Modular hyperbolas and bilinear forms of Kloosterman sums
Ilya D. Shkredov

TL;DR
This paper explores incidence geometry of hyperbolas over finite fields and applies linear sum-product techniques to derive new bounds for bilinear Kloosterman sum forms.
Contribution
It introduces a combinatorial approach to bounding bilinear Kloosterman sums using incidence results for hyperbolas in finite fields.
Findings
Established incidence bounds for hyperbolas in finite fields
Derived a new upper bound for bilinear Kloosterman sums
Demonstrated the effectiveness of sum-product methods on hyperbolic curves
Abstract
In this paper we study incidences for hyperbolas in and show how linear sum--product methods work for such curves. As an application we give a purely combinatorial proof of a nontrivial upper bound for bilinear forms of Kloosterman sums.
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Modular hyperbolas and bilinear forms of Kloosterman sums
††This work is supported by the Russian Science Foundation under grant 19–11–00001.
Shkredov I.D
Annotation.
*In this paper we study incidences for hyperbolas in and show how linear sum–product methods work for such curves. As an application we give a purely combinatorial proof of a nontrivial upper bound for bilinear forms of Kloosterman sums. *
1 Introduction
Let be an odd prime number, and be the finite field. Given two sets , define the sumset, the product set and the quotient set of and as
[TABLE]
[TABLE]
and
[TABLE]
correspondingly. This paper is devoted to the so–called sum–product phenomenon, which says that either the sumset or the product set of a set must be large up to some natural algebraic constrains. One of the strongest form of this principle is the Erdős–Szemerédi conjecture [9], which says that for any sufficiently large set of reals and an arbitrary one has
[TABLE]
The best up to date results in the direction can be found in [30] and in [26] for and , respectively. Basically, in this paper we restrict ourselves to the case of the finite fields only.
It was Elekes [7] who realised that the sum–product phenomenon is connected with Incidence Geometry. Incidence Geometry deals with the incidences among basic geometrical objects such as points, lines, curves, surfaces and so on. After Elekes various results on incidences of different types in were obtained by many authors (see, e.g., [37]). Nevertheless, in only linear incidences, i.e., incidences between linear objects as points/planes, points/lines, lines/lines were obtained see, e.g., [27], [35], [38]. A remarkable exception is the case of so–called –hyperbolas and this exception was suggested by Bourgain [2] who gives, in particular, the first nontrivial upper bound for cardinality of the following set
[TABLE]
for any and arbitrary sets . The importance of hyperbolas in Additive Combinatorics and Number Theory was discussed in [32]. Bourgain’s approach was connected with the group actions (the importance of the group actions in Additive Combinatorics was realized by Elekes as well, see [6], [8]) and it was based on Helgott’s result on growth in , see [12], [13] and on some additional considerations [3].
In this paper we obtain a series of new upper bounds for cardinality of the set from (1). Here are two of our results (other results can be found in Sections 5, 6, see, e.g., Theorem 32 below).
Theorem 1
Let be sets. Then for any , one has
[TABLE]
[TABLE]
The Theorem above allows to obtain a uniform upper bound for size of hyperbola with elements from a set with the small sumset.
Corollary 2
Let be a set. Suppose that and . Then for any , one has
[TABLE]
Another rather unusual result (for example, the proof uses the fact that the group contains free subgroups) on incidences (1) is the following (an analogue of this statement in is our Theorem 32 from Section 6).
Theorem 3
Let , be sets, and be any number. Then
[TABLE]
[TABLE]
Rather mysterious part of Helfgott’s proof of –growth result was that the sum–product phenomenon in , which deals exclusively with linear objects as points/lines, points/planes and so on gives absolutely nontrivial results for completely different curves, namely, for hyperbolas. An explanation in a particular but a transparent case is given in our Lemma 28, where we estimate a certain energy of a subset of matrices from via purely linear sum–product quantity. Now it remains to notice that energies of subsets of acting groups are naturally related with the incidences, see, e.g., [23], [24], [28].
It turns out that incidences between hyperbolas and points are connected with bilinear forms of Kloosterman sums, see [1], [10], [14]–[19], [32]–[34] and other papers. We obtain the following result in this direction (see Theorems 33, 34 from Section 7), which we formulate here in a particular case (the main advantage of our method is that it allows to consider rather general sets and weights). Recall that the Kloosterman sum in a finite field is
[TABLE]
We are interested in bilinear forms of Kloosterman sums [15]–[17], that is, the sums of the form
[TABLE]
where , are rather arbitrary functions.
Theorem 4
Let be functions with supports on and , respectively, and or is at most , . Then
[TABLE]
where is a positive constant. Besides, if , then
[TABLE]
It is easy to check that the last result is better than [33, Theorem 7], as well as [10, Theorem 1.17(2)] but worse than the current world record from [16] in the case . Of course the advantage of our results is that they hold in very general situation. Also, the method of the proof is not analytical but combinatorial one and hence does not require deep tools from Algebraic Geometry as in [16].
In our paper we develop the ideas from [23], where growth in was applied to the Zaremba conjecture about continued fractions. Before this paper various analytical tools (as Kloosterman sums) were used in the aforementioned area, see, e.g., [22]. After [23] it is not surprising that sometimes combinatorial methods give results of comparable quality to the ones, which were obtained via deep analytical techniques.
All logarithms are to base The signs and are the usual Vinogradov symbols. For a positive integer we set Having a set , we will write or if , .
The author is grateful to Brendan Murphy, Nikolay Moshchevitin, Dmitrii Frolenkov and Maxim Korolev for very useful discussions and fruitful explanations.
2 Notation
In this paper is a field, and is an odd prime number, and . We denote the Fourier transform of a function by namely,
[TABLE]
where . We rely on the following basic identities. The first one is called the Plancherel formula and its particular case is called the Parseval identity
[TABLE]
Another particular case of (8) is
[TABLE]
and the identity
[TABLE]
is called the inversion formula. The (normalized) Wiener norm of is defined as
[TABLE]
Clearly, by the Parseval identity (8), the inverse formula (10) and the Cauchy–Schwarz inequality, we have
[TABLE]
It is well–known that equipped with the Wiener norm the set of functions on the group forms an algebra relatively pointwise multiplication. In this paper we use the same letter to denote a set and its characteristic function . Also, we write for the balanced function of a set , namely, . Let be the set .
Put for the common additive energy of two sets (see, e.g., [37]), that is,
[TABLE]
If , then we simply write instead of and the quantity is called the additive energy in this case. One can consider for any complex function as well. More generally, we deal with a higher energy
[TABLE]
The last identity follows from (9). Another sort of higher energy is [29]
[TABLE]
Sometimes we use representation function notations like or , which counts the number of ways can be expressed as a product or a sum with , , respectively. Further clearly
[TABLE]
and by (9),
[TABLE]
Similarly, one can define , , and so on.
3 Preliminaries
We need in a sum–product result from [31, Theorem 32], as well as [25, Theorem 35].
Lemma 5
Let be sets. Then
[TABLE]
Lemma 6
Suppose that is a subset of such that and . Then
[TABLE]
In [5, Theorem 2] it was obtained a very precise result on multiplicative energy of arithmetic progressions.
Theorem 7
Let and be arithmetic progressions with the difference equals one. Then
[TABLE]
The last result about Fourier transform of arithmetic progressions is well–known.
Lemma 8
Let be an arithmetic progression. Then and for any the following holds
[TABLE]
4 Some non–abelian results
We will formulate and prove a series of results, which hold in general groups although, of course, our main applications concerns and .
Let be a group and be sets. For put
[TABLE]
More generally, one can define for any functions . Basically, we are interested in the case of the characteristic functions . If , then we write instead of as in Section 2. For any one has
[TABLE]
One of the reasons that we have defined as in (15) is that we have property (16). For example, if was defined as just the number of the solutions to the equation then formula (16) fails. Another reason is that for such defined Lemmas 19, 12 take place. Finally, in terms of eigenvalues of some operators, see the proof of Lemma 12 and Remark 13, we have for such a full analogue with the abelian case, compare formula (13) and formula (25).
Now if , then we write for and similarly for . It is convenient to put . Also, denote . Since for any , it follows that in any matrix group (as ) an arbitrary permutation of rows or columns preserves . Also, notice that . Further, , because the operator, which fix any positions from the left side and from the right side in (15) is, clearly, symmetric and nonnegatively defined (obviously, one has for any nonnegative operator defined on a set ). Using the Cauchy–Schwarz inequality, we have
[TABLE]
Further for consider the higher energies [29]
[TABLE]
and, similarly, .
We need in a lemma about quantities .
Lemma 9
Let be functions. Then
[TABLE]
In particular, for any one has
[TABLE]
P r o o f. For typographical reasons we will assume sometimes that for some sets . Clearly, by the Cauchy–Schwarz inequality for any
[TABLE]
and thus it is enough to have deal with the last quantities. Let us begin with (19) because its simplicity and to have the basis of the induction. From the last bound we see that . Further, using the Cauchy–Schwarz inequality again, we have
[TABLE]
[TABLE]
as required. Clearly, the same is true for functions. Now let is even (for odd a similar arguments hold). Using induction we obtain
[TABLE]
and hence it is enough to prove for any and that
[TABLE]
Now rewrite as
[TABLE]
and using induction again and the arguments as in (20), we obtain
[TABLE]
and, similarly,
[TABLE]
Combining the last two formulae, we get
[TABLE]
as required.
Corollary 10
The formula , defines a norm of an arbitrary function . Also, .
We need a well–known lemma, which we prove for the sake of completeness.
Lemma 11
Let be a group and let acts –transitively on a set . Suppose that and are sets. Then
[TABLE]
P r o o f. Using the Hölder inequality, we get
[TABLE]
By the assumption acts –transitively on . Hence fixing and , we find a unique such that , . Thus
[TABLE]
It gives us
[TABLE]
as required.
The well–known ”counting lemma” for general actions was proved many times, see, e.g., [2] or [31, Lemma 53]. We recall the proof for the case of completeness and because we will use some parts of the proofs later. Also, we replace in (22) to any even integer for an arbitrary finite group.
Lemma 12
Let be a group, which acts on a set and let be functions. Also, let be a set. Then for any , we get
[TABLE]
The same is true in the case if one replaces to any nonzero even integer.
P r o o f. Denote by the left–hand side of (22). Using the Cauchy–Schwarz, we obtain
[TABLE]
Continuing this way, we get
[TABLE]
where the term in is taken times. Thus, (22) follows.
Let us give another proof for even powers and finite group . Returning to (23), we have
[TABLE]
Consider a hermitian nonnegatively defined operator
[TABLE]
where are eigenvalues and are correspondent eigenfunctions. Thus
[TABLE]
Using the Hölder inequality and the orthogonality of the functions , we obtain
[TABLE]
[TABLE]
[TABLE]
This completes the proof.
Remark 13
In terms of the eigenfunctions of the operator from (24), we have the following formula (let for simplicity)
[TABLE]
and, clearly, .
5 First results on incidences for hyperbolas
Take any and consider our basic equation
[TABLE]
or, in other words,
[TABLE]
where
[TABLE]
Clearly, and hence in our main case we have . Also, in the next Section we will consider the set
[TABLE]
Notice that (”u” for a unipotent matrix from ) and
[TABLE]
Lemma below shows the connection between energy of a subset of and the sum–product phenomenon. Formulae (27), (28) say us that any nontrivial upper bound for linear incidences in an arbitrary field implies a good upper estimate for , .
Lemma 14
For any and , one has
[TABLE]
Besides
[TABLE]
P r o o f. Take three elements , , from . Putting , , we obtain
[TABLE]
[TABLE]
If , then we reconstruct , having the matrix above fixed. Now it remains to notice that
[TABLE]
[TABLE]
Further if , then and we can find, say, , having , and the matrix above fixed (see the right–up corner of the matrix above). Hence we need to count an additional term, which is at most
[TABLE]
Similarly, to calculate , we see that
[TABLE]
and hence
[TABLE]
This completes the proof.
Remark 15
Similarly, one can calculate higher energies of the set , and prove
[TABLE]
and
[TABLE]
Using these upper bounds for the energy of the set , we obtain our first incidence result. Theorem 30 implies Theorem 2 from the Introduction if one applies a trivial bound . Further, the first bound of Theorem 30 is nontrivial only if and , where but the second one is always nontrivial. Nevertheless it is interesting that incidences for hyperbolas are connected with the ordinary additive energy of a set. Also, the first bound takes place in any field not only in .
Theorem 16
Let be sets. Then for any , one has
[TABLE]
[TABLE]
[TABLE]
P r o o f. Rewrite our basic equation as , where we have new variables , , , . In other words, we need to count the number of the solutions to the equation with and , . Let . Then
[TABLE]
Here one can consider other balanced functions, e.g., of the set or even of the sets , in our set of actions (in other words is taken with the correspondent weight in this case). Using Lemma 12 with , we get
[TABLE]
Applying Lemma 21 with , as well as the second part of Lemma 28, we obtain
[TABLE]
[TABLE]
Similarly, using Lemma 12 with , we have
[TABLE]
Denote by . It gives us
[TABLE]
and by the pigeonhole principle there is such that
[TABLE]
where . From the last inequality one can derive . It follows that if , then . Otherwise in view of Lemma 21, we have . Now combining (32), the second part of Lemma 19 and the Cauchy–Schwarz inequality, we obtain
[TABLE]
Using and our lower bound , we get
[TABLE]
Applying Lemma 28 and Lemma 5 to estimate , we derive
[TABLE]
Here we do not need to have deal the term in Lemma 5 because one can consider the balanced function of , in the set of actions (see details in [31]). Combining the last inequality with (33), we obtain
[TABLE]
This completes the proof.
Remark 17
One can apply general results from [23], [31] to nontrivially estimate via in Theorem 30 (see formula (31)) but we prefer to use because it gives better bounds.
Using a trivial bound , we obtain
Corollary 18
Let be sets. Then for any , one has
[TABLE]
[TABLE]
Remark 19
In [31, Theorem 41] it was proved, in particular, that for any one has , provided . It gives an improvement of Theorem 30 at least in the symmetric case (in particular, it gives a better bound in formula (36) of Corollary 37 below for small ).
Now let us obtain an upper bound for size of hyperbola with elements from a set with small sumset. First results of this type were obtained in [23] but our new bound is more ”quantitative”.
Corollary 20
Let be a set. Suppose that . Then for any , one has
[TABLE]
Finally, if , then
[TABLE]
P r o o f. Put . We have for any . Hence
[TABLE]
Applying the second part of Theorem 30, as well as a trivial estimate , we get
[TABLE]
To obtain the second bound of Corollary 37 we apply estimate (38) and then we use the first part of Lemma 28 directly. It gives us (see formulae (33), (34) from the proof of Theorem 30)
[TABLE]
To estimate , we use the Plünnecke inequality [37], combining with Lemma 6, and obtain
[TABLE]
provided . The last inequality satisfies thanks to our condition . This completes the proof.
To compare, using the Szemerédi–Trotter Theorem [36], one can obtain for any finite with and .
In our final consequence of Theorem 30 we have deal with the case of arithmetic progressions.
Corollary 21
Let be sets and , be arithmetic progressions with the differences equal one. Then for any , one has
[TABLE]
[TABLE]
P r o o f. Indeed, by Theorem 7, we know that
[TABLE]
We have
[TABLE]
After that apply the arguments of the proof of Theorem 30 and our upper bound for . It gives us, in particular,
[TABLE]
[TABLE]
and after that we substitute this bound into estimate as in Theorem 30. This completes the proof.
In a natural way, in the case of arithmetic progressions one can try to estimate higher energies . It turns out that in this situation ”first–stage” methods [3] work rather good and it will be done in the next Section, see Proposition 47 and Theorem 52 below.
6 Asymmetric results
In [23] and [31] the authors obtain a series of upper bounds for equation (1) in asymmetric cases (i.e. when the set of actions is relatively small). Let us recall two results from these papers.
Theorem 22
Let , be functions, and be sets. Also, let and . Then there is such that
[TABLE]
Further, if are any sets with and , then
[TABLE]
[TABLE]
The first part of Theorem 42 is Lemma 53 from [31] and the second part follows by the same arguments (with , , , , say) if one uses, in addition, any rough incidence result in see, e.g., [24] or our Lemma 21.
Now if the sets , in our sets , are special, then one can improve Theorem 42 as was done in [Theorem 11][23] (or see the sketch of the proof of Theorem 32 below).
Theorem 23
Let be any sets, and , , . Suppose that , . Then
[TABLE]
Here are absolute constants.
Corollary 24
Let be a set. Suppose that and , where is an absolute constant. Then there is such that
[TABLE]
where is an absolute constant.
The proof of Theorem 23 uses the following result, see [23, Lemma 27].
Lemma 25
Let . Then there is an absolute constant such that for an arbitrary integer the following holds
[TABLE]
In the same is true for all such that
[TABLE]
Remark 26
Actually, one can check from the proof of [23, Lemma 27], see [23, Theorem 25,29] that condition (45) can be replaced by for any and sufficiently large and . This square root condition looks rather natural. Further, in one can consider a more general family , where , see the proof of Theorem 52.
In the real setting one can easily calculate the constant from (44) in a simple way. Surprisingly, that our saving in the asymmetric case of sets of rather different cardinality (when are large comparable to , see below) is better than the famous Szemerédi–Trotter Theorem gives us (of course it is because a pair of our sets are arithmetic progressions). Although the focus of this paper is we give a proof of this result here because its simplicity and because we will use some parts of the proof later.
Proposition 27
Let be any number, be a set and let be an integer. Then for one has
[TABLE]
More precisely, if for a certain the following holds , then
[TABLE]
P r o o f. Denote by the left-hand side of (46) and let . Using Lemma 12, we obtain that for any the following holds
[TABLE]
Applying the Szemerédi–Trotter Theorem [36], we see that either
[TABLE]
or
[TABLE]
By Lemma 45 (also, see Remark 26) we know that , where is an absolute constant and is an arbitrary integer. Hence in the second case, we have
[TABLE]
Now let be the first number such that (48) takes place. We can assume that because otherwise we are done. Then (50) holds with . Comparing bounds (48), (50), we obtain
[TABLE]
as required. To prove (47) suppose that (50) does not hold with . Then by (48), we get
[TABLE]
or, in other words, and this contradicts with our assumption. This completes the proof.
Example 28
*Suppose that is an arithmetic progression on length and put
, . Then it is easy to see that for any the set contains . Also, choosing in an appropriate way, we can assume that . Hence our saving in (46) (or analogously the saving in (47)) cannot be replaced by any number strictly greater than .*
Now we formulate an analogue of Proposition 47 for an arbitrary set .
Theorem 29
Let , be sets, and be any number. Then
[TABLE]
[TABLE]
where
[TABLE]
More precisely, if for a certain the following holds , then
[TABLE]
[TABLE]
P r o o f. We use the arguments from the proof of Proposition 47. In particular, applying Lemma 12, we see that our aim is to estimate the quantity as in (49) but before we need some preparations. Put and . Split onto odd/even numbers , , further, split onto congruence classes modulo and use Lemma 19 or its consequence Corollary 10 to estimate via on sets . In the notation of the beginning of Section 5, we get
[TABLE]
[TABLE]
where variables and are from , correspondingly. Further, it is well–known (see, e.g., [20]) that the matrices
[TABLE]
generate a free subgroup of , provided or even when (it easily follows from the ping–pong lemma). Rewriting (53) as
[TABLE]
we see that the number solutions to the last equation is (for it coincides with the second bound of Lemma 28 in the symmetric case). Indeed, since , , it follows that all and are powers of matrices from (54) with and , correspondingly, and hence equation (55) has no nontrivial solutions. Thus, as in (48), (49), we have either
[TABLE]
or
[TABLE]
and hence as before
[TABLE]
as required. To obtain (52) we use the same calculations as in Proposition 47. This completes the proof.
As we have seen the proof of Theorem 52 gives us an analogue of Lemma 45, which we formulate in and in . Write .
Lemma 30
Let , be a real number. Put . Then for an arbitrary integer the following holds
[TABLE]
Now, let and , . Then
[TABLE]
P r o o f. Take and split onto odd/even numbers and onto congruence classes modulo . Using Corollary 10 and calculations in (53), (55), we obtain
[TABLE]
as required.
Now let us obtain bound (58) and again we split modulo two and , correspondingly, but before let us remark that by the definition of the set the operator –norm of any element of is
[TABLE]
Hence and implies that
[TABLE]
where for a matrix one has (see similar arguments in [21], [11], [4]). Clearly, there are at most of such matrices . Fixing and in (59), we need to solve this equation in . Thanks to (55) there are at most choices for . This completes the proof.
Remark 31
Notice that there is a universal way to estimate the energy in any field, namely, by Lemma 19 we always have . Again it connects the problem about incidences for hyperbolas with ordinary additive energies of sets.
The same arguments as in the proof of Theorem 23, Theorem 52 and Lemma 58 (or see the proof of [23, Theorem 24]) give us an analogues result for subsets of and for our two–parametric family of transformations from .
Theorem 32
Let , be any sets, and , , , . Suppose that , and . Then
[TABLE]
Here are absolute constants.
S k e t c h o f t h e p r o o f. Let be the left–hand side of (60) and . We take such that and thus by Lemma 58 one has . Considering , we have by estimate (17) that and similar for the intersection of with any proper subgroup of , see [3], [23]. By Lemma 19 one has
[TABLE]
Put . Thanks to our condition , we have and similar for the intersection of with any proper subgroup of . Then by general expansion result in , see [23, Theorem 9] or just formula of Theorem 42, we get
[TABLE]
where and . The first term in the last formula is negligible because our assumption . Thus, our saving is . This completes the proof.
We write Theorem 32 similar to Theorem 23 for compare these two results. Of course constants in (60) are worse than in (43).
7 On bilinear forms of Kloosterman sums
Let be a finite field, , be two weights and let
[TABLE]
be the Kloosterman sum. We are interested in bilinear forms of Kloosterman sums [15]–[17], that is, expressions
[TABLE]
Using the definition of the Fourier transform (7), we see that
[TABLE]
From the Parseval identity (8) and the Cauchy–Schwarz inequality, we obtain
[TABLE]
and applying usual upper bound for Kloosterman sum, as well as the Cauchy–Schwarz inequality again, we get
[TABLE]
Both basic bounds (62), (63) give for, say, and equal the characteristic function of some sets of sizes . This estimate is a kind of barrier and our task is to beat it for wide range of functions , .
The next general result demonstrates that the quantity is connected with a sum–product question, namely, with the counting of incidences for some hyperbolas. Actually, even simple formula (61) shows that this problem has the sum–product flavour. Indeed, suppose for simplicity that is the characteristic function of a progression, then the question about estimation of bilinear sums is equivalent to the problem how the inverse of a progression correlates with the set of large Fourier coefficients of . In other words, it is a question about how additive and multiplicative structure agree.
Theorem 33
Let be functions, . Then either
[TABLE]
or
[TABLE]
where depends on only. In particular, if and if or is at most , , then
[TABLE]
where is a positive constant. Here the sign depends on .
P r o o f. By (61) and (10), applied for the convolution, we have
[TABLE]
Let , , , . The number of such sets is at most and our sing below depends on this quantity. By the pigeon–hole principle there are and sets , , , , which we denote as , , , and numbers , , , such that
[TABLE]
If (or ) is at most , then by (12), the Parseval and the previous formulae, we have
[TABLE]
and thus we obtain (64). Now we use the fact that equals to apply our incidences results for hyperbolas. Using bound (41) from Theorem 42, as well as formula (12), we get
[TABLE]
[TABLE]
[TABLE]
as required.
Finally, inequality (66) follows from (64), (65) by the inverse formula (10), which gives
[TABLE]
and hence bound (64) is negligible. The first term in (65) is less than the second one, again because (12) (which gives , ) and our assumption that or is at most . This completes the proof.
Once again the main advantage of our result is its generality. For example, one can easily consider more general sets than arithmetic progressions in (66), say, Bohr sets of bounded dimension [37].
It is easy to check that the last result is better than [33, Theorem 7], as well as [10, Theorem 1.17(2)]. Thus, using relatively simple methods from Additive Combinatorics we break barrier in this problem.
Now we obtain a result on bilinear Kloosterman sums in a specific situation when the supports of the weights belong to arithmetical progressions.
Theorem 34
Let , be a function, , and be some shifts. Then
[TABLE]
and if , then
[TABLE]
Here the sign depends on .
P r o o f. We can suppose that and are sufficiently large because otherwise the result is trivial. Let us begin with (67). Let and be the characteristic functions of the arithmetic progressions and , respectively. Then for any weights , we can write and . After that we repeat the arguments of the proof of Theorem 33. Namely, splitting the level sets of the functions , we obtain sets , and positive numbers such that
[TABLE]
[TABLE]
Here we have used Corollary 35 and again in (69) and below our sing depends on . We will show later that the first two terms in (69) give the last two terms in (67) and now let us consider the third term in (70). From Parseval identity (8), we have
[TABLE]
In view of Lemma 8, we get
[TABLE]
and the same for and . Thus, we obtain
[TABLE]
as required. It remains to show that two terms in (69) give the last two terms in (67). In view of Lemma 8 and inequality (12) the first one gives
[TABLE]
and by the same lemma and the Parseval identity, as well as (14), (71), (72), we have for the second term
[TABLE]
Now let us prove (68). Let , be symmetric arithmetic progressions with steps equal one such that
[TABLE]
Let be any set and write and similar for (in this part of the proof one can put, simply, ). If , then we have
[TABLE]
[TABLE]
[TABLE]
and because is a symmetric set, as well as conditions (73), we obtain
[TABLE]
The same holds for and below we will write , where and similar for . Clearly, , and , for any . Hence by (61), the Cauchy–Schwarz inequality and formula (8), we get
[TABLE]
[TABLE]
[TABLE]
Now our task is to estimate the first sum in (74), which we denote as . As before splitting the level sets of the functions , , we obtain sets , and numbers such that
[TABLE]
The trick with , allows us to choose , not depending on the sets (but here, actually, we do not need in this additional information). Applying Corollary 40, we have
[TABLE]
Again two first terms in the last formula do not exceed two last terms in (68). Additionally, we consider the term later. As before, one has
[TABLE]
Using the last formula and recalling (74), we see that the optimal choice of the parameters is and hence , . The assumption guarantees that conditions (73) hold. Thus
[TABLE]
Finally, let us consider the situation when the term in (76) dominates. In this case and
[TABLE]
as required.
It was proved in [1, Theorem 6.1] that under some mild assumptions on , and the case of the initial interval one has
[TABLE]
Our bound (67) is better (let for simplicity) in the case when and , . Obviously, more precise estimate (68) is even better.
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