On the asymptotic Plateau problem for area minimizing surfaces in $\mathbb{E}(-1,\tau)$
Patr\'icia Klaser, Ana Menezes, \'Alvaro Ramos

TL;DR
This paper investigates the existence of complete area minimizing surfaces in the homogeneous space (-1, au), providing conditions under which certain boundary curves guarantee solutions to the asymptotic Plateau problem.
Contribution
It establishes new sufficient conditions for the existence of area minimizing surfaces with prescribed asymptotic boundaries in (-1, au).
Findings
Identifies conditions for existence of solutions to the asymptotic Plateau problem.
Provides non-existence results under certain boundary configurations.
Advances understanding of minimal surfaces in homogeneous spaces.
Abstract
We prove some existence and non-existence results for complete area minimizing surfaces in the homogeneous space . As one of our main results, we present sufficient conditions for a curve in to admit a solution to the asymptotic Plateau problem, in the sense that there exists a complete area minimizing surface in having as its asymptotic boundary.
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On the asymptotic Plateau problem for area minimizing surfaces in .
P. Klaser
A. Menezes
A. Ramos First and third authors were partially supported by CNPq/Brazil, grant number 406431/2016-7
Abstract
We prove some existence and non-existence results for complete area minimizing surfaces in the homogeneous space . As one of our main results, we present sufficient conditions for a curve in to admit a solution to the asymptotic Plateau problem, in the sense that there exists a complete area minimizing surface in having as its asymptotic boundary.
2010 Mathematics Subject Classification: Primary 53A10, Secondary 53C42.
Key words: Asymptotic Plateau Problem, Area Minimizing Surfaces.
1 Introduction.
In the last few years the asymptotic Plateau problem in the homogeneous space has been actively studied. For instance, Nelli and Rosenberg [10] proved that for any given Jordan curve that is a graph over there exists an entire minimal graph with as its asymptotic boundary; in particular, is area minimizing. Sa Earp and Toubiana [4] also considered the asymptotic Plateau problem in and they showed a general non existence result (see Theorem 2.1 in [4]) and got as a consequence that there is no complete properly immersed minimal surface whose asymptotic boundary is a Jordan curve homologous to zero in contained in an open slab between two horizontal circles of with height equal to
Kloeckner and Mazzeo [7] worked with a more general class of curves in the asymptotic boundary of (considering different compactifications of the space) and got a good characterization of curves for which there exists a minimal surface that has as its asymptotic boundary (see, for instance, Proposition 4.4 and Theorem 4.5 in [7]).
For the Plateau problem involving two closed curves (not homotopically trivial) in the asymptotic boundary of , Ferrer, Martín, Mazzeo and Rodríguez [5] proved some existence and non existence results for minimal annuli having these two curves as the asymptotic boundary (see Theorem 1.2 and Theorem 5.1 in [5]).
In addition to the aforementioned results, Coskunuzer [2] showed that for any tall curve (i.e., a curve with height greater than , see Definition 1.1 below) in , there exists an area minimizing surface with that curve as the asymptotic boundary. He also showed a non existence result for certain curves that are not tall. Here, we obtain similar results to the ones in [2] in the ambient space , which is the total space of a fibration over with bundle curvature . In particular, when , is isometric to the Riemannian product , which allows us to reobtain and extend some of the results of [2].
Throughout this work, unless specified otherwise, we use the cylinder model for . Specifically, let denote the unitary open disk in the complex plane and let, for , , where is the metric defined by
[TABLE]
for . We consider the asymptotic boundary of as being induced by the product topology of , . Moreover, if is a complete surface immersed in we define the asymptotic boundary of as the set
[TABLE]
In order to state our main results, we next give the definition of height of a curve in . We notice that throughout the paper, curves will be assumed to be piecewise smooth and non-degenerate.
Definition 1.1** (Height of a curve).**
Let be a finite collection of pairwise disjoint simple closed curves in and . For each , let denote the vertical line over in and let be the connected components of . For , let denote the (possibly infinite) euclidean length of . Then, the height of at is and the height of is
[TABLE]
Remark 1.2**.**
As in , an isometry of induces an isometry in . Nevertheless, for , the induced isometry changes the -coordinate, as observed in Proposition 2.1. Since this change is constant along any fiber, the vertical distance between two points in the same fiber is invariant under isometries. In particular, the definition of the height of a curve is well posed. Furthermore, differently from , there is no intrinsic notion of a height function in , . An example that shows this dependence is the horizontal slice in the half-plane model, which becomes (see (7)) a piece of a helicoid in the disk model: its height should be constant and equal to zero in the half plane model but it is not constant in the disk model. To avoid this ambiguity, throughout the paper the height of a curve in is here defined for the cylinder model of .
We next make precise the notion of a tall curve in . Note that our definition differs slightly from the one introduced by [2, Definition 2.4], which allows us to treat a broader class of curves.
Definition 1.3**.**
Let be a finite, pairwise disjoint collection of simple closed curves in . We say that is a tall curve if for all . Otherwise, we say that is a short curve.
Our first main result is the following.
Theorem 1.4**.**
Let be a finite collection of pairwise disjoint simple closed curves. If is tall, there exists a complete, possibly disconnected, area minimizing surface in with .
Note that if is a short curve, then there exists a point such that . Concerning such curves, we expect that, at least for the case where there is an open arc such that for all , there is no area minimizing surface with asymptotic boundary . However, this question is still open, even in the case of . In the following result we are able to prove a special situation of this nonexistence result.
Theorem 1.5**.**
Let be a short curve for which there exists an open arc where
[TABLE]
Then, there is no area minimizing surface in with .
Remark 1.6**.**
In the case , Theorem 1.5 is equivalent to the nonexistence result of Coskunuzer [2]. When , it is not clear whether the bound assumed in (2) is sharp, and it only gives information for . This bound is necessary to our proof since isometries in do not preserve the -coordinate; see Proposition 2.1, Corollary 2.2 and Remark 2.3.
Let us mention that after the completion of this paper, J. Castro-Infantes [1] considered the same asymptotic Plateau problem and among other results, using the halfplane model for , was able to improve the constant in Theorem 1.5.
The organization of the paper is the following. In Section 2, we present some background material for the study of minimal surfaces in . In Section 3 we prove our main theorems; and in Section 4 we prove a technical fact used in the proof of Theorem 1.5.
Acknowledgements**.**
The authors would like to thank Baris Coskunuzer, Francisco Martín and Magdalena Rodríguez for useful discussions concerning the topics of this manuscript.
2 Preliminaries.
Let denote the universal covering of the special linear group of real matrices. For each there exists a left invariant metric in such that becomes the total space of a Riemannian fibration over the hyperbolic plane with bundle curvature . Note that for any the group of isometries of has dimension four (for a nice discussion about the spaces, see Daniel [3]). A special case to be considered is when , where is isometric to the Riemannian product . In particular, all of our results also hold in . We also note that for , the spaces and are isometric, hence it is without loss of generality that we assume that .
As stated in the Introduction, we use the cylinder model to , where is given in (1). We also let and be the projections onto the first and the second coordinates, respectively.
The isometry group of is generated by the lifts of the isometries of the disk model of , together with vertical translations along the fibers (see, for instance, Theorem 2.9 in [12]). Precisely, the following holds.
Proposition 2.1**.**
The isometries of are given by
[TABLE]
or
[TABLE]
where is a positive isometry of the disk model of , and arg is a smooth angle function for .
One of the main difficulties that arises when working in the cylinder model of when is that isometries do not preserve the -coordinate. The next result gives an upper bound to this gap on the -coordinate for some isometries of ; we make use of this bound in the proof of our non-existence result.
Corollary 2.2**.**
For any positive isometry of the disk model of , there exists an isometry such that the projections and satisfy, for all and , that and .
Proof.
First, note that any positive isometry of the disk model of can be represented by a Möbius transformation
[TABLE]
where are such that . In particular, it holds that
[TABLE]
where . Note that , hence for all . For any , let
[TABLE]
We next analyze the image set to show that there exist with such that .
Let be such that . Since multiplication by a positive constant does not change the argument of a complex number, it follows from (5) that
[TABLE]
Note that is an open disk in with a positive distance to the origin. Hence, there are with such that . After choosing, for , , it follows that with .
This implies that we may choose a branch of the argument function such that for all , . After letting in (3), the result follows. ∎
Remark 2.3**.**
The bound on Corollary 2.2 cannot, in general, be improved. Indeed, depends uniquely on , as shown in the proof of Corollary 2.2. Moreover, if is a sequence of isometries such that , then the respective isometries satisfy .
In the cylinder model to , both horizontal planes and vertical planes (i.e. the inverse image of a geodesic of by ) are minimal (in fact, they are area minimizing) surfaces. We next describe some other families of minimal surfaces in that will be used as barriers throughout this paper.
2.1 Rotational Catenoids
We first describe a one-parameter family of complete (without boundary) minimal annuli in , which plays a key role in the proof of Theorem 1.5. Such a family was first obtained by B. Nelli and H. Rosenberg [10] for the case and extended to the case where by C. Peñafiel [11]. Each surface in this family is called a catenoid of and is invariant under the group of isometries corresponding to rotations about the -axis of the cylinder model.
Following the notation of [11], for any let be defined by
[TABLE]
Then, extends continuously to by setting and is strictly increasing. Moreover, there exists an increasing function such that, for each , . It also holds that
[TABLE]
Using this notation, for each the catenoid given by [11, Propositions 3.6 and 3.9] is , where and are the rotational surfaces parameterized by
[TABLE]
It follows directly from its definition that the asymptotic boundary of is the union of the two horizontal circles and .
2.2 Tall Rectangles
Here we will present some key properties of complete minimal planes in that are invariant under a one-parameter group of hyperbolic isometries. These surfaces are the so-called tall rectangles and were first described in the case by Sa Earp and Toubiana [4] and extended, when , to the halfspace model for by Folha and Peñafiel [6]. In what follows, we describe this family in the cylinder model and prove that they are in fact area minimizing surfaces.
For a fixed , let and be given and let
[TABLE]
[TABLE]
Using this notation, we next prove the following.
Proposition 2.4**.**
There exists an area minimizing plane , invariant under a one-parameter group of hyperbolic isometries of and with asymptotic boundary given by the union of and the two vertical segments joining their endpoints (see Figure 1).
Proof.
When , the result follows immediately from Proposition 2.1 of [4], hence we next assume that . We follow the notation of Folha and Peñafiel [6], where such tall rectangles were described. For the purpose of simplifying the computations, we start our proof in the half space model for , i.e.,
[TABLE]
where
[TABLE]
In this model, Corollary 5.1 of [6] implies that for and , there exists a minimal plane with asymptotic boundary given by the rectangle at with the four vertices , , and , see Figure 1. Furthermore, is invariant under the one-parameter subgroup of isometries of the half space model which is generated by the hyperbolic isometries of that fix the points at infinity corresponding to the vertical segments of .
Note that the family of hyperbolic translations are isometries of . Hence, the image surfaces give a foliation of the open slab by minimal surfaces. This was proved by Lima [8, Lemma 6] and follows from the fact that for any , the intersection is a graphical arc of circle with endpoints and . Hence, it follows that each is area minimizing.
To prove the existence of as claimed, we just use an isometry between models as we next present. Let be a complex coordinate system for and let be the Möbius transformation given by . Then,
[TABLE]
is an isometry between the two models of , and . For a given , take and let . It is straightforward to see that has the asymptotic boundary as claimed. ∎
The next result is a direct consequence of Proposition 2.4. We will make use of this result in the proof of Theorem 1.4.
Corollary 2.5**.**
Given with , there is such that for any with there exists an area minimizing surface with .
Proof.
This proof follows from the fact that rotations about the -axis and vertical translations in are isometries of , as we next explain. Let and be as stated and let
[TABLE]
Let be such that for any it holds that . Then, if are such that , we may vertically translate and rotate the surface to find as claimed. ∎
3 Existence and nonexistence results.
We next prove the main results of the paper. In Section 3.1 we prove that for any tall curve there exists an area minimizing surface with . In Section 3.2, we prove that for certain short curves with there is no area minimizing surface with .
Throughout this section, for any , we let denote the horizontal plane at height in .
3.1 The proof of Theorem 1.4.
First, we prove the theorem when is a finite union of disjoint parallel circles,
[TABLE]
where for all . Note that each separates and is area minimizing. Hence, to show that is area minimizing, it suffices to prove it is the unique minimal surface in with asymptotic boundary . We prove this by showing that there is no connected minimal surface in with asymptotic boundary , when .
Suppose to the contrary that there is a connected minimal surface in with . For two consecutive , let be such that and let and . Let be the slab bounded by the planes and . Then is a compact minimal surface that admits a connected component with , and .
Let be the family of rotational catenoids of given in Section 2.1, vertically translated so that for all , . To obtain a contradiction, we now just recall that when goes to infinity, the surfaces escape from any compact, and when approaches zero, they converge (away from the origin, with multiplicity two) to a horizontal plane. In particular, there must be a first contact point between and some , which is a contradiction by the maximum principle.
Hence, we next proceed with the proof of Theorem 1.4 with the additional assumption that is not a family of parallel circles.
Proof of Theorem 1.4.
We start the proof by setting up the notation. For each and , let be the disk in the horizontal plane centered at the origin and with euclidean radius . In particular, the family gives an exhaustion of . Also, for a given , let be a compact solid cylinder in . Since both horizontal planes and vertical planes over complete geodesics are minimal surfaces in the metric of , is mean convex for all and .
Let be a tall curve in and let be such that is contained in the open slab of . For each , let be the radial projection of in . Since is mean convex and is an embedded, piecewise smooth curve in , there exists an embedded, possibly disconnected, area minimizing surface with . Our next argument is to show that when , then, up to a subsequence, converges to a nonempty complete surface such that .
Since each is area minimizing, the number of connected components of is uniformly bounded by the number of connected components of , which is equal to the number of components of . In particular, we may pass to a subsequence to assume that there exists some such that the number of connected components of each is , and we let denote such components, labeled in such a way that for each the radial projection of to correspond to the same component of for all . In particular, we just need to prove the result when , since the general case follows from a finite diagonal argument. Hence, from now on we will assume that is connected, for all .
Let . Since is tall, Corollary 2.5 gives that for any there exists a tall rectangle such that is disjoint from and separates from in . Let be the region defined by in such that .
We claim that , for all sufficiently large. In the topology of , and are two disjoint compact sets, and the sequence converges to . Hence there is such that for all , , from where it follows that in .
To prove the claim, we argue by contradiction and assume that intersects for some . Now, a standard replacement argument yields a contradiction. In fact, since does not intersect , then is a compact smooth surface with boundary in . Since is a topological plane, there exists a compact subdomain with . Then, from the fact that both and are area minimizing, we obtain that . In particular, the compact surface defined by
[TABLE]
is a nonsmooth area minimizing surface, a contradiction.
Next, we use the fact proved above to show that the sequence admits a limit point in ; in other words, the surfaces do not escape to infinity. Since is not a finite collection of parallel circles, there exists a horizontal plane in such that intersects transversely at some point . Hence, we may choose points that bound a closed arc containing in its interior and such that , see Figure 2 (a). Let be a complete arc in with endpoints and let be the region bounded by in that contains in its asymptotic boundary. Since converges to , it follows that intersects transversely and only in one point, for all sufficiently large.
The above argument shows that, when we consider as a simple closed curve in , the linking number between and is one, for all sufficiently large. In particular, since , there must be a point .
Let and be the respective regions bounded by two tall rectangles and as before. Then, for sufficiently large, . Since is compact, the sequence admits a convergent subsequence, and then the surfaces do not escape to infinity. In particular, after passing to a subsequence, it follows that converges (in the topology on compacts of ) to a complete, area minimizing surface .
It remains to prove that . First, note that the fact that for any there exists such that for all gives immediately that . Next, we show that given , then . First, assume that there is a plane such that intersects transversely at . Take a sequence of arcs (each resembles the arc in Figure 2 (b)) such that the endpoints of determine arcs in that intersect uniquely at and such that the respective regions bounded by satisfy that and that . The same arguments as above give that for all there exists a point , from where it follows that . Since the above argument is purely topological, we notice that the general case when the -coordinate of has a local extremal value at can be treated in a similar manner, by considering a vertical plane instead of a horizontal one, and this finishes the proof of Theorem 1.4. ∎
3.2 The proof of Theorem 1.5.
In this section, we prove our nonexistence result stated as Theorem 1.5 in the Introduction. The proof follows the ideas contained in Step 2 of the proof of Theorem 2.13 in [2], with a few changes and necessary adaptations to the setting. A key step in the proof of our result is, when , to show the existence of a compact, connected area minimizing surface in with boundary contained in two parallel planes that are sufficiently far from each other. This is stated in Proposition 3.1 below and is proved in Section 4, since the arguments used in its proof are technical.
To what follows, for each and , we let
[TABLE]
be the circle in the horizontal plane (with coordinates given by the open disk ) centered at the origin with euclidean radius .
Proposition 3.1**.**
For any there exist and a compact, connected, area minimizing surface such that
[TABLE]
Assuming Proposition 3.1, we now proceed to the proof of Theorem 1.5.
Proof of Theorem 1.5.
Arguing by contradiction, let us assume that is a curve as stated and that is a complete, connected, area minimizing surface in such that . Since is area minimizing, then is properly embedded. In particular, is orientable and the fact that is connected implies that it separates into two connected open regions .
The asymptotic boundaries of and intersect along and their union is the whole . In particular, if we let and , it follows that .
After rotating about the -axis and performing a vertical translation, the assumptions over imply that there exist and such that, for all the vertical segment intersects transversely, in exactly two points, and both points are interior to . We may also reindex to assume, without loss of generality, that , where ; see Figure 3 (a).
Let be open sets in such that and that , . Also, let be another open set in such that and that with . For instance, we could take as sufficiently small neighborhoods of and of , respectively (see Figure 3 (b)).
Let, for , . Then is an open set of that contains in the interior of its asymptotic boundary. Let (see Figure 3 (c)).
From equation (2), we may choose such that , and then Proposition 3.1 implies the existence of and of a connected, area minimizing surface with boundary . As before, let denote the disk in centered at the origin and with euclidean radius . By the maximum principle using horizontal and vertical planes, we know that . Furthermore, is a connected, embedded, compact surface in ; then separates and defines a unique bounded region with .
For , let be the hyperbolic isometry of that translates along the geodesic given by the real axis and maps [math] to , and let be its related isometry of given by Corollary 2.2. Then, for all and , and
[TABLE]
Let and . Then is an area minimizing surface of contained in the boundary of the region . Let for . Since, when , is collapsing into the point at infinity and is an open set which contains in the interior of its asymptotic boundary, there exists such that for all , .
Note that (8), together with the fact that , gives that intersects both regions and . In particular, since and is connected, there exists a connected component of with boundary intersecting both and . In particular, intersects .
On the other hand, separates into two connected components that intersect , and then , from where it follows that also intersects and that contains a compact connected component with boundary contained in . Now, a standard replacement argument using that both and are area minimizing produces a nonsmooth area minimizing surface, which is a contradiction that proves Theorem 1.5. ∎
4 The proof of Proposition 3.1.
The proof of Proposition 3.1, which follows the ideas presented in [2, Lemma 7.1], will be carried out along this section. For , let be the rotational catenoid introduced in Section 2.1. The main idea here is to show that for any and sufficiently large, the surface
[TABLE]
has less area than the union of the two disks in the parallel planes which share a boundary component with . Hence, the area minimizing surface with boundary is necessarily connected. Note that is compact if and only if , which is equivalent to the existence of such that . For convenience, for given and , we define
[TABLE]
Our first result is an area estimate for for large values of .
Lemma 4.1**.**
There exists such that for any and it holds that
[TABLE]
Proof.
Let be a smooth function and let be the rotational surface in parameterized by
[TABLE]
Then, a straightforward computation implies that the area of is given by
[TABLE]
Hence, it follows from (9) and from (6) that
[TABLE]
In particular, since for all , we obtain that
[TABLE]
The next argument presents an adequate estimate to the integral in (10), which we will denote by . Under the assumption that , we may write where
[TABLE]
To estimate , we first use that , obtaining
[TABLE]
Next, we use the change of variables , the identity and the fact that for any the function is a primitive to to obtain that
[TABLE]
In order to estimate , we use the inequalities and , which hold for all , so that
[TABLE]
Since is a primitive to and , we obtain that
[TABLE]
Using (10), (11) and (12) we obtain that, for any and ,
[TABLE]
Since
[TABLE]
the lemma follows. ∎
Let and be the respective disks in the horizontal planes and such that . Since vertical translations are isometries of , it follows that . Using this fact, we prove the next result, which compares the area of with the area of for and sufficiently large.
Lemma 4.2**.**
Let . Then, there exists such that for all it holds that
[TABLE]
In particular, there exists such that for all it holds that
[TABLE]
Proof.
For any , we have that
[TABLE]
In order to see this, just apply (9) for the function , after using the identity . Thus, if we denote
[TABLE]
it holds that . Our next arguments estimate from below.
First, use the substitution to obtain that
[TABLE]
Using that for any ,
[TABLE]
we may compute in terms of as follows
[TABLE]
Since and , it follows from (15) that
[TABLE]
Assuming that is large enough so and setting
[TABLE]
we obtain that
[TABLE]
In particular, for , it holds that
[TABLE]
for all sufficiently large. To conclude the proof that (13) holds, we just notice that there exists large enough so that for all , it holds that .
Now, to finish the proof of the lemma it remains to show that there exists some such that (14) holds for all . We first observe that , hence there exists some such that for any it holds that . Without loss of generality, we may assume that , where is defined in Lemma 4.1. In particular, for all
[TABLE]
Now, we just use the fact that
[TABLE]
to obtain some such that for all
[TABLE]
and we can use (13) and (16) to finish the proof of the lemma. ∎
At this point, we know that for sufficiently large and , the area of is less than the area of the two horizontal disks with the same boundary as . In particular, any area minimizing surface of with boundary will be connected, since the unique disconnected minimal surface with such boundary is .
Our next result shows that for any there exists so that , thereby completing the proof of Proposition 3.1.
Lemma 4.3**.**
For , it holds that
[TABLE]
Proof.
For a given let be defined by
[TABLE]
It is immediate to obtain that for all we have the inequality
[TABLE]
Since the results from Peñafiel [11, Proposition 3.9] imply that and
[TABLE]
in order to prove the lemma it suffices to show that
[TABLE]
Equation (18) is precisely Lemma 7.3 of [2], but, for the sake of completeness, we present its proof here.
We start with the change of variables used in Proposition 5.2 of [9], , so that (17) becomes
[TABLE]
In particular, if we let , it follows that
[TABLE]
Let be defined by . Then
[TABLE]
For any it holds that
[TABLE]
and then
[TABLE]
We note that ; in particular, . On the other hand, from where it follows that both lower an upper bounds on (20) converge to , as . This, together with (19), implies that
[TABLE]
which proves the lemma. As already explained, this also finishes the proof of Proposition 3.1. ∎
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