Uniqueness for an obstacle problem arising from logistic-type equations with fractional Laplacian
Tomasz Klimsiak

TL;DR
This paper establishes a new uniqueness theorem for an obstacle problem involving the fractional Laplacian, extending classical results and employing probabilistic potential theory applicable to various integro-differential operators.
Contribution
It introduces a novel proof technique based on probabilistic potential theory for the fractional Laplacian obstacle problem, broadening applicability beyond classical operators.
Findings
Proved uniqueness for the obstacle problem with fractional Laplacian
Extended classical Laplace operator results to fractional case
Developed a new probabilistic proof method
Abstract
We prove a uniqueness theorem for the obstacle problem for linear equations involving the fractional Laplacian with zero Dirichlet exterior condition. The problem under consideration arises as the limit of some logistic-type equations. Our result extends (and slightly strengthens) the known corresponding results for the classical Laplace operator with zero boundary condition. Our proof, as compared with the known proof for the classical Laplace operator, is entirely new, and is based on the probabilistic potential theory. Its advantage is that it may be applied to a wide class of integro-differential operators.
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Taxonomy
TopicsAdvanced Mathematical Modeling in Engineering · Nonlinear Partial Differential Equations · Numerical methods in inverse problems
Uniqueness for an obstacle problem arising from logistic-type equations
with fractional Laplacian
Tomasz Klimsiak
Faculty of Mathematics and Computer Science, Nicolaus Copernicus University
Chopina 12/18, 87–100 Toruń, Poland
E-mail address: [email protected]
Abstract
We prove a uniqueness theorem for the obstacle problem for linear equations involving the fractional Laplacian with zero Dirichlet exterior condition. The problem under consideration arises as the limit of some logistic-type equations. Our result extends (and slightly strengthens) the known corresponding results for the classical Laplace operator with zero boundary condition. Our proof, as compared with the known proof for the classical Laplace operator, is entirely new, and is based on the probabilistic potential theory. Its advantage is that it may be applied to a wide class of integro-differential operators.
††footnotetext: Mathematics Subject Classification: Primary 35R35; Secondary 35R11††footnotetext: Keywords: Dirichlet fractional Laplacian, obstacle problem, logistic equation, intrinsic ultracontractivity.
1 Introduction
Let , , be a bounded Lipschitz domain, be a bounded Dirichlet regular domain (with respect to the fractional Laplacian). For , we denote by the Dirichlet fractional Laplacian on with zero exterior condition (see Section 2 for details). In case , by we mean the classical Laplace operator on with zero boundary condition. In the present paper, we prove a uniqueness result for the following obstacle problem:
[TABLE]
where is a positive constant, and
[TABLE]
Problem of this type arises in the study of asymptotic behaviour, as , of logistic type equations (see [11, 29] for the case and [22] for equations with ). Problem (1.1) with also arises as the limit of some predator-prey models (see [9, 12]).
From [11] (in case ) and [22] (in case ) we know that (1.1) has a solution if and only if , where stand for the first eigenvalue of and , respectively. In the present paper, we concentrate on the uniqueness of solutions to (1.1). This problem is quite subtle and difficult. In [10] it is investigated in case . Suppose that are smooth and . The main result of [10] states that (1.1) has at most one solution if . This result is proved by using an equivalent free boundary formulation of (1.1) and tools from the theory of variational inequalities and harmonic functions.
The method used in [10] seems to be suitable only for . To deal with nonlocal operators, we propose a new method. It allows us to prove that if , then for any there exists at most one solution to (1.1). This generalizes the result of [10] to nonlocal operators but also slightly strengthens the known uniqueness result for because we assume that and not that as in [10]. Moreover, we consider less regular than in [10] domains (see comments in [10, Remark (i)]).
In the present paper, we use a definition of solution to (1.1), which is equivalent to, but different from that of [10]. Let denote the Dirichlet form associated with the operator (see Section 2). By a solution to (1.1) we mean a strictly positive function (closure of in ) having the property that -a.e. and such that for some bounded smooth nonnegative Borel measure on (called the reaction measure for ) we have
[TABLE]
where stands for the usual inner product in and is a quasi-continuous -version of ( stands for the Lebesgue measure on ). Moreover, we require that satisfies the minimality condition, which says that for every quasi-continuous such that -a.e. we have
[TABLE]
where is a quasi-continuous -version of . In other words, is a solution of the following equation with measure data
[TABLE]
where is a positive measure which acts only when touches the barrier. Our proof of uniqueness is based on the following two crucial observations. The first one is that if is a solution to (1.1), then
[TABLE]
so in fact,
[TABLE]
Equivalently,
[TABLE]
This shows that any solution to (1.1) is in fact an eigenfunction for the operator , i.e. the operator perturbed by the smooth bounded measure . It is well known that this operator is a self-adjoint nonnegative operator on generating a Markov -semigroup of contractions on . The second crucial observation is that has a compact support in . This allows us to prove, by using some results of Hansen [17], that the Green function for is comparable with the Green function for . These two facts, when combined with the sub and supersolutions method (generalized in the present paper to the case of our obstacle problem), give the uniqueness result.
2 Potential theory for fractional Laplacian on bounded domain
For fixed and , we denote . In the whole paper, we assume that is an open bounded Lipschitz domain in with Lipschitz character , , i.e. open nonempty subset of such that: for every there exists a function such that
[TABLE]
and there exists an orthogonal coordinate system such that if in , then
[TABLE]
We denote by the Lebesgue measure on . By (resp. , we denote the set of Borel measurable functions on (on ) with values in . is the subset of consisting of all bounded functions.
2.1 Dirichlet fractional Laplacian
Let . To define the Dirichlet fractional Laplacian on , we first set
[TABLE]
and for , we set
[TABLE]
where stands for the Fourier transform of . Let us consider the form defined as
[TABLE]
where
[TABLE]
By [15, Example 1.4.1], is a regular symmetric Dirichlet form on . In the language of Sobolev spaces, (see [26, page 76]). When the more explicit formula for is known (see e.g. [15, Example 1.4.1]):
[TABLE]
The capacity Cap associated with is defined as follows: for an arbitrary open set , we set
[TABLE]
and then, for an arbitrary , we set
[TABLE]
We say that some property holds -quasi everywhere (-q.e. in abbreviation) if it holds except possibly a set of capacity Cap zero. Such sets shall be called -exceptional.
Recall that a function on is called -quasi-continuous if for every there exists a closed set such that Cap and is continuous. By [15, Theorem 2.1.3], each admits an -quasi-continuous -version. In what follows for given function , we denote by its -quasi-continuous -version (whenever it exists).
We denote by the part of on . Recall that
[TABLE]
By [15, Theorem 4.4.3], is a regular symmetric Dirichlet form on . Therefore, by [15, Sections 1.3,1.4], there exists a unique self-adjoint nonpositive definite operator on such that
[TABLE]
The operator is called the Dirichlet fractional Laplacian. We put
[TABLE]
By [15, Theorem 4.4.3], is a dense subspace of in the norm determined by . Therefore (see [26, page 77]). For ,
[TABLE]
where
[TABLE]
It is worth noting here that , where is the Laplace operator with zero Dirichlet boundary condition on . The latter operator is called the fractional Dirichlet Laplacian.
By replacing by and by in (2.1) and (2.2), we define the capacity CapD associated with , and then we define the notions of -exceptional sets and -quasi-continuity. By [15, Theorem 4.4.4], Cap and CapD are strongly equivalent on . Therefore, without ambiguity, we may write q.e., exceptional or quasi-continuous instead of -q.e., -q.e. -exceptional, -exceptional or -quasi-continuous, -quasi-continuous.
2.2 Green functions and transition functions
We denote by , the resolvent and the -semigroup of contractions generated by , respectively, and by , the resolvent and the -semigroup of contractions generated by , respectively.
Let be a one-point compactification of . Let denote the set of all functions , that are right continuous and possess the left limits for all (cádlágs), and have the property that if , then . We equip with the Skorokhod topology, see e.g. Section 12 of [1]. Define the canonical process: , , , shift operator: , , and life time: , . It is well known that there exists a rotation invariant -stable Lévy process on such that for every nonnegative ,
[TABLE]
We let for and
[TABLE]
In the whole paper we adopt the convention that any function defined on a subset of equals zero at . By [15, Theorem 4.4.2], there exists a Hunt process on such that
[TABLE]
Here is a filtration (non-decreasing sequence of -fields of subsets of ). By [15, Theorem 4.4.1, Theorem 4.4.2], for all and nonnegative ,
[TABLE]
where
[TABLE]
Hence
[TABLE]
It is well known (see [15, Exercise 4.2.1, Lemma 4.2.4]) that there is (called the -Green function) such that for every ,
[TABLE]
Similarly, there is (called the -Green function for ) such that for every ,
[TABLE]
Given a nonnegative Borel measure on , we set
[TABLE]
Note that -a.e. for every . Moreover, by [15, Theorem 4.2.3], and q.e. for . By [15, Exercise 4.2.1], there exists a transition function such that for every ,
[TABLE]
It is well known (see e.g. [16]) that is finite and strictly positive for . Given a nonnegative Borel measure on , we set
[TABLE]
By [15, Theorem 4.2.3], and q.e. for all and . Moreover,
[TABLE]
It follows that we can set
[TABLE]
It is well known that is a bijection. From the above definition of it follows that for every ,
[TABLE]
By [15, Lemma 2.2.11], and q.e. for every . For a nonnegative Borel measure on , we set
[TABLE]
Recall that a positive Borel measurable function on is called excessive if
[TABLE]
By [15, Lemma 4.2.4], for every positive Borel measure , is an excessive function.
2.3 Smooth measures
An increasing sequence of closed subsets of (resp. ) is called a generalized -nest (resp. generalized -nest) if for every compact (resp. ), Cap (resp. Cap) as . A Borel signed measure on (resp. ) is called -smooth (resp. -smooth) if it charges no set of capacity Cap (resp. CapD) zero and there exists a generalized -nest (resp. -nest) such that , , where denotes the variation of . Note that if a Borel measure on is bounded, then it is -smooth if and only if it is -smooth. This follows from the fact that Cap and CapD are equivalent.
We denote by (resp. ) the set of all -smooth (resp. -smooth) measures on (resp. ). We also set
[TABLE]
By [23, Proposition 5.13],
[TABLE]
Also note that if is a Borel measure such that on , then (see [15, Exercise 4.2.2]). We say that an -smooth measure belongs to the class (called the class of measures of finite energy integral) if there exists such that
[TABLE]
By [15, Theorem 2.2.2], for any positive and ,
[TABLE]
2.4 Probabilistic potential theory
Recall that a bounded subset of is called Dirichlet regular (with respect to the fractional Laplacian) if for every ,
[TABLE]
By [2, Example VII.3.4.3], each bounded Lipschitz domain is Dirichlet regular. From this and [6] it follows that is doubly Feller. This means that it is strongly Feller, i.e. for every , and it is Fellerian, i.e. for every .
By [15, Theorem 5.1.4], there is a one-to-one correspondence between nonnegative -smooth measures and positive continuous additive functionals (PCAFs) of (see [15, Section 5.1]). By we denote the unique PCAF of associated with . By [15, Theorem 5.1.3] and (2.6),
[TABLE]
for q.e. . For a signed measure having a decomopsition into a positive and negative part, we set . Note also that if and , then there exists a strict PCAF of such that (2.9) holds for every (see [15, Theorem 5.1.6]).
Recall that a càdlàg process adapted to is called a martingale additive functional (MAF) of iff , is an additive functional, q.e. , and q.e. . A MAF of is called uniformly integrable iff for q.e. , and every stopping time ,
[TABLE]
The following very useful result will be frequently used in the sequel.
Lemma 2.1**.**
Assume that and . Then
[TABLE]
for q.e. if and only if there exists a uniformly integrable MAF of such that for q.e. ,
[TABLE]
Moreover, if , then ”for q.e. ” may be replaced by ”for every ” with being a strict PCAF of .
Proof.
First suppose that (2.11) is satisfied. Taking the expectation with respect to of both sides of (2.11) with , and then using (2.9) with we get (2.10). Now suppose that (2.10) holds. Let be an exceptional set such that (2.10) holds for . By [15, Theorem 4.1.1], we may assume that for every . Hence, by (2.10), additivity of , and strong Markov property, for every and every stopping time , we have
[TABLE]
Set
[TABLE]
By quasi-continuity of and [15, Theorem 4.6.1], is a càdlàg process. Clearly, is an additive functional and . By (2.12), is a uniformly integrable martingale on under measure . Equivalently, by (2.5), is a uniformly integrable martingale on under measure for . If , then the above argument holds true with with one exception that instead of [15, Theorem 4.6.1] one need to apply [3, Theorem III.5.7]. ∎
2.5 Feynman-Kac formula
For a nonnegative measure such that , we define the perturbation of the form by as follows:
[TABLE]
By [15, Theorem 6.1.2], is a regular symmetric Dirichlet form on . Let be the semigroup generated by and be its generator. We let
[TABLE]
By [15] there exists a Hunt process on such that
[TABLE]
We denote by the Green function for (see [15, Exercise 6.1.1]). By [15, Theorem 6.1.1], we have the Feynman-Kac representation formula
[TABLE]
3 Integral supersolutions of the obstacle problem
Let be a measurable strictly positive function and be a continuous function. Consider the following obstacle problem:
[TABLE]
In this section, we give a definition of an integral solution to (3.1). We also recall widely used in the literature definition of weak solutions via variational inequalities. We show that both definitions are equivalent under regularity assumptions on . However, we prefer to work on integral solutions. The advantage of this notion is that its formulation does not require any regularity from solutions (merely integrability), and it allows us introduce the notion of super and subsolutions. Moreover, by using integral solutions, we may apply probabilistic potential theory, which is very useful in many reasonings. We then show that minimum of two integral supersolutions of (3.1) is again an integral supersolution. This property will be one of the crucial ingredients in the proof of uniqueness of (1.1).
Definition 3.1**.**
We say that a quasi-continuous function is an integral solution to (3.1) if there exists a nonnegative (we call it the reaction measure for ) such that
- (a)
-a.e. and q.e., 2. (b)
For q.e. ,
[TABLE] 3. (c)
For any quasi-continuous function on such that -a.e.,
[TABLE]
Remark 3.2**.**
(i) Take any quasi-continuous function such that -a.e. Observe that is an integral solution to (3.1) if and only if is an integral solution to (3.1) with replaced by .
(ii) If is quasi-continuous, then is an integral solution to (3.1) if and only if (a), (b) are satisfied and .
(iii) Recall that by [15, Lemma 2.1.4], if -a.e. and are quasi-continuous, then q.e.
(iv) Note that by [15, Theorem 4.6.1,Theorem A.2.7], functions , , are quasi-continuous as all the mentioned functions are excessive and finite q.e. So, if (b) holds -a.e., then by (iii), (b) holds q.e. Clearly, does not depend on the version of . Therefore, if we assume in the Definition 3.1 that is merely a measurable function such that (a), (c) hold, and (b) holds -a.e., then there exists a version of such that is quasi-continuous and (b) holds q.e. with replaced by : this version is given by if and zero otherwise. Clearly, q.e.
Recall that stands for the usual inner product in .
Definition 3.3**.**
We say that a quasi-continuous function is a weak solution to (3.1) if
- (a)
-a.e. and , 2. (b)
For every such that -a.e.,
[TABLE]
Proposition 3.4**.**
Let and . Then is an integral solution to (3.1) iff is a weak solution to (3.1).
Proof.
Let be an integral solution to (3.1). Since , . Thus, . Therefore, by (2.8) and (c) of Definition 3.1, for every such that -a.e.,
[TABLE]
Now, let be a weak solution to (3.1). By [25, Theorem 5.2, Chapter 3] weakly in , where is a unique solution to the following variational equality
[TABLE]
Clearly, , -a.e., where . By [21, Theorem 3.8], , where is an integral solution to
[TABLE]
Since -a.e., we get the desired result (cf. Remark 3.2(iv)). ∎
Definition 3.5**.**
We say that a quasi-continuous function is an integral supersolution (resp. integral subsolution) to (3.1) if there exists a nonnegative measure and a nonnegative (resp. nonpositive) measure such that conditions (a) and (c) of Definition 3.1 are satisfied, and moreover, for q.e. ,
[TABLE]
Proposition 3.6**.**
*If is an integral supersolution and an integral subsolution to (3.1), then is an integral solution to *(3.1).
Proof.
By assumptions and Definition 3.5, there exist nonnegative measures such that
[TABLE]
[TABLE]
and for every quasi-continuous on such that -a.e. Thus,
[TABLE]
for q.e. . From this, we conclude that . Therefore, there exist nonnegative such that and
[TABLE]
Consequently, for q.e ,
[TABLE]
Since for every quasi-continuous on such that -a.e., we see that is an integral solution to (3.1). ∎
Proposition 3.7**.**
*Let be integral supersolutions to (3.1). Then is a an integral supersolution to *(3.1).
Proof.
By the definition of a an integral supersolution to (3.1) and Lemma 2.1, for q.e. , we have
[TABLE]
, for some nonnegative and some uniformly integrable MAFs of . By the Tanaka-Meyer formula (see, e.g., [27, IV.Theorem 70]) applied to , there exists an increasing càdlàg process with such that for q.e. ,
[TABLE]
From the above formula, we get, in particular, that is a positive AF of . By [15, Theorem A.3.16] there exists a positive AF which is the dual predictable projection of under measure for q.e. . Since is a Hunt process it is, by the very definition, quasi-left continuous, so it has only totally inaccessible jumps. Therefore, since is quasi-continuous, process has only totally inaccessible jumps under measure for q.e. (see [15, Theorem 4.2.2]). Moreover, by [7, Proposition 2, Proposition 4] every local -martingale has only totally inaccessible jumps. By the definition of dual predictable projection, is an -martingale. Therefore, by (3), has only totally inaccessible jumps under measure for q.e. . However, is predictable. Consequently, is continuous. So, is a PCAF of . Hence for some nonnegative (cf. Section 2.4). Define and . By Lemma 2.1, for q.e ,
[TABLE]
Let be a quasi-continuous function such that -a.e. Observe that
[TABLE]
Clearly, -a.e., and -a.e. So, by condition (c) of Definition 3.1 applied to and , we get
[TABLE]
Thus, . This combined with (3.4) implies that is an integral supersolution to (3.1). ∎
Proposition 3.8**.**
Assume that is nondecreasing. Let (resp. ) be a bounded integral subsolution (resp. supersolution) to (3.1) and q.e. Then there exists an integral solution to (3.1) such that q.e.
Proof.
Let . We first show that for each there exists an integral solution to the problem
[TABLE]
and
[TABLE]
where is the reaction measure for . Indeed, the existence of follows from [21, Theorem 3.8]. By [21, Proposition 3.12], q.e. In particular, q.e. Hence, by [21, Theorem 3.8] again, there exists an integral solution to (3.5), and by [21, Proposition 3.12] again, q.e. and q.e. Continuing in this fashion, we get the existence of having the desired properties. Moreover, by [21, Proposition 3.12], . Let , and
[TABLE]
Observe that
[TABLE]
Therefore, by [23, Lemma 5.4],
[TABLE]
The right-hand side is finite since are bounded and is bounded. By the Vitali-Hahn-Saks theorem is a bounded Borel measure and
[TABLE]
By (2.7), q.e., and q.e. So, by (3.6) and the Lebesgue dominated convergence theorem,
[TABLE]
Thus,
[TABLE]
By Remark 3.2(iv), is quasi-continuous. Clearly, -a.e. Let be an arbitrary quasi-continuous function such that -a.e. Then, by the minimality condition (c) of Definition 3.1 applied to , and by (3.6),
[TABLE]
Thus, is an integral solution to (3.1). ∎
4 Uniqueness result
As in Sections 2 and 3, we assume that is a bounded Lipschitz domain in () and is a bounded Dirichlet regular domain. We assume that , where is the first eigenvalue for the operator . By we denote the ground state for , i.e. a unique strictly positive function such that and
[TABLE]
It is well known that , and by the regularity of , .
To prove a uniqueness result for (1.1), we shall need some regularity results for integral solutions to (1.1), and the result which compare the Green function for with the Green function for .
It is well known (see e.g. [16]) that the semigroup is intrinsically ultracontractive, which implies that for every there exist constants such that
[TABLE]
Proposition 4.1**.**
Let be an integral solution to (1.1) and be the reaction measure for . Then .
Proof.
Set , and
[TABLE]
Clearly, since . By Dynkin’s formula (see [15, (4.4.2)]),
[TABLE]
By [15, Lemma 4.3.1], is an excessive function for . So, by [3, Proposition II.2.2], is an excessive function. By the definition of an integral solution, . Therefore, by (2.7), is finite q.e. So, by (4.3), is finite q.e. Consequently, as a difference of excessive functions finite q.e. is quasi-continuous (see comments in Remark 3.2(iv)). Thus, is quasi-continuous. By regularity of , . Moreover,
[TABLE]
By Dynkin’s formula again
[TABLE]
From this and the fact that on , we get that the -th power of satisfies
[TABLE]
Hence, by the definition of an integral solution to the obstacle problem,
[TABLE]
By (4.4), for every , as . It follows from (4.5) that supp. By this and (4.5) again, for every nonnegative we have
[TABLE]
which implies the desired result. ∎
Proposition 4.2**.**
If is an integral solution to (1.1), then
- (i)
* for q.e. .* 2. (ii)
. 3. (iii)
The reaction measure for is bounded and .
Proof.
By the definition of an integral solution to (1.1) and Proposition 4.1,
[TABLE]
for q.e . Using Lemma 2.1 and the integration by part formula applied to the product yields
[TABLE]
for q.e. . Therefore, by the ultracontractivity of , for every ,
[TABLE]
for q.e. , which proves (i). To prove (ii), consider the function defined by (4.2). By regularity of the set and [6], is doubly Feller (cf. Section 2.4). Therefore, by (i) . By regularity of , in fact . Thus, . By the proof of Proposition 4.1,
[TABLE]
So, by Remark 3.2(i), is an integral solution to (1.1) with replaced by . Therefore, by [30, Theorem 1], which proves (ii). By the definition of an integral solution to (1.1),
[TABLE]
for q.e. . From (4.6) and [23, Lemma 5.4] we get (iii). ∎
Proposition 4.3**.**
Let be an integral solution to (1.1) and be its reaction measure. Then
- (i)
supp* is a compact subset of .* 2. (ii)
.
Proof.
By Proposition 4.1, supp, which when combined with Proposition 4.2(ii) implies (i). Assertion (ii) follows easily from (4.6), Proposition 4.2 and (2.9). ∎
Proposition 4.4**.**
Let be an integral solution to (1.1) and let be its reaction measure. Then , and for every ,
[TABLE]
Proof.
By Proposition 4.2, and . Therefore, by [24, Theorem 3.5], is a renormalized solution to (1.1) in the sense defined in [24]. By the definition of a renormalized solution, , , which when combined with Proposition 4.2(i) implies that . Moreover, by the definition of a renormalized solution, there exists a sequence such that and for every bounded ,
[TABLE]
Letting yields (4.7) for every bounded . Applying now a simple approximation argument, we get that , and (4.7) holds for any . ∎
Let be a strictly positive excessive function with respect to . We say that has -triangle property iff there exists such that
[TABLE]
The above notion was introduced in [17]. Observe that if we set
[TABLE]
then (4.8) is equivalent to
[TABLE]
Clearly, if and only if , and . Therefore, -triangle property is equivalent to the statement that is a quasi-metric on .
Recall here that at the beginning of Section 2, we introduced and . We shall show that has -triangle property for Lipschitz domains, where and
[TABLE]
for a fixed . Here . Set , and fix such that . We let .
Proposition 4.5**.**
Green function has -triangle property.
Proof.
Let . By [18, Theorem 1],
[TABLE]
for , where depend only on . Here, for ,
[TABLE]
and for . Suppose that . Set . By (4.10),
[TABLE]
Observe that . Therefore, by [18, Lemma 13], there exists such that , where depends only on , and . Consequently, there exists such that
[TABLE]
Equivalently,
[TABLE]
Hence we get easily (4.9). ∎
Let denote the Green function for (and the operator ). It is well known that there is such that
[TABLE]
Lemma 4.6**.**
Assume that is nonnegative, is a compact subset of and . Then , i.e. there exist such that on .
Proof.
Let be an extension of to defined as for any Borel set . Let be an open set such that , and let . By [5, Theorem 1.2], there is such that
[TABLE]
From this and the assumptions of the lemma it follows that
[TABLE]
Next, for all ,
[TABLE]
By the 3G Theorem (see [19]),
[TABLE]
This when combined with (4) and (4) shows that there exists such that
[TABLE]
From this we conclude that for every nonnegative Borel measure on ,
[TABLE]
Equivalently,
[TABLE]
It is well known (see [14, Theorem 17, page 230]) that each -excessive function is an increasing limit of functions of the form for some nonnegative Borel measure . Therefore from (4.14) it follows that for every excessive function ,
[TABLE]
Taking (it is excessive as a minimum of excessive functions), we get
[TABLE]
From this, Proposition 4.5, and [17, Theorem 9.1] we get the desired result. ∎
Theorem 4.7**.**
Assume that . Then there exists at most one integral solution to (1.1).
Proof.
Let be two integral solutions to (1.1). We divide the proof into two steps.
Step 1. We shall show that without loss of generality we may assume that . Assume that whenever we know that are integral solutions to (1.1) such that , then . By Proposition 3.8, is a an integral supersolution to (1.1). It is clear that for a sufficiently small , . Therefore, since
[TABLE]
and , we see that is a an integral subsolution to (1.1) (cf. (2.8)). By the definition of an integral supersolution to (1.1), there exist nonnegative measures such that
[TABLE]
and is the reaction measure for . By Proposition 4.1, the above equation may be equivalently rewritten as
[TABLE]
By Lemma 2.1 there exists a MAF such that for any ,
[TABLE]
By the integration by parts formula applied to the product , we get
[TABLE]
Taking expectation of both sides of the above equation with yields
[TABLE]
Therefore, by (2.15),
[TABLE]
By Proposition 4.2, Proposition 4.3 and Lemma 4.6, . This when combined with the above equation and (4.1) gives
[TABLE]
so for some . Hence, for a sufficiently small , is a an integral subsolution to (1.1) such that . By Proposition 3.8, there exists an integral solution to (1.1) such that . Hence and . By the assumption of Step 1, .
Step 2. Assume that . Let be the reaction measures for and , respectively. Then, by Proposition 4.4,
[TABLE]
Hence
[TABLE]
From this and Proposition 4.1 we conclude that
[TABLE]
We can regard as a solution to the following obstacle problem
[TABLE]
where . Since , we have . Applying [21, Proposition 3.12] yields . This when combined with (4.17) and the fact that are strictly positive implies that . Therefore, we have
[TABLE]
Thus,
[TABLE]
We have assumed that . Striving for a contradiction, suppose that for some . Then continuity of and (4.18) would imply that is strictly positive on , in contradiction with the fact that . ∎
Remark 4.8**.**
All the results of the paper hold for . In case the proofs run in the same way as in case , the only difference being in the proof of Proposition 4.5 and Lemma 4.6. In case , Proposition 4.5 follows from [28, Theorem 3.1], and in case it follows from [17, Corollary 9.6] - we need however to be finitely connected. As to the proof of Lemma 4.6, in case , to get (4.13), we use [8, Theorem 6.24], and in case , we use [8, Theorem 6.5]. Instead of [5, Theorem 1.2], we use [8, Lemma 6.7].
Ultracontractivity of the semigroup generated by follows from [13, Theorem 9.3]. That Lipschitz bounded domains are Dirichlet regular is well known (see, e.g., [2, page 350]).
Acknowledgements
This work was supported by Polish National Science Centre (Grant No. 2017/25/B/ST1/00878).
Data sharing not applicable to this article as no datasets were generated or analysed during the current study.
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