On the unordered configuration space C(RP^n,2)
Donald M. Davis

TL;DR
This paper investigates the embedding and immersion properties of the unordered configuration space of two points in real projective space, providing optimal bounds and cohomological insights, especially when n is a power of two.
Contribution
It establishes new optimal bounds for immersions and embeddings of C(RP^n,2) and offers a novel description of the mod-2 cohomology algebra of G_{n+1,2}.
Findings
C(RP^n,2) cannot be immersed in R^{4n-2} when n is a 2-power.
C(RP^n,2) can be immersed in R^{4n-3} when n is not a 2-power.
Cohomological lower bounds for topological complexity are nearly optimal for 2-power n.
Abstract
We prove that, if n is a 2-power, the unordered configuration space C(RP^n,2) cannot be immersed in R^{4n-2} nor embedded as a closed subspace of R^{4n-1}, optimal results, while if n is not a 2-power, C(RP^n,2) can be immersed in R^{4n-3}. We also obtain cohomological lower bounds for the topological complexity of C(RP^n,2), which are nearly optimal when n is a 2-power. We also give a new description of the mod-2 cohomology algebra of the Grassmann manifold G_{n+1,2}.
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On the unordered configuration space
Donald M. Davis
Department of Mathematics, Lehigh University
Bethlehem, PA 18015, USA
(Date: May 24, 2019)
Abstract.
We prove that, if is a 2-power, the unordered configuration space cannot be immersed in nor embedded as a closed subspace of , optimal results, while if is not a 2-power, can be immersed in . We also obtain cohomological lower bounds for the topological complexity of , which are nearly optimal when is a 2-power. We also give a new description of the mod-2 cohomology algebra of the Grassmann manifold .
Key words and phrases:
configuration space, immersions, topological complexity, Grassmann manifold
2000 Mathematics Subject Classification: 55R80, 57R42, 55M30, 55S15.
1. Nonimmersions, nonembeddings, and immersions of
If is an -manifold, the unordered configuration space of two points in , , is a noncompact -manifold, and hence can be immersed in ([17]) and embedded as a closed subspace of .([7]) We prove the following optimal nonimmersion and nonembedding theorem for when is a 2-power. Here denotes -dimensional real projective space.
Theorem 1.1**.**
If is a -power, cannot be immersed in nor embedded as a closed subspace of .
This will be accomplished by showing that the Stiefel-Whiney class of its stable normal bundle is nonzero. The implication for embeddings of noncompact manifolds, which is not so well-known as that for immersions, is proved in [12, Cor 11.4].
For contrast, we prove the following immersion theorem.
Theorem 1.2**.**
If is not a -power, then can be immersed in .
This work was motivated by a question of Mike Harrison. In [10], he introduces the notion of totally nonparallel immersions and proves that if a manifold admits a totally nonparallel immersion in , then immerses in . Thus we obtain a result about nonexistence of totally nonparallel immersions of 2-power real projective spaces.
Proof of Theorem 1.1.
We denote , which we think of as the space of unordered pairs of distinct lines through the origin in . Also, denotes the subspace consisting of unordered pairs of orthogonal lines through the origin in , and the Grassmann manifold, usually denoted , of 2-planes in . There is a deformation retraction described in [6, p.324], which we will discuss thoroughly in our proof of Lemma 1.8, and also an obvious map , which is a -bundle.
We will work only with -cohomology. In Section 2, we give a new description of the algebra . Here we describe just the part needed in this proof, which was first obtained by Feder in [6, Cor 4.1]. The algebra is generated by classes and modulo two relations which cause the top two groups to be (resp. ) with (resp. ) iff for (resp. ) and . By [6, Thm 4.3], is injective and
[TABLE]
with . Also, .
Let denote the tangent bundle, a stable normal bundle, and the total Stiefel-Whitney class of a bundle. In [15, (3)], it is shown that
[TABLE]
The map induces a surjective vector bundle homomorphism , and hence a surjective homomorphism
[TABLE]
of vector bundles over . Then is a line-bundle over , and there is a vector bundle isomorphism
[TABLE]
Thus
[TABLE]
By the Wu formula, equals the element of for which
[TABLE]
Since, for , and
[TABLE]
we deduce . From (1.5), we obtain
[TABLE]
so and (1.5) becomes
[TABLE]
and hence
[TABLE]
By Lemma 1.8, we obtain
[TABLE]
Since for , and
[TABLE]
By (1.3), , and the portion with the will always give a stronger result than the portion without. Thus the relevant part of is
[TABLE]
The top dimension has as its only nonzero monomials (all equal), and so
[TABLE]
Using Lucas’s Theorem, it is easy to see that is odd iff is a 2-power, and when is a 2-power and , is odd iff , proving the theorem.
The following lemma was used above
Lemma 1.8**.**
With notation as above, .
Proof.
The map is defined as follows. For distinct lines and , working in their plane, let and be the pair of orthogonal lines bisecting the two angles between and , and then let and be rotations of and . Then , and the homotopy from the identity map of to moves and uniformly toward the closer of and . Here is the inclusion of in . Two scenarios for this are illustrated in Figure 1.9.
Figure 1.9**.**
The map **
m$$m$$m$$m$$k$$k$$k$$k$$\ell$$\ell^{\prime}$$\ell^{\prime}$$\ell
Let be the space of ordered pairs of orthogonal lines in , and the space of ordered pairs of orthogonal lines in together with an orientation on the plane which they span. Let forget the order and the orientation. This is a 4-sheeted covering space. Suppose has a section on an open set of . If , then specifies an order on and an orientation on the plane containing these vectors. A local trivialization of is defined by maps with , where is the angle, with respect to the orientation, through which or was rotated to end at . Thus is a line bundle over .
Reversing the order of in negates , as does reversing the orientation selected by . Thus our line bundle is , where is the line bundle (named for Reversing) over associated to the double cover , and is the line bundle (named for Orientation) over associated to the pullback over of the double cover from the oriented Grassmannian to the unoriented one. Thus .
Clearly equals of the universal of the Grassmannian, and this is our class . That is proved in [9, Lemma 3.3 and Prop 3.5]. Our map is Handel’s map . Thus , establishing the lemma, since .
The proof of Theorem 1.1 showed that is nonzero iff is a 2-power. We believe that Theorem 1.1 gives all nonimmersion and nonembedding results for spaces implied by Stiefel-Whitney classes of the normal bundle. Using our description of in Section 2 and its implications for along with (1.7), we have performed an extensive computer search for other results. Those which we found said that if (resp. or ), then (resp. or ), but the nonimmersion and nonembedding results for implied by these are in the same dimension as the result for , and so are implied by Theorem 1.1.
Now we prove the existence of immersions in when is not a 2-power. We continue to denote as .
Proof of Theorem 1.2.
We use obstruction theory to show that the map which classifies the stable normal bundle factors through , which implies the immersion by the well-known theorem of Hirsch.([11]) The theory of modified Postnikov towers developed in [8] applies to the fibration when is odd by [14]. The fiber is a union of Stiefel manifolds, and in our case, all we need is
[TABLE]
Since , the only possible obstructions are in and . The first obstruction is , which is 0 when is not a 2-power by a calculation very similar to that in our proof of Theorem 1.1. This already implies the immersion when is odd. When is even, we argue similarly to [13, Thm 2.3]. The final obstruction has indeterminacy
[TABLE]
By (1.6), we have, for even, . The nonzero element in is for an appropriate . In there is a class on which is 0, multiplication by and are 0, but multiplication by is nonzero. Therefore the final obstruction can be canceled if it is nonzero.
2. Cohomology of
Descriptions of the cohomology ring (mod 2) of the Grassmann manifold of -planes in were given initially by Chern ([3]) and Borel ([2]). Here we present what we think is a new description that has been useful in our analysis. It is based on the description given by Feder in [6]. As in the proof of Theorem 1.1, we denote by . In our proof of Theorem 1.1, we used [6, Cor 4.1] which stated that, with and the generators, in the top dimension, , the nonzero monomials are those for which is a 2-power. Working backwards from this, we can prove the following result.
Theorem 2.1**.**
In the ring , monomials are independent if . For , if , then has basis , and equals the sum of those for which is a -power.
Proof.
That the first relation occurs in grading is well-known (e.g., [6, Prop 4.1]). The case , is the result of [6, Cor 4.1] cited above. Multiplication by is an isomorphism of groups of order 2, implying the result when and . We will prove the result by induction on when . The induction when is identical.
Let , a vector space of dimension by Poincaré duality. Assume the result for . Define
[TABLE]
In , let
[TABLE]
By the induction hypothesis,
[TABLE]
where denotes the set of 2-powers.
Let be the subspace of spanned by . We will show that maps onto . Then since , is injective. Let . Then is a basis for , and
[TABLE]
extending the induction and completing the proof, once we establish the surjectivity of onto .
Let with . We first consider the case . Letting for (ignoring 1 or 2 monomials not required for the surjectivity), the matrix of with respect to the bases and is that of Lemma 2.2, and so is surjective. The cases of smaller values of have larger domain and smaller codomain, with being an extension of a quotient of the case , and hence is surjective since the case was.
Lemma 2.2**.**
Let denote the -by- matrix over with
[TABLE]
Then .
Proof.
The proof is by induction on . Let with . For , row contains a single 1, in column . Subtract this row from other rows which have a 1 in column . Then do a similar thing with columns , . The result has in the top left, and a -by- matrix with 1’s along the antidiagonal in the bottom right. All other elements are 0. By the induction hypothesis, this matrix has determinant 1.
In moderately large gradings, there is, for each , a monomial equal to . For example, in , the following monomials equal , respectively:
[TABLE]
and a similar pattern holds in for . However, in , , and there is no monomial which equals either or . We can obtain as , since and .
3. Topological complexity of
The topological complexity of a topological space is a homotopy invariant introduced by Farber in [4] which is one less than the number of nice subsets into which can be partitioned such that there is a continuous map such that is a path from to . This is of interest ([5]) for ordered (resp. unordered) configuration spaces (resp. ) as it measures how efficiently distinguishable (resp. indistinguishable) robots can be moved from one set of points in to another. The determination of has been particularly difficult.([16],[1])
Farber showed ([4]) that if is a CW complex. Here , the zero-divisor-cup-length, is the largest number of elements of with nonzero product, where is the diagonal map. The main theorem of this section determines .
Theorem 3.1**.**
If and , then
[TABLE]
and .
Since has the homotopy type of the compact -manifold described in the proof of Theorem 1.1, . For , the gap between our upper and lower bounds for is , respectively.
Proof.
Let and let , , and be as in the proof of Theorem 1.1. We identify with and note that the impact of (1.3) is that if .
Let , and define and similarly. We claim that since
[TABLE]
To see this, we first note that the indicated product is, in bigrading , equal to
[TABLE]
Since the terms divisible by are independent from those not divisible by , we restrict to terms whose right factor is not divisible by , and obtain
[TABLE]
Terms with (resp. ) have left (resp. right) factor equal to 0 since . Thus (3.3) equals , which is nonzero by (1.3) and Theorem 2.1.
To see that this bound for zcl cannot be improved, first note that the exponents of and in (3.2) cannot be increased since . If the exponent of is increased by 1, the top term occurs with even coefficient by symmetry. The only hope of getting a larger nonzero product would be to increase the exponent of . We will use our analysis of to see that this will fail to improve the zcl.
The key observation is that, with and , a nonzero monomial in with must have . This will follow from Theorem 2.1 once we show that if has and , and , then is not a 2-power. We have . On the other hand, .
If appears in the expansion of with maximal exponent sum, it should have , , and , as we do not want to sacrifice -exponents on both sides of the . To have a monomial whose exponent sum exceeds our zcl bound would require . If , then , so we would need with strict inequality unless . We also have , half the dimension of . We would also need mod 2. But this is impossible by Lemma 3.4 unless and . But then . The alternative is . But, since we need mod 2, the largest such was what was used in obtaining our lower bound.
Lemma 3.4**.**
If and , then .
Proof.
For to be odd, the binary expansions of and must be disjoint. Since , these 1’s would have to be a subset of those of .
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