Non-radial solutions to a bi-harmonic equation with negative exponent
Ali Hyder, Juncheng Wei

TL;DR
This paper establishes the existence of non-radial entire solutions to a specific bi-harmonic equation with a negative exponent in three-dimensional space, addressing an open question in the field.
Contribution
It proves the existence of non-radial solutions to a bi-harmonic PDE with negative exponent, solving an open problem posed by McKenna and Reichel.
Findings
Existence of non-radial solutions for q>1
Answers an open question in PDE theory
Extends understanding of bi-harmonic equations with negative exponents
Abstract
We prove the existence of non-radial entire solution to for . This answers an open question raised by P. J. McKenna and W. Reichel (E. J. D. E. \textbf{37} (2003) 1-13).
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Taxonomy
TopicsNonlinear Partial Differential Equations · Nonlinear Differential Equations Analysis · Advanced Mathematical Modeling in Engineering
Non-radial solutions to a bi-harmonic equation with negative exponent
Ali Hyder
Department of Mathematics, University of British Columbia, Vancouver BC V6T1Z2, Canada
[email protected] The author is supported by the Swiss National Science Foundation, Grant No. P2BSP2-172064
Juncheng Wei
Department of Mathematics, University of British Columbia, Vancouver BC V6T1Z2, Canada
[email protected] The research is partially supported by NSERC
Abstract
We prove the existence of non-radial entire solution to
[TABLE]
for . This answers an open question raised by P. J. McKenna and W. Reichel (E. J. D. E. 37 (2003) 1-13).
1 Introduction
We consider the following bi-harmonic equation with negative exponent
[TABLE]
where .
For , problem (1) can be seen as a fourth order analog of the Yamabe equation (see [1, 5, 21]), namely
[TABLE]
In the recent past, radial solutions to equation (1) have been studied by many authors, especially the existence and asymptotic behavior:
Theorem A
- i)
There is no entire solution to (1) for .
- ii)
If has exact linear growth at infinity, that is,
[TABLE]
then . Moreover, for , is given by , and is unique up to dilation and translations.
- iii)
For there exists radial solution with exact linear growth.
- iv)
For there exists radial solution with exact quadratic growth, that is,
[TABLE]
- v)
For there exists a radial solution such that as (the constant is explicitly known).
- vi)
For there exists a radial solution such that as .
It has been shown by Choi-Xu [5] that if is a solution to (1) with , and has exact linear growth at infinity then satisfies the integral equation
[TABLE]
for some , and if and only if . In fact, every positive solution to
[TABLE]
with exact linear growth at infinity satisfies
[TABLE]
where is a dimensional constant, see [7], [17]. For the classification of solutions to the above integral equation we refer the reader to [12], [20].
In [16] McKenna-Reichel proved the existence of non-radial solution to
[TABLE]
for . This was a simple consequence of their existence results to (4) in lower dimension. More precisely, if is a radial solution to (4) with then is a non-radial solution to in , where . Then they asked whether in non-radial positive entire solution exist. (See [Open Questions (1), [16]].)
We answer this question affirmatively. (See Theorem 1.2 below.) In fact we prove the following theorems.
Theorem 1.1
Let be a solution to (1) for some . Assume that
[TABLE]
Then, up to a rotation and translation, we have
[TABLE]
where
[TABLE]
Theorem 1.2
Let . Then for every there exists a non-radial solution to (1) such that
[TABLE]
Theorem 1.3
Let . Then for every there exists a non-radial solution to (1) such that
[TABLE]
The non-radial solutions constructed in Theorem 1.2 also satisfies the following integral condition
[TABLE]
for . Note that McKenna-Reichel’s non-radial example has infinite bound: .
The existence of infinitely many entire non-radial solutions with different growth rates for the conformally invariant equation in is in striking contrast to other conformally invariant equations in , and in . In both cases all solutions are radially symmetric with respect to some point in , see [2], [4], [13] and [18].
Our motivation in the proof of Theorems 1.2-1.3 come from a similar phenomena exhibited in the following equation
[TABLE]
It has been proved that for problem (9) admits non-radial entire solutions with polynomial growth at infinity, see [3], [9], [10], [14], [15], [19] and the references therein. It is surprising to see that conformally invariant equations with negative powers share similar phenomena.
In the remaining part of the paper we prove Theorems 1.1-1.3 respectively. We also give a new proof of - of Theorem A, see sub-section 2.1.
2 Proof of the theorems
We begin by proving Theorem 1.1.
Proof of Theorem 1.1 Let be a solution to (1)-(5). We set
[TABLE]
Fixing and so that
[TABLE]
one gets
[TABLE]
Using that , form (10), we obtain
[TABLE]
Combining these estimates we deduce that
[TABLE]
It follows that satisfies
[TABLE]
and hence, is a polynomial of degree at most , see for instance [14, Theorem 5]. Indeed, up to a rotation and translation, we can write
[TABLE]
where are two disjoint (possibly empty) subsets of , for , for and . Therefore, up to a rotation and translation, we have
[TABLE]
Now and lead to for , for and .
In order to prove that we assume by contradiction that for some . Up to relabelling we may assume that . Then
[TABLE]
a contradiction to (5).
We conclude the proof.
Now we move on to the existence results. We look for solutions to (1) of the form where is a polynomial of degree . Notice that satisfies (1) if and only if satisfies
[TABLE]
In particular, if , and satisfies the integral equation
[TABLE]
then satisfies (11). Thus, we only need to find solutions to (12) (or a variant of it), and we shall do that by a fixed point argument. Let us first define the spaces on which we shall work:
[TABLE]
[TABLE]
[TABLE]
The following proposition is crucial in proving Theorem 1.2.
Proposition 2.1
Let be a positive function on such that and for some
[TABLE]
Then there exists a function satisfying ,
[TABLE]
and
[TABLE]
Moreover, if is radially symmetric then there exists a solution to (13) in .
Proof.
Let us define an operator , , (In case is radial we restrict the operator on . Notice that .) where
[TABLE]
We proceed by steps.
Step 1 is compact.
Using that we bound
[TABLE]
Differentiating under the integral sign one gets
[TABLE]
We let be a sequence in . Then is bounded in . Moreover, up to a subsequence, for some with , we have
[TABLE]
We rewrite (14) (with and ) as
[TABLE]
It follows that
[TABLE]
Using that we bound
[TABLE]
This implies that
[TABLE]
Since
[TABLE]
up to a subsequence,
[TABLE]
for some . This proves Step 1 as is continuous.
Step 2 has a fixed point in .
It follows form (15) that there exists such that . In particular, . Hence, by Schauder fixed point theorem there exists a fixed point of in .
Step 3
Step 3 follows from
[TABLE]
Step 4 If is a fixed point of then .
Differentiating under the integral sign, from (14) one can show that the hessian is strictly positive definite, and hence is strictly convex. Moreover, using that is an even function, one obtains . This leads to
[TABLE]
We conclude the proposition. ∎
In the same spirit one can prove the following proposition.
Proposition 2.2
Let be a positive even function on such that for some
[TABLE]
Then there exists a positive function satisfying
[TABLE]
Proof of Theorem 1.2 Let and be fixed. For every let be a solution of (13), that is,
[TABLE]
where
[TABLE]
We claim that for every multi-index with
[TABLE]
where
[TABLE]
For , differentiating under the integral sign, from (17), we obtain
[TABLE]
where
[TABLE]
Since we have on . For we bound
[TABLE]
[TABLE]
[TABLE]
This proves (18). Since , by (18), we have
[TABLE]
Therefore, for some we must have in for some in , where satisfies
[TABLE]
Hence, is a solution to (1). Moreover, as satisfies (22), we have
[TABLE]
This completes the proof.
Proof of Theorem 1.3 Let be fixed. Then for every there exists a positive solution to (16) with
[TABLE]
Setting one gets
[TABLE]
Since for , from (26), one obtains
[TABLE]
which implies that , that is, . Therefore, by (23)
[TABLE]
Hence, differentiating under the integral sign, from (23)
[TABLE]
Thus, is bounded in . This yields
[TABLE]
for some . Using this, and recalling that , we deduce
[TABLE]
Therefore, for some , we have , where satisfies
[TABLE]
We conclude the proof.
2.1 A new proof of - of Theorem A
Proof of Let be fixed. Then by Proposition 2.1, for every , there exists a radial function satisfying
[TABLE]
Since is radially symmetric, one has (see Eq. (3.3) in [5])
[TABLE]
for some . Therefore, as
[TABLE]
which gives
[TABLE]
As , one would get
[TABLE]
Thus, the family is bounded in . Hence, for some we have where satisfies
[TABLE]
Finally, as before, we have
[TABLE]
This completes the proof of .
Proof of Let be fixed. Then by Proposition 2.1, for every , there exists a non-negative radial function satisfying
[TABLE]
The rest of the proof is similar to that of Theorem 1.2.
In the spirit of [5, Lemma 4.9] we prove the following Pohozaev type identity.
Lemma 2.3** **(Pohozaev identity)
Let be a positive solution to
[TABLE]
for some non-negative polynomial of degree at most and . Then
[TABLE]
Proof.
Differentiating under the integral sign, from (25)
[TABLE]
Multiplying the above identity by and integrating on
[TABLE]
Integration by parts yields
[TABLE]
Since and for some and large
[TABLE]
Writing , and setting
[TABLE]
we get
[TABLE]
Notice that . Hence,
[TABLE]
and
[TABLE]
where the last equality follows from . Combining these estimates and taking in (27) one gets (26). ∎
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