Uniform local well-posedness and inviscid limit for the Benjamin-Ono-Burgers equation
Mingjuan Chen, Boling Guo, Lijia Han

TL;DR
This paper establishes uniform local well-posedness and inviscid limit results for the Benjamin-Ono-Burgers equation in a refined Sobolev space, advancing understanding of its behavior for small initial data.
Contribution
It proves uniform local well-posedness and inviscid limit behavior for the Benjamin-Ono-Burgers equation in a novel refined Sobolev space, handling low and high-frequency components.
Findings
Uniform local well-posedness for small data in the refined Sobolev space
Inviscid limit behavior in the same function space
Handling of low-frequency scaling criticality
Abstract
In this paper, we study the Cauchy problem for the Benjamin-Ono-Burgers equation , where denotes the Hilbert transform. We obtain that it is uniformly locally well-posed for small data in the refined Sobolev space (), whose low-frequency part is scaling critical and high-frequency part is equal to Sobolev space (). Furthermore, we also obtain its inviscid limit behavior in ().
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Taxonomy
TopicsAdvanced Mathematical Physics Problems · Navier-Stokes equation solutions · Nonlinear Waves and Solitons
Uniform local well-posedness and inviscid limit for the Benjamin-Ono-Burgers equation
**Mingjuan Chena, Boling Guoa, Lijia Han*b,*111Corresponding author.
***a. Institute of Applied Physics and Computational Mathematics, Beijing 100088, PR China;
b. Department of Mathematics and Physics, North China Electric Power University, Beijing 102206, PR China.
Emails: [email protected]; [email protected]; [email protected]
**Abstract. In this paper, we study the Cauchy problem for the Benjamin-Ono-Burgers equation , where denotes the Hilbert transform. We obtain that it is uniformly locally well-posed for small data in the refined Sobolev space (), whose low-frequency part is scaling critical and high-frequency part is equal to Sobolev space (). Furthermore, we also obtain its inviscid limit behavior in ().
**
**Keywords: Benjamin-Ono-Burgers equation; Cauchy Problem; Inviscid limit behavior.
**
**2010 MSC: 35Q53, 35Q55, 35A01.
**
1 Introduction
In this paper, we study the Cauchy problem for the Benjamin-Ono-Burgers (BOB) equation on the real line
[TABLE]
where , is a real-valued function of , is the Hilbert transform operator defined as follows
[TABLE]
When , the equation (1.1) reduces to the classical Benjamin-Ono(BO) equation
[TABLE]
which was originally derived as a model in the study of one-dimensional long internal gravity waves in deep stratified fluids with great depth [2, 20]. The BOB model (1.1) was obtained by Ewdin and Roberts [3] in the study of intense magnetic flux tubes of the solar atmosphere. The dissipative effects in that literature are due to weak thermal conduction, where is a measure of the importance of thermal conduction and is assumed small.
Recently, there are many authors who devoted themselves to studying the well-posedness theory and limit behavior of BO and BOB equations. The best result so far for global well-posedness of BO equation was proved by Ionescu and Kenig [7] in Sobolev space , . For BOB equation, thanks to the dissipative effects, there are many results about its wellposedness. Otani [21] derived the global well-posedness in for by using the Picard methods. Vento [24] proved this result is critical in the sense that the mapping data-solution fails to be continuous if . For more results, we refer to [1, 9, 10, 11, 12, 13, 15, 16, 17, 19, 22, 23] and the references therein. However, if we consider the uniform well-posedness and inviscid limit for the solutions of BOB equation, the dissipative effects which related to could not be used.
In [23], Tao conjectured it is feasible to prove that the solutions of BOB equation converge to those of BO equation when . Motivated by [7] and [23], Guo and his co-authors [5] obtained that BOB equations were uniformly globally well-posed in for and the solutions of BOB converged to those of BO in ) for any . This result was improved to the energy space by Molinet [14]. In the light of [7], it seems natural to obtain the limit behavior of the real-valued solutions to BOB equation in , . To the best of our knowledge, the limit behavior of BOB equation in () is still open. Our main goal in this paper is to fill the gap between and .
We obtain that BOB equation is uniformly locally well-posed for small data in the refined Sobolev space (), whose low-frequency part is scaling critical and high-frequency part is equal to Sobolev space (). In fact, the high-frequency part has already reduced to , while the low-frequency part has some special structure. For BO equation, the special structure can be eliminated by performing a gauge transformation in [7]. However, this gauge transformation is not available for BOB equation, due to the dissipative structure. We notice that both [5] and [14] did not apply gauge transformation.
The basic ideas for the inviscid limit are to get the uniform well-posedness and difference estimates. We first use similar spaces as that in [7] which considered BO equation to obtain the bilinear estimates. In order to weaken the interaction between very low and very high frequencies, which is out of control by standard Bourgain method, we assume that low-frequency functions have some additional structure(see the definitions of , and ). To avoid the logarithmic divergences we work with high-frequency functions that have two components: a weighted -type component(see ) and a normalized component(see ) which related to smoothing effect. This type of spaces have been used in [7, 8] and the references about wave maps therein.
Different from [7], we have to construct the uniform homogeneous and inhomogeneous linear estimates for BOB equation. The dissipative structure destroys some symmetries and brings some logarithmic divergences, which will bring several technical difficulties to obtain the uniform estimates. In order to avoid the logarithmic divergence, the homogeneous dyadic decomposition is performed to construct the low-frequency space . Specifically, we need to conquer the singularity which occurs in low-frequency low-modulation cases, when treating . We lead the readers to Lemma 3.2 and the proof of Lemma 3.3. We believe that these techniques can be used in some other problems.
Let () denote the (inverse) Fourier transform operators on . Let () and () denote the (inverse) Fourier transform operators with respect to the space variable and the time variable respectively. We introduce the initial data spaces , :
[TABLE]
where are the symbols of nonhomogeneous dyadic decomposition operators, and the Banach space is defined by
[TABLE]
where are the symbols of homogeneous dyadic decomposition operators. It is easy to see from the definitions that , . Moreover, from the scaling point of view, we have
[TABLE]
where . In fact, the spaces are scaling critical for the low-frequency part, due to for any . Because of this, the inequality (1.5) could not be improved and we can only allow small initial data.
Let with the induced metric. Let denote the nonlinear mapping that associates to any data the corresponding classical solution of the initial value problem (1.1). For any Banach space and , let denote the open ball . Our main theorem states uniform local well-posedness of the BOB initial-value problem (1.1) for small data in , .
Theorem 1.1
(a) For any , there exists a constant with the property that for any there is a unique solution
[TABLE]
of the initial-value problem (1.1).
(b) For any , the mapping extends (uniquely) to a Lipschitz mapping
[TABLE]
uniformly on with the property that is a solution of the initial-value problem (1.1).
(c) For any we have the local Lipschitz bound which is independent of
[TABLE]
for any and . As a consequence, the mapping restricts to a locally Lipschitz mapping
[TABLE]
uniformly on .
(d) For any , denote the solution mapping of the initial-value problem (1.2), then we have the limit behavior
[TABLE]
Notations. In the sequel will denote a universal positive constant which can be different at each appearance. (for , ) means that , and stands for and . () denotes the (inverse) Fourier transform. also denotes the Fourier transform of a distribution .
2 Function spaces and known results
At the beginning, let us recall the dyadic decomposition. Denote . Let denote an even smooth function supported in and equal to in . For let , supported in , and
[TABLE]
For simplicity of notation, let if and if . Also, for let
[TABLE]
For any and we define the operator by the formula
[TABLE]
By a slight abuse of notation we also define the operators on by the formula . For let . For let if and if . For and let
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For let denote the dispersive relation of BO equation, i.e.,
[TABLE]
Definition 2.1
We define the Banach spaces , : for we define
[TABLE]
where
[TABLE]
For we define
[TABLE]
The choices of the coefficients and the large factor are important in order to get the bilinear estimates. The spaces are not sufficient for our purpose, due to various logarithmic divergences involving the modulation variable. For and we also define the Banach spaces .
Definition 2.2
For we define
[TABLE]
where is the unit imaginary number. For we define
[TABLE]
Remark 2.3
The definition of is different from that in [7, 8]. It is easy to see that the space in this paper is smaller than the corresponding space (denote it by ) in [7, 8], whose norm is given by
[TABLE]
We use the homogeneous dyadic decomposition to avoid the logarithmic divergences which occur in getting uniform estimates of Benjamin-Ono-Burgers equation.
Definition 2.4
We define our basic Banach spaces .
[TABLE]
In some estimates we will also need the space , .
Definition 2.5
[TABLE]
For let
[TABLE]
Definition 2.6
For we define the Banach spaces , and :
[TABLE]
and
[TABLE]
We establish some basic properties and known estimates which are similar to that in [7]. Using the definitions, if and then can be written in the form
[TABLE]
such that is supported in and is supported in (if then ). If then can be written in the form
[TABLE]
such that is supported in and is supported in .
Lemma 2.7
(a) If , , and then
[TABLE]
(b) If , , and then
[TABLE]
(c) If , , and is supported in then
[TABLE]
Lemma 2.8
If , , and then
[TABLE]
As a consequence,
[TABLE]
3 Uniform linear estimates
In this section, we construct the uniform homogeneous and inhomogeneous linear estimates for BOB equation. The dissipative structure destroys some symmetries and brings some logarithmic divergences, which will bring several technical difficulties.
For , let denote the solution of the free Benjamin-Ono-Burgers evolution given by
[TABLE]
where is defined in (2.1). Assume is an even smooth function supported in and equal to in . In the following discussions, the implicit constant in inequality sign “ ” is independent of . We first prove a uniform estimate for the free solution.
Lemma 3.1
If and then for any ,
[TABLE]
where the constant is independent of .
Proof. It follows from the definition of that
[TABLE]
In view of the definition of , it suffices to prove that
[TABLE]
Denote , we have
[TABLE]
(1) , proof of (3.2). From (3.4) we have
[TABLE]
Write , where is supported in , then
[TABLE]
and (3.5) is controlled by
[TABLE]
We divide the first term in (3.7) into two parts as follows
[TABLE]
For the term , by the definition and Young’s inequality, we know that
[TABLE]
It suffices to prove that
[TABLE]
and
[TABLE]
We divide them into and two cases. If , by Hölder’s inequality and Taylor’s expansion we know that
[TABLE]
Similarly, combining with Hausdorff-Young inequality, we can get
[TABLE]
where we used the fact that . If , then . For any fixed , we have
[TABLE]
and
[TABLE]
Therefore, one can get the conclusion (3.9) and (3.10). For the term , by the definition, the mean value theorem, and Taylor’s expansion, for some , we have
[TABLE]
In view of (3.8)-(3.11), we can get that
[TABLE]
For the second term in (3.7), recall that is supported in , from the definition and Taylor’s expansion, we can obtain that for any fixed ,
[TABLE]
Therefore, combining (3.5)-(3.7) and (3.12)-(3.13), we obtain the conclusion (3.2).
(2) , proof of (3.3). For any , by the change of variables and Hölder’s inequality, we get
[TABLE]
It suffices to show that for any ,
[TABLE]
where the implicit constant is independent of and . By using Plancherel’s equality and the fact that
[TABLE]
we know that if , then for any ,
[TABLE]
To prove (3.14) we may assume in the summation. Using the para-product homogeneous decomposition, we have
[TABLE]
Now we take and . For , it follows from Hölder’s inequality and (3.15) that
[TABLE]
Then by discrete Young’s inequality we can get
[TABLE]
[TABLE]
where we used the facts that and . For , it follows from Bernstein’s estimate, Hölder’s inequality and (3.15) that
[TABLE]
Now we obtain the conclusion (3.14) and then complete the proof of (3.3).
Before giving the inhomogeneous linear estimates, we state an important lemma, which will conquer the singularity when treating . In addition, this lemma will effectively simplify the proof of uniform inhomogeneous estimates.
Lemma 3.2
If one of the following two assumptions holds:
(1) , is supported in such that ;
*(2) , is supported in such that ,
then for any ,*
[TABLE]
In particular, we have
[TABLE]
Proof. (1) . By the definition of , it suffices to prove that
[TABLE]
In view of Plancherel’s theorem and the support of , we only need to prove that
[TABLE]
The function in the left-hand side of (3.18) is not zero only if . By symmetry, we may assume . Rewrite
[TABLE]
For , by integration by parts, it is easy to show that
[TABLE]
where we used the fact .
For , the case is trivial, thus we just consider . Indeed, let
[TABLE]
then by the fact
[TABLE]
we can get
[TABLE]
Therefore,
[TABLE]
whose norm is bounded, then we get the conclusion (3.18).
(2) . By the definition of , we need to show that for any ,
[TABLE]
Combining the Plancherel’s theorem with Young’s inequality, it suffices to prove that
[TABLE]
Similar to (1), we may assume and rewrite
[TABLE]
Notice that
[TABLE]
then we can get (3.19) in the same way as we used in (1). The proof is completed.
For the inhomogeneous linear operator, we have the following uniform estimates.
Lemma 3.3
If and , then for any ,
[TABLE]
where the constant is independent of .
Proof. By the definitions, it suffices to prove that ,
[TABLE]
From a straightforward calculation, we have
[TABLE]
Let , and for . For let
[TABLE]
In view of (3)-(3.22), to prove (3.20), we only need to prove that
[TABLE]
(1) Case .
(1-) Assume first that . The idea of this part is essential due to [18] and [4]. Denote and . Then,
[TABLE]
It suffices to prove that
[TABLE]
We divide into four parts:
[TABLE]
When , the denominator in the fraction is far from 0, then is bounded, see the parts and . When , we could use Taylor’s expansion for the numerator to cancel the denominator, see the parts and . We now estimate the contributions of . Firstly, we consider the contribution of .
[TABLE]
where we use the inequality (3.14). Secondly, we consider the contribution of .
[TABLE]
where we used the facts that and are multiplication algebras and that and . Thirdly, we consider the contribution of . By Taylor’s expansion, we obtain
[TABLE]
where in the last inequality we used the fact . Finally, we consider the contribution of . For , the denominator in the fraction is far from 0, we can easily get that
[TABLE]
where we use the inequality (3.14) and . For , using Taylor’s expansion, we have
[TABLE]
Now we have shown that
[TABLE]
(1-) Assume now that , . From (2.14), we know that , thus we may assume that is supported in the set . For convenience, we decompose
[TABLE]
then (3.22) becomes
[TABLE]
We can use (3.26) to control the third term in (3). Notice that
[TABLE]
then we have from (3.26) that
[TABLE]
For the first and second terms in (3), it suffices to prove that
[TABLE]
and
[TABLE]
Thanks to Lemma 3.2, we know that
[TABLE]
then we can make the proof clearer and simpler. To prove (3.30) and (3.31), we just need to prove
[TABLE]
and
[TABLE]
The inequality (3.32) has been obtained by Ionescu and Kenig in [7]. For the sake of completeness, we give the rigorous proof. For the low modulation part, we divide it into two subparts:
[TABLE]
Then the left-hand side of (3.32) is dominated by
[TABLE]
For , we use Lemma 2.7 (c) to bound it by
[TABLE]
as desired. For , from (3.29) we can get
[TABLE]
For , let , then
[TABLE]
Finally, to prove (3.33), we define the modified Hilbert transform operator
[TABLE]
Notice that
[TABLE]
Hence by Plancherel’s theorem and Hölder’s inequality, we have , uniformly in . We notice that if then can be written in the form
[TABLE]
From (3.14) and a change of variables, the left-hand side of (3.33) is dominated by
[TABLE]
the proof of (3.33) is completed. Thus we have shown that
[TABLE]
(2) Case .
(2-a) Assume first that . Similar to , we still denote and . Due to , it follows immediately that and . The similar argument as , we still divide into four parts:
[TABLE]
We first consider the contribution of . By the definition of and Taylor’s expansion, we obtain
[TABLE]
For , we just take Taylor’s expansion to , then use the factor to eliminate the denominator and get the conclusion similar to . We then consider the contribution of . Due to the algebraic structure of , we know
[TABLE]
Finally, we consider the contribution of ,
[TABLE]
Now we have obtained that
[TABLE]
(2-b) Assume now that is supported in . We analyze two cases: and . When , it follows that , thus the denominator is far from origin and there is no singularity. When , the singularity occurs so that we must handle this case more carefully.
If , we get that due to . We rewrite
[TABLE]
and divide each term into two parts:
[TABLE]
[TABLE]
We claim that
[TABLE]
Indeed, by the definition of and Plancherel’s theorem, we have
[TABLE]
For , if , we know that , thus by using Young’s inequality, we can get that
[TABLE]
For , we could use Hölder’s inequality and Young’s inequality to obtain that
[TABLE]
Now the claim (3.34) is obtained, as desired.
For the term , from (3.34) we only need to show that
[TABLE]
By the definition of , Plancherel’s theorem and Hölder’s inequalities, to prove (3.35), it suffices to prove that
[TABLE]
Using the facts that and , it is easy to get from integration by parts that
[TABLE]
which implies (3.36).
The estimates of the term can be achieved by using the results before. For , from (3.12) we see that
[TABLE]
Furthermore, (3.35) and (3.37) lead to .
If , the singularity occurs by the reason that is near origin. We rewrite
[TABLE]
Lemma 3.2 yields that for part we only need to prove
[TABLE]
A simple calculation shows that
[TABLE]
Because of and , we write
[TABLE]
where
[TABLE]
Therefore, to prove (3.38), we just need to show that for any
[TABLE]
and
[TABLE]
In fact, for and , if , we have . Thus, Minkowski’s inequality and Hölder’s inequality give that
[TABLE]
where we used the fact that . In addition, we can easily get that
[TABLE]
This completes the proof of (3.38).
For part , in order to eliminate the singularity, we will divide it into three sub-parts. Due to Taylor’s expansion, we have
[TABLE]
Let
[TABLE]
[TABLE]
and
[TABLE]
Next we will prove that , and . For , we use , which comes from Taylor’s expansion, to cancel the denominator , and use , which comes from the mean value theorem, to absorb the big weight in the definition of . Specifically, by using the mean value theorem and Taylor’s expansion, for some , we have
[TABLE]
For , there is a small factor as . We use one to cancel the denominator , and another to absorb the big weight in the definition of . Thus we can get
[TABLE]
For , notice that
[TABLE]
by the proof of Lemma 3.2, we have that
[TABLE]
Therefore,
[TABLE]
Now we have proved that
[TABLE]
Therefore, we complete the proof of Lemma 3.3.
4 Bilinear estimates
In this section we state the main bilinear estimates. We show first the dyadic bilinear estimates in spaces .
Lemma 4.1
() Assume , , , and . Then
[TABLE]
Lemma 4.2
() Assume , , , and for any . Then
[TABLE]
Lemma 4.3
() Assume , , , , and . Then
[TABLE]
Lemma 4.4
() Assume have the property that , , and . Then
[TABLE]
Moreover, any spaces in the right-hand side of (4.4) can be replaced with .
The main proofs of Lemmas 4.1-4.4 are already given in [7, Sections 7 and 8] and [8, Lemma 3.3]. The same argument of bilinear estimates as [7, 8] works, except for the estimates corresponding to . We only need to consider that appears in the left-hand side of bilinear estimates, since the norm of in this paper is larger than that in [7, 8]. Therefore, we only provide a proof of Lemma 4.4.
Proof of Lemma 4.4. We only consider and . If or , we may replace the spaces in the right-hand side of (4.4) with . A comparison of () and indicates that the proofs of the cases or are identical to the proofs in the corresponding cases or . Therefore we may assume , is supported in , and is supported in . Clearly, , and . It suffices to prove that
[TABLE]
By using the definitions, the left-hand side of (4.5) is dominated by
[TABLE]
We first estimate the term . If , from Hölder’s inequality and Plancherel’s theorem, we know that
[TABLE]
If , by examining the supports of the functions, we know that . Therefore we assume and , then
[TABLE]
We next estimate the term . By Plancherel’s theorem and Hölder’s inequality, we achieve that
[TABLE]
This completes the proof of (4.5).
With these dyadic bilinear estimates in hand, we can use para-product to decompose the bilinear product, and divide it into several cases according to the interactions. The idea is similar to that in [7, Section 10], so we omit the details and just state the main bilinear estimates for functions in spaces .
Proposition 4.5
If and then
[TABLE]
5 Proof of Theorem 1.1
In this section we complete the proof of Theorem 1.1. In terms of the uniform estimates Lemma 3.1 and Lemma 3.3, bilinear estiamtes Proposition 4.5, the proofs of Theorem 1.1 (a), (b) and (c) are similar to that in [8], thus we only give the ideas. For any interval , , , and we define the normed spaces
[TABLE]
With this notation, the uniform estimates in Lemma 3.1 and Lemma 3.3 become
[TABLE]
and
[TABLE]
By combining Proposition 4.5 we obtain
[TABLE]
for any , . Finally, the estimate (2.17) becomes
[TABLE]
Given , we construct a solution of (1.1) by iteration:
[TABLE]
In the following discussion, we assume that is sufficiently small. By using (5.1) and (5.3), we get easily that
[TABLE]
by induction over . Using (5.3) with , (5.5) and (5.6), we can show that
[TABLE]
by induction over . Next, we can obtain that
[TABLE]
and
[TABLE]
For , the bound (5.8) and (5.10) follow in the same way as the bound (5.6) and (5.7), by combining (5.1), (5.3), and induction over . For , we write , , , and argue by induction over similar to Section 4 in [8] to complete the proofs of (5.8) and (5.10). Therefore, we can use (5.10) and (5.4) to construct
[TABLE]
In view of (5.5),
[TABLE]
so is a solution of the initial-value problem (1.1), which completes the proof of Theorem 1.1 (a). For Theorem 1.1 (b) and (c), similar to above argument, we can get easily that for then
[TABLE]
which implies Theorem 1.1 (b) and (c).
Finally, we prove Theorem 1.1 (d), i.e. the inviscid limit behavior in , . Assume , let and denote the nonlinear mappings that associate to any initial data the corresponding solutions of the Cauchy problem (1.1) and (1.2). For convenience, we only give the proof of the case , since the proofs of the case are similar. It suffices to prove
[TABLE]
We know that
[TABLE]
where is the solution of the free Benjamin-Ono evolution. In terms of (5.2), (5.3), (5.13), and (5.14), we have
[TABLE]
Similar to (5.6), we have , and . Combining that with the definitions , and (5.8), (5) becomes
[TABLE]
In terms of (5.4), we have shown that
[TABLE]
We now prove (5.12). , it follows from the Lipschitz continuity that there exists a such that
[TABLE]
Fixing , by taking sufficiently small, we can get from (5.17) that
[TABLE]
Therefore, we have
[TABLE]
which implies (5.12). The proof of Theorem 1.1 is completed.
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