Absolute continuity of the spectrum in a twisted Dirichlet-Neumann waveguide
Philippe Briet, Jaroslav Dittrich, David Krejcirik

TL;DR
This paper proves that a specific quantum waveguide with mixed boundary conditions has purely absolutely continuous spectrum, meaning no point or singular continuous spectrum exists, which is important for understanding wave propagation.
Contribution
It establishes the absence of point and singular continuous spectrum in a twisted Dirichlet-Neumann waveguide, advancing spectral analysis in quantum waveguides with mixed boundary conditions.
Findings
No point spectrum in the waveguide
No singular continuous spectrum in the waveguide
Spectrum is purely absolutely continuous
Abstract
Quantum waveguide with the shape of planar infinite straight strip and combined Dirichlet and Neumann boundary conditions on the opposite half-lines of the boundary is considered. The absence of the point as well as of the singular continuous spectrum is proved.
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**Absolute continuity of the spectrum
in a twisted Dirichlet-Neumann waveguide **
Ph. Briet,1 J. Dittrich2 and D. Krejčiřík3
1 Aix-Marseille Université, Université de Toulon, CNRS, CPT, F-13288 Marseille, France
2 Nuclear Physics Institute, Czech Academy of Sciences, CZ-250 68 Řež, Czech Republic
3 Department of Mathematics, Faculty of Nuclear Sciences and Physical Engineering,
Czech Technical University in Prague, Trojanova 13, CZ-120 00 Prague 2, Czech Republic
Electronic mail: [email protected], [email protected], [email protected]
(20 January 2020)
Abstract
Quantum waveguides with the shape of a planar infinite straight strip and combined Dirichlet and Neumann boundary conditions on the opposite half-lines of the boundary are considered. The absence of the point as well as of the singular continuous spectrum is proved.
1 Introduction
Two-dimensional straight waveguides with combined boundary conditions, classical as well as quantum, were considered in a number of papers [1]–[5]. Mostly, the existence of isolated eigenvalues was studied. We consider a very special configuration of such quantum waveguides here for which we show the absence of the eigenvalues, including that embedded in the essential spectrum ones, and the absence of the singular continuous spectrum.
Let be the operator that acts as the Laplacian in a straight strip with and satisfies Dirichlet boundary conditions on and Neumann boundary conditions on the other part of the boundary . We understand as the self-adjoint operator in the Hilbert space generated by the closed form
[TABLE]
One has
[TABLE]
Here we denote by a generic point in .
The model belongs to the configurations introduced in [6]. Let with denote the eigenvalues of the Laplacian in , subject to a Dirichlet boundary condition at [math] and a Neumann boundary condition at (or vice versa). It is easy to see that
[TABLE]
In [7] it was shown that the operator satisfies a Hardy-type inequality with a positive constant , and in [8], the consequences on the behavior of the heat semigroup for large times were studied. In particular, it follows that cannot be an eigenvalue of . As the last progress, the existence of a scattering stationary wave function was established in [9].
To complete the study of the model, in this paper, we study the nature of the essential spectrum and show that the spectrum of is actually purely absolutely continuous.
Theorem 1**.**
One has
[TABLE]
The idea of our proof of the absence of the point spectrum is based on the (here formal) commutator identity
[TABLE]
where is the dilation operator in the longitudinal direction acting as
[TABLE]
It follows from (1.2) that if there exists such that with , then
[TABLE]
where and denote the inner product and norm in , respectively. Consequently, as an element of , and therefore, necessarily . It essentially shows that the point spectrum of is empty. To prove the other statement of Theorem 1, we employ the positivity of the right-hand side of (1.2), apart from the set of thresholds
[TABLE]
with help of the Mourre theory of conjugate operators [10].
The danger of the formal procedure described above is best illustrated by observing that the same conclusions are obtained for the modified operator generated by the form (1.1), where is replaced by with any real . But if is positive (so that the Neumann boundary conditions overlap) and sufficiently large, then it is known (see [6]) that admits (discrete) eigenvalues. The reason behind this apparent contradiction is the fact that the function does not necessarily belong to , so identity (1.2) does not make sense even when applied to .
We prove the absence of the point and singular continuous spectrum for a very special configuration of the planar straight quantum waveguide with combined Dirichlet and Neumann boundary conditions. While the specific configuration is essential for the non-existence of discrete eigenvalues, the absence of the singular continuous spectrum is a more robust property. As the used conjugate operator is localized at infinity (acts as zero near the origin ), the same proofs can be done for variants of modified in a bounded subset of . For instance, we could consider an arbitrary finite combination of Dirichlet-Neumann boundary conditions in or even Robin boundary conditions and perhaps compactly supported potentials. However, the modifications should be such that Proposition 2, i.e., the bound of used in the estimate of (3.11), holds. This might be a restriction on the possibility of the waveguide shape local modifications.
We use the Mourre theory in its original form [10]. More advanced exposition can be found in the book [11]. The first application of the Mourre theory in the context of quantum waveguides is in [12]; see also [13]-[15] for further developments.
The organization of the paper is as follows. In order to justify that the formal argument goes through in our situation , in Section 2, we use a cut-off approximation of both for large and small and proceed by the method of multipliers in the spirit of [16, 17]. It is interesting that this apparently technical regularization actually gives an insight into why this procedure for with positive cannot generally work. Finally, in Section 3, we modify (1.3) to a conjugate operator “localized at infinity” and prove a (non-strict) Mourre estimate.
2 Absence of the point spectrum
Let us assume that there exists an eigenfunction and an eigenvalue satisfying
[TABLE]
Then for any ,
[TABLE]
We would like to construct a special such that from the last equation would follow , and so there is no eigenvector. More precisely, our choice of would not lie in , so we need to construct a sequence of regularized functions and obtain the result in the limit.
Without loss of generality, we assume that is real as and satisfy (2.1) separately. As a solution of the differential equation , (cf., e.g., [18, Thm. 2.2 of Chapt. 4], together with the Sobolev embedding theorem). In particular, the derivatives of and its powers may be calculated as classical.
For the regularization purposes, let us first define a sequence of functions ()
[TABLE]
belonging to with the derivatives defined almost everywhere. Then set
[TABLE]
Now
[TABLE]
Evidently, and so satisfies (2.2). Remembering the properties of [6], ,,, , and , we write
[TABLE]
Integration by parts with respect to , and also with respect to in one case, gives
[TABLE]
Inserting to (2.14), we get with
[TABLE]
By similar calculations,
[TABLE]
Looking at the definition (2.12), it is clear that, , for every and for every . Furthermore, only for
[TABLE]
Consequently,
[TABLE]
by the dominated convergence. As
[TABLE]
it follows that , so is necessarily -independent. Now because , and there is no non-zero eigenfunction and no eigenvalue satisfying (2.1). So the relation from Theorem 1 is proved.
3 Absence of the singular continuous spectrum
Given any and , will denote the spectral projection of onto the interval . We restrict to , where the set is introduced in (1.4), and choose so small that . Let be as above and let be a self-adjoint operator to be specified in a moment (it will be a regularization of (1.3)). To apply the abstract theorem of [10] and thus conclude the absence of the singular continuous spectrum of , it is enough to verify the following properties:
- (a)
The intersection is a core of . 2. (b)
The unitary group leaves the domain of invariant and
[TABLE] 3. (c)
The form
[TABLE]
is bounded from below and closable. Moreover, the operator associated with the closure of satisfies
[TABLE] 4. (d)
The operator defined by the form
[TABLE]
extends to an operator
[TABLE]
being equipped with the graph norm and being its dual space. 5. (e)
There exists a positive number and a compact operator on such that
[TABLE]
Note that (respectively, ) can be interpreted as a realization of the commutator (respectively, the double commutator ).
3.1 The Hamiltonian
We begin with establishing some new results about the operator which will be needed later.
Proposition 1**.**
For every positive , the set
[TABLE]
is a core of .
Proof.
Let be an arbitrary function from . We show that it can be approximated by functions from . Let and be functions from such that and
[TABLE]
Let us define
[TABLE]
so that
[TABLE]
It is sufficient to approximate and by functions from . It is known that ; see [6]. Let us extend them to first. To keep the boundary conditions, let us choose extensions symmetric with respect to the Neumann parts of the boundary and antisymmetric with respect to the Dirichlet parts. Note that in half-planes where the functions are zero, it means the same. So we define
[TABLE]
The extended functions are in and ). As the traces of functions and the normal derivatives on the boundaries of from both sides coincide, the extended functions are in . In fact, we used a special case of [19, Thm 4.26] and its proof. Then, extend them to which is possible over the straight boundary.
Furthermore, we need to approximate and by functions. We use the standard mollifications, see [19, Lem. 3.15],
[TABLE]
where
[TABLE]
Let us consider only for . Then, and approach there as . These function are in if they satisfy the corresponding boundary conditions at which are easily verified for the usual symmetric choice of .
Let us show it here for the case of Neumann boundary condition on . The trace exists as and we can simply calculate
[TABLE]
and the required boundary condition at follows. The other boundary conditions are verified similarly.
Finally, let , , where is a suitable function with the support in and the value in while is a function with the support in and the value in . Then is an arbitrarily good approximation of in with the graph norm choosing sufficiently small and large enough. So is a core of . ∎
Proposition 2**.**
There exists a positive constant such that, for every ,
[TABLE]
Moreover, for every positive , there exists a positive constant such that, for every ,
[TABLE]
where denotes the characteristic function of the set .
Proof.
Given any , let be the unique solution of the resolvent equation [the problem is well defined because ]. The weak formulation reads
[TABLE]
Choosing in (3.4), we get
[TABLE]
Consequently, , and . This proves (3.2).
To establish (3.3), we follow the ideas of standard elliptic regularity (see [20, Sec. 6.3]). Let be such that , if and if . Now we choose in (3.4), where
[TABLE]
is the difference quotient of in the direction . With an abuse of notation (followed also at other places in the paper), we denote by the same symbol the function on as well as on . Choosing , we have (it is only important to ensure the Dirichlet boundary conditions). Using the integration-by-parts formula for the difference quotients, (3.4) yields
[TABLE]
To deal with the right-hand side, we write
[TABLE]
where . On the left-hand side, we use
[TABLE]
Consequently, (3.5) yields
[TABLE]
with any positive numbers and , where the second inequality employs (3.2) with the explicitly given constant. Choosing and sufficiently small, the left-hand side is a sum of two non-negative terms and the desired claims follow by further estimating (and similarly for the other norm) and by sending to [math]. ∎
3.2 The conjugate operator
Let be such that , if and if . For every , we define and . Finally, we set and . Notice that as and that .
With these preliminaries, we define
[TABLE]
where is understood as an operator of multiplication. The following considerations are full analogy of [14, Props. 6.1–2]. However, as there is a difference in the cut-off at zero instead of the cut-off at infinity, we give the proofs here.
The operator is essentially self-adjoint in . This is a consequence of [11, Prop. 7.3.6(a)] and its proof. In our special case, it can also be seen directly that the deficiency indices of are zero due to the properties of function .
Let denote the (self-adjoint) closure of . Using the Hilbert-space identification , we set
[TABLE]
which is a self-adjoint operator in .
For any fixed , consider the initial-value problem
[TABLE]
By classical results (see [21, Thm. 4.1 of Chapt. V]), (3.8) admits a unique global solution in . One has
[TABLE]
for every and . Define
[TABLE]
Proposition 3**.**
* is a strongly continuous unitary group on with the generator (3.7).*
Proof.
It is clear from (3.8) that for , and for . Using the properties of , the relation (3.9) is now improved to
[TABLE]
for every and
[TABLE]
The unitarity of then follows from its construction (3.10).
Equation (3.8) together with the unicity of its solution implies the relation
[TABLE]
from which the group property
[TABLE]
follows.
It is sufficient to verify the strong continuity of at . The continuity of is easily seen for and then extends to by the density argument as .
Direct calculations show
[TABLE]
for . As the generator of the group is self-adjoint, it equals necessarily. ∎
The following proposition establishes property (b).
Proposition 4**.**
* is stable under the action of and (3.1) holds.*
Proof.
Let . We need to check that then , for every . We have seen in the previous proof that the map leaves and invariant. So satisfies the required boundary conditions at and .
Equation (3.9) implies that the derivatives , , and are bounded in for a fixed . Then . Let us calculate
[TABLE]
Every terms on the right-hand side are clearly square integrable, possibly except of the second one. However, for according to (3.9) and the properties of . So the second term is also square integrable as , see [6]. Now the relation is proved. Further, the continuity of the used bounds with respect to implies (3.1). ∎
The following proposition establishes property (a).
Proposition 5**.**
* is dense in for the graph norm associated with .*
Proof.
The claim follows from Proposition 1 and the fact that . ∎
3.3 The first commutator
Let . Using the formula (3.7) with (3.6) and integrating by parts, we compute
[TABLE]
keeping in mind the properties of and . For brevity, here we have stopped to write the measures of integration in the integrals.
Since is non-negative, we immediately see that is bounded from below. Explicitly,
[TABLE]
so the lower bound actually tends to [math] as .
Since , where
[TABLE]
is obviously a symmetric below bounded operator in , it follows that is closable (see, [22, Thm. VI.1.2.7]). The closure satisfies
[TABLE]
By the representation theorem, we have
[TABLE]
It is evident that .
Summing up, in this subsection, we have established property (c).
3.4 The second commutator
Here, we follow the same lines as in the Sec. 3.3. Let and compute
[TABLE]
First, consider
[TABLE]
Then,
[TABLE]
We also have
[TABLE]
Finally we get
[TABLE]
By Proposition 2, is continuous in the graph norm associated with and so extends continuously to the form defined again by the equation (3.11) on . Then it defines a bounded map , and the statement (d) is proved.
3.5 The Mourre estimate
Finally, we are concerned with the essential condition (e). We rewrite the restriction of as follows
[TABLE]
Now, we look at the individual terms and try to eventually estimate from below by a positive multiple of plus a compact operator sandwiched between the projections s.
3.5.1 Operator
For every , we have
[TABLE]
Here we have used the spectral theorem at the last estimate. Hence, this term can be made negligible by choosing small and we shall estimate it as
[TABLE]
3.5.2 Operator
We demonstrate our approach on ; the operator can be handled in a similar way. At the same time, let us suppose that .
Let be the self-adjoint realization of the Laplacian in , subject to the Dirichlet boundary conditions on and the Neumann boundary condition on . Let be the eigenfunctions of the one-dimensional Laplacian in , subject to the Neumann boundary condition at [math] and the Dirichlet boundary condition at . We define
[TABLE]
the projection on the th transverse mode of . We have
[TABLE]
with
[TABLE]
Note that the operator is not compact. Denote by the restriction of on . Let with . We have for any ,
[TABLE]
on the domain of the right-hand side. Now, let us choose . If , then
[TABLE]
At the same time, if , we have
[TABLE]
The first term on the right-hand side of the second line of (3.15) can be estimated as
[TABLE]
Hereafter, denotes a generic strictly positive constant which does not depend on the index and on (but depends on fixed ) and can change its value from line to line. If , we have
[TABLE]
Now, we turn to estimating the second term on the right-hand side of the second line of (3.15). We choose . We could improve the bound to be obtained by choosing larger but with more complicated calculations. On the range of , we have
[TABLE]
with
[TABLE]
Noticing that the support of the derivative of is compact and not intersecting , we use Proposition 2 to obtain
[TABLE]
Consequently,
[TABLE]
Summing up, we have proved that for small and large,
[TABLE]
When analyzing , we consider which is defined in the same manner as but with interchanged boundary conditions. The corresponding projections and the operator are defined with an obvious modification of the formulas above. By using the same arguments as above, we get the same estimate (3.20) for . Writing ,
[TABLE]
However, since , , and we conclude with the estimate
[TABLE]
being valid in the form sense.
3.5.3 Operator
The operator is not small. However, since the function has a compact support, it follows that is a compact operator. This is seen form the fact that which is compactly embedded in by the Rellich-Kondrachov theorem (see [19, Thm. 6.2]). Now
[TABLE]
is also a compact operator. Note that the presence of (its part ) in (3.12) is the only obstruction to get a strict Mourre estimate (i.e., with ).
3.5.4 Conclusion
If , it follows from the preceding subsections that for small and large, the Mourre estimate
[TABLE]
holds true, where is a compact operator.
We have verified all the properties (a)–(e) required for the application of the abstract theorem of [10]. Since is a discrete set, this concludes the proof that the singular continuous spectrum of is empty.
In fact, our result gives more information. In particular, the limiting absorption principle holds for every energy ; see [10] or [11].
Acknowledgement
The second author (J.D.) was supported by the Czech Science Foundation, Project No. 17-01706S and the NPI CAS institutional support, No. RVO 61389005. The last author (D.K.) was partially supported by the Czech Science Foundation, Project No. 18-08835S.
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