The algebraic dimension of compact complex threefolds with vanishing second Betti numbers
Frederic Campana, Jean-Pierre Demailly, Thomas Peternell

TL;DR
This paper investigates the algebraic dimension of compact complex threefolds that have a second Betti number equal to zero, providing insights into their geometric and topological properties.
Contribution
It introduces new results relating the algebraic dimension to the vanishing of the second Betti number in complex threefolds.
Findings
Characterization of algebraic dimension for these threefolds
Identification of conditions under which the algebraic dimension is maximized
Extension of previous results to broader classes of threefolds
Abstract
Small changes in sections 4 and 5, results not affected
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The algebraic dimension of compact complex threefolds with vanishing second Betti number
Frédéric Campana
,
Jean-Pierre Demailly
and
Thomas Peternell
Frédéric Campana, Institut Elie Cartan, Université Henri Poincaré, BP 239, F-54506. Vandoeuvre-les-Nancy Cédex, France
Jean-Pierre Demailly, Universitée de Grenoble-Alpes, Institut Fourier, UMR 5582 du C.N.R.S., 100 rue des Maths, 38610 Gières, France
Thomas Peternell, Mathematisches Institut, Universität Bayreuth, 95440 Bayreuth, Germany
1. Introduction
The paper [CDP98] studied compact complex threefolds such that the second Betti number The main result is based on Lemma 1.5, which happens to be incorrect in general (but might still hold in the context of the paper). In any case, some of the statements and proofs need to be adapted to fill the possible gaps; this is done in the present Corrigendum, with special regards to potential complex structures on the -sphere.
2. Statement of the results
We prove Theorem 2.1 in [CDP98] in full generality in case has a meromorphic non-holomorphic map In the remaining case, has algebraic dimension and the algebraic reduction is holomorphic. In this case we prove that ; for simplicity, we will assume not only that but slightly stronger that and moreover that , hence . This suffices to treat the main application of complex structures on .
In summary, we shall prove
2.1**.**
Theorem.* Let be a dimensional compact complex manifold with . Assume that there exists a non-holomorphic meromorphic non-constant map . Let be a holomorphic vector bundle on . Then*
- a)
* for and generic.* 2. b)
* for all * 3. c)
; i.e., either and , or and .
Another proof has been given in [LSS18].
Theorem 2.1 takes care of all threefolds with and except of those whose algebraic reduction is holomorphic onto a curve . In this case the general fiber has Kodaira dimension .
By topological considerations and surface classification, the general fiber of is either a torus, a primary Kodaira surface or a surface of type VII; in the latter case it is actually a primary Hopf surface or an Inoue surface, by Lemma 4.2 and Lemma 4.3. The case that the general fiber is a Kodaira surface is ruled out in Corollary 5.3. Then we show
2.2**.**
Theorem.* Let be a dimensional compact complex manifold with and algebraic dimension . Assume that the algebraic reduction is holomorphic. Then*
- a)
* for .* 2. b)
. 3. c)
.
As a consequence we deduce
2.3**.**
Corollary.* Let be a 3-dimensional compact complex manifold homeomorphic to . Then .*
Proof.
Obviously, , otherwise is Moishezon and therefore . If then there exists a meromorphic non-holomorphic map . Then we conclude by Theorem 2.1 that . By Hopf’s theorem, , a contradiction. If and the algebraic reduction is not holomorphic, then , and we conclude again by Theorem 2.1. If and the algebraic reduction is holomorphic, then we apply Theorem 2.2 and obtain the same contradiction as before. ∎
We now comment on the strategy to prove Theorem 2.2. The arguments of [CDP98] show the following
2.4**.**
Proposition.* Let be a 3-dimensional compact complex manifold with and algebraic dimension . Assume that the algebraic reduction is holomorphic. If*
[TABLE]
for some (or general) , then the assertions of Theorem 2.2 hold.
Equation (1) is equivalent to the vanishing
[TABLE]
for all complex-analytic fibers (with the natural fiber structure) of , equivalently,
[TABLE]
The key is to show that the restriction of some or the general line bundle to any fiber is never torsion. Then we compute directly on ; here the case when is singular, in particular non-normal, needs special care.
For further informations on the problem of complex structures on , we refer to [Et15] and to volume 57 of the journal Differential Geometry and its Applications.
3. Proof of Theorem 2.1
Instead of simply pointing out the additions in the proof of [CDP98, Theorem 2.1] to be made, we give full details for the benefit of the reader. Notice first that (2.1)(b) follows from (2.1)(a) since does not depend on , and (2.1)(c) is a consequence of (2.1)(b) by applying Riemann-Roch to and . So it remains to prove (2.1)(a). By Serre duality, (2.1)(a) needs only to be shown for and . The case follows from [CDP98, Cor1.3], since does carry effective non-zero divisors. Thus it remains to prove that
[TABLE]
for generic, equivalently one, line bundle . Let be a non-constant non-holomorphic meromorphic map and be a resolution of indeterminacies of . Let
[TABLE]
be the fiber space given by the Stein factorization of the holomorphic map Replacing by the induced meromorphic map , we may assume from the beginning that has connected fibers, hence no Stein factorization has to be taken. Note that the canonical map
[TABLE]
is injective (by the Leray spectral sequence). Hence Equation (2) follows from
[TABLE]
Fix an ample divisor on . Then can be written as
[TABLE]
with a line bundle on and a suitable effective divisor which is supported on the exceptional set of and projects onto . To verify Equation (3) it suffices to show that
[TABLE]
for some effective divisor supported on the exceptional locus of and some . In fact, consider the exact sequence
[TABLE]
and note that
[TABLE]
This last vanishing is seen as follows: let be the complex subspace of defined by the ideal sheaf . Then by
[TABLE]
for and the Leray spectral sequence,
[TABLE]
Now the last group vanishes since .
By replacing by for some positive integer and using (4), Equation (5) reads
[TABLE]
[TABLE]
By the Leray spectral sequence applied to , Equation (6) comes down to verify
[TABLE]
and
[TABLE]
for suitable positive integers and and some line bundle .
To prove (7), let be the finite set of points such that some component of the fiber does not meet . In particular, if is irreducible, then . Notice also that
[TABLE]
by the standard base change theorem. Applying Serre duality, we obtain
[TABLE]
[TABLE]
We claim first that there is a number such that for ,
[TABLE]
This is equivalent to saying that
[TABLE]
for . Fixing any point , this number clearly exists; in case is reducible, we apply [CDP98, Prop.1.1]. Hence the support of the direct image sheaf is contained in a finite set in . Since is effective, it follows that . Thus, enlarging if necessary, (9) is verified.
Hence we only need to consider the fibers with . Let the set of line bundles of the form
[TABLE]
with positive integers and fiber components of not meeting (the considered as surfaces in ).
Since all line bundles are trivial on , our previous considerations imply the existence of a number such that for all and all ,
[TABLE]
We are now going to construct a line bundle such that
[TABLE]
for a suitable number . Fix a point . Let be the sub-divisor of consisting of all components meeting ; let further be the sub-divisor consisting of all components which meet but not . Continuing in this way we obtain a decomposition
[TABLE]
of sub-divisors who pairwise do not have common components and which have the property that all components of meet but do not meet for . Now choose such that
[TABLE]
This is possible by our construction. Next choose such that
[TABLE]
Since , we obtain
[TABLE]
Continuing in this way, we obtain a line bundle
[TABLE]
(having in mind that the divisors do not meet the exceptional locus of ), such that
[TABLE]
Since the component meets , it needs a special treatment. We observe that
[TABLE]
with some effective -exceptional divisor . Hence, choosing and setting
[TABLE]
then
[TABLE]
Finally, enlarging , we get
[TABLE]
Setting
[TABLE]
this settles (7).
As to (8), we fix as in (7) and then apply Serre’s vanishing theorem to the ample divisor to obtain .
4. General structure of the fibers
From now on - for the rest of the paper - we let be a compact complex manifold of dimension with
[TABLE]
and holomorphic algebraic reduction to the curve . We will freely use the theory of compact complex surfaces, in particular of non-Kähler surfaces, and refer to [BHPV04] as general reference. Deviating from [BHPV04], we call bi-elliptic surfaces hyperelliptic.
An application of Riemann-Roch gives
4.1**.**
Lemma.* for all effective divisors on .*
Proof.
By Riemann-Roch,
[TABLE]
hence
[TABLE]
∎
4.2**.**
Lemma.* Let be the number of singular fibers and be the numbers of irreducible components of the singular fibers. Then*
[TABLE]
where is a smooth fiber. Moreover is torsion free for all smooth fibers .
Proof.
The first assertion is [CDP98, Lemma 3.2]. For the second, fix a smooth fiber and let the union of all singular fibers of and set . As seen in the proof of [CDP98, Lemma 3.2],
[TABLE]
hence it suffices to show that is torsion free. To do this, we consider the cohomology sequence for pairs,
[TABLE]
Notice first that is torsion free. Further, is torsion free by the universal coefficent theorem, since is torsion free: by Poincaré duality,
[TABLE]
Actually, . Consequently,
[TABLE]
is torsion free. ∎
4.3**.**
Lemma.* Let be a smooth fiber of . Then is either a primary Hopf surface, an Inoue surface, a torus, a hyperelliptic surface with torsion free first homology group or a primary Kodaira surface with torsion free first homology group.*
Proof.
Note first that is topologically trivial, since is topologically trivial, due to . Then we use the tangent sequence
[TABLE]
and observe that , since . Thus . Since the (sufficiently) general fiber of an algebraic reduction has non-positive Kodaira dimension, [Ue75, Thm. 12.1], so does every smooth fiber (see e.g. [BHPV04, VI.8.1]. Then we conclude by surface classification and using the torsion freeness of , Lemma 4.2. Note here that for a secondary Kodaira surface has torsion, since is torsion in (then apply the universal coefficient theorem) and that a secondary Hopf surface has torsion in by definition.
∎
4.4**.**
Corollary.*
All fibers of are irreducible unless the general fiber of is a torus, a hyperelliptic surface with torsion free first homology or a primary Kodaira surface with torsion free first homology.*
We fix some notations for the rest of the paper.
4.5**.**
Notation.* *Let be an irreducible reduced surface. In particular, is Gorenstein. We denote by the dualizing sheaf, which is a line bundle. Let
[TABLE]
be the normalization of ; denote by the non-normal locus, equipped with the complex structure given by the conductor ideal. Let be the complex-analytic preimage. Let
[TABLE]
be a minimal desingularization and
[TABLE]
be a minimal model. For the class of we write , analogously for , etc.
4.6**.**
Lemma.* In the notations of (4.5), we have*
[TABLE]
and
[TABLE]
with an effective divisor supported on the exceptional locus of and the strict transform of in . Moreover, there are exact sequences
[TABLE]
and
[TABLE]
Proof.
[Mo82, chap.3, sect.8]. ∎
As an immediate consequence, we note
4.7**.**
Proposition.* Let be any irreducible reduced compact Gorenstein surface with and Then*
- a)
; 2. b)
**
Proof.
The first equation in (a) follows from Lemma 4.6. As to the second equation in (a), observe by Serre duality
[TABLE]
since . For the same reasons
[TABLE]
∎
4.8**.**
Proposition.* Let be a smooth fiber of . Then*
[TABLE]
Proof.
Consider the exact sequence
[TABLE]
If , the assertion is clear. So it remains to treat the case that has no vector fields. Then by Lemma 4.3 and [In74], is an Inoue surface of type or , in which cases . Thus is rigid and is surjective, so that also in these cases.
∎
4.9**.**
Corollary.* Let be a fiber with an irreducible singular surface and . Then there exists a finite étale cover such that .*
Proof.
We consider the tangent sequence
[TABLE]
If , then . However, is not surjective, since is singular. Hence
[TABLE]
By semicontinuity and Proposition 4.8, and we conclude.
If , arguing in the same way, we obtain a torsion line bundle on such that
[TABLE]
Then we pass to a finite étale cover to trivialize .
∎
4.10**.**
Remark. A vector field induces canonically a vector field . For brevity, we say that comes from .
4.11**.**
Proposition.* Let with singular, irreducible. Then is non-normal.*
Proof.
Suppose normal and let be a minimal desingularization and a minimal model.
(a) Suppose that has only rational singularities, hence has only rational double points. Then , in particular is a minimal surface containing -curves. By surface classification, is either a K3 surface, an Enriques surface, of type VII or non-Kähler of Kodaira dimension . The first two cases are impossible since
[TABLE]
If is of type VII, then it must be a Hopf surface or an Inoue surface, since , but these surfaces do not contain -curves. If , then, since has a vector field, it does not any rational curve, see e.g. [GH90, Satz 1].
(b) Suppose now that has at least one irrational singularity. Then hence
[TABLE]
Suppose first that is not Kähler. By classification, has to be a primary Kodaira surface or . By Corollary 4.9, (up to finite étale cover). Choose a non-zero vector field coming from ; then does not have zeroes by classification, [GH90, Satz 1]; note that in case , is an elliptic bundle over a curve of genus at least . Hence we must have . But then does not contain contractible curves, so that is smooth, a contradiction.
Thus is Kähler. Since with a non-zero effective divisor, and is a ruled surface over a curve of genus . Since has an irrational singularity, must contract an irrational curve whose normalization necessarily has genus at least . Thus
[TABLE]
and therefore
[TABLE]
which is absurd. ∎
5. Kodaira surfaces, hyperelliptic surfaces and tori
In this section we consider the case that the general fiber of is a Kodaira surface, a hyperelliptic surface or a torus. We rule out the case of Kodaira and hyperelliptic fibers and show in the torus case that for general line bundles on , the restriction to any fiber is never torsion.
5.1**.**
Proposition.* Assume that the general fiber of is a Kodaira surface or a torus. Then is locally free for all , in fact, is independent on .*
Proof.
It suffices to show that is independent of . Indeed, since for all and since is constant, does not depend on as well, and the assertions follow by Grauert’s theorem. By Serre duality,
[TABLE]
Setting , a locally free sheaf of rank one, we obtain
[TABLE]
where are the non-reduced fiber components. In particular, for all reduced fibers and therefore
[TABLE]
for all those . So let be a non-reduced fiber and set . We consider the complex subspace
[TABLE]
of and have an induced exact sequence
[TABLE]
Applying and observing that
[TABLE]
shows that the restriction map
[TABLE]
vanishes. Since
[TABLE]
we conclude .
∎
5.2**.**
Corollary.* Assume that the general smooth fiber of is a Kodaira surface, a hyperelliptic surface or a torus. Then the restriction map*
[TABLE]
is surjective.
Proof.
Suppose first that is a Kodaira surface or a torus. Then the assertion is Theorem 3.1 in [CDP98]; the proof works since we now know that is locally free. If is hyperelliptic, then is one-dimensional, hence it suffices to show that . Let be the canonical isomorphism and write . Then . In fact, otherwise , noticing also that since . But , a contradition. ∎
As a consequence, we obtain
5.3**.**
Corollary.**
The general fiber of cannot be a Kodaira or hyperelliptic surface.
Proof.
This is Proposition 3.6 in [CDP98]. In the proof of Proposition 3.6, Theorem 3.1 is used which is now established by Corollary 5.2. Notice that in Step 2 of the proof of Proposition 3.6 in [CDP98], the local freeness of is used only generically. ∎
5.4**.**
Remark. The same arguments also rule out Hopf surfaces of algebraic dimension one.
From now - for the remainder of this section - we assume that the general fiber of is a torus.
5.5**.**
Proposition.* with .*
Proof.
By Proposition 5.1, the sheaf is locally free of rank two. Write
[TABLE]
We observe that is generically spanned by Corollary 5.2, since
[TABLE]
Hence .
∎
5.6**.**
Proposition.* For general , the restriction is non-torsion for all .*
Proof.
By Proposition 5.5, and the restriction
[TABLE]
is surjective for all . Consequently, the kernel of the restriction
[TABLE]
is discrete for all plus a linear subspace of codimension . Since , it follows that for general, the restriction is never trivial and thus also non-torsion. ∎
6. Hopf and Inoue surfaces
In this section we assume that the general fiber of is a Hopf or Inoue surface and show that for general line bundles on , the restriction is never torsion.
6.1**.**
Proposition.* Assume that the general fiber of is a Hopf or Inoue surface. Let be general. Then is non-torsion for all , and the restriction map is surjective for any smooth fiber .*
Proof.
The exact sequence
[TABLE]
and our assumptions give
[TABLE]
Moreover, is torsion. Consider the canonical morphism
[TABLE]
Then by the Leray spectral sequence, is injective and the cokernel is torsion. Hence
[TABLE]
Choose
[TABLE]
non-torsion. This section defines an inclusion
[TABLE]
Let be the smooth locus of in . We claim that
[TABLE]
Suppose first that Claim (10) holds. Then we conclude as follows. Certainly, is an isomorphism over . Thus we obtain a sequence
[TABLE]
where is supported on the finite set . Since and since , it follows , hence . Thus is an isomorphism everywhere and consequently never takes value one, nor does - by our choice of - any multiple . Hence defines a line bundle such that is non-torsion for all . It remains to prove Claim (10). As before, set , and . Then, as in the proof of Lemma 4.2,
[TABLE]
Since , it follows
[TABLE]
Since is locally constant of rank one, the claim follows.
∎
As a consequence we obtain
6.2**.**
Corollary.**
- a)
; 2. b)
; 3. c)
for general and all , we have
[TABLE]
Proof.
(a) Since has rank one, we may write
[TABLE]
By Proposition 6.1, . So it remains to show that is torsion free. If not, there exists a line bundle , such that is non-torsion for some but for . Write . Then
[TABLE]
with an effective divisor supported on . Since is irreducible, and therefore is a torsion line bundle, contradiction.
(b) By (a), . Since the general fiber of having negative Kodaira dimension, we have
[TABLE]
Thus we conclude from , that
[TABLE]
Hence, by the Leray spectral sequence, must be torsion free, therefore
[TABLE]
(c) As a consequence of (b), for general , hence
[TABLE]
for all . Thus
[TABLE]
for general and all as well. In summary, we may say that
[TABLE]
for general and all .
Now defines a section . Notice that for , the smooth locus of , the bundle is never trivial and thus does not take value on . Since , the section never takes value , hence our claim follows. ∎
We will further need the following basic statement on Hopf and Inoue surfaces.
6.3**.**
Proposition.**
Let be a primary Hopf surface. Assume that
[TABLE]
for some line bundle on . Then
[TABLE]
Proof.
Choose a vector field on and let be the zero locus of which is purely one-dimensional. We obtain an exact sequence
[TABLE]
Dualizing,
[TABLE]
Hence
[TABLE]
or
[TABLE]
In the latter case, the claim is clear. In the first case we observe that
[TABLE]
Indeed, there exists another vector field , and is a section of vanishing on .
∎
6.4**.**
Proposition.* Let be an Inoue surface. Then there is a unique line bundle such that*
[TABLE]
Moreover, one of the following statements holds.
- a)
either and 2. b)
or and .
Proof.
The existence of is classical, [In74].
If has a non-zero vector field , necessarily without zeroes, then induces an exact sequence
[TABLE]
and the claim is immediate, since has no curves and since . If , consider the exact sequence
[TABLE]
Since the sequence does not split,
[TABLE]
Hence either or , [In74, Lemma 1]. The second case however cannot happen, since
[TABLE]
[In74, Prop.2].
∎
7. Proof of Theorem 2.2
As already said in the introduction, it suffices to prove Proposition 2.4. Thus we need to show that
[TABLE]
for all . By Serre duality, this comes down to show that
[TABLE]
for some and for all .
We first consider irreducible fibers. Let
[TABLE]
Using the (co-)tangent sheaf sequence
[TABLE]
it is immediate that it suffices to show - provided is non-torsion - the following statement
[TABLE]
where
[TABLE]
We first treat smooth fibers .
7.1**.**
Proposition.* Equations (11) holds for smooth fibers (independent on the structure of the general fiber), i.e., for general*
[TABLE]
simultaneously for all smooth fibers .
Proof.
(a) First, if is a torus, then
[TABLE]
for all non-trivial , hence we may take any such that is never trivial, Proposition 5.6.
(b) If is a Hopf surface, then by Corollary 6.2, for general , hence we conclude by Propositions 6.1 and 6.3.
(c) If is an Inoue surface with a vector field, then for general, also is general, hence
[TABLE]
hence we conclude by Propositions 6.1 and 6.4.
(d) Finally, assume that is an Inoue surface without vector field. Then we argue as in (c), observing that is general for general . ∎
7.2**.**
Remark. Since the conormal bundle of a multiple fiber is torsion, the arguments also apply to fibers with and smooth.
7.3**.**
Proposition.* Equation (11) holds for singular reduced fibers.*
Proof.
Recall the notations 4.5. By Lemma 4.6 and Proposition 4.11, , the surface is non-normal and
[TABLE]
Arguing by contradiction, there exists a one-dimensional family of line bundles on such that
[TABLE]
Passing to a desingularization and then to a minimal model as in Notation 4.5, there are numerically trivial line bundles on such that
[TABLE]
with a one-dimensional family of sections in
[TABLE]
Thus
[TABLE]
Observe that all line bundles might be trivial. Step 1. Suppose first that is Kähler. Then by (12), must be ruled over a curve of genus at least two.
Claim. has rational singularities, only.
Proof of the Claim. Assume to the contrary that has an irrational singularity. We claim that . In fact, must contract a curve projecting onto . Thus and therefore . Since , the Leray spectral sequence yields (and ).
Thus all line bundles are trivial and we obtain a one-dimensional family of holomorphic one-forms on . Moreover there exists a one-dimensional family of one-forms on such that
[TABLE]
where is the ruling. Since , we have . On the other hand, since contracts , it follows that , a contradiction. This proves the Claim and thus has rational singularities, only.
In this case the morphism induced a morphism . In the language of divisors and using the notations of (4.5) and (4.6) we have
[TABLE]
where is the strict transform of in . Set
[TABLE]
We are now using the theory of ruled surfaces as in [Ha77, section V.2], taking over also the notations from [Ha77]. In particular we have the invariant and a section with minimal self-intersection . Moreover,
[TABLE]
where is a fiber of and the genus of . Since has rational singularities, cannot contract any curve projecting onto . Hence we must have
[TABLE]
with . Taking into account the numerical description of irreducible curves in , as given in [Ha77, section V.2], it follows immediately that and that
[TABLE]
with an effective divisor (note that the curve is the unique contractible curve in ). Consequently, has a unique component, say , projecting onto , and this component has multiplicity two. The map induces a holomorphic map and a commutative diagram
[TABLE]
The general fiber of is a reduced Gorenstein curve with
[TABLE]
whose normalization of is a disjoint union of smooth rational curves. Thus, if is irreducible, then is a rational curve with one node or cusp, and if is reducible, it is a cycle of smooth rational curves. In case has a node or is a cycle, the normalization map is generically along . In these cases however, would be reduced, see [KW88], a contradiction. In the remaining case, has degree one along , hence has degree one, too. Unless is an isomorphism and , we have , hence . Since , we conclude
[TABLE]
Since is Moishezon and , this is impossible. Alternatively, apply Proposition 5.5 or Corollary 6.2, respectively.
Hence is biholomorphic, i.e., maps to the smooth curve of genus two and . Moreover, , and therefore . The map being flat, is locally free of rank one, and by relative duality,
[TABLE]
hence
[TABLE]
But then , a contradiction. This shows that is impossible and concludes the proof in the Kähler case.
Step 2. We thus are reduced to the case that is not Kähler.
If is of type VII, then hence for general, contradicting (12).
The same argument applies to a secondary Kodaira surface . If is a primary Kodaira surface, then the cotangent sequence reads
[TABLE]
which immediately gives a contradiction by tensorizing with .
It remains to exclude the case . Since , (4.9) and (4.10), the Iitaka fibration is an elliptic bundle over a curve of genus , [GH90, Satz 1] and, as already noticed, the induced vector field has no zeroes. Hence . Since , we have
[TABLE]
hence , contradicting Proposition 5.5 or Corollary 6.2, respectively.
∎
7.4**.**
Remark. If the fiber with an irreducible reduced singular surface and , we argue in the same way, passing to a finite étale cover.
Finally, we have to treat reducible fibers:
7.5**.**
Proposition.* Equation (11) holds for reducible fibers.*
Proof.
Let
[TABLE]
be a reducible fiber. Arguing by contradiction, there is a one-dimensional family of line bundles on such that
[TABLE]
Hence there exists a number such that
[TABLE]
for all , and therefore
[TABLE]
Now we argue as in Proposition 7.3 to obtain a contradiction. One might also use the line bundle for , where the surface meets in in a curve.
∎
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