Fano manifolds containing a negative divisor isomorphic to a rational homogeneous space of Picard number one
Jie Liu

TL;DR
This paper classifies complex Fano manifolds containing a special negative divisor isomorphic to a rational homogeneous space with Picard number one, extending previous research in algebraic geometry.
Contribution
It provides a complete classification of pairs (X, A) where X is a Fano manifold and A is a rational homogeneous divisor with an ample conormal bundle.
Findings
Complete classification of pairs (X, A) under given conditions.
Extension of previous classification results by Tsukioka, Watanabe, Casagrande-Druel.
Identification of new geometric structures in Fano manifolds.
Abstract
Let be an -dimensional complex Fano manifolds . Assume that contains a divisor , which is isomorphic to a rational homogeneous space with Picard number one, such that the conormal bundle is ample over . Building on the works of Tsukioka, Watanabe and Casagrande-Druel, we give a complete classification of such pairs .
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Fano manifolds containing a negative divisor isomorphic to a rational homogeneous space of Picard number one
Jie Liu
Jie Liu, Institute of Mathematics, Academy of Mathematics and Systems Science, Chinese Academy of Sciences, Beijing, 100190, China
Abstract.
Let be an -dimensional complex Fano manifolds . Assume that contains a divisor , which is isomorphic to a rational homogeneous space with Picard number one, such that the conormal bundle is ample over . Building on the works of Tsukioka, Watanabe and Casagrande-Druel, we give a complete classification of such pairs .
Key words and phrases:
Fano manifolds, rational homogeneous spaces, extremal contraction, Mori theory
2010 Mathematics Subject Classification:
14J45, 14M17, 14E30
Contents
1. Introduction
Throughout this paper, we work over the complex numbers. As an application of Mori theory, Mori and Mukai succeeded in classifying Fano threefolds by viewing extremal rays in details [MM81]. In general it is very difficult to describe the extremal rays and contractions of higher dimensional Fano manifolds. However, if there exists a "special" divisor on , then it is possible to get various information about . For example, Watanabe classified Fano manifolds containing an ample divisor isomorphic to a homogeneous space in [Wat08].
1.1**.**
Theorem.[Wat08, Theorem 1]*
Let be a projective manifold of dimension containing an ample divisor isomorphic to a rational homogeneous space. If , then the pair is isomorphic to one of the following:*
- (1)
; 2. (2)
* and ;* 3. (3)
* and ;* 4. (4)
* and , where is the Grassmannian of -dimensional subspaces in an -dimensional vector space and is the ample generator of the Picard group of ;* 5. (5)
, where is the -dimensional rational homogeneous space of type and is the ample generator of the Picard group of .
On the other hand, Bonavero, Campana and Wiśniewski gave the classification of -dimensional complex Fano manifolds containing a divisor isomorphic to with normal bundle in [BCW02, Theorem 1]. Some years latter, in [Tsu06], Tsukioka generalized this result to the case where is isomorphic to for some integer . In particular, Tsukioka proved in [Tsu06, Proposition 5] that if an -dimensional Fano manifold contains a prime divisor with , then . In [CD15, Lemma 3.1 and Theorem 3.8], Casagrande and Druel described in details the extremal contractions of such a pair and gave a general classification of such pairs in the extremal case .
The main result of this note is to generalize the results of [Tsu06] and [BCW02] to the case where is isomorphic to a rational homogeneous space with Picard number one.
1.2**.**
Theorem.* Let be a Fano manifold of dimension containing a divisor isomorphic to a rational homogeneous space with Picard number one. Denote by the ample generator of and by the index of . Assume that is isomorphic to for some integer . Then and we are in one of the following cases.*
- (1)
* and the pair is isomorphic to one of the following:*
- (1.1)
* is isomorphic to and is a section with normal bundle ;* 2. (1.2)
* is obtained by blowing up one of the pairs listed in Theorem 1.1 along a smooth center , where is the ample generator of , and is the strict transform of .* 3. (1.3)
* is a smooth element in and is isomorphic to a quadric hypersurface such that , where is the vector bundle , the map is the natural projection and the variety is the subbundle corresponding to the quotient .*** 2. (2)
* and is obtained by blowing up a Fano manifold along a smooth center such that , where is isomorphic to , is a section with normal bundle , is the ample generator of and is the strict transform of .*
1.3**.**
Remark. In the published version of this paper [Internat. J. Math., 2020, 31, 2050066, 14], the case (1.3) is missed in the statement. The mistake appears in the proof of Lemma 3.2, which is false in general. See Appendix A for the correction.
Acknowledgements
I would like to thank Baohua Fu for patiently answering my numerous questions. This work is supported by China Postdoctoral Science Foundation (2019M650873). I want to thank the referee for pointing out some inaccuracies in the first version.
2. Examples and inextendability criterion
2.A. Examples
In this subsection, we collect some examples of Fano manifolds.
2.1**.**
Example. Let be a pair where is a Fano manifold with for some ample and is a smooth member with . Assume that the restriction is surjective. Denote by the ample generator of . Suppose moreover that is a Fano manifold with index . For a given positive integer , we choose a smooth member and denote by the blow-up of along . Let be the strict transform of in . Then is isomorphic to .
2.2**.**
Lemma.* In Example 2.1, is a Fano manifold if and only if .*
Proof.
Firstly we show . Denote by the exceptional divisor of . By assumption, we have
[TABLE]
and
[TABLE]
It follows immediately that .
Next we show that is ample. As , we can assume that and are the generators of . Moreover, by the construction, we may assume that is generated by the curves contained in the fibers of the blow-up . We claim that is generated by curves contained in . Indeed, to see this, it suffices to find a non-trivial nef -divisor such that . We set
[TABLE]
Then we have . Moreover, since is nef and big and is effective, we obtain for any irreducible curve not contained in . In particular, is nef and consequently is generated by curves contained in .
Finally, note that is an extremal contraction, we have . Moreover, by the adjunction formula, we get
[TABLE]
Hence, by Kleiman’s criterion, is ample if and only if . ∎
2.3**.**
Example. Fix integers and such that . Let be a Fano manifold of dimension , with and index . Let be the ample generator of . Set , and denote by the natural projection.
2.4**.**
Lemma.* In Example 2.3, is a Fano manifold if and only if .*
Proof.
As , we shall denote by and the generators of . Moreover, as is an extremal contraction, we may assume that is generated by the curves contracted by . On the other hand, since is isomorphic to , without loss of generality, we shall assume that . If , then is isomorphic to the product , and it is clear that is a Fano manifold. Thus we may assume that .
Let be the section of with normal bundle , and let be a section of with normal bundle . Then is disjoint from . In particular, we have . Moreover, as , is nef. Therefore, is generated by the curves contained in .
As is an extremal contraction, we have . On the other hand, by the adjunction formula, we get
[TABLE]
Hence, by Kleiman’s criterion, is ample if and only if . ∎
2.5**.**
Example. Let be a Fano manifold as in Example 2.3, and let be a section of with normal bundle . Suppose that is a smooth hypersurface of such that for some . Denote by the blow-up of along .
2.6**.**
Lemma.* In Example 2.5, is a Fano manifold if and only if , where is the index of .*
2.7**.**
Remark. This result is proved in the case by Casagrande and Druel in [CD15, Example 3.4 and Lemma 3.5] and a slight modification of the argument can be applied to the case . We include a proof for the reader’s convenience.
Proof.
If , it is proved in [CD15, Lemma 3.5 and Remark 3.6]. Thus we may assume that . Denote by the divisor and denote by the exceptional divisor of . Let (resp. ) be the strict transform of (resp. ) in . Note that is isomorphic to . Let be a fiber of the contraction . Then we obtain
and .
Moreover, let be an ample divisor on . Then . As a consequence, we can find an extremal ray of such that
and .
Then one can easily see that is actually generated by . Let be the associated contraction. Then both and are smooth and is the blow-up of along the codimension submanifold (see [Wiś91, Theorem 1.2]).
As , is generated by two rays and . In the following, we give a detail description of these two rays. Denote by and the strict transforms of in and , respectively. Then and are isomorphic to . Moreover, as is disjoint from , we get
[TABLE]
and
[TABLE]
By assumption, we have and . As consequence, the ray generated by curves contained in is an extremal ray of and we will denote it by . On the other hand, let be a general fiber of . Then the birational map
[TABLE]
is an isomorphism in a neighborhood of . Denote its image by . Then we have
[TABLE]
On the other hand, let be the strict transform of in . Then we get
[TABLE]
As a consequence, is nef and so is . Since is disjoint from , we have . Hence, is generated by and it is an extremal ray of . In particular, is a Fano manifold.
Let be the extremal contraction associated to . Then is of fiber type since the strict transform of every general fiber of is contracted by . Moreover, as , it follows that and is a -bundle (see [Fuj87, Lemma 2.12]). In particular, we have the following factorization:
[TABLE]
Thanks to [CD15, Lemma 3.9], is isomorphic to . Let be a section of with . Then one can see that the strict transform of in is a section of containing such that
[TABLE]
Then applying [CD15, Lemma 3.5 and Remark 3.6] to shows that is a Fano manifold if and only if . ∎
2.8**.**
Remark. In Theorem 1.2, the restriction is ample, thus we have always . In particular, the examples given above show that the projective manifolds provided in Theorem 1.2 are indeed Fano manifolds.
2.B. Projective extension
Recall that an irreducible non-degenerate smooth projective variety is called projectively extendable if there exists a projective variety and a hyperplane such that intersects transversely, and is not a cone. In this case, is called a projective extension of . The following inextendability criterion due to Zak is very useful (see also [Lv92, Theorem 0.1 and Corollary 1]).
2.9**.**
Theorem.[Zak91, Corollary 3]* If is an irreducible, non-degenerate, smooth projective variety such that , then either is a twisted cubic curve or a quadric or is inextendable.*
Let be a projective variety. Recall that a line bundle over is called simply generated if the graded algebra
[TABLE]
is generated by as a -algebra. Moreover, a line bundle is very ample if is ample and simply generated. Using this notion we have the following useful very ampleness criterion.
2.10**.**
Proposition.* Let be a normal projective and let be an ample line bundle on . Suppose that is a member which is irreducible and reduced as a subscheme of . If and is simply generated, then is very ample.*
Proof.
It suffices to prove that is simply generated. As , the restriction map is surjective. Since is simply generated, then [Fuj90, Chapter I, Corollary 2.5] says that is itself simply generated. ∎
As a consequence of Proposition 2.10, one can easily derive the following variant of Theorem 2.9.
2.11**.**
Proposition.* Let be a normal projective variety of dimension , and let be an ample line bundle over . Suppose that and is a scheme-theoretically smooth member with simply generated. If , then one of the following statements holds.*
- (1)
The map defined by the complete linear system is an embedding which sends to a cone over . 2. (2)
The pair is isomorphic to , where is a quadric hypersurface of dimension .
Furthermore, suppose in addition that is smooth, then the pair is isomorphic to either or .
Proof.
Since is an ample divisor on and , is connected. It follows that is irreducible for being smooth. Then, by Proposition 2.10, is a very ample line bundle over .
Denote by the embedding defined by the complete linear system . As , we have . In particular, as is smooth, there exists a hyperplane of such that intersects transversely and . Therefore, by the definition of projective extension, either is a cone over or is a projective extension of .
According to Theorem 2.9, if is a projective extension of , then is a quadric hypersurface in because .
Suppose now that is smooth. If case (1) holds, then is smooth if and only if is a projective space. In particular, the pair is isomorphic to and must be isomorphic to . If case (2) holds, then it is well known that is isomorphic to (see for instance Theorem 1.1). ∎
3. Proof of Theorem 1.2
This section is devoted to prove Theorem 1.2. Since is a negative divisor on , we get . On the other hand, as mentioned in the introduction, according to [Tsu06, Proposition 5], we also have .
3.A. Case
The proof of the following lemmas can be adapted from that of [Tsu06, Lemma 1 and Lemma 2], and follows some strategies used in [BCW02].
3.1**.**
Lemma.* Let be the blow-up of a projective manifold along an irreducible smooth center of codimension . Suppose that is a smooth irreducible hypersurface such that and there exists a birational morphism onto a projective variety sending to a point. Then the restriction is an isomorphism.*
Proof.
Denote by the exceptional divisor of . If is disjoint from , it is clear that is an isomorphism. Now we shall asume that is not empty. Set . Then the restriction sends to a point. By [CD15, Lemma 3.9], is a section of the -bundle with conormal bundle ample. On the other hand, as and is effective, the line bundle is ample. In particular, is different from and consequently is generically reduced. As is Cohen-Macaulay, is actually reduced. In particular, we have . Hence, the restriction map is an isomorphism. ∎
3.2**.**
Lemma.* Let be a Fano manifold of dimension and with , and let be a smooth Fano hypersurface of such that for some ample line bundle and for some . Assume furthermore that is covered by lines, i.e. for any point , there exists a rational curve passing through such that . If admits an extremal contraction , which is a conic bundle, such that is finite over , then is a section of . In particular, is a -bundle and is isomorphic to .*
3.3**.**
Remark. This statement is false in general. See Lemma A.2 fo the correct statement. The mistake appears in the computation of the value of , which should be , not .
Proof.
Denote by the index of , i.e., . As is Fano, the line bundle is ample. We get . Since is not nef and is Fano, there exists an extremal ray of such that . Let be the associated contraction. Then as . On the other hand, every curve contained in has class in since and is negative. This implies that and that is a point. By adjunction, we have
[TABLE]
Denote by . Since and the contraction map is supposed to be elementary, there exist such that
[TABLE]
Denote by the degree . Set and . Then we get
[TABLE]
and
[TABLE]
Set . Then the proof of [Tsu06, Lemma 1] can be applied verbatim in our case to obtain that is an integer and .
To prove , as in the proof [Tsu06, Lemma 1], it suffices to exclude the case and . Indeed, if , then we must have . By Kobayashi-Ochiai’s theorem, then is isomorphic to , which is impossible as shown in the proof of [Tsu06, Lemma 1]. Thus, we have and as a consequence, we have
[TABLE]
On the other hand, by (3.1) and (3.2), we have
[TABLE]
It yields
[TABLE]
and
[TABLE]
It follows that
[TABLE]
Hence, as , we have . Consequently, is isomorphic to and is a section of (see [Fuj87, Lemma 2.12]) ∎
Now we are in the position to prove the first part of Theorem 1.2. Let us recall that rational homogeneous spaces are covered by lines, see for instance [Kol96, V, Theorem 1.15].
Proof of Theorem 1.2 (1).
Denote by and the extremal rays of and, without loss of generality, we shall assume (cf. [CD15, Lemma 3.1]). Then we have the following diagram:
[TABLE]
where (resp. ) is the extremal contraction corresponding to (resp. ). Since is not nef, by [CD15, Remark 3.2], and is a divisorial contraction sending to a point. Furthermore, by [CD15, Lemma 3.1], the possibilities of are as follows:
- (a)
is a conic bundle, finite on , such that is a Fano manifold; 2. (b)
is the blow-up of along a smooth center of codimension and is a Fano manifold.
Suppose first that is a conic bundle. Then the restriction is surjective. Since is a rational homogeneous space of Picard number one, according to [HM99, Main Theorem], then either or is an isomorphism. Moreover, if is isomorphic to , by Lemma 3.2, is also a section of . In particular, is actually a -bundle. Then [CD15, Lemma 3.9] shows that is isomorphic to , where is an ample line bundle over and identifies with the section of corresponding to . It follows that we have and we are in case (1.1).
We assume now that is a divisorial contraction. Thanks to Lemma 3.1, the restriction map is an isomorphism. On the other hand, as , is an ample divisor in . Then the pair is one of the possibilities listed in Theorem 1.1. Moreover, as , is a smooth hypersurface in . In particular, there exists a positive integer such that . Then a straightforward computation shows that is isomorphic to . Thus, we get , where and we are in case (1.2). ∎
3.B. Case
Let be a normal projective variety. We denote by the vector space of -cycles, with real coefficients, modulo numerical equivalence. For any closed subset , we denote by the subspaces of generated by classes of curves contained in . The following result due to Casagrande and Druel provides a classification of Fano manifolds of maximal Picard number containing a prime divisor with ; see [Fuj12] for related results.
3.4**.**
Theorem.[CD15, Lemma 3.1 and Theorem 3.8]*
Let be a Fano manifold of dimension and let be a prime divisor with . Then . Moreover, if , then is isomorphic to the blow-up of a Fano manifold along an irreducible submanifold of dimension contained in a section of the -bundle , where is a Fano manifold of dimension and .*
Though we are interested in the case where is a negative divisor, to prove the second part of Theorem 1.2, we still need to deal with the case where is a nef divisor. In particular, we prove the following preliminary result, which may be of independent interest.
3.5**.**
Proposition.* Let be an -dimensional Fano manifold with and . Assume that contains a nef divisor isomorphic to a rational homogeneous space of Picard number one. Let be the ample generator of . Denote by and the extremal rays of so that , and let and be the associated extremal contractions, respectively. Assume moreover that is a -bundle and is not small. Then one of the following statements holds.*
- (1)
* is isomorphic to , where is the index of , and is a section with normal bundle .* 2. (2)
* is isomorphic to the blow-up of at a point (or, equivalently, is isomorphic to the -bundle , and is the strict transform of a smooth quadric hypersurface in not containing .*
Proof.
By our assumption and [CD15, Lemma 3.1], we have a diagram:
[TABLE]
where is a Fano manifold and is finite over . Since is not small, by [CD15, Proposition 3.3], either is a fiber type contraction onto , having as a fiber, or is a divisorial contraction sending its exceptional divisor to a point and . If is a fiber type, then is isomorphic to (see [Cas09, Lemma 4.9]) and we are in case (1) with .
Now we shall assume that is birational. Then is a Fano variety with only -factorial terminal singularities so that . Since is a birational map sending to a point, by [CD15, Lemma 3.9], there exists an ample line bundle over , where is the ample generator of and , such that is isomorphic to so that the exceptional divisor of identifies with the section corresponding to the projection . On the other hand, since is a rational homogeneous space of Picard number one and the restriction is surjective, according to [HM99, Main Theorem], then either is a section of or is isomorphic to the projective space . If is a section of , then is isomorphic to . In particular, is isomorphic to . On the other hand, since is disjoint from the negative section , it follows that corresponds to a quotient . In particular, we are in case (1) with .
In the sequel we shall assume that is isomorphic to and is not a section of . Then is isomorphic to . Denote by the pull-back . Then there exist such that because is a Fano manifold with . On the other hand, note that we have
and .
Thus, both and are positive integers and . Set . Then . Since is not a section of , we must have . On the other hand, as and is an extremal contraction, by the Cone Theorem (see [KM98, Theorem 3.7]), there exists a line bundle on such that . Then we have
[TABLE]
Since is disjoint from and is an isomorphism outside , is contained in the smooth locus of and it is isomorphic to . As and is -factorial, is an ample Cartier divisor on . Moreover, since is a Fano variety, by Kawamata-Viehweg vanishing theorem, we have . Then, by Proposition 2.10, the line bundle is very ample. Denote by the embedding defined by .
As , we have for any curve . In particular, is not a cone over . Moreover, note that the pair is not isomorphic to as . By Proposition 2.11, we have
[TABLE]
Therefore, by [MS99, Theorem B], the possibilities of the pair are as follows:
[TABLE]
As and is Cartier, one can easily see that is the ample generator of . On the other hand, note that the case can not happen, because in this case we have
[TABLE]
which is impossible. If is isomorphic to , then we have
[TABLE]
Furthermore, since is a Fano manifold with and is ample, by Kawamata-Viehweg vanishing theorem, we have . As a consequence, from the following exact sequence
[TABLE]
we obtain
[TABLE]
Then, according to [Fuj90, Chapter I, Theorem 1.1], the pair is isomorphic to . We claim that in this case. Indeed, note that is the tautological bundle , where , so we have
[TABLE]
On the other hand, note that , by the adjunction formula, we have
[TABLE]
Combining (3.3) and (3.4) yields
[TABLE]
This is possible if and only if because is not numerically proportional to . Hence, is isomorphic to and we are in case (2). ∎
Now we are ready to prove the second part of Theorem 1.2. It can be regarded as a refinement of Theorem 3.4.
Proof of Theorem 1.2 (2).
By the proof of [CD15, Theorem 3.8], there exists a blow-up along a smooth center of codimension , is smooth and Fano, and , where is the extremal ray of generated by the class of a curve contracted by . Moreover, there exists a Fano manifold of dimension , and a -bundle . Set . Thanks to Lemma 3.1, the restriction is an isomorphism. Note that is contained in and we will denote by the positive integer such that .
First suppose that is not nef in . Then the pair is isomorphic to one of the varieties listed in Theorem 1.2 (1.1); that is, and is a section of with normal bundle . Moreover, the normal bundle is isomorphic to . Thus it follows that and . Thus, we are done in this case.
We assume now that is nef in . By [CD15, Proposition 3.3], does not admit small contractions. Therefore the pair is isomorphic to one of the varieties listed in Proposition 3.5.
We claim that case (2) of Proposition 3.5 cannot happen. Otherwise, is isomorphic to the blow-up of at a point . Denote by the blow-up. Then is contained in a section of . We note that is a the strict transform of a hyperplane passing through under . In particular, is contained in and consequently is a hyperplane section of . Then a straightforward computation shows that is isomorphic to , a contradiction.
Finally suppose that we are in case (1) of Proposition 3.5; that is, the pair is isomorphic to and is a section with normal bundle . Then the normal bundle is isomorphic to . Thus we have and . ∎
Appendix A Corrigendum
The purpose of this note is to make a correction to [Liu20]. In [Liu20, Theorem 1.2], we give a classification of pairs such that is a Fano manifold of dimension and is a smooth ample divisor which is isomorphic to some rational homogeneous space of Picard number and the conormal bundle is ample. However, it turns out that there exists one case missed in the statement of the theorem and [Liu20, Theorem 1.2] should be read as follows.
A.1**.**
Theorem.* Let be a Fano manifold of dimension containing a divisor isomorphic to a rational homogeneous space with Picard number one. Denote by the ample generator of and by the index of . Assume that is isomorphic to for some integer . Then and we are in one of the following cases.*
- (1)
* and the pair is isomorphic to one of the following:*
- (1.1)
* is isomorphic to and is a section with normal bundle ;* 2. (1.2)
* is obtained by blowing up one of the pairs listed [Wat08, Theorem 1] along a smooth center , where is the ample generator of , and is the strict transform of .* 3. (1.3)
* is a smooth element in and is isomorphic to a quadric hypersurface such that , where is the vector bundle , the map is the natural projection and the variety is the subbundle corresponding to the quotient .*** 2. (2)
* and is obtained by blowing up a Fano manifold along a smooth center such that , where is isomorphic to , is a section with normal bundle , is the ample generator of and is the strict transform of .*
The mistake appears in the proof of [Liu20, Lemma 3.2] and the statement of [Liu20, Lemma 3.2] is false in general. Indeed, in the proof of [Liu20, Lemma 3.2], the value of should be
[TABLE]
while in the published paper in the denominator disappeared. In particular, the last equation in the same page should be as which is trivial. We correct [Liu20, Lemma 3.2] in Lemma A.2 by proving a weaker statement; that is, the number is an integer. In particular, for being a rational homogeneous space of Picard number , Lemma A.2 can be applied to show that is actually a section of the conic bundle unless it is isomorphic to a quadric hypersurface or the -dimensional spinor variety . Then by a detailed analysis of the conic bundle structure , we exclude the spinor variety case by an ad-hoc argument.
Here is the organisation of this short note. In Section A.A we give an explicit construction of examples for the new case (1.3) of Theorem A.1. In Section A.B we prove a weaker statement of [Liu20, Lemma 3.2] to show that is an integer and then applying it to show that in [Liu20, Lemma 3.2] if is assumed to be a rational homogeneous space of Picard number , then is a section of unless is isomorphic to a quadric hypersurface. Finally we finish the proof of Theorem A.1 by pointing out the parts affected by [Liu20, Lemma 3.2].
A.A. Examples
In this subsection, we construct some examples for case (1.3) of Theorem A.1. We start from the following example (see [Liu20, Proposition 3.4 (2)]). Let be the vector bundle with . Then is isomorphic to the blowing-up of at a point. Denote by the blowing-up and let be the exceptional divisor. Denote by the tautological divisor of and by the natural projection. Let be a Weil divisor associated to the pull-back . Then we have
[TABLE]
Let be a general smooth member in such that is disjoint from . Then is isomorphic to an -dimensional quadric hypersurface. Consider the the vector bundle which is isomorphic to with . Then is a smooth prime divisor. Denote by the tautological divisor of and by a Weil divisor associated to the pull-back . Then we have
[TABLE]
Recall that the restriction is isomorphic to and . Consider the following short exact sequence
[TABLE]
As , we have
[TABLE]
As and , is ample. By Kodaira’s vanishing theorem, we have . In particular, the induced morphism
[TABLE]
is surjective and there exists a divisor such that . Moreover, as is general and is globally generated, we may assume that is again smooth. Note that we have
[TABLE]
On the other hand, as , we get
[TABLE]
Now we claim that is a Fano manifold. By adjunction formula, we have
[TABLE]
If , then is a semi-ample big and nef divisor with non-ample locus contained in . By our construction, the variety is disjoint from , thus the restriction is ample and hence is ample.
A.B. Correction of [Liu20, Lemma 3.2]
As pointed out in the beginning, [Liu20, Lemma 3.2] is not correct in general. We replace it by the following weaker statement.
A.2**.**
Lemma.*
Let be a Fano manifold of dimension and with , and let be a smooth Fano hypersurface of such that for some ample line bundle and for some . Assume furthermore that there exists a curve of degree on ; i.e. an irreducible curve such that . If admits an extremal contraction , which is a conic bundle, such that is finite over . Then and is an integer, where .*
Proof.
Denote by the index of , i.e., . As is Fano, the line bundle is ample. We get . Since is not nef and is Fano, there exists an extremal ray of such that . Let be the associated contraction. Then as . On the other hand, every curve contained in has class in since and is negative. This implies that and that is a point. By adjunction, we have
[TABLE]
Let be a Weil divisor associated to . Since and the contraction map is supposed to be elementary, there exist such that
[TABLE]
Denote by the degree . Set and . Then we get
[TABLE]
and
[TABLE]
Set . Now we follow the argument of [Tsu06, Lemma 1] to show that . By (A.1), we have
[TABLE]
Combining (A.1) and (A.2) yields
[TABLE]
This implies
[TABLE]
It follows
[TABLE]
As is an integer, it follows that
[TABLE]
is an integer. In particular, is an integer. As , we obtain
[TABLE]
As is an integer and , we must have . Moreover, if , we have , hence . On the other hand, as , we have . In particular, as , we obtain . If , then we must have . By Kobayashi-Ochiai’s theorem, then is isomorphic to , which is impossible by [Tsu06, Lemma 1]. Thus, we have and as a consequence, we have
[TABLE]
In particular, we get . As a consequence, we obtain
[TABLE]
It yields
[TABLE]
This implies
[TABLE]
As is an integer, it follows that is an integer. On the other hand, set , we also have
[TABLE]
As and are integers, it follows that is an integer. This implies that is an integer. In particular, we have . ∎
The remaining part of this section is devoted to prove the following result, which will be used to finish the proof of Theorem A.1.
A.3**.**
Proposition.*
In Lemma A.2, if we assume in addition that is isomorphic to a rational homogeneous space of Picard number , then is a section of unless is isomorphic to a quadric hypersurface.*
The proof of Proposition A.3 above will be divided into two different parts. In the first part, we show that a rational homogeneous space of Picard number satisfies if and only if it is isomorphic to one of the following: a projective space, a quadric hypersurface, the Grassmann variety and the -dimensional spinor variety . The projective space cases are proved in [Tsu06] and the Grassmann variety can be easily excluded by the fact that is an integer for some . In the second part, we exclude the spinor variety case by studying the conic bundle structure carefully.
A.B.1. Rational homogeneous space of small degrees
Now we proceed to classify rational homogeneous spaces of Picard number satisfying .
A.4**.**
Proposition.*
Let be an -dimensional rational homogeneous space of Picard number with degree and index . Then if and only if is isomorphic to one of the following varieties:*
- (1)
a projective space with and ; 2. (2)
a quadric hypersurface with and ; 3. (3)
the Grassmann variety with and ; 4. (4)
the -dimensional spinor variety with and .
A.5**.**
Theorem.* [Ion08]
Let be an -dimensional irreducible, smooth, non-degenerate and linearly normal projective variety of degree . Assume that is a Fano manifold of Picard number such that and . If , then has index at least .*
Proof.
Denote by the codimension of . Then we have by assumption. Firstly we assume that . Then we have
[TABLE]
As has Picard number , it follows from [Ion85, Theorem I] that has index at least .
Secondly we assume that . Let be the -genus of . If , it is well known from the classification of Fano manifolds that is has index (see for instance [Ion08, Theorem A and B]). Thus we may assume that . Then it follows from [Ion08, Propoistion 10] that has index . ∎
A.6**.**
Lemma.*
Let be an -dimensional rational homogeneous space of Picard number . If , then is isomorphic to one of the following*
, , , , , , .
In particular, if and only is isomorphic to one of the varieties listed in Proposition A.4.
Proof.
This is well-known from the classification of Fano manifold of index at least , see [IP99, Theorem 3.1.14, Table 12.1 and Theorem 5.2.3]. In particular, the corresponding pairs are as follows
, , , , , .
This finishes the proof. ∎
A.7**.**
Lemma.*
Let be a rational homogeneous space of Picard number , with index . Let be the ample generator of . Then if and only if is isomorphic to either or .*
Proof.
We refer the reader to [Kon86, Table 1] for the explicit values of and in terms of and . We just remark that in [Kon86, Table 1], the index of is denoted by and the node is denote by . Moreover, we also recall that is isomorphic to the -dimensional quadric hypersurface . In particular, if is of E-F-G type, it can be easily shown that if and only if is isomorphic to , where . Now we prove it for being of classical type. In the following table, we collect the values of and for of classical types. Here we remark that is isomorphic to and it is also isomorphic to which is called the spinor variety , and is isomorphic to which is the projective space .
- (1)
. Firstly we note that is isomorphic to . Thus we may assume that . Moreover, is isomorphic to the projective space and is isomorphic to which is the -dimensional quadric hypersurface. For , by our assumption, we have
[TABLE]
This implies that and ; that is, is isomorphic to . 2. (2)
. Firstly we note that is isomorphic to the -dimensional quadric hypersurface . If , by our assumption, we have
[TABLE]
which is obviously impossible. 3. (3)
. Firstly we note that is isomorphic to the -dimensional quadric hypersurface. By our assumption, we have since is very ample. Recall that the dimension of is as follows:
[TABLE]
Thus, if , then we have
[TABLE]
which is possible only if . Nevertheless, if , then we have and , which is impossible as . Thus we may assume that . Then we obtain
[TABLE]
which is impossible unless . On the other hand, note that is isomorphic to the -dimensional quadric hypersurface, which is again impossible. 4. (4)
and . Firstly we note that is the -dimensional quadric hypersurface. For , by our assumption, we have
[TABLE]
which is impossible as . 5. (5)
and . If , the variety is isomorphic to , and the -dimensional quadric hypersurface . Thus, we may assume that . Then by our assumption, we obtain
[TABLE]
which is impossible.
This finishes the proof. ∎
Now we are in the position to prove Proposition A.4.
Proof of Proposition A.4.
Let be the ample generator of . Then is very ample. Denote by .
If , by Lemma A.7, is isomorphic to either a projective space or a quadric hypersurface.
If , then we get and therefore Theorem A.5 implies that either has index , or . In the former case, we can conclude by lemma A.6. In the latter case, we note that is quadric; that is, the embedding is scheme-theoretically cut out by quadric hypersurfaces. Then is actually a complete intersection in (cf. [IR13]). Hence, is actually a quadric hypersurface. ∎
A.B.2. Fano conic bundles
Let be an -dimensional Fano conic bundle with , i.e., is a Fano manifold and is a conic bundle structure. Denote by the locally free sheaf of rank . Let be the tautological divisor of . Denote by the integer such that . Let be a Weil divisor associated to , where is the natural projection. Then can be embedded in as a divisor such that
[TABLE]
Let be an irreducible smooth divisor which is a Fano manifold of Picard number such that is the ample generator of and for some . Denote by the degree of with respect to and by the induced finite morphism. Let be the index of .
A.8**.**
Lemma.*
Let be a non-zero morphism of coherent sheaves. If , then there exists an integer such that and*
[TABLE]
Proof.
Let be the image of and denote by the reflexive hull of . Then we have . In particular, the generically surjective morphism defines a rational section such that there exists a Zariski open subset satisfying
- (1)
; 2. (2)
is an isomorphism; 3. (3)
.
Take a log resolution such that is an isomorphism over and denote by the induced birational morphism. Then we have
[TABLE]
where is a -exceptional divisor. Since is -ample, the pull-back is -nef. Then the negativity lemma implies that is effective.
Claim 1. Let be an irreducible projective curve such that . Then we have .
Proof of Claim 1. By assumption, the intersection is empty. Let be the strict transform of . Then we have
[TABLE]
This finishes the proof of Claim 1.
Note that is ample, thus Claim 1 implies that the image is contained in . In particular, let be a general line and let be the section corresponding to the quotient . Then is disjoint from . In particular, we have
[TABLE]
As a consequence, we have .
Claim 2. The morphism is surjective.
Proof of Claim 2. Let be an arbitrary point and let be a general line passing through such that . We consider the restriction
[TABLE]
We claim that is surjective. Otherwise, let be the image of . Then we must have for some . Let be the section corresponding to the quotient . Then we obtain
[TABLE]
In particular, is contained in and , which is impossible as is ample. This finishes the proof of claim 2.
Claim 3. The vector bundles splits as a direct sum of line bundles as follows
[TABLE]
Proof of Claim 3. Firstly note that we have . Thus admits a quotient line bundle with the corresponding section such that
[TABLE]
where is the induced morphism.
On the other hand, let be the section corresponding to the induced quotient line bundle . Then we have . By Claim 2, is a section of such that . This yields that is disjoint from and hence is disjoint from . Thus, is also disjoint from . Let be the kernel of . Then the induced morphism is surjective. As a consequence, we obtain the following exact sequence of vector bundles
[TABLE]
As is a Fano manifold of Picard number and of dimension , we must have for any by Kodaira’s vanishing theorem. Then we obtain
[TABLE]
Then Lemma A.9 below implies that and we are done. ∎
A.9**.**
Lemma.*
Let be a finite morphism between Fano manifolds of Picard number with dimension at least . Let be a vector bundle of rank over . If , then there exist line bundles on such that for , and .*
Proof.
Firstly we assume that is semistable. Then we have as is Fano with . In particular, the vector bundle is numerically projectively flat (see [LOY20, Definition 4.1]), so is itself. As is simply connected, it follows that is a direct sum such that . Then it is clear that we have as .
Next we assume that is not semistable. Then itself is not semistable. Without loss of generality, we may assume that . Let be the maximal destabilisor. Then we have . In particular, the induced morphism factors through ; that is, . As is an invertible sheaf and is saturated in , it follows that is also saturated and hence is an isomorphism. Thus, the line bundle is a subbundle of and therefore is a line bundle satisfying . In particular, as is a Fano manifold of Picard number with dimension at least , it follows for any line bundle over , and hence . ∎
Now we assume that is the -dimensional spinor variety. As is an integer, and , as computed in the proof of Lemma A.2, we obtain
, , , and .
Moreover, we have the following equations:
[TABLE]
Denote by a general hyperplane section of . We are ready to calculate the Chern classes of . Recall that we have the following
[TABLE]
Firstly we have
[TABLE]
This implies that and hence .
Secondly we have
[TABLE]
This implies that . One can also calculate that , but we do not need it in the following so we leave it for the interested reader.
A.10**.**
Proposition.*
In Lemma A.2, is not isomorphic to the -dimensional spinor variety .*
Proof.
As , the Bogomolov inequality implies that is not semi-stable. Let the last graded piece of the Harder-Narasimhan filtration of and denote by the quotient . Then the determinant is isomorphic to for some .
Firstly we assume that has rank . Then by Lemma A.8 above, and we have
[TABLE]
Let be the line bundle quotient corresponding to a section such that . Then it is clear that we have the following factorisation
[TABLE]
This implies that is contained in the prime divisor
[TABLE]
Note that is a generically finite morphism of degree since is a conic bundle and . Nevertheless, this is impossible as is an irreducible component of and is of degree .
Now we assume that has rank . Let be the kernel of . Then we have for some by the construction of .
Claim. .
Proof of Claim. Assume to the contrary that . By our assumption, there exists a line bundle quotient with the corresponding section such that . Moreover, as , it follows that the composition
[TABLE]
is identically zero. Hence, we have a factorisation
[TABLE]
Let be the main component of . Then is a prime divisor such that and . As before, the induced morphism is a generically finite morphism of degree , while is of degree , which is impossible. This finishes the proof of the claim.
Note that is semistable by our assumption. Thus the Bogomolov’s inequality says that (see [HL10, Theorem 3.4.1]). Nevertheless, by the definition of Chern classes, we have
[TABLE]
This implies
[TABLE]
which is a contradiction. ∎
A.11**.**
Remark. One can see that the direct sum has Chern classes with respect to .
Now we are in the position to prove Proposition A.3.
Proof of Proposition A.3.
By Lemma A.2 and Proposition A.4, the only possibilities of are as follows: a projective space, a quadric hypersurface, the Grassmann variety and the -dimensional spinor variety . If is a projective space, then it is proved in [Tsu06] that is a section of . If is the Grassmann variety , then we have . In particular, there does not exists positive integers such that is an integer and we can exclude it by Lemma A.2. The -dimensional spinor variety is excluded in Proposition A.10. ∎
A.C. Proof of Theorem A.1
Now we are ready to prove Theorem A.1. We will only deal with the cases which are affected by Lemma 3.2. The proof is based on a discussion with Masaru Nagaoka.
For case (1), denote by and the extremal rays of and, without loss of generality, we shall assume that . Then we have the following diagram
[TABLE]
where is the contraction corresponding to . The case affected by [Liu20, Lemma 3.2] is that is a conic bundle and the induced morphism is not an isomorphism. Note that is always isomorphic to the projective space by [HM99, Main Theorem]. Thus Proposition A.3 shows that is isomorphic to a quadric hypersurface. Then, by adjunction formula, we have
[TABLE]
where is the pull-back of a hyperplane section of . Consider the following short exact sequence
[TABLE]
Tensoring it with yields
[TABLE]
Here we use the fact that . Moreover, as , pushing-forward the exact sequence by yields
[TABLE]
This implies
[TABLE]
Note that is -very ample, it follows that is embedded in as a divisor such that for some integer , where is the pull-back of a hyperplane section of to and is the tautological divisor of . Then we obtain
[TABLE]
Here we use the fact that . Hence we have . Moreover, let be the prime divisor corresponding to the quotient
[TABLE]
Then is contained and we have
[TABLE]
Hence, we obtain and we are in case (1.3).
For case (2), there exists a blow-up along a smooth centre of codimension , is a smooth Fano variety and , where is the extremal ray of generated by the class of a curve contracted by . Moreover, there exists a Fano manifold of dimension , and a -bundle . Set . Then is an isomorphism and is contained . Denote by the unique positive integer such that . The case affected by [Liu20, Lemma 3.2] is that is not a nef divisor in . Then the pair is isomorphic to one of the varieties listed in (1.1) and (1.3). The case (1.1) is already done and it remains to consider the case (1.3). Nevertheless, in this case, since is a -bundle and there exists a contraction sending to a point, by [CD15, Lemma 3.9], the divisor must be a section of , which is a contraction. Hence, the case (1.3) does not happen.
A.D. Some other typos
In [Liu20, Proposition 2.10], the condition " is very ample" should be replaced by the condition " is simply generated". Similarly, in [Liu20, Proposition 2.11], the condition " is very ample" should be replaced by the condition " is simply generated". In the proof, these two propositions are used in the case with and being a rational homogeneous space of Picard number and it is known that any ample line bundles on rational homogeneous spaces are simply generated (see for instance [RR85, Theorem 1]).
Acknowledgements
I would like to express my gratitude to Masaru Nagaoka for pointing out the mistakes in the proof of Lemma 3.2 and also for many useful discussion to correct the main theorem in this paper. I also would like to thank Jinhyung Park for pointing out the mistakes in [Liu20, Proposition 2.10 and 2.11].
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