notions coincide there in a reasonable class of domains. More precisely, an algebraic set in is a Carathéodory set if and only if it has extension property. Moreover, there are one dimensional Carathéodory sets in that are not complex geodesics.
To see this one needs to follow the proof in [3] to get that any Carathéodory set is either or , , and or there is a biholomorphic mapping . In the latter case, for Thus for and we get , which means that is a geodesic.
Remark 13*.*
The extension problem has been studied in the tridisc in [14], where partial characterization of extension sets were obtained. One can modify arguments used there along methods exploited within the proof of Theorems 9 and 10 to get that all the assertions of the main results for extension sets in [14] are also satisfied by Carathéodory sets.
3. Carathéodory sets in the tridisc - the case of the sets
Our first and main result of this section is the proof of the fact that the sets – two dimensional algebraic submanifolds of defined earlier – are Carathéodory sets. Moreover, the equality as in the Lempert theorem holds for them. The main result is formulated below.
Theorem 14**.**
The set is Carathéodory. Moreover, .
What remains unclear for us is whether the sets have the extension property. Moreover, as we shall also see later in the section, the sets give rise to a construction of two-dimensional domains (denote by ) that are Lempert. To the best of our knowledge the fact that the domains are Lempert cannot be proven by methods developed by Lempert. This makes the sets extremely interesting from that point of view - we shall address these problems at the end of the present Section.
The result is trivial if is a retract. Therefore, from now on we shall assume that this is not the case. In other words the inequalities are satisfied for all permutations of the set . In the sequel the triples satisfying this property will be called the ones that satisfy the triangle inequality. Note that if the triple satisfies the triangle inequality then , .
According to Proposition 6 to get the assertion it is sufficient to show that is totally geodesic. To prove it we shall first show in Lemma 15 that it is infinitesimally totally geodesic. Then a topological argument will finish the proof.
Using Remark 2 we may make the following reduction. Instead of proving the fact that is Carathéodory for the fixed it is sufficient to show that
[TABLE]
for any being not a retract.
Then the idea of the proof of the above equality is the following. First we show the existence of a complex geodesic passing through the origin and arbitrary vector tangent to at [math]. It is theoretically possible that not all the points from the set will be achieved by such geodesics. But the use of some topological argument will provide the existence of a geodesic passing through [math] and arbitrary point of . At the same time we show that left inverses to all such geodesics may be attained by one of three functions: the projections of onto one of the three axes.
We fix now being not a retract. Note that can be written as
[TABLE]
for some numbers such that the triple satisfies the triangle inequality and unimodular . Using linear automorphism of we can additionally assume that and . Note that in such a case .
We start the proof with the following statement.
Lemma 15**.**
Define
[TABLE]
Then there are two continuous mappings
[TABLE]
such that for any the image of the mapping
[TABLE]
lies in (, , ).
The two existing mappings are such that both components differ at each argument.
Consequently, for any there are two non-equivalent geodesics (i.e. having different image) passing through the pair .
We also have the ’infinitesimal’ version of the Lempert theorem at [math], namely, the equality holds for any .
Remark 16*.*
The set is geometrically lens (linear transformation of intersection of two discs) with exactly two points from the closure that lie in .
Proof of Lemma 15.
Let us recall that the triple satisfies the triangle inequality - it will be used in the sequel extensively.
Our aim is to show for any the existence of exactly two pairs (moreover, varying continuously) such that the following equality
[TABLE]
holds for all .
Keeping in mind that we easily get that the above equality holds if and only if
[TABLE]
Keeping in mind that (more precisely making use of the equality ) we get that the last is equivalent to
[TABLE]
The elementary planar geometric properties show that to finish the proof it is sufficient to show that for all the following inequalities hold
[TABLE]
To prove the right inequality we consider the function
[TABLE]
that is defined on a complex line containing (that is identified as a subdomain of ). The function is subharmonic as a function of a complex variable. To prove the desired inequality it is sufficient to show that is [math] on the boundary of . Take from the boundary of . We may assume that . Then the elementary calculations give
[TABLE]
The proof of the second inequality goes as follows. Due to the symmetry it is sufficient to show that
[TABLE]
Note that the left side of the above inequality is
[TABLE]
Therefore, it is sufficient to show that for all we have
[TABLE]
Simplifying above and then dividing by the last is equivalent to
[TABLE]
which is equivalent to the inequality
[TABLE]
And the last inequality holds trivially. ∎∎
Remark 17*.*
A small modification of the proof of Lemma 15 gives a much wider variety of complex geodesics having the components being the Blaschke product of degree one or two. The idea is the following. For , we put
[TABLE]
Our aim will be to find so that the above mapping lies entirely in and the second component is the Blaschke product of degree two.
Recall that the Schur algorithm gives that the square polynomial has both roots outside if and only if and . Applying this property to our function (coming from the denominator of the second component) we get the following inequality for that has to be satisfied
[TABLE]
The above inequality is equivalent to the following one
[TABLE]
where , . And now we make use of the calculations conducted in the proof of the previous lemma – to see that the above inequality holds for lying in a non-empty open arc.
The above reasoning gives the following property for the variety . If only is such that , we get following functions
[TABLE]
where is suitably chosen and may be chosen from some non-empty arc.
The above result gives an example of a two-dimensional domain for which the infinitesimal version of the Lempert theorem holds. Namely, let
[TABLE]
where .
Corollary 18**.**
The following equality holds
[TABLE]
In the special case of the origin we have the following formula
[TABLE]
Having proven Lemma 15 we shall show that is the Carathéodory set. As we already announced the proof will be a consequence of Lemma 15 and a topological argument.
Proof of Theorem 14.
We show that
[TABLE]
Below we use the notation as in Lemma 15. To show the above it is sufficient to show that for any and any , where
[TABLE]
there is a such that . Denote . To finish the proof it is sufficient to show that the function
[TABLE]
is onto. The properties of the functions imply that is not only continuous but it also extends continuously onto the closure of . Moreover, if is such that then the extension satisfies the equality . Both and are simply connected two dimensional surfaces bounded by union of two arcs and such that is a homeomorphism between the boundaries. Consequently, is onto.
∎
As a direct consequence of the theorem we get the equality of invariant functions in a class of two-dimensional domains.
Theorem 19**.**
The domain is a Lempert domain.
Remark 20*.*
Note that if the triple satisfies the triangle inequality then the domain is never linearly convex. Actually, to see this take an arbitrary point . Then . Assuming the linear convexity we find a vector such that for close to zero. The minimum principle for holomorphic functions implies that equals some unimodular constant for close to [math], which in view of the explicit formula for easily implies that either or is zero. Assume that . Then the function is a homography, the elementary calculations give that it is constant precisely when
[TABLE]
But the above equation is satisfied only for (use the triangle inequality for the triple to see that the roots of the above square equation are not reals), which gives the contradiction.
Remark 21*.*
As we saw the Lempert Theorem holds for the bounded hyperconvex domain which is not linearly convex. It would be desirable to decide whether the domain is not biholomorphic to a convex domain. Note that the domains are the next candidates for examples of that kind. Perhaps from the point of view of the Lempert Theory the domains have much less nice properties than the existing examples of that type (the symmetrized bidisc and tetrablock). In any case it seems reasonable that an effort should be undertaken to understand better the function geometric properties of that class of domains.
Remark 22*.*
Let us underline once more that a study of a class of two-dimensional submanifolds of the tridisc that appeared in the study of the extension property in [14] led not only to introducing a new property that seems to be better suited in the study of the extension property (Carathéodory sets) but also provides examples of domains interesting for the geometric function theory.
4. Universal sets for the (infinitesimal) Carathéodory extremal problem
In [2] the authors introduced the notion of universal sets for the Carathéodory extremal problem concentrating mainly on the problem in the symmetrized bidisc. In the present section we concentrate on that topic presenting results on the domains admitting finite universal sets.
Let be a domain in . We say that is a universal set for the Carathéodory (respectively, for the infinitesimal Carathéodory) extremal problem if for any , (respectively, , , ) there is an such that (respectively, ).
Remark 23*.*
Assume that is -hyperbolic and -hyperbolic (i.e. for all , and , , ). If is a universal set for the Carathéodory extremal problem then is also a universal set for the infinitesimal Carathéodory extremal problem.
As to the problem of the existence of finite universal sets we present a result on one dimensional domains and show that the domains introduced in Section 3 are examples showing that the situation in dimension one and two differs completely. We also simplify and extend results on characterization of domains with finite universal sets presented in [2].
Recall that the domain is *-finitely compact * if the Carathéodory balls are relatively compact in for all , .
4.1. Planar domains with minimal universal sets
Recall that for planar domains -hyperbolicity is equivalent to -hyperbolicity and this is equivalent to the existence of a non-constant bounded holomorphic function (see e. g. [12]).
The infinitesimal version of the proposition below is the content of Theorem 1 in [9]. The non-infinitesimal case can be obtained along the same lines.
Proposition 24**.**
(cf. Theorem 1 in [9]).* Let be a planar domain. Then Carathéodory extremals and infinitesimal Carathéodory extremals are uniquely determined which means that up to automorphisms of the unit disc for any (respectively, ) there is only one such that*
[TABLE]
We show that in the case of the planar domains the existence of finite universal sets makes the domain (under some evident assumptions) be the unit disc which is contained in the following.
Theorem 25**.**
Let be a domain in that has a finite universal set for the infinitesimal Carathéodory problem. Then has a universal set consisting of one element. In particular, if is additionally -finitely compact then it is biholomorphic to the unit disc.
Proof.
Without loss of generality we may assume that is -hyperbolic. Let be a minimal finite universal set for the infinitesimal Carathéodory extremal problem. It is sufficient to show that . Suppose that . Denote . The uniqueness of -extremals and the minimality of imply that for any there is a such that
[TABLE]
On the other hand the minimality of the set implies that for any there is a such that
[TABLE]
Standard connectivity argument shows, however, that both statements cannot hold simultanuously. ∎
4.2. Finite universal sets induce embeddings into polydiscs
Below we generalize Theorem 2.3 from [2] with a simpler proof.
Theorem 26**.**
Let be -hyperbolic and -hyperbolic. Assume additionally that is a universal set for the Carathéodory extremal problem. Then the mapping
[TABLE]
is a holomorphic embedding. In particular, and is a connected complex submanifold of dimension .
Moreover, is a Carathéodory set. In particular we get
[TABLE]
, .
If is additionally -finitely compact then is proper so in the case we get that .
Proof.
The definition of the universal Carathéodory set gives
[TABLE]
Let be such that . Then and the -hyperbolicity implies that . Therefore, is injective. Similarly, because of the fact that is a universal set for the infinitesimal Carathéodory extremal problem we get
[TABLE]
Since is -hyperbolic we get that the rank of is .
We prove that is a Carathéodory set. This can be seen as follows.
[TABLE]
Assume that is additionally -finitely compact. We show below that is proper.
Fix and let have no accumulation point in . Then the equality
[TABLE]
implies that has no accumulation point in which gives the desired properness of . ∎
4.3. Not only polydisc admits finite universal sets for the Carathéodory extremal problem in higher dimension
It is shown in [2] that the projections are contained in any universal Carathéodory set of the bidisc. It turns out that under evident assumptions domains have similar property - the three functions defining must lie in any universal Carathéodory set. Moreover, the domains are examples of (very nice, for instance -finitely compact) domains which admit the finite universal Carathéodory sets and still not being the bidisc. This shows that the situation in the case differs from the case of bigger. The fact that is not biholomorphic to the bidisc follows for instance from the fact that the indicatrix of at [math] is the domain (see Corollary 18)
[TABLE]
which is not linearly isomorphic to the bidisc under the assumption that the triple satisfies the triangle inequality.
Example 27**.**
Recall that Agler, Lykova and Young remarked that in the bidisc any universal set for the Carathéodory problem must contain (up to an automorphism) both projections. Similar property holds for the domains . More precisely, if the triple satisfies the triangle inequality then the universal set for the Carathéodory extremal problem for the domain contains (up to automorphisms) three functions:
[TABLE]
To show above note that it is sufficient to see that any of the functions (up to an automorphism), , must belong to a universal set for the Carathéodory problem in being not a retract. Take such a variety. Consider the functions as in Remark 17
[TABLE]
where is fixed and is from some non-empty arc. Then one of left inverses (call it ) of the function for the fixed is a left inverse for all from the given arc. Consequently, the function depends only on the first variable and this equals .
Remark 28*.*
It follows from [14] that any subdomain of that has a universal set composing of three elements is biholomorphic to a submanifold of that is a graph of a holomorphic function for each choice of the coordinates. In particular, it is biholomorphic to a domain of the form , where is a holomorphic function such that (respectively ) is injective for every (resp. ). Some other properties of were obtained in [14]. Recall that the results in [14] are stated with the additional assumption of polynomial convexity. However, here they can be dropped out. This forces two natural questions. The first one is if any domain with a -element (or finite) universal set comes from the variety .
The second one is more particular; namely, whether any domain having finite universal set is a Lempert domain.
5. Universal sets for the Carathéodory extremal problem for the unit ball
In the last section we make some remarks on the universal sets in the unit ball. The results presented may be seen as the starting point for the further study of a possible structure of (in some at the moment not well determined sense) small universal sets for the Carathéodory extremal problem.
We start with an easy observation that the unit ball , , does not have a finite universal set for the Carathéodory extremal problem.
Proposition 29**.**
The unit ball , , does not have a finite universal set for the Carathéodory problem.
Proof.
It is a direct consequence of Lemma 5 from [17] which states the following.
Any two different complex geodesics of the ball passing through [math] have different (up to automorphisms of the unit disc) left inverses. ∎
Remark 30*.*
The result on the existence of many complex geodesics passing through [math] in the symmetrized bidisc and tetrablock that admit only one (up to an automorphism of the unit disc) left inverse can be found in [16]. The fact that the symmetrized bidisc does not have a finite universal set follows from Theorem 3.1 in [2]. Consequently, the same holds for the tetrablock.
The most standard and natural procedure producing a class of the universal set for the Carathéodory extremal problem in the unit ball is following. As the unit ball is an example of a Lempert domain both notions: extremals and infinitesimal Carathéodory extremals coincide. Moreover, the extremals are precisely the ones being the left inverses to complex geodesic, which in turn are parametrizations of portions of complex lines lying in the unit ball. To produce extremal to one of complex geodesic (represented by ) we may proceed as follows. Let be the point of the minimal norm. Let be the automorphism of the unit ball such that , – recall that
[TABLE]
for all and .
Now we may apply the unitary mapping such that . And now the mapping is one of possible Carathéodory extremals for the points from the geodesic .
In the simplest case of we may apply the above method and we see that the universal set for the Carathéodory extremal problem may be chosen in the following way.
[TABLE]
Let us make one more remark on the properties of the above construction. It follows directly from the construction of that it is a rational mapping that is holomorphic on a neghborhood of and . In other words the universal set for the Carathéodory extremal problem just defined is parametrized by complex lines intersecting and it is minimal in the sense that no proper subset of is a universal set. Moreover, any extremal mapping is a left inverse to the unique geodesic.
It is natural to see whether one could define a class of Carathéodory extremals that could be extremals for a wider variety of geodesics, which would yield then a universal set being ’smaller’ than the one produced above. Following the construction of extremals from a recent paper [17] we shall below get the desired class of functions. We restrict ourselves for the dimension .
Let
[TABLE]
Recall that and , (see [17]).
Remark 31*.*
Note that the mapping just defined assumes the value of absolute value one on a bigger portion of than that of the most natural form of extremal mappings ( from the previous Section). Actually, note that elementary calculations give the property that for the equality if and only if
[TABLE]
The above property (fact that the absolute value equal to one is assumed at two dimensional subset of suggests that the function may be a left inverse to a one-dimensional family of complex geodesics). And this is really the case as the next observation shows.
We claim that for any the mapping is the left inverse to the mapping (complex geodesic in )
[TABLE]
Recall that ()
[TABLE]
It is elementary then to check that . It is therefore sufficient to show that
[TABLE]
which follows directly form the formula for the Carathéodory distance for the unit ball and the Poincaré distance.
Acknowledgments. The authors wanted to thank the anonymous referee for comments and corrections that improved the shape of the paper.
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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- 2[2] J. Agler, Z. Lykova, N. J. Young , Characterizations of some domains via Carathéodory extremals , J. Geometric Analysis, 29(4), 2019, 3039–3054.
- 3[3] J. Agler, Z. Lykova, N. J. Young , Geodesics, retracts, and the norm-preserving extension property in the symmetrized bidisc , Memoirs of the American Mathematical Society 2019, 258, no. 1242, 106pp.
- 4[4] J. Agler and J.E. Mc Carthy , Norm preserving extensions of holomorphic functions from subvarieties of the bidisk , Ann. of Math., 157(1), 289–312, 2003.
- 5[5] J. Agler, N. J. Young , The hyperbolic geometry of the symmetrized bidisc , J. Geom. Anal. 14 (2004), no. 3, 375–403.
- 6[6] T. Bhattacharyya, H. Sau , Holomorphic functions on the symmetrized bidisk—realization, interpolation and extension , J. Funct. Anal. 274 (2018), no. 2, 504–524.
- 7[7] C. Costara , The symmetrized bidisc and Lempert’s theorem , Bull. London Math. Soc. 36 (2004), no. 5, 656–662.
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