Geometric description of C-vectors and real L\"osungen
Kyu-Hwan Lee, Kyungyong Lee, Matthew R. Mills

TL;DR
This paper introduces real Loesungen as a geometric analogue of real roots, connecting mutation sequences, reflection families, and curves on Riemann surfaces to provide a new combinatorial description of c-vectors.
Contribution
It defines real Loesungen and the L-matrix, linking them to C-matrices and proposing a geometric interpretation of c-vectors in cluster algebras.
Findings
L-matrix arises from vectors associated with mutation sequences
Conjecture that L-matrix depends only on the seed (up to signs)
Curves can be drawn without self-intersections, offering a geometric view
Abstract
We introduce real Loesungen as an analogue of real roots. For each mutation sequence of an arbitrary skew-symmetrizable matrix, we define a family of reflections along with associated vectors which are real Loesungen and a set of curves on a Riemann surface. The matrix consisting of these vectors is called L-matrix. We explain how the L-matrix naturally arises in connection with the C-matrix. Then we conjecture that the L-matrix depends (up to signs of row vectors) only on the seed, and that the curves can be drawn without self-intersections, providing a new combinatorial/geometric description of c-vectors.
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Taxonomy
TopicsAdvanced Topics in Algebra · Homotopy and Cohomology in Algebraic Topology · Topological and Geometric Data Analysis
Geometric description of -vectors and real Lösungen
Kyu-Hwan Lee*⋆*
Department of Mathematics, University of Connecticut, Storrs, CT 06269, U.S.A.
,
Kyungyong Lee*†*
Department of Mathematics, University of Alabama, Tuscaloosa, AL 35487, U.S.A. and Korea Institute for Advanced Study, Seoul 02455, Republic of Korea
[email protected]; [email protected]
and
Matthew R. Mills*⋄*
Department of Mathematics, Michigan State University, East Lansing, MI 48824, U.S.A.
Abstract.
We introduce real Lösungen as an analogue of real roots. For each mutation sequence of an arbitrary skew-symmetrizable matrix, we define a family of reflections along with associated vectors which are real Lösungen and a set of curves on a Riemann surface. The matrix consisting of these vectors is called -matrix. We explain how the -matrix naturally arises in connection with the -matrix. Then we conjecture that the -matrix depends (up to signs of row vectors) only on the seed, and that the curves can be drawn without self-intersections, providing a new combinatorial/geometric description of -vectors.
*⋆*This work was partially supported by a grant from the Simons Foundation (#712100).
*†*This work was partially supported by NSF grant DMS 1800207, the University of Alabama, and Korea Institute for Advanced Study.
*⋄*This material is based upon work supported by the National Science Foundation under Award No. 1803521 and Michigan State University.
1. Introduction
Let be a quiver with vertices and no oriented cycles of length . The most basic invariant of a representation of is its dimension vector. By Kac’s Theorem [19], the dimension vectors of indecomposable representations of are positive roots of the Kac–Moody algebra associated to the quiver .
When is acyclic, a representation of is called rigid if , and the dimension vectors of indecomposable rigid representations are called real Schur roots as they are indeed real roots of . In the category of representations of , rigid objects are foundational. Therefore an explicit description of real Schur roots is essential for the study of the category, and there have been various results related to description of real Schur roots of an acyclic quiver ([6, 16, 17, 27, 29, 34]).
In a previous paper [20], we conjectured a correspondence between real Schur roots of an acyclic quiver and non-self-crossing curves on a marked Riemann surface and hence proposed a new combinatorial/geometric description. Recently, Felikson and Tumarkin [12] proved our conjecture for all -complete acyclic quivers. (An acyclic quiver is called -complete if it has multiple edges between any pair of vertices.)
Now, when is general, it is natural to consider the -vectors of as dimension vectors of rigid objects. Indeed, when is acyclic, the set of positive -vectors is identical with the set of real Schur roots [22]. For an arbitrary quiver , a positive -vector is the dimension vector of a rigid indecomposable representation of a quotient of the completed path algebra. This quotient was introduced by Derksen, Weyman and Zelevinksy [9], and is called a Jacobian algebra. Thus -vectors naturally generalize real Schur roots in this sense, though they are not necessarily real roots of the corresponding Kac–Moody algebra.
Originally, -vectors (and -matrices) were defined in the theory of cluster algebras [13], and together with their companions, -vectors (and -matrices), played fundamental roles in the study of cluster algebras (for instance, see [9, 14, 15, 21, 24]). As a cluster algebra is defined not only for a skew-symmetric matrix (i.e. a quiver) but also for an arbitrary skew-symmetrizable matrix, one can ask:
Can we have a combinatorial/geometric description of the -vectors (and -matrices) of a cluster algebra associated with an arbitrary skew-symmetrizable matrix?
In this paper, we propose a conjectural, combinatorial/geometric model for -matrices associated to an arbitrary skew-symmetrizable matrix, which extends our model from the acyclic case [20].
For this purpose, we introduce the notion of real Lösungen as an analogue of real roots, and define a family of reflections along with associated vectors which are real Lösungen for each mutation sequence of an arbitrary skew-symmetrizable matrix. The matrix consisting of these real Lösungen is called -matrix. We show that the -matrix comes from certain leading terms when the -matrix is presented using reflections. We conjecture that the -matrices (up to signs of row vectors) depend only on seeds, i.e., do not depend on mutation sequences leading to the same seed. We believe that understanding these new matrices is a key to generalizing Coxeter groups and their quotients arising from cluster algebras, in particular, generalizing Felikson–Tumarkin’s result [11].
When a skew-symmetrizable matrix is acyclic, it is natural to consider the corresponding symmetrizable generalized Cartan matrix. For a general skew-symmetrizable matrix, we consider generalized intersection matrices (GIMs)111Some authors call them quasi-Cartan matrices. For example, see [4]. introduced by Slodowy [33, 32]. A GIM is a square matrix with integral entries such that
- (1)
for diagonal entries, ; 2. (2)
if and only if ; 3. (3)
if and only if .
Since we are more interested in cluster algebras associated with skew-symmetrizable matrices, we restrict ourselves to the class of symmetrizable GIMs. This class contains the collection of all symmetrizable generalized Cartan matrices as a special subclass.
Let be the (unital) -algebra generated by , , subject to the following relations:
[TABLE]
Let be the subgroup of the units of generated by , . Note that is (isomorphic to) the universal Coxeter group. Thus the algebra can be considered as the algebra generated by the reflections and projections of the universal Coxeter group. Keeping computations at the level of will reveal some important features of mutations.
Definition 1.1**.**
Let be an symmetrizable GIM, and be the symmetrizer, i.e. the diagonal matrix such that , and is symmetric. Let be the lattice generated by the formal symbols .
- (1)
An element is called a Lösung if
[TABLE]
A Lösung is positive if for all . Each is called a simple Lösung. 2. (2)
Define a representation by
[TABLE]
We suppress when we write the action of an element of on . A Lösung is real if for some and .
Remark 1.2**.**
When is symmetric, a Lösung is also called a root in some literature. For example, see [1, 25]. When is a generalized Cartan matrix of finite, affine or hyperbolic type, this terminology does not bring any confusion with a root222Historically, when Killing investigated the structure of a finite dimensional simple Lie algebra with Cartan subalgebra , the roots of the characteristic polynomial , , were called the roots [3]. of the root system associated with because a Lösung is a root of the root system [18, Proposition 5.10]. However, in general, a Lösung is not a root of the root system. See [23, p.11] for the case when is of type . In order to avoid possible confusion, we introduce the term Lösung to distinguish it from a root of a root system.
Nevertheless, if is a generalized Cartan matrix, real Lösungen are the same as real roots of the Kac–Moody algebra associated with . We expect that, for each symmetrizable GIM, there may exist a Lie algebra for which real roots can be defined and are compatible with real Lösungen, but we do not yet know which Lie algebra would be adequate. Some related works can be found in [4, 5, 7, 8, 26, 32, 33, 35].
Fix an skew-symmetrizable matrix and let be its symmetrizer such that is skew-symmetric, and . Consider the matrix . After a sequence of mutations, we obtain . The matrix is called the -matrix and its row vectors the -vectors. Write their entries as
[TABLE]
where are the -vectors. For a mutation sequence , , we define .
Definition 1.3**.**
For each mutation sequence , define inductively with the initial elements , , as follows:
[TABLE]
Clearly, each is written in the form
[TABLE]
This construction has been used in the literature including [2, 11, 12, 34] when the associated GIM is a Cartan matrix.
Definition 1.4**.**
Fix a GIM , and define
[TABLE]
Then the -matrix associated to is defined to be the matrix whose row is for , i.e.,
[TABLE]
and the vectors are called the -vectors of .
Note that the -matrix and -vectors associated to a GIM implicitly depend on the representation which is suppressed from the notation. When multiple GIMs are being discussed we will use the notation to distinguish between different sets of -vectors.
When we fix a GIM, we will always choose a linear ordering on and define the associated GIM by
[TABLE]
An ordering provides a certain way for us to regard the skew-symmetrizable matrix as acyclic even when it is not.
As our geometric model, we consider a Riemann surface and admissible curves (Definition 2.1), and define a map from the set of admissible curves to the set of monomials in ’s in (Definition 2.3). The first conjecture below extends our conjecture in [20] from acyclic quivers to skew-symmetrizable matrices. The second conjecture claims that we can choose a GIM to obtain a set of reflections that only depend on the seed.
Conjecture 1.5**.**
Fix an ordering on so that a GIM is determined. Then for any mutation sequence , there exist non-self-intersecting admissible curves such that where are the monomials in associated to for .
Conjecture 1.6**.**
For any skew-symmetrizable matrix , there exists a linear ordering and its associated GIM such that if and are two mutation sequences with then
For any acyclic skew-symmetrizable matrix, choosing a linear ordering where if and only if yields a GIM that is a Cartan matrix by (1.4). In this case, Conjecture 1.6 has been proven in [34] using some results from categorification of cluster algebras.
As the main result of this paper, we show that the reflections naturally arise in connection with the -matrix. It also justifies potential importance of the matrix . The key idea is to maintain that we should have a “root system” for each mutation sequence as in the acyclic case. More precisely, we choose a linear ordering and its associated GIM, and inductively define an -tuple of elements and an -tuple of vectors , , so that the following formulae hold:
[TABLE]
where . We denote by the matrix whose rows are .
Theorem 1.7**.**
Fix a linear ordering on to obtain its associated GIM . Then, for each mutation sequence , we have
[TABLE]
Moreover,
[TABLE]
As one can see from the flow chart in Table 1, the definitions of and are somewhat convoluted and heavily depend on . Nevertheless, in the end, we obtain and which do not depend on . Moreover, this process reveals that are certain leading terms in . Since are related to and to , the -vectors can be considered as “leading terms” of the -vectors . What Conjectures 1.5 and 1.6 claim is that these leading terms carry essential information.
To illustrate Theorem 1.7, we present Example 1.8 below. Conjecture 1.5 will be checked for this example in Example 2.2 after an admissible curve is defined. Conjecture 1.6 is trivially satisfied for this matrix since its exchange graph is a tree (see [28]) and thus does not occur (unless and differ only by repeated mutations at the same index). A non-trivial example of Conjecture 1.6 is given in Example 2.15.
Example 1.8**.**
Consider the skew-symmetrizable matrix with the symmetrizer , and the sequence of consecutive mutations at indices :
Thus we have obtained three -vectors , and .
We take the linear ordering . Then its GIM and the symmetrized matrix are as follows:
[TABLE]
In accordance with (1.1), define a quadratic form by
[TABLE]
Then we have
[TABLE]
Thus all three -vectors are Lösungen for .
From Definition 1.3, we obtain
[TABLE]
where is the mutation sequence . For the GIM , Definition 1.4 gives rise to the -vectors
[TABLE]
On the other hand, following the definitions in Section 2, we obtain similar results for the . In particular,
[TABLE]
Thus the matrix equals the -matrix.
However, -vectors will not always be equal to positive -vectors. Indeed, they need not even be sign-coherent. For the choice of GIM we see that
[TABLE]
1.1. Organization of the paper
In Section 2, precise definitions will be made for the objects appeared in this introduction, and Conjectures 1.5 and 1.6 will be presented in a more refined way, and other examples will be given. In Section 3 the elements and the vectors will be defined with a running example, and Theorem 1.7 will be stated more precisely. In Section 4, Theorem 1.7 will be proven through induction. The main induction step consists of six different cases, each of which has a few subcases.
Acknowledgments
We are very grateful to Pavel Tumarkin, Ahmet Seven and anonymous referees for correspondences and comments, which substantially improved the exposition of this paper.
2. Conjectures
In this section, we present our conjectures in a more precise way after making necessary definitions.
For a nonzero vector , we define if all are non-negative, and if all are non-positive. This induces a partial ordering on . Define .
Assume that is an matrix of integers. Let be the set of indices. For , , we define the matrix inductively: the initial matrix is for , and assuming we have , define the matrix for with by
[TABLE]
where is the signature of . The matrix is called the mutation of at the index .
Let be an skew-symmetrizable matrix and be its symmetrizer such that is symmetric, and . Consider the matrix and a mutation sequence . After the mutations at the indices consecutively, we obtain . Write their entries as in (1.2). It is well-known that the -vector is non-zero for each , and either or due to sign coherence of -vectors ([10, 14]).
Choose a linear ordering on the set , and define a GIM by (1.4). From Definition 1.1, we have Lösungen associated with . Set to be a basis of . Recall that we have defined the algebra in the introduction. Define a representation by
[TABLE]
and by extending it through linearity, where is the Kronecker delta. We will suppress when we write the action of an element of on . As before, denote by the subgroup of the units of generated by , .
To introduce our geometric model333An alternative geometric model can be found in [12]. for -vectors, we need a Riemann surface equipped with labeled curves as below. Let and be two identical copies of a regular -gon. For , label the edges of each of the two -gons by counter-clockwise.
On , let be the line segment from the center of to the common endpoint of and . Later, these line segments will only be used to designate the end points of admissible curves and will not be used elsewhere. Fix the orientation of every edge of (resp. ) to be counter-clockwise (resp. clockwise) as in the following picture.
T_{\sigma(n-1)}$$T_{\sigma(1)}$$T_{\sigma(n)}$$T_{\sigma(n-2)}$$T_{\sigma(2)}⋮
L_{2}$$T_{\sigma(2)}$$T_{\sigma(n-2)}⋮T_{\sigma(1)}$$T_{\sigma(n-1)}
Let be the Riemann surface of genus obtained by gluing together the two -gons with all the edges of the same label identified according to their orientations. The edges of the -gons become different curves in . If is odd, all the vertices of the two -gons are identified to become one point in and the curves obtained from the edges become loops. If is even, two distinct vertices are shared by all curves. Let , and be the set of the vertex (or vertices) on .
Let be the universal Coxeter group of rank , which is by definition isomorphic to the free product of -copies of , and let be the set of reflections in . We will denote an element of as a word from the alphabet . In particular, an element of can be written as such that is an odd integer and for all .
Definition 2.1**.**
An admissible curve is a continuous function such that
-
if and only if ;
-
there exists such that and ;
-
if then meets transversally for sufficiently small ;
-
, where is given by
[TABLE]
We consider curves up to isotopy. When , , for , the curve is isotopic to a curve with . If and are curves with and , define their concatenation to be a curve such that .
Example 2.2**.**
Continuing Example 1.8, we choose admissible curves on a triangulated torus such that and draw the curves in Figure 1 to illustrate that they are non-self-intersecting. This verifies Conjecture 1.5 for this example. (In this example, it is not necessary to go through .) We also draw the curves on the universal cover of in Figure 2 to see that they have no pairwise intersections.
Definition 2.3**.**
For , define . We write for an admissible curve .
Now we state Conjecture 1.5 in a more refined way.
Conjecture 2.4** (Conjecture 1.5).**
Fix an ordering on so that a GIM is determined. Then, for each mutation sequence , there exists a family of non-self-crossing admissible curves , , on the Riemann surface for some such that
Example 2.5**.**
Consider the matrix . It arises from a triangulation of the torus with one boundary component with one marked point. It is commonly referred to as the dreaded torus. With the mutation sequence we have
[TABLE]
Choose the linear ordering . From Definition 1.3, we obtain
[TABLE]
In Figure 3 we provide curves such that for all It is clear that they are non-self-intersecting on the surface with written in one-line notation. By inspection these curves can be seen to be pairwise non-crossing.
In Example 2.6 we show is necessary in Conjecture 2.4 to avoid self-intersections.
Example 2.6**.**
Consider the matrix . Applying to the mutation sequence we have
[TABLE]
Let be the curve defined by . Upon inspection, for any the curve has a self-intersection in However, for any choice of GIM we have so the curve given by satisfies and can be drawn with no self-intersections.
In order to refine Conjecture 1.6, we need a new definition. A sequence of indices is said to be a chordless cycle in a skew-symmetrizable matrix if
- (1)
if and only if , 2. (2)
for any distinct we have if and only if ,
Additionally, a chordless cycle is said to be oriented if and only if all entries for have the same sign. Two chordless cycles are considered equivalent if they have the same underlying set of indices.
Conjecture 2.7** (Conjecture 1.6).**
Let be a skew-symmetrizable matrix.
- (1)
There exists a linear ordering on such that every oriented chordless cycle in has an odd number of positive , , where is the GIM determined by . 2. (2)
Fix an ordering and its GIM satisfying the condition in (1). If and are two mutation sequences such that then
The elements can be viewed as elements of , and Conjecture 2.7 can be interpreted as a statement about relations in Relations for these groups have been explored for particular skew-symmetrizable matrices and a restricted class of GIMs in [2, 11, 30]. A thorough investigation of relations in and their application to Conjecture 2.7 will take place in a subsequent article. It is expected that all of the discovered relations will hold for any GIM satisfying the condition in Conjecture 2.7 (1) which is a weaker than Seven’s notion of admissibility [29, 30].
In Proposition 2.9 below, we will prove Conjecture 2.7 (1) for a special family using results in [29, 31]. In discussing the notion of cycles we will briefly switch from the perspective of matrices to that of the directed graph.
Definition 2.8**.**
Let be an skew-symmetrizable matrix. Define to be the directed graph with vertices in and arrows for .
Note that the definition of a chordless cycle for a matirx is equivalent to the standard definition of chordless cycle in the directed graph .
Now, for the time being, assume that is a skew-symmetrizable matrix which can be mutated from an acyclic matrix through a mutation sequence , i.e., assume . Let be the generalized Cartan matrix associated with , and define
[TABLE]
Then, by [31, Theorems 1.2] (see also [29]), the matrix is a GIM such that for and
[TABLE]
Let us consider the following conditions for :
- (AC1)
every oriented (not necessarily chordless) cycle has at least one edge such that ;
- (AC2)
if an edge with is contained in a cycle either oreinted or non-oriented, then it is also contained in an oriented chordless cycle.
Proposition 2.9**.**
Assume that is a skew-symmetrizable matrix which can be mutated from an acyclic matrix . Let be the GIM defined in (2.3). Suppose that (AC1) and (AC2) hold. Then Conjecture 2.7 (1) is true.
Proof.
It follows from (2.4) that satisfies Conjecture 2.7 (1) if it arises from a linear ordering. To this effect, let , and define to be the graph obtained from by reversing the directions of edges with . We will show that is acyclic, and define a relation on the set of vertices as follows:
[TABLE]
Then the relation will be a strict partial order on .
Suppose that there is an oriented cycle in . Then it is also a cycle in , but not necessarily oriented. We inductively define the sequence of oriented cycles in as follows: Suppose that is defined for some . If then we define to be equal to . Suppose that . By (AC2), there must be an oriented chordless cycle in . Then we define as a subgraph of to be the oriented cycle obtained from by replacing the single arrow with the oriented path . Here, thanks to (2.4), we have , for , and . Once are defined, the last one is an oriented cycle such that and for all . By definition of , the graph also has the same oriented cycle . This contradicts (AC1). Thus is acyclic.
Now refine to a linear ordering on . Let be given by (1.4). We need to show that . We have if , and if . Assume and . If , then by definition, which is a contradiction. Thus and . Assume and . Then . If , then and hence by definition, which is a contradiction. Thus and . The other cases are similar, and we have in all the cases. ∎
Example 2.10**.**
Let be the skew-symmetric matrix associated with the quiver below via the rule if and if there is no arrow between and . This quiver is obtained applying mutations at vertices to the acyclic quiver also shown below.
[TABLE]
From (2.3), we obtain GIM associated to (or ). We specify the signature of on and draw the acyclic graph defined in the proof of Proposition 2.9:
[TABLE]
It is easy to see that satisfies (AC1) and (AC2). Indeed, we see (2.4) holds, and there is only one additional (simple) oriented cycle with chords, which has two positive edges. Now the definition of in the proof of Proposition 2.9 yields , and . Thus a refinement to a linear odering is given by , which gives rise to via (1.4). Clearly, Conjecture 2.7 (1) holds with this linear ordering.
Example 2.11**.**
Let be the skew-symmetric matrix associated with the quiver below in the same way as in Example 2.10. This quiver is obtained applying mutations at vertices to the acyclic quiver also shown below.
[TABLE]
From (2.3), we obtain GIM . We specify the signature of on and draw the acyclic graph :
[TABLE]
It is straightforward to check that satisfies (AC1) and (AC2), and we can take for Conjecture 2.7 (1).
Remark 2.12**.**
It will be interesting to investigate when a skew-symmetrizable matrix mutated from an acyclic matrix satisfies (AC1) and (AC2). It may be that such a matrix always satisfies the conditions.
The lemma below provides another sufficient condition for existence of a linear ordering and its GIM satisfying the condition in Conjecture 2.7 (1). If we do not require that a GIM is determined by a linear ordering, it can be proven that a GIM satisfying the condition of Conjecture 2.7 (1) always exists for any skew-symmetrizable matrix. But in order to define the elements as in the next section, it is necessary that arises from a linear ordering.
Lemma 2.13**.**
Let be a skew-symmetrizable matrix. Consider as undirected. Assume that each of the (undirected) chordless cycles in has an edge in the cycle that is not contained in any other (undirected) chordless cycles. Then Conjecture 2.7 (1) is true.
Proof.
For a collection of arrows in , we can define a new directed graph by reversing the direction of the arrows of . If is acyclic we may define a linear order by setting if is an arrow of and extending it to a linear ordering on . We will show that there exists a set of arrows that contains an odd number of arrows (actually one arrow) from every oriented chordless cycle of such that is acyclic. Therefore it follows from (1.4) that the associated GIM satisfies the condition in the statement of the lemma.
As in the statement of the lemma, we consider undirected for the time being. Let be the set of undirected chordless cycles in and take to be the set of edges in such that is an edge of and not an edge of for any . Such an exists by the assumption. Let be the spanning tree obtained from removing the edges in from . Now we consider directed again, and let be the opposite arrow of We will construct the desired sequence of arrows as a subset of by iteratively taking to be in if and only if either
- (1)
is oriented in , or 2. (2)
has an oriented cycle.
Now define from by reversing the direction of the arrows of . Then for any oriented cycle of we have reversed only one arrow of the cycle by (1) and the choice of , so any oriented chordless cycle of is no longer oriented in . Furthermore every non-oriented cycle of remains non-oriented in by (2). Therefore all of the chordless cycles of are non-oriented and it must be that is acyclic. ∎
We now give an example illustrating the proof of Lemma 2.13.
Example 2.14**.**
Let be the skew-symmetric matrix given in Figure 4, or any skew-symmetric matrix with the same directed graph shown in the figure. The graph has two oriented chordless cycles and , and three undirected chordless cycles and given by , , and , respectively. Consider , , and . Then satisfies the assumption of Lemma 2.13, and we obtain the spanning tree \mathcal{T}=\raisebox{-28.45274pt}{ \leavevmode\hbox to0pt{\vbox to0pt{\pgfpicture\makeatletter\hbox{\hskip 0.0pt\lower 0.0pt\hbox to0.0pt{\pgfsys@beginscope\pgfsys@invoke{ }\definecolor{pgfstrokecolor}{rgb}{0,0,0}\pgfsys@color@rgb@stroke{0}{0}{0}\pgfsys@invoke{ }\pgfsys@color@rgb@fill{0}{0}{0}\pgfsys@invoke{ }\pgfsys@setlinewidth{0.4pt}\pgfsys@invoke{ }\nullfont\hbox to0.0pt{\pgfsys@beginscope\pgfsys@invoke{ }{{}} \centering\tkzDefPoint(0,0){A} \tkzDefShiftPoint[A](0:2.42){B} \tkzDefShiftPoint[A](-120:2.5){C} \tkzDefShiftPoint[A](-60:2.5){D} \tkzDefShiftPoint[B](-60:2.5){E} \tkzDrawPoints(A,B,C,D,E) \tkzLabelPoint[above right](B){ \tiny2} \tkzLabelPoint[above left](A){ \tiny1} \tkzLabelPoint[below left](C){ \tiny3} \tkzLabelPoint[below](D){ \tiny4} \tkzLabelPoint[below right](E){ \tiny5} \tkzDrawSegments[->, shorten >=5, shorten <=5, >=stealth'](D,C A,D D,E B,D) \@add@centering \pgfsys@invoke{\lxSVG@closescope }\pgfsys@endscope{}{}{}\hss}\pgfsys@discardpath\pgfsys@invoke{\lxSVG@closescope }\pgfsys@endscope\hss}}\lxSVG@closescope\endpgfpicture}}} by removing from . Now to construct we see that by condition (1), since is not oriented and \mathcal{T}\cup\{\overline{e_{1}},e_{2}\}=\raisebox{-28.45274pt}{ \leavevmode\hbox to0pt{\vbox to0pt{\pgfpicture\makeatletter\hbox{\hskip 0.0pt\lower 0.0pt\hbox to0.0pt{\pgfsys@beginscope\pgfsys@invoke{ }\definecolor{pgfstrokecolor}{rgb}{0,0,0}\pgfsys@color@rgb@stroke{0}{0}{0}\pgfsys@invoke{ }\pgfsys@color@rgb@fill{0}{0}{0}\pgfsys@invoke{ }\pgfsys@setlinewidth{0.4pt}\pgfsys@invoke{ }\nullfont\hbox to0.0pt{\pgfsys@beginscope\pgfsys@invoke{ }{{}} \centering\tkzDefPoint(0,0){A} \tkzDefShiftPoint[A](0:2.42){B} \tkzDefShiftPoint[A](-120:2.5){C} \tkzDefShiftPoint[A](-60:2.5){D} \tkzDefShiftPoint[B](-60:2.5){E} \tkzDrawPoints(A,B,C,D,E) \tkzLabelPoint[above right](B){ \tiny2} \tkzLabelPoint[above left](A){ \tiny1} \tkzLabelPoint[below left](C){ \tiny3} \tkzLabelPoint[below](D){ \tiny4} \tkzLabelPoint[below right](E){ \tiny5} \tkzDrawSegments[->, shorten >=5, shorten <=5, >=stealth'](A,C A,B D,C A,D D,E B,D) \@add@centering \pgfsys@invoke{\lxSVG@closescope }\pgfsys@endscope{}{}{}\hss}\pgfsys@discardpath\pgfsys@invoke{\lxSVG@closescope }\pgfsys@endscope\hss}}\lxSVG@closescope\endpgfpicture}}} does not have an oriented cycle, and by condition (1). Thus , and \mathcal{H}=\raisebox{-28.45274pt}{ \leavevmode\hbox to0pt{\vbox to0pt{\pgfpicture\makeatletter\hbox{\hskip 0.0pt\lower 0.0pt\hbox to0.0pt{\pgfsys@beginscope\pgfsys@invoke{ }\definecolor{pgfstrokecolor}{rgb}{0,0,0}\pgfsys@color@rgb@stroke{0}{0}{0}\pgfsys@invoke{ }\pgfsys@color@rgb@fill{0}{0}{0}\pgfsys@invoke{ }\pgfsys@setlinewidth{0.4pt}\pgfsys@invoke{ }\nullfont\hbox to0.0pt{\pgfsys@beginscope\pgfsys@invoke{ }{{}} \centering\tkzDefPoint(0,0){A} \tkzDefShiftPoint[A](0:2.42){B} \tkzDefShiftPoint[A](-120:2.5){C} \tkzDefShiftPoint[A](-60:2.5){D} \tkzDefShiftPoint[B](-60:2.5){E} \tkzDrawPoints(A,B,C,D,E) \tkzLabelPoint[above right](B){ \tiny2} \tkzLabelPoint[above left](A){ \tiny1} \tkzLabelPoint[below left](C){ \tiny3} \tkzLabelPoint[below](D){ \tiny4} \tkzLabelPoint[below right](E){ \tiny5} \tkzDrawSegments[->, shorten >=5, shorten <=5, >=stealth'](A,C A,B D,C A,D D,E B,D B,E) \@add@centering \pgfsys@invoke{\lxSVG@closescope }\pgfsys@endscope{}{}{}\hss}\pgfsys@discardpath\pgfsys@invoke{\lxSVG@closescope }\pgfsys@endscope\hss}}\lxSVG@closescope\endpgfpicture}}}. The covering relations dictated by the acyclic graph are , , and One extension of these relations to a linear ordering is It is straightforward to check that the associated GIM has exactly one positive entry for each oriented chordless cycle of (or of ).
Recall the definition of an -matrix from Definition 1.4. We now provide an example illustrating Conjecture 2.7 and -vectors.
Example 2.15**.**
Let be the matrix from Example 2.5. For the two mutation sequences and we have On the other hand,
[TABLE]
and
[TABLE]
There are two oriented cycles on vertices and in . Take the GIM arising from the linear ordering . Then only the entry is positive for the cycles, and the condition in Corollary 1.6 is satisfied. Direct computation shows that , and Conjecture 1.6 is verified.
We identify with in Definition 1.4 and compute the -vectors
[TABLE]
and obtain the -matrix
[TABLE]
On the other hand,
[TABLE]
One may hope that the reflections would give a direct generalization of [34, Theorem 1.4] with the expectation that a product of ’s might equal in for some . However Example 2.16 provides a counterexample.
Example 2.16**.**
Let be the matrix from Example 2.6. After the mutation sequence we have
[TABLE]
It is straightforward to check that for any pair of The same is true when considering the matrix representation of the for any choice of GIM associated to .
This collection also provides an example where for any there will always be some pair of curves in and satisfying Conjecture 2.4 that intersect.
3. Main Theorem
In this section, we define the elements and the vectors to present the main theorem of this paper precisely. The key idea is that we make the formulae (1.5) inductively hold for each mutation sequence . This process shows that there is a unique term in that survives mod without regard to the choice of an ordering . More precisely, we prove (mod ). When is acyclic, the -vectors are the reflection vectors of as shown in [34] with the linear ordering defined by if and only if . However, for general , it is not true any more and comparing with will help us understand how the reflections arise in relation to the -vectors as it will be shown as a part of the main theorem that .
Throughout this section, assume that is a skew-symmetrizable matrix. Fix a linear ordering on to obtain its associated GIM from (1.4).
Example - 1**.**
As a running example in this section, we consider the skew-symmetrizable matrix
[TABLE]
with symmetrizer and linear ordering Following the convention in (1.4), we produce the GIM
[TABLE]
Assume that a mutation sequence is given. We will inductively define the elements and the vectors , , in what follows. The procedure is summarized in Table 1.
For convenience, we recall the definition of and its representation on . As before, set to be a basis of .
Definition - 1**.**
Let be the (unital) -algebra generated by , , subject to the following relations:
[TABLE]
Define a representation by
[TABLE]
and by extending it through linearity, where is the Kronecker delta. We will suppress when we write the action of an element of on .
Example - 2**.**
Continuing from Example -1, the action of , , are respectively given by the following matrices:
[TABLE]
Here the action of on the vector is to be understood by multiplication of the matrix on the right.
Definition - 2**.**
Suppose that starts with . Let be the set of , , such that
- , or
- .
Let be the set of , , such that
- , or
- .
Definition - 3**.**
Define
[TABLE]
where the sum is over such that or , and define
[TABLE]
Definition - 4**.**
Define
[TABLE]
Example - 3**.**
Continuing from Example -2, take so We have and . It follows that and Putting everything together we see that
[TABLE]
We then have
[TABLE]
By (3.3) we define for all .
Definition - 5**.**
Inductively, assume , including the case . For , define
[TABLE]
and
[TABLE]
where we set
[TABLE]
Example - 4**.**
Continuing from Example -3 we have and For we have More explicitly,
[TABLE]
For ,
[TABLE]
and finally
[TABLE]
Definition - 6**.**
Define
[TABLE]
where the sum is over such that or , and define
[TABLE]
Example - 5**.**
In Example -3 we computed so
[TABLE]
Now by comparing given in Example -2 to , we have
[TABLE]
Definition - 7**.**
Let be the collection of such that
- , or
- , or
- .
Similarly, let be the collection of such that
- , or
- , or
- .
Example - 6**.**
Continuing from Example -5 we have
[TABLE]
*so and *
Definition - 8**.**
Define
[TABLE]
where the sum is over such that or , and define
[TABLE]
Definition - 9**.**
Finally, define
[TABLE]
Example - 7**.**
Continuing from Example -6 we have
[TABLE]
Furthermore,
[TABLE]
In Example -5 we computed Finishing our running example we conclude that
[TABLE]
For any mutation sequence , set
[TABLE]
Now we restate the main theorem of this paper.
Theorem 3.1** (Theorem 1.7).**
Let be a skew-symmetrizable matrix. Fix a linear ordering on to obtain a GIM . Then, for any mutation sequence , we have
[TABLE]
or equivalently,
[TABLE]
for ,
[TABLE]
moreover, for all ,
[TABLE]
In what follows, we prove (C3). A proof of (C1) and (C2) will be given in Section 4.
Proof of (C3).
Notice from (3.6) that modulo . Then the equation (3.5) becomes modulo
[TABLE]
Using (C1) and (C2), both of the conditions and can be rewritten as
[TABLE]
which does not depend on the choice of a GIM. Now (C3) follows from the definitions (3.2), (3.5) and (3.6) and from induction. ∎
3.1. Some observations
We close this section with examples which show some relationship between -vectors and Lösungen.
Example 3.2**.**
Consider the matrix . The mutation sequence produces the -vector which is not a Lösung for any choice of GIM associated to .
Example 3.3 below shows that even if a -vector is a real Lösung our formula may not always express it as such.
Example 3.3**.**
Consider the matrix This is a finite-type matrix that corresponds to an orientation of the Dynkin diagram After the mutation sequence with the GIM associated to the linear order our formula produces
[TABLE]
However, we also have so we see that could just be expressed as the real Lösung as opposed to the linear combination of real Lösungen given above. For completeness, we have and
It is also worth noting that the matrix representation of is not equal to the matrix representation of . Furthermore, for any choice of linear ordering the expression for that our formula produces will always have three or four terms even though the vector is a real Lösung.
4. Proof of (C1) and (C2) in Theorem 3.1
In this section we prove Theorem 3.1. We start with the following proposition which shows that satisfy natural relations for each .
Proposition 4.1**.**
For and for any mutation sequence , the following relations hold:
[TABLE]
Proof.
We use induction. If , all the relations follow from the definitions. Assume the relations hold for . In what follows, we show that they hold for , .
Relation (4.1): Since for by induction, we have , and obtain
[TABLE]
Relations (4.2): Suppose that and . Note that and . Assume and . Then
[TABLE]
Assume and . Then
[TABLE]
Assume and . Then
[TABLE]
Assume and . Then
[TABLE]
For and , write for the time being, and we get
[TABLE]
We have proven
[TABLE]
for all .
Relations (4.3): Assume that and . Suppose that and . Then we have
[TABLE]
Suppose that and .
[TABLE]
Suppose that and .
[TABLE]
Suppose that and . Note that
[TABLE]
Then we have
[TABLE]
Assume that . Suppose that . Note that
[TABLE]
Then we have
[TABLE]
Suppose that . Note that
[TABLE]
Then we have
[TABLE]
Assume that . Suppose that . Since , we get
[TABLE]
The case is similar to the case . We omit the computations for this case.
Assume that . Then
[TABLE]
Relations (4.4): For , we have and
[TABLE]
For , we get
[TABLE]
Relations (4.5): Suppose that or and . Since and for , we have
[TABLE]
Thus or , and we have
[TABLE]
Suppose that and . Since for , the computation is similar to the previous case to obtain in this case as well. Furthermore, since , we get
[TABLE]
Relations (4.6): Assume , and suppose that . Then
[TABLE]
The case is similar. For , we obtain
[TABLE]
For , we have
[TABLE]
∎
Proof of Theorem 3.1.
The statements (C1) and (C2) are true for from the definitions. Assume that (C1) and (C2) hold for . We will show that they also hold for , . There are cases (1)-(6) according to the order of , and each case has several subcases. Since arguments are all similar, we will show details for the cases (1), (3), (4) and (6) and skip some details for the other cases.
To begin with, let us recall some definitions for ease of reference. From the definition of mutation in (2.1), we have
[TABLE]
and rewrite the definition of -vectors as
[TABLE]
For , consider the condition
[TABLE]
and rewrite (3.7), (3.4) and (3.5):
[TABLE]
In each of the following cases (1)-(6), we will show the statements (C1) and (C2):
[TABLE]
for ,
[TABLE]
- Assume that . By induction we have
[TABLE]
a) Suppose and . Then from (4.8), we have
[TABLE]
and obtain from (4.8)
[TABLE]
By induction,
[TABLE]
which proves (C1) in this case.
From (4.9),
[TABLE]
and by induction,
[TABLE]
We also have
[TABLE]
From the definitions, , and thus
[TABLE]
Similarly, we get
[TABLE]
This proves (C2) in this case.
b) Suppose and . From (4.8), we have
[TABLE]
On the other hand, we obtain from (4.8)
[TABLE]
If then and
[TABLE]
by induction. If then and
[TABLE]
Similarly, . This proves (C1) in this case.
From (4.9),
[TABLE]
and by induction,
[TABLE]
Similarly, and .
We have
[TABLE]
From the definitions, , and thus
[TABLE]
If and , then we obtain from (4.11)
[TABLE]
If and , then it follows from (4.12) that
[TABLE]
Similarly, we get
[TABLE]
If then
[TABLE]
This proves (C2) in this case.
c) Suppose and . From (4.8), we have
[TABLE]
On the other hand, we obtain from (4.8)
[TABLE]
Thus by induction, and using the same argument as in (b), we also see that . Therefore (C1) is true in this case.
From (4.9),
[TABLE]
and it follows from similar computations to those in (a) and (b) that
[TABLE]
We have
[TABLE]
From the definitions, , and thus
[TABLE]
If and , then , , and thus and by (4.7)
[TABLE]
If and , then , and thus and by (4.7)
[TABLE]
Similarly, we get
[TABLE]
This proves (C2) in this case.
d) Suppose and . This case is similar to case (c) right above.
-
Assume that . Since this case is similar to case (1), we omit the details.
-
Assume that . By induction we have
[TABLE]
a) Suppose and . From (4.8), we have
[TABLE]
It follows from (4.8) that
[TABLE]
Thus and by induction. Thus (C1) is true in this case.
From (4.9),
[TABLE]
and it follows from induction that
[TABLE]
We have
[TABLE]
Clearly, , and thus
[TABLE]
Similarly, we get
[TABLE]
This proves (C2) in this case.
b) Suppose and . From (4.8), we have
[TABLE]
We obtain from (4.8)
[TABLE]
If then and
[TABLE]
by induction. If then and
[TABLE]
Similarly, . This proves (C1) in this case.
From (4.9),
[TABLE]
and it follows from induction that
[TABLE]
We have
[TABLE]
Clearly, , and as in (1)-(b),
[TABLE]
If , then we obtain from (4.13)
[TABLE]
If , then it follows from (4.14) that
[TABLE]
Similarly, we get
[TABLE]
This proves (C2) in this case.
c) Suppose and . From (4.8), we have
[TABLE]
On the other hand, we obtain from (4.8)
[TABLE]
Thus by induction, and using the same argument as in (b), we also see that . Therefore (C1) is true in this case.
From (4.9),
[TABLE]
and it follows from induction that
[TABLE]
We have
[TABLE]
From the definitions, , and thus
[TABLE]
If , then , , and thus and by (4.7)
[TABLE]
If , then and thus and by (4.7)
[TABLE]
Similarly, we get
[TABLE]
This proves (C2) in this case.
d) Suppose and . This case is similar to (c) and we omit the details.
- Assume that . By induction we have
[TABLE]
a) Suppose . From (4.8), we have
[TABLE]
Since , we obtain from (3.7) and induction
[TABLE]
Thus and by induction, and (C1) is true in this case.
[TABLE]
and it follows from induction that
[TABLE]
We have
[TABLE]
We see that , and thus
[TABLE]
Similarly, we get
[TABLE]
This proves (C2) in this case.
b) Suppose . From (4.8), we have
[TABLE]
On the other hand, we obtain from (3.7)
[TABLE]
If then and ; if then and . Thus and by induction, and (C1) is true in this case.
[TABLE]
and it follows from induction that
[TABLE]
We have
[TABLE]
If , then and , and thus
[TABLE]
and since we have
[TABLE]
If , then and , and the computations are similar to the case right above. This proves (C2) in this case.
-
Assume that . Since this case is similar to case (4), we omit the details.
-
Assume that . From (4.8), we have . As seen in (4.15), we have . Thus by induction , and (C1) holds. In cases (4) and (5), it is proven that for . Thus using (4.1), we have
[TABLE]
Finally, since , we see that
[TABLE]
where we use (4.5). This proves (C2) in this case, and a proof of Theorem 3.1 has been completed.
∎
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