This paper proves the entire nature of adjoint L-functions for cuspidal representations of GL(3) and GL(4) over any global field, including twisted cases, advancing understanding of their analytic properties.
Contribution
It establishes the entireness of complete adjoint L-functions for GL(3) and GL(4), extending previous results to all cuspidal representations over arbitrary global fields.
Findings
01
Proves entireness of adjoint L-functions for GL(3) and GL(4)
02
Includes twisted cases in the analysis
03
Applies to any cuspidal representation over global fields
Abstract
We show entireness of complete adjoint L-functions associated to \textbf{any} cuspidal representations of \GL(3) or \GL(4) over an arbitrary global field. Twisted cases are also investigated.
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Taxonomy
TopicsAdvanced Algebra and Geometry · Analytic Number Theory Research · Finite Group Theory Research
We show entireness of complete adjoint L-functions associated to any unitary cuspidal representations of GL(3) or GL(4) over an arbitrary global field. Twisted cases are also investigated.
It is conjectured that for any L-series L(s) in Selberg class, normalized to have functonal equation relating s to 1−s, if L(s) has a pole of order r at s=1, then L(s)=ζ(s)r⋅L1(s), with L1(s) being holomorphic. This folk conjecture is wide open. For L(s) attached to motivic L-functions, this is implied by Tate; while for L(s) automorphic, Langlands Program implies it. In fact, every L(s) of Selberg type is conjectured to be (isobaric) automorphic on GL(n). In this paper, we consider one of the most fundamental cases, i.e., when L(s) is a Rankin-Selberg convolution with a simple pole at s=1.
Let F be a global field, and π be any unitary cuspidal representation of GL(n,AF). Let π~ be the contragredient of π. Then one has the complete Rankin-Selberg L-function Λ(s,π×π~), which has quite similar analytic properties as the complete Dedekind zeta function ΛF(s) associated to F: they have simple poles at s=0,1; and are both holomorphic elsewhere. Hence the ratio
[TABLE]
is meromorphic and is regular at s=1. Conventionally Λ(s,π;Ad) is called complete adjoint L-function for π. One basic conjecture is
Conjecture 1**.**
Let notation be as before. Then the complete adjoint L-function Λ(s,π,Ad) admits an analytic continuation to the whole complex plane.
Note that the adjoint L-function defined by (1) is actually equal to the Langlands L-function associated to the adjoint action of the dual group LGL(n;C) on the complex Lie algebra sl(n,C) of SL(n). Then according to Langlands Program, Conjecture 1 should hold. On the other hand, to study Langlands functoriality conjecture, it is important to obtain analytic continuation of completeL-functions, rather than their finite parts.
The first breakthrough was made for classical holomorphic cusp forms by Shimura [Shi75] and independently by Zagier [Zag77]; Shimura’s approach was generalized by Gelbart-Jacquet [GJ78] to the adelic setting, while Zagier’s method was further developed by Jacquet-Zagier [JZ87] in terms of representation language. Furthermore, Jacquet and Zagier proposed an auxiliary speculation that Conjecture 1 might be a consequence of Dedekind Conjecture, which asserts that the ratio ΛE(s)/ΛF(s) is entire for any number field extension E/F. Note that ΛE(s)/ΛF(s) can be written as a product of Artin L-functions, then Dedekind Conjecture is a consequence of Artin’s holomorphy conjecture. Flicker [Fli92] gave an argument suggesting that Dedekind Conjecture implies certain cases of Conjecture 1 for general n, under some local conditions on π. In [Yan19], we proved the converse direction: Conjecture 1 implies Dedekind Conjecture.
Another approach to attack Conjecture 1 for small rank n (e.g., n=3) is based on an integral representation, which was pioneered by Ginzburg [Gin91], and a method of ruling out poles which was pioneered by Ginzburg-Jiang [GJ00]. Typically this method helps continue partial adjoint L-function to some right half plane. See [HZ18] on GL(3) case for instance.
1.2. Statement of the Main Results
In general, Conjecture 1 remains wide open. It was not even known for general cuspidal representation of GL(3). In this paper, we show Conjecture 1 holds for n≤4. In fact, we can handle the twist case as well: let
[TABLE]
be the twist adjoint L-function, where τ be a character on F×\AF×. We have
Theorem A**.**
Let notation be as before. Let n≤4. Then the complete L-function Λ(s,π,Ad⊗τ) is entire, unless τ=1 and π⊗τ≃π, in which case Λ(s,π,Ad⊗τ) is meromorphic with only simple poles at s=0,1. In particular, Conjecture 1 holds for any cuspidal representation π when n≤4.
Then a computation using local Langlands correspondence leads to
Corollary 3**.**
Let notation be as before. Let n≤4. Then the finite L-function L(s,π,Ad⊗τ)=L(s,π⊗τ×π~)/L(s,τ) is entire, unless τ=1 and π⊗τ≃π, in which case L(s,π,Ad⊗τ) is meromorphic with only possible simple poles at s=0,1. In particular, the adjoint L-function L(s,π,Ad)=L(s,π×π~)/ζF(s) is entire.
Remark*.*
If F is a function field, by using the cohomology of stacks of shtukas and the Arthur-Selberg trace formula, L. Lafforgue showed the Langlands correspondence of cuspidal representations π of GLn(AF) to Galois representations ρ (see [Laf02]). Then Theorem A follows from the identity Λ(s,π,Ad⊗τ)=Λ(s,Adρ⊗τ) and analytic properties of Λ(s,Adρ⊗τ), which is known well (see [Wei74]). Hence we shall focus on the case that F is a number field, where such a correspondence is not available yet.
Remark*.*
If we admit Piatetski-Shapiro’s strong conjecture on converse theorem (e.g. see Chap. 10 in [Cog04]), Theorem A would imply that for any cuspidal representation π of GL(n,AF), there exists an adjoint lifting Ad(π), which is a representation of GL(n2−1,AF), in the sense of [GJ78]. Hence, in principle, Theorem A will play a role in Langlands functoriality in this case.
1.3. Idea of Proofs and Plan of This Paper
Our method is introduced in [Yan19], which is a generalization of [JZ87] to higher rank case. Roughly speaking, we prove an identity of the form
[TABLE]
where L-S means Langlands-Shahidi and R-S refers to Rankin-Selberg for non-discrete representations, and sums above are typically infinite. We then show the convergence of sums and meromorphic continuation of the above mentioned L-functions and cancellation of their poles. In conjunction with certain spectral analysis and computing global root number, we eventually prove Theorem A.
Let G=GL(n),n≤4. We consider a smooth function φ:G(AF)→C which is left and right K-finite, transforms by a unitary character ω of ZG(AF), and has compact support modulo ZG(AF). Then φ defines an integral operator
[TABLE]
on the space L2(G(F)\G(AF),ω−1) of functions on G(F)\G(AF) which transform under ZG(AF) by w−1 and are square integrable on G(F)ZG(AF)\G(AF). This operator can clearly be represented by the kernel function
[TABLE]
It is well known that L2(G(F)\G(AF),ω−1) decomposes into the direct sums of the space L02(G(F)\G(AF),ω−1) of cusp forms and spaces LEis2(G(F)\G(AF),ω−1) and LRes2(G(F)\G(AF),ω−1) defined using Eisenstein series and residues of Eisenstein series respectively. Then K splits up as: K=K0+KEis+KRes. Selberg trace formula gives an expression for the trace of the operator R(φ) restricted to the discrete spectrum, and this is given by
[TABLE]
We denote by S(AFn) the space of Schwartz-Bruhat functions on the vector space AFn and by S0(AFn) the subspace spanned by products Φ=∏vΦv whose components at real and complex places have the form
[TABLE]
where Fv≃R, and Q(xv,1,xv,2,⋯,xv,n)∈C[xv,1,xv,2,⋯,xv,n]; and
[TABLE]
where Fv≃C and Q(xv,1,xˉv,1,xv,2,xˉv,2,⋯,xv,n,xˉv,n) is a polynomial in the ring C[xv,1,xˉv,1,xv,2,xˉv,2,⋯,xv,n,xˉv,n].
Denote by ΞF the set of characters on F×\AF× which are trivial on R+×. Let Φ∈S0(AFn) and τ∈ΞF. Let η=(0,⋯,0,1)∈Fn. Set
[TABLE]
which is a Tate integral (up to holomorphic factors) for Λ(ns,x.Φ,τn). It converges absolutely uniformly in compact subsets of Re(s)>1/n. Since the mirabolic subgroup P0 is the stabilizer of η. Let P=P0ZG be the full (n−1,1) parabolic subgroup of G, then f(x,s)∈IndP(AF)G(AF)(δPs−1/2τ−n), where δP is the modulus character for the parabolic P. Then we can define the Eisenstein series
[TABLE]
which converges absolutely for Re(s)>1. Also, we define the integral:
[TABLE]
If there is no confusion in the context, we will alway write I(s,τ) (resp. f(x,s)) instead of Iφ(s,τ) (resp. f(x,Φ,τ;s)) for simplicity.
In [Yan19] (see Theorem A), we proved the expansion of I0(s,τ)=I0φ(s,τ):
[TABLE]
and investigated analytic behaviors of IGeo,Reg(s,τ),I∞,Reg(s,τ) and Iχ(s,τ,λ). Nevertheless, we still need to study the delicate geometric term ISing(s,τ) and prove the sum over χ in the spectral side admits a meromorphic continuation to some domain containing Re(s)≥1/2. This is the goal of this paper. As a consequence, we will deduce Theorem A.
By Proposition in Section 3.3 of [JZ87], Theorem A will follow if I0(s,τ)⋅Λ(s,τ)−1,Re(s)>1, admits a holomorphic continuation outside s=1. On the other hand, by Theorem D and Theorem E in [Yan19], we see Λ(s,τ)−1⋅IGeo,Reg(s,τ) and Λ(s,τ)−1⋅I∞,Reg(s,τ) admits a meromorphic continuation to the half plane Re(s)>1/3, holomorphic when s∈/{1,1/2}, and has a possible simple pole at s=1/2 if τ2=1, namely, τ is either trivial or has order 2. Therefore, according to decomposition (4), it suffices to show Λ(s,τ)−1⋅ISing(s,τ) and Λ(s,τ)−1⋅∑χ∫(iR)n−1Iχ(s,τ,λ)dλ admit meromorphic continuation to the whole s-plane, and the poles of all these mentioned functions cancel.
In Section 2, we study ISing(s,τ), proving Theorem B for G=GL(3) and GL(4) separately. In fact, if we further decompose the distributions by Bruhat decomposition, it is easy to see that many cells give no contribution. However, there are some cells such that the corresponding distributions diverge. Such problematic cells will be gathered together and the distribution I∞Mix(s,τ) from (finite) linear combination of these cells will be shown vanishing via Poisson summation and Fourier expansion of certain orbital integrals (see Proposition 14). Moreover, we obtain analytic behaviors of surviving (convergent) parts, they either contribute products of degree 1 L-functions, or may be reduced to Jacquet-Zagier’s work [JZ87] on GL(2) (e.g., see Proposition 11, Proposition 18 and Proposition 19).
In Section 3, we study I∞(1)(s,τ)=∑χ∫(iR)n−1Iχ(s,τ,λ)dλ, obtaining meromorphic continuation of it. When τ=1, the residue of I∞(1)(s,τ) at s=1 should give the weighted character distribution in Arthur-Selberg trace formula. We call I∞(1)(s,τ) the generic character distribution for G. In [Yan19], we obtained meromorphic continuation of ∫(iR)n−1Iχ(s,τ,λ)dλ, which is related to Rankin-Selberg convolution for non-cuspidal representations. Thus, we can write I∞(1)(s,τ) as an infinite sum of meromorphic functions, yet each individual may have poles. Then the next step is to analyze these possible poles and show that they do cancel with each other (see Theorem C). However, by this approach we can only rule out all potential poles of I0(s,τ)⋅Λ(s,τ)−1 except for a possible simple pole at s=1/2 when τ is quadratic.
In Section 4, we will prove Theorem A. In fact, Theorem C in Section 3 will eventually imply the that Λ(s,π,Ad⊗τ) admits a meromorphic continuation with at most a simple pole at s=1/2. To remedy it, we prove the root number of Λ(s,π,Ad⊗τ) is always 1 in this case (see Proposition 25). This would exclude the possibility of existence of a simple pole at s=1/2. Now Theorem A follows.
Acknowledgements
I am very grateful to my advisor Dinakar Ramakrishnan for instructive discussions and helpful comments. I would like to thank Ashay Burungale, Li Cai, Hervé Jacquet, Dihua Jiang, Simon Marshall, Kimball Martin, Yiannis Sakellaridis, Chen Wan and Xinwen Zhu for their precise comments and useful suggestions. Part of this paper was revised during my visit to École polytechnique fédérale de Lausanne in Switzerland and I would like to thank their hospitality.
2. Contributions from Geometric Side
2.1. Basic Notation and Singular Orbital Distributions
Fix an integer n≥2. The maximal unipotent subgroup of G(AF), denoted by N(AF), is defined to be the set of all n×n upper triangular matrices in G(AF) with ones on the diagonal and arbitrary entries above the diagonal. Let ψF/Q(⋅)=e2πiTrF/Q(⋅) be the standard additive character, then we can define a character θ:N(AF)→C× by
[TABLE]
Let Rk be the standard parabolic subgroup of G of type (k,n−k) consisting of matrices whose GL(n−k) part is upper triangular unipotent. Let Vk be the unipotent subgroup of the standard parabolic subgroup of type (k−1,1,n−k). Denote by Vk′=diag(Ik,Nn−k). For an algebraic group H over F, we will use the notation [H] to refer H(F)\H(AF) for simplicity.
Let Vk be the unipotent subgroup of the standard parabolic subgroup of GL(n) of type (k,n−k). Let Vk′=Vk\Vk−1. Let Nk=diag(Ik−1,N2,In−k−1), the unipotent subgroup corresponding to the root wk,1≤k≤n−1. For an algebraic group H, sometimes we will write H for its F-points H(F) for simplicity. Also, for sets A and B, denote by AB the set {b−1ab:a∈A,b∈B}.
2.1.1. Fourier Expansion of Mirabolic Orbital Functions
Let h be a Schwartz function on G(AF). Let S be a subset of G(F). Let
[TABLE]
where SP0(F) is the set consisting of p−1γp, for all γ∈S and p∈P0(F). We call Oh(x,y) a mirabolic orbital function on G(AF)×G(AF) associated to h and S.
Proposition 4**.**
Let notation be as before. Then
[TABLE]
if the right hand side converges absolutely and locally uniformly.
Proposition 4 will play a role in the crucial Proposition 14 (see Sec. 2.3). Since the proof of (5) is essentially the same as Prop. 17 in [Yan19], we omit the proof here.
2.1.2. The Singular Orbital Distribution
Denote by S=⋃k=1n−1(ZG(F)\Qk(F))P0(F). Following the approach in [Yan19], we will treat I(s) via the decomposition
[TABLE]
where C runs through all nontrivial conjugacy classes in G(F)/ZG(F) and
[TABLE]
and for simplicity we denote by K∞(x,y)=KEis(x,y)+KRes(x,y). Then substitute Fourier expansion of K∞(x,y) (e.g. Prop. 17 in loc. cit.) into (6) to obtain
[TABLE]
where the sum over k indicates the Fourier expansion of K∞(x,y):
[TABLE]
We can further decompose K∞(n)(x,y)=K∞,Reg(x,y)+K∞,Sing(x,y), where
[TABLE]
Let XG=ZG(AF)P0(F)\G(AF). By the above expansion (7), we then obtain
[TABLE]
where IGeo,Reg(s,τ),I∞,Reg(s,τ) and I∞(1)(s,τ) are defined by integrating the kernel functions KGeo,Reg(x,x),K∞,Reg(x,x) and K∞(1)(x,x) against f(x,s) over XG, respectively; and the distribution ISing(s,τ) is defined by
[TABLE]
In fact, the integral with respect to each term in the bracket will diverge, while the linear combination KGeo,Sing(x,x)−K∞,Sing(x,x)−∑k=2n−1K∞(k)(x,x) will make the divergent parts cancel. Hence we will call ISing(s,τ) singular orbital distribution for G.
In loc. cit. we investigate analytic behaviors of IGeo,Reg(s,τ),I∞,Reg(s,τ) and (partially) I∞(1)(s,τ), circumventing ISing(s,τ) by a choice of test functions. In this section, we shall use general test functions to prove some basic properties of ISing(s,τ), and conclude the following result:
Theorem B**.**
Let notation be as before. Let n≤4. Then ISing(s,τ) admits a meromorphic continuation to the whole s-plane. Moreover, the function ISing(s,τ)/Λ(s,τ) is holomorphic in the right half plane Re(s)>0 if s∈/{1,1/2,1/3,⋯,1/n}, and ISing(s,τ)⋅Λ(s,τ)−1 may have at most simple poles when s∈{1/2,1/3,⋯,1/n}.
Remark*.*
To deal with general GL(n), one of the initial steps is to classify the relevant orbital integrals of Fourier type for all 2≤k≤n. The classification of k=1 case, i.e., Kloosterman integrals, can also be found in [BFG86] or [Jac03]. For lower rank, e.g., n≤4, we can do this by brute force.
The proof of Theorem B follows readily by gathering results in Sec. 2.2 and Sec. 2.3 below.
2.2. Singular Expansion for GL(3)
Let notation be as before. Recall that
[TABLE]
To prove Theorem B, we need to investigate KSing(x,x)=KGeo,Sing(x,x)−K∞,Sing(3)(x,x) and K∞(2)(x,x). From the definition of KGeo,Sing(x,x) and K∞,Sing(3)(x,x), we need a description of G:
Lemma 6**.**
Let notation be as before. Then we have
[TABLE]
Moreover, any γ∈G−P0(F) can be written uniquely as
[TABLE]
where p∈B0(F)\P0(F),b∈B0(F), and u∈N2(F).
Since Lemma 6 is a straightforward computation using Bruhat decomposition, we omit the proof. However, we will proved a detailed proof to Lemma 7 (see Sec. 2.3), which is a higher rank version of Lemma 6.
Let A1(F)=(B0w2N2)B0\P0, and A2(F)=P0. For 1≤i≤2, we denote by
[TABLE]
Then, KSing(x,y)=KSing,1(x,y)+KSing,2(x,y), where KSing,i(x,y)=KGeo,Sing,i(x,y)−K∞,Sing,i(3)(x,y),1≤i≤2. On the other hand, by Bruhat decomposition, K∞(2)(x,x)=∑i=15K∞,i(2)(x,x), where
[TABLE]
with B1(F)=B0(F)w2N2(F),B2(F)=P0(F),B3(F)=B0(F)w1w2w1N(F),B4(F)=B0(F)w1w2N12(F), and B5(F)=B0(F)w2w1N21(F).
Denote by KSing,2(x,x)=KGeo,Sing,2(x,y)−K∞,Sing,2(3)(x,y)−K∞,2(2)(x,x). Then one can apply Proposition 4 to KGeo,Sing,2(x,y), to deduce
[TABLE]
Let ISing,2(s)=∫ZG(AF)P0(F)\G(AF)KSing,2(x,x)⋅f(x,s)dx. Then by (11),
[TABLE]
Using Bruhat decomposition to write P0(F)=B0(F)⊔B0(F)w1N1(F), then
[TABLE]
since the contribution from γ∈B0(F)w1N1(F) vanishes. Now we can apply Iwasawa decomposition G(AF)=N(AF)T(AF)K into (12) to obtain
[TABLE]
Then by Tate’s thesis, we conclude that ISing,2(s) is an integral representation for Λ(s,τ)Λ(2s,τ2)Λ(3s,τ3). Hence ISing,2(s) converges absolutely when Re(s)>1, and it has the analytic property
[TABLE]
As a consequence, ISing,2(s) admits a meromorphic continuation to s-plane, with possible poles (which are simple if exist) at s∈{1,1/2,1/3}.
By a simple changing of variables, we see
[TABLE]
So we have to deal with the rest contribution from K∞(2)(x,x), namely,
[TABLE]
where i∈{1,3}. We compute I∞,3(2)(s) first:
[TABLE]
Let w=w1w2w1. Again, apply Iwasawa decomposition to see
[TABLE]
Then by Tate’s thesis and intertwining operator theory, we conclude that I∞,3(2)(s) is an integral representation for Λ(s,τ)Λ(s+1,τ)Λ(3s,τ3)/Λ(s+2,τ). Hence I∞,3(2)(s) converges absolutely when Re(s)>1, and it has the analytic property
[TABLE]
We claim the term I∞,1(2)(s) will be canceled by contribution from some part of KSing,1(x,x). This will be presented in the following computation. Denote by
[TABLE]
Then KSing,1(2)(x;y) is well defined function with respect to y on B0(F)\B0(AF)⊂P02(F)\G2(AF), where G2=diag(GL(2),1), and P2 is the (only) standard parabolic subgroup of G2; and P02 is the mirabolic subgroup of P2. Hence, we can apply Fourier expansion to KSing,1(2)(x;y) and set y=I3 to obtain:
[TABLE]
where
[TABLE]
To deal with KSing,1(2,1)(x), we will apply Poisson summation: write γ=b0w2n2∈B0(F)w2N2(F), where b0∈B0(F) and n2∈N2(F). Noting N2(F)≃F, we can apply Poisson summation to see KSing,1(2,1)(x,x)=KSing,1,0(2,1)(x,x)+KSing,1,=0(2,1)(x,x), where the constant term KSing,1,0(2,1)(x,x) is equal to
[TABLE]
and KSing,1,=0(2,1)(x,x), the contribution from non-constant terms, is equal to
[TABLE]
By a change of variable, we see KSing,1,=0(2,1)(x,x) can be rewritten as
Integrating (18) over [NP]=NP(F)\NP(AF) to see
[TABLE]
Also, substituting the expression of KSing,1,=0(2,1)(x,x) we then obtain:
[TABLE]
Hence, by (13), (16), (19), (20) and (8), we only need to consider the contribution from K∞,1(2)(x,x),KSing,1,=0(2,1)(x,x) and KSing,1(1,1)(x,x). In fact, a straightforward computation shows that the contribution from KSing,1,=0(2,1)(x,x) cancels that from K∞,1(2)(x,x). Therefore, we only need to compute the contribution from KSing,1(1,1)(x,x).
To deal with KSing,1(1,1)(x,x), we still need to apply Poisson summation, which implies that KSing,1(1,1)(x,x)=KSing,1,0(1,1)(x,x)+KSing,1,=0(1,1)(x,x), where the constant term KSing,1,0(1,1)(x,x) is equal to
[TABLE]
and KSing,1,=0(1,1)(x,x) the contribution from non-constant terms, is equal to
[TABLE]
By a change of variable, we see KSing,1,=0(1,1)(x,x) can be rewritten as
[TABLE]
As before, we can form the distributions respectively:
[TABLE]
Let t0=diag(t1,t2,1)∈B0(F). Let
[TABLE]
Then h(t0) is well defined. Let v0=1a1b1, where a=−t1b. Note that
[TABLE]
namely, h(t0)=θ((t1−1−t1t2−1)a)h(t0) for any a∈AF. Hence h(t0) is nonvanishing unless t2=t12. Therefore, we can replace KSing,1,0(1,1)(s) with
[TABLE]
where B0∗(F) consists of elements diag(t,t2,1)modZG(F),t∈F×. Then
[TABLE]
Now we use Iawasawa decomposition to obtain
[TABLE]
Then by Tate’s thesis, we conclude that ISing,1,0(1,1)(s) can be written as
[TABLE]
where Qφ(t1,s) is entire with respect to s and has compact support as function of t1. Hence ISing,1,0(1,1)(s) converges absolutely when Re(s)>1, and it has the analytic property
[TABLE]
Let X=AF××AF×. Likewise, we have
[TABLE]
Likewise, t1 actually runs over a compact set, by Tate’s thesis, we conclude that ISing,1,=0(1,1)(s) is an integral representation for Λ(s,τ)Λ(3s,τ3). Hence ISing,1,=0(1,1)(s) converges absolutely when Re(s)>1, and it has the analytic property
[TABLE]
Now we put the above formulas together to see
[TABLE]
By (13), (16), (21) and (22), we then conclude that ISing(s) converges absolutely when Re(s)>1; admits a meromorphic continuation to the whole s-plane; moreover, ISing(s)⋅Λ(s,τ)−1 admits a meromorphic continuation to Re(s)>1/3, with possible simple poles at s∈{1,1/2}, proving Theorem B.
2.3. Singular Expansion for GL(4)
To study ISing(s), we need to investigate KSing(x,y):=KGeo,Sing(x,y)−K∞,Sing(4)(x,y) and each K∞(k)(x,y),2≤k≤3. Hence, we first need a similar result as Lemma 6 to describe the P(F)-conjugacy classes of
[TABLE]
in terms of B(F)\P(F). Let S be the standard parabolic subgroup of type (2,1,1). Denote by S0(F)=ZG(F)\S(F). First, we consider the conjugation by S(F)\P(F).
Lemma 7**.**
Let notation be as before. Denote by G1=(Bw3N⊔Bw1w3N⊔Bw2w3N)B(F)\S(F). Then
[TABLE]
Moreover, Bw3N⊔Bw1w3N⊔Bw2w3N forms a set of representatives of B(F)\P(F)-conjugacy classes of Q1(F)∪Q2(F)−P(F).
Proof.
By Bruhat decomposition, we see
[TABLE]
Since (Bw3w2N)w2⊆Bw2w3w2N⊔Bw2w3N, the B(F)\P(F) conjugacy class of Bw3w2N is contained in that of Bw2w3w2N⊔Bw2w3N. Let γ∈Bw2w3w2N. Write γ into its Bruhat normal form:
[TABLE]
If a+b=0, then γ∈(Bw2w3N)w2N2; if a+b=0, then γ∈(Bw3N)w2N2. Hence (Bw2w3w2N)B(F)\P(F)⊆(Bw3N)B(F)\P(F)∪(Bw2w3N)B(F)\P(F). Thus, G−P(F)=(Bw3N⊔Bw1w3N⊔Bw2w3N)B(F)\P(F). Hence, (24) follows. Moreover, we have:
Claim 8**.**
The set Bw3N3⊔Bw1w3N13⊔Bw2w3N23 forms representatives of (Bw3N⊔Bw1w3N⊔Bw2w3N)S(F)\P(F).
Let w,sα be Weyl elements and the length l(sα)=1. Let C(w) and C(sα) be the Bruhat cells, respectively. Recall we have proved in [Yan19] that
[TABLE]
where C(w)sα:=C(sα)C(w)C(sα). Then by (26) and (25) we see that
[TABLE]
Thus, by the disjointness of different Bruhat cells, the only possible intersection of orbits (Bw3N)S(F)\P(F),(Bw1w3N)S(F)\P(F) and (Bw2w3N)S(F)\P(F) must lie in Bw1w2w3w2w1N. Suppose (Bw3N)S(F)\P(F)∩(Bw2w3N)S(F)\P(F) is nonempty. Then there exists some b∈B(F,)v3∈N3(F) and u21∈N21(F) such that
[TABLE]
However, w2w1u21w1w2∈B(F)⊔B(F)w2w1w2N(F)⊔B(F)w2N(F). Denote by γ=w2w1u21−1w1w2bw3v3w2w1u21w1w2. Then applying (26) again we obtain that
[TABLE]
Nevertheless, the Bruhat cells on the right hand side of (28) are different from B(F)w2w3N23(F), hence there is no intersection with B(F)w2w3N23(F), namely, (27) cannot hold. A contradiction!
Thus the orbits (Bw3N)S(F)\P(F),(Bw1w3N)S(F)\P(F) and (Bw2w3N)S(F)\P(F) do not have any intersection. Next we need to show these orbits are transversal. We verify them separately as follows:
(i).
Assume there are b1w3u1,b2w3v1∈B(F)w3N3(F), and λ1,λ2∈B(F)\P(F), such that λ1−1b1w3u1λ1=λ2−1b2w3v1λ2. Then by disjointness of different Bruhat cells, λ1 and λ2 must lie in the same connected component given on the right hand side of (25). Assume further λ1=λ2, then λ1λ2−1∈B(F)w2N(F)⊔B(F)w2w1w2N(F). Then λ1−1b1w3u1λ1 can not equal λ2−1b2w3v1λ2. A contradiction! Thus the conjugation of B(F)\P(F) on B(F)w3N3(F) is transversal.
2. (ii).
Assume there are b1w1w3u1,b2w1w3v1∈B(F)w1w3N3(F), and λ1,λ2∈B(F)\P(F), such that λ1−1b1w1w3u1λ1=λ2−1b2w1w3v1λ2. Then by disjointness of different Bruhat cells, λ1 and λ2 must lie in the same connected component given on the right hand side of (25). Assume further λ1=λ2, then λ1λ2−1∈B(F)w2N(F)⊔B(F)w2w1w2N(F). Then by (26), λ1−1b1w1w3u1λ1 can not equal λ2−1b2w1w3v1λ2. A contradiction! Thus the conjugation of B(F)\P(F) on B(F)w1w3N3(F) is transversal.
3. (iii).
Assume there are b1w2w3u1,b2w2w3v1∈B(F)w1w3N3(F), and λ1,λ2∈B(F)\P(F), such that λ1−1b1w2w3u1λ1=λ2−1b2w2w3v1λ2. Likewise, λ1 and λ2 must lie in the same connected component given on the right hand side of (25). Assume further λ1=λ2, then λ1λ2−1∈B(F)w2N(F)⊔B(F)w2w1w2N(F). Then by (26), λ1−1b1w1w3u1λ1=λ2−1b2w1w3v1λ2. A contradiction! Thus the conjugation of B(F)\P(F) on B(F)w1w3N3(F) is transversal.
Therefore, the set Bw3N3⊔Bw1w3N13⊔Bw2w3N23 forms representatives of (Bw3N⊔Bw1w3N⊔Bw2w3N)S(F)\P(F).
∎
where KSing,0(x,y)=KGeo,Sing,0(x,y)−K∞,Sing,0(4)(x,y), and
[TABLE]
One then has to handle terms on the right hand side of the above identity separately. We deal with KSing,0(x,y) first. Denote by
[TABLE]
where 2≤k≤3. Denote by K∞,0(1)(x,x)=KSing,0(x,x)−K∞,0(3)(x,x)−K∞,0(2)(x,x). Hence we can apply Proposition 4 to get
[TABLE]
2.3.1. Contribution from K∞,0(1)(x,x)
Now we defined the distribution I∞,0(1)(s) correspondingly, namely,
[TABLE]
Using Bruhat decomposition P0(F)=B0(F)⊔B0(F)w1N(F)⊔B0(F)w2N(F)⊔B0(F)w2w1N(F)⊔B0(F)w1w2N(F)⊔B0(F)w1w2w1N(F) to further expand the function K∞,0(1)(x,x), then substituting them into (30), we then obtain
[TABLE]
Now we can apply Iwasawa decomposition G(AF)=N(AF)T(AF)K into (31) to obtain
[TABLE]
where dn=dadbdcdedfdg. Then by Tate’s thesis, we conclude that I∞,0(1)(s) is an integral representation for Λ(s,τ)Λ(2s,τ2)Λ(3s,τ3)Λ(4s,τ4). Hence I∞,0(1)(s) converges absolutely when Re(s)>1, and it has the analytic property
[TABLE]
As a consequence, I∞,0(1)(s) admits a meromorphic continuation to s-plane, with possible poles (which are simple if exist) at s∈{1,1/2,1/3,1/4}.
2.3.2. Contributions from K∞(2)(x,x)
For a Weyl element w, denote by C(w) the Bruhat cell B(F)wN(F). Then
[TABLE]
Based on this decomposition, we can write K∞(2)(x,y)=∑i=018K∞,i(2)(x,y), where
[TABLE]
where B0(2)(F)=P0(F), and ⊔i=118Bi(2)(F) consists of the above 18 Bruhat cells modulo ZG(F). Explicitly, let B1(2)(F)=C(w2w3)⊔C(w3w2)⊔C(w2w3w2),B2(2)(F)=C(w1w2w3w2w1), and
B3(2)(F)=C(w1w2w3w1w2w1). Denote also by
[TABLE]
Then a straightforward computation shows that
[TABLE]
Thus, formally one has I∞(2)(s)=I∞,0(2)(s)+I∞,1(2)(s)+I∞,2(2)(s)+I∞,3(2)(s), where
[TABLE]
Proposition 10**.**
Let notation be as before. Then I∞,2(2)(s) admits a meromorphic continuation to the whole s-plane, and
[TABLE]
Proof.
For any γ∈B2(2)(F), we can write γ uniquely as γ=u1tu2, where u1∈N(F),t=diag(t1,t2,t3,1) and u2∈Nw1w2w3w2w1(F). Let I4=v∈N2(AF). Substituting (33) into (34) we then obtain, by writing X1=ZG(AF)R1(F)\G(AF), that I∞,2(2)(s)=∑t1,t2,t3I∞,2(2)(s;t1,t2,t3), where
[TABLE]
since I∞,2(2)(s) converges absolutely when Re(s)>1. Now a changing of variable x↦vx implies I∞,2(2)(s;t1,t2,t3)=θ((1−t3t2−1)v)I∞,2(2)(s;t1,t2,t3). Hence, we have I∞,2(2)(s;t1,t2,t3)=0 unless t2=t3. Therefore, using Iwasawa decomposition,
[TABLE]
where w=w1w2w3w2w1,dn=dadb⋯dgda′⋯dg′; and
[TABLE]
Since γ runs over a compact subset of AF×, we then conclude (10) from Tate’s thesis.
∎
Proposition 11**.**
Let notation be as before. Then I∞,3(2)(s) admits a meromorphic continuation to the whole s-plane, and
[TABLE]
where the sum over number fields E is finite, each QE(s,τ) is entire; and Q(s,τ) is entire.
Proof.
Let w=w1w2w3w1w2w1=w1w2, where w1=w1w2w3w2w1 Then
[TABLE]
Then we can apply Iwasawa decomposition to see
[TABLE]
where dn=dadb⋯dg⋅dhdl⋯dr;d×y=d×y1d×y2d×y3; and
[TABLE]
Then Proposition 11 follows from induction: the integral over y1 and k contributes the L-factor Λ(2s,τ2)Λ(4s,τ4); and y3 runs over a compact set, thus the integral over y3 contributes an entire function; the only thing left is the contribution from integration over y2, which can be reduced (by (36) and Fourier expansion of K(x,y)) to the geometric side of Jacquet-Zagier’s work [JZ87] in GL(2) case.
∎
However, neither I∞,0(2)(s) nor I∞,1(2)(s) converges for any s∈C. Since the contribution from K∞,0(2)(x,y) has been handled in (30), we only need to deal with the contribution from K∞,1(2)(x,y). In fact, we will see in the below, K∞,1(2)(x,x), in conjunction with some singular parts of K∞(3)(x,x), will be canceled by the singular part of KSing,2(x,x)=KGeo,Sing,2(x,x)−K∞,Sing,2(4)(x,x).
2.3.3. Contributions Related to KSing,1(x,x),KSing,2(x,x) and K∞(3)(x,x)
By Bruhat decomposition,
[TABLE]
On the other hand, one can verify that
[TABLE]
where NS is the unipotent subgroup of S, and X=Sw3Sw2S⊔Sw2Sw3S. Hence, we only need to consider the contribution from γ∈Sw3S⊔Sw2Sw3Sw2S. Let
[TABLE]
where δ runs through R2(F)\R3(F). Denote also by
[TABLE]
Then KSing,1(x;y) is a Schwartz function on S0(F)\R3(AF). Hence, we can apply Fourier expansion to KSing,1(x;y) and evaluate at y=I4 to obtain
[TABLE]
where we denote by T3=diag(I2,GL1,1), and
[TABLE]
Lemma 12**.**
Let notation be as before. Then the distribution
[TABLE]
converges absolutely when Re(s)>1. Moreover, ISing,1(2)(s) admits a meromorphic continuation to s∈C such that
[TABLE]
Proof.
This can be reduced to the treatment of ISing,1,0(1,1)(s) and ISing,1,=0(1,1)(s) in GL(3) case. In fact, a straightforward computation shows (38).
∎
Recall that we have the decomposition (37). In this subsection, we further decompose the set Sw2Sw3Sw2S:
Lemma 13**.**
Let notation be as before. Then Sw2Sw3Sw2S is equal to
[TABLE]
Moreover, the set Bw2w3w2N⊔Bw2w3w2w1⊔Bw2w1w3w2N⊔Bw2w1w3w2w1 consists of representatives under the conjugation of B(F)\S(F).
Proof.
Since S=B⊔Bw1N, we have Sw2Sw3Sw2S=Bw2w3w2N⊔Bw1w2w3w2N⊔Bw2w3w2w1⊔Bw1w2w3w2w1N⊔Bw2w1w3w2N⊔Bw2w1w3w2w1⊔Bw1w2w1w3w2N⊔Bw1w2w1w3w2w1N. Noting that B\S={1}⊔w1N1, by (26) we deduce that
[TABLE]
is contained in Sw2Sw3Sw2S. Hence, it is sufficient to show that
[TABLE]
is contained in (Bw2w3w2N⊔Bw2w3w2w1⊔Bw2w1w3w2N⊔Bw2w1w3w2w1)B\S.
(i).
Let γ∈Bw1w2w3w2N. Then one can write
[TABLE]
Let δ=w11−a1I2∈w1N1.Then δγδ−1∈Bw2w3w2w1N. Hence
[TABLE]
2. (ii).
Let γ∈Bw1w2w3w2w1N. Then one can write
[TABLE]
Let δ=w11−a1I2∈w1N1. If a+b=0, then δγδ−1∈Bw2w3w2N; if a+b=0, then δγδ−1∈Bw2w3w2w1N. In all, we have
[TABLE]
3. (iii).
Let γ∈Bw1w2w1w3w2N. Then one can write
[TABLE]
Let δ=w11−a1I2. Then δγδ−1∈Bw2w1w3w2w1N; namely,
[TABLE]
4. (iv).
Let γ∈Bw1w2w1w3w2w1N. Then one can write
[TABLE]
Let δ=w11−a1I2. If a+b=0, then δγδ−1∈Bw2w1w3w2N; if a+b=0, then δγδ−1∈Bw2w1w3w2w1N. In all, we have
[TABLE]
One then deduces from (40), (41), (42) and (43) that Sw2Sw3Sw2S is equal to (39). Also, by (26), supposing
[TABLE]
and γ1∈γ2B\S, then γ1 and γ2 must lie in the same Bruhat cell. However, by uniqueness of Bruhat normal form and (26), this cannot happen unless γ1=γ2. Hence, Lemma 13 follows.
∎
According to Lemma 13, we can set B1(F)=(Bw2w3w2N)B(F)\S(F),B2(F)=(Bw2w3w2w1N)B(F)\S(F),B3(F)=(Bw2w1w3w2N)B(F)\S(F), and let B4(F)=(Bw2w1w3w2w1N)B(F)\S(F). Then we obtain a refined decomposition K∞,2(3)(x,x)=K∞,2;1(3)(x,x)+K∞,2;2(3)(x,x)+K∞,2;3(3)(x,x)+K∞,2;4(3)(x,x), where
[TABLE]
where Bk,0(F)=ZG(F)\Bk,0(F), and 1≤k≤4. Let B2 be the group consisting of nonsingular 4×4 matrix of the form ∗∗∗∗∗1∗∗∗1. Then
[TABLE]
where B1,0∗(F)=B0w2w3w2N,B2,0∗(F)=B0w2w3w2w1N,B3,0∗(F)=B0w2w1w3w2N, and B4,0∗(F)=B0w2w1w3w2w1N.
In conjunction with the contribution from KGeo,Sing,2(x,y), we (formally) define
[TABLE]
where X=ZG(AF)P0(F)\G(AF). Then we have
Proposition 14**.**
Let notation be as before. Then ISingMix(s)=0.
Let Φ=B0w3N⊔B0w2w3N⊔B0w3w2N⊔B0w2w3w2N. Let Q be the standard parabolic subgroup of GL(4) of type (1,3). Denote by NQ the unipotent of Q. Let H be the standard parabolic subgroup of GL(4) of type (1,2,1). Set H0=ZG\H. Let
[TABLE]
Set ΔΦ(x;y)=ΔΦ(1)(x;y)−ΔΦ(2)(x;y), where for any set S,
[TABLE]
Lemma 15**.**
Let notation be as before. Then
[TABLE]
Proof.
For fixed x, the function ΔΦ(x;y) is a Schwartz function with respect to y∈H0(F)\Q(AF). Thus we can apply Proposition 4 to ΔΦ(x;y) and evaluate at y=I4 to obtain ΔΦ(x;I4)=Υ∞(2)(x)+Υ∞(3)(x)+Υ∞(4)(x).
Claim 16**.**
Let notation be as before. Then
[TABLE]
Since Claim 16 follows from the proof of Lemma 7, we thus omit the proof. Then by (45) we conclude that
[TABLE]
where Δ∗(k)(x;I4)=Δ(B0(F)w3N(F))B0(F)\H0(F)(k)(x;I4),1≤k≤2. Explicitly,
Considering the compatibility of Bruhat normal forms and the generic character, we have
[TABLE]
Then ISingMix(s)=0, as a consequence of Lemma 15.
∎
2.3.4. Contributions from K∞,2;k(3)
Let notation be as before. Let 2≤k≤4. Define the distribution by
[TABLE]
Write X=ZG(AF)B2(F)\G(AF). Then explicitly we have
[TABLE]
Proposition 17**.**
Let notation be as before. Then I∞,2;2(3)(s) admits a meromorphic continuation to the whole s-plane, and
[TABLE]
Proof.
Let w=w2w3w2w1. For any γ∈B2,0∗(F), we can write γ uniquely as γ=u1tu2, where u1∈N(F),t=diag(t1,t2,t3,1) and u2∈Nw(F). Note that
[TABLE]
Then
[TABLE]
where w=w1w2w3w2w1,dn=dadb⋯dgda′⋯dg′; and
[TABLE]
Since y2 and y1y2 runs over compact subsets of AF×,y1 runs over some compact subset as well. We then conclude (48) from Tate’s thesis.
∎
Proposition 18**.**
Let notation be as before. Then I∞,2;3(3)(s)⋅Λ(s,τ)−1 admits a holomorphic continuation when Re(s)>0 and s=1.
Proof.
Let X=ZG(AF)B2(F)\G(AF). By definition, we have
[TABLE]
Let w=w2w3w1w2. Then by changing of variables we then have
[TABLE]
where γ=u1wtu2, with t=diag(t1,t2,1,1)∈diag(F×\(F×)2,F×,1,1); and u1,u2∈N2(F)\N(F). Applying Iwasawa decomposition we then obtain
[TABLE]
where the first ellipsis represents the expression
[TABLE]
Then we rewrite (49) and apply a change of variables to see I∞,2;3(3)(s) becomes
[TABLE]
where
[TABLE]
From this expression, the analytic behavior of I∞,2;3(3)(s) can be detected via Jacquet-Zagier trace formula on GL(2). The contribution from a3 and t1 can be computed by the lemma in Sec. 2.4 of [JZ87], and can be further realized as a finite sum of intertwining operators; the contribution from a2 and t2 can be handles via Fourier expansion, the same as Proposition 11. As a consequence, I∞,2;3(3)(s) converges absolutely when Re(s)>1; and I∞,2;3(3)(s)⋅Λ(s,τ)−1 admits a meromorphic continuation when Re(s)>0, with the only possible pole at s=1.
∎
Proposition 19**.**
Let notation be as before. Then I∞,2;4(3)(s)⋅Λ(s,τ)−1 admits a meromorphic continuation to Re(s)>0, with no pole outside s=1.
Proof.
Let X=ZG(AF)B2(F)\G(AF). By definition, we have
[TABLE]
Let w=w2w3w1w2w1. Then by changing of variables we then have
[TABLE]
where γ=u1wtu2, with u1∈N2(F)\N(F),u2∈N(F), and t=diag(t1,t2,1,1)∈diag(F×\(F×)2,F×,1,1). Applying Iwasawa decomposition we then obtain
[TABLE]
where the first ellipsis represents the expression
[TABLE]
Then we rewrite (50) and apply a change of variables to see I∞,2;4(3)(s) becomes
[TABLE]
where
[TABLE]
From this expression, the analytic behavior of I∞,2;4(3)(s) can be deduced from Jacquet-Zagier trace formula on GL(2). Precisely, the contribution from a3 and t1 can be computed by the lemma in Sec. 2.4 of [JZ87], and eventually be realized as a finite sum of intertwining operators; the contribution from a2 and t2 can be handles via Fourier expansion, the same as Proposition 11. As a consequence, I∞,2;4(3)(s) converges absolutely when Re(s)>1; and I∞,2;4(3)(s)⋅Λ(s,τ)−1 admits a meromorphic continuation when Re(s)>0, with the only possible pole at s=1.
∎
3. Contributions from Spectral Side
In this section, we deal with the generic character distribution I∞(1)(s,τ). By Theorem G in [Yan19], when Re(s)>1,I∞(1)(s,τ) is equal to
[TABLE]
where YG=ZG(AF)N(AF)\G(AF),χ runs over proper cuspidal data, i.e., χ is not of the form {(G,π)}; and ϕ1,ϕ2 runs over an orthogonal basis BP,χ of the representation space determined by χ. The sum converges absolutely. Particularly, as a function of s,I∞(1)(s) is analytic when Re(s)>1. Moreover, when τk=1,1≤k≤n, then Theorem G in loc. cit. and functional equation give meromorphic continuation of I∞(1)(s) to the whole s-plane.
However, for general τ, e.g., τ=1, the continuation of I∞(1)(s) is rather involved, since the function (51) is singular at every point on the boundary Re(s)=1. To continue I∞(1)(s) meromorphically to the whole plane, we will follow Section 8 in loc. cit., taking advantage of zero-free regions of Rankin-Selberg convolutions and estimates from analytic number theory.
3.1. Notation and Zero-free Region
In this subsection, we introduce some notation used in Section 8 of [Yan19]. Let ΣF be the set of places on F. Recall that we fix the unitary character τ. Let Dτ be a standard (open) zero-free region of LF(s,τ) (e.g. ref. [Bru06]). We fix such a Dτ once for all. Let
[TABLE]
In Section 3.2, we will continue I∞(1)(s,τ) to the open set R(1/2;τ)−. Invoking (52) with functional equation we then obtain a meromorphic continuation of I∞(1)(s) to the whole complex plane.
Let G=GL(3) or GL(4). Let P be a standard parabolic subgroup of G of type (n1,n2,⋯,nr). Let XP be the subset of cuspidal data χ={(M,σ)} such that M=MP=diag(M1,M2,⋯,Mr), where Mi is ni by ni matrix, 1≤i≤r. We may write σ=(σ1,σ2,⋯,σr), where σi∈A0(Mi(F)\Mi(AF)). Let π be a representation induced from χ={(M,σ)}.
For any λ=(λ1,λ2,⋯,λr)∈iaP∗/iaG∗≃(iR)r−1, satisfying that λ1+λ2+⋯+λr=0, we let κ=(κ1,κ2,⋯,κr)∈Cr−1 be such that
[TABLE]
Then we have a bijection iaP∗/iaG∗1:1iaP∗/iaG∗,λ↦κ given by (53), which induces a change of coordinates with dλ=mPdκ, where mP is an absolute constant (the determinant of the transform (53)). So that we can write λ=λ(κ). Let
[TABLE]
where Λ(s,πλ⊗τ×π−λ) is the complete L-function, defined by ∏v∈ΣFLv(s,πλ,v⊗τv×π−λ,v); and Ψ(s,W1,W2;λ)=∫YGW1(x;λ)W2(x;λ)f(x,s)dxdλ is the Rankin-Selberg period (see Section 6 of [Yan19] for basic analytic properties).
Then we can write Rφ(s,λ;ϕ)=Rφ(s,κ;ϕ) and Λ(s,πλ⊗τ×π−λ)=Λ(s,πκ⊗τ×π−κ). Recall that if v∈ΣF,fin is a finite place such that πv is unramified and Φv=Φv∘ is the characteristic function of G(OF,v). Assume further that ϕ1,v=ϕ2,v=ϕv∘ be the unique G(OF,v)-fixed vector in the space of πv such that ϕv0(e)=1. Then Rv(s,W1,v,W2,v;λ)=Rv(s,W1,v,W2,v;κ) is equal to
[TABLE]
where κi,j=κi+⋯+κj−1. By the K-finiteness of φ, there exists a finite set Sφ,τ,Φ of nonarchimedean places such that for any π from some cuspidal datum χ∈XP,Rv(s,W1,v,W2,v;κ) is equal to the formula in (54). Then according to Proposition 43 and Proposition 50 in loc. cit., we see that, when Re(s)>0,Rv(s,W1,v,W2,v;κ) is independent of s for all but finitely many places v. Therefore, as a function of s,Rφ(s,κ;ϕ) is a finite product of holomorphic function in Re(s)>0; for any given s such that Re(s)>0, as a complex function of multiple variables with respect to κ,Rφ(s,κ;ϕ) has the property that Rφ(s,κ;ϕ)LS(κ,π,π) is holomorphic, where LS(κ,π,π) is denoted by the meromorphic function
[TABLE]
Hence Rφ(s,κ;ϕ) is holomorphic in some domain D if LS(κ,π,π) is nonvanishing in D. Now we are picking up such a zero-free region D explicitly.
Let 1≤m,m′≤n be two integers. Let σ∈A0(GLm(F)\GLm(AF)) and σ′∈A0(GLm′(F)\GLm′(AF)). Fix ϵ0>0. For any c′>0, let Dc′(σ,σ′) be
[TABLE]
if σ′≆σ; and let Dc′(σ,σ′) denote by the region
[TABLE]
if σ′≃σ. According to [Bru06] and the Appendix of [Lap13], there exists a constant cm,m′>0 depending only on m and m′, such that L(κ,σ×σ′) does not vanish in κ=(κ1,⋯,κr)∈Dcm,m′(σ,σ′)×⋯×Dcm,m′(σ,σ′). Let c=min1≤m,m′≤ncm,m′ and C(σ,σ′) be the boundary of Dc(σ,σ′). We may assume that c is small such that the curve C(σ,σ′) lies in the strip 1−1/(n+4)<Re(κj)<1,1≤j≤r. Fix such a c henceforth. Note that by our choice of c,L(κ,σ×σ′) is nonvanishing in Dc(σ,σ′)×⋯×Dc(σ,σ′) for any 1≤m,m′≤n. For v∈Sφ,τ,Φ, we have that
[TABLE]
for any κ such that each Re(κj)≥0,1≤j≤r. Let LS(κ,σ×σ′)=L(κ,σ×σ′)∏v∈Sφ,τ,ΦLv(κ,σv×σ′v)−1. Then LS(κ,σ×σ′) is nonvanishing in Dc(σ,σ′)×⋯×Dc(σ,σ′) for any 1≤m,m′≤n.
Let χ∈XP and π=IndP(AF)G(AF)(σ1,σ2,⋯,σr)∈χ. For any ϵ∈(0,1] we set
[TABLE]
Also, for ϵ=0, we set \mathcal{D}_{\chi}(\epsilon)=\big{\{}\kappa\in\mathbb{C}:\ \operatorname{Re}(\kappa)\geq 0\big{\}}. Then by the above discussion, as a function of κ,LS(κ,π,π) is nonzero in the region \mathcal{D}_{\chi}(\boldsymbol{\epsilon})=\big{\{}\boldsymbol{\kappa}=(\kappa_{1},\cdots,\kappa_{r})\in\mathbb{C}^{r}:\ \kappa_{l}\in\mathcal{D}_{\chi}(\epsilon_{l})\big{\}}, where ϵ=(ϵ1,⋯,ϵr)∈[0,1]r. We can write Dχ(ϵ) as a product space Dχ(ϵ)=∏l=1rDχ(ϵl), and let ∂Dχ(ϵl) be the boundary of Dχ(ϵl). Then when ϵl>0,∂Dχ(ϵl) has two connected components and one of which is exactly the imaginary axis. Let Cχ(ϵl) be the other component, which is a continuous curve, where 0≤ϵl≤1. When ϵl=0, let Cχ(ϵl) be the maginary axis. Set Cχ(ϵ)=Cχ(ϵ1)×⋯×Cχ(ϵr−1),0≤ϵl≤1,1≤l≤r−1.
Let ϵ=(ϵ1,⋯,ϵr−1)∈[0,1]r−1. Then by the above construction, Rφ(s,κ;ϕ) is holomorphic in Dχ(ϵ). Hence Rφ(s,κ;ϕ)Λ(s,πκ⊗τ×π−κ) is holomorphic in Dχ(ϵ). Moreover, LS(κ,π,π)=0 on Cχ(ϵ), for any ϵ=(ϵ1,⋯,ϵr−1)∈[0,1]r−1 and any cuspidal datum χ∈XP. Let Re(s)>1. For any ϕ∈BP,χ and ϵ=(ϵ1,⋯,ϵr−1)∈[0,1]r−1, let
[TABLE]
which is well defined because JP,χ(s;ϕ,Cχ(ϵ))=JP,χ(s;ϕ,Cχ(0)) by Cauchy integral formula. Therefore, according to Theorem F in loc. cit.,
[TABLE]
for any Re(s)>1,ϵ=(ϵ1,⋯,ϵr−1)∈[0,1]r−1.
Let ϵ=(ϵ1,⋯,ϵr−1)∈[0,1]r−1. For any β≥1/2, we denote by
[TABLE]
Let s∈R(1;χ,ϵ) and 1≤m≤r−1. Let jm,jm−1,⋯,j1 be m integers such that 1≤jm<⋯<j1≤r−1. Consider the distribution:
[TABLE]
where F(κ;s)=F(κ;s,P,χ):=Rφ(s,κ;ϕ)Λ(s,πκ⊗τ×π−κ). Then each Im,χ(s,τ) is meromorphic in R(1;χ,ϵ) with a possible pole at s=1.
Let n≤4. Let χ∈XP. Assume that the adjoint L-function L(s,σ,Ad⊗τ) is holomorphic inside the strip 0<Re(s)<1 for any cuspidal representation σ∈A0(GL(k,AF)), and any k≤n−1. Then according to Theorem H in loc. cit., for any 0≤m≤r−1, the function
[TABLE]
admits a meromorphic continuation to the area R(1/2;τ)−, with possible simple poles at s∈{1/2,2/3,⋯,(n−1)/n,1}, where R(1/2;τ)− is defined in (52). Moreover, for any 3≤k≤n, if LF((k−1)/k,τ)=0, then s=(k−1)/k is not a pole.
Recall that we need to investigate the analytic behavior of the function
[TABLE]
where the sum over standard parabolic subgroups P is finite while the sum over cuspidal data χ is infinite. According to Theorem F in loc. cit., Z∗(s,τ) converges absolutely and locally normally in the region Re(s)>1. Since each summand ∑ϕ∈BP,χIm,χ(s)⋅Λ(s,τ)−1 admits a meromorphic continuation to the region R(1/2;τ)−, with possible simple poles at s∈{1/2,2/3,⋯,(n−1)/n} and a pole of order at most 4 at s=1, we can consider (at least formally) the distribution
[TABLE]
where Im,χ(s) is the continuation of Im,χ(s,τ). Then we only need to show that (s−1/2)(s−2/3)(s−3/4)(s−1)4Z(s) converges absolutely and locally normally inside the domain R(1/2;τ)−.
Theorem C**.**
Let notation be as before. Let 0≤m≤r−1. Then Zm(s,τ) admits a meromorphic continuation to the domain R(1/2;τ)−, where it has possible poles at s=1/2 and s=1. Moreover, if s=1/2 is a pole, then it must be simple.
3.2. Generic Characters for G
Let v be a nonarchimedean place of F. Let P be a standard parabolic subgroup of G. Fix a Levi decomposition of P=MN with M containing the maximal splitting torus Gmn. Let σv be an irreducible admissible unitary representation of M(Fv) and fix λ∈aP∗(C)=aP∗⊗C. We shall use I(λ,σv) to denote the induced representation
[TABLE]
Since Fv is nonarchimedean, the space V(λ,σv) of I(λ,σv) consists of the space of locally constant functions from G(Fv) into the space H(σv) of σv, such that
[TABLE]
The group acts on V(λ,σv) via the right regular action. Define the Whittaker function for the representation I(λ,σv) as follows:
[TABLE]
Lemma 21**.**
Let notation be as above, then there exists a test function hv∈H(σv) such that for any λ∈aP∗(C), the Whittaker function
[TABLE]
Proof.
To construct such a hv, we start with the following auxiliary result:
Claim 22**.**
Let notation be as before, then there exists an hv∘∈H(σv) such that
[TABLE]
Let N− be the opposite of N, i.e., N−=w0Nw0−1. Then one may take arbitrarily two functions φ1∈Cc∞(P(Fv)) and φ1∈Cc∞(N−1(Fv)) to define
[TABLE]
Now we let hv (depending on φ1 and φ2) be the function
[TABLE]
Since exp⟨ρP,HM(m)⟩ is the modular character, for any m1∈M(Fv),n1∈N(Fv), one has d(m1nm1−1)=exp⟨ρP,HM(m1)⟩dn. Then by changing m to mm1−1 and n to nn1−1 we obtain that
[TABLE]
which implies that hv∈V(λ,σ). Now we have
[TABLE]
We will choose φ1 so that φ1(mn)σ(m−1)hv∘=φ1(mn)hv∘. Then we have
[TABLE]
where F(n−,m,n):=exp⟨−λ+ρP,HM(m)⟩Wv(hv∘;σv)φ1(mn)φ2(n−)θ(w0−1n−w0). Therefore, Wv(hv;λ,σv) is equal to the product of Wv(hv∘;σv) and
[TABLE]
One can take appropriate φ1 and φ2 to make the above integral nonzero constant independent of λ. Now Lemma 21 follows from Claim 22.
∎
Remark*.*
When IndM(Fv)N(Fv)G(Fv)σv⊗1 is unramified, we can simply take hv to be a spherical vector in H(σv). However, when IndM(Fv)N(Fv)G(Fv)σv⊗1 is ramified, one cannot take hv to be a new vector in H(σv) any more, since otherwise Wv(hv;λ,σv) would vanish identically.
Write πv for the representation IntM(Fv)N(Fv)G(Fv)σv⊗1. Let Φv∈S(Fvn), and h1,v,h2,v∈H(σv). Let s∈C such that Re(s)>1. Then we consider the local Rankin-Selberg integral Ψv(s;h1,v,h2,v,Φv) defined by
[TABLE]
where for 1≤j≤2,Wv(xv;hj,v,σv) is defined by
[TABLE]
By [JPSS83], there exists h1,v∘,h2,v∘∈H(σv) and Φv∘∈S(Fvn), such that the local Rankin-Selberg integral Ψv(s;h1,v∘,h2,v∘,Φv∘) equals exactly the local L-function Lv(s,πv×πv). One then applies the bound in [LRS99] to see that ∣Lv(s,πv×πv)∣>0. Hence Iv(s;h1,v∘,h2,v∘,Φv∘)=0, which implies that there exists some xv∈G(Fv) such that Wv(xv;h1,v∘,σv)=0. Then we can take hv∘=πv(xv)h1,v∘ to get (59).
∎
Let ϵ0>0 be a small constant (smaller than 1/(n2+1)). Let Cϵ0+ be the piecewise smooth curve consisted of three pieces: {s∈C:Re(s)=0,Im(s)≥ϵ0},{s∈C:Re(s)≥0,∣s∣=ϵ0}, and {s∈C:Re(s)=0,Im(s)≥ϵ0}. Then by Lemma LABEL:49lem, for any s∈Cϵ0+ and any cuspidal representations σ and σ′ as above,
[TABLE]
where the implied constant depends only on F and ϵ0. We will fix ϵ0 henceforth.
As before, we fix a proper parabolic subgroup P∈P of type (n1,n2,⋯,nr). Let XP be the subset of cuspidal data χ={(M,σ)} such that M=MP. For any meromorphic function F and ϵ≥0, we denote by V(F) the set of poles of M and denote by Uϵ(F) the set {s∈C:∣s−ρ∣>ϵ,∀ρ∈V(F)}.
For any a<b, write S(a,b) for the strip a<Re(s)<b. Let s∈S(0,1) and 1≤m≤r−1. Let jm,⋯,j1 be m integers such that 1≤jm<⋯<j1≤r−1. For any 1≤l≤m, let δl(s) be of the form als+bl, with al,bl∈Z; and for l∈{1,2,⋯,r−1}∖{jk:1≤k≤m},Cl∈{Cϵ0+,C}. We say (δm(s),⋯,δ1(s)) is nicewithrespecttoχ=Indσ1∣⋅∣λ1⊗⋯⊗σr∣⋅∣λr∈XP if there exists a finite set of integers L (where elements might have multiplicities) and linear forms c(s,κl) and c~(s,κl) with respect to s and κl,l∈L, i.e., c(s,κl) (resp. c~(s,κl)) is of the form als+blκl+cl with bl=0, (resp. al′s+bl′κl+cl′ with bl′=0), where the coefficients are integers, such that κjm=δm(s)Res⋯κj1=δ1(s)ResG(κ;s) is of the form
[TABLE]
where G(κ;s)=G(κ;s,P,χ) is defined as
[TABLE]
c~(s,κl)∈1−Dχ for any s∈S(1/3,1),κl∈Dχ; and the function R(s;χ) is meromorphic satisfying that for any s∈Uϵ(R(⋅;χ)),
[TABLE]
for some finite index set L′ (with multiplicities) and linear forms cl′(s) and c~l′(s).
Theorem 23**.**
Let notation be as before. Assume that (δm(s),⋯,δ1(s)) is nicewithrespecttoχ. Then for any test function φ and Φ, we have
[TABLE]
for any s∈R(1/2;τ)− outside the set Sex⋃∪χU0(R(⋅;χ)), where
[TABLE]
Moreover, the point-wise defined function
[TABLE]
converges locally normally in the region R(1/2;τ)−∖(Sex⋃∪χU0(R(⋅;χ))); admits a meromorphic continuation to the area R(1/2;τ)−∖Sex.
Proof.
Recall that we have written F(κ;s)=F(κ;s,P,χ) for the meromorphic function Rφ(s,κ;ϕ)Λ(s,πκ⊗τ×π−κ). Hence for any Re(s)>1,
[TABLE]
which admits a meromorphic continuation to the whole complex plane (see Theorem H in [Yan19]). From the transform (53) we see that
[TABLE]
Hence, we may write ⟨IP(λ,φ)ϕ1,ϕ2⟩=⟨IP(κ,φ)ϕ1,ϕ2⟩, and Ψ(s,W1,W2;λ)=Ψ(s,W1,W2;κ). Since ⟨IP(κ,φ)ϕ1,ϕ2⟩ is the Mellin inversion of some compact support smooth function, so it is entire with respect to κ. Therefore,
[TABLE]
where ϕ1 runs over BP,χ;κs=(κ1,⋯,κjm−1,δm(s),⋯,κj1−1,δ1(s),⋯,κr−1);Ψ(s;κ)=Ψ(s,W1,W2;κ). Let ι be the canonical isomorphism of vector spaces ι:iaP∗/iaG∗∼Rr−1. Let {e1,e2,⋯,er−1} be an orthonormal basis of Rr−1. Set κ∘=(κ1∘,κ2∘,⋯,κr−1∘), where
[TABLE]
Let κs∘=κs−κ∘. Then ⟨IP(κs,φ)ϕ1,ϕ2⟩ is equal to ⟨IP(κ∘+κs∘,φ)ϕ1,ϕ2⟩.
Now we shall study analytic behavior of κjm=δm(s)Res⋯κj1=δ1(s)ResΨ(s,W1,W2;κ). Fix arbitrarily an s0∈S(0,1)∖Sex, then there exists ϵ=ϵ(s)>0 such that for any s such that ∣s−s0∣≤ϵ one has ∣c(s,κl)∣≥ϵ and ∣c(s,κl)−1∣≥ϵ for any l∈L. Denote by Bϵ(s0) the open neighborhood {s∈C:∣s−s0∣≤ϵ}. Let Sin(s0,ϵ) be the collection of poles (with multiplicity) of R(s;χ) in Bϵ(s0). Let
[TABLE]
Then RSing(s;χ) is a well defined polynomial since Sing(s0,ϵ) is finite. Note that the meromorphic function RSing(s;χ)R(s;χ) is holomorphic in Bϵ(s0). Then the function RSing(s;χ)⋅κjm=δm(s)Res⋯κj1=δ1(s)ResΨ(s,W1,W2;κ) is holomorphic in Bϵ(s0).
Case 1:
If c(s,δj(s))=1, then L(c(s,κl),σ⊗τ×σ′) has a simple pole at κl=δj(s). Let Cϵ={s∈C:∣s−1∣=ϵ}. By trianGLe inequality, we have that ∣Resκl=δj(s)L(c(s,κl),σ⊗τ×σ′)∣=∣Ress=1L(s,σ⊗τ×σ′)∣≤(2π)−1⋅∫Cϵ∣L(s,σ⊗τ×σ′)∣∣ds∣, which is dominated, according to Lemma LABEL:49lem, by
[TABLE]
where the implied constant is absolute, depending only on the base field F. In this case, the archimedean L-factor becomes
[TABLE]
Note that for each local factor ΓFv(1+μσ⊗τ×σ′;v,i,j), one can apply Lemma LABEL:48' to show that ΓFv(1+μσ⊗τ×σ′;v,i,j)≍sΓFv(s+μσ⊗τ×σ′;v,i,j), where the implied constant depends only on s. Hence, L∞(1,σ⊗τ×σ′)≍sL∞(s,σ⊗τ×σ′), with the implied constant relying only on s. Hence,
[TABLE]
Case 2:
If c(s,δj(s))=0, then archimedean factor L∞(c(s,κl),σ⊗τ×σ′) has a possible simple pole at κl=δj(s). Then one has that Resκl=δj(s)Λ(c(s,κl),σ⊗τ×σ′)=Resc(s,κl)=0Λ(c(s,κl),σ⊗τ×σ′)=L(0,σ⊗τ×σ′)Ress=0L∞(s,σ⊗τ×σ′). Note that
[TABLE]
Since τ is unitary, by [LRS99] one has that Re(uσ⊗τ×σ′;v,i,j)≥−3/5>−1, for any v,i,j as above. Note that Γ(s) only has simple poles at s=−k,k∈N≥0. Hence, there is a unique archimedean place v0 and a unique Satake parameter uσ⊗τ×σ′;v0,i0,j0 such that ΓFv(s+μσ⊗τ×σ′;v0,i0,j0) has a simple pole at s=0. Hence μσ⊗τ×σ′;v0,i0,j0=0. The residue is Ress=0ΓFv(s)=1. In this case, since μσ⊗τ×σ′;v0,i0,j0=0, Stirling formula implies that
[TABLE]
where the implies constant is absolute. Since in this case we have σ⊗τ≃σ′,L(s,σ⊗τ×σ′) has simple poles precisely at s=1. Consider instead the function f(s)=(s−1)(s+2)−(5+βn1,n1′−β)/2L(s,σ⊗τ×σ′), where βn1,n1′:=1−1/(n12+1)−1/(n1′2+1) and β=Re(s). Then clearly f(s) is holomorphic and of order 1 in the right half plane Re(s)>−βn1,n1′. Hence by Phragmén-Lindelöf principle we have that f(s) is bounded by Oϵ(C(σ⊗τ×σ′;γ)(1+βn1,n1′−β)/2+ϵ) in the strip −βn1,n1′≤Re(s)≤1+βn1,n1′, leading to the estimate
[TABLE]
where the implied constant is absolute. Hence, combining the estimates (65) and (66) we then obtain
where the implied constant depends only on ϵ and the base field F.
Let Φ=Φ∞⋅∏v<∞Φv∈S0(AFn) be a test function, where Φ∞=∏v∣∞Φv. Let xv=(xv,1,xv,2,⋯,xv,n)∈Fvn, then by definition, Φv is of the form
[TABLE]
where Fv≃R,Qk(xv,1,xv,2,⋯,xv,n)∈C[xv,1,xv,2,⋯,xv,n] are monomials; and
[TABLE]
where Fv≃C and Qk(xv,1,xˉv,1,xv,2,xˉv,2,⋯,xv,n,xˉv,n) are monomials in the ring C[xv,1,xˉv,1,xv,2,xˉv,2,⋯,xv,n,xˉv,n]. Thus there exists a finite index set J such that
[TABLE]
where each Φv,jv is of the form in (69) or (70) with m=1. Let Φ∞,j=∏v∣∞Φv,j−v,j=(jv)v∣∞∈J. Then Φ is equal to the sum over j∈J of each Φj=Φ∞,j∏v<∞Φv∈S0(AFn). According to [Jac09], Ψv(s,W1,v,W2,v;κ,Φv,j) converges absolutely in Re(s′)>0 for each v∣∞ and j∈J. Hence, one has that
[TABLE]
Since each Φv,jv is a monomial multiplying an exponential function with negative exponent, Ψv(s,W1,v,W2,v;0,Φv,jv) is in fact of the form c1πc2s∏i∏jΓ(s+νi,j), where c1=c1(v),c2=c2(v) and νi,j=νi,j(v) are some constants and the product is finite. Hence, Ψv(s,W1,v,W2,v;κ,Φv,jv) is in fact of the form c1πc2s∏i∏jΓ(s+λi−λj+νi,j). Since the local integral Ψv(s,W1,v,W2,v;κ,Φv,j) converges absolutely in Re(s)>0 for each v∣∞,κ∈iaP∗/iaG∗ and j∈J, then there is no pole in the right half plane Re(s)>0. So one must have that Re(νi)≥0. Also, note that for each archimedean place v, there exists a polynomial Q1(s,κ)∈C[s,κ1,⋯,κr−1] (see loc. cit.) with integers ni,j and Ni,j depending on π∞ and κ, such that
[TABLE]
where Re(s)>βni,nj:=1−1/(ni2+1)−1/(nj2+1). Since each σv,j is unitary, Lv(s+κi,j−1,σv,i⊗τv×σv,j) is holomorphic when Re(s)>βni,nj, then Q1(s,κ) is nonvanishing in Re(s)>βn,n=1−2/(n2+1), and each zero of Q1(s,κ) must be a pole of some Lv(s+κi,j−1,σv,i⊗τv×σv,j) (after meromorphic continuation), for some 1≤i,j≤r. Let μpi,qj,1≤pi≤ni,1≤qj≤nj, be Satake parameters such that Lv(s+λi−λj,σv,i⊗τv×σv,j)=c1,i,jπc2,i,js∏pi∏qjΓ(s+λi−λj+μpi,qj). Then Re(μpi,qj)≥βni,nj. Then there exist constants cχ, nonnegative integers mpi,qj and exponents epi,qj∈N≥0 such that
[TABLE]
In conclusion, when Re(s)>1,Ψv(s,W1,v,W2,v;κ,Φv,jv) is equal to product of the meromorphic function Q1(s,κ)Hv(s,κ) and the meromorphic function
[TABLE]
where Hv(s,κ)=Hv(s,λ) defined just before (LABEL:ar), depending on πv and Φv,jv. We thus obtain meromorphic continuation of Ψv(s,W1,v,W2,v;κ,Φv,jv) to the whole complex plane. Now we identify Ψv(s,W1,v,W2,v;κ,Φv,jv) with its continuation. Then by (72) and preceding analysis we have
[TABLE]
where for any i<j,κi,j−1=∑k=ij−1⟨ek,κ⟩; and Q2(s,κ) is equal to the product of cχHv(s,κ) and the function
[TABLE]
where I and J are some finite set of indexes; si,j=s+λi−λj and μi,j,pi,qj′=μpi,qj+mpi,qj. One can check directly the type of residues in the proof of Theorem H in [Yan19] to conclude that for n≤4 the function
[TABLE]
is entire as a function of κ∘ and as a function of s it is nonvanishing in Re(s)≥c0′>0 for some absolute constant c0′. The existence of c0′ comes from the fact that Re(κ) lies in the box [−4,4]n−1.
Since ∣Re(μi,j,pi,qj′)∣≤βni,nj, there exists some c0>0 such that for any s≥c0,\big{|}Q_{2}(s,\boldsymbol{\kappa})\big{|} is bounded by the product of ∣cχHv(s,κ)∣ and
[TABLE]
where si,j=s+κi,j,s. Recall that we have restricted s in a fixed compact set, then Im(s+κi,j,s)≍Im(κi,j∘), where for any i<j,κi,j−1∘=⟨ei,κ∘⟩+⋯+⟨ej−1,κ∘⟩. Therefore, we can take c0 to be large enough (depending only on the fixed neighborhood of s) to get that
[TABLE]
where s′ is any complex number such that Im(s′)=Im(κi,j∘) and Re(s′)≥c0.
Note that the function c(s,κl)(c(s,κl)−1)Λ(c(s,κl),σ⊗τ×σ′) is entire. Then by Phragmén-Lindelöf principle and the functional equation we have
[TABLE]
where s2 is the unique complex number such that Re(c(s2,κl))=2∣Re(c(s,κl))∣+2 and Im(c(s2,κl))=Im(c(s,κl)); and α(s2) is positive depending only on Re(s2).
Let s∈Bϵ(s0). Then by our definition min{∣c(s,κl)∣,∣c(s,κl)−1∣}≥ϵ, for any κl∈Cl. Then one has, for any s∈Bϵ(s0), that
[TABLE]
since L(c(s2,κl),σ⊗τ×σ′)≪1. Therefore, we then obtain that
[TABLE]
where N>0 is large and s′ is such that Re(s′)=4N+2 and Im(c(s′,κl))=Im(c(s,κl)). Moreover, the implied constant in (74) is independent of N. Note that L(s′,σ⊗τ×σ′)≫1. One can deduce from (74) that
where s∈Bϵ(s0); the parameters N and s′ are defined as in (75).
Let S(φ,Φ) be the finite set of nonarchimedean places such that both φv and Φv=Φv∘ are the characteristic function of G(OF,v) outside ΣF,∞∪S(π,Φ). Note that when φv is G(OF,v)-invariant, then πv,λ is unramified. So the cardinality of the finite set S(π,Φ) is bounded in terms of τ,Φ and the K-finite type of the test function φ. Namely, there exists a finite set Sφ,τ,Φ of prime ideals of the base field F such that for any π induced from some cuspidal datum χ∈XP, one has S(π,Φ)⊆Sφ,τ,Φ. Let χ=(σ1,⋯,σr), where each σj is a cuspidal representation of some GL(nj,AF). By spectral expansion, For each v∈Sφ,τ,Φ, every possible local component σj,v has bounded conductor in terms of Kv-type of φv,τv and Φv. Then there can only be finitely many (depending on φv,τv and Φv) such σj,v’s. Hence there are only finitely many possible πv’s, for any v∈Sφ,τ,Φ. Moreover, for each πv, there are finitely many vectors in πv having the given Kv-type. Hence #BP,χ,v<∞ for each v∈Sφ,τ,Φ. Denote by D(v;φv,τv,Φv) the sum of all finitely many possible #BP,χ,v. Let Dφ,τ,Φ be the product of D(v;φv,τv,Φv) over v∈Sφ,τ,Φ. Then Dφ,τ,Φ is an integer depending only on τ and the test functions φ and Φ. Note that for each v∈Sφ,τ,Φ, the local Whittaker function Wv(x;πv,κ) is dominated by a gauge ξπv uniformly in fixed strips c1≤Re(κj)≤c2,1≤j≤r−1. Hence we have
[TABLE]
which is finite since ξα and ξβ are Bruhat-Schwartz functions. Given s∈S(0,1)∖Sex, since there are only finitely many possible local Rankin-Selberg integrals Ψv(s,W1,v,W2,v;κs,Φv),v∈Sφ,τ,Φ, and each is finite, we see that
[TABLE]
Since κs=κ∘+κs∘, then ⟨IP,v(κs,φv)ϕ1,v,ϕ2,v⟩v=⟨IP,v(κ∘+κs∘,φv)ϕ1,v,ϕ2,v⟩v=⟨IP,v(κ∘,φve(κs∘+ρP)HP)ϕ1,v,ϕ2,v⟩v. Noting that φve(κs∘+ρP)HP is Bruhat-Schwartz and the representation IP,v(κ∘,φve(κs∘+ρP)HP) is unitary, we have by trianGLe inequality that ∣⟨IP,v(κs,φv)ϕ1,v,ϕ2,v⟩v∣≤⟨ϕ1,v,ϕ1,v⟩v⟨ϕ2,v,ϕ2,v⟩v=1. Applying estimates for Satake parameters to the local Eulerian product we get that ∣L(c(s,κl),σv⊗τv×σv′)∣−1≤(1+NF/Q(p)M1)M2, for some absolute positive constants M1 and M2. Hence by definition of Rv(s,W1,v,W2,v;κs,Φv) we have
[TABLE]
where the implied constant depends only on the base field F. Since c′(s,κl)∈1−Dχ,Re(c′(s,κl))>4/5. Then applying the upper bounds for Satake parameters we get ∣Lv(c′(s,κl),σ×σ′)∣≤∏∏∣1−NF/Q(p)−1/2∣−1<∞. Therefore,
[TABLE]
where the implied constant depends only on F,τ,φ and Φ.
Let σ and σ′ be cuspidal representations of GL(n1,AF) and GL(n1′,AF), respectively. Since ∣c(s,κl)∣≥ϵ and ∣c(s,κ)−1∣≥ϵ, then by convexity bound,
[TABLE]
Also, since c′(s,κl)∈1−Dχ, then we can apply the result in [Lap13] to deduce
[TABLE]
where cl>0 is absolute. Denote R(s;χ)κjm=δm(s)Res⋯κj1=δ1(s)ResΨ(s,W1,W2;κ) by ResΨ12(s). Gather (60), (68), (71), (75), (76), (73), (78), (79) and (80) to obtain
[TABLE]
where Hχ(κ∘) is a function depending on χ and κ∘, and it is defined by
[TABLE]
where N is an absolute constant. Let s0′>4N+1 be a large enough (depending at most possibly on ϵ) real number. Then substituting Stirling formula into the estimate (81) we have that
[TABLE]
Since LS(s′,σ×σ′)=∏v∈Sφ,τ,ΦLv(s′,σv×σv′)≫1 when Re(s′)>4/5, where the implied constant is absolute, then from (82) we deduce that
[TABLE]
where ResΨ=ResΨ12(s) and LS(s′,σ×σ′)=∏v∈/ΣF,∞∪Sφ,τ,ΦLv(s′,σv×σv′) is the partial L-function, and the implied constant in (83) depends only on F and ϵ.
On the other hand, for any v∈Sφ,τ,Φ, by Lemma 21, there exists some ϕv∘∈H(σ1,v,⋯,σr,v) such that W(e;ϕv∘,κ)=0, for any κ∈iaP∗/iaG∗. Since Φv is a Schwartz-Bruhat function, we can write Φv as a finite sum of Φv,l, where each Φv,l is a constant multiplying a characteristic function of some connected compact subset of Fvn. Then the Fourier transform of Φv,l is of the same form. Let the integral Ψv∗(s′,Wv∘,Wv∘;κ,Φv,l) be defined by
[TABLE]
If Ψv∗(s′,Wv∘,Wv∘;κ,Φv,l)=0 for some κ∈iaP∗/iaG∗ and some s′>3, then 0=∣Ψv∗(s′,Wv∘,Wv∘;κ,Φv,l)∣=Ψv∗(s′,Wv∘,Wv∘;κ,∣Φv,l∣), which amounts to that
[TABLE]
Since W(xv;ϕv∘,κ) is a continuous function of xv, then W(xv;ϕv∘,κ)=0 for any xv. In particular, W(e;ϕv∘,κ)=0, which is a contradiction. Hence, one sees that Ψv∗(s′,Wv∘,Wv∘;κ,Φv,l)=0 for any κ∈iaP∗/iaG∗ and any s′>3. Note that by Proposition 43 in [Yan19], for any s′>3, we have
[TABLE]
Then for fix s′>3 and for any κ,Ψv(s′,Wv∘,Wv∘;κ,Φv,l)Lv(s′,πκ,v⊗τv×π−κ,v)−1 is a polynomial nonvanishing in a compact domain. Then there exists a positive constant Cv,s′′=C(s′;φv,Φv,τv) such that for any κ, one has ∣Ψv(s′,Wv∘,Wv∘;κ,Φv,l)Lv(s′,πκ,v⊗τv×π−κ,v)−1∣≥Cv,s′′. Since s′>3, we have
[TABLE]
where the right hand side is larger than ∏i=1r∏j=1re−2n∑pp−2≥e−4nr2. Let Cv,s′=e−4nr2Cv,s′′. Then we have that ∣Ψv(s,Wv∘,Wv∘;κ,Φv,l)∣≥Cv>0, for any v∈Sφ,τ,Φ. Let Cφ,τ,Φ∘(s′) be the product of Cv,s′ over v∈Sφ,τ,Φ. Denote by ΨSφ,τ,Φ(s′,Wv∘,Wv∘;κ,Φv,l) the product of local Rankin-Selberg integrals Ψv(s′,Wv∘,Wv∘;κ,Φv,l) over v∈Sφ,τ,Φ. Then
[TABLE]
For each v∈Sφ,τ,Φ, let φv∘ be a fundamental idempotent with respect to a small compact subgroup such that ϕv∘ is right suppφv∘-invariant. Then IP,v(κ,φv∘)ϕv∘=ϕv∘. Hence we get ⟨IP,v(κ,φv∘)ϕv∘,ϕv∘⟩v=⟨ϕv∘,ϕv∘⟩v=1. Therefore, by (84),
[TABLE]
When v is a nonarchimedean place and v∈/Sφ,τ,Φ, then each πv is unramified and Φv is the characteristic function of G(OFv). Then by Proposition 43 in loc. cit., when Re(s′)>1, the local Rankin-Selberg integral Ψv(s′,W1,v,W2,v;κ,Φv) is equal to the product ∏k=1rLv(s′,σk,v⊗τv×σk,v) multiplying
[TABLE]
Let Re(s′)>3 and κ∈iaP∗/iaG∗. Denote by the partial Rankin-Selberg integral ΨS(s′,W1,W2;κ,Φ) the product of each local integral Ψv(s′,W1,v,W2,v;κ,Φv), where v is a nonarchimedean place and v∈/Sφ,τ,Φ. Similarly we define the partial L-function LS(s′,σ×σ′). Then for any cuspidal representations σ (resp. σ′) of GL(n1,AF) (resp. GL(n1′,AF)), we have
[TABLE]
where d=[F:Q]. Therefore, for any ϕ1,ϕ2∈BP,χ, we have that
[TABLE]
where Ψ12S(s′)=ΨS(s′,W1,W2;κ,Φ) and the implied constant depends only on n.
Let ResF(s)=R(s;χ)κjm=δm(s)Res⋯κj1=δ1(s)ResF(κ;s). Now combining (83), (85) and (86) we then obtain that
[TABLE]
where ϕ1′ runs over B such that ϕ1,v=ϕv∘,v∈Sφ,τ,Φ. Now Theorem 23 follows from Corollary 41 in [Yan19].
∎
According to Theorem H in loc. cit. the function (s−1/2)⋅Im,χ(s)⋅Λ(s,τ)−1 is holomorphic in the region S(1/3,∞) for each 0≤m≤r−1. Invoking the computation in the appendix of loc. cit. with Theorem G in loc. cit. and Theorem 23 we see that
[TABLE]
converges locally normally in the region S(1/3,∞)∖{s:Re(s)=1/2,⋯,(n−1)/n,1}. Let s0 be such that Re(s0)=β, where β∈{1/2,⋯,(n−1)/n,1}. Let ϵ>0 be sufficiently small. Let Uϵ(s0)={s:∣s−s0∣<ϵ}. We shall prove that Zm(s) converges uniformly in the region Uϵ(s0), which follows clearly from Corollary 41 in loc. cit. and the following Claim 24.
∎
Claim 24**.**
Let s∈Uϵ(s0). Then (s−1)nIm,χ(s)⋅Λ(s,τ)−1 is bounded uniformly by a finite sum of \big{|}\langle\mathcal{I}_{P}(\boldsymbol{\kappa},\varphi)\phi,\phi\rangle\Psi\left(s^{\prime},W,W;\boldsymbol{\kappa},\Phi\right)\big{|}, where Re(s′)=Re(s0) and Re(s′) is large (depending on s0), and the sum depends only on the test functions φ and Φ.
Recall that for χ∈XP and β∈R, we set Rχ(β):=(β−Dχ(ϵ))∪(β−Dχ(ϵ)). Then there are only finitely many χ such that Rχ(1)⊇Uϵ(s0). The contribution from these χ’s is clearly convergent uniformly. Let χ be such that Rχ(β)⊉Uϵ(s0). Then we can divide Uϵ(s0) into three parts Uϵ(s0)−∪Uϵ(s0)0∪Uϵ(s0)+, where Uϵ(s0)0=Uϵ(s0)∩Rχ(β),Rχ(β)−=(Rχ(β)∖Rχ(β))∩S(0,β), and Rχ(β)−=(Rχ(β)∖Rχ(β))∩S(β,2).
Note that by (6) we see that R(s,W1,W2;κ,ϕ)Λ(s,πκ⊗τ×π−κ) is equal to F(s,κ;χ)G(κ;s,P,χ), where G(κ;s,P,χ) is defined to be
[TABLE]
Then κjm=δm(s)Res⋯κj1=δ1(s)ResR(s,W1,W2;κ,ϕ)Λ(s,πκ⊗τ×π−κ) is equal to the function F(s,κs;χ)κjm=δm(s)Res⋯κj1=δ1(s)ResG(κ;s,P,χ), where κs=(κ1,⋯,κr−1) with κj=δj(s),j=j1,⋯,jm. It follows from the proof of Theorem LABEL:47' (resp. Theorem 23) that ∣F(s,κ;χ)∣≪ϵ∣F(s′,κ;χ)∣ (resp. ∣F(s,κs;χ)∣≪ϵF(s′,κ∘;χ)) for s′ such that Im(s′)=Im(s0) and Re(s′) is large enough.
Also, by the definition of Im,χ(s) we see that κjm=δm(s)Res⋯κj1=δ1(s)ResG(κ;s,P,χ) is of the form (61) and (δ1(s),⋯,δm(s)) is nicewithrespecttoχ∈XP. Let s∈Rχ(β)0, then one sees from the explicit construction of Im,χ(s) that κi,j∈/(β−Dχ(nϵ))∪(β−Dχ(nϵ)). While s∈Rχ(β)−∪Rχ(β)+,Re(κi,j)=0. In all, one has min{∣s±κi,j∣,∣s±κi,j−1∣}≫τC(σi×σj;s0)−N, and min{∣c(s,κl)∣,∣c(s,κl)−1∣}≫τC(σl×σl′)−N (see (61) for the notation here), where N is a positive absolute constant coming from definition of the zero-free region (see (55) and (56)). Now apply preconvex bound to see that ∣Λ(s±κi,j,σi⊗τ×σj+1)∣≪Λ(s′±κi,j,σi⊗τ×σj+1) and ∣(s−1/2)(s−1)nΛ(s,σk⊗τ×σk)∣≤∣Λ(s′,σk⊗τ×σk)∣. One then concludes Claim 24 for m=0 form the proof of Theorem G in [Yan19]. Likewise, one has bounds for ∣Λ(c(s,κl),σl⊗τ×σl′)∣≪∣Λ(c(s′,κl),σl⊗τ×σl′)∣ and ∣(s−1/2)(s−2/3)(s−3/4)(s−1)nΛ(cl′(s),σl′⊗τ×σl′′)∣≪∣Λ(cl′(s′),σl′⊗τ×σl′′)∣. Then the m≥1 part of Claim 24 follows from the proof of Theorem 23 and the fact that (s−1/2)(s−1)nIm,χ(s)⋅Λ(s,τ)−1 is holomorphic at s∈{2/3,⋯,(n−1)/n}.
∎
4. Proof of Main Theorems
Proposition 25**.**
Let n≥1 be an integer. Let π be an cuspidal representation of GL(n,AF) and τ be a Hecke character on F×\AF×, where F is a number field. Assume τ has order at most 2. Then the root number of ΛF(s,π,Ad⊗τ) is 1.
Proof.
Denote by W(π,Ad⊗τ)=∏v∈ΣFW(πv,Ad⊗τv) the root number associated with ΛF(s,π,Ad⊗τ), where W(πv,Ad⊗τv) are local root number in the functional equation of L(s,πv,Ad⊗τv). First we deal with the case where τ is trivial. The general case will be reduced to this special case by base change. Write W(π,Ad)=∏v∈ΣFW(πv,Ad). According to [BH99], for any v∈ΣF,fin and any irreducible admissible representation πv of GL(n,Fv), one has that W(πv,Ad)=wπv(−1)n−1, where wπv is the central character of πv.
Hence, we need to compute archimedean root numbers W(πv,Ad). Since our approach is using Langlands classification (see [Kna94]), we will separate the cases where the place v is archimedean or finite.
Case 1:
Assume that Fv≃C. One has WFv≃C×. So all irreducible representations are one dimensional. We may write any such characters as χk,ν(z)=(z/∣z∣)k∣z∣Cν=(z/∣z∣)k∣z∣2ν, for k∈Z and ν∈C. The root number associated to this character is W(χk,ν)=i∣k∣. Since χk,ν⊗χk′,ν′=χk+k′,ν+ν′, we then have W(χk+k′,ν+ν′)=i∣k+k′∣. Let ⊕j=1nχkj,νj be the representation corresponding to πv. Then Adπv corresponds to
[TABLE]
where 1 is the trivial representation of WFv. Therefore, we have
[TABLE]
By comparing multiplicity of each kj one concludes that ∑1≤l<j≤n(kl−kj)≅(n−1)∑j=1nkjmod2. Consequently, we have
[TABLE]
Case 2:
Assume that Fv≃R. One has WFv≃C×⊔jC×, where j2=−1 and jzj−1=zˉ for any z∈C×. Hence each irreducible representation σ of WFv is of dimension 1 or 2. If dimσ=1, then its restriction to C× is of the form χ0,ν for some ν∈C (see (3.2) of [Kna94]). If σ(j)=1, then W(σ), the root number associated to σ, is trivial. If σ(j)=−1, then W(σ)=i. If dimσ=2, then it is the induction of χk,ν from C× to GL(2,R), where k∈N≥1 and ν∈C. In this case, the root number W(σ)=ik. Let σ1 and σ2 be two irreducible representations of WFv. We shall examine the tensor product parameters σ1⊗σ2.
(a)
If dimσ1=dimσ2=1, then so is σ1⊗σ2. Let σ1=χ0,ν1 and σ2=χ0,ν2. Then σ1⊗σ1=χ1−σ1(j)σ1(j),ν1+ν1=χ0,2ν1. Thus one has the formula W(σ1⊗σ1)=1,W(σ1⊗σ2)=i1−σ1(j)σ2(j), and
[TABLE]
(b)
If dimσ1⋅dimσ2=2, then σ1⊗σ2 is irreducible and two dimensional. Let σ1=χ0,ν1 and σ2 be induced from C× by χk2,ν2, where k2∈N. Then σ1⊗σ2 is induced from C× by χk2,ν1+ν2. Thus W(σ1⊗σ2)=ik2 and
[TABLE]
(c)
If dimσ1=dimσ2=2, then we may assume that σ1 is induced from C× by χk1,ν1 and σ2 is induced from C× by χk2,ν2. Then σ1⊗σ2 is the direct sum of two two-dimensional representations, induced from C× from the characters χk1,ν1χ−k2,−ν2=χk1−k2,ν1−μ2 and χ−k1,−ν1χ−k2,−ν2=χ−k1−k2,−ν1−μ2. Note that the former representation id reducible when k1=k2. It then follows that W(σ1⊗σ1)=i2∣k1∣=(−1)k1, and
[TABLE]
Let ⊕j=1r⊕j=1rσj be the representation corresponding to πv, where dimσ∈{1,2} and ∑j=1rdimσj=n. Assume further that dimσk=1, for 1≤k≤r0≤r; and dimσk=2, for r0<k≤r. For 1≤k≤r0, write σk=χwk,νk; for r0<k≤r, we may assume σk is induced from C× by χwk,νk, where wk≥0. Then Adπv⊞1 corresponds to
[TABLE]
where 1 is the trivial representation of WFv. Therefore, we have
[TABLE]
Now applying the relation r0+2(r−r0)=n one deduces easily that (−1)(r0+1)∑k=r0+1rwk=(−1)(n−1)∑k=r0+1rwk=wπv(−1)n−1. So we have
[TABLE]
Then combining (87), (91) with results from [BH99] we conclude that
[TABLE]
Let v be a place of F. Let σv be an n-dimensional representation of WFv×GL(2,C) (resp. WFv) for v nonarchimedean (resp. archimedean) associated to πv via local Langlands correspondence (see [Hen00] and [HT01]). Let Adσv be the adjoint representation of σv. Then dimAdσv=n2−1.
Now assume τ is nontrivial. If π⊗τ≃π, then from previous result, we have
[TABLE]
as W(τ)=1. Since τ is quadratic, then there exists some quadratic extension K/F such that τ is the character associated to this extension. Let π∗ be the base change of π with respect to K/F. By proceeding analysis we may assume that π⊗τ≆π. Then π∗ is cuspidal. Let θ=⊗vθv be a nontrivial additive character on F\AF. Write τ=⊗vτv. Let v∈ΣF and p=pv be a place of K above v, then Kp is a quadratic extension of Fv and τv is the character associated to this extension. Let σv∗=ResKp/Fvσv. Then one has (see [Tat79]) that
[TABLE]
Hence ϵ(Adσv,θFv)ϵ(Adσv⊗τv,θFv)=ϵ(τv,θFv)n2−1ϵ(Adσv∗,θFv∘TrKp/Fv), implying that ϵ(Adσv⊗τv,θFv)=ϵ(τv,θFv)n2−1ϵ(Adσv∗,θFv∘TrKv/Fv)ϵ(Adσv,θFv)−1. Therefore, via local Langlands correspondence we have
[TABLE]
Then we have GLobally that W(π,Ad⊗τ)=W(τ)n2−1W(π∗,Ad)W(π,Ad). Since τ is quadratic, it is of orthogonal type. Thus by [Del76], W(τ)=1. Therefore we have W(π,Ad⊗τ)=W(π∗,Ad)W(π,Ad). Then Proposition 25 will follow from (92).
∎
Recall that we have shown, for any test function φ∈F(w),
[TABLE]
where I∞(s,τ)=I∞,Reg(s,τ)+I∞(1)(s,τ)+ISing(s,τ).
Since n≤4, then according to Uchida-Van der Waal Theorem (see [Uch75] and [vdW75]) and its generalization to twist form (see [MR00]), each ΛE(s,τ∘NE/F)⋅ΛF(s,τ)−1 admits a holomorphic continuation to the whole complex plane. It then follows from Theorem D in [Yan19] that the function IGeo,Reg(s,τ)/ΛF(s,τ) admits an entire continuation.
Also, by Theorem B, Theorem C and Theorem E in loc. cit., the function I∞(s,τ)/ΛF(s,τ) admits a meromorphic continuation to R(1/2;τ)−∪S(1/2,∞), with possible simple poles at s∈{1/2,2/3,3/4}. Moreover, if LF(2/3,τ)=0, then I∞(s,τ)⋅ΛF(s,τ)−1 is regular at s=2/3; if LF(3/4,τ)=0, then I∞(s,τ)⋅ΛF(s,τ)−1 is regular at s=3/4.
Let ρ∈R(1/2;τ)−∪S(1/2,1) be a zero of Λ(s,τ) of order rρ≥1. Denote by
[TABLE]
If ρ=1/2, we then see that J(ρ;j)=0 for any 0≤j≤rρ−1 and φ∈F(w). According to the Proposition in Section 3.3 of [JZ87], one has, for all cuspidal representations π∈A0(G(F)∖G(AF),w−1), and all K-finite functions ϕ1,ϕ2∈Vπ, that
[TABLE]
Then by Rankin-Selberg theory, we have, for all cuspidal representations π∈A0(G(F)∖G(AF),w−1), that ∂sj∂jΛ(s,π⊗τ×π)∣s=ρ=0,1≤j<rρ, implying that the adjoint L-function Λ(s,π,Ad⊗τ) is regular at s=ρ.
Now assume that ρ=1/2, namely, LF(1/2,τ)=0. If τ is not quadratic, then by Theorem C, I∞(1)(s,τ)⋅ΛF(s,τ)−1 is regular at s=1/2. Therefore, we have J(1/2;j)=0, for 1≤j≤r1/2−1. Hence, by similar analysis as above we see that ∂sj∂jΛ(s,π⊗τ×π)∣s=1/2=0,1≤j≤r1/2−1, implying that the adjoint L-function Λ(s,π,Ad) is regular at s=1/2. Now we assume that τ2=1. If r1/2≥2, then by Theorem B, Theorem C and Theorem A in [Yan19], we see that J(1/2;j)=0, for 1≤j≤r1/2−2. Hence, by the Proposition in Section 3.3 of [JZ87] we see that ∂sj∂jΛ(s,π⊗τ×π)∣s=1/2=0,1≤j<r1/2−1, implying that the adjoint L-function Λ(s,π,Ad) has at most a simple pole at s=1/2. Now we apply Proposition 25 to exclude this possible simple pole at 1/2. Suppose that Λ(s,π,Ad⊗τ) has a pole at s=1/2. Since the root number of Λ(s,π,Ad⊗τ) is trivial, then the order of the pole s=1/2 must be even. So Λ(s,π,Ad⊗τ) cannot have a simple pole at s=1/2. A contradiction. If r1/2=1, then clearly, the adjoint L-function Λ(s,π,Ad) has at most a simple pole at s=1/2. The same argument on root number excludes the possibility of pole at s=1/2.
In all, we have shown that Λ(s,π,Ad⊗τ) is holomorphic in R(1/2;τ)−∪S(1/2,∞). Now Theorem A follows from GLobal functional equation of Λ(s,π,Ad⊗τ).
∎
It follows from local Langlands correspondence that the local factor L∞(s,π∞⊗τ∞×π∞)⋅L∞(s,τ∞)−1 is equal to a finite product of exponential functions and Gamma functions. Therefore, L∞(s,τ∞)⋅L∞(s,π∞⊗τ∞×π∞)−1 admits a holomorphic continuation to the whole complex plane. Therefore, by Theorem A, we conclude that
[TABLE]
admits a holomorphic continuation to the whole complex plane.
∎
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