This paper applies the Schur algorithm to characterize the variability regions of certain analytic functions mapping the unit disk into convex domains, providing explicit boundary descriptions and convexity properties.
Contribution
It introduces a novel application of the Schur algorithm to describe variability regions of functions into convex domains, including boundary parametrization.
Findings
01
Variability regions are convex closed Jordan domains.
02
Explicit boundary parametrization is provided.
03
The regions depend on the Schur algorithm and polynomial coefficients.
Abstract
Let Ω be a convex domain in the complex plane C with Ω=C, and P be a conformal map of the unit disk D onto Ω. Let FΩ be the class of analytic functions g in D with g(D)⊂Ω, and H1∞(D) be the closed unit ball of the Banach space H∞(D) of bounded analytic functions ω in D, with norm ∥ω∥∞=supz∈D∣ω(z)∣. Let C(n)={(c0,c1,…,cn)∈Cn+1:there existsω∈H1∞(D)satisfyingω(z)=c0+c1z+⋯+cnzn+⋯ for z∈D}. For each fixed z0∈D, j=−1,0,1,2,… and c=(c0,c1,…,cn)∈C(n), we use the Schur…
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Taxonomy
TopicsAnalytic and geometric function theory · Meromorphic and Entire Functions · Holomorphic and Operator Theory
Full text
An application of the Schur algorithm to variability regions of certain analytic functions
Md Firoz Ali
Md Firoz Ali,
Department of Mathematics,
National Institute of Technology Durgapur,
Durgapur - 713209,
West Bengal,
India.
Let Ω be a convex domain in the complex plane C with Ω=C, and P be a conformal map of the unit disk D onto Ω. Let FΩ be the class of analytic functions g in D with g(D)⊂Ω, and H1∞(D) be the closed unit ball of the Banach space H∞(D) of bounded analytic functions ω in D, with norm ∥ω∥∞=supz∈D∣ω(z)∣. Let C(n)={(c0,c1,…,cn)∈Cn+1:there existsω∈H1∞(D)satisfyingω(z)=c0+c1z+⋯+cnzn+⋯ for z∈D}. For each fixed z0∈D, j=−1,0,1,2,… and c=(c0,c1,…,cn)∈C(n), we use the Schur algorithm to determine the region of variability VΩj(z0,c)={∫0z0zj(g(z)−g(0))dz:g∈FΩwith(P−1∘g)(z)=c0+c1z+⋯+cnzn+⋯}. We also show that for z0∈D\{0} and c∈IntC(n), VΩj(z0,c) is a convex closed Jordan domain, which we determine by giving a parametric representation of the boundary curve ∂VΩj(z0,c).
Let C be the complex plane.
For c∈C and r>0, let
D(c,r)={z∈C:∣z−c∣<r},
and D(c,r)={z∈C:∣z−c∣≤r}.
In particular, we denote the unit disk by D:=D(0,1).
Let A(D) be the class of analytic functions
in the unit disk D with the topology of uniform convergence
on every compact subset of D.
Let H∞(D) be the Banach space of
analytic functions f in D with norm
∥f∥∞=supz∈D∣f(z)∣,
and H1∞(D) be the closed unit ball of H∞(D), i.e.,
H1∞(D)={ω∈H∞(D):∥ω∥∞≤1}.
Denote by S, the class of univalent (i.e., one-to-one) functions
f in A(D), normalized so that f(0)=f′(0)−1=0.
The subclasses S∗ of starlike, and CV of convex functions are respectively defined by
[TABLE]
and
[TABLE]
Then CV⊂S∗⊂S.
For f∈A(D) with f(0)=f′(0)−1=0,
f∈S∗ if, and only if, Re(zf′(z)/f(z))>0 in D.
Similarly for f∈A(D) with f(0)=f′(0)−1=0,
f∈CV if, and only if, Re(zf′′(z)/f′(z)+1)>0 in D.
The basic properties of these classes of functions can be found for example in [2, 9].
Let F be a subclass of A(D)
and z0∈D. Then upper and lower estimates of the form
[TABLE]
are respectively called a distortion theorem, and
a rotation theorem at z0 for F,
where Mj and mj (j=1,2) are some non-negative constants.
Estimates such as these deal only with absolute values,
or arguments of f′(z0).
In order to study the complex value f′(z0) itself,
it is necessary to consider the variability region of
f′(z0) when f ranges over the class F,
i.e., the set {f′(z0):f∈F}.
For example, it is known that
[TABLE]
For a proof, we refer to [2, Chapter 2, Exercise 10, 11 and 13].
For other examples see [7, 8] and the references therein.
Let H={w∈C:Rew>0}.
For f∈CV, the function g given by g(z)=1+zf′′(z)/f′(z)
satisfies g(D)⊂H, i.e.,
Reg(z)>0 in D.
Applying Schwarz’s lemma to (g(z)−1)/(g(z)+1)
we obtain ∣f′′(0)∣≤2 for f∈CV.
Gronwall [4], and independently
Finkelstein [3] obtained
the sharp lower and upper estimates
for ∣f′(z0)∣, when f∈CV satisfies
the additional condition f′′(0)=2λ,
where z0∈D and
λ∈D are arbitrarily
preassigned. Let
[TABLE]
It is easy to see that
V(e−iθz0,eiθλ)=V(z0,λ)
for all θ∈R.
If ∣λ∣=1, then by Schwarz’s lemma, for f∈CV the condition
f′′(0)=2λ forces f(z)≡z/(1−λz),
and hence V(z0,λ)={log1/(1−λz0)2}.
Thus it suffices to consider the case 0≤λ<1.
In 2006, one of the present authors [15]
obtained the following extension to Gronwall’s [4] result.
Theorem A**.**
For any z0∈D\{0} and 0≤λ<1,
the set V(z0,λ)
is a convex closed Jordan domain surrounded by the curve
[TABLE]
In order to prove Theorem A, Yanagihara [15] implicitly showed the following.
Theorem B**.**
For any
z0∈D\{0} and 0≤λ<1, the variability region
[TABLE]
is the same convex closed Jordan domain as in Theorem A.
Note that putting g(z)=1+zf′′(z)/f′(z), Theorem A is a direct consequence of
Theorem B. For similar results, we refer to [10, 14].
The aim of this paper is to extend
Theorem B, and to refine Theorem A.
Throughout the paper, we will, unless otherwise stated, assume that Ω is a convex domain in C with
Ω=C, and P is a conformal map of
D onto Ω.
Let FΩ be the
class of analytic functions g in D with
g(D)⊂Ω. Then the map
FΩ∋g↦ω=P−1∘g∈H1∞(D)\E
is bijective, where
E={ω∈H1∞(D):ω(z)≡awith∣a∣=1}.
For c=(c0,c1,…,cn)∈Cn+1, let
[TABLE]
For f∈A(D) with f(0)=f′(0)−1=0,
let g(z)=1+zf′′(z)/f′(z).
Then the coefficients of the Taylor series of f up to order n+1
are uniquely determined by the coefficients of ω=P−1∘g
up to order n, and vice versa. Thus in order to extend Theorem B,
we consider the following problem.
Problem 1.1**.**
Let n∈N∪{0}. For j=−1,0,1,…,
z0∈D\{0}
and c=(c0,…,cn)∈Cn+1,
determine the variability region
[TABLE]
We note that the coefficient body C(n) defined by
[TABLE]
is a compact and convex subset of Cn+1.
We note that Schur [12, 13] characterized C(n) completely.
We also refer to [5, Chapter I] and
[1, Chapter 1], for a detailed treatment.
For c=(c0,…,cn)∈Cn+1,
one can calculate the corresponding Schur parameter
γ=(γ0,…,γk) of c,
where 0≤k≤n, and necessary and sufficient conditions
for c∈IntC(n), c∈∂C(n)
and c∈C(n) can be described in terms of γ
(see Section 2).
The organization of this paper is as follows. In Section 2, we summarize the definitions and known facts concerning the Schur parameter γ.
We then state our main theorem and its variant, which gives the solution to Problem 1.1.
In Section 3, we state some lemmas on p-valent starlike and convex functions, and
introduce the Schur polynomials associated with the Schur parameter γ. We then
prove several lemmas on the Schur polynomials.
In Section 4, we prove our main theorem, and its variant.
2. The Schur parameter and statement of results
For the sake of completeness we state the Carathéodry interpolation problem and its
solution given by Schur [12, 13], which plays an important role
in the proof of our main theorem.
Problem 2.1** (The Carathéodory interpolation problem).**
Let n∈N∪{0}. For c=(c0,…,cn)∈Cn+1,
find necessary and sufficient conditions for the existence of ω∈H1∞(D)
such that ω(z) has a series expansion of the form
[TABLE]
Furthermore, find an explicit description of all solutions.
We call c=(c0,…,cn) the Carathéodory data of length n+1.
For a∈D, define σa∈\mboxAut(D) by
It follows from the maximum modulus principle that Problem 2.1
has no solution if ∣c0∣>1, and has a unique solution
ω(z)≡c0, if ∣c0∣=1. So suppose that ∣c0∣<1 and
ω∈H1∞(D) satisfies ω(0)=c0.
Then by the maximum modulus principle,
[TABLE]
belongs to H1∞(D).
This relation between ω and ω1 can be convertible.
Consequently, the set of all solutions ω∈H1∞(D) is given by
[TABLE]
where ω1∈H1∞(D) is arbitrary.
The general solution to Problem 2.1
can now be obtained from the above consideration and
by recursively applying the following
proposition, which was implicitly proved in
[12, 13] and [5, Chapter 1].
Proposition 2.1**.**
Let c=(c0,…,cn)∈Cn+1
be a Carathéodory data of length n+1.
(1)
If ∣c0∣>1, or ∣c0∣=1 with (c1,…,cn)=(0,…,0),
then the Carathéodory problem with data c has no solution.
2. (2)
If ∣c0∣=1 with (c1,…,cn)=(0,…,0),
then the Carathéodory problem data c has the unique solution
ω(z)≡c0.
3. (3)
Assume that ∣c0∣<1. If ω is a solution to the Carathéodory problem
with data c, then
[TABLE]
is a solution to the Carathéodory problem with data c(1), where
c(1)=(c0(1),…,cn−1(1)) is a data of length n defined by
[TABLE]
Conversely, if we define c(1)=(c0(1),…,cn−1(1))∈Cn
by (2.1), and ω1 is a solution to
the Carathéodory problem with data c(1), then
[TABLE]
is a solution to the Carathéodory problem with data c=(c0,…,cn).
We note that c=(c0,…,cn) and
(c0,c(1))=(c0,c0(1),…,cn−1(1))
are uniquely determined each other by (2.1).
For a given Carathéodory data c=(c0,…,cn)∈Cn+1,
the Schur parameter γ=(γ0,…,γk),
k=0,1,…,n is defined as follows.
First, let
c(0)=(c0(0),…,cn(0))=(c0,…,cn) and γ0=c0(0).
If ∣γ0∣>1, we set k=0 and γ=(γ0).
If ∣γ0∣=1, we set k=n, and for p=1,2,…,n,
[TABLE]
If ∣γ0∣<1, we define c(1)=(c0(1),…,cn−1(1))∈Cn by (2.1).
Now assume that γ0,…,γj−1 and c(j)=(c0(j),…,cn−j(j))
are already defined and satisfy ∣γ0∣<1,…,∣γj−1∣<1
for some j with 1≤j≤n−1. Then put γj=c0(j).
If ∣γj∣>1, put k=j and γ=(γ0,…,γj).
If ∣γj∣=1, put k=n and for p=j+1,…,n,
[TABLE]
If ∣γj∣<1, we define c(j+1)=(c0(j+1),…,cn−j−1(j+1))∈Cn−j
as in Proposition 2.1, i.e.,
[TABLE]
Applying this procedure recursively, one obtains the Schur parameter
γ=(γ0,…,γk), k=0,…,n of c=(c0,…,cn).
When ∣γ0∣<1,…,∣γj∣<1, the equations in (2.2)
and γj=c0(j) show that
c(j)=(c0(j),c1(j),…,cn−j(j))
and (γj,c0(j+1),…,cn−j−1(j+1))
are uniquely determined by each other. Thus when ∣γ0∣<1,…,∣γn∣<1,
c=(c0,…,cn)=c(0) and γ=(γ0,…,γn)
are also uniquely determined by each other. For an explicit representation of
γ in terms of c, we refer to the following results of Schur [12, 13].
For a detailed proof of Theorem C, we refer to [5, Chapter 1].
It is not difficult to see that for a given Carathéodory data c,
the hypotheses of (i), (ii) and (iii)
in Theorem C are respectively equivalent to c∈IntC(n),
c∈∂C(n) and c∈C(n).
Let Ω be a convex domain with Ω=C, and P be a conformal map of D onto Ω. When c∈C(n) or c∈∂C(n), Theorem C gives the following simple solution to Problem 1.1.
Theorem 2.1**.**
Let c=(c0,…,cn)∈Cn+1 be a Carathéodory data.
If c∈C(n) i.e., the hypothesis of (iii) in Theorem C holds,
then VΩj(z0,c)=∅. If c∈∂C(n) i.e.,
the hypothesis of (ii) in Theorem C holds,
then VΩj(z0,c) reduces to a set consisting of a single point w0,
where
[TABLE]
and γ=(γ0,…,γi,0,…,0) is the Schur parameter of c.
Now we introduce a family of functions, which are extremal for Problem 1.1
in the case c∈IntC(n).
For ε∈D
and Schur parameter γ=(γ0,…,γn) of c∈IntC(n), let
[TABLE]
Then ωγ,ε∈H1∞(D) is a solution to the Carathéodory problem with the data c, i.e.,
[TABLE]
In particular, we have ωγ,ε(0)=c0. We note that for each fixed ε∈D, ωγ,ε(z) and Qγ,j(z,ε) are analytic functions of z∈D, and for each fixed z∈D, ωγ,ε(z) and Qγ,j(z,ε) are analytic functions of ε∈D.
When ε∈∂D, ωγ,ε(z) is a finite Blaschke product of z. Indeed, it follows from (2.4) that ωγ,ε(z) is a rational function of z, which is analytic on D. If ∣ε∣=1, then again by (2.4) it is easy to see that ωγ,ε maps ∂D into ∂D. Thus ωγ,ε is a finite Blaschke product of z.
We next state the following, which is the main result of this paper.
Theorem 2.2**.**
Let n∈N∪{0}, j∈{−1,0,1,2,…},
c=(c0,…,cn)∈IntC(n)
and γ=(γ0,…,γn) be the Schur parameter of c.
Then for each fixed z0∈D\{0}, Qγ,j(z0,ε)
is a convex univalent function of ε∈D and
[TABLE]
Furthermore
[TABLE]
for some g∈FΩ(c) and ε∈∂D
if, and only if, g(z)≡P(ωγ,ε(z)).
3. Preliminaries
First we note the following (which is elementary).
Lemma 3.1**.**
Let n∈N∪{0} and g0, g1∈A(D) satisfying
g1(z)−g0(z)=O(zn+1) as z→0. Then for any analytic function φ defined in
a neighborhood of g0(0)=g1(0), φ(g0(z))−φ(g1(z))=O(zn+1) as z→0.
We next give some simple lemmas concerning multivalent starlike and convex functions.
For a positive integer p, we write (S∗)p:={f0p:f0∈S∗}.
Lemma 3.2**.**
Let f∈A(D)
with f(z)=zp+⋯ for z∈D. Then f∈(S∗)p, i.e., there exists
f0∈S∗ with f=f0p if, and only if,
[TABLE]
Proof.
When p=1, the lemma is well known (see [2, Theorem 2.10]).
For general p, if there exists f0∈S∗ with f=f0p, then by the identity zf′(z)/f(z)=pzf0′(z)/f0(z)
we have Re{zf′(z)/f(z)}>0.
Inequality (3.1) ensures that f has no zeros in D\{0}. Thus there exists f0∈A(D) with f0p=f and f0′(0)=1. Again from the identity zf′(z)/f(z)=pzf0′(z)/f0(z) it follows that Re{zf0′(z)/f0(z)}>0 in D. Thus f0∈S∗.
∎
Lemma 3.3**.**
Let f∈A(D)
with f(z)=zp+⋯ for z∈D. If f satisfies
[TABLE]
then there exists f0∈S∗ with f=f0p.
Proof.
Let q∈N∪{0}, and A and B be analytic functions in D
such that A(z)=azq+⋯ and B(z)=bzq+⋯ in D with a,b=0.
Suppose that a−1A∈(S∗)q, or b−1B∈(S∗)q. Then Libera [6] showed that
Re{A′(z)/B′(z)}>0 in D implies Re{A(z)/B(z)}>0 in D.
Now note that 1+zf′′(z)/f′(z)=(zf′(z))′/f′(z). Let g(z)=p−1zf′(z). Since Re(zg′(z)/g(z))=\mboxRe(1+zf′′(z)/f′(z))>0, it follows from Lemma 3.2 that g∈(S∗)p.
Thus, with A(z)=zf′(z) and B(z)=f(z) Libera’s result, shows that Re(zf′(z)/f(z))>0 for z∈D, and so
the lemma now follows from Lemma 3.2.
∎
A well known theorem due to Robertson [11] states that each f∈CV can be approximated by a sequence of conformal maps of
D onto convex polygons, uniformly on any compact subset of D as follows.
Lemma 3.4**.**
[11]**
For any function f∈CV, η>0 and a compact subset E of D,
there exists h∈A(D) with supz∈E∣f′(z)−h(z)∣<η, such that
h(z) can be written in the form
[TABLE]
where ηi∈∂D, 0<βi≤2(i=1,…,m), and ∑i=1mβi=2.
The following brief summary of Schur polynomials will assist in the proof of our main theorem. For more details we refer to [1].
Let c=(c0,…,cn)∈IntC(n) and γ=(γ0,…,γn)
be the Schur parameter of c. Note that c=(c0,…,cn)∈IntC(n) forces
∣γ0∣<1,…,∣γn∣<1. Suppose that ω∈H1∞(D)
satisfies ω(z)=c0+…+cnzn+⋯, and define ω0,ω1,…,ωn∈H1∞(D) by (2.3) and ωn+1∈H1∞(D) by
[TABLE]
Then since γk=ωk(0), k=0,…,n, we have
[TABLE]
We now define sequences of polynomials recursively by
The polynomials Ak(z),Bk(z),Ak(z) and Bk(z) (k=0,1,…,n)
are of degree at most k, and are called the Schur polynomials associated with γ.
For convenience, we put ω∗(z)=ωn+1(z). Then by Theorem C and
(3.5) we obtain the following.
Lemma 3.5**.**
Let c=(c0,…,cn)∈IntC(n), and γ=(γ0,…,γn) be the Schur parameter of c.
Then for any ω∈H1∞(D) with ω(z)=c0+⋯+cnzn+⋯ in D, there exists a unique ω∗∈H1∞(D) such that
[TABLE]
Conversely, for any ω∗∈H1∞(D), if ω is given by (\refeq:SChurrepresentation), then ω satisfies ω(z)=c0+⋯+cnzn+⋯ in D. In particular, the function ωγ,ε defined by (2.4) can be written as
[TABLE]
and P∘ωγ,ε∈FΩ(c).
We next give some important properties of the Schur polynomials.
From (3.3) and
(3.4) it easily follows that Ak(z) is a monic polynomial of
degree k. Also
[TABLE]
for k=0,1,…,n and the degrees of Ak(z),Bk(z) and Bk(z) are at most k.
Lemma 3.6**.**
For k=0,…,n,
[TABLE]
Proof.
When k=0, (3.9) directly follows form (3.3).
Assume that (3.9) holds for k≥0,
then by (3.4) we have
[TABLE]
Similarly Bk+1(z)=zk+1Ak+1(1/z).
∎
Lemma 3.7**.**
For k=0,…,n,
[TABLE]
Proof.
We use induction on k. When k=0, (3.10)
follows directly from (3.3). Assume
(3.10) holds for k≥0,
then by (3.4) we have
[TABLE]
∎
Lemma 3.8**.**
For k=0,…,n, the inequality
[TABLE]
holds for z∈D.
Proof.
When k=0, it follows from (3.3) that ∣B0(z)∣2−∣A0(z)∣2=1−∣γ0∣2.
Assume (3.11) holds for k≥0,
then for ∣z∣≤1, and (3.4) we have
[TABLE]
∎
Lemma 3.9**.**
For k=0,…,n, the inequality
[TABLE]
holds for z∈D.
Proof.
By Lemma 3.8, the function Bk(z) has no zeros on D.
Hence Bk(z)/Bk(z) is analytic on D. For ∣z∣=1, using
Lemmas 3.6 and 3.8 we have
[TABLE]
Thus we have ∣Bk(z)/Bk(z)∣<1 on ∂D,
and hence by the maximum modulus principle for analytic functions,
∣Bk(z)/Bk(z)∣<1 holds on D.
∎
4. Proof of the Main Theorem
First we show that VΩj(z0,c) is a compact and convex subset of C.
Proposition 4.1**.**
For c=(c0,…,cn)∈IntC(n), the class
FΩ(c) is a compact and convex subset of A(D).
Proof.
For g∈FΩ(c), by Schwarz’s lemma we have
[TABLE]
This implies P−1(g(z))∈Δ(c0,r)={w∈C:∣w−c0∣/∣1−c0w∣≤r}(⊂D)
for ∣z∣≤r<1. Thus g(z)∈P(Δ(c0,r)) for any
g∈FΩ(c), and ∣z∣≤r<1. Therefore FΩ(c) is
locally uniformly bounded, and hence by Montel’s theorem forms a normal family.
We next show that FΩ(c) is closed.
Let gk∈FΩ(c), k∈N
and g0∈A(D) such that gk→g0 locally uniformly in D
as k→∞. Then
[TABLE]
Thus (P−1∘g0)(z)=c0+c1z+⋯+cnzn+⋯ for z∈D.
Similarly, it follows that g0(D)⊂Ω.
Now suppose that g0(D)\Ω=∅.
Then there exists z∗∈D such that w∗=g0(z∗)∈∂Ω.
Since g0(0)=P(c0)=w∗=g0(z∗), g0 is a non-constant analytic function and hence is an open map.
Thus g0(D) is a neighborhood of w∗∈∂Ω.
Since there exists a support line of the convex set Ω through w∗,
the neighborhood g0(D) of w∗ contains an exterior point of Ω.
This contradicts g0(D)⊂Ω.
Hence g0(D)⊂Ω and g0∈FΩ(c),
and so FΩ(c) is closed in A(D).
Since FΩ(c) is normal and closed in the metric space A(D),
it is therefore a compact subset of A(D).
Next suppose g0, g1∈FΩ(c). Then P−1(g0(z))−P−1(g1(z))=O(zn+1) as z→0. Hence by Lemma 3.1, g0(z)−g1(z)=O(zn+1) as z→0. Thus for any t∈[0,1],
gt(z)=(1−t)g0(z)+tg1(z) satisfies gt(z)−g0(z)=O(zn+1) as z→0.
Hence again using Lemma 3.1, it follows that P−1(gt(z))−P−1(g0(z))=O(zn+1),
as z→0. This shows that P−1(gt(z))=c0+⋯+cnzn+⋯
for z∈D. Since Ω is convex, gt(z)=(1−t)g0(z)+tg1(z)∈Ω for all z∈D.
Thus gt(D)⊂Ω, and hence gt∈FΩ(c).
Therefore FΩ(c) is convex.
∎
Corollary 4.1**.**
For c=(c0,…,cn)∈IntC(n), the set
VΩj(z0,c) is a compact and convex subset of C.
Proof.
Since the functional A(D)∋g↦∫0z0ζj(g(ζ)−g(0))dζ
is linear and continuous on A(D), and VΩj(z0,c)
is the image of the compact and convex subset FΩ(c) of A(D)
under this functional, VΩj(z0,c) is also a compact and convex subset of C.
∎
Proposition 4.2**.**
Let c=(c0,…,cn)∈IntC(n) and z0∈D\{0}.
Then Qγ,j(z0,0)=∫0z0ζj{P(ωγ,0(ζ)−P(c0)}dζ
is an interior point of the set VΩj(z0,c), where γ=(γ0,…,γn) is the Schur parameter of c.
Proof.
For fixed z0∈D, note that Qγ,j(z0,ε) defined by (2.5)
is an analytic function of ε∈D. Since a non-constant analytic function is an open map,
in order to prove the proposition it suffices to show that Qγ,j(z0,ε) is a non-constant
function of ε.
Let
[TABLE]
Then the problem reduces to showing that ψ(z)=0 for z∈D\{0}.
By (3.7) and Lemma 3.7
we have
[TABLE]
We note that ψ has a Taylor series representation of the form ψ(z)=azn+j+2+⋯,
with a=(n+j+2)−1∏k=0n(1−∣γk∣2)P′(c0). The assertion will be proved
provided we can show that \mboxRe(zψ′′(z)/ψ′(z))≥0, since in this case,
Lemmas 3.3 and (3.8) imply
that there exists a starlike univalent function ψ0∈S∗ satisfying
ψ(z)=aψ0(z)n+j+2, and so ψ(z) has no zeros in D\{0}.
In order to show Re(zψ′′(z)/ψ′(z))≥0, by Lemma 3.4
we may assume without loss of generality that
[TABLE]
where ηi∈∂D, 0<βi≤2(i=1,2,…,m), and ∑i=1mβi=2.
Under this assumption
[TABLE]
and so
[TABLE]
For i=1,…,m, let zi1,…,zipi(0≤pi≤n) be zeros of
Bn(z)−ηiBn(z). Then by Lemma 3.9,
we have ∣ziℓ∣>1 for all i=1,…m and ℓ=1,…,pi.
Since Bn(0)=1 and Bn(0)=γ0, it follows that
Bn(z)−ηiBn(z)=(1−ηiγ0)∏ℓ=1pi(1−z/ziℓ).
Thus using the identity w/(1−w)=2−1{(1+w)/(1−w))−1} we have
[TABLE]
∎
Proposition 4.3**.**
Let c=(c0,…,cn)∈IntC(n) and z0∈D\{0}.
Then
[TABLE]
holds for all ε∈∂D, where γ is the Schur parameter of c.
Furthermore,
[TABLE]
for some g∈FΩ(c), and ε∈∂D
if, and only if, g(z)≡P(ωγ,ε(z)).
Proof.
Let g∈FΩ(c) and ω=P−1∘g.
Then by Lemma 3.5,
there exists ω∗∈H1∞(D) such that
[TABLE]
where An(z), Bn(z), An(z) and Bn(z) are the Schur polynomials associated with γ.
Since ω∗∈H1∞(D), we have
[TABLE]
It follows from Lemmas 3.7 and 3.8
that the inequality (4.1) is equivalent to
[TABLE]
where
[TABLE]
Thus (P−1∘g)(z)=ω(z)∈D(ρ(z),r(z)),
and so g(z)∈P(D(ρ(z),r(z))) for any g∈FΩ(c).
Since a convex univalent function maps any closed subdisk of D onto a convex closed Jordan domain
with an analytic convex boundary curve, for any z∈D\{0} and
θ∈R, g(z) belongs to the left half plane
of the tangential line at P(ρ(z)+r(z)eiθ) with the tangential vector
ir(z)eiθP′(ρ(z)+r(z)eiθ) (see Figure 1). Thus
[TABLE]
Since the tangential line intersects the boundary curve only at P(ρ(z)+r(z)eiθ),
equality in (4.2) holds if, and only if, g(z)=P(ρ(z)+r(z)eiθ).
If g(z)=(P∘ωγ,ε)(z) with ∣ε∣=1,
Lemma 3.5 shows that
Assuming the inequality (4.6) for the moment, we complete the proof.
Notice that h has a Taylor series representation of the form h(z)=azn+j+2+⋯,
with a=(n+j+2)−1P′(c0). By Lemma 3.3,
there exists h0∈S∗ such that h(z)=ah0(z)n+j+2.
Since h0 is starlike, for any z0∈D\{0}, the line segment joining
[math] and h0(z0) lies entirely in h0(D).
Define a curve Γ:z=z(t), 0≤t≤1 joining [math] to z0 by
z(t)=h0−1(t1/(n+j+2)h0(z0)). Then
[TABLE]
Thus h′(z(t))z′(t)≡h(z0) for 0<t≤1. This, and (4.5), shows that
[TABLE]
This implies that for any g∈FΩ(c), the value of the integral
∫0z0zj{g(z)−g(0)}dz belongs to a closed half plane, i.e.,
[TABLE]
where w0=Qγ,j(z0,ε) and α=εh(z0). Thus
[TABLE]
Since P∘ωγ,ε∈FΩ(c), it follows that
[TABLE]
and so from (4.8) and (4.9) we obtain
Qγ,j(z0,ε)=w0∈∂VΩj(z0,c).
We next deal with uniqueness. Suppose that
[TABLE]
holds for some g∈FΩ(c) and ε∈∂D.
Then from (4.7) it follows that
[TABLE]
holds on the curve Γ, and so
[TABLE]
on Γ. By the equality condition of (4.4), we have g(z)=P(ωγ,ε(z)) on Γ,
and from the identity theorem for analytic functions it follows that g=P∘ωγ,ε.
Since the harmonic function
Re(zh′′(z)/h′(z))+1 assumes the value n+j+2≥1>0 at the origin,
by using the minimum principle it suffices to show Re(zh′′(z)/h′(z))+1≥0
in D.
As in the proof of Proposition 4.2,
we may assume without loss of generality that
[TABLE]
where ηi∈∂D, 0<βi≤2(i=1,2,…,m), and ∑i=1mβi=2.
Thus from Lemma 3.5 we have
[TABLE]
and hence a simple computation gives
[TABLE]
We note that for each ∣ε∣=1, the function ωγ,ε(z)={Bn(z)+εzAn(z)}/{Bn(z)+εzAn(z)} is a finite Blaschke product. Thus for each i, the polynomials qi(z):=Bn(z)+εzAn(z)−ηi{Bn(z)+εzAn(z)} have no zeros in D, and are of degree n+1 at most.
Since Bn(0)=1 and Bn(0)=γ0, the polynomials qi(z) can be expressed as
[TABLE]
where zi1,…,zipi∈C\D
are the zeros of the polynomial qi(z), and 0≤pi≤n+1. Therefore using the identity
w/(1−w)=2−1{(1+w)/(1−w)−1} we have
[TABLE]
∎
Now we are in a position to prove our main result.
Let c∈\mboxIntC(n), z0∈D\{0}
and γ=(γ0,…,γn) be the Schur parameter of c.
Corollary 4.1 and Proposition 4.2,
shows that the set VΩj(z0,c) is a compact and convex subset of C,
and Qγ,j(z0,0) is an interior point of VΩj(z0,c).
From these properties it is not difficult to see that ∂VΩj(z0,c)
is a Jordan curve, and VΩj(z0,c) is a union of ∂VΩj(z0,c)
and its inside domain, i.e., VΩj(z0,c) is a closed Jordan domain.
Proposition 4.3 shows that the map
∂D∋ε↦Qγ,j(z0,ε)∈∂VΩj(z0,c)
is a closed curve. Furthermore, it is a simple curve. Indeed, if
Qγ,j(z0,ε1)=Qγ,j(z0,ε2)
for some ε1,ε2∈∂D,
then by the uniqueness part of Proposition 4.3 we have
P(ωγ,ε1(z))≡P(ωγ,ε2(z)),
and so ωγ,ε1(z)≡ωγ,ε2(z).
Using the representation (3.7) for
ωγ,ε, we have
[TABLE]
which gives
[TABLE]
Consequently, by Lemma 3.7 we conclude that ε1=ε2.
Since a simple closed curve cannot contain any simple closed curve other than itself, the map
∂D∋ε↦Qγ,j(z0,ε)∈∂VΩj(z0,c)
is surjective, and a parametrization of the boundary curve ∂VΩj(z0,c).
It therefore follows from Darboux’s theorem (see [9, Lemma 1.1])
that for fixed z0∈D\{0}, Qγ,j(z0,ε) is a convex univalent analytic
function of ε∈D, and
VΩj(z0,c)={Qγ,j(z0,ε):ε∈D}.
This completes the proof.
∎
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