On the complexity of classes of uncountable structures: trees on $\aleph_1$
Sy-David Friedman, D\'aniel T. Soukup

TL;DR
This paper investigates the descriptive set-theoretic complexity of classes of special uncountable trees, establishing their completeness in the projective hierarchy under certain set-theoretic assumptions.
Contribution
It provides the first detailed analysis of the projective complexity of classes of Aronszajn, Suslin, and Kurepa trees, including completeness results and definable reductions.
Findings
Aronszajn and Suslin trees are $oldsymbol{ ext{Pi}}_1^1$-complete under $(V=L)$
Special Aronszajn trees are $oldsymbol{ ext{Sigma}}_1^1$-complete under $(V=L)$
Kurepa trees are $oldsymbol{ ext{Pi}}_2^1$-complete under $(V=L)$
Abstract
We analyse the complexity of the class of (special) Aronszajn, Suslin and Kurepa trees in the projective hierarchy of the higher Baire-space . First, we will show that none of these classes have the Baire property (unless they are empty). Moreover, under , (a) the class of Aronszajn and Suslin trees is -complete, (b) the class of special Aronszajn trees is -complete, and (c) the class of Kurepa trees is -complete. We achieve these results by finding nicely definable reductions that map subsets of to trees so that is in a given tree-class if and only if is stationary/non-stationary (depending on the class ). Finally, we present models of CH where these classes have lower projective complexity.
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On the complexity of classes of uncountable structures: trees on
Sy-David Friedman
Universität Wien, Kurt Gödel Research Center for Mathematical Logic, Wien, Austria
and
Dániel T. Soukup
Universität Wien, Kurt Gödel Research Center for Mathematical Logic, Wien, Austria
[email protected] http://www.logic.univie.ac.at/$\sim$soukupd73/
Abstract.
We analyse the complexity of the class of (special) Aronszajn, Suslin and Kurepa trees in the projective hierarchy of the higher Baire-space . First, we will show that none of these classes have the Baire property (unless they are empty). Moreover, under , (a) the class of Aronszajn and Suslin trees is -complete, (b) the class of special Aronszajn trees is -complete, and (c) the class of Kurepa trees is -complete. We achieve these results by finding nicely definable reductions that map subsets of to trees so that is in a given tree-class if and only if is stationary/non-stationary (depending on the class ). Finally, we present models of CH where these classes have lower projective complexity.
1. Introduction
We set out to investigate the complexity of certain well-studied classes of -trees on . In particular, under various set-theoretic assumptions, we determine the Borel/projective complexity of the class of Aronszajn, Suslin and Kurepa trees as a subset of the higher Baire space . In several cases, we prove the existence of nicely definable reductions between these tree classes and the stationary relation on . As the latter is -complete under , we get the parallel completeness of the tree classes. In the case of Kurepa-trees, we use a different coding argument.
The general setting of our paper is the higher Baire space111The name generalized Baire space is also commonly used. on and . Basic open sets correspond to countable partial functions which, in turn, give rise to a -Borel structure on , and so as well. This allows us to measure the complexity of subsets of or, equivalently, of families of natural combinatorial structures on . In this paper, we will focus on models of CH i.e., . This is a fairly natural assumption in this higher Baire setting which, in particular, ensures that has a basis of size . This, of course, is analogous to the standard Baire space having a countable basis.
Our primary interest lies in the set of -trees: partial orders on so that (1) the set of predecessors of each node is well-ordered,222This allows us to define a height function on and the levels of and (2) for any ordinal , the set of nodes of height is countable and non-empty if and empty otherwise.
Following [16], we will use to denote the class of trees without uncountable branches; so we allow trees with uncountable levels here. A tree in is called Aronszajn if is also an -tree (i.e., all levels are countable). We call a Suslin tree if it is an Aronszajn tree without uncountable antichains. On the other hand, an -tree is Kurepa if it has at least uncountable branches. We will denote the classes of these trees with , and , respectively. An Aronszajn tree is special if it is the union of countably many antichains. The latter collection will be denoted by . These are the main classes of trees we will be analyzing in detail. Let us refer the reader to the classical set theory textbooks [14, 11] and to [23] for a nice introduction to trees of height ; the latter survey emphasizes the connection of trees to topology and linear orders.
Recall that special Aronszajn trees exist in ZFC, however, even assuming the Continuum Hypothesis, and may be empty. In fact, as proved by R. Jensen, CH is consistent with [5] and so in this model.333We mention that does not imply the existence of Suslin-trees [19]. The consistency of no Kurepa trees was prove by Silver [21].
On the other hand, under (or just assuming strong enough diamonds), both Suslin and Kurepa-trees exist [11].
Let us present some results that will place our paper in the context of past research. Trees have played a significant role in the study of both the standard and higher Baire space [12, 16, 24, 6, 17]. Recall that the set of trees on without infinite branches is complete co-analytic. Analogously, a classical result from the theory of higher descriptive set theory is the following theorem of J. Väänänen.
Theorem 1.1**.**
[16]** CH implies that , the set of all trees on without uncountable branches, is -complete.
We mention that is if holds; indeed, implies that is exactly the set of special trees on [3] which is easily verified as a definition.
Yet another subclass of is the following: a canary tree is a tree of size continuum with no uncountable branches with the property that in any extension of the universe with , if a stationary set of is no longer stationary in then has an uncountable branch in . Now, canary trees give a simple definition for a subset of to be stationary.
Theorem 1.2**.**
[17, 10]** There is a Canary-tree iff , the set of all stationary subsets of , is . Moreover, the existence of Canary trees is independent of GCH.
If then there are no canary trees and in fact, the following polar opposite result holds which appears implicitly in [7].
Theorem 1.3**.**
[7]** If then is -complete.
We will use this theorem to show that certain classes of trees are complete in their complexity class. Finally, let us mention that there are strong connections between infinitary logic, trees and the complexity questions that our paper is concerned with [24, 20, 7]. We only included the results most relevant for our studies but we would like to refer the reader to the survey [24] and the book [8] for more details.
First, we will start by showing that non of the classes and have the Baire property and hence they are non Borel (unless and are empty, in which case they are trivially Borel). Moreover, we will prove the following results about the complexity of these classes:
Some of these results are easy consequences of known theorems (such as the results regarding the Abraham-Shelah model which we will describe shortly). However, the completeness of the classes under requires significant work and new ideas. We present the ZFC results and facts about the Abraham-Shelah model in Section 2. Then, in Section 3, we will show that stationarity can be reduced (in a Borel way) to the classes and . The results on will follow easily then. Finally, we deal with Kurepa-trees in Section 4. Note that under and , so the last line of Figure 2 follows by wrapping out the definitions.444In fact, in the latter model, all Aronszajn trees are club-isomorphic [25]. We end our paper with some remarks and open problems in Section 5.
1.1. Preliminaries
We defined the tree classes already but let us review the most important descriptive set theoretic notions that we need. The family of Borel sets in is the smallest family containing all open sets which is closed under taking complements and unions/intersections of size . It is easy to see that the set of -trees forms a Borel set with an appropriate coding of the order into a subset of .
Now, a subset of is (and called co-analytic) if there is an open so that if and only for all , . Complements of sets, denoted by , are called analytic sets. In Section 2, the reader can see elementary applications of this definition.
Finally, a subset of is complete for a complexity class iff and for any , there is a continuous so that if and only if . That is, no matter how we pick in , we can completely decide by our single fixed set and using an appropriate continuous map. In Section 3, we shall see this definition at work.
Let us also recall some classical guessing principles: asserts the existence of a sequence of countable sets so that for any , there is a club so that for any . In this situation, we say that witnesses .
We say that is a -oracle over if
- (1)
is an increasing sequence of countable elementary submodels of , 2. (2)
for all , and 3. (3)
witnesses .
Clearly, if holds then for any , there is a -oracle over . Also, recall that implies that and are non-empty [11].
For later reference, we state a few consistency results, the first being a now classical theorem of R. Jensen.
Theorem 1.4**.**
[5]** Consistently, CH holds and all Aronszajn-trees are special.
Jensen’s argument was built on an elaborate ccc forcing (in fact, a completely new iteration technique). A more mainstream proof of this theorem is due to S. Shelah [19] using countable support iteration of proper posets.
Given two trees , a club-embedding of into is an order preserving injection defined on , where is a club (closed and unbounded subset), with range in . A derived tree of is a level product of the form where the are distinct nodes from the same level of .555Here, . A fully Suslin tree is a Suslin tree with the property that all its derived trees are Suslin as well.
We will refer to the model in the next theorem as the Abraham-Shelah model.
Theorem 1.5**.**
[1]** Consistently, CH holds and there is a fully Suslin tree and special Aronszajn tree so that, for any Aronszajn tree , either
- (1)
* club-embeds into or* 2. (2)
there is a derived tree of that club-embeds into .
Moreover, there are only -many Suslin-trees modulo club-isomorphism.666It is an intriguing open problem if one can find a model with a single Suslin-tree (modulo club-isomorphism).
In essence, the above theorem says that any Aronszajn tree is either special or embeds a Suslin tree closely associated to .
Finally, the fact that there might be no Kurepa trees was proved by J. Silver in 1971.
Theorem 1.6**.**
[21]** If a strongly inaccessible cardinal is Lévy collapsed to then in the resulting model, there are no Kurepa trees.
1.2. Acknowledgments
The authors would like to thank the Austrian Science Fund (FWF) for the generous support through Grant I1921. The second author was also supported by NKFIH OTKA-113047.
2. Aronszajn and Suslin trees
To avoid some technicalities, let us restrict our attention to certain regular trees only from now on: those trees which are rooted, every node in has at least two immediate successors and is pruned i.e., for any of height and any above , there is some of height that extends . These are simple Borel conditions and we assume that our classes , and later consist of only regular trees.
Now, let us start the complexity analysis of these classes. Our first observation follows from the definitions immediately.
Observation 2.1**.**
- (1)
The set of all -trees on is Borel. 2. (2)
* and are both sets.* 3. (3)
* is .*
Proof.
The proof is a fairly standard exercise in descriptive set theory. To demonstrate the definitions, we prove that is and leave the rest to the interested reader. We need to find an open so that if and only for all , . Indeed, let denote the set of pairs so that is an -tree on and does not code an uncountable branch in . Now, is open in the product of codes for -trees (a Borel set) and . Indeed, if does not code an uncountable branch then either codes a countable branch in (i.e., there is a level of without any element of ) or codes two incomparable elements. Both cases can be witnessed by fixing a countable initial segment of and and hence, is open. Now, an -tree is Aronszajn if and only if for any , . ∎
So in models where e.g., in Jensen’s model of CH from Theorem 1.4, we get the following.
Corollary 2.2**.**
Consistently, CH holds and and so .777We remark here that implies so they are both however CH fails.
Our next goal is to show that none of the classes and are Borel, that is, unless in which case it is trivially Borel. We will apply the following well-known fact.
Lemma 2.3**.**
Suppose that are countable, rooted, binary branching, and pruned trees of height . Then and are isomorphic. In fact, any isomorphism with extends to an isomorphism .
The proof is an easy back-and-forth argument that we omit. This allows us to prove a new, relatively straightforward result.
Lemma 2.4**.**
Suppose that is a regular -tree and is somewhere co-meager in the set of all regular trees on . Then
- (1)
there is an isomorphic copy of in , and 2. (2)
* contains a tree with an uncountable branch.*
Proof.
(1) Suppose that where each is a nowhere dense set of trees. I.e., any countable tree has a countable end-extension so that any extension of into a tree on is not in . Here, denotes the (basic open) set of all trees extending .
Now, we construct an increasing sequence of countable trees and isomorphisms . Given , we look at . The latter is isomorphic to where witnessed by
[TABLE]
Define an end extension of of height by adding upper bounds to exactly those branches so that the chain has an upper bound in . Clearly, there is an isomorphism that extends . Now, let be an end-extension of which cannot be extended to a tree on that is in . This can be done since is nowhere dense. Finally, apply Lemma 2.3 to extend to some isomorphism .
This finishes the construction and the tree is as desired.
(2) Since there is a regular -tree which contains an uncountable branch, we can apply (1). ∎
We shall use the fact that any non-meager set with the Baire property is somewhere co-meager. The previous lemma and latter fact immediately yields the following corollaries.
Corollary 2.5**.**
- (1)
The isomorphism class of any regular -tree is everywhere non-meager. 2. (2)
Suppose that are non-isomorphic -trees. Then their isomorphism classes cannot be separated by sets with the Baire-property. 3. (3)
The set of trees isomorphic to a fixed tree without an uncountable branch is but does not have the Baire property and hence is not Borel. 4. (4)
The sets and do not have the Baire property. In turn, and are not Borel. 5. (5)
If then does not have the Baire property and so is not Borel. 6. (6)
If then does not have the Baire property and so is not Borel.
Proof.
(1) and (2) immediate from Lemma 2.4 (1).
(3) If such an isomorphism class has the Baire property then there is a somewhere co-meager set of trees all isomorphic to a fixed tree with no uncountable branch. This is not possible by Lemma 2.4 (2).
(4), (5) and (6) again follow from Lemma 2.4 (2): these classes are closed under isomorphism classes so must be everywhere non-meager. If they are Baire then they are somewhere comeager and hence contain a tree with an uncountable branch and also a special Aronszajn tree. This leads to a contradiction in case of any of these classes.
∎
So, whenever there is a Suslin tree then the set of all Suslin-trees is not Borel (but always ). Could it be analytic too? We show that this is independent (even assuming CH).
Proposition 2.6**.**
In the Abraham-Shelah model, and as well.
Proof.
Indeed, there are non-special Aronszajn trees (even Suslin-trees) and a tree is special if and only if it club-embeds no derived subtree of a fixed Suslin tree . Since there are only -many such derived subtrees, this gives and so (using Observation 2.1).
In the Abraham-Shelah model, there are only many Suslin trees modulo club isomorphism so fix a representative of each class and collect them as . Now, being Suslin is characterized by being club-isomorphic to some element of which in turn implies and as well (using again Observation 2.1). ∎
In the next section, we show that both and are -complete if we assume .
3. Reductions between subsets of and -trees
Our first theorem in this section establishes a continuous reduction between stationarity and in a strong form.
Theorem 3.1**.**
Suppose . There is a map from subsets of to the set of downward closed -subtrees of so that
- (1)
if then , 2. (2)
if is stationary then is Suslin, and 3. (3)
if is non-stationary then has an uncountable branch.
Note that by CH, has size so we can easily transform our trees to live on . So, we immediately get the following corollary by Theorem 1.3.
Corollary 3.2**.**
If then and are both -complete.
Let us proceed with the proof of the theorem.
Proof of Theorem 3.1.
Let is start by fixing a -oracle i.e., a sequence of elementary submodels of so that and witnesses .
Given , we construct the downward closed subtree level by level in an induction, so that for all . In each step, we shall add a new countable level to the tree constructed so far. In successor steps , we simply take the binary extension of .
Now, assume is a limit ordinal. If then we let
[TABLE]
In other words, we continue all branches through which are in . Since is countable, this is a valid extension and is defined in . Moreover, any has an extension in (i.e., the tree remains pruned).
Second, if then, working in , we make sure that
- (1)
any has an extension in , and 2. (2)
for any so that is a maximal antichain, any new element is above a node in .
Since is countable and , the level can be constructed in (just as in the classical construction of Suslin trees [14]).
This induction certainly defines an -tree for any . The next two claims will conclude the proof of the theorem.
Claim 3.3**.**
If is stationary then is Suslin.
Proof.
Suppose that is a maximal antichain. Since guesses at club many points, we can find some so that and is a maximal antichain in . So, at stage , we made sure that any is above some element of . In turn, we must have and so is countable.
∎
Claim 3.4**.**
If is non stationary then has an uncountable branch.
Proof.
There is some club that is disjoint from , and there is a club so that whenever . In particular, for any . Let be the increasing enumeration of .
We construct so that
- (1)
for all , 2. (2)
, and 3. (3)
is the -minimal element of that extends all elements in the chain .
In limit steps, note that . So the sequence is in too since it can be uniquely defined from . As , we sealed all branches that are in , so as well. In turn, .
∎
This proves the theorem. ∎
It would be interesting to see whether a single Suslin-tree suffices to construct such a reduction or if weaker reductions (say between stationarity and ) exist under weaker assumptions than .
Next, we present a variation that reduces non-stationarity to .
Theorem 3.5**.**
Suppose . There is a map from subsets of to the set of downward closed -subtrees of so that
- (1)
if then , 2. (2)
if is stationary then is Suslin, and 3. (3)
if is non-stationary then is a special Aronszajn tree.
Proof.
The idea is very similar: we build level by level and aim for a Suslin tree at stages . However, if then we shall try to make special. In fact, we will add the new level so that any nice enough monotone map that is also in has an extension to . We will need to make sure that any new node at level works simultaneously for all such specializing maps which inspires the definition of a specializing pair below. Intuitively, we not just assign a rational number to a tree node but also a promise (in the form of a positive number ) to keep all values close to whenever is above . The details follow below.
Fix a -oracle . Given , we construct the downward closed subtree so that for all . If is successor or if then, working in , we repeat the construction in the previour theorem. We make sure that
- (1)
any has an extension in , and 2. (2)
for any so that is a maximal antichain, any new element is above a node in .
This will certainly make sure that is Suslin whenever is stationary. Let us turn to the construction when is a limit ordinal from .
First, a new definition. Given any tree of height , we say that is a specializing pair on if
- (i)
is monotone (in particular, is special), 2. (ii)
if then , and 3. (iii)
if , and then there is some above so that
[TABLE]
Our first goal is the following: given a countable tree of limit height and a countable family of specializing pairs for , we show that there is a cofinal branch through so that any can be extended to .
Lemma 3.6**.**
Suppose that is a countable tree of limit height and is a countable family of specializing pairs for . Fix some , and . Then there is a cofinal, downward closed branch containing so that
[TABLE]
and for any and ,
[TABLE]
Indeed, if the lemma holds and we set and define for then still satisfies (i) and (ii) from the definition of a specializing pair on the extra node . Moreover, if we set then for this particular and , we made sure that condition (iii) for is witnessed by . By repeating the procedure of Lemma 3.6 for all the elements of with all possible rational , we get the following.
Lemma 3.7**.**
Suppose that is a countable tree of limit height and is a countable family of specializing pairs for . Then has a pruned end-extension of height so that any has an extension that is a specializing pair on .
Proof of Lemma 3.6.
Given and , let . This measures how much slack we have after jumping from to . List all and as , each infinitely often. We define so that for some fixed cofinal sequence in . First, we pick so that
[TABLE]
and
[TABLE]
This can be done by (iii). Moreover, note that no matter how we pick above , we will always have and so for any cofinal branch above ,
[TABLE]
by the triangle inequality.
Given , we pick as follows: look at and assume (if the latter fails, pick arbitrarily). Now, look at and pick so that
[TABLE]
and
[TABLE]
where . This is again possible by (iii). As before, for any above , we will always have and so for any cofinal branch above ,
[TABLE]
by the triangle inequality and unwrapping the definition of .
The final branch is given by the downward closure of . Since any and specializing pair was considered infinitely often during the construction, we clearly satisfied the requirements.
∎
Finally, we can describe what happens in the construction of at limit steps . Working in , we consider the tree and is a specializing pair for . Now, applying Lemma 3.7, we add a new level to so that any specializing pair from extends to .
This ends the construction of and we are left to prove the following.
Claim 3.8**.**
If is non-stationary then is a special Aronszajn tree.
Proof.
In fact, we prove that has a specializing pair. By our assumption on , we can find a club so that for any , . Let be the increasing enumeration of and we define an for so that
- (1)
is a specializing pair on uniquely definable from , 2. (2)
for , extends .
As before, has all the information to reconstruct the sequence and so
[TABLE]
Since , we made sure that this specializing pair has an extension to level which gives . ∎
∎
Corollary 3.9**.**
If then is -complete.
4. Kurepa trees
Our goal in this section is to show the following.
Theorem 4.1**.**
* The set of all Kurepa trees is -complete.*
We prove the above result through a series of lemmas. First, we will build on the following representation of sets.
Lemma 4.2**.**
If is a subset of then for some formula and some parameter , the following are equivalent
- (1)
, 2. (2)
.
Proof.
Since is , we can find a Borel set so that is in if and only if
[TABLE]
Let be a bijection which is over and choose a formula with parameter in so that if and only if .
Then if and only if
[TABLE]
Let be the formula
[TABLE]
Then (4.1) (and so as well) is equivalent to
[TABLE]
as desired. ∎
Fix some with corresponding formula and parameter . First, note that
[TABLE]
Our plan is to form an -tree consisting of triples from which resemble a triple from with . Distinct uncountable branches in the tree will correspond to distinct triples . In turn, whether has many branches (i.e., if is Kurepa) will characterize whether . This will prove that is -complete.
We will say that a triple from is good (with respect to and ) if
- (1)
, 2. (2)
, 3. (3)
is the least limit ordinal so that
- (a)
, 2. (b)
, 3. (c)
.
Note that ; in case of equality, and . If then as well by (2).
The next claim should be clear from the minimality of .
Claim 4.3**.**
If is good then the Skolem hull of in is all of .
Next, we define an ordering on good triples: we write
[TABLE]
if and there is a (unique) elementary embedding
[TABLE]
so that
- (1)
is the identity, 2. (2)
, 3. (3)
, and 4. (4)
Note that is the transitive closure of in . In turn, for a given good triple and , there is so that iff for the above hull , .
Let us summarize the basic properties of the relation .
Claim 4.4**.**
- (1)
The relation is transitive.
Moreover, for any good triple ,
- (2)
for any , there is at most one choice of so that ; 2. (3)
the set
[TABLE]
is closed in .
Claim 4.5**.**
The relation is a tree order on good triples.
Proof.
Suppose that we are given good triples for so that
[TABLE]
If then ; indeed, this follows from the Claim 4.4. So we can assume . Now, if witnesses that for then witnesses .
∎
For some technical reasons, instead of taking the tree of good triples, we will look at functions associated to good triples and the tree formed by them. For each good triple , define a function with domain as follows:
[TABLE]
This is well-defined by Claim 4.4.
Claim 4.6**.**
For any , .
Proof.
This follows immediately from the fact that is a tree order. ∎
We let be the set of function where is a good triple (with respect to ) of countable ordinals and .
Claim 4.7**.**
* is a tree of height at most and countable levels.*
Proof.
We prove that every level of is countable by induction. Elements of at level are of the form . These functions either satisfy (i) or (ii) . In case (i), must be constant 0 on an end-segment of and so is completely determined by the previous levels so by induction, there are only countably many choices for . In case (ii), we note that by Claim 4.6. Finally, note that there are only countably many possibilites for the value of since for any large enough , This proves that level of must be countable.
∎
The next lemma will conlcude the proof of the theorem.
Claim 4.8**.**
* has uncountable branches if and only if the set*
[TABLE]
Proof.
First, assume that for some . Pick the minimal so that and so is a good triple with respect to .
Subclaim 4.8.1**.**
* is an uncountable branch in .*
Moreover, the branch uniquely determines the triple by the following claim.
Subclaim 4.8.2**.**
* is the direct limit of for .*
Thus distinct good triples correspond to different branches in .
Conversely, suppose that we have a branch in , which is not eventually 0. Now, the direct limit of the for yields some and a good triple . Moreover, is the restriction of . Distinct -branches yield distinct triples and since is uniquely determined by , we get -many such that holds in .
∎
5. Open problems and future goals
A positive answer to the following question would show that there are no ZFC reductions between stationarity and .
Question 5.1**.**
Is it consistent with CH that all Aronszajn trees are special and there are no Canary trees?
Regarding Kurepa-trees, the following remains open.
Question 5.2**.**
Can be and nonempty?
Question 5.3**.**
What is the complexity of under (given such trees exist)?
The following would also be very interesting.
Question 5.4**.**
Find a natural class of structures in or which is not complete for its complexity class.
The reason we ask for a natural class is that under , one can build such artificial examples (and for inaccessible cardinals there are even natural examples) but we wonder if there are more combinatorial examples on . Also, Harrington proved that consistently no such intermediate classes exist.
Yet another axiom to consider in more detail is for coherent Suslin-trees (see e.g., [22]). Such models allow the existence of Suslin-trees while share many properties with models of the proper forcing axiom.
Question 5.5**.**
How does affect the complexity of the classes and ?
Once we force with the Suslin tree over a model of , the resulting extension has no Suslin trees any more and in fact, any two Aronszajn trees will be club-isomorphic [25]. In turn, the complexity of and is as mentioned in Figure 2.
It would certainly be interesting to see to what extent our results generalise to higher cardinals above . In particular, we mention a recent result of Krueger [13] on the club-isomorphism of higher Aronszajn trees that could substitute the Abraham-Shelah model. The construction schemes developed by Brodsky, Lambie-Hanson and Rinot [4, 18, 15] for higher Suslin and Aronszajn trees also seems rather relevant. The theorem of Jensen on CH and all Aronszajn trees being special was recently generalized to higher cardinals in a breakthrough result by Asperó and Golshani [2]. Definability of on successor cardinals was investigated by Friedman, Wu and Zdomskyy [9].
We believe that a similar analysis of other classes of structures on is well worth exploring. To name the most natural candidates, we would be interested in the following:
- (1)
Graphs and more generally colourings with . One might look at graphs with chromatic or colouring number ; or strong colourings that witness the failure of square bracket relations (i.e., ). Hypergraphs and various set-systems are also natural candidates. 2. (2)
Ladder systems on . Natural classes are ladder systems with various guessing properties (i.e., sequences or club guessing sequences); and ladder systems with or without the uniformization property. 3. (3)
Linear orders on . For Aronszajn and Suslin-lines, our analysis most likely yields the appropriate complexities but we did not address the important class of Countryman lines. 4. (4)
Forcing notions. We can consider various classes of forcing posets on such as ccc, Knaster, -centered, -linked or proper partial orders.
Finally, it will be very natural to consider the classical equivalence relations on these classes and to find Borel definable reductions between them. To mention a few, we name the order isomorphism of trees and linear orders; the notion of club-isomorphism between trees; graph isomorphism; bi-embeddability of various structures; or forcing equivalence of posets.
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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