On the complex conjugate zeros of the partial theta function
Vladimir Petrov Kostov

TL;DR
This paper characterizes the location of complex conjugate zeros of the partial theta function for q in (-1,1), providing bounds on their real and imaginary parts for different q ranges.
Contribution
It establishes precise bounds on the complex conjugate zeros of the partial theta function depending on the parameter q, extending understanding of its zero distribution.
Findings
Zeros for q in (0,1) lie within specified bounds in the complex plane.
Zeros for q in (-1,0) are confined within a particular rectangle.
The results provide explicit regions where zeros can be located.
Abstract
We prove that 1) for any , all complex conjugate pairs of zeros of the partial theta function belong to the set ~Re\,~Im\, and 2) for any , they belong to the rectangle ~Re\,~Im\,.
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Taxonomy
TopicsAdvanced Mathematical Identities · Analytic Number Theory Research · Mathematical functions and polynomials
On the complex conjugate zeros of the partial theta function
Vladimir Petrov Kostov
Université Côte d’Azur, CNRS, LJAD, France
e-mail: [email protected]
Abstract
We prove that 1) for any , all complex conjugate pairs of zeros of the partial theta function belong to the set Re Im and 2) for any , they belong to the rectangle Re Im .
Key words: partial theta function, Jacobi theta function, Jacobi triple product
AMS classification: 26A06
1 Introduction
For any fixed (), the sum of the bivariate series is an entire function in called the partial theta function. We remind that the Jacobi theta function equals and that . We consider the case when is real. In the present note we prove the following theorem:
Theorem 1**.**
(1) For any , all complex conjugate pairs of zeros of belong to the set Re Im .
(2) For any , all complex conjugate pairs of zeros of belong to the set Re Im .
One of the most recent applications of is connected with a problem on section-hyperbolic polynomials, i.e. real univariate polynomials with all roots real and such that all their truncations of positive degree have also all their roots real. Inspired by classical results of Hardy, Petrovitch and Hutchinson (see [6], [16] and [7]), the study of the problem was continued in [15], [8] and [14]. Other areas of application of are modularity and asymptotics of regularized characters and quantum dimensions of the -singlet algebra modules (see [3] and [5]), the theory of (mock) modular forms (see [4]), Ramanujan-type -series (see [18]), asymptotic analysis (see [2]) and statistical physics and combinatorics (see [17]); see also [1].
The following properties of are proved in [10]: For each , the function has infinitely-many negative and no nonnegative zeros. There exists a sequence of values of (tending to ) for which has exactly one multiple zero. This is the rightmost of its (negative) zeros; it is a double one. For , has exactly complex conjugate pairs of zeros counted with multiplicity.
Analogous properties for read (see [11]): For each , the function has infinitely-many negative and infinitely-many positive zeros. There exists a sequence of values of (tending to , the largest of which is ) for which has exactly one multiple zero; it is a double one. This is the rightmost of its negative zeros for odd and the second from the left of its positive zeros for even. For , all zeros of are real.
2 Proof of Theorem 1
Proof of part (1).
We write “CCP” for “complex conjugate pair (of zeros of )”. We use a result of [12]: For any , all zeros of belong to the domain \{{\rm Re}~{}x<0,|{\rm Im}~{}x|<132\}$$\cup$$\{{\rm Re}~{}x\geq 0,|x|<18\}. To prove part (1) of Theorem 1 means to show that the real parts of the CCPs are . The proof is based on a comparison between the functions , and . Obviously, . For the function we use the following formula (derived from the Jacobi triple product, see [9]):
[TABLE]
Consider the functions , and restricted to the vertical line in the -plane Re , which avoids the zeros of . The product is minimal for (because for , and , one has and ). Obviously,
[TABLE]
When , the right-hand side is maximal for . If for given and one has
[TABLE]
then the inequality , hence , holds true along and the function has no zeros on the line . We set , where . We set also and , if .
Lemma 2**.**
For , and , one has (hence ).
Proof.
For , one has and for , , . Denote by the product and set . Thus
[TABLE]
with equality only for . Both factors and can be minorized by their respective values and for , so and
[TABLE]
At the same time, for and for , the majoration of (see (1)) is maximal for , , in which case it equals .
For , we use the inequality which holds true for , see Lemma 4 in [9]. As in the case , one obtains , . The product is represented in the form (with as above), where
[TABLE]
It is clear that ; the rightmost inequality follows from , . Set , , and . The factor is minorized by . The function is decreasing on , with and , therefore . Hence
[TABLE]
The function is increasing on , so . For one obtains
[TABLE]
∎
Lemma 3**.**
For , the double zero of belongs to the interval .
Proof.
We use a result of [13]: Consider the function with , , . Set . Then for and for , there exists exactly one (and simple) zero of satisfying the conditions , no zero is of modulus , and exactly zeros counted with multiplicity are of modulus .
Hence for , for any multiple zero of one has . Indeed, the quantity is maximal for and no multiple zero of is of modulus . For , the sequence is decreasing, and , so for , any double zero of is in . ∎
Simple zeros of (real or complex) depend continuously on . Two simple real zeros of coalesce for to become a complex pair for (as we say, a pair born from the double zero of ), see [10]. For each fixed, the line is to the right of . As increases, the number increases and moves from left to right. For any , the line , , is to the left of the double zero of , see [14] or [10]; one has Re and Re . Recall that . Hence for , there is exactly one CCP, the one born from the double zero of . For , there are no zeros of on , so as increases from to , the line does not encounter the only CCP of and thus there are no CCPs on and to the left of .
Thus there are no CCPs on and to the left of . One has Re , Re and Re (here and below the values , and of are chosen for the convenience of computation). As increases from to , the line moves from Re to Re and encounters no zeros of on its way. As CCPs can be born only on the interval , for , no CCPs are born to the left of . For , there are no CCPs with Re , and for , there are no CCPs with Re .
One has Re and Re . For , the line encounters no zeros of and it does not intersect , so there are no CCPs on and to the left of it. One has Re and Re . Thus there are no CCPs on and to the left of for . One has Re , therefore there are no CCPs on and to the left of for , hence there are no CCPs in Re for .
Consider the numbers , . These are the values of for . The sequence is increasing, with and . Hence for , . For , there is at least one number , , in the interval ; this follows from . The corresponding line contains no zeros of for ; this results from Lemma 2 and from for . For each line , , it is true that for , there are no CCPs on and to the left of it. As increases in , the line might begin to intersect the interval , but it is always true that any line , , which does not intersect has no CCPs on it and to its left (and there is at least one such line for Re ). Hence there are no CCPs for and Re . ∎
Proof of part (2).
We use again a result of [12]: For any , all zeros of belong to the strip . We have to show that the real part of any complex zero of belongs to the interval . For , we consider in the same way the intervals , . We set . For , we consider the vertical lines Re and Re , . As increases, the line moves to the right and moves to the left. We compare the factors , and in cases A) , Re and B) , Re ; we denote them by , , , , or according to the case. Clearly, Im Im , Im Im and either or , either Re Re or Re Re and either Re Re or Re Re . Hence .
The majoration (1) of remains valid. The quantity takes the same values for , so along and . The double zero of , , belongs to the interval (with and , see [11]); this follows from and , see Lemma 3 and its proof.
One has , , so for , . For , there exists a number with (because ) and a line (resp. ) with no CCPs on and to the left (resp. right) of it. By analogy with the case one shows that for , the moduli of the real parts of the complex zeros of are bounded by . ∎
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