Quantitative Oppenheim conjecture for $S$-arithmetic quadratic forms of rank $3$ and $4$
Jiyoung Han

TL;DR
This paper extends the quantitative Oppenheim conjecture results to $S$-arithmetic quadratic forms of rank 3 and 4, showing that almost all such forms satisfy the conjecture despite exceptions in low dimensions.
Contribution
It generalizes the quantitative Oppenheim conjecture to the $S$-arithmetic setting for quadratic forms of rank 3 and 4, including almost all forms.
Findings
Almost all $S$-arithmetic quadratic forms of rank 3 and 4 satisfy the conjecture.
Extension of previous results from real to $S$-arithmetic quadratic forms.
The result holds despite known exceptions in low-dimensional cases.
Abstract
The celebrated result of Eskin, Margulis and Mozes (1998) and Dani and Margulis (1993) on quantitative Oppenheim conjecture says that for irrational quadratic forms of rank at least 5, the number of integral vectors such that is in a given bounded interval is asymptotically equal to the volume of the set of real vectors such that is in the same interval. In dimension or , there are exceptional quadratic forms which fail to satisfy the quantitative Oppenheim conjecture. Even in those cases, one can say that almost all quadratic forms hold that two asymptotic limits are the same ([Eskin-Margulis-Mozes'98, Theorem 2.4]). In this paper, we extend this result to the -arithmetic version.
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Taxonomy
TopicsAdvanced Algebra and Geometry · Algebraic Geometry and Number Theory · Analytic Number Theory Research
Quantitative Oppenheim conjecture for -arithmetic quadratic forms of rank and
Jiyoung Han
J. Han. Research institute of Mathematics, Seoul National University Email address: [email protected]
Abstract.
The celebrated result of Eskin, Margulis and Mozes ([7]) and Dani and Margulis ([6]) on quantitative Oppenheim conjecture says that for irrational quadratic forms of rank at least 5, the number of integral vectors such that is in a given bounded interval is asymptotically equal to the volume of the set of real vectors such that is in the same interval.
In dimension or , there are exceptional quadratic forms which fail to satisfy the quantitative Oppenheim conjecture. Even in those cases, one can say that almost all quadratic forms hold that two asymptotic limits are the same ([7, Theorem 2.4]). In this paper, we extend this result to the -arithmetic version.
2010 Mathematics Subject Classification:
22F30, 22E45, 20F65, 20E08, 37P55
1. Introduction
History
The Oppenheim conjecture, proved by Margulis [15], says that the image set of integral vectors of an isotropic irrational quadratic form of rank at least 3 is dense in the real line (See [17] for the original statement of Oppenheim conjecutre).
Let be a bounded interval and let be a convex set containing the origin. Dani and Margulis [6] and Eskin, Margulis and Mozes [7] established a quantitative version of Oppenheim conjecture: for a quadratic form , let be the volume of the region and be the number of integral vectors in . They found that if an irrational isotropic quadratic form is of rank greater than or equal to 4 and is not a split form, then approximates as goes to infinity. Moreover, in this case, the image set is equidistributed in the real line.
Their works heavily rely on the dynamical properties of orbits of a certain semisimple Lie group, generated by its unipotent one-parameter subgroups, on the associated homogeneous space.
The -arithmetic space is one of the optimal candidates to consider a generalization of their work, since it has a lattice which is similar to the integral lattice in . Borel and Prasad [4] extend Margulis’ theorem to the -arithmetic version and Han, Lim and Mallahi-Karai [12] proved the quantitative version of -arithmetic Oppenheim conjecture. See also [27] and [13] for flows on -arithmetic symmetric spaces. Ratner [19] generalized her measure rigidity of unipotent subgroups in the real case to the cartesian product of real and -adic spaces.
Main statements
Consider a finite set of odd primes and let . For each , denote by the completion field of with respect to the -adic norm. If , the norm is the usual Euclidean norm and . Define . The diagonal embedding of
[TABLE]
is a uniform lattice subgroup in an additive group . We will define an -lattice in as a free -module of rank . An -quadratic form is a collection of quadratic forms defined over , . We call nondegenerate or isotropic if every in is nondegenerate or isotropic, respectively. We say that is rational if there is a single rational quadratic form such that , where and is irrational if it is not rational.
Notation. For a nonzero vector , the -adic norm refers the -adic norm of -adic component . We will use the following notation
[TABLE]
We use the notation for a vector consisting of unit vectors in each place .
For , we fix a star-shaped convex set on centered at the origin defined as
[TABLE]
where is a positive function on the set of unit vectors in and let . If , we will assume that is -invariant: for any and for any unit vector ,
[TABLE]
Let be a bounded convex set of the form if and if . We call a -adic interval. Define an -interval . Denote by the collection of radius parameters , . Consider the dilation of by .
We are interested in the number of vectors in such that . Let be the product of Haar measures on , . We assume that is the usual Lebesgue measure on and when . Let be the volume of the set with respect to on .
Recall that a quadratic form of rank is split if it is equivalent to . In [12], when an isotropic irrational quadratic form is of rank and does not contain a split form, then as , is approximated to . Here, we say that if for all . Moreover, it is possible to estimate in terms of and . As a result, there is a constant such that
[TABLE]
where .
When is of rank or is of rank and contains a split form, there exist quadratic forms such that fails to approximate . For instance, there is an irrational quadratic form of rank and a sequence for a given so that (see [7, Theorem 2.2] and [12, Lemma 9.2]).
Even in the low dimensional cases, one can expect that for generic isotropic quadratic forms, approximates , which is our main theorem.
Here, the term generic is with respect to the following measure: fix some quadratic form . One can identify with the space of quadratic forms of the same discriminant with . Under this identification, one can assign a natural -invariant measure on the space of quadratic forms.
Theorem 1.1**.**
For almost all isotropic quadratic forms of rank 3 or 4, as ,
[TABLE]
where and is a constant depending on a quadratic form and a convex set .
For real quadratic forms of signature , Eskin, Margulis and Mozes describe quadratic forms such that does not approximate to ([8]).
On the generic quadratic forms and their Oppenheim conjecture-type problems, there is a work of Bourgain [5] for real diagonal quadratic forms using analytic number theoretical method. Ghosh and Kelmer [9] showed another version of quantitative version of Oppenheim problem for real generic ternary quadratic forms and Ghosh, Gorodnik and Nevo [10] extended this result for more general setting, such as for generic characteristic polynomial maps. Recently, Athreya and Margulis [2] provided the bound of error terms for almost every real quadratic forms of rank at least 3.
For a pair of a quadratic form and a linear form of , Gorodnik [11] showed the density of under the certain assumption and Lazar [14] generalized his result for the -arithmetic setting. Sargent showed the density of , where is a rational quadratic form and is a linear map ([21]). In [22], he showed the quantitative version of his result.
In Section 2, we briefly review the symmetric space of the real and -adic Lie groups. In Section 3, we introduce an -arithmetic alpha function, defined on and equidistribution properties. We prove the main theorem in Section 4.
Acknowledgments
I would like to thank Seonhee Lim and Keivan Mallahi-Karai for suggesting this problem and providing valuable advices. This paper is supported by the Samsung Science and Technology Foundation under project No. SSTF-BA1601-03.
2. Symmetric spaces
Let us denote by an -arithmetic group of the form , where is a semisimple Lie group defined over , . An element of is , where . In most of cases, will be , . Consider the lattice subgroup of and the symmetric space , which can be embedded in the space of unimodular -lattices in .
The notation refers to a standard quadratic form, which is the collection of quadratic forms such that
[TABLE]
where if and if . Here is some fixed square-free integer in (See [24, Section 4.2]).
In , we fix a maximal compact subgroup of
[TABLE]
and a diagonal subgroup
[TABLE]
where and , . These groups and will be heavily used throughout the paper.
We assume that and have the relation
[TABLE]
unless otherwise specified. Also we briefly denote by or instead of or respectively.
In this section, we take and , , where or . Corresponding maximal compact subgroups are and respectively.
2.1. The 3-dimensional hyperbolic space
Let be a standard isotropic quadratic form of rank , . The special orthogonal subgroup is one of the well-known linear groups , and . Let us examine the symmetric space of quotiented by and define a metric invariant by right multiplication.
Case i) : Set to be the 3-dimensional hyperbolic space . The group is locally isomorphic to , which is the group of orientation-preserving isometries of . Since the stabilizer of the point in is the maximal compact subgroup , we may identify the symmetric space , which is isomorphic to , with the hyperbolic space . Let be the projection given by Define the metric of by
[TABLE]
Case ii) : Consider the isomorphism . We will use the notation for the projection as well. We define the metric of by
[TABLE]
Case iii): In the case of , consider the isomorphism between real vector spaces and given by
[TABLE]
The split form of corresponds to the determinant of \left(\begin{array}[]{cc}x&y\\ z&w\end{array}\right) in . Moreover, there is the local isomorphism from to , which is induced by the action
[TABLE]
Hence we deduce that
[TABLE]
where . Note also that the action of splits into the action of , where . Put
[TABLE]
Lemma 2.1**.**
Let be one of , or . Let be a maximal compact subgroup of . Then there exists a constant such that for any and for any ,
[TABLE]
where is the normalized Haar measure on .
Proof.
Assume that and . For each , acts transitively on the hyperbolic sphere of radius centered at .
Since is -invariant,
[TABLE]
The -invariant measure of is identified with the normalized Lebesgue measure of the unit sphere which is isomorphic to .
Let and let be the angle between two geodesics from to and from to (Figure 1). By the hyperbolic law of cosines
[TABLE]
and since , we obtain that is bounded by . Hence
[TABLE]
for some constant .
The case of follows immediately from the compatibility between two embeddings and with the projection (see also [7, Lemma 3.12]).
If , using the local isometry (2.2), acts transitively on the product of two hyperbolic spheres in . Thus we have
[TABLE]
∎
2.2. A tree in the building
For a prime and , let us briefly recall the Euclidean building , whose vertex set is isomorphic to . Recall the Cartan decomposition ([18, Theorem 3.14])
[TABLE]
where
[TABLE]
Consider the space of free -modules of rank in on which acts by
[TABLE]
where and are -basis of . Two rank- free -modules and are said to be equivalent if for some .
The building is an -dimensional CW complex whose vertices are equivalence classes of free -modules of rank . Vertices , , in form a -simplex if there are representatives , , in such that
[TABLE]
In particular, at each vertex in , the number of adjacent vertices with equals the number of proper nontrivial subspaces of the space . Note that at most vertices form a simplex in : there is an -generating set of such that
[TABLE]
Vertices in is also denoted by by matrices whose rows are generators of . By right multiplication of , they are represented by upper triangle matrices whose diagonal entries are in .
In , an apartment is defined as follows. The vertex set is
[TABLE]
for some . A -simplicial complex is in if its vertices are all contained in . Denote by the apartment whose vertex set is
[TABLE]
Note that is isometric to and is a lattice in (See Figure 2), which is the reason that is called a Euclidean building. There is the natural covering map given by
[TABLE]
where the matrix in the above map is a reduced type, i.e., and , .
We give a distance on by , where is the minimal number of edges connecting and .
Let be any geodesic in the vertex set of . Then the inverse image
[TABLE]
is a tree in . If the above set is generated by one element, then is a regular tree. More basic properties about buildings can be found in [1], [20] for Euclidean buildings, and see also [25] for Bruhat-Tits trees.
Lemma 2.2**.**
Let be a -rank one connected and simply connected semisimple algebraic subgroup of . Denote the Cartan decomposition of by , where . Then the symmetric space is a tree.
Proof.
Note that there is the natural embedding from to given by , . For , we denote by and by .
Since is of -rank one, up to an appropriate conjugation, is generated by some element with and . Hence we may assume that . Choose a geodesic in containing . Then is a subset of a tree . ∎
Let us show that for a -dimensional nondegenerate isotropic quadratic form on , if it is not a split form, then the special orthogonal group is of -rank one, similar to the case of real.
Lemma 2.3**.**
Let be an isotropic non-split quadratic form of rank . If we denote , where , then is isomorphic to the diagonal subgroup .
Proof.
Without loss of generality, let , where for some fixed , square-free over . Since is not a split form, . Hence, up to a change of variables, we may further assume that
- (1)
if is square-free; 2. (2)
otherwise.
Since any semisimple element of a connected algebraic group is contained in a maximal abelian subgroup and two maximal abelian subgroups are conjugate to each other ([26, Theorem 6.3.5]), we may assume that
[TABLE]
If the -rank of is larger than one, there is an element such that for any .
From the commutativity, for any , it follows that
[TABLE]
Since , it satisfies that for any ,
[TABLE]
Since , have no restriction except , by multiplying appropriate and to , where and , we may assume that . Hence we need to find such that (a) , (b) , (c) .
If , , , let us denote , where .
Suppose that and let , where is the first term such that . Denote by the -adic valuation. Then
- (1)
If , then is even and . Then and which contradicts to (a). 2. (2)
If , then is odd and . Then and which is also impossible according to (a).
Hence . Similarly, .
Now, assume . In this case, is a square. If there exists satisfying (a) through (c), then which contradict to the fact that is square-free. ∎
If is an isotropic quadratic form of rank 3, is isomorphic to . Then the symmetric space is isomorphic to a subtree of the regular tree . By Lemma 2.2 and Lemma 2.3, if is an isotropic non-split quadratic form of rank 4, then is a subtree of the building . Lastly, if is a split form of rank 4, then is locally isomorphic to as in (2.2). Then is properly embedded to the product of two -regular trees.
Corollary 2.4**.**
Let be a standard -adic isotropic quadratic form of rank or . Let . For any ,
[TABLE]
Proof.
Suppose that is an isotropic quadratic form of rank 3 or of rank 4 and non-split. By Lemma 2.2 and Lemma 2.3, is isomorphic to a tree. Since is right -invariant, the left hand side of (2.4) is
[TABLE]
For any , consider the geodesic segment in . If , since is a tree, and have the common segment of length at least . Therefore
[TABLE]
where is the largest integer less than or equal to .
Since is embedded in , for any , there are at least vertices in the sphere of radius in .
In the split case, the action of on is converted to the action of on , where . Then similar to the case of , we obtain the inequality (2.4). ∎
3. Equidistribution property for generic points
For , let be an -lattice in associated to , i.e., if , . We call a -rational subspace if is generated by elements in . If is a -rational subspace, is an -lattice in . Let be a covolume of in . If is an -basis of a -dimensional -rational subspace , then is given by
[TABLE]
Here for each , the -adic norm of is canonically extended to , which we also denote by .
Define a function by
[TABLE]
The following lemma is originated from [23], stated for lattices in . The statement and the proof of the -arithmetic version can be found in [12].
Lemma 3.1**.**
For a bounded function of compact support, the Siegel transform of is defined by
[TABLE]
Then there is a constant such that for any .
By Lemma 3.1 and Proposition 3.2, one can easily deduce that a Siegel transform is in .
Proposition 3.2**.**
[12, Lemma 3.9]** The function on belongs to every , .
In this section, we prove the equidistribution theorem for functions bounded by . We first recall the Howe-Moore theorem for . The statement for more general settings can be found in [3] or [16].
Theorem 3.3**.**
Consider and , . Take a maximal subgroup of as . Then, there exist constants , satisfying the following: if satisfy either
- (1)
both and are smooth of compact support or 2. (2)
both and are left -invariant,
then there exists a constant so that
[TABLE]
where .
Recall that is a diagonal element of defined in (2.1).
Lemma 3.4**.**
Let be a nondegenerate isotropic quadratic form of rank or . Let be a maximal compact subgroup of as in Section 3. Then there exist and a constant such that for and for any ,
[TABLE]
Proof.
Let and consider such that . From Lemma 2.1 and Lemma 2.2,
[TABLE]
The number of such nonnegative vectors is bounded above by . Since for any odd prime , the inequality (3.1) holds for . ∎
We say that a sequence is divergent if escapes any bounded subset of as . Recall that in Theorem 1.1, we are interested in the asymptotic limit of the given quantity when every component of goes to infinity. However, for the proof of the main theorem, we need to consider more general divergence in the next proposition and corollary.
Proposition 3.5**.**
Let and be as in Lemma 3.4 and let be a continuous function on . Assume that there are constants and for which
[TABLE]
Then for any nonnegative bounded function on and a divergent sequence ,
[TABLE]
for almost all .
Proof.
Let be arbitrary. For any function on , define
[TABLE]
For , let us denote by . We claim that one can find and constants such that for any ,
[TABLE]
Then (3.3) implies that
[TABLE]
Let . Choose a smooth non-negative function such that
- (1)
is -invariant, i.e., for all ; 2. (2)
if is in and if is outside of .
Take and . Then and is compactly supported. Choose such that . Then for any ,
[TABLE]
Put . By the above inequalities and Proposition 3.2,
[TABLE]
Let be either a smooth function of compact support or a left -invariant function. Later, we will put or . By Theorem 3.3, there are , such that for any ,
[TABLE]
where . For instance, we can take , where ’s are in Proposition 3.3. Note that
[TABLE]
where , . By Lemma 3.4,
[TABLE]
Hence by Cauchy-Schwartz inequality, we have that
[TABLE]
It is deduced from (3.4) that
[TABLE]
Hence by combining (3.5) and (3.6), there are and a constant such that for ,
[TABLE]
Now let us show following inequalities:
[TABLE]
[TABLE]
for some positive constants and . It is obvious that (3.7) and (3.8) imply (3.2).
First we note that . Let . Then there is such that for all , for all , . Hence we have
[TABLE]
Choose sufficiently large so that . Then
[TABLE]
By taking in (3.6) and using the Chebyshev’s inequality, there are and such that for any ,
[TABLE]
Hence using the geometric series argument, there is a constant such that the inequality (3.7) holds.
[TABLE]
For (3.8), note that since is compactly supported, is uniformly continuous. Hence there is such that
[TABLE]
for all , and . Again by (3.6) and Chebyshev’s inequality, there are and such that for all ,
[TABLE]
Then (3.8) follows from the similar geometric argument used above. ∎
From now on, a function on , , is always assumed to be compactly supported. If , we additionally assume that is -invariant:
[TABLE]
Let be the product of non-negative continuous functions on the unit sphere in , . For , we also assume that
[TABLE]
Define a function for by , where
[TABLE]
where is determined by the equation (If , replace by ). By Lemma 3.6 in [7] and Lemma 4.1 in [12], for sufficiently small , there are and for each , such that if ,
[TABLE]
[TABLE]
Recall that for the infinite place and for the finite place. Define
[TABLE]
By Lemma 3.6 in [7] and Lemma 4.1 in [12], there is a constant such that for sufficiently small and sufficiently large ,
[TABLE]
Corollary 3.6**.**
Let be a divergent sequence. Define
[TABLE]
Let be as in Theorem 1.1. Then for almost all nondegenerate isotropic quadratic form , there is a constant such that
[TABLE]
where is the rank of .
Proof.
Since we want to show the upper bound, for simplicity, we may assume that is the product of unit balls in , .
Let be given. For each , let be a compact set of the space of nondegenerate isotropic quadratic forms over of a given signature. Let .
Let be an element of such that for all . Then for each , there is such that if , for all .
Choose bounded continuous functions , , of compact support such that
[TABLE]
If satisfies that and , then
[TABLE]
for with . By (3.11) and (3.12), there is such that for each and for all ,
[TABLE]
For , we may further assume that for all .
Finally for each , choose a nonnegative bounded function on of compact support such that if and ,
[TABLE]
Take and let be the Siegel transform of defined in Lemma 3.1. Then for such that , , we obtain that
[TABLE]
By Proposition 3.5, for almost all quadratic form , as diverges,
[TABLE]
Hence there is a constant such that for all ,
[TABLE]
Therefore we have
[TABLE]
∎
4. The proof of the main theorem
The proof of Theorem 1.1 is similar to that of Theorem 1.5 in [12] except we use Proposition 3.5 instead of Theorem 7.1 in [12]. Let be any compact subset of the space of isotropic quadratic forms with equal signature and let be given. Let and be compactly supported functions defined as before.
Theorem 7.1 in [12] says that there is such that except on a finite union of orbits of , satisfies the following: for all ,
[TABLE]
Proposition 4.1**.**
Let be an isotropic quadratic form of rank or . Let and be as before. Assume further that satisfies the following condition: there is a nonnegative continuous function of compact support on such that , where is an interior of and
[TABLE]
Then there exists such that if ,
[TABLE]
Proof.
We first claim that there is a constant such that
[TABLE]
Since the interior of contains , there is such that
[TABLE]
Note that since is compactly supported, the set is finite. Take such that . Then by (3.13), for sufficiently large , we have that
[TABLE]
By (4.1), . This implies (4.3).
Now (4.2) follows from applying (3.13) by putting instead of and taking summation over all . ∎
Recall that a convex set is defined using a non-negative continuous function , where is a positive function on the unit sphere of , .
Define the shell of by
[TABLE]
Note that when , the inequality in the above definition is in fact the equality: .
The following proposition was originally stated for but the proof can be easily modified for .
Proposition 4.2**.**
[12, Proposition 1.2]** There is a constant such that as ,
[TABLE]
Lemma 4.3**.**
[12, Lemma 5.2]** Let and be as in Proposition 4.1. Take
[TABLE]
and set . Then we have
[TABLE]
Proof of Theorem 1.1.
Since in Proposition 4.1 is compactly supported, there is such that . By Proposition 3.5 with and ,
[TABLE]
for almost all . By Lemma 3.1 and Proposition 3.2, the integral of over is finite. Hence one can apply Proposition 4.1 for almost all .
We also remark that the set of functions of the form , where , with (3.9) and (3.10) respectively, is a generating set of
[TABLE]
Hence Proposition 4.1 holds for functions in as well (see details in [12]). Define
[TABLE]
The characteristic function is contained in . Let be given. Take continuous functions , depending on , and such that
[TABLE]
From (4.2), (3.2) and (4.4), for , and any , there is such that if ,
[TABLE]
for almost every . By the definition of and rescaling if necessary, we also obtain that
[TABLE]
Combining (4.6) and (4.7) with (4.5), if we regard as the characteristic function of ,
[TABLE]
Since
[TABLE]
the lemma follows from Proposition 4.2 and the classical argument of geometric series, if we obtain the following: as , the summation over all with is
[TABLE]
For this, by rescaling if necessary, let us assume that Corollary 3.6 holds for any . Denote the set by , where
[TABLE]
Then for , by Corollary 3.6, there is a constant such that
[TABLE]
where . Here for and for . Hence the left hand side of (4.8) is . If , since
[TABLE]
it is obviously . ∎
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