The topological Hochschild homology of algebraic $K$-theory of finite fields
Eva H\"oning

TL;DR
This paper computes the topological Hochschild homology of algebraic K-theory spectra of finite fields at primes p ≥ 5, using spectral sequences to analyze different cases based on the behavior of q^n-1.
Contribution
It provides explicit calculations of topological Hochschild homology for algebraic K-theory of finite fields, extending previous spectral sequence methods to new cases.
Findings
Computed $THH_*(K( ext{finite field})); H ext{F}_p$ explicitly.
Determined $V(1)_*THH(K( ext{finite field}))$ in two cases.
Organized computations based on the mod p behavior of $q^n-1$.
Abstract
Let be the algebraic -theory spectrum of the finite field with elements and let be a prime number coprime to . In this paper we study the mod and topological Hochschild homology of , denoted , as an -algebra. The computations are organized in four different cases, depending on the mod behaviour of the function . We use different spectral sequences, in particular the B\"okstedt spectral sequence and a generalization of a spectral sequence of Brun developed in an earlier paper. We calculate the -algebras , and we compute in the first two cases.
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The topological Hochschild homology of algebraic -theory of finite fields
Eva Höning
Fachbereich Mathematik der Universität Hamburg, Bundesstraße 55, 20146 Hamburg, Germany
Abstract.
Let be the algebraic -theory spectrum of the finite field with elements and let be a prime number coprime to . In this paper we study the mod and topological Hochschild homology of , denoted , as an -algebra. The computations are organized in four different cases, depending on the mod behaviour of the function . We use different spectral sequences, in particular the Bökstedt spectral sequence and a generalization of a spectral sequence of Brun developed in an earlier paper. We calculate the -algebras , and we compute in the first two cases.
1. Introduction
Let be a prime power and let be the algebraic -theory spectrum of the finite field with elements. Let be a prime number with and . In this paper we study the mod and topological Hochschild homology of , denoted by . In [22] we constructed a generalization of a spectral sequence of Brun and we applied it to give a short computation of the mod and topological Hochschild homology of -completed connective complex -theory . In this paper we apply the spectral sequence in a similar fashion to .
Topological Hochschild homology is an ingredient for the computation of topological cyclic homology () via homotopy fixed points and Tate spectral sequences. By [20] and [17] the connective cover of is equivalent to . The study of iterated algebraic -theory is interesting because of the red-shift conjecture predicting that algebraic -theory increases the chromatic level by one [7].
By Quillen’s computations [34] the homotopy of is given by
[TABLE]
Our computations depend on the degree of the first homotopy group with -torsion and on the order of the -torsion subgroup. We define to be the order of in , so that the first -torsion appears in degree , and we define to be the -adic valuation of , so that the -torsion subgroup of has order . We distinguish the following four cases:
- (1)
and , 2. (2)
and , 3. (3)
and , 4. (4)
and .
We study by means of the Bökstedt spectral sequence, the generalized Brun spectral sequence developed in [22] and a spectral sequence of Veen [39].
The Bökstedt spectral sequence of a commutative -algebra and a commutative -algebra has the form
[TABLE]
Here, is the Eilenberg-Mac Lane spectrum of , is mod homology and denotes ordinary Hochschild homology over the ground ring . The Bökstedt spectral sequence is an -comodule -algebra spectral sequence and under some flatness condition one additionally has a coalgebra structure.
We define . We use the following instances of the generalized Brun spectral sequence:
- a)
, 2. b)
.
Here, denotes the mod Moore spectrum. Note that is isomorphic to , so that the abutment of a) is an input of b).
Veen’s spectral sequence has the form
[TABLE]
We examine Veen’s spectral sequence in small total degrees and use our result to determine the differentials of a).
In case (1) and (2) the mod homology of has an easy form and the Bökstedt spectral sequence converging to has a coalgebra structure. This is useful to compute the differentials. In case (1) the Bökstedt spectral sequence has already been computed by Angeltveit and Rognes [5]. We proceed similarly in case (2) (Subsection 6.2). In case (2) an Ext spectral sequence argument shows that the th Postnikov invariant of is in the image of the forgetful functor from the homotopy category of -modules to the homotopy category of -modules (Lemma 6.12). This implies that is an -module and we can identify with the -comodule primitives in . We obtain (see Theorem 6.14):
Theorem**.**
In case (2) we have an isomorphism of -algebras
[TABLE]
Here, , and denote the polynomial, exterior and divided power algebra over and the degrees are given by , , and .
We compute via the spectral sequence a) in all the cases except for the subcase of case (4) where (Subsection 7.2). In case (4) it seems harder to compute via the Bökstedt spectral sequence, because this depends on the mod homology of which is complicated in this case. In order to compute the differentials in the spectral sequence a) we only need to examine Veen’s spectral sequence in small total degrees. This only depends on low degrees of .
We determine the spectral sequences b) in case (1) (Subsection 7.3). There is only one possible differential. Its existence follows from the fact that the mod homology of has no non-trivial comodule primitives in degree (Subsection 6.1). We obtain (see Theorem 7.21):
Theorem**.**
In case (1) the -homotopy of is the homology of the differential graded algebra
[TABLE]
with , , , and .
The last result was also obtained by Angelini-Knoll using a different approach [3]. In [2] Angelini-Knoll also shows that detects the -family in case (1).
There is a fiber sequence of spectra
[TABLE]
(see [21]). Denoting by the Adams operation, the map is the unique lift of to the -connective covering of . The relation between and the multiplication of can be informally written as
[TABLE]
(see [40]). We show that this fiber sequence can be constructed in the homotopy category of -modules and that the equation (1) also holds in this category (Section 3). These observations are very useful for our computations: The -linearity of the fiber sequence is helpful to determine the multiplicative structure of and (Section 4 and Section 5). We use the -linearity of the fiber sequence and equation (1) to compute the ring (Subsection 7.1).
Acknowledgments
The content of this article is part of my PhD thesis. I am very grateful to my PhD supervisor Christian Ausoni for his support. I woud like to thank Birgit Richter for telling me that one of my initial attempts probably does not work and for her help. I am very thankful to Magdalena Kedziorek for her feedback. I would like to thank Gabriel Angelini-Knoll for helpful discussions about the subject and I would like thank Irina Bobkova Gemma Halliwell, Ayelet Lindenstrauss, Kate Poirier, Birgit Richter and Inna Zakharevich for helpful discussions about higher during the Women in topology II and the AIM SQuaRE project. This work was supported by grants from Région Île-de-France and the project ANR-16-CE40-0003 ChroK. I would like to thank the MPIM Bonn for providing ideal working conditions during final stages of this work.
2. Notations and recollections
We work in the setting of Elmendorf, Kriz, Mandell and May [18]. For a commutative -algebra let be the category of -modules. We denote its symmetric monoidal smash product by . The category is a model category, where the weak equivalences are the -isomorphisms, the cofibrations are the retracts of relative cell -modules and where all objects are fibrant. We denote its homotopy category by . The category is a tensor triangulated category (see [11, Definition 1.1]), where the distinguished triangles are given, up to isomorphism, by the images of the cofiber sequences under . The functor is lax symmetric monoidal and, denoting the tensor product in by , the structure map
[TABLE]
is an isomorphism in if or is a cofibrant -module. For a morphism of commutative -algebras the functor maps distinguished triangles to distinguished triangles and is lax symmetric monoidal. Spheres in are denoted by and homotopy groups are given by for . We denote the right adjoint of by . The functor preserves distinguished triangles. We set . Note that we have a natural isomorphism . An -ring spectrum is an object with maps and in satisfying the left and right unit laws. We denote the category of commutative -algebras by . It has a model category structure, where the weak equivalences are the -isomorphisms and all objects are fibrant [18, Chapter VII]. The category can be identified with the the category of commutative -algebras under and the model category structure on is the one inherited from . By [22, Lemma 2.2] the map (2) is an isomorphism of -ring spectra if and are maps between cofibrant commutative -algebras and if or is a cofibration in .
For a prime we denote by and the mod Moore spectrum and the mod Toda-Smith complex. We can assume that and are cell -modules. We have distinguished triangles in
[TABLE]
[TABLE]
where and are maps of associative and commutative -ring spectra, [31], [32], [33].
By [24, Example VI.5.2],[26], [28] and [18, Corollary II.3.6] algebraic -theory can be realized as a functor from the category of commutative rings to . For a commutative ring the -algebra is connective. One has and is Quillen’s th algebraic -theory group for [27, Example 6.2].
Recall that -completion is Bousfield localization with respect to . By the proofs of [18, Lemma VII.5.8], [18, Lemma VII.5.2] and [18, Theorem VIII.2.2] the -completion of a commutative -algebra can be constructed as a commutative -algebra in such a way that we get a functor with values in cofibrant commutative -algebras.
For an abelian group we denote by its Eilenberg-Mac Lane spectrum. Recall that by [28], [25], [24], [18, Corollary II.3.6] and by functoriality of cofibrant replacements [18, LemmaVII.5.8] the Eilenberg-Mac Lane spectrum of a commutative ring can be realized as a cofibrant commutative -algebra in such a way that we get a functor from the category of commutative rings to .
We denote by , , and the polynomial algebra, the exterior algebra, the divided power algebra and the truncated polynomial algebra over , and we write for . Furthermore, we write if and are equal up to multiplication by a unit in .
An infinite cycle in a spectral sequence is a class such that we have for all . A permanent cycle is an infinite cycle that is not in the image of for any .
3. The fiber sequence relating and
Throughout this paper we fix a prime power for and denote by the finite field with elements. Let be a prime number with and let and be built with respect to this prime.
By [34] we have a fiber sequence of spaces
[TABLE]
where is the Adams operation. After -completion one gets an analogous fiber sequence of spectra [21]. In this section we construct a fiber sequence of this form in .
We define to be the commutative -algebra . Quillen’s computations [34, Theorem 8] imply that we have
[TABLE]
where is the order of in . Let be the algebraic closure of . Then, is equivalent as a ring spectrum to -completed connective complex -theory [27, Section7]. We thus have an isomorphism of rings
[TABLE]
with . By [27, Section 7] the Adams operation corresponds to the map induced by the Frobenius automorphism . In homotopy it is the map given by [35, Subsection 5.5.1]. We have isomorphisms of -algebras and .
By functoriality the map induced by the Frobenius automorphism is a map of -algebras and therefore of -modules. We consider the element
[TABLE]
Note that the [math]-connected covering of in -modules is given by the morphism in defined by
[TABLE]
Here is the product of the -ring spectrum .
Lemma 3.1**.**
There exist exactly one element f\in\mathscr{D}_{\operatorname{K}}\bigl{(}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p},S^{2}_{\operatorname{K}}\wedge_{\operatorname{K}}^{L}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)} that is mapped to under
[TABLE]
Proof.
We have an exact sequence:
[TABLE]
By [23] and [12, Theorem 7.1] we have a cohomological strongly convergent spectral sequence of the form
[TABLE]
Since for , we get \operatorname{Ext}^{-1}_{\operatorname{K}}\bigl{(}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p},H\mathbb{Z}_{p}\bigr{)}=0. We have a commutative diagram
[TABLE]
The right vertical map is an isomorphism because it identifies with the edge homomorphism in the above spectral sequence [23]. Since is the identity, we have that
[TABLE]
is zero. ∎
The map is part of a distinguished triangle in :
[TABLE]
From the long exact sequence in homotopy we get:
Lemma 3.2**.**
We have
[TABLE]
Lemma 3.3**.**
We have
[TABLE]
Proof.
For let be the -adic valuation of . For we have
[TABLE]
The claim now follows by using the distinguished triangle (3). ∎
Lemma 3.4**.**
The map
[TABLE]
is an isomorphism for .
Proof.
For there is an exact sequence
[TABLE]
Since the first term is zero, and since the second and third term are both , this proves the lemma. ∎
We want to show that in . We denote the map induced by the inclusion of fields by .
Lemma 3.5**.**
The map
[TABLE]
is an isomorphism for .
Proof.
For we have \pi_{2rj}\bigl{(}\operatorname{K}(\bar{\mathbb{F}}_{l})\bigr{)}=0 by [34, p.585], so we get a map of exact sequences
[TABLE]
Because V(0)_{2rj}\bigl{(}\operatorname{K}(\mathbb{F}_{q})\bigr{)} and V(0)_{2rj}\bigl{(}\operatorname{K}(\bar{\mathbb{F}}_{l})\bigr{)} are both isomorphic to , it suffices to show that \pi_{2rj-1}\bigl{(}\operatorname{K}(\mathbb{F}_{q})\bigr{)}\to\pi_{2rj-1}\bigl{(}\operatorname{K}(\bar{\mathbb{F}}_{l})\bigr{)} is injective. This follows because by [34, p.585] the abelian group is the filtered colimit of the abelian groups \pi_{*}\bigl{(}\operatorname{K}(k)\bigr{)}, where runs over the finite subfields of , and because by [34, Theorem 8] the maps \pi_{*}\bigl{(}\operatorname{K}(k)\bigr{)}\to\pi_{*}\bigl{(}\operatorname{K}(k^{\prime})\bigr{)} induced by inclusions of finite fields are injective. ∎
Lemma 3.6**.**
There exist an that is mapped to under
[TABLE]
Proof.
We have an exact sequence
[TABLE]
It thus suffices to show that . There is an exact sequence
[TABLE]
Using the spectral sequence one gets that . We therefore only have to show that is zero. This is clear. ∎
We will show that is an isomorphism. We show this by proving that its image under is a -equivalence between -local -modules.
Lemma 3.7**.**
The map
[TABLE]
is an isomorphism.
Proof.
It is clear that is an isomorphism in the degrees for . It thus suffices to show that is an isomorphism in the degrees for .
The map induces a map between the exact couples
[TABLE]
and
[TABLE]
and therefore a map of the associated singly-graded Bockstein spectral sequences. Fix . Let be a generator of . Since we get that
[TABLE]
is an element of order . It follows that has a preimage under the map
[TABLE]
but not under the map
[TABLE]
Hence, survives to the -page in the spectral sequence associated to the exact couple (5) and
[TABLE]
Since has the same homotopy and mod homotopy groups as , the same argument as above shows that the preimage of under the isomorphism
[TABLE]
has to survive to the -page of the spectral sequence associated to the exact couple (4) and that . We conclude that maps
[TABLE]
to
[TABLE]
Thus, is an isomorphism. ∎
By definition, is -local.
Lemma 3.8**.**
The -module is -local.
Proof.
Let be a -acyclic -module. We have an exact sequence
[TABLE]
Because is -local, one has \mathscr{D}_{S}\bigl{(}W,\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)}=0. Since desuspensions of -acyclic -modules are -acyclic, we get
[TABLE]
∎
Corollary 3.9**.**
We have a distinguished triangle of the form
[TABLE]
in .
The following lemma will be useful later to determine multiplicative structures.
Lemma 3.10**.**
In we have the following equality of morphisms:
[TABLE]
Proof.
By a spectral sequence argument it follows that is connective. An spectral sequence computation shows that
[TABLE]
It follows that
[TABLE]
is injective. It thus suffices to show that the equality holds after composing with . Now, we can argue as in [40, Lemma 4.1]. In [40] a similar statement is proven for the category of spectra (instead of ) and for that generates .
∎
4. The algebras and
In this section we determine the multiplicative structure of and . In [14, Theorem 2.6] Browder computes the ring . Browder works with spaces. In this section we present a computation using the -linearity of the distinguished triangle (6).
Lemma 4.1**.**
We have an isomorphism of -algebras
[TABLE]
where and .
Proof.
By Corollary 3.9 we have an -linear exact sequence
[TABLE]
where is a map of degree and where is a map of degree [math] that is a map of -algebras.
The map is an isomorphism, so we can define to be the preimage of under . For we then have . In particular, we get .
For we have
[TABLE]
Hence,
[TABLE]
is an isomorphism. We define . In order to prove the lemma it now suffices to show that for . We have
[TABLE]
∎
We define .
Lemma 4.2**.**
We have an isomorphism of -algebras
[TABLE]
Proof.
We have a long exact sequence
[TABLE]
where is a map of -algebras. It suffices to show that is in the image of , or equivalently that . For this, we consider the commutative diagram
[TABLE]
To show , it suffices to prove that . This follows from . ∎
5. The mod homology of
In this section we study the mod homology of . We define to be the -adic valuation of . By [19, Lemma VIII.2.4] this is equal to the -adic valuation of . We distinguish the four different cases:
- (1)
and , 2. (2)
and , 3. (3)
and , 4. (4)
and .
The section is in part inspired by Hirata’s article [21] which treats the cohomology of algebraic -theory of finite fields and by Angeltveit’s and Rognes’ article [5] which treats the mod homology of in case (1).
Similarly to [21] we first split the image of the distinguished triangle (6) under into a wedge of distinguished triangles corresponding to the splitting of into a wedge of suspensions of the -completed connective Adams summand.
Let be a power of a prime (possibly different from ) such that is a generator of . We set
[TABLE]
Then, is a commutative -algebra model for the -completed connective Adams summand, [29, Proposition 9.2], [10, Section 2]. We define
[TABLE]
and claim that there is a weak equivalence of commutative -algebras : By Quillen’s computations [34, pp.583–585] one gets that is an isomorphism in -homotopy and therefore a weak equivalence. By [10] and since and are cofibrant commutative -algebras, we get a weak equivalence . The morphism , given by the inclusion of fields, induces the identification as a subring of . We have and as rings. Using the Tor and Ext spectral sequence one concludes that as -ring spectra. The maps
[TABLE]
for induce an isomorphism in :
[TABLE]
We get an isomorphism in which we denote by . We claim that the following diagram commutes in :
[TABLE]
Here, denoting by the inclusion and by the projection , for and is defined to be the unique map that is mapped to after composing with
[TABLE]
It suffices to show commutativity after composing with
[TABLE]
Commutativity then follows because identifies under with the map that is on the wedge summand and on the other wedge summands, and because by [1, Corollary 6.4.8] two self-maps of -completed connective complex -theory in the stable homotopy category are equal if and only if they induce the same maps on homotopy groups. Let be the fiber of . We get a morphism of distinguished triangles in
[TABLE]
which is an isomorphism by the five lemma.
Recall that the dual Steenrod algebra is an -Hopf algebra and that for the mod homology has a natural left -comodule structure [9, Theorem 1.1]. We use the letter to denote the -coactions. For the canonical map
[TABLE]
is an isomorphism of comodules [38, Theorem 17.8.vii]. We get that is an -comodule algebra if is an associative -ring spectrum. If and are associative -ring spectra then (7) is an isomorphism of comodule algebras. Recall that
[TABLE]
with and [5, Section 5.1]. Here, and are the generators defined in [30], and and are their images under the antipode of . We have
[TABLE]
where by convention . Since the coaction of is the comultiplication, has no non-trivial comodule primitives in positive degrees. Since is a connective, cofibrant commutative -algebra, we have a map in that is the identity on [18, Proposition IV.3.1]. The morphisms induce the maps
[TABLE]
in mod homology [5, Proposition 5.3]. Let be the image of under the Hurewicz map . Then, induces an isomorphism
[TABLE]
(see [6, Theorem 2.5]).
In the following we compute the mod homology of by computing the mod homology of the separately.
Lemma 5.1**.**
For with we have .
Proof.
For the map
[TABLE]
is the multiplication with on . We have and thus
[TABLE]
is not zero. Therefore, is a unit in . We get that is an isomorphism and that in . ∎
Recall that we defined .
Lemma 5.2**.**
For we have a short exact sequence
[TABLE]
Proof.
It suffices to show that is zero. From the homotopy of we deduce that
[TABLE]
Using that and the Tor spectral sequence we get that . It follows that is zero in degree . We show by induction that for all . Let and suppose that we already know that the claim is true for all . Let . Using the induction hypothesis one sees that is an -comodule primitive. Since it has degree , it has to be zero. ∎
Lemma 5.3**.**
Let . Then, we have a short exact sequence
[TABLE]
For the unique class that is mapped to is an -comodule primitive.
Proof.
Using that for -modules and whose homotopy is concentrated in degree zero, we get a map of distinguished triangles
[TABLE]
where . Thus, after applying , we get a map of long exact sequences. Since is additive, this shows the first part of the statement. Now, let . We have that
[TABLE]
is an isomorphism and that
[TABLE]
is zero. Let be the generator of that is mapped to under
[TABLE]
We can write the coaction of as for an element . Because of we have and therefore . ∎
Lemma 5.4**.**
We have
[TABLE]
Proof.
We have an exact sequence
[TABLE]
Therefore, we have . Recall that for an -connected -module one has a map realizing the identity on [36, Theorem II.4.13]. Using this we can inductively construct a Whitehead tower in :
[TABLE]
Here, the sequences are part of distinguished triangles
[TABLE]
Applying we get an unrolled exact couple and therefore a spectral sequence . Let be the -adic valuation of . Then, the -page of the spectral sequence is in column [math], in column for and zero in all other columns. We claim that the spectral sequence converges strongly to . Since is -connected, we have for . This implies that the spectral sequence converges conditionally to (see [12, Definition 5.10]). Because is finite in every bidegree, the spectral sequence converges strongly by [12, Theorem 7.1].
Since is compatible with the comodule action, the spectral sequence is a spectral sequence of -comodules.
It is clear that for . Let be a non-trivial class. In total degree the -page is a -dimensional -vector space generated by in column [math] and by in column . The class survives to the -page if and only if . The class survives to the -page if and only if for the class in column zero the equality holds. We can write for an element . Let denote the coaction of the -page. We have
[TABLE]
Suppose that . Then, we have and is an -comodule primitive by Lemma 5.3. It follows that and that .
Now, suppose . Then, is not primitive. If was zero, i.e. , the equation (8) would imply that . One would get , which is a contradiction. Therefore, we have . With equation (8) we get . We conclude that . ∎
Lemma 5.5**.**
For we have an exact sequence
[TABLE]
Proof.
By Lemma 5.4 we have an exact sequence
[TABLE]
We get that is zero. As in Lemma 5.2 it follows by induction that for all . ∎
For the following result is in [5, p.1265].
Lemma 5.6**.**
If we have an exact sequence
[TABLE]
where is given by .
Proof.
Because of the map
[TABLE]
is an isomorphism. Let be the unit in such that holds. We claim that the diagram
[TABLE]
is commutative, where is defined by
[TABLE]
It is clear that we have commutativity in degrees . For and we equip with the -coaction given by the coaction of . Then, all the maps in (9) are maps of -comodules. Since the difference of two maps of comodules is a map of comodules, it follows as in Lemma 5.2 that (9) is commutative. We have
[TABLE]
where the expression on the right means zero if . It follows that
[TABLE]
and
[TABLE]
We now consider case (1). In this case is a generator of and we can take in the definition of . The map factors through and the diagram
[TABLE]
is commutative in . Furthermore, the left vertical map in this diagram is an isomorphism by the proof of Lemma 5.1. We define to be the image of under . By Lemma 5.6 there are unique classes and that map to and under
[TABLE]
Recall from [16, Theorem III.1.1] that the mod homology of a commutative -algebra admits natural Dyer-Lashof operations
[TABLE]
For we recursively define
[TABLE]
Furthermore, we set
[TABLE]
for , where is the mod homology Bockstein homomorphism. We get by [5, Proposition 7.12]:
Proposition 5.7** (Angeltveit, Rognes).**
In case (1) the -algebra map
[TABLE]
is an isomorphism. The class is an -comodule primitive and we have
[TABLE]
The map maps , , and to , , and zero, respectively.
In the following lemma we use the -linearity of the distinguished triangle (6) to determine the multiplicative structure of in case (2) and (3). One could also use an argument similar to the one that Angeltveit and Rognes use in case (1).
Proposition 5.8**.**
In cases (2) and (3) there is an isomorphism of -algebras
[TABLE]
for certain classes , , and with the following properties:
- •
The degrees are , , and .
- •
The map maps to zero, to , to and to .
- •
For we have and .
- •
For the -coaction on we have:
[TABLE]
The classes and are comodule primitives.
Note that we have in case (2), so that .
Proof.
We have a commutative diagram with exact rows:
[TABLE]
The vertical maps are injections. We treat them as inclusions.
We set . We have that is zero in degree . Therefore, for there is a unique class such that . For we set . Since is zero in degree , there is a unique class with . The vector space is zero in degree . Thus, there is a unique class with . For we define recursively
[TABLE]
Furthermore, for we define . Since in the dual Steenrod algebra the analogous equations hold [5, pp.1244–1245], we get that and .
We have . Since is zero in degree it follows that . Thus, we get a map of graded commutative -algebras
[TABLE]
We claim that is an isomorphism. Given numbers , for and for that are almost all equal to zero, we have
[TABLE]
and
[TABLE]
Here, the second equality uses that is -linear. Thus, maps the canonical basis to a basis and is therefore an isomorphism.
It remains to study the comodule structure. We first recall some facts about the Steenrod algebra (see [30]): A basis of is given by
[TABLE]
where and . Here, denotes the Steenrod reduced th power and denotes the Bockstein. One has and is generated as an algebra by
[TABLE]
We have a right action of the Steenrod algebra on the mod homology of an -module (see [8, p.244]): For and with coaction the element is defined by
[TABLE]
Here, is considered as the -linear dual of and is the dual pairing. Note that because of , we have that and the mod homology Bockstein agree degreewise up to a unit.
To determine the comodule structure of we will compute for certain classes and . We will use that , and are linked via the Nishida relations (see [37, Section 6]). This allows to prove the formulas for and by an inductive argument.
It is clear that is a comodule primitive, because is compatible with the comodule action. For the class is obviously primitive. For we can write
[TABLE]
for an element . To show , we prove : The unit induces a map that commutes with the Bockstein. Because of the proof of Lemma 3.7 shows that the Bockstein maps to zero. Thus, it suffices to prove that maps to . Since is injective in degree , we only need to show that maps to . This follows from the commutativity of the diagram
[TABLE]
For degree reasons and because of we have
[TABLE]
for an element . Since and since , we get for degree reasons
[TABLE]
for certain . The classes lie in the degrees for . The classes lie in the degrees for . A basis of the Steenrod algebra in these degrees is given by
[TABLE]
To prove we show for and for . Because of we have . Since is one-dimensional, (11) implies that . By (10) we have
[TABLE]
Thus, and therefore . For the element lies in
[TABLE]
This implies that and therefore that . Because of we have
[TABLE]
Because of and and since and are one-dimensional in the degrees [math] and , this class also lies in . Using that
[TABLE]
one gets
[TABLE]
for certain . The elements
[TABLE]
lie in the degrees for . A basis of the Steenrod algebra in these degrees is given by
[TABLE]
Since for we get that . Therefore, we have proven the formulas
[TABLE]
for . We suppose that and that we have shown these formulas for . We can write
[TABLE]
for an element . In order to show it is enough to prove that
[TABLE]
for all . Since by the induction hypothesis
[TABLE]
for all , it suffices to show that , and for . We have . By the Nishida relations [37, Section 6] we have
[TABLE]
By the induction hypothesis we have for . Hence, the first sum is equal to
[TABLE]
This is zero, because we have which implies that by [16, Theorem III.1.1]. The summand
[TABLE]
in the second sum is zero if , because then the binomial coefficient is zero. If the summand is zero as well, because in this case . The equality is only possible if and . In this case the summand is equal to . Because of this is equal to by [16, Theorem III.1.1]. We now show for all . Because of this implies with the same argument as above the formula for the coaction of . By the Nishida relations we have
[TABLE]
Since by the induction hypothesis is zero for , this is equal to
[TABLE]
This is zero, because . ∎
Lemma 5.9**.**
We consider case (4). Suppose that . Then there is map of graded -algebras
[TABLE]
that is an isomorphism in degrees . Here, we have and .
Proof.
We have the following commutative diagram with exact rows:
[TABLE]
The middle vertical map is an isomorphism in degrees and we treat it as an inclusion. We define by and by the preimage of under . Since is zero in the degrees and , we have and . Hence, we have a map of -algebras
[TABLE]
In order to show that it is an isomorphism in degrees , it suffices to show that for and that for . For we have and hence . For we have
[TABLE]
by -linearity of . ∎
6. Computations with the Bökstedt spectral sequence
We first recall some facts about (topological) Hochschild homology and the Bökstedt spectral sequence. See [5, Section 2, 3 and 4] and [6, Section 3 and 4] for more details.
Let be a field, let be a graded-commutative -algebra and let be a graded-commutative -algebra. Then, the Hochschild homology of with coefficients in is the homology of the chain complex associated to the simplicial graded -vector space given by and the usual face and degeneracy maps. Here, note that we equip the category of graded -vector spaces with the symmetry , so that the last face map includes signs. We write for . We have that is an augmented -algebra, and if is flat over , then is a -bialgebra. The map defines a morphism that satisfies the derivation rule [6, p.1271].
Now, let be a commutative -algebra and let be a commutative -algebra. We implicitly assume that the necessary cofibrancy conditions are satisfied. The topological Hochschild homology of with coefficients in , denoted by , is the geometric realization of the simplicial -module . We have that is an augmented commutative -algebra. Moreover, in the stable homotopy category admits the structure of a -bialgebra. In the stable homotopy category there is a morphism . We denote the composition also by . The by induced map in mod homology satisfies the Leibniz rule [5, Proposition 5.10].
Recall that the Bökstedt spectral sequence is a a strongly convergent spectral sequence of the form
[TABLE]
The spectral sequence is an -comodule -algebra spectral sequence. We will use that the -comodule structure on the -page is induced by the following map on the Hochschild complex:
[TABLE]
Here, the second map is given by the symmetry (including signs) and the third map is given by the multiplication of . If is flat over , it is an -comodule -bialgebra. If each term is flat over , the Bökstedt spectral sequence is an -comodule -bialgebra spectral sequence, and if only the terms
[TABLE]
are flat over , then these are -comodule -bialgebras and the differentials respect this structure. We have that the edge homomorphism
[TABLE]
is the unit map. As a consequence one gets that the zeroth step of the filtration splits off from naturally. For we can therefore choose a natural representative in the first step of the filtration. For we have in [6, Proposition 4.4]. If is an arbitrary class (not necessarily of filtration degree ) and if there is no non-trivial class in the same total degree and lower filtration we will use the notation to denote the unique representative of in .
6.1. The first case
In this subsection we consider case (1). In this case Angeltveit and Rognes obtained the following result using the Bökstedt spectral sequence [5, Theorem 7.15]:
Theorem 6.1** (Angeltveit, Rognes).**
In case (1) we have an isomorphism of -algebras
[TABLE]
In Subsection 7.3 we apply the generalized Brun spectral sequence to compute the -homotopy of in case (1). For the calculation we need the following lemma:
Lemma 6.2**.**
In case (1) there is no non-trivial -comodule primitive in
[TABLE]
Proof.
We have an isomorphism of comodule algebras:
[TABLE]
Recall that with and and that contains no non-trivial comodule primitive in positive degree. This follows from the observation that we can map injectively into via the map of comodule algebras
[TABLE]
With Theorem 6.1 we get that an -basis of (H\mathbb{F}_{p})_{2p^{2}-1}\bigl{(}V(1)\wedge_{S}^{L}\operatorname{THH}(\operatorname{K})\bigr{)} is given by the classes
[TABLE]
By Proposition 5.7 the class is a comodule primitive and we have
[TABLE]
Let x\in(H\mathbb{F}_{p})_{2p^{2}-1}\bigl{(}V(1)\wedge_{S}^{L}\operatorname{THH}(\operatorname{K})\bigr{)} be a comodule primitive. We write
[TABLE]
with . The -coaction of and the -coaction of
[TABLE]
lie in
[TABLE]
Since this is not true for it follows that . The -coaction of and
[TABLE]
lie in
[TABLE]
Since is not primitive, this is not the case for . We get . Hence, we have
[TABLE]
The class has to be in the kernel of
[TABLE]
because there is no non-trivial comodule primitive in (H\mathbb{F}_{p})_{*}\bigl{(}V(1)\wedge_{S}^{L}\ell_{p}\bigr{)}\cong A_{*} in positive degree. By Proposition 5.7 the kernel is given by
[TABLE]
This implies . Since is a comodule primitive and is not primitive, is not primitive. We get and therefore . ∎
6.2. The second case
In this subsection we compute the -homotopy of in case (2). We first consider the Bökstedt spectral sequences converging to and . In this part we apply methods from [5] and [6]. Furthermore, we use the naturality of the Bökstedt spectral sequence with respect to the morphism and Ausoni’s results [6] about the Bökstedt spectral sequences for connective complex -theory. After computing we show that is a module over the -ring spectrum and we deduce the -homotopy of .
In this subsection we use the map
[TABLE]
to build . We denote by and the Bökstedt spectral sequences converging to and . We have a map of spectral sequences , which we denote by . We define
[TABLE]
Recall from [6, p.1283] that the map is given by , and . Using standard facts about Hochschild homology (see [5, Proposition 2.4], [6, Proposition 3.2]) we get the following: We have
[TABLE]
as a -algebra. Every is a coalgebra primitive. For the classes we have the following formula for the comultiplication:
[TABLE]
The class is represented in the Hochschild complex by the cycle . Since is primitive, is a comodule primitive. Because is a derivation we get that the classes are comodule primitives for and that the coactions on and are given by:
[TABLE]
Here, is the element of defined in Proposition 5.8. Recall from [6, Section 6] that
[TABLE]
where has the bidegree . For we have . Furthermore, we have for , and .
Lemma 6.3**.**
We have for .
Proof.
The -page is generated as a -algebra by
[TABLE]
Suppose that the spectral sequence has non-trivial differentials. Let be the minimal number such that and let be a class of minimal total degree in with . Because the classes , and lie in the first column they cannot support differentials. Thus, has filtration degree at least . Because the differential is compatible with the coalgebra structure has to be a coalgebra primitive [5, Proposition 4.8]. The -module of coalgebra primitives of is given by
[TABLE]
It follows that has filtration degree one. ∎
Lemma 6.4**.**
We have for all .
Proof.
We assume that there is an with . Let be minimal with this property. We must have for a . Since is a comodule primitive, is also a comodule primitive. Because of the minimality of it follows from the formula for that is a coalgebra primitive. The coalgebra primitives have filtration degree one. Therefore, we have . For degree reasons we get
[TABLE]
If the comodule primitives in this vector space are . If the comodule primitives are . Since the total degree of is different from the total degree of and from the total degree of we get a contradiction. ∎
Lemma 6.5**.**
We have for and and therefore
[TABLE]
Proof.
We first prove by induction on that . By [6, Lemma 6.6] we have for a unit . Because the kernel of
[TABLE]
is given by we get
[TABLE]
for a class of positive degree. By Lemma 6.4 every class in a total degree less than the total degree of has trivial -differential. This implies that is a comodule primitive. Therefore, has to be zero. Assume that we have proven the assertion for all . By comparing with the spectral sequence we get
[TABLE]
for a unit and a class of positive degree. We get
[TABLE]
On the other hand we can write
[TABLE]
for certain and certain whose internal degree is less than the internal degree of . This implies that
[TABLE]
By the induction hypothesis and by Lemma 6.4 we have
[TABLE]
for certain . It follows that . This proves the induction step.
We now fix . Suppose that and that we have already shown
[TABLE]
for all . Then by the induction hypothesis
[TABLE]
is a coalgebra primitive. Because it lies in a filtration degree , it has to be zero. This proves the induction step and therefore the lemma. ∎
Lemma 6.6**.**
We have for all . Therefore, we get
[TABLE]
Proof.
Suppose that the statement is wrong. Let be the minimal number with and let be the minimal number with . Then, is a comodule and coalgebra primitive in total degree . The coalgebra primitives are given by
[TABLE]
If the comodule primitives in this -vector space are
[TABLE]
If the comodule primitive are given by
[TABLE]
These classes all lie in total degrees different from . Thus, we get a contradiction. ∎
Recall from [6, Proposition 6.7] that we have
[TABLE]
For degree reasons has to be a coalgebra primitive.
Theorem 6.7**.**
In case (2) we have an isomorphism of -algebras
[TABLE]
Proof.
By [5, Proposition 5.9] we have . Since one gets as in [5, Theorem 5.12] or [6, Lemma 5.2] that for . We show by induction on that we can find a class
[TABLE]
that represents the class in and that has the property . We define . Then, we have . We claim that . For degree reasons we have . The comodule action of is given by
[TABLE]
Since the Steenrod algebra is one-dimensional in degree we have . On the other hand, we have
[TABLE]
by the Nishida relations. Hence, we can conclude . Suppose that and that we have already shown the assertion for all . It suffices to show that we can find a representative for that has the property that is a comodule and coalgebra primitive: Every non-trivial comodule and coalgebra primitive of gives a non-trivial comodule and coalgebra primitive in . By the proof of Lemma 6.6 the simultaneous coalgebra and comodule primitives of lie in the total degrees , , and for , which are all different from . By the induction hypothesis we have a map of -algebras
[TABLE]
which is injective and an isomorphism in degree . For a graded-commutative -algebra we denote by the homogeneous ideal of all elements with . The map
[TABLE]
is an isomorphism in degrees . Furthermore, the map
[TABLE]
and the map from
[TABLE]
to
[TABLE]
are isomorphisms. First, let be an arbitrary representative for . We can assume that it is in the kernel of the augmentation
[TABLE]
We consider its image under
[TABLE]
We have
[TABLE]
for certain with . Since lies in the kernel of the augmentation, we have . We show that for all that are not divisible by : The degree of every non-zero class in is divisible by . Thus, is zero in degree and we get . We have
[TABLE]
On the other hand, since is in we can write
[TABLE]
for certain with . It follows that
[TABLE]
for certain . Applying and using that by [6, Lemma 6.5] the relation holds in (H\mathbb{F}_{p})_{*}\operatorname{THH}\bigl{(}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p};H\mathbb{Z}_{p}), we get
[TABLE]
Let be a natural number that is not divisible by . In (12) the coefficient of is and in (13) it is zero. We get that . We conclude that we have
[TABLE]
where is zero for . The class lies in filtration . Thus, the element is also a representative for , it lies in the kernel of the augmentation and it satisfies
[TABLE]
We replace by and denote this class again by . Because the maps and are injective on the images of
[TABLE]
and
[TABLE]
in
[TABLE]
and
[TABLE]
now is a comodule and coalgebra primitive. ∎
We now study the Bökstedt spectral sequence converging to . Similarly as above, one sees that
[TABLE]
The classes are coalgebra primitives. For the classes we have the following formula for the comultiplication:
[TABLE]
For the classes are comodule primitives. All the classes are comodule primitives. The coactions on and are given by:
[TABLE]
Lemma 6.8**.**
For the differential vanishes. We have
[TABLE]
for all and
[TABLE]
for all and . Therefore, we get
[TABLE]
Proof.
By [5, Proposition 5.6] the differentials vanish for and we have
[TABLE]
The proof of Theorem 6.7 shows that . Using Proposition 5.8 we get
[TABLE]
Note that the coalgebra primitives of the -page are given by
[TABLE]
By induction on one proves that
[TABLE]
The induction step follows because the classes are coalgabra primitives in filtration degree . ∎
Lemma 6.9**.**
We have for all . Therefore, we have
[TABLE]
Proof.
This follows as in Lemma 6.6 noticing that the coalgebra primitives of the -page are given by
[TABLE]
and that the comodule primitives in this vector space are a subspace of
[TABLE]
∎
Theorem 6.10**.**
In case (2) we have an isomorphism of -algebras
[TABLE]
Proof.
As before one shows that for . We show by induction on that we can find representatives
[TABLE]
of such that . As in Theorem 6.7 one proves that the element satisfies . Assume that and that the assertion has been shown for all . It suffices to show that we can find a representative for such that is a comodule and coalgebra primitive: By Lemma 6.9 the simultaneous comodule and coalgebra primitives of lie in total degrees different from . First, let be an arbitrary representatives of that is in the kernel of the augmentation. Let be the map . We can write
[TABLE]
for certain with . Since lies in the kernel of the augmentation we have . Let be the element of that corresponds to under the canonical isomorphism
[TABLE]
Then is also a representative for that is in the kernel of the augmentation and it satisfies
[TABLE]
We denote this new representative again by . As in the proof of Theorem 6.7 one shows that is a comodule and coalgebra primitive. ∎
We want to deduce the -homotopy of in case (2). We do this by proving that in this case is a module in over the -ring spectrum . Note that this implies that it is isomorphic in to a coproduct of -modules of the form and that the Hurewicz morphism induces an isomorphism between and the comodule primitives in (H\mathbb{F}_{p})_{*}\bigl{(}V(1)\wedge_{S}^{L}\operatorname{THH}(\operatorname{K})\bigr{)}.
Remark 6.11**.**
Let be a morphism of commutative -algebras, and let and be -modules. Note that we have a map . We need that it has a compatible map of spectral sequences. Ext spectral sequences can be constructed by applying to a projective topological resolution of or by applying to an injective topological resolution of [23, Section 6]. Since in [23] conditional convergence is shown for the unrolled exact couples that are constructed from injective topological resolutions, we use these. Let be an -injective resolution. We consider a compatible injective topological resolution, i.e. fiber sequences
[TABLE]
in for such that and is a monomorphism, and such that we have isomorphisms under which corresponds to the augmentation and corresponds to . Analogously, we consider an -injective resolution and a compatible injective topological resolution in . Let be an -linear map of resolutions lifting the identity map of . Using that if is injective [23, Corollary 5.7], one inductively constructs compatible maps of fiber sequences in . Using the natural transformation we get a map of unrolled exact couples and therefore a map of spectral sequences. On -pages it is in bidegree for given by
[TABLE]
Now, let be an -projective resolution, let be an -projective resolution and let be an -linear chain map lifting the identity map of . Then, by comparing with the maps on total complexes given by
[TABLE]
one sees that the map on -pages is also induced by the maps
[TABLE]
Lemma 6.12**.**
In case (2) the -module is isomorphic in to an object in the image of the map
[TABLE]
induced by the inclusion of into the second smash factor of .
Proof.
Since we have with and
[TABLE]
we get a map that is the identity on and this is part of a distinguished triangle
[TABLE]
in . It now suffices to show that there is a that is mapped to under
[TABLE]
That is because then the image of the fiber of under is isomorphic to . We show that
[TABLE]
is an isomorphism. We have a free resolution of as an -module
[TABLE]
where
[TABLE]
and
[TABLE]
and where if and . We get
[TABLE]
We have a free resolution of as a -module
[TABLE]
where
[TABLE]
and
[TABLE]
and where if and . We get
[TABLE]
Furthermore, we have a -linear map of chain complexes
[TABLE]
with and . To prove this, it suffices to show that the Hurewicz map maps the element
[TABLE]
to . This follows from the commutativity of the diagram
[TABLE]
and from and .
Using Remark 6.11 we see that the map
[TABLE]
has a compatible map of spectral sequence that is an isomorphism on -pages in total degree zero. Since by [23, Theorem 6.7] and [12, Theorem 7.1] the spectral sequences converge strongly, the claim follows. ∎
Lemma 6.13**.**
In case (2) the -module is isomorphic in to an -module. The two -vector spaces and
[TABLE]
have the same dimension in every degree.
Proof.
We have that is a cell -module [18, Proposition III.4.1]. We therefore have an isomorphism in :
[TABLE]
By Lemma 6.12 the latter is isomorphic in to , where is an -bimodule and is a cell approximation of the -module . We get that is isomorphic in to an -module. As a consequence, we have
[TABLE]
where the are natural numbers such that for all the cardinality of
[TABLE]
is equal to the dimension of . On the other hand (H\mathbb{F}_{p})_{*}\bigl{(}V(1)\wedge_{S}^{L}\operatorname{THH}(\operatorname{K})\bigr{)} is isomorphic to
[TABLE]
This proves the lemma. ∎
Theorem 6.14**.**
In case (2) we have an isomorphism of -algebras
[TABLE]
with , , and .
Proof.
We compute the -comodule primitives in (H\mathbb{F}_{p})_{*}\bigl{(}V(1)\wedge_{S}^{L}\operatorname{THH}(\operatorname{K})\bigr{)}. Since we have that injects into the dual Steenrod algebra via a map of comodule algebras, we can assume that the -comodule action of is given by
[TABLE]
We define classes in (H\mathbb{F}_{p})_{*}\bigl{(}V(1)\wedge_{S}^{L}\operatorname{THH}(\operatorname{K})\bigr{)} by
[TABLE]
where is the element in that we defined in Proposition 5.8. Then, the -coaction of is given by
[TABLE]
and the classes , and are comodule primitives . Let be the classes defined in Theorem 6.10. We set
[TABLE]
The map of -algebras
[TABLE]
is an isomorphism, because it is surjective and both sides have the same dimension over in every degree. We treat it as the identity. Note that is a subcomodule algebra of (H\mathbb{F}_{p})_{*}\bigr{(}V(1)\wedge_{S}^{L}\operatorname{THH}(\operatorname{K})\bigl{)}, because
[TABLE]
for . It is isomorphic to . We show by induction on that we can find classes
[TABLE]
with the following properties:
- •
The class is a comodule primitive.
- •
We have .
- •
For the map
[TABLE]
is an isomorphism.
We set . Suppose that and that we have already defined for . The -vector space
[TABLE]
is included in the subspace of primitives in (H\mathbb{F}_{p})_{(2p-2)p^{i}}\bigl{(}V(1)\wedge_{S}^{L}\operatorname{THH}(\operatorname{K})\bigr{)}. By Lemma 6.13 we have
[TABLE]
Therefore, there is a class with . The class cannot be an element of
[TABLE]
because the comodule primitives in this vector space are the elements of . Therefore, we have
[TABLE]
for an . We have
[TABLE]
and
[TABLE]
The -algebra map , induced on these quotients by the coaction , is given by and
[TABLE]
Since is a comodule primitive, we get
[TABLE]
for a if , and
[TABLE]
if . We set if and if . Then has the desired properties. We get
[TABLE]
This finishes the proof. ∎
Remark 6.15**.**
The methods we used to compute in case (2) do not apply in the cases (1), (3) and (4):
In case (1) the object is not a module over the -ring spectrum : Suppose the contrary. Then, we would have
[TABLE]
This is a contradiction to Proposition 5.7.
In case (3) one can compute using the above methods. But since we have a tensor factor in , the Hochschild homology of is not flat over . The Bökstedt spectral sequence converging to therefore has no coalgebra structure.
In case (4) the mod homology of has a more complicated form and one needs different methods to compute its Hochschild homology.
7. Computations with the Brun spectral sequence
In [22] we have constructed a generalization of the spectral sequence of Brun in [15, Theorem 6.2.10]. We will refer to this generalization as the Brun spectral sequence. In this section we consider the Brun spectral sequence for . We pursue the same strategy that we used in [22] to compute , where is -completed connective complex -theory.
By [22, Theorem 4.11] and [22, Lemma 4.13] we have a Brun spectral sequence of the form
[TABLE]
which is multiplicative. Here, recall that since is a connective cofibrant commutative -algebra, we have a map of commutative -algebras realizing the identity on . We can compose this with the map induced by the ring homomorphism to get a map . We factor the map in as a cofibration followed by an acyclic fibration:
[TABLE]
Analogously to the case of in [22] we have an isomorphism of -ring spectra
[TABLE]
Again by [22, Theorem 4.11, Lemma 4.13] we have the Brun spectral sequence
[TABLE]
In Subsection 7.1 we will compute the ring , in Subsection 7.2 we will consider the spectral sequence (15), and finally in Subsection 7.3 we will consider the spectral sequence (14).
7.1. The mod homotopy of
In this subsection we will compute the graded -algebra .
Remark 7.1**.**
A tempting strategy to compute would be to use an Eilenberg-Moore type spectral sequence [18, Section IV.6]
[TABLE]
Such a spectral sequence would have to collapse at the -page and would yield
[TABLE]
with and . But this requires to be an -algebra. As in [4, Example 3.3] one can use that there is a -fold Massey product in defined with no indeterminacy to show that is no -algebra in case (1). We therefore cannot use the above strategy, but we still obtain (16).
Lemma 7.2**.**
We have a multiplicative spectral sequence of the form
[TABLE]
where
[TABLE]
Here, we use that is an -ring spectrum that is isomorphic to and that one therefore gets isomorphic -ring spectra by applying the lax symmetric monoidal functor .
Proof.
The canonical map in
[TABLE]
is an isomorphism of -ring spectra. The diagram
[TABLE]
is homotopy commutative in and therefore in the category of -modules [18, Proposition VII.2.11]. We get that the left-most -ring spectrum in (18) is isomorphic to , but where the -module structure of is now given by
[TABLE]
This is isomorphic as an -ring spectrum to . We have isomorphisms of commutative -algebras
[TABLE]
Since cofibrations are stable under cobase change, the map
[TABLE]
is a cofibration of commutative -algebras. Therefore, the canonical map
[TABLE]
in is an isomorphism of -ring spectra. Thus, we have an isomorphism of -ring spectra
[TABLE]
By [22, Remark 4.10] the latter -ring spectrum is isomorphic to
[TABLE]
Here, note that V(0)\wedge_{S}\bigl{(}\hat{H}\mathbb{Z}_{p}\wedge_{\operatorname{K}}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)} is an -ring spectrum and that we therefore get a -ring spectrum after applying the lax symmetric monoidal functor . By [9, Lemma 1.3] we get a multiplicative spectral sequence
[TABLE]
with B_{*}=\pi_{*}\Bigl{(}V(0)\wedge_{S}\bigl{(}\hat{H}\mathbb{Z}_{p}\wedge_{\operatorname{K}}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)}\Bigr{)}.
We have an isomorphism of -ring spectra
[TABLE]
Again by [22, Remark 4.10] this is isomorphic to as an -ring spectrum. The last three identifications are induced by maps under in . ∎
In the following lemmas we compute the -algebra .
Lemma 7.3**.**
We have
[TABLE]
Moreover, the map \pi_{*}(\operatorname{K}(\bar{\mathbb{F}}_{l})_{p})\to\pi_{*}\bigl{(}H\mathbb{F}_{p}\wedge_{\operatorname{K}}^{L}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)} factors as
[TABLE]
and P_{r}(u)\to\pi_{*}\bigl{(}H\mathbb{F}_{p}\wedge_{\operatorname{K}}^{L}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)} is an isomorphism in degrees .
Proof.
Define and . The -module map defines a map of -ring spectra. Applying to the distinguished triangle (6) we get a map between long exact sequences
[TABLE]
Using the spectral sequence one gets that is connective. Using that is concentrated in degree [math] the above long exact sequence yields
[TABLE]
and for . This shows the first part of the statement. We now show the second part of the statement: The map factors in as
[TABLE]
The map \pi_{*}\bigl{(}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)}\to\pi_{*}\bigl{(}Y\wedge_{\operatorname{K}}^{L}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)} identifies with the canonical map . Hence, it suffices to show that
[TABLE]
maps to zero and is an isomorphism in degrees . It is clear that it is an isomorphism in odd degrees, because in these degrees both sides are zero. It is also clear that it is an isomorphism in degree zero: In degree zero both sides are equal to , and the map is not zero because it is a map of rings and therefore maps the unit to the unit. We now suppose that is even and that we have already shown that is an isomorphism for all even . By Lemma 4.1 is zero. Therefore, diagram (19) is given by
[TABLE]
The right vertical map is an isomorphism by the induction hypothesis. Thus, the vertical map in the middle is also an isomorphism, and this map is . We conclude that is an isomorphism for all . We now consider diagram (19) for . Since by the proof of Lemma 4.1 the map \pi_{2r}(Y\wedge_{\operatorname{K}}^{L}\operatorname{K})\to\pi_{2r}\bigl{(}Y\wedge_{\operatorname{K}}^{L}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)} is an isomorphism, it is given by
[TABLE]
It follows that is zero. ∎
Let be the map
[TABLE]
where is the morphism in the distinguished triangle (6). Let be the map
[TABLE]
The following diagram commutes:
[TABLE]
To determine the multiplicative structure of \pi_{*}\bigl{(}H\mathbb{F}_{p}\wedge_{\operatorname{K}}^{L}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)} we need the following lemma:
Lemma 7.4**.**
Let a,b\in\pi_{*}\bigr{(}H\mathbb{F}_{p}\wedge_{\operatorname{K}}^{L}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigl{)}. The following equations hold:
[TABLE]
Proof.
Formula (21) follows from Lemma 3.10. Formula (22) follows from formula (21) by induction. ∎
Lemma 7.5**.**
There is an isomorphism of \pi_{*}\bigl{(}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)}-algebras
[TABLE]
where .
Proof.
By Lemma 7.3 the unit \pi_{*}\bigl{(}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)}\to\pi_{*}\bigl{(}H\mathbb{F}_{p}\wedge_{\operatorname{K}}^{L}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)} induces a map P_{r}(u)\to\pi_{*}\bigl{(}H\mathbb{F}_{p}\wedge_{\operatorname{K}}^{L}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)} that is an isomorphism in degrees . For choose a non-zero class
[TABLE]
By formula (22) we have
[TABLE]
Because of the commutativity of the diagram (20) the class G\bigl{(}\gamma_{p^{i}}(\sigma x)\bigr{)}^{p-1} is divisible by and is therefore zero. Since is injective in positive degrees by the proof of Lemma 7.3, it follows that is zero. We therefore have a well-defined map of -algebras
[TABLE]
We claim that it is an isomorphism. Since both sides are one-dimensional over in each even non-negative degree and zero in all other degrees, it suffices to show the following: For numbers and that are almost all zero, the classes
[TABLE]
are non-zero. We show this by induction on the degree of . If , we have for some and we already know that the claim is true. We now assume that and that we have already proven that all classes of the form (23) with degree less than are non-zero. Let be minimal with . We first consider the case . If the claim is true by definition of . If we write
[TABLE]
Since is injective in positive degrees, we know by the induction hypothesis that
[TABLE]
Since G\bigl{(}\gamma_{p^{k}}(\sigma x)\bigr{)}^{i} is divisible by for , we get
[TABLE]
By the induction hypothesis we know that this is non-zero. Thus, in this case. In the other cases we write
[TABLE]
By the induction hypothesis we know that is non-zero. Thus, we have
[TABLE]
Since G\bigr{(}\gamma_{p^{k+1}}(\sigma x)^{i_{k+1}}\cdots u^{j}\bigr{)} is divisible by , the third summand of the right side of (7.1) is zero. We consider the case . Then the first summand in (7.1) is zero, too. By the induction hypothesis is non-zero, and so we get
[TABLE]
and
[TABLE]
By the induction hypothesis this is non-zero and thus we get . We now consider the case . Let be minimal with . By the induction hypothesis we have
[TABLE]
Because of the second summand in (7.1) is zero. We get that
[TABLE]
By the induction hypothesis this is not zero. Thus, is non-zero. ∎
Lemma 7.5 implies the following:
Lemma 7.6**.**
We have an isomorphism of graded rings
[TABLE]
with and .
Proof.
The sequence
[TABLE]
is a free resolution of as a \pi_{*}\bigl{(}\operatorname{K}(\bar{\mathbb{F}}_{l})_{p}\bigr{)}-module. Thus, the -page of the spectral sequence (17) is the homology of
[TABLE]
which is
[TABLE]
in homological degree one and in homological degree zero. The spectral sequence has to collapse at the -page because the -page is concentrated in columns [math] and .
We denote the free resolution by . Let be the element in . The usual multiplication on
[TABLE]
defines a map of complexes
[TABLE]
that lifts the multiplication of . This implies that the -page is multiplicatively given by , where represents . Since lies in column zero, there are no multiplicative extensions. ∎
7.2. The algebra
In this subsection we consider the spectral sequence (15):
[TABLE]
By Bökstedt’s computations [13] and Lemma 7.6 we have
[TABLE]
with , , and . We will prove the following result:
Theorem 7.7**.**
In case (1) we have an isomorphism of rings
[TABLE]
In case (2) we have an isomorphism of rings
[TABLE]
In case (3) we have an isomorphism of rings
[TABLE]
In case (4) we have an isomorphism of rings
[TABLE]
at least if we assume .
In order to compute the differentials in the Brun spectral sequence (15) we need an additional spectral sequence:
Lemma 7.8**.**
Let be a morphism between cofibrant commutative -algebras. Then, there is a multiplicative spectral sequence of the form
[TABLE]
Proof.
This follows by using a method of Veen [39]. Writing one sees that as -ring spectra. ∎
Lemma 7.9**.**
In case (1) we have
[TABLE]
for .
Proof.
By Lemma 7.8 we have a spectral sequence of the form
[TABLE]
Using Proposition 5.7 one gets
[TABLE]
with . Obviously, this bigraded abelian group is zero in the total degrees . ∎
Lemma 7.10**.**
In case (1) the differentials of the spectral sequence (15) are given by
[TABLE]
We have
[TABLE]
There are no multiplicative extensions.
Proof.
The -page of (15) is multiplicatively generated by the classes , , and . The classes and are infinite cycles because they lie in column zero. For bidegree reasons the only possible differential on and are
[TABLE]
We conclude that for . If was zero, the class would be a permanent cycle. This would contradict the fact that we have
[TABLE]
by Lemma 7.9. Thus, we have and
[TABLE]
This algebra is generated by the classes , for , and . There cannot be any non-trivial differential on , because this class lies in column . Thus, the only possible differential on a generator is
[TABLE]
This differential must exist, because otherwise would survive to the -page, which would contradict Lemma 7.9. It follows that
[TABLE]
as -algebras. Now, the spectral sequence has to collapse: The class has total degree , and therefore its differentials have total degree . All non-trivial classes in an even degree lie in \Gamma\bigl{(}\gamma_{p}(\sigma x)\bigr{)}. Since the total degree of every class in \Gamma\bigl{(}\gamma_{p}(\sigma x)\bigr{)} is divisible by , it follows that is an infinite cycle. The class is an infinite cycle, too: The differentials of have total degree . There cannot be any differential
[TABLE]
for , because lies in column and lies in column . The classes in \mathbb{F}_{p}\{\sigma x^{p-1}\lambda_{1}\}\otimes\Gamma\bigl{(}\gamma_{p}(\sigma x)\bigr{)} have total degrees
[TABLE]
for . Since this is always modulo , and since is modulo , the spectral sequence collapses at the -page. Since \Gamma\bigl{(}\gamma_{p}(\sigma x)\bigr{)} lies in column zero, there cannot be any multiplicative extensions. ∎
Lemma 7.11**.**
In case (2) we have
[TABLE]
Proof.
As in case (1) we consider the spectral sequence
[TABLE]
Using Proposition 5.8, we obtain
[TABLE]
with . This bigraded abelian group is zero in total degree , and therefore we have
[TABLE]
It is zero in total degree , in total degree and in total degree . Since lies in column , it is an infinite cycle. Therefore, we get
[TABLE]
The -page is given by in total degree , by
[TABLE]
in total degree , by in total degree and by zero in total degree . Since lies in column , it is an infinite cycle and we get
[TABLE]
The classes and are also infinite cycles: For this is clear, because this class lies in column . For it follows since no differential of can hit , because both classes lie in column . We get
[TABLE]
∎
Lemma 7.12**.**
In case (2) the spectral sequence (15) has the differential
[TABLE]
We have
[TABLE]
There are no multiplicative extensions.
Proof.
As in case (1) the only possible differentials on the canonical algebra generators of the -page are
[TABLE]
Hence, we have for . The -page is given by in total degree . If there was a differential , the -page would be zero in total degree . This would contradict Lemma 7.11. Thus, we have . If was zero, the class would survive to the -page. This would contradict \dim_{\mathbb{F}_{p}}\bigl{(}V(0)_{2p}\operatorname{THH}(\operatorname{K},\hat{H}\mathbb{Z}_{p})\bigr{)}=0. Therefore, we get and
[TABLE]
The -page is given by
[TABLE]
in total degree and by in total degree . So, by Lemma 7.11, there cannot be any differentials on or . We conclude that
[TABLE]
∎
Lemma 7.13**.**
In case (3) we have
[TABLE]
There is a class
[TABLE]
and a class
[TABLE]
such that .
Proof.
As in the other cases we use the multiplicative spectral sequence
[TABLE]
Using Proposition 5.8 it follows that
[TABLE]
with . The -page is in total degree and
[TABLE]
in total degree . The classes , and are infinite cycles, because they are products of classes in column . This implies that
[TABLE]
The -page is in total degree given by if and by
[TABLE]
if . The differentials of cannot hit because lies in column and lies in a column . If the class lies in column . Since lies in column , its differentials cannot hit . Therefore, is a permanent cycle. ∎
Lemma 7.14**.**
In case (3) the spectral sequence (15) collapses at the -page and there are no multiplicative extensions.
Proof.
The only possible differentials on the canonical algebra generators of the -page are
[TABLE]
This implies that for . In total degree the -page is given by . Therefore, by Lemma 7.13, the differential cannot exist. Hence, we have . In total degree the -page is generated as an -vector space by , in total degree the -page is generated by . Because the classes have filtration degree zero, Lemma 7.13 implies that they survive to the -page and that in . Hence, we cannot have and the spectral sequence collapses at the -page. ∎
In case (4) the mod homology of is more complicated than in the other cases and we only consider the subcase . In order to be able to compute the -page of the spectral sequence
[TABLE]
in the necessary degrees we need a couple of lemmas. The statements are probably well-known, but since we did not find references, we include proofs.
Lemma 7.15**.**
Let be a homomorphism of non-negatively graded-commutative rings that is an isomorphism in degrees . Let and be non-negatively graded -modules. Then, we have
[TABLE]
for .
Proof.
We construct by induction a commutative diagram of graded -modules
[TABLE]
with the following properties:
- •
We have , and .
- •
The lines are exact.
- •
The are free non-negatively graded -modules for .
- •
The are free non-negatively graded -modules for and the lower line is a sequence of -modules.
- •
The maps are isomorphisms in degrees .
We start by defining , and . Let be the unique map . Let and suppose that we have constructed the diagram up to . We set
[TABLE]
and define to be the obvious map of -modules. Furthermore, we set
[TABLE]
and define to be the obvious map of -modules. Let be the map of -modules that is defined by
[TABLE]
It is then clear that
[TABLE]
is commutative. The map is an isomorphism in degrees . This is because by the induction hypothesis we know that induces a bijection
[TABLE]
and because is an isomorphism in degree . This shows the induction step. We have commutative diagrams
[TABLE]
where the vertical maps are induced by the - and -actions. The horizontal maps are isomorphism in degrees . We get maps on the coequalizers
[TABLE]
that are isomorphisms in degrees and that give a map of complexes. Since homology is taken degreewise this shows the claim. ∎
Lemma 7.16**.**
Let be a graded-commutative ring and let be a non-negatively graded -module. Let be a complex of graded -modules and let be a subcomplex with the following properties:
- (1)
If has total degree , then we have . 2. (2)
* is a direct summand of . *
Then, the map
[TABLE]
is an isomorphism in total degrees .
Proof.
Note that the maps
[TABLE]
are injective. Thus, is a subcomplex of . Moreover, every class in total degree lies in . The lemma now follows from the following fact: Let a subcomplex with the property that every class in total degree lies in , then the induced map
[TABLE]
is an isomorphism in total degrees . ∎
Lemma 7.17**.**
Let be a non-negatively graded-commutative ring and let be a graded -module. Suppose that we have a chain complex
[TABLE]
with the following properties:
- (1)
The are free graded -modules. 2. (2)
The map is surjective. 3. (3)
If has total degree , then we have .
Then there exists a free resolution such that is a subcomplex of with the properties (1) and (2) in Lemma 7.16.
Proof.
We define the resolution inductively. We define
[TABLE]
to be
[TABLE]
Suppose that and that we have already constructed an exact sequence
[TABLE]
such that:
- •
For we have
[TABLE]
for a set and natural numbers for with .
- •
The diagram
[TABLE]
commutes.
We define
[TABLE]
Here, means the internal degree of the element . Let be the map that is given by
[TABLE]
on and that maps to . Then, the sequence
[TABLE]
is exact: If and , then and we have by item (3). This shows the induction step. ∎
Lemma 7.18**.**
We consider case (4). If we have
[TABLE]
Proof.
As in the other cases we consider the spectral sequence
[TABLE]
By Lemma 5.9 we have a map
[TABLE]
that is an isomorphism in degrees . By Lemma 7.15 we have
[TABLE]
for . We set . We will construct a chain complex
[TABLE]
of free graded -modules with the following properties:
- •
The map is surjective.
- •
If has total degree , then we have .
By the Lemmas 7.16 and 7.17 we then have
[TABLE]
in total degrees and therefore in total degrees .
We set . Let be the -module map defined by . We define
[TABLE]
and . Note that then has to have bidegree and that has to have bidegree . Obviously,
[TABLE]
is exact. The kernel of is given by
[TABLE]
We set
[TABLE]
and define by , , , and . Then, the bidegrees of the generators of are given by , , , , and the sequence
[TABLE]
is exact. The -vector space
[TABLE]
is included in and contains every element in with total degree . We set
[TABLE]
and define by , , , , and . We then have , , , , , , the composition
[TABLE]
is zero and every class in with total degree is in the image of . The -vector space
[TABLE]
is included in the kernel of and contains every element in the kernel that has a total degree . For we set
[TABLE]
where the internal degrees of the generators are defined to be , , , and . We set , , , and . For the -vector space
[TABLE]
is included in and contains every class in that has total degree . This shows that for the following holds: The composition
[TABLE]
is zero and every element in with a total degree is in the image of .
The complex is given by
[TABLE]
Here, maps all generators to zero, except for . It maps to if and it maps to if . The bigraded abelian group is in total degree zero, in total degree given by , in total degree given by and in total degree given by . Thus, the same is true for the -page of the spectral sequence (26). The differentials of and cannot hit , because the homological degree of is greater as or equal to the homological degree of and . For the same reason has to be an infinite cycle. This proves the lemma. ∎
Lemma 7.19**.**
We consider case (4). If the spectral sequence (15) collapses at the -page. There are no multiplicative extensions.
Proof.
As in case (3) the only possible differentials on the canonical algebra generators of the -page are
[TABLE]
We conclude that for . The -page is in total degree given by . Therefore, by Lemma 7.18, the differential cannot exist and we get . In total degree the -page is given by
[TABLE]
Hence, by Lemma 7.18, the differential cannot exist and we conclude that the spectral sequence collapses at the -page. ∎
Remark 7.20**.**
It seems likely that Lemma 7.19 is also true for . However, the above proof does not work in this case, because some of the degree arguments require .
7.3. The -homotopy of \operatorname{THH}\bigl{(}\operatorname{K}(\mathbb{F}_{q})_{p}\bigr{)} in the first case
In this subsection we consider the spectral sequence (14)
[TABLE]
in case (1). By Lemma 4.2 and Theorem 7.7 we have
[TABLE]
with , , , and .
Theorem 7.21**.**
In case (1) the spectral sequence (14) has the differential
[TABLE]
We have
[TABLE]
where is the graded-commutative -algebra with generators , , , in degrees , , , and relations
[TABLE]
Proof.
Note that the spectral sequence only has two non-trivial lines, namely line zero which is
[TABLE]
and line which is
[TABLE]
We claim that the classes are infinite cycles for . We have
[TABLE]
for a class in in degree . Since has even degree it lies in
[TABLE]
Every class in this graded abelian group has a degree divisible by . Since is not divisible by , we get . The classes and are infinite cycles, because is trivial in degrees and in degree .
We claim that there is a differential . Since in total degree the th line of the -page is given by , it suffices to show that is not an infinite cycle. To prove this, we note that by [22, Lemma 3.15, proofs of Theorem 4.11 and Lemma 4.13] the edge homomorphism
[TABLE]
is induced by a map in . We therefore have a commutative diagram
[TABLE]
where the upper horizontal map is the edge homomorphism and where the vertical maps are the Hurewicz homomorphisms. We suppose that is an infinite cycle. Let be a representative of . We have . Since is a module over the -ring spectrum , the right Hurewicz homomorphism in (28) is injective. We get and therefore . This is a contradiction, because by [38, Corollary 17.14] the image of the Hurewicz morphism is always contained in the subspace of comodule primitives and because by Lemma 6.2 there is no non-trivial comodule primitive in
[TABLE]
We conclude that . We get
[TABLE]
and one easily sees that as an -vector space one has
[TABLE]
The th line of is therefore given by
[TABLE]
Thus, line is zero in total degrees divisible by . It follows that the classes , and have unique representatives , and in . The class has a unique representative because is zero in total degrees . The classes and also have unique representatives and because they lie in line . Since and in and since the total degrees of and are divisible by , we get and in . The equations , , , , and holds, because the corresponding equations in are true and because , , , and reduce to classes in lines . Hence, we have a map of -algebras
[TABLE]
Because of the relations (7.21) the classes , , . , and generate as an -vector space. Thus, maps a generating set bijectively onto a basis of and therefore is an isomorphism. ∎
We mention some ideas for the differentials of the spectral sequence (14) in the other cases:
Remark 7.22**.**
In case (2) the -page of the spectral sequence (14) is given by
[TABLE]
where the total degrees are , , , and . By our result obtained with the Bökstedt spectral sequence (Theorem 6.14), the spectral sequence has to collapse.
We now consider the cases (3) and (4). In case (4) we assume that . Then, the -page of the spectral sequence (14) is given by
[TABLE]
In case (3) we have the equation in . In case (4) we have the relations and in . It seems plausible that, analogous to the case of (see [22]), we get a differential
[TABLE]
in case (3) and differentials
[TABLE]
in case (4). In case (4) it seems plausible that there are additional differentials, similar to case (1).
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- 4[4] V. Angeltveit “Topological Hochschild homology and cohomology of A ∞ subscript 𝐴 A_{\infty} ring spectra” In Geometry & Topology 12.2 , 2008, pp. 987–1032
- 5[5] V. Angeltveit and J. Rognes “Hopf algebra structure on topological Hochschild homology” In Algebraic & Geometric Topology 5 , 2005, pp. 1223–1290
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