On the discrete spectrum of Schroedinger operators with Ahlfors regular potentials in a strip
Martin Karuhanga

TL;DR
This paper provides quantitative upper bounds on the number of eigenvalues below the essential spectrum for Schroedinger operators with Ahlfors regular potentials in a strip, considering Robin and Dirichlet boundary conditions, using weighted norms.
Contribution
It introduces new upper estimates for eigenvalues of Schroedinger operators with Ahlfors regular potentials, expressed via weighted L^1 and Orlicz norms, for different boundary conditions.
Findings
Eigenvalue bounds depend on weighted L^1 norms of potentials.
Orlicz norms provide alternative estimates.
Results apply to operators with Robin and Dirichlet boundary conditions.
Abstract
In this paper, quantitative upper estimates for the number of eigenvalues lying below the essential spectrum of Schroedinger operators with potentials generated by Ahlfors regular measures in a strip subject to two different types of boundary conditions (Robin and Dirichlet respectively) are presented. The estimates are presented in terms of weighted L^1 norms and Orlicz norms of the potential.
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Taxonomy
TopicsSpectral Theory in Mathematical Physics · Advanced Mathematical Modeling in Engineering · Numerical methods in inverse problems
On the discrete spectrum of Schrödinger operators with Ahlfors regular potentials in a strip
Martin Karuhanga111Department of Mathematics, Mbarara University of Science and Technology, P.O BOX 1410, Mbarara, Uganda, E-mail: [email protected], ORCID : 0000-0002-7254-9073
Abstract
In this paper, quantitative upper estimates for the number of eigenvalues lying below the essential spectrum of Schrödinger operators with potentials generated by Ahlfors regular measures in a strip subject to two different types of boundary conditions (Robin and Dirichlet respectively) are presented. The estimates are presented in terms of weighted norms and Orlicz norms of the potential.
Keywords: Discrete spectrum; Schrödinger operators; Ahlfors regular potential; strip.
Mathematics Subject Classification (2010): 35P05, 35P15
1 Introduction
Let . According to the Cwikel-Lieb-Rozenblum (CLR) inequality (see, e.g., [3, 25]), the number of negative eigenvalues of the Schrödinger operator on with is estimated above by . In the case , this estimate fails, but there has been significant recent progress in obtaining estimates of the CLR-type in two-dimensions and the best known estimates have been obtained in [26]. Estimates for the number of negative eigenvalues of Schrödinger operators with potential of the form , where is a Radon measure and is an appropriate function, were obtained in [6], and results from [26] were extended to this setting in [13, 16]. In the present paper, we obtain estimates for the number of eigenvalues below the essential spectrum of a Schrödinger operator with potential of the form similar to those in [16] in a strip subject to boundary conditions of the Robin type. Similar estimates are also obtained when the domain of the operator is characterized by Dirichlet boundary conditions (see remark 6.4). Below is a precise description of the operator studied herein.
Let be a strip, a -finite positive Radon measure on and a non-negative function integrable on bounded subsets of with respect to . We study the following Schrödinger operator
[TABLE]
where , subject to the following Robin boundary conditions
[TABLE]
where . Here denotes the partial derivative of with respect to and note that does not have to be the two-dimensional Lebesgue measure. A physical motivation to this problem is closely related to the study of spectral properties of quantum waveguides (see, e.g., [8, 9, 18, 21, 24]).
Under certain assumptions about and , (1) is well defined and self-adjoint on and its essential spectrum is the interval , where is the first eigenvalue of considered along the width of the strip with boundary conditions (2) (see, e.g., [2, 12, 18, 29]). For a detailed discussion about what is, see e.g. [14]. The case where both and are equal to zero with being the two-dimensional Lebesgue measure has been previously studied by A. Grigor’yan and N. Nadirashvili [11] who obtained estimates in terms of weighted norms and norms of . Below, we prove stronger results in our more general setting.
Let be a Hilbert space and let be a Hermitian form with a domain . Set
[TABLE]
where denotes a linear subspace of . The number is called the Morse index of in . If is the quadratic form of a self-adjoint operator with no essential spectrum in , then is the number of negative eigenvalues of repeated according to their multiplicity (see, e.g., [4, S1.3] or [5, Theorem 10.2.3]).
Estimating the number of eigenvalues of (1) below its essential spectrum is equivalent to estimating the number of negative eigenvalues of the operator
[TABLE]
subject to boundary conditions in (2). Now, defining (4) via its quadratic form we have
[TABLE]
Note that we take the closure of the open strip in the terms involving as this measure might charge subsets of the horizontal lines and .
We denote by the number of negative eigenvalues of (4) counting multiplicities.
Let Then it follows from the variational principle [13, Lemma 1.6.2] (see also [7, Ch.6, 2.1, Theorem 4] for the case when is absolutely continuous with respect to the Lebesgue measure) that
[TABLE]
where are the restrictions of the form to . Let , where is an eigenfunction of considered along the width of the strip with boundary conditions (2) corresponding to the first eigenvalue . Then it is easy to see that
[TABLE]
and since , the right-hand side is strictly negative unless
[TABLE]
So, one usually has and thus the right-hand side of (6) diverges. To avoid this, we shall split the problem into two problems. The first will be defined by the restriction of the form to the subspace of functions obtained by multiplying by functions depending only on , and is thus reduced to a well studied one-dimensional Schrödinger operator. The second problem will be defined by a class of functions orthogonal to in the inner product.
2 Notation
In order to state the estimate for , we need some notation from the theory of Orlicz spaces (see, e.g., [1, 17, 22]). Let and be mutually complementary -functions, and let , be the corresponding Orlicz spaces. We will use the following norms on
[TABLE]
and
[TABLE]
These two norms are equivalent
[TABLE]
(see [1]).
Note that
[TABLE]
Indeed, since is convex and increasing on , and , we get for any ,
[TABLE]
(see [26]). It follows from (10) with that
[TABLE]
We will also need the following equivalent norm on with , which was introduced in [27]:
[TABLE]
We will use the following pair of mutually complementary -functions
[TABLE]
Definition 2.1**.**
Let be a positive Radon measure on . We say the measure is Ahlfors regular of dimension if there exist positive constants and such that
[TABLE]
for all diam(supp) and all , where is the ball of radius centred at , and the constants and are independent of the balls.
Definition 2.2**.**
(Local Ahlfors regularity)* We say that a measure is locally Ahlfors regular on a bounded set if for every there exist and positive constants and such that*
[TABLE]
for all and all . We say that is locally Ahlfors regular on the strip if (15) holds for all and all , and there exist constants such that
[TABLE]
Thus for each ,
[TABLE]
From now onwards, it will be assumed that is a -finite positive Radon measure that is locally Ahlfors regular on .
3 Statement of the main result
Let
[TABLE]
[TABLE]
where is a normalized eigenfunction of on with boundary conditions (2) corresponding to the first eigenvalue (here the normalization is with respect to the Lebesgue measure).
Theorem 3.1**.**
Let be a -finite positive Radon measure on that is locally Ahlfors regular on and for every . Then there exist constants such that
[TABLE]
4 Auxiliary results
We start with a result that was obtained in [16] (see also [13, Lemma 3.1.1]). For the reader’s convenience, we reproduce the proof here.
Lemma 4.1**.**
Let be a -finite Radon measure on such that for all . Let
[TABLE]
where is a line in in the direction of the vector . Then is at most countable.
Proof.
Let
[TABLE]
where is the ball of radius centred at [math]. Then
[TABLE]
It is now enough to show that is at most countable for . Suppose that is uncountable. Then there exists a such that
[TABLE]
is infinite. Otherwise, would have been finite or countable. Now take . Then
[TABLE]
Since contains at most one point, then
[TABLE]
Let
[TABLE]
Then and . So
[TABLE]
But
[TABLE]
which implies
[TABLE]
This contradiction means that is at most countable for each . Hence is at most countable. ∎
Corollary 4.2**.**
There exists such that and .
Proof.
The set
[TABLE]
is at most countable. This implies that there exists a . Thus . ∎
Let be a bounded set with Lipschitz boundary such that . Let be the smallest square containing with sides chosen in the directions and from Corollary 4.2, and let be the closed square with the same centre as and sides in the same direction but of length times that of . Let
[TABLE]
There exists a bounded linear operator
[TABLE]
which satisfies
[TABLE]
(see, e.g., [28, Ch.VI, Theorem 5]). We will use the following notation:
[TABLE]
where is a set of a finite two dimensional Lebesgue measure .
The following result is similar to [13, Lemma 3.2.13] and follows directly from the proof of the latter.
Lemma 4.3**.**
Let be as above and be a -finite positive Radon measure on that is locally Ahlfors regular on . Choose and fix a direction satisfying Corollary 4.2. Further, for all and for all , let be a square with edges of length in the chosen direction centred at . Then for any and any there exists a finite cover of by squares , such that and
[TABLE]
for all with , where the constant depends only on and is invariant under parallel translations of , depends only on in (15), and is the diameter of . If , one can take .
Let
[TABLE]
for all .
Let be the eigenvalues of the above boundary value problem. By the Min-Max principle, we have
[TABLE]
where is a normalized eigenfunction corresponding to . The function does not depend on and, viewed as a function of one variable , it is a normalized eigenfunction of on with boundary conditions (2) corresponding to the first eigenvalue , moreover (see [14] or [13, Section 1.5]).
It follows from the above that for all , one has
[TABLE]
which in turn implies
[TABLE]
Since , one gets
[TABLE]
Lemma 4.4**.**
[Ehrling’s Lemma]* Let be Banach spaces such that is compact and . Then for every , there exists a constant such that*
[TABLE]
See, e.g., [23] for details and proof.
Let be the class of all functions such that for any multi-index and any ,
[TABLE]
Denote by the dual space of . For , let
[TABLE]
Here, is the Fourier image of defined by
[TABLE]
Let
[TABLE]
[TABLE]
Now, let in Lemma 4.4. That is compact follows from the Sobolev compact embedding theorem (see, e.g., [1, Ch. VII] or [20, 1.4.6]). Thus we have the following lemma:
Lemma 4.5**.**
Let be given. Then there exists a constant such that
[TABLE]
Proof.
In this proof, we make use of (22) and Lemma 4.4. For , the trace theorem and Lemma 4.4 imply
[TABLE]
Take . Then
[TABLE]
Hence (22) yields
[TABLE]
where
[TABLE]
∎
As a consequence of Lemma 4.5 and (22) we have the following Lemma
Lemma 4.6**.**
There exists a constant such that
[TABLE]
Proof.
[TABLE]
where
[TABLE]
∎
Let and , where
[TABLE]
and
[TABLE]
Then is a projection since .
Lemma 4.7**.**
For all for almost all .
Proof.
Since , then
[TABLE]
∎
Lemma 4.8**.**
For all and .
Proof.
[TABLE]
Since for every , one has for all ,
[TABLE]
and hence it follows from the above that
[TABLE]
∎
Lemma 4.9**.**
Let
[TABLE]
Then
[TABLE]
Proof.
[TABLE]
Integration by parts and Lemma 4.7 give
[TABLE]
Thus, this together with Lemma 4.8 yield
[TABLE]
This means that for all
[TABLE]
∎
5 Proof of Threorem 3.1
Let
[TABLE]
and
[TABLE]
Then one has
[TABLE]
where and are the restrictions of the form to the spaces and respectively. We start by estimating the first term in the right-hand side of (27).
Recall that for all (see (26)). Let be an arbitrary interval in and let
[TABLE]
Then
[TABLE]
On the subspace , one has
[TABLE]
But
[TABLE]
which implies
[TABLE]
Hence, we have the following one-dimensional Schrödinger operator
[TABLE]
Let
[TABLE]
[TABLE]
Then
[TABLE]
(see [13, (2.42)], see also the estimate before (39) in [26]). To write the above estimate in terms of the original measure, let
[TABLE]
Then . Hence
[TABLE]
Next, we consider the subspace . By (22) and (25), one has
[TABLE]
for all .
Let , with be the set in Lemma 4.3 and be defined as above (see the paragraph after Corollary 4.2). For each , intersects not more than rectangles to the left of and rectangles to right of , where depends only on and in Corollary 4.2. (It is not difficult to see that the side length of is less than or equal to and hence provides an upper estimate for .) Then (17) implies
[TABLE]
where
[TABLE]
Now it follows from Lemma 4.3 that for any
[TABLE]
for all satisfying the orthogonality conditions in Lemma 4.3, where the constant is independent of , , and . Hence (31) implies
[TABLE]
for all satisfying the orthogonality conditions, where
[TABLE]
Let
[TABLE]
(see (21)). Taking in (32), one has
[TABLE]
where (see [13, Lemma 3.2.14]). Again, taking (and ; see Lemma 4.3) in (32), we get
[TABLE]
for all . If , then
[TABLE]
Otherwise, (34) implies
[TABLE]
where .
Let (see Section 3). Then for any , the variational principle (see (6)) implies
[TABLE]
Thus (27), (30) and (35) imply (18).
6 Concluding remarks
Remark 6.1**.**
Recall that a sequence belongs to the “weak -space” (Lorentz space) if the following quasinorm
[TABLE]
is finite. It is a quasinorm in the sense that it satisfies the weak version of the triangle inequality:
[TABLE]
(see, e.g., [10] for more details).**
Theorem 6.2**.**
(cf. [26, Theorem 9.2])* Let . If , then .*
Proof.
Consider the function
[TABLE]
. Let . Then by a computation similar to the one leading to (28) we get
[TABLE]
Now
[TABLE]
It follows from the above that if , .
One can define functions for similarly to the above and extend to them the previous estimate. The fact that and have disjoint supports if implies that
[TABLE]
(see [26, Theorem 9.1]). If , then
[TABLE]
which implies
[TABLE]
With , we have
[TABLE]
where . ∎
Remark 6.3**.**
Suppose that , the Lebesgue measure. Then
[TABLE]
Let and write and instead of and respectively. Further, let
[TABLE]
Then, using [26, Lemma 7.6] in place of our Lemma 4.3, one gets
[TABLE]
This estimate is stronger than (18). Indeed, suppose that . Since satisfies the -condition, then (see (9.21) in [17]). Using (9) and (12), we have
[TABLE]
The scaling , allows one to extend the above inequality to an arbitrary .
By the same procedure as the one leading to (56) in [15], one has the following estimate
[TABLE]
where
[TABLE]
Estimates (37) and (39) are equivalent to each other but the advantage of the latter is that it separates the contribution to the eigenvalues of from that of . The condition is necessary and sufficient for the semi-classical behaviour of the estimate coming from the subspace (see Theorem 6.2 above). In addition, if , then one gets an analogue of [19, Theorem 1.1], i.e.,
[TABLE]
if and only if . **
Remark 6.4**.**
One can think of the Dirichlet boundary conditions as the limit of the boundary conditions in (2) as and tend to infinity. In this case,
[TABLE]
Let . Then for all , one has an analogue of (22)
[TABLE]
Also, similarly to Lemma 4.6, there is a constant such that
[TABLE]
Now, for all , let
[TABLE]
Then an orthogonal projection (cf. Lemma 4.9). Let and . Furthermore, let
[TABLE]
Then similarly to (27), we have
[TABLE]
where and are the restrictions of the form to the subspaces and respectively. For an arbitrary interval on , let
[TABLE]
Then on the subspace , a procedure similar to the one leading to (30) gives an estimate for the first term in (42), where in this case is given by
[TABLE]
On the subspace , it follows from (40) and (41) that there is a constant such that
[TABLE]
Thus, we obtain, similarly to (35), an estimate for the second term in (42). **
7 Acknowledgments
The author acknowledges the funding from the Commonwealth Scholarship Commission in the UK, grant UGCA-2013-138. The author is also very grateful to Eugene Shargorodsky for his valuable guidance and discussions during the preparation of this work.
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