Coefficient estimates for $H^p$ spaces with $0<p<1$
Ole Fredrik Brevig, Eero Saksman

TL;DR
This paper calculates specific coefficient bounds for functions in the Hardy spaces with 0<p<1, providing explicit constants and identifying extremal functions.
Contribution
It explicitly computes the constants C(2,p) for 0<p<1 and C(3,2/3), and characterizes the functions that attain these bounds.
Findings
Computed C(2,p) for 0<p<1.
Determined C(3,2/3).
Identified extremal functions for these bounds.
Abstract
Let denote the smallest real number such that the estimate holds for every in the space of the unit disc. We compute for and , and identify the functions attaining equality in the estimate.
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Coefficient estimates for spaces with
Ole Fredrik Brevig
Department of Mathematical Sciences, Norwegian University of Science and Technology (NTNU), NO-7491 Trondheim, Norway
and
Eero Saksman
Department of Mathematical Sciences, Norwegian University of Science and Technology (NTNU), NO-7491 Trondheim, Norway
Department of Mathematics and Statistics, University of Helsinki, FI-00170 Helsinki, Finland
(Date: March 16, 2024)
Abstract.
Let denote the smallest real number such that the estimate holds for every in the space of the unit disc. We compute for and , and identify the functions attaining equality in the estimate.
2010 Mathematics Subject Classification:
Primary 30H10. Secondary 42A05.
Some of the work on the present paper was carried out during the workshop “Operator related Function Theory” at the Erwin Schrödinger Institute. The authors gratefully acknowledge the support of the ESI
1. Introduction
For , the Hardy space is comprised of the analytic functions in the unit disc which satisfy
[TABLE]
The Hardy space is a Banach space when and a quasi-Banach space when . For an integer , let denote the smallest real number such that
[TABLE]
holds for every in . In other words, is the norm of the bounded linear functional on .
In the range it follows readily from the triangle inequality and Hölder’s inequality that for every . Estimates for when were first obtained by Hardy and Littlewood [7], who proved that there is a constant such that holds for every .
In this paper we are interested in computing explicitly in the non-trivial range . For this purpose it is fruitful to express this quantity via the associated linear extremal problem
[TABLE]
A normal family argument implies that there are functions in the unit ball of attaining the supremum (1). In a recent joint paper with Bondarenko and Seip [2], we proved that the extremal function for in (1) is given by
[TABLE]
up to rotations . Consequently, we found that
[TABLE]
The approach used in [2] is to write in the unit ball of as , where and are in the unit ball of and does not vanish in . If the coefficient sequences of and are and , respectively, then
[TABLE]
For any fixed non-vanishing in the unit ball of , it is now easy to find the optimal in the unit ball of to maximize (4) by the Cauchy–Schwarz inequality. This translates the linear extremal problem (1) in to a non-linear extremal problem for non-vanishing functions in .
By using the Cauchy–Schwarz inequality in this way and treating and as completely independent, we actually double the degree of the non-linear extremal problem. When this does not make the problem much harder, but already for this approach becomes computationally untenable.
For a class of linear extremal problems including (1) on with , there is a well-developed theory which yields that the extremal functions have a very specific structure (see e.g. [5, Sec. 8.4]). The proof of this structure result relies on the fact that is a Banach space and duality arguments. These techniques do not apply for , but we can replace them with a variational argument which goes back to F. Riesz [12] and obtain the same result also for .
This structure result is a special case of a more general result on the structure of the solutions to the Carathéodory–Fejér problem, which was extended from the range to the range by Kabaila [9] (see also [10, pp. 82–83] — the latter reference actually develops a general theory that covers many related variational problems on spaces). This extension to explicitly uses the structure of the solutions for , while the variational argument presented in the present paper actually applies in the range without modification.
The information regarding the structure of the extremals for the linear extremal problem (1) thus obtained shows that and in the factorization are closely related. This greatly simplifies the non-linear extremal problem we have to solve in order to identify the extremals. Consequently, we are able to completely settle the case .
Theorem 1**.**
For we have
[TABLE]
and, up to the rotations , the extremal function in (1) is
[TABLE]
Comparing (3) and Theorem 1, we see the curious identity . The next result demonstrates that the same relationship does not hold in general.
Theorem 2**.**
We have
[TABLE]
and, up to the rotations , the extremal function in (1) is
[TABLE]
This paper is organized into four additional sections. In Section 2 we recall some preliminaries about Hardy spaces and obtain the above-mentioned structure result for . The proofs of Theorems 1 and 2 are presented, respectively, in Sections 3 and 4. Section 5 contains some concluding remarks, conjectures and discussions of related work.
2. Preliminaries
In the present section, we will use several basic facts pertaining to Hardy spaces. We refer generally to the monograph [5], which contains most of what which we require. Our goal is to describe the structure of the extremals for bounded linear functionals on , when depends only on the first coefficients of the function . In the case , this description is a consequence of a general theory of linear extremal problems for spaces developed by Macintyre, Rogosinski, Shapiro and Havinson (see e.g. [8, 11] and [5, Ch. 8]).
To set the stage for a discussion of their approach and ours, we recall that every in has non-tangential boundary limits
[TABLE]
for almost every . It also holds that , so is identified with a subspace of , the latter defined in terms of the normalized Lebesgue arc length measure on .
Every bounded linear functional on , for , can be represented in the inner product of as
[TABLE]
for some analytic function in which is (at least) integrable on . Since is a Hilbert space, the analytic function generating the functional is (up to a constant) equal to the extremal for the functional . This fact leads naturally to the following.
Since is a Banach space when , the Hahn–Banach theorem extends every bounded linear functional on to a bounded linear functional on with the same norm. This makes it possible to formulate the dual extremal problem, which is to find an element of minimal norm in , where , such that . These two problems are closely related, and this can be exploited obtain a description of the structure of the extremals (and the structure of the element of minimal norm generating the functional) when the functional depends only on the first coefficients of .
These techniques are not available to us in the range , both since we cannot use the Hahn–Banach theorem and even if we could, supports no non-trivial bounded linear functionals. We will therefore replace the duality approach outlined above with a variational argument essentially due to F. Riesz [12]. See also [13, Sec. 2] for a similar argument in a somewhat different context. Note that this method actually applies in the range without modification. We require two additional preliminary facts before proceeding.
Every function in can be written as , where is an inner function and is an outer function. In particular, does not vanish in and for almost every . This allows us to factor
[TABLE]
where and . We note that holds for almost every , which yields the norm equalities .
Let denote the algebra of all bounded analytic functions in , setting
[TABLE]
Recall that is the multiplier algebra of , for , i.e. the algebra of functions such that is in for every in .
Here is the key variational lemma which will give the structure of the extremals as discussed above. We will only use the special case where is a monomial, but the proof of the lemma in this special case is identical to the proof for the general case.
Lemma 3**.**
Fix . Suppose that is a bounded linear functional on and that is an extremal for with . If such that and does not vanish in , then it holds that
[TABLE]
for every .
Proof.
Set . By (5) the extremal in the unit ball of may be written as where and are in the unit ball of and does not vanish in . If there is nothing to prove, so we therefore assume that and consider . A computation reveals that
[TABLE]
since . Hence
[TABLE]
satisfies . We then compute
[TABLE]
If , then is analytic in owing to the fact that and do not vanish in . Hence, by Hölder’s inequality and the fact that we find that is in the unit ball of . Since is extremal for , clearly for every . Using that the functional is bounded, we conclude that
[TABLE]
This inequality also holds when is replaced by and , which implies that . ∎
One final preliminary result is required. The Fejér–Riesz theorem (see [6]) states that the trigonometric polynomial is non-negative if and only if for a polynomial of degree at most .
Lemma 4**.**
Fix and let be a bounded linear functional on such that depends only on the first coefficients of . Any extremal for is given by a sequence with and a constant such that
[TABLE]
where and for . In particular, if is normalised by = 1 and as in (5), we have that and are polynomials that can be written as
[TABLE]
with suitable constants .
Proof.
We begin by writing as in (5). We use Lemma 3 with to obtain
[TABLE]
Since for , we conclude that is a trigonometric polynomial of degree at most . The non-negativity of and the Fejér–Riesz theorem implies that for some polynomial of degree at most . It is clear that , where is a finite Blaschke product and is an outer polynomial of degree at most . Since an outer function is determined up to a unimodular constant by its modulus on , we therefore find that , which means that
[TABLE]
for . Our next goal is to establish that is also a polynomial of degree at most . Suppose that is fixed as above and note that is in since . The fact that is extremal for and Hölder’s inequality implies that is an function of unit norm attaining the maximum of
[TABLE]
It is clear that (8) defines a bounded linear functional on which depends only on the first coefficients of . The Cauchy–Schwarz inequality then implies that is a polynomial of degree at most . By (5), we recall that for a inner function and a polynomial . Clearly this is only possible if the inner function is a finite Blaschke product of degree . Hence
[TABLE]
for . Since is a polynomial, we must have for . ∎
Let us now return to the bounded linear functional defined by for in . In the case , the strict convexity of yields easily that the extremal for is . Hence and in (7). In the case it is known (see e.g. [5, p. 143]) that every function of the form (6) is an extremal for .
For , we can factor the extremal as
[TABLE]
where and are polynomials related by (7). Our plan is to consider each of the cases in Lemma 4 through the Cauchy product (4). Since we may assume that for any extremal , there must be a constant such that the equation
[TABLE]
holds. Namely, otherwise we could modify to obtain equality in Cauchy–Schwarz in (4) while keeping and a fortiori , by Hölder’s inequality. By the same argument, it follows that any such (not necessarily normalized) solution of the equation (9) satisfies
[TABLE]
In practice this approach will yield a non-linear system of equations in the unknowns which needs to be solved in order to identify the candidate extremal function. We complete the program by comparing the solutions for .
Using Lemma 4 and (9) in this way, it is possible to give a (computationally) simpler proof of (3) compared to the one given in [2, Thm. 4.1].
3. Proof of Theorem 1
For define . For the functional we get from Lemma 4 that the extremal functions are of the form
[TABLE]
where with strict inequality for . We get three equations from . Recall that , so the normalizing constant is . We begin by computing
[TABLE]
where and . Hence the equation (9) becomes
[TABLE]
Note that if is a normalized solution of the equation (11), then by (10) we get
[TABLE]
The case
Here we have
[TABLE]
so the equation (11) takes the form:
[TABLE]
Recalling that we conclude that . Hence and the normalized candidate extremal function function is which has .
The case
Here we have
[TABLE]
By a rotation, we assume that and hence the equation (11) takes the form:
[TABLE]
From (13) we get that . Inserting this into (14) yields that
[TABLE]
Since we now see that is real. We then multiply (16) with and rearrange to obtain , which when inserted into (15) yields
[TABLE]
Taking the square root of this we find that
[TABLE]
where the second equality was obtained by inserting the first into (16). Note that for we see from the second equation that we have to choose the negative sign to ensure that . In the range we also have to choose the negative sign to ensure that the sign requirement from first equation also holds in the second. In particular, we get that in general. Evidently,
[TABLE]
Recalling that , we get from (12) that the normalized candidate extremal function satisfies
[TABLE]
The case
Here we have
[TABLE]
If we get the extremal (2) for with the argument squared. Assume therefore that . There are two rotations and such that . The equation (11) takes the form:
[TABLE]
From (19) we get that . Since we get from (21) that is real, and hence is real or imaginary. By (20) we see that cannot be imaginary, since . We conclude that is real. Choosing the appropriate rotation above we get that . Combining (19) and (20) yields that . Inserting this into (21) we find that
[TABLE]
We get from (12) that the normalized candidate extremal function satisfies
[TABLE]
Final part in the proof of Theorem 1
We need to compare the normalized candidate extremal functions from the equations . Clearly from can be discarded at once. Comparing (18) and (22), we claim that
[TABLE]
where and are given by (17). We recall that , so a stronger statement is
[TABLE]
where we used that . Note that . We compute
[TABLE]
For it holds that , so
[TABLE]
The final inequality is easily checked directly. Consequently
[TABLE]
We get that is increasing on by proving that in the same range, which can be deduced by checking the non-negativity of in the endpoints and at the critical point . Hence we conclude that the case provides the extremal function and that
[TABLE]
In the case we have that , so a computation yields the stated extremal function. ∎
4. Proof of Theorem 2
By Lemma 4, we get that the candidate extremal functions for the functional acting on with are of the form
[TABLE]
where with strict inequality for . There are four equations, from . Recall that and that the normalizing constant is . We begin by computing
[TABLE]
where , and . Hence the equation (9) becomes
[TABLE]
Note that if is a normalized solution to the equation (23), then by (10) we get
[TABLE]
The case
Here we get
[TABLE]
which means that the equation (23) takes the form:
[TABLE]
The only solution is , which implies . The normalized candidate extremal function is , which has .
The case
Here we get
[TABLE]
Set , and . By a rotation, we may assume that . The equation (23) takes the form:
[TABLE]
From (25) we get that . Inserting (25) into (26) and solving for yields that
[TABLE]
Inserting (25) into (27) and solving for yields that
[TABLE]
where we in the penultimate equality used (29). Inserting (25), (29) and (30) into (28) now yields
[TABLE]
Since we get that , which by (29) and (30) implies that and , respectively. Recalling that , , and , we get from (24) that the normalized candidate extremal function satisfies
[TABLE]
The case
Here we get
[TABLE]
Set , and . There are four rotations , and such that is real. The equation (23) then takes the form:
[TABLE]
From (32) we get that and . Inserting this into (33), we obtain
[TABLE]
Inserting (32) and (36) into (34), we obtain
[TABLE]
Hence we find that is real. By choosing the appropriate rotation above, we may assume that , in which case it holds that
[TABLE]
We then insert (32) and (36) into (35), keeping in mind that , to obtain
[TABLE]
The equation (38) with as in (37) has five real solutions. Before we compute them, let us recall that that , and , so we get from (31) that in each case the normalized candidate extremal function satisfies
[TABLE]
The first two solutions of (38) arise from the case , which occurs when and . Here we easily find from (39) that
[TABLE]
If , we may multiply (38) by , then insert the value for and simplify to obtain
[TABLE]
This equation has the following solutions:
[TABLE]
Inserting these and the corresponding and into (39) yields, respectively,
[TABLE]
The case
Here we get
[TABLE]
There are three rotations, , and such that . The equation (23) takes the form:
[TABLE]
The first equation shows that . We insert it into the others and obtain:
[TABLE]
Our goal is to show that (and hence ) is real. We begin with (43). Inserting the conjugate of (42), multiplying with and applying (44) yields
[TABLE]
Hence is real, so we may choose a rotation above to ensure that is real. Note now that if and only if , which leads to the extremal (2) for with the argument cubed. Hence we assume . Since know that and are real and non-zero, we insert (42) into (43) to obtain that
[TABLE]
where we used (42) again for the second implication. Inserting the values for and into (44) yields the equation . Since there are only two solutions:
[TABLE]
Recalling that , we get from (24) that the normalized candidate extremal function satisfies
[TABLE]
To maximize this, we choose the negative sign in the expression for , which yields that and the value in (45).
Final part in the proof of Theorem 2
We need to compare the candidate extremal functions from the equations . Clearly from can be discarded at once. Comparing (31), (40), (41) and (45) we find that the latter is the largest. Hence the case provides the extremal function so that
[TABLE]
In the case we have , so a computation yields the stated extremal function. ∎
5. Concluding remarks
5.1.
Our first observation is that neither the extremal for from (2) nor the extremals for and from Theorem 1 and Theorem 2, respectively, vanish in . This is of course a consequence of the fact that the extremals in each case stem from the case in Lemma 4.
Conjecture 1*.*
For any extremal for does not vanish in .
If we a priori knew that Conjecture 1 held, it would significantly decrease the effort needed to prove Theorem 1 and Theorem 2, since it would be sufficient to consider only the case . Apart from the above-mentioned examples we have little concrete evidence for the conjecture. However, the following weaker statement could be a starting point.
Conjecture 2*.*
For the sequence is strictly increasing.
Conjecture 2 is equivalent to the following statement: For any extremal for does not vanish at the origin. Indeed, if for some then we can multiply an extremal for with to obtain an extremal for vanishing at the origin. Conversely, if an extremal for vanishes at the origin, then we find that by dividing the extremal by . Note that this is precisely how the extremals can be obtained in the range , where it holds that for every .
5.2.
Let denote the subset of consisting of the elements which do not vanish in . Suffridge [13] investigated the extremal problem
[TABLE]
Clearly it holds that . By Lemma 4 (see also [5, p. 143]) this is an equality when . For this inequality is strict, by the strict convexity of and the fact that are not in .
Note that Conjecture 1 is equivalent to the claim for and . In particular, we observe that [2, Thm. 4.1] and Theorem 1 extend the statements for in [13, Thm. 2] and [13, Thm. 7], respectively.
The approach employed in [13] to study is related to the approach of the present paper to study . The difference is that the version of Lemma 4 for does not contain a Blaschke product, but instead contains a singular inner function. It is conjectured on [13, p. 187] that this singular inner function is trivial when . This conjecture is evidently a consequence of Conjecture 1 in view of Lemma 4.
5.3.
Fix and let denote the subset of consisting of the elements for which . For , consider the extremal problem
[TABLE]
This extremal problem was solved by Beneteau and Korenblum [1] in the range as follows. They first demonstrate that holds for every using F. Wiener’s trick, which relies on the triangle inequality. Following this, they solve the extremal problem directly in the case using the factorization similarly to how we used the factorization above. Inspecting the solution, it is easy to verify that the function is decreasing from to .
We make a couple of comments on this extremal problem in the range . Since the triangle inequality here takes the form
[TABLE]
we find by F. Wiener’s trick that . This estimate should be compared with the Hardy–Littlewood estimate mentioned in the introduction. The situation for is also different, since by (2) and (3) we find that the maxima of the function is in the range attained at .
5.4.
The dual space of with , is (non-isometrically) identified in [4] through the embedding
[TABLE]
where denotes Lebesgue area measure and . The embedding is, of course, also due to Hardy and Littlewood [7]. It is conjectured (see e.g. [3, Sec. 2]) that for every , but this is known to hold only when is an integer. Assuming that this conjecture holds, we can obtain the estimate
[TABLE]
For comparison with Theorem 1 and Theorem 2, we record the special cases
[TABLE]
Acknowledgements
The authors would like to extend their gratitude to Kristian Seip for several helpful conversations in the early phase of the project and to the anonymous referee for pointing out an inaccuracy in a draft of the paper and for helpful comments that increased the readability of the paper.
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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