Compact embeddings of some weighted
fractional Sobolev spaces on Rn
Qi Han
Department of Science and Mathematics, Texas A&M University at San Antonio
San Antonio, Texas 78224, USA Email: [email protected]
Dedicated to my little angel Jacquelyn and her mother, my dear wife, Jingbo.
Abstract.
In this paper, we study a family of general fractional Sobolev spaces Ms;q,p(Ω) when Ω=Rn or Ω is a bounded domain, having a compact, Lipschitz boundary ∂Ω, in Rn for n≥2.
Among other results, some compact embedding results of MVs;q,p(Rn)↪Lq(Rn) and MVs;q,p(Rn)↪L1(Rn) for suitable potential functions V(x) are described.
2010 Mathematics Subject Classification. 46E35, 35S05, 47A75, 49R05.
Keywords. Fractional Sobolev spaces, compact embedding results, fractional Laplacian eigenvalue problems.
Recently, fractional Sobolev function spaces Ws,p(Rn), and the associated nonlocal equations, attracted great attentions due to their impressive applications to various disciplines, as briefed for example in the introduction of Di Nezza, Palatucci and Valdinoci [9].
See also Chapter 4 of Demengel and Demengel [8] or Chapters 1-2 of Molica Bisci, Radulescu and Servadei [21] for some concise, self-contained discussions of this matter.
In his classical monograph [20, Section 5.1.1], Maz’ya defined the general Sobolev function spaces Wp,q1(Rn); using the notation Mq,p(Rn), the author described some relationships among those spaces and their compact embedding results in [12, 13, 14, 15] with the desire of providing a complement to Lions [19, Lemma I.1] in the sense of function space settings.
In the hope of suggesting a little bit more insight regarding the similarity between W1,p(Rn) and Ws,p(Rn) as observed in [8, 9, 21], this paper is devoted to the description of some general fractional Sobolev function spaces Ms;q,p(Rn) when n≥2, their relations and certain compact embedding results of MVs;q,p(Rn)↪Lq(Rn) and MVs;q,p(Rn)↪L1(Rn) for suitable potentials V(x)≥0.
As expected, Mq,p(Rn) and Ms;q,p(Rn) share several common properties.
In the sequel, we always assume that n≥2, 1≤p,q≤∞, and 0<s<1.
Denote Ω a bounded domain in Rn having a compact, Lipschitz boundary ∂Ω, or Ω=Rn.
Define Ms;q,p(Ω) to be the Banach space as the completion of the set C1(Ω) if Ω is bounded, or as that of the set Cc1(Rn) for Ω=Rn, with respect to the norm
[TABLE]
where ∥u∥q,Ωq:=∫Ω∣u∣qdx and [u]s,p,Ωp:=∫Ω∫Ω∣x−y∣n+sp∣u(x)−u(y)∣pdxdy.
Note Ws,p(Ω)=Ms;p,p(Ω), and if Ω is bounded, Ms;q,∞(Ω)=C0,s(Ω) (independent of q).
From now on, we shall write both continuous embedding of function spaces and convergence of functions by “ → ”, compact embedding of function spaces by “ ↪ ”, and weak convergence of functions by “ ⇀ ”.
Other notations will be specified when appropriate.
Below, let’s embark on the elaboration of our analyses for the spaces Ms;q,p(Ω).
(I.) Ω is a bounded domain with a compact, Lipschitz boundary ∂Ω.
In this case, it is trivial to notice Ms;q,p(Ω)→L1(Ω), so that from the fractional Poincaré’s inequality (see for instance Bellido and Mora-Corral [3, Lemma 3.1], or Drelichman and Durán [11, Estimate (1.3)]), one derives Ms;q,p(Ω)→Ws,p(Ω) in view of Minkowski’s inequality.
This, together with Corollary 4.53 in [8], yields the conclusions listed as follows.
(1.) When sp<n, then we have, with ps∗:=n−spnp,
[TABLE]
Also, there exists a constant Cp,q>0, depending on n,p,q,s,Ω, such that
[TABLE]
(2.) When sp=n, then we have
[TABLE]
and Ms;q,p(Ω) is not a subset of L∞(Ω) by [8, Example 4.25] unless q=∞.
A recent result of Parini and Ruf [23] provides a fractional Moser-Trudinger inequality that says
[TABLE]
Here, α∗,CΩ>0 are constants depending on n,p,s,Ω and W~0s,p(Ω), as a proper subspace of Ws,p(Ω), is the completion of the set Cc1(Ω) with respect to the semi-norm [u]s,p,Rn, which is equivalent to (1) in Rn on this occasion by Brasco, Lindgren and Parini [6, Lemma 2.4].
(3.) When sp>n, then we have, with γs∗:=psp−n,
[TABLE]
Further, via [8, Theorem 4.54] and [9, Theorem 7.1], one easily verifies the result below.
Proposition 1**.**
Assume n≥2, p,q∈[1,∞] and s∈(0,1).
When sp<n, then the embedding ι:Ms;q,p(Ω)→Lr(Ω) is continuous if 1≤r≤max{ps∗,q} and compact if 1≤r<max{ps∗,q}.
When sp≥n, then the embedding ι:Ms;q,p(Ω)↪Lr(Ω) is compact if 1≤r<∞.
Proof.
Via (4) and (6), we only need to consider the case sp<n; this follows almost identically from the proof of [9, Theorem 7.1] seeing (2)-(3).
As a matter of fact, for any cube Q containing Ω, one has for each u∈Ms;q,p(Ω), recalling Ω is an extension domain,
[TABLE]
Here, u~ denotes the extension of u to Ws,p(Rn), and CΩ′,Cp,q′>0 are constants depending on n,p,q,s,Ω.
Therefore, we can follow [9, Theorem 7.1] to complete the proof.
∎
Recall for sp>n, one actually has
[TABLE]
(II.) Ω=Rn.
First, note that Ms;q,p(Rn) represents the Banach space as the completion of the set Cc1(Rn) with respect to the norm (1).
Now, following Lieb and Loss [18, Sections 3.2 and 4.3], a function u∈Lloc1(Rn) is said to vanish at infinity provided that L({x∈Rn:∣u(x)∣≥c})<∞ for each positive constant c>0, with L being the Lebesgue measure.
(1.) When sp<n, denote by Ds,p(Rn) the space of functions u∈Lloc1(Rn), where u vanish at infinity and [u]s,p,Rn<∞.
Then, a careful check of Lemma 6.3 and Theorem 6.5 in [9] implies u∈Lps∗(Rn), and one has the fractional Sobolev inequality, saying that
[TABLE]
Here, C1>0 is an absolute constant depending on n,p,s with 1≤p<∞.
This leads to Ds,p(Rn)=Ms;ps∗,p(Rn)111Equivalently, Ds,p(Rn) is the completion of the set Cc1(Rn) with respect to [⋅]s,p,Rn., and one furthermore has
[TABLE]
using Chebyshev’s inequality and the standard interpolation inequality.
Notice if one would like to have q=∞ included, then u needs to be compactly supported.
(2.) When sp=n, then one has the fractional Gagliardo-Nirenberg inequality (see Nguyen and Squassina [22, Lemma 2.1]) that says
[TABLE]
Here, we only cited a tailored version for our purpose with 1≤q≤r<∞ and θ:=rq∈(0,1], and C2>0 is an absolute constant depending on n,p,q,r,s.
Therefore, we have
[TABLE]
Notice here q=∞ doesn’t contribute to the embedding result (11).
(3.) When sp>n, a careful reading of Theorem 8.2 in [9], especially their Estimates (8.3) and (8.9), suggests Ms;q,p(Rn)→C0,γs∗(Rn) so that Ms;q,p(Rn)→L∞(Rn).
Thus, one has
[TABLE]
Notice Ms;q,∞(Rn)→C0,s(Rn) that is consistent with the observation shown at [9, Page 565], while Ms;∞,p(Rn) is the largest possible space for fixed p,s in (12).
Proposition 2**.**
Let n≥2, p∈[1,∞], q∈[1,∞) and s∈(0,1).
If sp<n, then the embedding ι:Ms;q,p(Rn)→Lr(Rn) is continuous for min{ps∗,q}≤r≤max{ps∗,q}.
If sp=n or sp>n, then the embedding ι:Ms;q,p(Rn)→Lr(Rn) is continuous for q≤r<∞ or q≤r≤∞.
(III.) A fractional Moser-Trudinger type inequality on Ms;q,p(Rn) when sp=n.
In this section, we employ the preceding result in [23] to characterize a possible extension of (5) to Rn concerning functions u∈Ms;q,p(Rn) when sp=n.
The proof presented here follows basically from Ruf [24] and do Ó [10] (see also Li and Ruf [17], and Iula [16] among many other important contributions on Rn, which cannot be exhaustively listed here).
We now recall some essential facts about Schwarz symmetrization by Berestycki and Lions [4, Appendix III], Lieb and Loss [18, Section 3.3], and Beckner [2, Theorem 3].
Let f(x) be a Borel measurable function vanishing at infinity in the sense of Lieb and Loss, and let f∗(x)(≥0) be the Schwarz symmetrization or spherical rearrangement of f(x) such that L({x∈Rn:∣f(x)∣≥c})=L({x∈Rn:f∗(x)≥c}) for all positive constants c>0.
Notice f∗(x) is unique, radial, decreasing in ∣x∣, and lower semi-continuous (so measurable).
Also, we have
[TABLE]
for all continuous functions Φ with Φ(∣f∣) integrable; so, ∥f∗∥q,Rn=∥f∥q,Rn when f∈Lq(Rn) for 1≤q≤∞.
Besides, one has
[TABLE]
For f∗(x)∈Lq(Rn), Berestycki-Lions’ radial lemma [4, Lemma A.IV] leads to
[TABLE]
for all x=0, where ωn−1 presents the surface area of the unit sphere in Rn.
We next prove a result following [10, Lemma 1] and [24, Proposition 2.1] via the Ms;q,p(Rn)-norm, which may be viewed as a fractional Moser-Trudinger inequality on Ms;q,p(Rn).
Theorem 3**.**
Assume n≥2, 1≤q<∞, 0<s<1, sp=n, 0≤α<α∗, and u∈Ms;q,p(Rn).
Then, there is an absolute constant C(α,q,s)>0 depending on α,n,q,s such that
[TABLE]
Here, for v≥0 and the least positive integer β0 with n−sβ0n≥q≥1, Ψα,q,s(v):=ℓ=β0∑∞ℓ!αℓvn−sℓn.
Proof.
To save notation, assume without loss of generality u≥0.
Via u∗, and seeing (13), (14) and Ψα,q,s(u∗)≥0, we can simply consider u=u∗ and decompose
[TABLE]
Here and hereafter, BR is the ball of radius R in Rn centered at the origin and BRc:=Rn∖BR, while R0>0 is a sufficiently large absolute constant to be determined later.
To estimate the integral over BR0, write v(x):=max{u(∣x∣)−u0,0} for u0:=u(R0)>0, a constant.
Then, v≡0 on BR0c and v∈W~0s,p(BR0), since by Lemma 2.4 of [6]
[TABLE]
follows; seeing u(∣y∣)≤u0 when ∣y∣≥R0, one has (36R0)nVn∥v∥p,BR0p≤[v]s,p,Rnp≤[u]s,p,Rnp≤1.
Here, Vn presents the volume of the unit ball in Rn, and BR0(x0) denotes a ball of radius R0 in BR0c centered at some point x0 with ∣x0∣=4R0.
Notice [10, Estimate (5)] yields (1+t)n−sn≤tn−sn+K1tn−ss+1 for all t∈(0,∞) with K1>0 an absolute constant.
Actually, for f(t):=tn−ss(1+t)n−sn−tn−sn−1 that is continuous on (0,∞), one sees t→0limf(t)=0 as n≥2>2s, while using t~:=t1 one sees t→∞limf(t)=n−sn.
Next, for t=u0v(x), it follows that un−sn≤{v+u0}n−sn≤vn−sn+K1vn−ssu0+u0n−sn.
Apply Young’s inequality to K1vn−ssu0 to observe, for an absolute constant K2>0,
[TABLE]
Define u~:=v(1+u0sn)nn−s∈W~0s,p(BR0) and notice [u~]s,p,Rn≤(1+u0sn)nn−s[v]s,p,Rn, so that by the discussions after (17) it leads to [u~]s,p,Rnp≤(1+u0sn)sn−s(1−∥u∥q,Rn)sn.
From (15), u0sn≤σ∥u∥q,Rnsn for \sigma:=\bigl{(}\frac{n}{\bm{\omega}_{n-1}R^{n}_{0}}\bigr{)}^{\frac{n}{qs}}.
Write g(t):=(1+σtsn)sn−s(1−t)sn−1 and take g^{\prime}(t)=\frac{n}{s}(1+\sigma t^{\frac{n}{s}})^{\frac{n-2s}{s}}(1-t)^{\frac{n-s}{s}}\bigl{(}\frac{n-s}{s}\sigma t^{\frac{n-s}{s}}-\frac{n}{s}\sigma t^{\frac{n}{s}}-1\bigr{)}, with g(0)=0 and g(1)=−1.
Define h(t):=sn−sσtsn−s−snσtsn−1 with h′(t0)=0 for t_{0}:=\bigl{(}\frac{n-s}{n}\bigr{)}^{2}.
So, when R0 is so large that \sigma\leq\bigl{(}\frac{n}{n-s}\bigr{)}^{\frac{2n-s}{s}}, then one sees h(t)≤0 and hence g′(t)≤0 on [0,1].
That is, g(t)≤0 for 0≤t≤1, which clearly implies [u~]s,p,Rn≤1 provided R^{n}_{0}\geq\frac{n}{\bm{\omega}_{n-1}}\bigl{(}\frac{n-s}{n}\bigr{)}^{\frac{q(2n-s)}{n}}.
As a result, one can combine this with (5) and (18) to deduce
[TABLE]
Here, C1(α,q,s)>0 is an absolute constant depending on α,n,q,s.
To estimate the integral over BR0c, one applies (15) with ∥u∥q,Rn≤1 to observe
[TABLE]
For n−sβ0n≥q, one employs Proposition 2 to the starting term in Ψα,q,s(u) and thus
[TABLE]
Here, C2(α,q,s)>0 is an absolute constant depending on α,n,q,s.
Accordingly, (16) follows for C(α,q,s):=max{C1(α,q,s),C2(α,q,s)}>0.
∎
(IV.) Some compact embedding results regarding MVs;q,p(Rn)↪LKr(Rn).
Let V(x)>0 be a Lebesgue measurable function in Rn such that DinfV(x)≥VD>0 for all compact subsets D⋐Rn.
Take n≥2, p∈[1,∞], q∈[1,∞), and s∈(0,1).
When sp<n, we designate MVs;q,p(Rn) to be the Banach space as the completion of the set Cc1(Rn) with respect to the norm ∥u∥MVs;q,p(Rn):=∥u∥LVq(Rn)+[u]s,p,Rn where ∥u∥LVq(Rn)q:=∫Rn∣u∣qVdx, so that MVs;q,p(Rn) is a subspace of Ds,p(Rn).
When sp≥n, we further require RninfV(x)≥V0>0 and define MVs;q,p(Rn) similarly, so that MVs;q,p(Rn) is a subspace of Ms;q,p(Rn).
One recalls that some closely related results on W1,p(Rn) may be found in Chiappinelli [7, Theorem 1], Schneider [25, Theorem 2.3], and Bonheure and Van Schaftingen [5, Theorem 4].
Yet, it seems that the results presented here are not available even on Ws,p(Rn).
(1.) When sp<n, we can prove some compact embedding results listed below.
Theorem 4**.**
Assume n≥2, 1≤p≤∞, 0<s<1 with sp<n, and 1≤q≤r<ps∗.
Let K(x),V(x)>0:Rn→R be two Lebesgue measurable functions such that K(x)∈Lt(Ω) for some t\in\bigl{(}\frac{p^{*}_{s}}{p^{*}_{s}-r},\infty\bigr{]} on each set Ω of Rn with L(Ω)<∞ and K(x)V−τ(x) vanishes at infinity for τ:=ps∗−qps∗−r.
Then, the embedding MVs;q,p(Rn)↪LKr(Rn) is compact.
Proof.
Without loss of generality, assume {ul:l≥1} is a sequence of functions in MVs;q,p(Rn) with ul⇀0 when l→∞ and ∥ul∥MVs;q,p(Rn) uniformly bounded.
For each ϵ>0, set \mathbf{W}_{\epsilon}:=\bigl{\{}x\in\mathbf{R}^{n}:K(x)V^{-\tau}(x)\geq\epsilon\bigr{\}} and Wϵc:=Rn∖Wϵ to decompose
[TABLE]
For the integral over Wϵc, as ps∗r−qτ=1−τ=ps∗−qr−q∈[0,1), it is easy to derive
[TABLE]
in view of (8), with C1′>0 an absolute constant independent of ul for any l≥1.
For the integral over Wϵ, noticing L(Wϵ)<∞ and the fact that BRinfV(x)≥VBR>0 yields the embedding MVs;q,p(BR)→Ms;q,p(BR)↪Lt−1rt(BR) with t−1rt∈[r,ps∗), we deduce
[TABLE]
as R→∞ and l→∞ for a subsequence of {ul:l≥1} using the same notation.
Notice the embedding MVs;q,p(Rn)→LKr(Rn) is continuous provided ps∗−rps∗≤t≤∞.
Hence, plugging (20) and (21) altogether back to (19) finishes our proof completely.
∎
Theorem 5**.**
Assume n≥2, 1≤p≤∞, 0<s<1 with sp<n, and 1≤ps∗≤r<q.
Let K(x),V(x)>0:Rn→R be such that K(x)∈Lt(Ω) for some t\in\bigl{(}\frac{q}{q-r},\infty\bigr{]} on each set Ω of Rn with L(Ω)<∞, RninfV(x)≥V0>0, and K(x)V−τ(x) vanishes at infinity for τ:=q−ps∗r−ps∗.
Then, the embedding MVs;q,p(Rn)↪LKr(Rn) is compact.
Proof.
The proof is a minor modification of Theorem 4 using the embeddings MVs;q,p(Rn)→Ms;q,p(Rn)→Lq(Rn) and MVs;q,p(BR)→Ms;q,p(BR)↪Lt−1rt(BR) for t−1rt∈[r,q).
There is no need for change in (20) while the only change in (21) is replacing ps∗ by q.
One also notices the embedding MVs;q,p(Rn)→LKr(Rn) is continuous provided q−rq≤t≤∞.
∎
Theorem 6**.**
Assume n≥2, 1≤p≤∞, 0<s<1 with sp<n, and 1≤ps∗≤r<q.
Let K(x),V(x)>0:Rn→R satisfy K(x)∈Lloct(Rn) for some t\in\bigl{(}\frac{q}{q-r},\infty\bigr{]} and K(x)V−τ(x)→0 uniformly for τ:=q−ps∗r−ps∗.
Then, the embedding MVs;q,p(Rn)↪LKr(Rn) is compact.
Proof.
Assume {ul:l≥1} is a sequence of functions in MVs;q,p(Rn) with ul⇀0 when l→∞ and ∥ul∥MVs;q,p(Rn) uniformly bounded.
Then, one can decompose
[TABLE]
For the integral over BR, seeing that BRinfV(x)≥VBR>0 yields the embedding MVs;q,p(BR)→Ms;q,p(BR)↪Lt−1rt(BR) with t−1rt∈[r,q), one deduces
[TABLE]
as l→∞ for a subsequence of {ul:l≥1} using the same notation.
For the integral over BRc, one deduces, similar to (20),
[TABLE]
as R→∞.
So, ul→0 in LKr(Rn) for a subsequence relabeled with the same index l.
Notice the embedding MVs;q,p(Rn)→LKr(Rn) is continuous provided K(x)∈Lloct(Rn) for q−rq≤t≤∞ and K(x)V−τ(x) is eventually bounded at infinity for τ=q−ps∗r−ps∗.
∎
Finally, let’s consider the case where 1≤r<min{ps∗,q} uncovered in the preceding results.
Theorem 7**.**
Assume n≥2, 1≤p≤∞, 0<s<1 with sp<n, and 1≤r<min{ps∗,q}≤max{ps∗,q}<∞.
Let K(x),V(x)>0 satisfy K(x)∈Lloct(Rn) for some t\in\bigl{(}\frac{\max\{p^{*}_{s},q\}}{\max\{p^{*}_{s},q\}-r},\infty\bigr{]} and Kψps∗(τ)(x)V−τ(x)∈L1(Rn) for ψps∗(τ):=ps∗−rps∗+τ(ps∗−q) and some \tau\in\bigl{[}0,\frac{r}{q-r}\bigr{]}.
Then, the embedding MVs;q,p(Rn)↪LKr(Rn) is compact.
Proof.
Write x=ps∗+τ(ps∗−q)τ(ps∗−r), y=ps∗+τ(ps∗−q)r+τ(r−q) and z=ps∗+τ(ps∗−q)ps∗−r with x+y+z=1.
Now, set r1=x−1, r2=y−1 and r3=z−1 to see, for u∈MVs;q,p(Rn) on all domains Ω in Rn,
[TABLE]
by Hölder’s inequality and (8) with ps∗=r2(r−qx), provided x,y,z∈(0,1).
To have x<1, one sees 0<τ<q−rps∗ when q≤ps∗, and either 0<τ<q−rps∗ or q−ps∗ps∗<τ<∞ when q>ps∗.
To have x>0, one sees 0<τ<∞ when q≤ps∗, and 0<τ<q−ps∗ps∗ when q>ps∗.
To have y>0, one sees 0<τ<q−rr when q≤ps∗, and either 0<τ<q−rr or q−ps∗ps∗<τ<∞ when q>ps∗.
To have y<1, one sees 0<τ<∞ when q≤ps∗, and 0<τ<q−ps∗ps∗ when q>ps∗.
Notice x=τz.
To have z<1, one sees 0<τ<∞ when q≤ps∗, and either 0<τ<q−ps∗r or q−ps∗ps∗<τ<∞ when q>ps∗.
Summarize the above analyses to conclude that \tau\in\bigl{(}0,\frac{r}{q-r}\bigr{)}.
We certainly can take y=0 and see τ=q−rr without having ps∗ involved, and may also take x=τ=0 corresponding to MVs;q,p(Rn)=Ds,p(Rn) with V(x)≡0.
Next, one has r1q+r2ps∗=qx+ps∗y=r and thus the embedding MVs;q,p(Rn)→LKr(Rn), when replacing Ω in (24) by Rn, is continuous (even for max{ps∗,q}−rmax{ps∗,q}≤t≤∞).
Finally, using the same {ul:l≥1}, one sees the decomposition (22) and the estimate (23), because MVs;q,p(BR)→Ms;q,p(BR)↪Lt−1rt(BR) with t−1rt∈[r,max{ps∗,q}).
For the integral over BRc, we apply (24) on Ω=BRc to derive, as R→∞,
[TABLE]
Thus, ul→0 in LKr(Rn) for a subsequence relabeled with the same index l.
∎
Notice in Theorems 4 and 6, we do not need RninfV(x)≥V0>0, which appeared in Theorem 5.
This condition can be replaced by an integrability condition as in Theorem 7.
Corollary 8**.**
Let n≥2, p∈[1,∞], s∈(0,1) with sp<n, 1≤ps∗≤r<q, and K(x),V(x)>0:Rn→R with K(x)∈Lloct(Rn) for some t\in\bigl{(}\frac{q}{q-r},\infty\bigr{]} and Kψps∗(τ)(x)V−τ(x)∈L1(Rn) for some \tau\in\bigl{[}\frac{r}{q-r},\infty\bigr{)}.
Then, the embedding MVs;q,p(Rn)↪LKr(Rn) is compact.
Proof.
The proof is essentially the same as that of Theorem 7.
One keeps in mind q>r≥ps∗ when ensuring x,y,z∈(0,1).
In fact, to see x>0, one has τ>q−ps∗ps∗ and to see x<1, one has τ>q−rps∗; to see y>0, one has τ>q−rr and to see y<1, one has τ>q−ps∗ps∗; to see z<1, one has τ>q−ps∗r.
Summarizing these leads to \tau\in\bigl{(}\frac{r}{q-r},\infty\bigr{)} while y=0 implies τ=q−rr without involving ps∗.
Notice MVs;q,p(Rn)→LKr(Rn) is continuous for q−rq≤t≤∞.
∎
(2.) When sp≥n, we similarly have the compact embedding results as follows.
Recall the fractional Gagliardo-Nirenberg inequality in [22, Lemma 2.1] says that
[TABLE]
Here, n≥2, 1<p≤∞, 1≤q<∞, 0<s<1, r1=(1−θ)npn−sp+θq1 with θ∈[0,1], and r lies in between q and ps∗ when sp<n while q≤r<∞ when sp≥n, with C2>0 an absolute constant depending on n,p,q,r,s.
Theorem 9**.**
Assume n≥2, 1≤p≤∞, 0<s<1 with sp≥n, and 1≤q≤r<∞.
Let K(x),V(x)>0:Rn→R be such that K(x)∈Lt(Ω) for some t∈(1,∞] on each set Ω of Rn with L(Ω)<∞, RninfV(x)≥V0>0, and K(x)V−τ(x) vanishes at infinity for some τ∈(0,1) if q<r or τ=1 if q=r.
Then, the embedding MVs;q,p(Rn)↪LKr(Rn) is compact.
Proof.
First, note the continuous embedding MVs;q,p(Rn)→Ms;q,p(Rn).
Employing the same notations as in Theorem 4, and seeing 1−τr−qτ≥q and (19), one derives, like (20),
[TABLE]
by virtue of (25), with C2′>0 an absolute constant independent of ul for any l≥1.
Moreover, seeing MVs;q,p(BR)→Ms;q,p(BR)↪Lt−1rt(BR) with t−1rt∈[r,∞), one observes that, for some \tilde{t}\in\bigl{(}\frac{t}{t-1},\infty\bigr{]} with \lim\limits_{\tilde{t}\to\infty}\Bigl{(}\int_{\mathbf{R}^{n}}|u_{l}|^{r\tilde{t}}\,\mathbf{d}x\Bigr{)}^{\frac{1}{\tilde{t}}}=\int_{\mathbf{R}^{n}}|u_{l}|^{r}\,\mathbf{d}x, like (21),
[TABLE]
as R→∞ and l→∞ for a subsequence of {ul:l≥1} using the same notation.
Note the embedding MVs;q,p(Rn)→LKr(Rn) is continuous if t−1t≤t~≤∞.
∎
Theorem 10**.**
Assume n≥2, 1≤p≤∞, 0<s<1 with sp≥n, and 1≤r<q<∞.
Let K(x),V(x)>0:Rn→R satisfy K(x)∈Lloct(Rn) for some t∈(1,∞], RninfV(x)≥V0>0, and Kψq~(τ)(x)V−τ(x)∈L1(Rn) for ψq~(τ):=q~−rq~+τ(q~−q), some q~∈(q,∞), and some \tau\in\bigl{(}0,\frac{r}{q-r}\bigr{]}.
Then, the embedding MVs;q,p(Rn)↪LKr(Rn) is compact.
Proof.
First, note the continuous embedding MVs;q,p(Rn)→Ms;q,p(Rn).
Employing the same notations as in Theorem 7 with x~=q~+τ(q~−q)τ(q~−r), y~=q~+τ(q~−q)r+τ(r−q) and z~=q~+τ(q~−q)q~−r for an arbitrarily chosen q~∈(q,∞) plus r~1=x~−1, r~2=y~−1 and r~3=z~−1, and seeing (25), one derives, like (24), the continuous embedding MVs;q,p(Rn)→LKr(Rn) since r~1q+r~2q~=qx~+q~y~=r.
In addition, similar calculations lead to \tau\in\bigl{(}0,\frac{r}{q-r}\bigr{]}.
Finally, using the same {ul:l≥1}, one sees the decomposition (22) and the estimate (23), because MVs;q,p(BR)→Ms;q,p(BR)↪Lt−1rt(BR) with t−1rt∈[r,∞).
For the integral over BRc, one analogously has, as R→∞,
[TABLE]
Thus, ul→0 in LKr(Rn) for a subsequence relabeled with the same index l.
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(3.) Some applications.
One feels free to set either V(x)≡1 or K(x)≡1 to see some compact embedding results, in particular, MVs;q,p(Rn)↪Lq(Rn) and MVs;q,p(Rn)↪L1(Rn) for appropriate weight functions V(x); when p=q, one has WVs,p(Rn)↪Lp(Rn) and WVs,p(Rn)↪L1(Rn).
Finally, following Servadei and Valdinoci [26, Section 3] (see also [21, Section 3.1]) or applying Auchmuty [1], for the standard fractional Laplacian (−Δ)s, the eigenvalue problems
[TABLE]
as well as the eigenvalue problems
[TABLE]
if sp<n, possess families of eigenvalues {λk>0:k≥1} and {δl>0:l≥1}, and sequences of associated eigenfunctions {fk∈WVs,2(Rn):k≥1} and {gl∈Ds,2(Rn):l≥1}, respectively, by virtue of Theorem 4 (when taking p=q=r=2 to work in Hilbert spaces) and Theorem 7 (when taking V(x)≡0 and p=r=2 to work in Hilbert spaces).
λ1,δ1 are simple, λk,δl have finite multiplicities, and {λk>0:k≥1} and {δl>0:l≥1} are increasing with k→∞limλk=∞ and l→∞limδl=∞.
Besides, f1,g1 are nonnegative in Rn, and the sequences {fk∈WVs,2(Rn):k≥1} and {gl∈Ds,2(Rn):l≥1} provide orthogonal bases to the spaces WVs,2(Rn),LK2(Rn) and Ds,2(Rn),LK~2(Rn), respectively.
The procedure is standard now, with details left for the interested reader.