$L^\infty$-estimation of generalized Thue-Morse trigonometric polynomials and ergodic maximization
Aihua Fan, Joerg Schmeling, Weixiao Shen

TL;DR
This paper establishes the asymptotic behavior of the $L^ abla$-norm of generalized Thue-Morse trigonometric polynomials, linking it to ergodic maximization and providing a method to compute the key exponent.
Contribution
It introduces a new connection between the $L^ abla$-norm growth of these polynomials and ergodic theory, specifically maximizing a certain function over a dynamical system.
Findings
The $L^ abla$-norm behaves like $N^{b3(q;c)}$ with $b3(q;c)$ linked to ergodic maximization.
The maximum is attained by a $q$-Sturmian measure.
Numerical methods can compute $b3(q;c)$ for given parameters.
Abstract
Given an integer and a real number , consider the generalized Thue-Morse sequence defined by , where is the sum of digits of the -expansion of . We prove that the -norm of the trigonometric polynomials , behaves like , where is equal to the dynamical maximal value of relative to the dynamics and that the maximum value is attained by a -Sturmian measure. Numerical values of can be computed.
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-estimation of generalized Thue-Morse trigonometric polynomials and ergodic maximization
Aihua FAN
LAMFA, UMR 7352 CNRS, University of Picardie, 33 rue Saint Leu, 80039 Amiens, France
,
JÖRG SCHMELING
Lund University
Centre for Mathematical Sciences
Box 118, 221 00 LUND, Sweden
and
Weixiao SHEN
Shanghai Center for Mathematical Sciences
Fudan University
220 Handan Road, Shanghai 200433, China
Abstract.
Given an integer and a real number , consider the generalized Thue-Morse sequence defined by , where is the sum of digits of the -expansion of . We prove that the -norm of the trigonometric polynomials , behaves like , where is equal to the dynamical maximal value of relative to the dynamics and that the maximum value is attained by a -Sturmian measure. Numerical values of can be computed.
Contents
- 1 Introduction and main results
- 2 General setting of maximization and minimization
- 3 Gelfond exponent and maximization problem
- 4 Maximization for and Sturmian measures
- 5 Pre-Sturmian condition implies Sturmian condition
- 6 Appendix A: -Sturmian measures
- 7 Appendix B: Computation of and
1. Introduction and main results
Let be a positive integer. For any integer , we denote by the sum of digits of expansion of in base . Fix , we define the generalized Thue-Morse sequence by
[TABLE]
The case that and corresponds to the classical Thue-Morse sequence:
[TABLE]
By a generalized Thue-Morse trigonometric series we mean
[TABLE]
which defines a distribution on the circle . We are interested in the asymptotic behaviors of its partial sums, called the generalized Thue-Morse trigonometric polynomials:
[TABLE]
The first problem is to find or to estimate the best constant such that
[TABLE]
Define , sometimes denoted , to be the infimum of all for which (1.2) holds. Following Fan [15], we call the Gelfond exponent of the generalized Thue-Morse sequence . The first result, due to Gelfond [20], is that
[TABLE]
Trivially . No other exact exponents are known. A basic fact, as a consequence of the so-called -multiplicativity of , is the following expression
[TABLE]
Thus the dynamical system defined by is naturally involved. Let
[TABLE]
We will simply write if there is no confusion. Let us point out that is a translation of and that for all and , and has singularities as a function on in the sense for . Furthermore, is concave between any two adjacent singularity points. Consequently attains its maximal value at and its singularity points are (). See Figure 1 for its graph.
As we shall see in Proposition 3.2, finding the Gelfond exponent is equivalent to maximizing . That is to say
[TABLE]
with
[TABLE]
where is the set of -invariant Borel probability measures (Theorem 2.1). It is easy to see that so that for all , just because
[TABLE]
A detailed argument is given in [16].
Our main result in this paper is the following theorem concerning the maximal value .
Main Theorem. *Fix an integer . The following hold.
(1) The supremum in (1.5) defining is attained by a unique measure and this measure is -Sturmian.
(2) Such a -Sturmian measure is periodic in most cases. More precisely, those parameters corresponding to non-periodic Sturmian measures form a set of zero Hausdorff dimension.
(3) There is a constant such that*
[TABLE]
A -Sturmian measure is by definition a -invariant Borel probability measure with its support contained in a closed arc of length . It is well-known that each closed arc of length supports a unique -invariant Borel probability measure. A proof of this fact is included in Appendix A for the reader’s convenience.
For the maximization, many of the existing results in the literature deal with the case that is a Hölder continuous function, by Bousch [6, 7], Jenkinson [24, 25, 26, 27], Jenkinson and Steel [28], Contreras, Lopes and Thieullen [11], Contreras [12], among others. There is a very nice survey paper [23] in which there is a rather complete list of references. See also Anagnostopoulou et al [2, 3, 4], Bochi [5].
Up to now, as far as we know, only the exact value of the Gelfond exponent is known, obtained by Gelfond [20]. Some estimate is obtained by Mauduit, Rivat and Sarkozy [34]. In Section 7, a computer-aided method will be provided to compute the Gelfond exponent , based on the theory developed in Section 4. Figure 2 shows the graph of for ’s corresponding to periodic Sturmian measures with period not exceeding . More details can be filled in by using Sturmian measures with larger periods. Let us point out that for , we get the exact value
[TABLE]
The modal around of the graph of is nothing but the graph of the function on the right hand side of (1.7). This is the contribution of the -cycle . Other details shown in Figure 2 are contributed by other cycles. See (7.3) for a formula more general than (1.7). The symmetry of the graph of reflects nothing but the fact which holds for all .
The Thue-Morse sequence and the digital sum function are extensively studied in harmonic analysis and number theory after the works of Mahler [31] and Gelfond [20]. The set of natural numbers such that are even is studied and the norms and are involved in the study of the distribution of such sets in [20, 19, 18, 14]. Queffélec [36] showed how to estimate the -norm using the -norm through an interpolation method. C. Mauduit and J. Rivat [33] answered a longstanding question of A. O. Gelfond [20] on how the sums of digits of primes are distributed. This study deals with ( being prime). Polynomials of the form are studied in [1]. Recently Fan and Konieczny [16] proved that for every and every integer there exist constants and such that
[TABLE]
See also [29]. But the optimal is not known.
A dual quantity is the minimal value
[TABLE]
which will play an important role in the study of the pointwise behavior of . This minimization and the multifractal analysis of are stuided in a forthcoming paper.
We start the paper with a general setting of dynamical maximization and minimization (Section 2) and an observation that the computation of the Gelfond exponents for generalized Thue-Morse sequences is a dynamical maximization problem (Section 3). Theorem A will be proved in Section 4 which is the core of the paper. Section 5 is an appendix, devoted to the numerical computation of and .
Acknowledgements. The authors are grateful to Thierry Bousch and Oliver Jenkinson for providing useful informations, to Geng Chen for numerical computation and graphic generation. The first author is supported by NSFC grant no. 11471132 and the third author is supported by NSFC grant no. 11731003. The first and second authors would like to thank Knuth and Alice Wallenberg Foundation and Institut Mittag-Leffler (Sweden) for their supports.
2. General setting of maximization and minimization
Let be a continuous map from a compact metric space to itself. Given an upper semi-continuous function , an interesting and natural problem is ergodic optimization which asks for the following maximization
[TABLE]
where denotes the convex set of all Borel probability -invariant measures. An -maximizing measure is by definition a probability invariant measure attaining the maximum in (2.1).
What we shall be mostly interested in is as follows: is the circle , for some integer , and
[TABLE]
where is an analytic function not identically zero and moreover,
[TABLE]
whenever . That is to say, on any interval where , is concave. Such a function has only singularities of logarithm type, i.e. if is a singular point then
[TABLE]
holds in a neighborhood of . A typical example is (see Figure 3).
2.1. Maximization
The points (1) and (2) in the following theorem were proved by Jenkinson [24]. They were discussed in [13] for continuous function . The point (2) provides three different ways to describe the maximization (2.1) through time averages along orbits. The point (3) provides a fourth way, using periodic points, in the case of the dynamics .
Let be the set of such exists, where
[TABLE]
Theorem 2.1**.**
*Suppose that is upper semi-continuous.
(1) The map is upper semi-continuous so that the supremum in (2.1) defining is attained.
(2) The maximum value is equal to*
[TABLE]
(3)* Assume , , and with an analytic function having a finite number of zeros. We have*
[TABLE]
where denote the collection of all -invariant probability measures supported on periodic orbits.
Proof.
(1) and (2) were proved in [24]. Here we only give an explanation that the last limit in (2) exists. Indeed, putting , we have , so the limit exists.
(3) Let us prove (2.2). Obviously the left hand side is not smaller than the right hand side. So it suffices to prove that for any with and any , there exist a periodic point of period such that
[TABLE]
By the ergodic decomposition, we may assume that is ergodic.
We first prove the following claim.
Claim. *Let denote the set of zeros of . There exists such that for -a.e. , there exists an arbitrarily large positive integer such that *
[TABLE]
To prove the claim, let be the -neighbourhood of . Since is -integrable, we must have and then as . Put
[TABLE]
Since is analytic and non-constant, for any we have
[TABLE]
for some real number and integer . Then there exist and such that
[TABLE]
Then as . Choose such that
[TABLE]
Since is ergodic, for -a.e. ,
[TABLE]
By Pliss Lemma [35], it follows that there is an arbitrarily large integer such that for any ,
[TABLE]
and in particular,
[TABLE]
The claim is proved.
Let us now complete the proof. Fix as we have chosen above and choose a point such that the conclusion of the Claim holds for a sequence of positive integers . Choose suitably so that
[TABLE]
Given , let be small such that
[TABLE]
Let be an accumulation point of . First fix such that . Then find such that and
[TABLE]
where and . Then
[TABLE]
We can choose and such that .
Let . Since maps J bijectively onto , there exists such that . Notice that for ,
[TABLE]
because , and . For the last inequality we used (2.9). According to (2.8), this implies that
[TABLE]
Therefore
[TABLE]
Thus (2.3) is proved. ∎
3. Gelfond exponent and maximization problem
We approach the computation of Gelfond exponent from the point of ergodic optimization. Throughout we fix an integer and will drop the superscript from notation. Recall that denotes the map on the circle . For each , put
[TABLE]
So and .
Fix and consider the function defined by
[TABLE]
which is -multiplicative in the sense that
[TABLE]
for all non-negative integers and such that (see [20]). Using this multiplicativity we can establish a relationship between Gelfond exponents and dynamical maximizations.
3.1. Gelfond exponent and maximization
Indeed, the -multiplicativity gives rise to
[TABLE]
Since the above sum is equal to
[TABLE]
we get
[TABLE]
Therefore, (1.2) is equivalent to the following estimation:
[TABLE]
In particular, is also the infimum of for which (3.2) holds. The function has the following symmetry.
Proposition 3.1**.**
We have for all . Moreover, for all and all we have
[TABLE]
Proof.
This follows simply from the parity and the -periodicity of which gives
[TABLE]
and of the fact . ∎
By definition, the sequences and are related in the following way
[TABLE]
An amazing relation! Apparently, and seem very different, but .
Proposition 3.2**.**
We have for each .
This is a consequence of (3.2) and Theorem 2.1.
4. Maximization for and Sturmian measures
In this section, we consider the maximizing problem in our most interesting particular case. Let denote the map on the circle , and for each , put
[TABLE]
Recall that our object of study is to find
[TABLE]
For each , there is a unique -invariant measure that is supported in circle arc , called -Sturmian measure. These measures are ergodic and whenever . See Appendix A for a proof of these facts.
The main result of this section is the following theorem.
Theorem 4.1**.**
Fix an integer .For any , has a unique maximizing measure . The measure is a -Sturmian measure. Moreover, there exists a constant , which is independent of , such that
[TABLE]
for each and each .
To prove Theorem 4.1, we shall apply and extend the theory of Bousch-Jenkinson. An important fact that is used in the argument is that is strictly concave away from the singularties, or equivalently that is the same for :
[TABLE]
We shall first recall the pre-Sturmian and Sturmian condition introduced by Bousch [6]. Bousch introduced these concepts in the case which extends to the general case in a straightforward way.
4.1. Pre-Sturmian condition and Sturmian condition
For each , let
[TABLE]
be the arc in , starting from and rotating in the anti-clockwise direction. Let and denote the inverse branch of restricted on . So is the unique point in such that .
The following definition comes from Bousch [6] which discusses the case with supposed Lipschitzian. We will only assume that is Lipschtzian on .
Definition 4.1**.**
Let be a Borel function and let . We say that satisfies the pre-q-Sturmian condition for , if is Lipschitz on and there exists a Lipschitz function and a constant such that
[TABLE]
If, furthermore,
[TABLE]
then we say that satisfies the q-Sturmian condition for .
To study the pre-Sturmian condition, let us consider the first time to leave
[TABLE]
Let and for . Then
[TABLE]
From this we verify the second equality in (4.3). Thus and
[TABLE]
Since , the function is supported by .
We have the following criterion for the pre-Sturmian condition, due to Bousch [6] (p.503).
Proposition 4.2**.**
Let be a Borel function bounded from above.
- (1)
If satisfies the q-Sturmian condition on for some , then is the unique maximizing measure of . 2. (2)
* satisfies the pre-q-Sturmian condition for if and only if is Lipschitzian on and*
[TABLE]
Proof.
These results were stated in [6] for Lipschitzian . But only the Lipschtzian condition on is actually needed. We repeat here the main lines of proofs for the convenience of reading.
(1) It is clear that is attained by the Sturmian measure. On the other hand, any other invariant measure has a support intersecting , by the uniqueness of Sturmian measure supported by . Then by the Sturmian condition.
(2) Let . Assume the pre-Sturmain condition which can be restated as
[TABLE]
By differentiating and iterating, we get
[TABLE]
Since is Lipschitzian, exists almost everywhere and . Letting , we get the following formula
[TABLE]
Then integrate it to obtain
[TABLE]
Now assume and is Lipschitzian on . Then exists almost everywhere on and . Since , the series in (4.4) defines a bounded function then a Lipschitzian function . The computation (4.5) shows that is -periodic. The formula (4.4) can be rewritten as
[TABLE]
In other words, the Lipschitzian function is a constant, say . ∎
In the case , we will first prove that the pre-Sturmian condition is satisfied and then prove that the pre-Sturmian condition implies the Sturmian condition. So, by Proposition 4.2, the maximizing measure of is unique and it is a Sturmian measure.
For any , we are going to look for such that satisfies the pre-Sturmian condition on , i.e. . But can be considered as a -periodic function on . So, set
[TABLE]
and
[TABLE]
The following lemma shows that the equation does have a real solution for every real , so that satisfies the pre-Sturmian condition for any . Actually for every fixed , it will be proved that there exists a unique number such that and that is an almost Lipschitzian homeomorphism from onto .
Lemma 4.3**.**
There is a homeomorphism such that
[TABLE]
Moreover,
- (1)
the function has modulus of continuity . 2. (2)
there exists such that
[TABLE]
Proof.
For each fixed , the function is clearly smooth on and
[TABLE]
where . Thus for each , there is at most one with . On the other hand, observe that for each , for all and for all . See Figure 4 for the graph of and the graph of is nothing but a translation of that of .
As , tends to . Since is supported in , this implies that
[TABLE]
Similarly we show that
[TABLE]
By the Intermediate Value Theorem, for each , there is one with . A similar argument by the Intermediate Value Theorem shows that for each , there is with . It follows that there is a bijective function such that (4.6) holds. By [6] (p. 505), , as a function from to , has modulus of continuity . This, together with the uniform upper bounds on , implies that c is continuous with modulus of continuity . In particular, is a homeomorphism.
Finally the statement (2) holds because is of period and it takes values in . ∎
4.2. Pre-Sturmian condition implies Sturmian condition for
Bousch mentioned that in the case , the pre--Sturmian condition, in practice, often implies the stronger -Sturmian condition. Jenkinson noticed that it is always the case for continuous maps which is strictly concave on . We shall develop further Jenkinson’s argument to show the following:
Proposition 4.4**.**
If satisfies the pre-q-Sturmian condition for some , then satisfies the Sturmian condition for .
The proof of this proposition is complicated and will be postponed to the next section.
4.3. Proof of Theorem 4.1
By Lemma 4.3 above, satisfies the pre--Sturmian condition for some . By Proposition 4.4, satisfies the -Sturmian condition for this . Thus there is a Lipschitz function and a constant such that
[TABLE]
and
[TABLE]
Moreover, by (4.4), there exists depending only on such that By Proposition 4.2, the Sturmian measure is the unique maximizing measure of , Clearly, for all ,
[TABLE]
4.4. is periodic for almost all
Recall that denotes the maximizing measure of (see Theorem 4.1). Let
[TABLE]
Theorem 4.2**.**
*The set is nowhere dense and has Hausdorff dimension zero. *
Proof.
Let c be the function as in Lemma 4.3 and let
[TABLE]
Then . Since c is a homeomorphism, . By Proposition 6.1, has Hausdorff dimension zero. Since c is -Hölder for each , it follows that
[TABLE]
which also implies that is nowhere dense. ∎
Remark 4.5*.*
We learned from Bousch (personal communication) that any bounded subset of has upper Minkowski dimension [math], and hence so does any bounded subset of .
5. Pre-Sturmian condition implies Sturmian condition
The goal of this section is to prove Proposition 4.4 which we restate as
Theorem 5.1**.**
Assume that satisfies the pre-Sturmian condition on for some . Then satisfies the Sturmian condition on .
The pre-Sturmian condition says that there exists Lipschitz function such that
[TABLE]
is constant (denoted by ) on . Let denote the inverse branch of . By Proposition 4.2 and its proof,
[TABLE]
and
[TABLE]
Proving Theorem 5.1 is to check for outside . Before going to details which are unfortunately quite cumbersome, let us describe the strategy. It suffices to show that for some . Put . Then
[TABLE]
The estimate on will be based on the formula defining , which is often a negative number with ‘big’ absolute value and contributes as the ‘main term’. An upper bound on can be deduced from the formula (5.1). An lower bound on can also be deduced from (5.1), although we shall often use simply the fact if .
We will have to distinguish three cases according to the location of . First let us present as follows
[TABLE]
where
[TABLE]
Let also
[TABLE]
So, is the disjoint union of and . Notice is continuous (even analytic) and strictly concave in and it attains its maximal value at . Also notice that so that .
We will check for in different parts of . Since is of length , for any there exists a unique such that . Similarly, for any there exists a unique such that . We will estimate for by for some in (the right half of ), and for by for some in (the left half of ). The interval will be cut into two by and the interval will be cut into two by .
We shall consider the following three cases:
Case I. .
Case II. and ; or and .
Case III. and ; or and .
Note that if , then and we only need to consider Case I, because . Similarly, if then we only need to consider Case I and Case II.
Before going further, let us state two useful elementary facts.
Lemma 5.1**.**
Given , the function is strictly decreasing in .
Proof.
We can continuously extend on [math] by and we have . By direct computation,
[TABLE]
[TABLE]
Therefore on , which implies that is strictly decreasing. ∎
Lemma 5.2**.**
For any , any integer and any , we have
[TABLE]
Proof.
This is of course true for . So assume which implies that . Notice that is increasing on and symmetric about . Then the announced inequality holds because
[TABLE]
and
[TABLE]
∎
5.1. Variation of
The following lemmas give us the estimates for the variations of and . Put
[TABLE]
Lemma 5.3**.**
(i)* For any , we have*
[TABLE]
(i)’* For any , we have*
[TABLE]
(ii)* For any with , we have*
[TABLE]
(ii)’* For with , we have*
[TABLE]
Proof.
We shall only prove (i) and (ii) and leave the analogous (i)’ and (ii)’ for the reader. Let and for each , . By the formula (5.1), we have
[TABLE]
(i) The second inequality is obvious because attains its maximal value at [math]. Let us prove the first inequality. Since and , ’s () are disjoint sets contained in . Together with the fact that is decreasing in , we immediately obtain the following estimate:
[TABLE]
Since is an even function, the desired inequality follows.
(ii) Since is contained in and is decreaing in , we have
[TABLE]
and for each , we simply estimate
[TABLE]
The first inequality follows. The second inequality holds because for any , . ∎
Lemma 5.4**.**
(i)* For any and , we have*
[TABLE]
(i)’* For and , we have*
[TABLE]
Proof.
We only deal with (i). Put which is the right end point of , and . We have . For any , . Hence
[TABLE]
where, for the last inequality, we used the formula (5.1), the facts and is decreasing in . Therefore, integrate to get
[TABLE]
which is equivalent to the desired inequality. ∎
5.2. Proof of in Case I
We deal with Case I in this subsection. The argument is motivated by Jenkinson [25].
Proposition 5.5**.**
For , we have .
Proof.
We only deal with the case as the other case is similar. Put and . Write
[TABLE]
Notice that , we have
[TABLE]
By Lemmas 5.3 (i) and 5.4 (ii), we have
[TABLE]
and
[TABLE]
Therefore is bounded by
[TABLE]
The sum of the third and the forth terms are strictly negative, because is strictly decreasing in and and , so that . Thus we get
[TABLE]
Since
[TABLE]
we conclude that . ∎
Note that the proposition above completes the proof of the theorem in the case .
5.3. Proof of in Case II
The following estimates of are needed in the proofs in Case II and Case III. Recall that .
Lemma 5.6**.**
Assume . Then
[TABLE]
Proof.
Without loss of generality, we assume that . Since is decreasing in , we have
[TABLE]
By (5.2), we obtain
[TABLE]
Since is a smooth and strictly decreasing function in ,
[TABLE]
for all . Therefore, is strictly decreasing in and it suffices to check , i.e.
[TABLE]
Indeed, if , by the mean value theorem we have
[TABLE]
where we have used Lemma 5.1, the inequality over and the fact , and the last inequality can be numerically checked; and if , then , , , , and hence
[TABLE]
∎
The following technical lemma is based on numerical calculation, which is needed to complete the proof in Case II.
Lemma 5.7**.**
Given , the following holds for all and all :
[TABLE]
where
[TABLE]
and
[TABLE]
Proof.
Let , a trapezoid in the plane. Then for any ,
[TABLE]
Thus, as function of , is increasing, and it suffices to check that is negative on the right-hand-side part of the boundary of , i.e.
- (i)
for all . 2. (ii)
for .
Note that
[TABLE]
Let us prove (i). First assume . In this case, we use
[TABLE]
Since
[TABLE]
and
[TABLE]
[TABLE]
we obtain
[TABLE]
Now assume . Then
[TABLE]
Since
[TABLE]
we obtain
[TABLE]
Finally, let us prove (ii). If , then
[TABLE]
where the last inequality holds because for , we check directly; for , we have
[TABLE]
If , then
[TABLE]
where the last inequality can be checked directly. ∎
Proposition 5.8**.**
Suppose that we are in Case II. Then .
Proof.
Once again we only deal with the case , as the other case is similar. Let be the unique point in with , let . We may assume that for otherwise . Let
[TABLE]
so . It suffices to prove that . By Lemma 5.3 (i) and (ii),
[TABLE]
Thus
[TABLE]
where we used Lemma 5.2 to obtain the last inequality. We can apply Lemma 5.2, because , which implies . As Case II only happens when , by Lemma 5.6, we have then . The proof is completed by Lemma 5.7. ∎
5.4. Proof of in Case III
The following lemma is based on numerical calculation which is needed to complete the proof in Case III.
Lemma 5.9**.**
Let be given. For , , we have
[TABLE]
where
[TABLE]
and
[TABLE]
Proof.
It suffices to check that and .
[TABLE]
But
[TABLE]
[TABLE]
When , we have , so . On the other hand,
[TABLE]
where the last inequality holds because: , and when , by Lemma 5.1
[TABLE]
so
[TABLE]
∎
Proposition 5.10**.**
We have in Case III.
Proof.
Once again, we shall only give details for the case when . let . Take such that is a positive integer. We can of course assume for otherwise . Put so that and . Since this case only happens for , by Lemma 5.6, we have . So it suffices to prove
[TABLE]
and then apply Lemma 5.9.
Let us prove (5.4). We have and
[TABLE]
which is a consequence of Lemma 5.2. Hence
[TABLE]
By Lemma 5.3 (i),
[TABLE]
[TABLE]
By Lemma 5.4 (i),
[TABLE]
Note that . Therefore,
[TABLE]
where we used (5.6), (5.7) and (5.8) for the first inequality and (5.5) for the second inequality. ∎
6. Appendix A: -Sturmian measures
In this section we give a proof of the existence and uniqueness of -Sturmian measures and review some relevant facts. Throughout fix an integer and let denote the circle map .
Proposition 6.1**.**
For each , there is a unique -invariant Borel probability measure supported in . We have for each . Moreover, putting
[TABLE]
*then has Hausdorff dimension zero. *
For each , let denote the continuous map which satisfies that and is constant in . So for each . The map is a monotone continuous circle map of degree one and it has a well-defined rotation number . Since is continuous in , is continuous in . For each , is monotone increasing, so is also monotone increasing in . It is well-known that if and only if has periodic points. See [21, Nitecki1971].
Proof.
The existence and uniqueness of are proved in Lemmas 6.2 and 6.3 below. By [37], , so it suffices to show that is countable. Indeed, if , then is a periodic measure and the support is not contained in the interior of , hence either , or is periodic under . Thus is countable. Consequently, . ∎
In the following two lemmas, we treat separately the cases of rational and irrational rotation numbers.
Lemma 6.2**.**
*Suppose that the rotation number is rational. Then has a unique invariant probability measure supported in , and the support of this measure is a periodic orbit of . *
Proof.
Since is rational, all invariant probability measures of are supported on periodic points. So it suffices to show that has a unique periodic orbit contained in . Let be the minimal positive integer such that . Then each periodic point of has period . Let us say that a periodic orbit of is of
- •
type I, if the orbit is contained in the interior of ;
- •
type II, if the orbit intersects ;
- •
type III, if the orbit is contained in but intersects .
A periodic point is said of type I (resp. II, III) if its orbit is of that type. Let us make the following remarks. If is a type I periodic point, then in a neighborhood of , so is two-sided repelling. If is a type II periodic point, then in a neighborhood of , so is two-sided attracting. Since both and are mapped by to the same point , only one of them can be periodic. So there can be at most one periodic orbit of type III, which contains either or , and each point in this orbit is attracting from one-side and repelling from the other side.
First assume that there exists a periodic orbit of type III. Then we show that is the only periodic orbit of . Without loss of generality, assume that the orbit contains . Since for all , there exists no type II periodic point. There cannot be periodic points of type I either, otherwise, there would exist an arc with and a periodic point of type I and with no periodic point in the interior of . This is impossible because is repelling from the right hand side and is repelling from the left hand side (in fact from both sides).
Next assume that there is no periodic orbit of type III, that is to say, all periodic points are of type I or II. Then, by the above remarks, each periodic point is either attracting (from both sides) or repelling from both sides. In particular, there are only finitely many periodic points.Note that if and are two adjacent periodic points, then one of them must be attracting and the other repelling. Thus the number of periodic points of type I is the same as that of type II. Since is constant on , there is only one periodic orbit of type II. It follows that there exists exactly one periodic orbit of type I and exactly one of type II.
We have thus proved that has exactly one periodic orbit contained in . ∎
Lemma 6.3**.**
*Suppose that is irrational. Then there is a unique -invariant Borel probability measure supported in . *
Proof.
By a classical theorem of Poincaré, there exists a monotone continuous circle map of degree one such that . Let
[TABLE]
Since is monotone, is a disjoint family of non-degenerate (closed) arcs in . So is countable. Note that , since is constant in .
Let be a -invariant measure supported by . Then is a -invariant probability measure. Let be an arbitrary -invariant probability measure. Let us prove that for any arc . This will imply that is uniquely ergodic and . Indeed, the image measure is an invariant probability measure of the rigid rotation , which is necessarily the Lebesgue measure, for is irrational. Observe that for each arc ,
[TABLE]
Thus we get because
[TABLE]
∎
7. Appendix B: Computation of and
The theory developed in Section 4 and Section 5 allows us to compute and then for a very large set of ’s. The computation is based on Proposition 4.2, Proposition 4.4 and Theorem 5.1. The method is computer-aided, but the results are exact because the computer is only used to test the signs of two quantities, which don’t need to be exactly computed. We just consider the case .
7.1. Algorithm
Let be an -periodic cycle which is contained in some closed semi-circle. Then the measure is a Sturmian measure. Let
[TABLE]
where and . Then for any , the semi-circle contains the support of the Sturmian measure . We emphasize that each contains a unique Sturmian measure, the same measure for all .
Given a parameter , put . Suppose
[TABLE]
such that
[TABLE]
Then there exists a unique number between and such that . Therefore the Sturmian measure with support in , which is , is the maximizing measure for . Thus
[TABLE]
In practice, we can take as the end points of the interval . We are happy that we don’t need to know what is exactly. See Table 7.4 for the values of for specific ’s.
Since is continuous, for given , (7.2) define an open set of . Thus, if (7.2) holds, then the formula (7.3) holds not only for but also on a neighbourhood of . In particular, is analytic at . For a given cycle, there is an interval on which (7.3) holds. These intervals are shown in Table LABEL:tab-1.
The graph of is shown in Figure 5.
7.2. First time leaving
Let . Then the map is defined by
[TABLE]
See Figure 6 for the branch . See Figure 7 for the graphs of and .
Let us look at . Observe that is symmetric with respect to , i.e. for a.e. . Indeed, is a union of two intervals of length which are symmetric with respect to , and if and if so that it maps two symmetric intervals to two symmetric intervals.
7.3. Some examples
Example 1. is maximizing for and
[TABLE]
This is known to Gelfond [20]. The following is another proof. Recall that in this case
[TABLE]
which contains . As have noticed above, the function is symmetric. On the other hand, is anti-symmetric about . In other words, we have
[TABLE]
It follows that . Thus is the maximizing measure for . It follows that
[TABLE]
Example 2. is maximizing for and
[TABLE]
[TABLE]
In fact, in this case
[TABLE]
Numerical computation shows that . Thus is the maximizing measure for .
Example 3. is maximizing for and
[TABLE]
In this case
[TABLE]
Numerical computation shows that . Thus is the maximizing measure for .
We can get immediately the value of from Example 2, by symmetry (Proposition 3.1). But we would like to remark the maximizing measures for and are different.
Example 4. is maximizing for and
[TABLE]
and
[TABLE]
We have only to check .
7.4. Numerical results
See Table 7.4 for the values of for specific ’s. The graph of is already shown in Figure 5.
We obtain these numerical and graphic results only using periodic Sturmian measures of period . There are totally Sturmian cycles of period . Thus we find -intervals and -intervals of parameter . These intervals are shown in Table LABEL:tab-1. Notice that both and are computed only for or . More results can be obtained if we consider periodic Sturmian measures of period .
For any Sturmian cycle , there is an interval of and an interval of . The value of for is expressed by the formula (7.3).
Values of and for specific ’s
**
- •
****** We don’t compute and if the parameter doesn’t belong to any of the intervals in Table LABEL:tab-1.
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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