On the completeness of the root functions of the Sturm-Liouville problems for the Lam\'e system in weighted spaces
A. Peicheva. A. Shlapunov

TL;DR
This paper investigates the completeness of root functions for Sturm-Liouville problems associated with the Lamé system in weighted spaces, establishing conditions for Fredholm properties and root function completeness.
Contribution
It provides new criteria for the completeness of root functions of Sturm-Liouville problems for the Lamé system in weighted Sobolev spaces, including both coercive and non-coercive cases.
Findings
Problems are shown to be Fredholm in weighted Sobolev spaces.
Conditions for the completeness of root functions are explicitly described.
Results apply to boundary value problems with Robin boundary conditions.
Abstract
We consider three Sturm--Liouville boundary value problems (the coercive ones and the non-coercive one) in a bounded Lipschitz domain for the perturbed Lam\'e operator with the boundary conditions of Robin type. We prove that the problems are Fredholm ones in proper weighted Sobolev type spaces. The conditions, providing the completeness of the root functions related to the boundary value problem, are described.
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Taxonomy
TopicsDifferential Equations and Boundary Problems · Spectral Theory in Mathematical Physics · Numerical methods in inverse problems
On the completeness of the root functions of the Sturm-Liouville problems for the Lamé
system in weighted spaces111This is a preprint version of the paper published in Z. Angew. Math. Mech., V. 95, N. 11 (2015), 1202–1214. DOI 10.1002/zamm.201300303.
A. Shlapunov
Siberian Federal University
Institute of Mathematics
pr. Svobodnyi 79
660041 Krasnoyarsk
Russia
and
A. Peicheva
Siberian Federal University
Institute of Mathematics
pr. Svobodnyi 79
660041 Krasnoyarsk
Russia
Abstract.
We consider three Sturm–Liouville boundary value problems (the coercive ones and the non-coercive one) in a bounded Lipschitz domain for the perturbed Lamé operator with the boundary conditions of Robin type. We prove that the problems are Fredholm ones in proper weighted Sobolev type spaces. The conditions, providing the completeness of the root functions related to the boundary value problem, are described.
Key words and phrases:
Sturm-Liouville problem, non-coercive problems, the Lamé system, root functions
2010 Mathematics Subject Classification:
35J48, 47A75
Contents
- 1 Introduction
- 2 Function spaces
- 3 The Sturm Liouville-problem for the Lamé type system
- 4 The spectral properties of the mixed problems
1. Introduction
Investigating a boundary value problem, it is important to know both solvability conditions and formulas for its exact and approximate solutions. For the linear problems, the latter ones can be obtain with the use of expansions over the (generalized) eigenfunctions related to the them (see, for instance, [13]). Then, to use numerical methods in the non-selfadjoint case, one needs to prove the completeness of the system of the corresponding root elements. The results of this kind are well known for the coercive (elliptic) boundary problems over smooth domains (see [1], [7], [14]). For the Spectral Theory related to the elliptic problems in Lipschitz domains we refer to the survey [4]. The root elements of general elliptic problems in weighted Sobolev spaces over domains with the conic and edge singularities were studied in [10], [16], [27].
Non-coercive boundary value problems for elliptic differential operators were discovered in the middle of XX-th century (see, [2], [15]). In the Elasticity Theory, the problems of this kind were indicated in [8], [9]. Considering the non-coercive problems, we essentially enlarge the class of boundary conditions for which the completeness of the root elements holds true. This may lead to a loss of the regularity of solutions to the problem near the boundary, but this is motivated by the very nature of the problems (cf. [23], [24]).
The aim of this paper is the proof of the completeness in weighted Sobolev type spaces of the root elements of three Sturm-Liouville problems for the perturbed Lamé operator with the boundary conditions of Robin type. The use of the weighted spaces allows us to choose the solutions with prescribed asymptotic behavior near the singular points of the boundary.
2. Function spaces
Let be a bounded domain in the Euclidean space , , with a Lipschitz boundary. We consider complex-valued functions defined over the domain and its closure . For and , denote by the set of times continuously differentiable functions over vanishing in a neighborhood of . Let be the space of smooth functions with compact supports in . The Hölder class with the exponent over the set we denote by . We write for the standard Lebesgue space (). We also write , , for the Sobolev space of functions with all the weak derivatives up to order belonging to . Let stand for the closure of in . For positive non-integer we denote by the Sobolev-Slobodetskii space, see, for instance, [20].
Considering the spaces with negative smoothness we use the following standard construction. Let and be complex Hilbert spaces with inner products and respectively. Assume that is embedded continuously into and denote by the corresponding embedding. Moreover, we assume that is dense in . Then let stand for the completion of with respect to the norm .
The following lemma is well known (see, for instance, [22, §3]).
Lemma 2.1**.**
The Banach space is topologically isomorphic to the dual space . Besides, the isomorphism is defined by the Hermitian form , , , where is a sequence in converging to in . Moreover, if the embedding is compact then the space is compactly embedded to .
Thus, , , corresponds to if , . If , the space will be denoted by .
The weighted spaces appears naturally during the investigation of mixed boundary problems because the weight can be used to control the behavior of the solutions near the set where the boundary conditions change the character. Choose a closed set on . In order to control the growth of functions near we introduce the weighted spaces associated to . Assume that is a -smooth function over such that , , , and if and only if . In particular, will correspond to the usual Sobolev spaces. If , then in typical situations, for domains with piece-wise smooth boundaries, the function is the distance form the point to the singular set .
Now, for , and we introduce the weighted Sobolev spaces as the completion of with respect to the norms, induced by the following scalar products:
[TABLE]
(cf. [6, §1.7] for the localized situation where the weight is given in local coordinates near the singularity). Moreover, for we introduce the weighted Sobolev-Slobodetskii spaces as the completion of with respect to the norms, induced by the following scalar product:
[TABLE]
Similar fractional weighted spaces were considered in [17] for the localized situation.
As before, the weighted negative Sobolev-Slobodetskii space , , will be defined as the space for , .
Lemma 2.2**.**
For each fixed the space is compactly embedded into , if . Moreover, if the trace operator is correctly defined and bounded.
Proof.
The proof is standard. It is based on the Rellich-Kondrashov Theorem and the Trace Theorem for the usual Sobolev spaces (see [6, §1.7]). ∎
Everywhere below, for a set we denote by the completion of in . In particular, .
Besides, for a function space over denote by the space of -vector functions with the components . If is a normed space then we endow the space with the norm \|u\|_{[{\mathfrak{B}}(D)]^{k}}=\Big{(}\sum_{j=1}^{k}\|u_{j}\|^{2}_{{\mathfrak{B}}(D)}\Big{)}^{1/2}. Thus, is a Hilbert space if the space is a Hilbert one.
3. The Sturm Liouville-problem for the Lamé type system
Fix an open connected set with piece-wise smooth boundary on the hypersurface , a set and a weight associated with them. Denote by the Lamé type operator in :
[TABLE]
where is the identity -matrix, is the Laplace operator in , is the gradient operator in , is the divergence operator in , and , are real-valued functions from such that , for a constant . If and , this operator plays an essential role in the description of the displacement of an elastic body under the load (see [12]). It also can be used as a linearization of the stationary version of the Navier-Stokes’ type equations for viscous compressible fluid if the pressure is known (see [19, §15]).
Clearly, the Lamé type operator is strongly elliptic and, if the functions , belong to then there is a formally non-negative self-adjoint operator that differs from by the low order summands; here is a differential -matrix first order operator and is its formal adjoint one. Of course, there are many such operators . To introduce three of them we denote by the Kronecker product of matrices and , by we denote \Big{(}\frac{(m^{2}-m)}{2}\times m\Big{)}-matrix operator with the lines , , representing the vorticity (or the standard rotation operator for , ), and by we denote \Big{(}\frac{(m^{2}+m)}{2}\times m\Big{)}-matrix operator with the lines , , and with , representing the deformation (the strain). The we set:
[TABLE]
here , for the first operator, , for the second operator, and , for the third operator.
Thus, everywhere below we assume that , .
Consider a -matrix linear differential operator in the domain associated with the operator , where is one of the operators , :
[TABLE]
here and are functional - and - matrices respectively with the components satisfying the following assumptions: , .
Let be the conormal derivative with respect to the operator , where is the field of the exterior unit normal vectors with respect to (defined for almost all points ). Clearly, two operators of the type above, differ on a matrix with entries being tangential derivatives with respect to the boundary.
Consider now the boundary operator
[TABLE]
where is a -matrix of tangential derivatives with respect to . As for the -matrices and , we will assume that their components are locally bounded functions on . We allow for the matrix to degenerate on ; in this case we assume that is not degenerate on and the components of the tangential part equal to zero on .
Remark 3.1*.*
Usually, the first order boundary conditions related to boundary problems for the Lamé operator are defined with the use of the stress boundary tensor with the components
[TABLE]
Then, with the tangential part , we have
[TABLE]
We will study the following mixed problem: given generalized -vector function in , find a -vector distribution in satisfying in a proper sense (cf. [12, §12] for )
[TABLE]
If then we obtain the classical Dirichlet problem for the strongly elliptic operator . As it is well known, it is coercive due to the Gårding inequality (see, for instance, [12], [18], [20]). That is why we will be concentrated on the case where .
The boundary problem (3.6) related to was discovered by S. Campanato (see [8], [9]). However he proved an Existence Theorem for it in the coercive case only.
In the classical Theory of Boundary Value Problems, a typical assumptions are the fulfillment of the Shapiro-Lopatinsky conditions for the pair on the smooth part of (see, for instance, [11], [18], [20], and others), that is a necessary for the problem to be coercive. We will show below that for and or the mixed problem (3.6) is coercive in the Sobolev spaces, but for and it is not (cf. [8] for ).
As we plan to use the perturbation method for compact self-adjoint operators, we split the coefficients and :
[TABLE]
where is a Hermitian non-negative functional -matrix over with the components satisfying , and where -matrix is chosen in such a way that is Hermitian non-negative functional matrix over .
Consider the following Hermitian forms on the space :
[TABLE]
The form is strongly coercive, i.e.
[TABLE]
with a constant being independent on . The forms corresponding to operators and are not strongly coercive because with non-constant vector , and in for any harmonic function in .
Denote by , , the completion of with respect to the norm induced by the inner product (of course, if it is an inner product).
Lemma 3.2**.**
The Hermitian form defines an inner product on if one of the following conditions holds true:
1) the open set is not empty (in the topology of );
2) with a constant on a non-empty open set ;
3) with a constant on a non-empty open set .
Besides, in these cases we have:
a) the space is continuously embedded in if the components of the matrix belong to ;
b) the elements of belong to .
Proof.
Regarding the statement on the scalar product, we only need to check that for implies in .
But the first order operators
[TABLE]
[TABLE]
have constant coefficients and injective principal symbols. Then Petrovskii Theorem implies that the distributions-solutions to in , , are real analytic there. Hence the statement on the scalar product under condition 2) follows from the Uniqueness Theorem for real analytic functions.
Then it follows from conditions 1) or 3) that any vector satisfying vanishes on an open non-empty subset of . As also satisfies in , the Uniqueness Theorem for the Cauchy problem for systems with injective symbols implies that in (see, for instance, [25, Theorem 2.8]).
As the solutions of the system in real analytic there, then there are no such solutions of the class . Then it follows from the Gårding inequality for the Hermitian form induced by the strongly elliptic operator that
[TABLE]
the constant being independent on . In particular, this implies that the statement b) holds true
Finally, the statement a) can be checked directly. ∎
Lemma 3.3**.**
Let , . If then the embedding , is bounded under one of the conditions 1), 2), 3) of Lemma 3.2. If there is such that
[TABLE]
then the space is continuously embedded into , .
Proof.
The continuity of the embedding follows from the second Korn inequality (see [12, formula (12.11)]). The continuity of the embedding follows from the strong coercive estimate (3.7). ∎
For the operator Lemma 3.3 is not true.
Example 3.4**.**
Take the cylinder
[TABLE]
with the base in as the domain. Let, for instance, , , , and . Then . Set , with being the imaginary unit and being the real part of a complex number . The function is harmonic in as the real part of the holomorphic monomial . It is easy to check that the system is orthogonal in and (the last one follows from the Fubini Theorem). Then Bessel’s Inequality implies that the sequence converges weakly to zero in . It follows from the Sobolev Embedding Theorem that the sequence converges to zero and while . Finally, as we see that if . This means that the continuous embedding is impossible.
Example 3.5**.**
In order to illustrate the case we set . In this situation one can easily modify the famous Hadamard’s example related to the ill-posed Cauchy for the Laplace operator. Namely, take the upper half-circle as the domain , and take the interval as the set . For instance, let , on , . Note that the matrix \left(\begin{array}[]{ll}\ \mbox{rot}_{2}\\ \ \rm{div}_{2}\end{array}\right) is adjoint to the Cauchy-Riemann system. On we consider the sequence with the components
[TABLE]
Obviously, each is a Lipschitz function on and the sequence converges to zero in . If stands for the Poisson integral for the Dirichlet Problem for the Laplace operator in then the sequence converges to zero in . Now it is clear that the functions
[TABLE]
belong to and they equal to zero on (here denotes the imaginary part of a complex number ). Moreover, by the construction, the sequence converges to zero in . That is why converges to zero in but it can not be convergent even in .
However, one can indicate conditions providing useful embedding theorems for the spaces generated by non-coercive forms (see [2]). The following statement describes reasonable assumptions for to be embedded into Sobolev-Slobodetskii spaces. The scheme of its proof is similar to the cases of scalar operators (see [23], [24]).
Theorem 3.6**.**
Let , belong to the class with a neighborhood of the compact , and let . Then
1) the space is continuously embedded into , if condition (3.9) holds true.
2) the space is continuously embedded into with any if
[TABLE]
Moreover, if , then (3.10) implies that the space is continuously embedded into .
Proof.
The statement 1) is obviously true.
Let estimate (3.10) is fulfilled. Then the norm is not weaker than the norm on , where
[TABLE]
Fix a number . Let us show that the norm is not weaker than the norm on . Indeed, integrating by parts it is easy to see that a vector function satisfy in if and only if in . As we have seen in the proof of Lemma 3.2, any weak solution to this equation is real analytic in and hence we have . Thus, under hypothesis of the theorem the operator has a two-sided fundamental solution on , say, . For instance, if and are constants, we may take the famous Kelvin-Somigliana kernel.
The volume potential
[TABLE]
induces the bounded linear operator for any bounded domain containing .
It is clear that any element extends up to an element via
[TABLE]
here is the pairing on for a space of distributions over . It is natural to denote it by . The defined in this way linear operator , is obviously bounded. Since the distribution is supported in , the volume potential (3.12) induces the bounded linear operator
[TABLE]
for any bounded domain containing (see, [3]).
Hence, the operators
[TABLE]
[TABLE]
are bounded, too, if because of the Trace Theorem for the Sobolev spaces. Note that for this statement is not true because the elements of the space may have no traces on .
Now integrating by parts we obtain for and :
[TABLE]
Take a sequence , converging to in the space , . As the space is reflexive for each , using (3.13) and the continuity of the operators , above, we obtain for :
[TABLE]
with a constant being independent on . Thus, there are constant , such that
[TABLE]
This proves the continuous embedding with any .
Due to the factorization, the operator is strongly elliptic formally-selfadjoint and the Dirichlet problem for it is Fredholm of index zero (see, for instance, [5], [26, Lemma 3.2]). As we noted above, in for if and only if . Therefore the Dirichlet problem for it is uniquely solvable. Let now and stand for the Green function and the Poisson integral of the Dirichlet Problem for the Dirichlet problem for the operator in . Then they induce the bounded operators (see, for instance, [5], [26, Theorem 3.3])
[TABLE]
As the operator extends to the continuous linear operator via
[TABLE]
then for each . Hence, for we have:
[TABLE]
On the other hand, integrating by parts, we obtain
[TABLE]
That is why, for all ,
[TABLE]
It follows from(3.8) and (3.14) that any sequence , converging to in the space can be presented as
[TABLE]
where the sequence converges in [ to an element .
Now the already proved part of the theorem yields that converges to an element in . This proves the continuous embedding .
To finish the proof of the theorem one has to almost literally repeat the corresponding arguments in the proof of [23, Theorem 1], related to the mixed problem for the Laplace operator. ∎
Corollary 3.7**.**
Let , and estimates (3.9), (3.10) hold true. Then is continuously embedded into for any .
The embeddings, described in Theorem 3.6 and Corollary 3.7, are rather sharp on the scale of the Sobolev-Slobodetskii spaces (see Example 4.5 below).
Remark 3.8*.*
Lemma 3.3, Theorem 3.6 and Corollary 3.7 imply that in the spaces and we can use arbitrary first order perturbations in (3.3) with while for the operators only the summands of the type , where is a -matrix with entries satisfying , can be used.
Now we proceed with the generalized formulation of the Sturm-Liouville Problem. With this aim, we assume that is continuously embedded into (the corresponding conditions were described above) and we denote by the completeness of the space with respect to the corresponding negative norm . The pairing, described in Lemma 2.1, will be denoted by .
Further, on integrating by parts we see that
[TABLE]
[TABLE]
for all and , satisfying the boundary condition of (3.6); here stands for the functional matrix . Suppose that (cf. Remark 3.8)
[TABLE]
for all , with a positive constant being independent of and .
Under condition (3.15), for each fixed the sesquilinear form
[TABLE]
[TABLE]
determines a continuous linear functional on via the equality for . By Lemma 2.1, there is a unique element in such that
[TABLE]
for all . We have thus defined a linear operator . It follows from (3.15) that the operator is bounded. The bounded linear operator defined in this way via the sesquilinear form , i.e.,
[TABLE]
for all , corresponds to the case , and .
Thus, the generalized setting of the problem (3.6) in the weighted spaces is the following: given find such that
[TABLE]
The problem (3.17) can be investigated by the standard methods of functional analysis [18, Ch. 3, §§ 4–6]) that are similar to the coercive case.
Lemma 3.9**.**
Suppose that is continuously embedded into , , and . Then for each there is a unique solution to problem (3.17), i.e., the operator is continuously invertible. Moreover, the norms of the operators and equal to .
The following three lemmas describe bounded and compact perturbations of the operator .
Lemma 3.10**.**
Let be continuously embedded into , . If , then the corresponding summands in problem (3.17) induce bounded operators, acting from to . Moreover, if there is such that , then the corresponding summands in problem 3.17) induce compact operators, acting from from to .
Proof.
It follows from Lemma 2.2. ∎
In the coercive case (corresponding to the operators , ) we can enlarge the class of the perturbations. With this purpose we fix a basis among the tangential vectors (with bounded integrable components). For instance, this may be formed by the vectors
[TABLE]
Then with -matrices .
Lemma 3.11**.**
Let or . Let (3.9) hold or . If then the corresponding summand in problem (3.17) induces a bounded operator, acting from to . if there is such that then the corresponding summand in problem (3.17) induces a compact operator, acting from . Moreover, if , , then the matrix of tangential derivatives induces a bounded operator, acting from to with the norm estimated via , .
Proof.
The continuity and the compactness of the operators induced by the summand follows from Lemma 3.3, the Embedding Theorem for Sobolev spaces and the continuity of the trace operator (see Lemma 2.2).
In order to finish the proof of the continuity of the tangential operator one has to almost literally repeat the corresponding arguments in the proof of [24, Lemma 6.6], related to the similar mixed problem for the scalar differential operators. ∎
Lemma 3.12**.**
Let inequality (3.10) be fulfilled and . If (3.9) is true or then the corresponding summand in problem (3.17) induces a bounded operator, acting from to .
As examples [23, Examples 1,2] show, the boundary terms and do not induce compact and bounded perturbations respectively for if and .
Now we split
[TABLE]
in such a way that the terms , and induce the compact perturbations of the operator and the summands , and induce the small ones. This gives the possibility to use the perturbation methods.
The proof of the following two statements is standard (see, for example, [20], [21], [24]).
Theorem 3.13**.**
Let or . Let , . Besides, let (3.9) hold or . If there exists such that , , , and
[TABLE]
for all with a constant being independent on and then problem (3.17) is a Fredholm one.
For we split in a different way: (cf. Remark 3.8).
Theorem 3.14**.**
Let , estimate (3.10) hold, are infinitely smooth in a neighborhood of , and . Besides, let (3.9) hold or . If there exists such that , , and
[TABLE]
for all with a constant , being independent on and then problem (3.17) is a Fredholm one.
4. The spectral properties of the mixed problems
In this section we use Theorems 3.13, 3.14 and the standard tools of Functional Analysis for the description of the completeness of the root elements of the mixed problem (3.17) in the spaces , and . We study both the coercive and the non-coercive cases.
With this aim we consider the sesquilinear form
[TABLE]
on the space . It is well known that for all . From now on we endow the space with the scalar product .
We recall that a compact self-adjoint operator is said to be of finite order if there is , such that the series converges where is the system of eigenvalues of the operator (here the summation is done counting the multiplicities of the eigenvalues, see, for instance, [13] and elsewhere).
Theorem 4.1**.**
If is continuously embedded into then the inverse of the operator given by (3.16) induces positive self-adjoint operators
[TABLE]
[TABLE]
which have the same systems of eigenvalues and eigenvectors; besides, the eigenvalues are positive. Moreover, if is continuously embedded into with then they are compact operators of finite orders and there are orthonormal basis in the spaces , and .
Proof.
The first part of the theorem is well-known (see, for instance, [20], [21], [24]). Besides,
[TABLE]
[TABLE]
Moreover, Lemma 2.2 implies that under the hypothesis of the lemma, the operator is compact. Therefore the statement on the basis follows from the Hilbert-Schmidt theorems and the identities (4.1). That is why it is left to prove the statement on operator’s orders only.
For the usual Sobolev spaces the statement follows from results of [1] (see also [24, Theorem 3.2]), because in this situation the operator maps, in fact, to , .
Since the embedding is obviously bounded, then for the weighted Sobolev spaces the correspondence induces a continuous map , and the correspondence induces a continuous map . Hence, if the embedding is continuous then the results of [1] imply that the order of the operator equals to and it has the same eigenvalues as the operator (here is the natural embedding. ∎
It is not difficult to show that the operator induces a closed densely defined linear operator with the domain . The the operator corresponds to a symmetric closed operator having the same eigenvectors as the operator . As it is known, non-selfadjoint operators in infinite-dimensional spaces may have not enough eigenvectors to form a basis. Hence the notion of the root vectors is very important.
Recall that a non-zero vector from the domain of a linear operator on a linear space is called a root vector (or, the generalized eigenvector) for , if there are numbers and satisfying , where is the identity operator in .
The conditions providing the completeness of the root vectors are well known in the frames of the functional analysis (see [4], [5], [13], [14] and others).
Corollary 4.2**.**
Under the hypotheses of Theorem 3.13, if then the system of the root vectors of the closed operator is complete in the spaces , and , . Moreover, for any all the eigenvalues of (except a finite number of them) belong to the angle in .
Proof.
Follows from Theorems 3.13, 4.1 and the Spectral Theory of non-selfadjoint operators (see, for instance, [4], [5], [7], [24, Theorem 6.8]). ∎
Corollary 4.3**.**
Under the hypotheses of Theorem 3.14, if , , and . Moreover, for any all the eigenvalues of (except a finite number of them) belong to the angle in .
Proof.
Follows from Theorems 3.14, 4.1 and the Spectral Theory of non-selfadjoint operators (see, for instance, [24, Theorem 4.5]). ∎
Example 4.4**.**
Let . The mixed problem (3.17) for and is classical in the Elasticity Theory (see [12, §12]); here is the characteristic function of the set . As the corresponding sesquilinear form is coercive for , , (see Lemma 3.3), we may also consider the boundary operators with a matrix having small entries of the class , and with the perturbation described in Theorem 3.13. The low order acceptable perturbations are also indicated in Theorem 3.13. The completeness conditions are described in Corollary 4.2.
Example 4.5**.**
Let be the unit circle in , ans be that part of its boundary where . For , consider mixed problem (3.17) with and , see (3.1), (3.4). Let , be constants and be a matrix with constant entries. Let equal to zero identically in a neighborhood of and equal to one on the part where . It is clear that the function , where
[TABLE]
belongs to but for any there is such that (cf. [23, Examples 1,2]). Thus, is continuously embedded into (see Theorem 3.6), but it is not embedded into for any (cf. [23, Examples 1, 2]). Moreover, as , then this example can be easily adopted to the weighted spaces.
Clearly, is responsible not for the stress/viscosity on the boundary but for a more large class of interactions with . For instance, interpreting the Lamé system as a linearization of the stationary version of the Navier-Stokes’ type equations for the compressible fluids, we see that the boundary operator reflects rather the vorticity and the source density on conormal directions to . This means that the boundary operator is more fit to study problems, related to models with the turbulent flows, than the operators and . Then it is natural that the class of the possible solutions to (3.17) extends up to due to the loss of the regularity of solutions near .
Example 4.6**.**
Let . Consider mixed problem (3.17) for and with a small parameter , see (3.1), (3.4), in the case where , . In particular, if we choose the vectors (3.18) as a basis among the tangential vectors to then , .
Assume that . Then , , for all . According to Lemma 3.3, the norms of the spaces and are equivalent. Lemma 3.10 implies that the first order terms induce the compact operators, acting from to . If the value is sufficiently small then problem (3.17) is a Fredholm one and its root vectors are dense in , , . If the value , is sufficiently small then problem (3.17) is uniquely solvable. The other acceptable perturbations are described in Theorem 3.13.
If the coefficients are constants then Gauß-Ostrogradskii formula implies
[TABLE]
i.e. . But it follows from (3.5) that . Thus, if then, for matrices with rather small entries, the mixed problem with the boundary operator can be interpreted as a small perturbation of the mixed problem with the boundary operator . However this contradicts with Example 4.6, because the space is not embedded into . Hence for constant Lamé coefficients the perturbation method is valid with . In particular, formula (3.5) means that the mixed problem with the boundary operator can not be investigated as the perturbation of the mixed problem with the boundary operator in the space .
In conclusion, we give examples of proper weight-functions.
Example 4.7**.**
Consider the cylinder with the base and the set , where is domain with smooth boundary in . Let be the defining function for the domain , i.e. it is a real-valued function with on such that . Then .
Example 4.8**.**
Consider the cube with a distinguished side and the set . In this situation we may set
[TABLE]
*The work was supported by RFBR grants 14-01-00544 and 14-01-00081. *
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