Large Sets with Small Injective Projections
Frank Coen, Nate Gillman, Tam\'as Keleti, Dylan King, Jennifer Zhu

TL;DR
This paper constructs complex fractal sets with prescribed projection properties, demonstrating the existence of high-dimensional sets with small or controlled projections, and applying these to geometric and measure-theoretic problems.
Contribution
It introduces a method to build compact sets with specified Hausdorff dimensions that project injectively into lines, and applies this to construct sets with unusual measure and dimension properties.
Findings
Existence of compact sets with prescribed projection dimensions
Construction of small unions of high-dimensional planes with large overall dimension
Examples of line collections with positive measure but limited intersection properties
Abstract
Let be a countable collection of lines in . For any we construct a compact set with Hausdorff dimension which projects injectively into each , such that the image of each projection has dimension . This immediately implies the existence of homeomorphisms between certain Cantor-type sets whose graphs have large dimensions. As an application, we construct a collection of disjoint, non-parallel -planes in , for , whose union is a small subset of , either in Hausdorff dimension or Lebesgue measure, while itself has large dimension. As a second application, for any countable collection of vertical lines in the plane we construct a collection of nonvertical lines , so that , the union of lines in , has positive Lebesgue measure,…
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Large Sets with Small Injective Projections
Frank Coen
Department of Mathematics & Statistics, Villanova University, 800 Lancaster Ave, Villanova, PA 19085, U.S.A.
,
Nate Gillman
Department of Mathematics, Brown University, Providence, Rhode Island 02912, U.S.A.
,
Tamás Keleti
Institute of Mathematics, Eötvös Loránd University, Pázmány Péter Sétány 1/c, H-1117 Budapest, Hungary
,
Dylan King
Department of Mathematics & Statistics, Wake Forest University, Winston-salem, NC 27109, U.S.A.
and
Jennifer Zhu
Department of Mathematics, University of California, Berkeley, Berkeley, CA 94720, U.S.A.
Abstract.
Let be a countable collection of lines in . For any we construct a compact set with Hausdorff dimension which projects injectively into each , such that the image of each projection has dimension . This immediately implies the existence of homeomorphisms between certain Cantor-type sets whose graphs have large dimensions. As an application, we construct a collection of disjoint, non-parallel -planes in , for , whose union is a small subset of , either in Hausdorff dimension or Lebesgue measure, while itself has large dimension. As a second application, for any countable collection of vertical lines in the plane we construct a collection of nonvertical lines , so that , the union of lines in , has positive Lebesgue measure, but each point of each line is contained in at most one and, for each , the Hausdorff dimension of is zero.
The third author was supported by the Hungarian National Research, Development ad Innovation Office - NKFIH, 124749 and 129335.
1. Introduction and statement of results
Weierstrass famously constructed a function which is everywhere continuous but nowhere differentiable. The so-called Weierstrass function is defined in his original 1872 paper [10] as the following Fourier series,
[TABLE]
where , is a positive odd integer, and . We know now that the graph of the Weierstrass function has Hausdorff dimension greater than one, which provides some explanation for this pathological function’s dearth of differentiability: in particular, one can easily show that differentiable functions have graphs of Hausdorff dimension 1. It is also well known that that there exist continuous functions with graph of Hausdorff dimension .
It turns out that the seemingly pathological behavior of a continuous function with a graph of large dimension is the rule rather than the exception. Balka, Darji and Elekes recently showed [1] that for any compact uncountable metric space , within the space of continuous functions , those with graphs of Hausdorff dimension are prevalent in a measure-theoretic sense. (In this paper always denotes Hausdorff dimension.) Intuition might suggest that these graphs rely heavily on local oscillations to increase their Hausdorff dimension, and therefore would not be injective. Many of the classical constructions take advantage of this strategy. For example, the Weierstrass function fails to be injective in the most spectacular way: it lacks monotonicity on all arbitrarily short intervals. This is an example of a continuous non-injective map with a large graph. More recently, Eiderman and Larsen found that it is possible to trade continuity for injectivity: they constructed [4] an injective non-continuous function on whose graph has Hausdorff dimension .
It is therefore natural to ask whether there exist injective and continuous real-valued functions that have large graph dimension. Such a function cannot rely on local oscillations in the same way as the Weierstrass function: clearly, if a continuous real-valued injective function is defined on an interval, then it is monotone and necessarily has dimension one. Hence, such a function must be defined on some carefully chosen set.
In the present paper, we answer this question in the affirmative. We construct compact sets of dimension , as well as a homeomorphism so that , for any desired value of . This dimension is maximal because is contained in the Cartesian product . The construction of such a function reduces to assembling a set which projects injectively onto in the domain and in the codomain. Our method of assembling is a modified Venetian blind construction, in which we make extra effort to ensure injectivity of the projections. This generalizes in many ways: first, the two coordinate axes can be replaced with any pair of (not necessarily orthogonal) lines, and this pair of lines can in turn be replaced with any finite or countable collection of lines. It is also natural to consider projections into lines inside the ambient space rather than . This is our main result.
Theorem 1.1**.**
Let be a finite or countable set of lines in . Then for any , there exists a compact set with , such that each orthogonal projection is injective with .
Furthermore, consider each of the following statements:
- (1)
The set has positive -capacity and infinite -dimensional Hausdorff measure. 2. (2)
The -dimensional Hausdorff measure of every is [math].
If , then (1) holds; if , then (2) holds; and if , then one can choose either of (1) or (2) to hold.
In we can consider projections into linear subspaces of any dimension. Analogously, we construct large such that the projection is injective and has dimension for any prescribed . In this most generalized form, we once again find an easy upper bound on : since is contained in an isometric image of , we have . This maximum possible dimension is precisely the one that we obtain as our first corollary.
Corollary 1.2**.**
Fix , and let be a finite or countable collection of linear subspaces in (not necessarily all of the same dimension). Then for any there exists a compact set with , such that each projection is injective with .
Without the injectivity of the projections, this was proved in Claim 2.4 of [2]. Next, by applying Theorem 1.1 to the standard basis vectors, we obtain the following corollary on the existence of homeomorphisms whose graphs have large dimension. The correspondence between bijective (specifically, coordinate-wise injective) functions and sets injective onto each coordinate axis is clear. That is a homeomorphism follows easily from the compactness of the graph .
Corollary 1.3**.**
For any and , there exist compact with dimension and a coordinate-wise injective homeomorphism such that . Further, if then each of has -dimensional Hausdorff measure [math].
Denoting by the set of -planes in , we can place a natural metric on through association with . Through this metric one can investigate the relationship between the Hausdorff dimension of a collection and the size (Lebesgue measure or dimension) of its union in . In [9, Theorem 1.3] Oberlin shows that if has Lebesgue measure zero then , and provides examples which demonstrate that this is tight. Concerning the Hausdorff dimension of , in [6, Corollary 1.12] Héra proves that , and provides examples which are tight in some specific cases. More concretely, for any she constructs a collection of -planes with such that the union of the -planes has the following Hausdorff dimension,
[TABLE]
Héra also formulates the conjecture that this is the best construction in the sense that whenever with and is the the union of the -planes of then .
The examples furnished by Héra and Oberlin involve collections of -planes which may intersect one another or are parallel. Since the objective is minimizing the size of , it is not clear whether these intersections or collections of parallel -planes are an important component of the construction. As an application of Corollary 1.3, we present constructions corresponding to those in [9] and [6], with the additional property that they consist of disjoint, nonparallel -planes. We found in Theorem 1.1 that requiring injectivity of a continuous function will not necessarily reduce the Hausdorff dimension of its graph; here we find an analogous statement, that requiring -planes to be disjoint and non-parallel does not necessarily increase the size of their union.
Theorem 1.4**.**
Let with .
- (i)
There exists a compact set of disjoint, nonparallel -planes with so that , the union of -planes in , has Lebesgue measure zero. 2. (ii)
*For any which satisfies , there exists a compact set of disjoint non-parallel -planes with such that , the union of -planes in , has Hausdorff dimension for the function defined in (1.1). *
Note that since any compact set has a compact subset of any given dimension less than we can also get with smaller than the above prescribed dimension. This observation, in combination with (i) and the result of [9] that if has Lebesgue measure zero then , gives the immediate corollary that we may exchange any such collection for another consisting of disjoint, nonparallel planes.
Corollary 1.5**.**
Suppose such that , the union of those -planes in , has Lebesgue measure zero. Then there exists a compact set consisting of disjoint, nonparallel -planes such that , with the property that , the union of the -planes in , has Lebesgue measure zero.
We now consider one final application of Theorem 1.1. It is well known that, for a collection of nonvertical lines in the plane which covers a vertical line, the union must have Hausdorff dimension . In fact, this is essentially the same as the classical result of Davies [3] which states that every Besicovitch set in the plane must have Hausdorff dimension . One can ask what we can say in the opposite situation: if a collection of lines in the plane intersects a vertical line in a small set, does this imply that the union of the lines is small? The answer is clearly in the negative: for example, taking all non-vertical lines through a fixed point of is a counter-example. There are two natural ways to exclude this triviality: we could request the chosen lines to intersect in distinct points; or alternatively, we can require small intersections not only with but with more than one vertical line. By combining Theorem 1.1 with duality and projection theorems we show that even if we have both requirements it is possible that the intersection with the prescribed vertical lines are very small despite the union of the lines being very large. In fact, more generally we can construct a collection of hyperplanes in with these properties.
Theorem 1.6**.**
Let and let be a countable collection of parallel lines in . Then there exists a compact collection of hyperplanes in , not parallel to the lines , such that every point of every intersects at most one , the set has positive Lebesgue measure, and for every .
Our paper is organized as follows. In Section 2, we deduce Corollary 1.2 and Theorem 1.6 from Theorem 1.1. In Section 3 we prove Theorem 1.4, using as a crucial ingredient the homeomorphisms furnished by Corollary 1.3. In Section 4 we construct a suitable set towards proving Theorem 1.1. There we also prove various geometric lemmas relating to our construction. Finally, in Section 5 we verify that and its projections have the alleged dimensions.
2. Proofs of the direct applications of our main result
2.1. Generalization to higher dimensional subspaces
Proof of Corollary 1.2.
Let be a collection of lines such that for each there is some such that . By Theorem 1.1, there exists a compact set of Hausdorff dimension such that for every . Since the projections are injective, so are the projections . Hence, it suffices to show that . Because is contained in some isometric image of , we have , which implies . As for the upper bound, by the inclusion we have that is contained in some isometric image of , which has dimension . ∎
2.2. Large union of hyperplanes with small injective sections
Proof of Theorem 1.6.
For any let denote the “vertical” line in . Without loss of generality we can suppose that the parallel lines are vertical; that is, they are of the form for some . For any let denote the hyperplane in , and for any let . Then, we have
[TABLE]
and therefore the map is a scaled copy of the orthogonal projection of to a line in the direction .
For each we let be a line in with direction and apply Theorem 1.1 to this collection with . This yields a compact set of positive -capacity such that \pi_{\ell_{i}}\big{|}_{\Gamma} is injective with . Now we take and . Then is a compact collection of -dimensional hyperplanes in , not parallel to the lines , and also . The projection of into the line in the direction corresponds to the intersection . Since these projections are injective, every point of each is contained in at most one . It is also clear that for every .
It remains to check that has positive Lebesgue measure. By a result of Mattila [8, Corollary 9.10], if a set has positive -capacity then its projection to almost every -dimensional subspace has positive Lebesgue measure. We can apply this with and deduce that the projection of to almost every line through the origin has positive Lebesgue measure. Thus almost every vertical slice has positive measure, so by Fubini, has positive Lebesgue measure. ∎
3. Disjoint non-parallel -planes
In this section we prove Theorem 1.4, which consists of modifications of constructions given in [6] and [9]. In both cases we present constructions with the same Hausdorff dimension as those previously presented, with the additional property that the -planes used are disjoint and non-parallel (whereas in [6] and [9] they were not).
As stated in the introduction, denotes the set of -dimensional affine subspaces in . We use a matrix formulation of the encoding of used in [9]. Given a pair , where is a matrix and is a vector, we define the following -plane,
[TABLE]
Note that this encoding cannot represent all -planes: if a -plane does not pass through a point where the first coordinates are [math], then it cannot be encoded in this form. For example, in , lines parallel to the axis cannot be written as . However, since this restriction is very weak, almost every plane in can be represented in this way and this is sufficient for our considerations. Having encoded almost all elements of as points in , we inherit a metric on these -planes from the Euclidean metric on .
The proofs of the two parts of Theorem 1.4 are similarly structured. They seek to create a collection of disjoint, nonparallel -planes so that is large, yet the union of those planes found in is small. This is accomplished by utilizing the function furnished by Corollary 1.3. In Equation (3.1) one may interpret as the orientation and the displacement of the given -plane. In our proof we will determine and the first coordinates of by applying to the th coordinate of . The large dimension of the graph of will provide the largeness of while the injectivitiy of will ensure that such a family of lines is not parallel.
3.1. has Lebesgue measure zero
Proof of Theorem 1.4, part (i).
Let denote the -dimensional Lebesgue measure. By Corollary 1.3, there exists a compact set with dimension 1 and Lebesgue measure 0, as well as a continuous entry-wise injective function such that . We view the codomain as the space of pairs of and matrices over , by splitting into and . Then we define the following collection of -planes.
[TABLE]
where is defined in (3.1).
The function determines the orientation and positioning of a single -plane lying in for a given . Then , and therefore this set satisfies , where the last equality is furnished by . Furthermore, our representation of is simply , viewing elements of by their identification in . Then , as needed. Additionally, each -plane in is disjoint since each -plane is contained within a different slice . Since is injective in each coordinate, each of the -planes will have a different value for in particular. Since this coordinate is one component of the orientation of the -planes, they will be nonparallel. ∎
3.2. has limited Hausdorff dimension
Proof of Theorem 1.4, part (ii).
We modify the construction given in [6] to select only -planes which are disjoint and nonparallel. Set . If then and setting to a single -plane suffices. If , then and so by [7] taking any -dimensional collection of disjoint, nonparallel -planes produces .
If and , then using Corollary 1.3 we choose some with , as well as a coordinate-wise injective homeomorphism with . Once again we view the codomain as the space of pairs of and matrices over , by splitting into two maps and . Then we define the following collection of -planes,
[TABLE]
In this case, viewing elements of by their identification in , we have , which implies , as needed. Further, since is contained within , we also have that . The -planes are disjoint because, as before, they each lie in a different copy of , and they are nonparallel because is coordinate-wise injective.
Finally, if , we again use Corollary 1.3 to choose some with , as well as a coordinate-wise injective homeomorphism with . Then setting as we defined in equation (3.2) above (replacing with in the definition of ), we have , while is contained within . This implies , as needed. Finally, since is closed we may take a compact -dimensional subset of to complete the proof. ∎
Remark 3.1**.**
While both of these constructions are at least as strong as the best existing results, (i) is more complete than (ii) because, as it was mentioned in the introduction, there are still gaps in our understanding of the dimension case, regardless of whether the -planes are required to be disjoint or nonparallel.
With some extra effort we can guarantee in Theorem 1.4 (ii) by augmenting with a suitably chosen simple collection of disjoint non-parallel -planes; it is not difficult to increase leaving the same. However, this may not be interesting, since if one happens to get in Theorem 1.4 (ii) then this construction surpasses the current best known (even without the extra condition that the -planes are disjoint and non-parallel). In fact, it would give a counter-example to the alread mentioned conjecture of Héra ([6, Conjecture 1.16]), which states that such example cannot exist. In other words, the conjecture of Héra would imply in Theorem 1.4 (ii).
On the other hand, in [9] it is shown that if has Lebesgue measure zero then , and therefore (i) of Theorem 1.4 constructs an extremal example. This dichotomy explains why we have Corollary 1.5 for (i) and not (ii) of Theorem 1.4.
4. The set
In this section, we construct and compute salient attributes of it that will affect dimension and measure computations in the following section.
4.1. Modification and extension of the collection of lines
As we will see later, it is prudent to replace our collection of lines with a sequence satisfying a convenient collection of properties.
Lemma 4.1**.**
Let be a countable collection of lines in which go through the origin. Then there exists a sequence so that:
- (1)
Every appears in infinitely many times. 2. (2)
Any consecutive lines in have linearly independent directions.
Proof.
First, we take a -dimensional subspace in which does not contain any , and let be lines in through the origin with linearly independent directions. Then enumerate the lines so that each appears infinitely often, and insert between each line the lines . This new enumeration satisfies our constraints. ∎
4.2. The construction of
Here we construct a compact set which, as we will argue in this section and the next, suffices to prove Theorem 1.1. It will depend on our choice of two sequences, and , which we will specify in Lemma 4.4, but for now we define for arbitrary positive real sequences and .
Definition 4.2**.**
Let and be positive real sequences. For , we define the following interval on the line :
[TABLE]
where by an interval on the line we mean the closed line segment connecting to , where is the unit vector in the direction of . Observe that for fixed , these are segments of the same length, and as we’ll prove in Lemma 4.7, these segments are disjoint for a suitable choice of and .
For a line , let be the orthogonal projection onto . We define sets by induction. We first set
[TABLE]
Suppose that is the union of a collection of identical disjoint solid closed parallelotopes:
[TABLE]
where . Using these, we inductively define
[TABLE]
Finally, we define
[TABLE]
4.3. Interpreting
We now motivate and illustrate this definition. We defined to be the intersection of a nested sequence of compact sets , where the are defined inductively in (4.2). Each is the disjoint union of identical closed parallelotopes , for ; we will use to denote the collection of such . We determined the size and relative positioning of these parallelotopes using positive real sequences and , and in this section we will illustrate these geometric objects. In the next section we will estimate in terms of these sequences.
For the purposes of visualization consider the case when and are both rapidly increasing with . When we assemble from , from each parallelotope in we are taking many smaller parallelotopes , as in Figure 1.
Injective projection onto is a major desired feature of . A natural way to guarantee such injectivity is to require the parallelotopes to be contained in preimages, under the projection , of carefully chosen disjoint intervals in . These intervals were first defined in (4.1) and are each of width .
To motivate the choice of these intervals, we look ahead to our goal: to bound the Hausdorff dimension of from below. For this estimate, it will be necessary to place an a lower bound on the distance between two in . If, inside a particular , we place the new sufficiently close together, then the distance between the in will be very large compared to the distance between in . This will ensure that the minimal distance between two parallelotopes in will be achieved only when the pair of polytopes originates from the same parallelotope in . This is illustrated in Figure 2, where the distance between in different is much larger than the distance between those in the same .
Our construction defined an offset of from the start of one to the next. This is a large multiple of the width (measured in distance between opposite faces) of a single parallelotope , so that the distance between two within the same is at least .
Recall the definition of from Equation (4.1). For fixed , the index determines an offset of . In Figure 2, these intervals are depicted as monochromatic. Next, we observe that the coefficient on is small relative to the coefficient on . Hence, for a fixed we have that shifts the interval by a very small distance: in particular, twice the width of a single . Our later constraints on the sequences and will imply that these intervals are disjoint as illustrated. Intervals of the same color in Figure 2 will be disjoint by definition, coming from the same , and we will, in Lemma 4.4, force intervals of different colors to be disjoint by choosing large enough.
From a fixed we took as many parallelotopes as this separating distance will allow. The specification that we take only parallelotopes is necessary because it will happen that some intersects the parallelotope in one of its corners, or more generally any pair of adjacent sides, and in this case the intersection is not a true parallelotope. In Lemma 4.6, we show that such discarded sets are negligible so long as we take to grow sufficiently fast.
4.4. Estimating
As is apparent from Definition 4.2, the construction of is completely determined by the sequences and . In particular, in order to calculate the size of and its projections, we need good estimates on in terms of the given sequences and .
Consider the projection of to , and recall that in (4.2) we must discard those sets where the preimage of this projection is in a “corner” of . In other words, we would like to estimate the length of the interval for which is a parallelotope if and only if . The following lemma gives the estimate we need.
Lemma 4.3**.**
Let be the sequence of lines given by Lemma 4.1, let and be positive real sequences, and let \Gamma=\Gamma\big{(}(\ell_{k}),(a_{k}),(n_{k})\big{)} be as in Definition 4.2.
There exist real numbers and that depend only on the sequence such that for any , under the assumption
[TABLE]
the following holds.
For each there exists a nonempty interval of length
[TABLE]
such that for every the set is a parallelotope if and only if .
Proof.
Fix and and let . Let be the set of those real numbers for which the hyperplane is between two opposite faces of the parallelotope . Note that then indeed is a parallelotope if and only if . By definition is nonempty if has two opposite faces such that their orthogonal projections to are disjoint and clearly the length of is the distance between these projections.
Note that by construction has pairs of opposite faces such that for every the faces and are perpendicular to and the distance between the hyperplanes containing and is .
For each let be the vector such that . Then is parallel to all faces of but and , which implies that is perpendicular to every line but . Let be the angle between and and let be the angle between and .
Note that
[TABLE]
Since by (2) of Lemma 4.1 the directions of are linearly independent, the directions of are determined by , hence we obtain that the angles depend only on the sequence of lines . We claim that for any and . Indeed, would imply that are all perpendicular to and would imply that are all perpendicular to , which in both cases would contradict the linear independence assumption (2) of Lemma 4.1. The geometric setup is illustrated in Figure 3.
Since is the distance between and , provided this distance is positive, we get that
[TABLE]
provided the lower estimate is positive. Define and by
[TABLE]
These numbers are well defined since none of these angles can be and they depend only on the sequence of lines and their own indices. Note that
[TABLE]
which gives the upper estimate of (4.4) via (4.6). By this and (4.6), to get the lower estimate in (4.4) it is enough to show that
[TABLE]
Using that projection cannot increase the distance, the edges of have lengths , and (4.5), we obtain
[TABLE]
On the other hand the assumption (4.3) and the definition of gives
[TABLE]
Combining these we get (4.8), which completes the proof. ∎
The following lemma contains our requirements about the sequences and in the construction.
Lemma 4.4**.**
Fix . Let be the sequence of lines given by Lemma 4.1, and let and be the sequences given by Lemma 4.3.
*There exist positive real sequences and such that for every , all of the following conditions hold: *
- I.
** 2. II.
** 3. III.
** 4. IV.
** 5. V.
n_{k}\geq 4k\cdot\big{(}2n_{k-1}+a_{k-1}+n_{k-d}+\alpha_{k}+\alpha_{k+d}+3d+2+\sum_{j=1}^{d-1}(n_{k-d+j}+\alpha_{k+j})\big{)}** 6. VI.
** 7. VII.
** 8. VIII.
** 9. IX.
** 10. X.
** 11. XI.
** 12. XII.
Consider the following statements:
- (1)
For large enough , we have 2. (2)
For large enough , we have
If , then (1) holds; if , then (2) holds; and if , then we can choose either of (1) or (2) to hold.
Remark 4.5**.**
In Lemma 4.4, the choice of imposing growth condition (1) or (2) on corresponds to the choice of alternative (1) or (2) in Theorem 1.1. We will justify this correspondence in Section 5.
Proof of Lemma 4.4.
For every , let us initially set
[TABLE]
where we choose if we want (2) in property XII and if we want (1) in property XII. This choice satisfies properties XI and XII for any sequence . We will now show that there is a choice of which increases rapidly enough to satisfy the remaining properties. Property X is satisfied for any sufficiently large , since , and similarly for property VIII.
By algebraically substituting every by and using that , we can see that all properties II through IX are of the form , where the constant and the function depend only on and the sequence of lines ; also, property I consists of finitely many inequalities of this form. Therefore by induction all of these properties can be satisfied. ∎
Now that we can estimate the width of the valuable space inside the projection of to , we estimate the number of intervals that can fit into the projection of a single . This allows us to effectively estimate the quantity of new parallelotopes born from a single , which in turn allows us to estimate the number of parallelotopes inside .
Lemma 4.6**.**
Fix . Let and be real sequences given by Lemma 4.4, let be the sequence of lines given by Lemma 4.1, and let be the corresponding real sequences provided in Definition 4.2. For , let be as in Lemma 4.4. Then, for some , we have
[TABLE]
In particular, there exist real sequences , , and with such that the following hold for :
- i)
We have . 2. ii)
We have . 3. iii)
We have .
Proof.
Let . We estimate , which we recall is entirely determined by our inductive definition (4.2).
Fix and let be the quantity of inside . By Property I of Lemma 4.4, the assumption (4.3) of Lemma 4.3 holds, so the conclusion holds as well. Let be the interval Lemma 4.3 gives. By construction, we have
[TABLE]
Combining this with (4.4) of Lemma 4.3 we obtain
[TABLE]
Using (III) of Lemma 4.4 and the fact that and for any , this gives
[TABLE]
Since by definition this implies that
[TABLE]
which completes the proof of the first paragraph of the lemma.
Now we verify i). If we define
[TABLE]
then an elementary calculation verifies that , so it remains to show that . We show this by induction on . As (by Definition 4.2) , the base case is equivalent to , which is implied by property IV in Lemma 4.4 for . Now let , and assume that By definition, . Using i) for , and , we obtain
[TABLE]
which is at most by property IV of Lemma 4.4. This proves i).
Next we verify ii). Towards this, we define
[TABLE]
Using telescopic sums, we can compute using (4.10) that ii) holds with this choice of , so it remains to show that . If, using i), we replace with in (4.12), then take the modulus of each term and use that for , then property V in Lemma 4.4 gives that .
Lastly we verify iii). Noting the similarity to ii), if we define
[TABLE]
then, using (4.10) for instead of , a straightforward calculation shows that iii) holds with this choice of . Note that in the previous paragraph we proved the stronger estimate . Therefore, follows from the triangle inequality applied to (4.13), in conjunction with property VI of Lemma 4.4. ∎
4.5. Injectivity of
Lemma 4.7**.**
Let be the sequence of lines given by Lemma 4.1, let and be the real sequences given by Lemma 4.4, and let be the corresponding set. Then, for fixed large enough , the intervals defined in (4.1) are disjoint for all distinct pairs with , .
Proof.
We consider two intervals and . If , then the distance between the left endpoint of and the right endpoint of is
[TABLE]
Next, property VII of Lemma 4.4, in conjunction with Lemma 4.6 i), imply that that for large enough that . Therefore the above distance is at least
[TABLE]
With a positive separating distance, the intervals are disjoint. On the other hand, if then we may assume , so the distance between the left endpoint of and the right endpoint of is
[TABLE]
hence the intervals are disjoint in this case as well. ∎
Having proved that the intervals are disjoint, we may proceed to injectivity.
Lemma 4.8**.**
The map is injective.
Proof.
Suppose we have two points with , and take the subsequence which is identically (here we use property 1 of Lemma 4.1). Then the point on is contained in a sequence of intervals . Since we proved above that these intervals are disjoint for large enough , the choice of is unique. Then we have since (by construction of ) this is the only parallelotope whose image under is . Finally we check that
[TABLE]
First, recognize that is constant across by construction. Recall those vectors and angles used in the proof of Lemma 4.3 and the equations (4.5) and (4.7) relating them to each other and the constants . Then using property II of Lemma 4.4 and that we have
[TABLE]
which indeed tends to [math] as . Showing that the diameters of the paralleletopes tends to [math] is enough to finish the proof because then , so is indeed injective. ∎
5. Dimension and measure computations for
Fix a line . In this section we prove the three estimates , , and in Subsections 5.1, 5.3, and 5.4 through 5.6, respectively. Together these clearly imply the first paragraph of Theorem 1.1.
Additionally, we show in Subsections 5.5 and 5.6 that for , the set has positive -capacity provided satisfies the following estimate for sufficiently large ,
[TABLE]
this is option (1) in Theorem 1.1, as well as property XII of Lemma 4.4. Separately, we will argue in Subsection 5.2 that for , the -dimensional Hausdorff measure of is zero provided that for sufficiently large , the ratio satisfies the following inequality,
[TABLE]
which is option (2) in Theorem 1.1, as well as property XII of Lemma 4.4. Observe that these conditions are not compatible, hence for we cannot guarantee both (1) and (2) in Theorem 1.1.
5.1. The upper bound
It suffices to construct a sequence of finite covers for such that for every , for sufficiently large , we have
[TABLE]
We examine the natural sequence of coverings generated by our construction. Namely, there exists a subsequence of which is identically , and as defined previously, the projection of into consists of intervals of width . Accordingly, we define the cover to be the collection of these intervals.
It follows that the above sum is . By Lemma 4.4 property XI and Lemma 4.6 i) we see as ,
[TABLE]
as needed, since and .
5.2. Option (2) in Theorem 1.1
Here we verify that for , if we assume (5.2), then we have . Utilizing the same sequence of covers defined above, we compute that
[TABLE]
Applying Lemma 4.4 property XI and Lemma 4.6 i) as above, as well as (5.2), we see that
[TABLE]
since by Lemma 4.6, and because by property VIII of Lemma 4.4. Hence the -dimensional Hausdorff measure of is [math], provided (5.2) holds.
5.3. The upper bound
This follows from the observation that is contained in some isometric image of .
5.4. The setup for the lower bound on the size of
To complete the proof of Theorem 1.1 it remains to prove and, in order to get option (1), to show that if and (5.1) holds then has positive -capacity and infinite -dimensional Hausdorff measure.
Towards this, we define a mass distribution on in the natural way, starting with unit mass for , uniformly distributing the mass from each paralellepiped in into the smaller sub-parallelotopes in , and letting be the limiting mass distribution. Let be a ball of diameter . By the mass distribution principle (see for example [5, pp. 61]), to prove that it would suffice to show for every . In option (1) we also need capacity estimates, so to make the argument more consistent for the two situations, instead of the mass distribution principle we will apply (for both options) the following slightly stronger standard result, which we prove for completeness.
Lemma 5.1**.**
If and is a finite Borel measure supported on a compact set , and
[TABLE]
then the -capacity of K is positive and has infinite -dimensional Hausdorff dimension.
Proof.
By the definition of -capacity (see [8]) in order to show it is enough prove that , where is the -energy of . As in [8], the inner integral can be rewritten as
[TABLE]
where denotes the ball centered at with radius . Since is a finite measure, this shows that in order to prove that is finite it is enough to prove that for some fixed and (not depending on ) we have
[TABLE]
Applying the assumption of the lemma for and taking small enough, we get that for , which implies that the above inequality indeed holds for some finite constant , which does not depend on .
Finally, by [8, Theorem 8.7 (1)], we have that if has positive -capacity then it also has infinite -dimensional Hausdorff dimension, as needed. ∎
By the above lemma, it remains to show the following.
Claim 5.2**.**
(i) If and (5.1) holds then we have (5.3) for . (ii) If and we assume only then (5.3) holds for every .
To prove this claim, we consider two cases which together cover all possible values of : namely, either , or for some uniquely chosen index . It is clear that these cover all possible cases, because property IX of Lemma 4.4 implies that .
5.5. Case 1:
Here, the diameter of is greater than the length of the shortest translation vector between two , but small enough that a translated copy fits inside the containing . This is illustrated in Figure 4.
In this case, we first obtain the following basic estimate,
[TABLE]
By our construction the mass of each is , and the second factor can be bounded as follows,
[TABLE]
where the first estimate holds since can intersect only one and the second estimate holds because the shortest translation vector between any two has length by our construction and all such sets must intersect . The final estimate holds by the fact that for any , which holds here by using the case hypothesis and that the sequence is non-decreasing by property IX of Lemma 4.4.
Hence, is implied by the following,
[TABLE]
By Lemma 4.6 ii) this is equivalent to
[TABLE]
Because both in (i) and (ii), there exists so that for we have is monotonically increasing in . Since by the hypothesis of this case, we find that it is enough to prove
[TABLE]
To check (i) observe that if we assume (5.1) then (5.4) for is implied by , and this last inequality holds by property X, in conjunction with the estimate . To check (ii) note that the right-hand side of (5.4) tends to , so (5.4) indeed holds for large enough for any .
5.6. Case 2:
Here, the diameter of is greater than the width of an projected onto , but smaller than the distance of the shortest translation vector between two . This is illustrated in Figure 5.
Accordingly, this time we start with a similar basic estimate,
[TABLE]
The number of which intersect is bounded similarly, but this time we only take the product over the first terms, and we use that can intersect at most two .
[TABLE]
Hence (5.3) is implied by the following,
[TABLE]
By Lemma 4.6 iii), it suffices to show
[TABLE]
Notice that , so by the hypothesis of this case , it suffices to show
[TABLE]
Note that this estimate is nearly identical to (5.4), hence the remainder of this argument follows mutatis mutandis.
Acknowledgements
The authors would like to thank Richárd Balka, Kornélia Héra, András Mathé, and Pertti Mattila for their suggestions and remarks, as well as the referees for their detailed suggestions regarding the exposition. They would also like to thank the Budapest Semesters in Mathematics program for providing the framework under which this research was conducted.
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