On asymptotically sharp bi-Lipschitz inequalities of quasiconformal mappings satisfying inhomogeneous polyharmonic equations
Shaolin Chen, David Kalaj

TL;DR
This paper establishes asymptotically sharp bi-Lipschitz inequalities for quasiconformal mappings satisfying inhomogeneous polyharmonic equations, demonstrating near-rotation behavior under small perturbations and boundary conditions.
Contribution
It proves that such quasiconformal solutions are Lipschitz and bi-Lipschitz under small inhomogeneous terms, with asymptotically sharp estimates as parameters approach ideal values.
Findings
Mappings are Lipschitz continuous.
Mappings are bi-Lipschitz when perturbations are small.
Estimates are asymptotically sharp as parameters approach ideal conditions.
Abstract
Suppose that is a -quasiconformal (-quasiconformal resp.) self-mapping of the unit disk , which satisfies the following: the inhomogeneous polyharmonic equation , (2) the boundary conditions ( for and denotes the unit circle), and , where is an integer and ( resp.). The main aim of this paper is to prove that is Lipschitz continuous, and,further, it is bi-Lipschitz continuous when are small enough for . Moreover, the estimates are asymptotically sharp as ( resp.) andβ¦
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Taxonomy
TopicsAnalytic and geometric function theory Β· Nonlinear Partial Differential Equations Β· Holomorphic and Operator Theory
β β footnotetext: File:Β 1905.02588.tex, printed: 15-3-2024, 20.12
On asymptotically sharp bi-Lipschitz inequalities of quasiconformal
mappings satisfying inhomogeneous polyharmonic equations
Shaolin Chen
Sh. Chen, College of Mathematics and Statistics, Hengyang Normal University, Hengyang, Hunan 421008, Peopleβs Republic of China.
Β andΒ
David Kalaj
D. Kalaj, Faculty of Natural Sciences and Mathematics, University of Montenegro, Cetinjski put b. b. 81000 Podgorica, Montenegro.
[email protected]; [email protected]
Abstract.
For two constants and , suppose that is a -quasiconformal self-mapping of the unit disk , which satisfies the following: the inhomogeneous polyharmonic equation in , (2) the boundary conditions on ( for and denotes the unit circle), and , where is an integer. The main aim of this paper is to prove that is Lipschitz continuous, and, further, it is bi-Lipschitz continuous when are small enough for . Moreover, the estimates are asymptotically sharp as , and for .
Key words and phrases:
Bi-Lipschitz continuity, Quasiconformal mapping, Polyharmonic equation.
2000 Mathematics Subject Classification:
Primary: 30C62; Secondary: 31A05.
1. Preliminaries and main results
Let be the complex plane. For and , let , the open disk with center and radius . For convenience, we use to denote , and the open unit disk . Let be the unit circle, i.e., the boundary of and . Also, we denote by the set of all complex-valued -times continuously differentiable functions from into , where is a subset of and . In particular, let , the set of all continuous functions in .
For a real matrix , we denote the matrix norm by and the matrix function by respectively.
For , the formal derivative of a complex-valued function is given by
[TABLE]
where , and are real-valued functions with partial derivatives. Then,
[TABLE]
where f_{z}:=\partial f/\partial z=\frac{1}{2}\big{(}f_{x}-if_{y}\big{)} and f_{\overline{z}}:=\partial f/\partial\overline{z}=\frac{1}{2}\big{(}f_{x}+if_{y}\big{)}. Moreover, we use
[TABLE]
to denote the Jacobian of .
A sense-preserving homeomorphism
[TABLE]
where and are subdomains of , is said to be a -quasiconformal mapping if is absolutely continuous on lines in , and there are constants and such that
[TABLE]
In particular, if , then is a -quasiconformal mapping (cf. [11, 39]).
Given a subset of , a function is said to be bi-Lipschitz if there is a constant such that for all ,
[TABLE]
In particular, is called Lipschitz if the inequality on the right of (1.1) holds, and is said to be co-Lipschitz if it satisfies the inequality on the left of (1.1). It is clear that any sense-preserving bi-Lipschitz mapping is quasiconformal mapping (see Chapter 14.78 in [17]). But quasiconformal mappings are not necessarily bi-Lipschitz, not even Lipschitz (see [28]).
In [43], PavlovΔ discussed the bi-Lipschitz characteristic of a harmonic homeomorphism of onto itself. Later, Partyka and Sakan [41] gave explicit estimates of bi-Lipschitz constants for a harmonic -quasiconformal mapping of onto itself. Under the additional assumption , the estimates are asymptotically sharp as , so behaves almost like a rotation for sufficiently small . Recently, the bi-Lipschitz characteristics of harmonic quasiconformal mappings have been attracted much attention (see [21, 23, 29, 36, 41, 43]). The Lipschitz continuity of -quasiconformal harmonic mappings has also been investigated in [5, 25, 47]. On the discussion of the related topic, we refer to [2, 3, 16, 20, 26, 33, 35, 43] and the related references therein. On the study of the Lipschitz characteristic of quasiconformal mappings satisfying certain elliptic PDEs, see [7, 22, 24, 27, 28]. In particular, let us recall the following two results.
Theorem A. ([7, Theorem 1.1])* Let , , and let be a constant. Suppose that is a -quasiconformal self-mapping of satisfying the bi-harmonic equation with in and . Then, there are nonnegative constants and () with and such that for all and in ,*
[TABLE]
*where and . *
Theorem B. ([7, Corollary 3.1])* Under the assumptions of Theorem , if, further, and , then is co-Lipschitz continuous, and so, it is bi-Lipschitz continuous, where and *
We remark that the bi-harmonic quasiconformal mappings between smooth domains are not necessarily Lipschitz (see the Example 1.1).
Example 1.1**.**
The mapping is bi-harmonic (i.e., ) in and quasiconformal in but is not Lipschitz in any neighborhood of . The mapping is not bi-harmonic in [math], since . The mapping is bi-harmonic in for small enough positive number , and maps onto a convex Jordan domain with boundary. Thus the bi-harmonic mapping maps quasiconformally onto the Jordan domain with , but it is not Lipschitz. So the Lipschitz continuity fails if we drop the condition is continuous up to the boundary. To prove that we observe first that is rectifiable. Namely by direct computation, we have
[TABLE]
and
[TABLE]
Since
[TABLE]
where
[TABLE]
is the natural parameter, and since the limit of left-hand side in (1.2) tends to , it follows that is continuous in , and therefore the function is . To show that the curve is , we find the curvature of at [math]. Namely if and , then the curvature
[TABLE]
Then it can be proved that . Thus is continuous in which means that the curve is .
The main aim of this paper is to improve and generalize Theorems and . In order to state our main results, we need to recall some basic definitions and some results which motivate the present work.
For with , let
[TABLE]
be the Green function and (harmonic) Poisson kernel, respectively, where
Let and , where is an integer. Of particular interest for our investigation is the following inhomogeneous polyharmonic equation (or n-harmonic equation):
[TABLE]
with the following associated Dirichlet boundary value condition:
[TABLE]
where ,
[TABLE]
stands for the Laplacian of , and for . Here on means that
[TABLE]
for all , where .
By the iterated Poly-Cauchy integral operators (cf. [4]), we see that all solutions to the equation (1.3) satisfying (1.4) are given by
[TABLE]
where
[TABLE]
[TABLE]
for , and
[TABLE]
Here is the Lebesgue area measure in . The behavior of solutions to the polyharmonic equations with the different boundary value conditions has attracted much attention of many authors (cf. [12, 13, 15, 30, 37, 40]).
The first aim of this paper is to investigate the asymptotically sharp bi-Lipschitz inequalities of -quasiconformal self-mapping of satisfying the inhomogeneous polyharmonic equation (1.3) with the boundary condition (1.4). It is read as follows.
Theorem 1.2**.**
Let be a sense-preserving homeomorphism of onto itself. For and , let and , and let and be constants. Suppose that is a -quasiconformal self-mapping of satisfying the inhomogeneous polyharmonic equation (1.3) with the Dirichlet boundary value condition (1.4).
If then is bi-Lipschitz continuous in . 2.
If and then there are nonnegative constants and () with
[TABLE]
and such that for all ,
[TABLE]
where and for .
In particular, if , then we have the following better estimate.
Theorem 1.3**.**
Let and , and let be a constant, where and . Suppose that is a -quasiconformal self-mapping of satisfying the inhomogeneous polyharmonic equation (1.3) with on and . Then, there are nonnegative constants and () with
[TABLE]
such that for all ,
[TABLE]
The following is the so-called Moriβs Theorem (cf. [9, 27, 38]). We refer to [10, 34] for some analogical results of Theorem in the higher dimensional case.
Theorem C. * Suppose that is a -quasiconformal self-mapping of with . Then, there exists a constant , satisfying the condition as , such that*
[TABLE]
*where the notation means that the constant depends only on . *
We remark that in [44] it is proved
[TABLE]
As a direct consequence of Claim 4.8 in the proof of Theorem 1.3, we have the following result.
Corollary 1.4**.**
Under the assumptions of Theorem 1.3, if, further,
[TABLE]
then is co-Lipschitz continuous, and so, it is bi-Lipschitz continuous, where is the same as in Theorem .
By (1.8) and [27, Formula 3.27], we see that
[TABLE]
which gives the following result, where is the Gamma function.
Corollary 1.5**.**
Under the assumptions of Theorem 1.3, if, further,
[TABLE]
then is co-Lipschitz continuous, and so, it is bi-Lipschitz continuous.
We remark that if , then Corollary 1.5 is an improvement of Theorem .
By the discussions in Step 3 of the proof of Theorem 1.3 in Section 4 or by Corollary 1.4, we see that the co-Lipschitz continuity coefficient
[TABLE]
is positive for small enough norms , where . The following example (Example 1.6) shows that the condition for to be co-Lipschitz continuous cannot be replaced by the one that are arbitrary, where .
Example 1.6**.**
For , let
[TABLE]
where and are constants with and . Suppose that satisfies the following polyharmonic equation
[TABLE]
with the following associated Dirichlet boundary value condition:
[TABLE]
where , and for ,
[TABLE]
It follows from (1.5) that
[TABLE]
is the solution to (1.9). Obviously, is a -quasiconformal self-mapping of with and . Furthermore,
[TABLE]
and for ,
[TABLE]
However, is not co-Lipschitz continuous because
[TABLE]
By applying Corollary 1.5, we illustrate the possibility of to be bi-Lipschitz continuous by the following example.
Example 1.7**.**
Suppose that satisfies the following bi-harmonic equation
[TABLE]
with the following associated Dirichlet boundary value condition:
[TABLE]
By (1.5), we see that
[TABLE]
is the solution to (1.10). It is not difficult to know that is a -quasiconformal self-mapping of with
[TABLE]
where . Since elementary computations lead to
[TABLE]
and
[TABLE]
we see that
[TABLE]
where and Now, it follows from Corollary 1.5 that is co-Lipschitz continuous, and so, it is bi-Lipschitz continuous.
We recall that the (periodic) Hilbert transformation of a periodic function is defined by
[TABLE]
It is well known that the Lipschitz continuity of in is not enough to guarantee that its harmonic extension is also Lipschitz continuous. In fact, is Lipschitz continuous if and only if the Hilbert transform of (cf. [6, 48]). The last aim of this paper is to investigate the Lipschitz continuity of solutions to the inhomogeneous polyharmonic equation (1.3) satisfying some certain boundary conditions.
Proposition 1.8**.**
For and , let and , and let be differentiable. Suppose that is a solution to the inhomogeneous polyharmonic equation (1.3) satisfying on . Then is Lipschitz continuous in if and only if the Hilbert transform of .
We will prove several auxiliary results in Section 2. The proof of Theorem 1.2 will be presented in Section 3. Theorem 1.3 and Proposition 1.8 will be proved in Sections 4 and 5, respectively.
2. Some auxiliary results
In this section, we shall prove several lemmas which will be used later on. The first lemma is as follows.
Lemma 2.1**.**
Let be the Green function. Then, for ,
[TABLE]
and
[TABLE]
Theorem D. (cf. [32])* For , we have*
[TABLE]
*where . *
Proof of Lemma 2.1
We first prove (2.1). Let
[TABLE]
where and . Since Theorem implies
[TABLE]
by (2.3), we obtain
[TABLE]
Now we show (2.2). For , let
[TABLE]
By Theorem , we have
[TABLE]
which, together with
[TABLE]
implies that
[TABLE]
The proof of this lemma is completed.β
Lemma 2.2**.**
For ,
[TABLE]
In particular, the inequality (2.5) is sharp at .
Proof. Let
[TABLE]
Then
[TABLE]
By Theorem , we obtain
[TABLE]
By computation, we have
[TABLE]
It follows from (2.6), (2) and (2.8) that
[TABLE]
The proof of this lemma is finished. β
Lemma 2.3**.**
Let be the Poisson kernel and . Then
[TABLE]
Proof. Let . By Theorem , we have
[TABLE]
which gives that
[TABLE]
β
Lemma 2.4**.**
Suppose that and are defined in (1), where and . Then, the following statements hold:
* For ,*
[TABLE]
where
[TABLE]
* Both and have continuous extensions to the boundary, and further, for ,*
[TABLE]
where
[TABLE]
Proof. In order to prove the first statement of this Lemma, we only need to prove the following inequality
[TABLE]
because the proof of the other one is similar, where is defined in the first statement of this Lemma. For this, let
[TABLE]
.
Then, by [27, Lemma 2.7], we have
[TABLE]
which, together with [27, Proposition 2.4] (see also [45]), gives that
[TABLE]
.
Let
[TABLE]
It follows from Lemma 2.1 that
[TABLE]
which, together with Lemma 2.2, implies that
[TABLE]
By (2) and [27, Proposition 2.4] (see also [45]), we conclude that
[TABLE]
Now we prove the second statement of this Lemma. In order to show this statement, we use the Vitali theorem (see [14, Theorem 26.C]) which asserts that if is a measurable space with finite measure and that is a sequence of functions such that
[TABLE]
then
[TABLE]
Let
[TABLE]
where . In order to estimate , we let
[TABLE]
where and . Since
[TABLE]
we see that
[TABLE]
which, together with (2.10) and Theorem , yield that
[TABLE]
It follows from (2.1) and (2) that
[TABLE]
Therefore, by the Vitali theorem, we conclude that has continuous extension to the boundary, and further, by [27, Lemma 2.7],
[TABLE]
where .
For , by Lemmas 2.1 and 2.3, we have
[TABLE]
Similarly, we can show that has continuous extension to the boundary, and for ,
[TABLE]
where . The proof of this lemma is complete. β
Lemma 2.5**.**
Suppose and is defined in (1). Then, the following statements hold:
* For ,*
[TABLE]
* Both and have continuous extensions to the boundary, and further, for ,*
[TABLE]
Proof. To prove the first statement, we only need to prove the inequality:
[TABLE]
because the proof to the other one is similar. For this, let
[TABLE]
By calculation, we have
[TABLE]
By (2), Lemmas 2.1 and 2.2, we see that
[TABLE]
which, together with [27, Proposition 2.4] (see also [45]), yields that
[TABLE]
Next, we prove the second part of this Lemma. Set
[TABLE]
Then by (2) and Lemma 2.1 (2.1), we get
[TABLE]
Hence, by the Vitali theorem, we see that has continuous extension to the boundary, and further, by Lemmas 2.1 and 2.3, we have
[TABLE]
where .
Similarly, we can prove that has continuous extension to the boundary, and for ,
[TABLE]
The proof of this lemma is finished. β
Lemma 2.6**.**
For and , suppose that is a sense-preserving homeomorphism from onto itself satisfying (1.3) and the boundary conditions on , and suppose that is Lipschitz continuous in , where and . Then, for almost every , the following limits exist:
[TABLE]
Further, we have
[TABLE]
and
[TABLE]
where and is a real-valued function in .
Proof of Lemma 2.6
We first prove the existence of the two limits in (2.14). By Lemmas 2.4 and 2.5, we get that for any ,
[TABLE]
where .
Again, by Lemmas 2.4 and 2.5, we know that is bounded, which implies the Lipschitz continuity of in . Since is Lipschitz continuous in , we see that is bounded in . Thus, it follows from (1.5) that
[TABLE]
is also Lipschitz continuous in , where . Now, we conclude from [27, Lemma 2.1] that for almost every ,
[TABLE]
does exist, which, together with (1.5) and (2.17), guarantees that for almost every
[TABLE]
also exists.
Since
[TABLE]
obviously, we see that
[TABLE]
exists for almost every
Next, we demonstrate the estimates in (2.6) and (2.6). For convenience, in the rest of the proof of the lemma, let
[TABLE]
By Lebesgue Dominated Convergence Theorem, the boundedness of , and by letting , we see that for any fixed ,
[TABLE]
which implies that is absolutely continuous. Let be a real-valued function in such that
[TABLE]
Then,
[TABLE]
holds almost everywhere in
Since
[TABLE]
we infer from (2.19) that
[TABLE]
where
[TABLE]
and
[TABLE]
Now, we are going to prove (2.6) and (2.6) by estimating the quantities and respectively, where We start with the estimate of . Since
[TABLE]
and
[TABLE]
where denotes the inner product, it follows that
[TABLE]
Next, we estimate for Since
[TABLE]
we deduce that
[TABLE]
where
It follows from (2), Lemmas 2.1 and 2.3 that
[TABLE]
By (2), we get
[TABLE]
At last, we estimate . By (2.22), Lemmas 2.1 and 2.3, we obtain
[TABLE]
Hence, (2.6) and (2.6) follow from the inequalities (2.21), (2) and (2) along with the following chain of inequalities:
[TABLE]
The proof of the lemma is complete. β
Theorem E. ([24, Theorem 3.4])* Suppose that is a quasiconformal diffeomorphism from the plane domain with compact boundary onto the plane domain with compact boundary. If there exist constants and such that*
[TABLE]
*in , then has bounded partial derivatives. In particular, it is a Lipschitz mapping in . *
Theorem F. ([42, Theorem 2.2])* Given , let be a -quasiconformal and harmonic self-mapping of satisfying . Then, for ,*
[TABLE]
*where is defined in [42, Lemma 1.4] and *
3. The proof of Theorem 1.2
We first prove part .
Step 3.1**.**
The co-Lipschitz continuity of .
Now we begin to prove the co-Lipschitz continuity of . Since is a -quasiconformal mapping, by [25, Lemma 4.2], we see that, for ,
[TABLE]
which implies that
[TABLE]
By (1.5), we have
[TABLE]
and
[TABLE]
which, together with (3.1), yield that
[TABLE]
where
[TABLE]
By Lemmas 2.4 and 2.5, we have
[TABLE]
where
[TABLE]
Since is a sense-preserving homeomorphic self-mapping of , by the Choquet-RadΓ³-Kneser theorem (see [8]), we see that is a harmonic diffeomorphism of onto itself. Then, by [46, Lemma 2.1], we obtain
[TABLE]
It follows from (3.2), (3.3) and (3.4) that
[TABLE]
which, together with the assumptions, gives that
[TABLE]
Then is a -quasiconformal mapping in , where
[TABLE]
Hence, by [46, Lemma 2.4], we have
[TABLE]
which, together with (3.1), yields that
[TABLE]
Claim 3.1**.**
[TABLE]
Now we prove this Claim. Let . By the assumptions, we have
[TABLE]
It follows from (3.6) and (3.9) that
[TABLE]
which implies that the Claim 3.1 is true. Since for all ,
[TABLE]
we conclude that is also co-Lipschitz continuous.
Step 3.2**.**
The Lipschitz continuity of .
The Lipschitz continuity of easy follows from (4.1), (4) and Theorem .
Next, we prove part .
Step 3.3**.**
The asymptotically sharp Lipschitz inequality of .
Since is a -quasiconformal mapping of onto itself with , by [41, Theorem 3.3], we see that, for all ,
[TABLE]
By Lemmas 2.4 and 2.5, we obtain that, for all ,
[TABLE]
and
[TABLE]
where . It follows from (1.5), (3.10), (3.11) and (3.12) that, for all ,
[TABLE]
where and
[TABLE]
It is easy to know that
[TABLE]
Step 3.4**.**
The asymptotically sharp co-Lipschitz inequality of .
Let
[TABLE]
and
[TABLE]
where is defined in (3.6) and is a positive constant satisfying
[TABLE]
Then
[TABLE]
It follows from the Claim 3.1 that
[TABLE]
Then, by Theorem , we have
[TABLE]
which, together with (3.1) and (3.13), yields that, for all ,
[TABLE]
Therefore, is co-Lipschitz continuous in . The proof of this theorem is complete.β
4. The proof of Theorem 1.3
The purpose of this section is to prove Theorem 1.3. The proof consists of three steps. In the first step, the Lipschitz continuity of the mappings is proved, the co-Lipschitz continuity of is demonstrated in the second step, and in the third step, the Lipschitz and co-Lipschitz continuity coefficients obtained in the first two steps are shown to have bounds with the forms as required in Theorem 1.3.
Step 4.1**.**
The asymptotically sharp Lipschitz inequality of .
We start the discussions of this step with the following claim.
Claim 4.1**.**
The limits
[TABLE]
exist almost everywhere in .
We are going to verify the existence of these two limits by applying Theorem and Lemma 2.6. For this, we need to get an upper bound of as stated in (4.1) and (4) below, and we will divide it into two cases to estimate.
By the formula (1.3) in [27] (see also [19, pp. 118-120]), we have that for ,
[TABLE]
It follows from Lemma 2.1 (2.1) that
[TABLE]
Since
[TABLE]
and
[TABLE]
on , by (1.5), we see that, for ,
[TABLE]
where
[TABLE]
for , and
[TABLE]
By Lemmas 2.1 and , for , we obtain that
[TABLE]
for , and
[TABLE]
which give that
[TABLE]
Since is a -quasiconformal self-mapping of , we see that can be extended to the homeomorphism of onto itself. Now, the existence of the limits
[TABLE]
almost everywhere in follows from (4), Theorem and Lemma 2.6.
For convenience, in the following, let
[TABLE]
Since for almost all and ,
[TABLE]
we see that, to prove the Lipschitz continuity of and investigate the behavior of the Lipschitz coefficient, it suffices to estimate the quantity . To reach this goal, we first show that the quantity satisfies an inequality which is stated in the following claim.
Claim 4.2**.**
C_{2}(K,\varphi_{1},\cdots,\varphi_{n})\leq\big{(}C_{2}(K,\varphi_{1},\cdots,\varphi_{n})\big{)}^{1-\frac{1}{K}}\mu_{1}+\mu_{2}, where
[TABLE]
is from Theorem ,
[TABLE]
and
[TABLE]
To prove the claim, we need the following preparation. Firstly, we prove that , and for almost every ,
[TABLE]
By [20, Lemma 1.6], we know that
[TABLE]
which shows . Next, we prove (4.4). For , let
[TABLE]
Then, by (2), we see that is absolutely continuous. It follows that
[TABLE]
which implies
[TABLE]
almost everywhere in where .
Since the existence of the two limits
[TABLE]
almost everywhere in guarantees that
[TABLE]
we deduce from (2.6) and (4.5) that
[TABLE]
from which the inequality (4.4) follows.
Secondly, we show that for any , there exists such that
[TABLE]
For the proof, let , and let
[TABLE]
in .
Since is harmonic, we see that is analytic in , and thus,
[TABLE]
Then, the facts
[TABLE]
and
[TABLE]
ensure
[TABLE]
which, together with Lemmas 2.4 and 2.5, guarantees that for all
[TABLE]
from which the inequality (4.6) follows.
Let
[TABLE]
Finally, we need the following estimate of :
[TABLE]
Since it follows from (4.3) that for almost all ,
[TABLE]
we infer that
[TABLE]
from which, together with Theorem , the inequality (4.7) follows.
Now, we are ready to finish the proof of the claim. It follows from (4.6) that
[TABLE]
[TABLE]
By letting , we get from (4.9) that
[TABLE]
as required.
The following is a lower bound for .
Claim 4.3**.**
.
Since
[TABLE]
we conclude that
[TABLE]
Then, it follows from (4.8) and the following fact
[TABLE]
that
[TABLE]
Hence, the claim is true.
An upper bound of is established in the following claim.
Claim 4.4**.**
If , then
[TABLE]
where
The proof of this claim easily follows from [27, Lemma 2.9].
Now, we are ready to finish the discussions in this step. By Claims 4.2 and 4.3, we obtain
[TABLE]
where
By letting
[TABLE]
we infer that
[TABLE]
Then, the Lipschtz continuity of follows from these estimates of .
Step 4.2**.**
The asymptotically sharp co-Lipschitz inequality of .
We begin the discussions of this step with some preparation which consists of the following two claims.
Claim 4.5**.**
almost everywhere on , where
[TABLE]
[TABLE]
and
[TABLE]
By (4.5), we have
[TABLE]
which, together with Lemmas 2.4 and 2.5, implies
[TABLE]
Then, we know from (4.13) that, to prove the claim, it suffices to show that
[TABLE]
Again, it follows from (4.5) that
[TABLE]
and thus, (2.6) gives
[TABLE]
This implies that, to prove (4.14), we only need to verify the validity of the following inequality:
[TABLE]
We now prove this inequality. On the one hand, since is a -quasiconformal mapping, it follows from Theorem that for any ,
[TABLE]
which implies
[TABLE]
On the other hand, since , we see from
[TABLE]
and
[TABLE]
that
[TABLE]
Then, we infer from (4.17) and the following fact:
[TABLE]
that
[TABLE]
Obviously, the inequality (4.15) follows from (4.16) and (4.18), and so, the claim is proved.
Claim 4.6**.**
For
By the Choquet-RadΓ³-Kneser theorem (see [1, 8]), we see that is a sense-preserving harmonic diffeomorphism of onto itself. It follows from Lewyβs theorem (cf. [31]) and [18, Inequality (17)] that
[TABLE]
Hence, for , we can let
[TABLE]
and let
[TABLE]
where . Since is a sense-preserving harmonic diffeomorphism of , by (4.19), we see that
[TABLE]
By Claim 4.5, we have
[TABLE]
almost everywhere on
Let
[TABLE]
Then the measure of the set is zero. Hence, for , we have
[TABLE]
which, together with (4.20), (4.21) and the Lebesgue Dominated Convergence Theorem, implies
[TABLE]
where . It follows from (4.22) and the arbitrariness of that, for ,
[TABLE]
from which the claim follows.
Now, we are ready to finish the proof of the co-Lipschitz continuity of . Since
[TABLE]
we see from Claim 4.6, Lemmas 2.4 and 2.5 that
[TABLE]
where
[TABLE]
And, we know from (4.11) and (4.12) that for small enough , where . Since for all ,
[TABLE]
we conclude that is co-Lipschitz continuous.
Step 4.3**.**
Bounds of the Lipschitz continuity coefficients and .
The discussions of this step consists of the following two claims.
Claim 4.7**.**
There are constants and such that
- (1)
2. (2)
and 3. (3)
[TABLE]
From (4.10), we see that
[TABLE]
where
[TABLE]
Then, we have
[TABLE]
where , , , , , and
[TABLE]
Let
[TABLE]
and
[TABLE]
It follows from the facts
[TABLE]
that these two constants are what we need, and so, the claim is proved.
Claim 4.8**.**
There are constants and such that
- (1)
2. (2)
, and 3. (3)
[TABLE]
By (4), we have
[TABLE]
where
[TABLE]
and
[TABLE]
The following facts
[TABLE]
show that these two constants are what we want, and thus, the claim is true.
Now, by the discussions of Steps 4.1 4.3, we see that the theorem is proved. β
5. The proof of Proposition 1.8
By (1.5), we have
[TABLE]
For , it follows from Lemmas 2.4 and 2.5 that are Lipschitz continuous in . Since is Lipschitz continuous in if and only if the Hilbert transform of , together with the Lipschitz continuity of , we conclude that is Lipschitz continuous in if and only if the Hilbert transform of , where . The proof of this proposition is complete. β
Acknowledgements: We are grateful to the referee for her/his comments and suggestions. This research was partly supported by the exchange project for the third regular session of the China-Montenegro Committee for Cooperation in Science and Technology (No. 3-13), the Hunan Provincial Education Department Outstanding Youth Project (No. 18B365), the Science and Technology Plan Project of Hengyang City (No. 2018KJ125), the National Natural Science Foundation of China (No. 11571216), the Science and Technology Plan Project of Hunan Province (No. 2016TP1020), the Science and Technology Plan Project of Hengyang City (No. 2017KJ183), and the Application-Oriented Characterized Disciplines, Double First-Class University Project of Hunan Province (Xiangjiaotong [2018]469).
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