Rothe method and numerical analysis for history-dependent hemivariational inequalities with applications to contact mechanics
Stanislaw Migorski, Shengda Zeng

TL;DR
This paper develops a numerical approach using the Rothe method to solve complex history-dependent hemivariational inequalities, with applications to contact mechanics involving viscoelastic materials and frictional contact.
Contribution
It introduces a novel numerical scheme with error estimates for solving history-dependent hemivariational inequalities, including an application to a contact mechanics problem.
Findings
Proved unique solvability and regularity of the inequality.
Derived optimal error estimates for the numerical scheme.
Applied the method successfully to a contact mechanics problem.
Abstract
In this paper an abstract evolutionary hemivariational inequality with a history-dependent operator is studied. First, a result on its unique solvability and solution regularity is proved by applying the Rothe method. Next, we introduce a numerical scheme to solve the inequality and derive error estimates. We apply the results to a quasistatic frictional contact problem in which the material is modeled with a viscoelastic constitutive law, the contact is given in the form of multivalued normal compliance, and friction is described with a subgradient of a locally Lipschitz potential. Finally, for the contact problem we provide the optimal error estimate.
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Taxonomy
TopicsContact Mechanics and Variational Inequalities · Mechanical stress and fatigue analysis · Gear and Bearing Dynamics Analysis
Rothe method and numerical analysis for history-dependent hemivariational inequalities with applications to contact mechanics ††thanks:
Project supported by the European Union’s Horizon 2020 Research and Innovation Programme under the Marie Skłodowska-Curie grant agreement No. 823731 CONMECH, the National Science Center of Poland under Maestro Project No. UMO-2012/06/A/ST1/00262, and National Science Center of Poland under Preludium Project No. 2017/25/N/ST1/00611. It is also supported by the International Project co-financed by the Ministry of Science and Higher Education of Republic of Poland under Grant No. 3792/GGPJ/H2020/2017/0.
Stanisław Migórski111 College of Applied Mathematics, Chengdu University of Information Technology, Chengdu, 610225, Sichuan Province, P.R. China, and Jagiellonian University in Krakow, Chair of Optimization and Control, ul. Lojasiewicza 6, 30348 Krakow, Poland. E-mail address: [email protected]. Tel.: +48-12-6646666. and Shengda Zeng222 Jagiellonian University in Krakow, Faculty of Mathematics and Computer Science, ul. Lojasiewicza 6, 30348 Krakow, Poland. Corresponding author. E-mail address: [email protected]; [email protected]; [email protected]. Tel.: +86-18059034172.
Abstract. In this paper an abstract evolutionary hemivariational inequality with a history-dependent operator is studied. First, a result on its unique solvability and solution regularity is proved by applying the Rothe method. Next, we introduce a numerical scheme to solve the inequality and derive error estimates. We apply the results to a quasistatic frictional contact problem in which the material is modeled with a viscoelastic constitutive law, the contact is given in the form of multivalued normal compliance, and friction is described with a subgradient of a locally Lipschitz potential. Finally, for the contact problem we provide the optimal error estimate.
Key words. Hemivariational inequality; Clarke subgradient; history-dependent operator; Rothe method; finite element method; error estimates; viscoelastic material; frictional contact.
**2010 Mathematics Subject Classification. ** 35L15, 35L86, 35L87, 74Hxx, 74M10.
1 Introduction
In this paper we are concerned with the existence and uniqueness of a solution to an abstract evolutionary hemivariational inequality which involve a history-dependent operator of the form
[TABLE]
for all , a.e. with . Here and are operators from a reflexive Banach space to its dual , is a linear, bounded operator, denotes the generalized gradient of a locally Lipschitz function, and are given, and represents a history-dependent operator.
The motivation to study the inequality of the form (1) comes from contact problems in solid mechanics. It is known that when the external forces and tractions evolve slowly in time in such a way that the acceleration in the system is rather small and negligible, then the inertial terms can be neglected. In such a way, we obtain the quasistatic approximation (equilibrium equation) for the equation of motion. Quasistatic contact models have been studied in several monographs and many papers dedicated to such phenomena, see [9, 14, 35, 36] and the references therein.
In the first part of the paper, we deal with an abstract time-dependent hemivariational inequality of the form (1). The main results are delivered on existence, uniqueness and regularity of a solution to the abstract hemivariational inequality, see Theorem 11. We apply the Rothe method, see [17, 18], combined with a surjectivity result for a multivalued and coercive operator. The hemivariational inequality (1) without a history-dependent operator has been recently investigated in [24] by using the vanishing acceleration method, where a local existence result was proved. In contrast to Theorem 17 of [24], here we provide a result on the global unique solvability to (1). Also, our proof is now based on the Rothe method and is simpler, since we have eliminated the additional space required in [24]. Moreover, being motivated by applications to contact mechanics in Section 6, the inequality (1) involves a history-dependent operator. We recall that the notion of a history-dependent operator is quite recent and it was introduced in [39]. Various problems with history-dependent operators have been studied for the evolution variational and hemivariational inequalities in [1, 6, 10, 11, 20, 21, 22, 27, 28, 29, 30, 34, 43, 44], and for the quasistatic problems in [19, 26, 37, 38, 40, 41, 45]. Furthermore, we study a fully discrete approximation for the problem (1) which consists in finite difference discretization in time and finite element approximation in the spatial variable. We prove in Theorem 13 the Céa type error estimate for the hemivariational inequality.
In the second part of the paper, we apply the abstract results to a quasistatic frictional contact model for viscoelastic materials. The process is described by multivalued versions of the nonmonotone normal compliance and friction boundary conditions. We provide the variational formulation of the contact problem for which we deliver a result on its unique weak global solvability. In this way we improve the local existence result of [24, Theorem 17]. Finally, for the frictionless contact we establish a result on an optimal error estimate for the fully discrete approximation scheme. Note that results on numerical anlaysis for hemivariational inequalities can be found in [3, 12, 15, 16, 37] and the references therein.
The outline of the paper is as follows. After recalling the basic notation in Section 2, in Section 3 we formulate the abstract hemivariational inequality with a history-dependent operator. In Section 4 we apply the Rothe method to deliver existence and uniquence result for this inequality. The error estimate of the Céa type for a fully discrete approximation is provided in Section 5. Finally, in Section 6, we illustrate the applicability of our results to the quasistatic frictional contact problem for viscoelastic material.
2 Preliminaries
In this section we recall the basic notation and some results which are needed in the sequel, see [5, 7, 8, 42]. We use the standard notation for the Lebesgue and Sobolev spaces of functions defined on a finite time interval with values in a Banach space. We denote by the space of linear and bounded operators from a Banach space to a Banach space endowed with the usual norm . For a subset of Banach space , we write .
Let be a reflexive Banach space and denote the duality of and . A single-valued mapping is called monotone if for all , . An operator is pseudomonotone if for every sequence converging weakly to such that , we have
[TABLE]
Note that the operator is pseudomonotone if and only if the conditions weakly in and entail and weakly in . It is also easy to check that if is nonnegative, then it is pseudomonotone.
We recall the notion of the pseudomonotonicity for a multivalued operator.
Definition 1**.**
Let be a reflexive Banach space. An operator is pseudomonotone if
(a) for every , the set is nonempty, closed and convex,
(b) is upper semicontinuous from each finite dimensional subspace of to endowed with the weak topology,
(c) for any sequences and such that weakly in , for all and , we have that for every , there exists such that
[TABLE]
We recall the following fundamental surjectivity theorem, see [8, Theorem 1.3.70] or [42], which will be used to prove existence of a solution to a static hemivariational inequality in Section 4.
Theorem 2**.**
Let be a reflexive Banach space and be pseudomonotone and coercive. Then is surjective, i.e., for every , there is such that .
We hereafter recall the definition of the Clarke subgradient.
Definition 3**.**
Given a locally Lipschitz function on a Banach space , we denote by the generalized (Clarke) directional derivative of at the point in the direction defined by
[TABLE]
The generalized gradient of at is defined by
[TABLE]
The following result provides an example of a multivalued pseudomonotone operator which is a superposition of the Clarke subgradient with a compact operator. The proof can be found in [3, Proposition 5.6].
Proposition 4**.**
Let and be reflexive Banach spaces, be a linear, bounded, and compact operator. We denote by the adjoint operator of . Let be a locally Lipschitz function such that
[TABLE]
with . Then the multivalued operator defined by for is pseudomonotone.
We conclude this section with a discrete version of the Gronwall inequality whose proof can be found in [14, Lemma 7.25].
Lemma 5**.**
Let be given. For a positive integer , we define . Assume that and are two sequences of nonnegative numbers satisfying
[TABLE]
for a positive constant independent of (or ). Then there exists a positive constant , independent of (or ) such that
[TABLE]
3 History-dependent hemivariational inequalities
In this section we introduce a class of history-dependent hemivariational inequalities. This class will be studied in Section 4 where the existence and uniqueness result for this class of inequalities will be provided. A fully discrete approximation for the inequalities in this class will be discussed in Section 5.
We use the following standard notation, see [7, 8, 29, 42] for details. Let be an evolution triple of spaces. Recall that this means that is a reflexive and separable Banach space, is a separable Hilbert space, and the embedding is dense and continuous. Let be the embedding operator between and which is assumed to be compact. It is known that the adjoint operator is also linear, continuous and compact. The duality pairing between and , and a norm in , are denoted by and , respectively. For the Hilbert space , we denote its scalar product and a norm by and , respectively.
Given , let and . It follows from the reflexivity of that both and its dual space are reflexive Banach spaces as well. Identifying with its dual, we have the continuous embeddings .
The notation stands for the duality pairing between and . Moreover, by we denote the spave of continuous functions on with values in .
Let be a separable and reflexive Banach space. Given operators , , , the function , and , we consider the following evolutionary hemivariational inequality involving a history-dependent operator.
Problem 6**.**
Find an element such that and
[TABLE]
Here is an operator defined by
[TABLE]
where , and .
We impose the following assumptions on the data of Problem 6.
: The operator is linear, bounded, coercive and symmetric, i.e.,
(i) .
(ii) for all with .
(iii) for all , .
: The operator is linear, bounded and coercive, i.e.,
(i) .
(ii) for all with .
: .
: The function is Lipschitz continuous with respect to the first variable, i.e., there exists such that
[TABLE]
: The functional is such that
(i) is locally Lipschitz.
(ii) There exists such that for all .
(iii) There exists such that
[TABLE]
for all , and , .
: .
: The operator is linear, continuous and compact.
: .
Remark 7**.**
Hypothesis (iii) is called the relaxed monotonicity condition for a locally Lipschitz function . It was used in the literature (cf. [23, Section 3.3]) to ensure the uniqueness of the solution to hemivariational inequalities. This hypothesis has the equivalent formulation as follows
[TABLE]
for all , . In addition, examples of nonconvex functions which satisfy the relaxed monotonicity condition can be found in [23, 37]. Particularly, it can be proved that for a convex function, condition (iii) holds with .
We recall, cf. [39], that an operator is called a history-dependent operator if there exists such that
[TABLE]
for all , and all . We remark that under hypotheses , and , the operator defined in (4) satisfies condition (5) with , where and .
4 Rothe method
In this section, we present a result on existence and uniqueness of solution for Problem 6. The technique of proof relies on the Rothe method (known also as a method of lines, see [17, 18]). It consists in a time discretization in which we define an approximate sequence of functions by using the implicit (backward) Euler formula. Next, in each time step, we will solve a stationary hemivational inequality. Finally, we construct the piecewise constant and piecewise affine interpolants and prove a convergence result.
In the rest of the section, we denote by a constant whose value may change from line to line.
Let be fixed and denote for , where and . Now, we discuss the following discretized problem called the Rothe problem.
Problem 8**.**
Find such that and
[TABLE]
for all and for , where is defined by
[TABLE]
First, we shall prove the existence and uniqueness of a solution to Problem 8.
Lemma 9**.**
Assume that , , , , , , and hold. Then there exists such that, for all , Problem 8 has a unique solution.
Proof. Let , be given. We will prove that there exists a unique element which satisfies inclusion (6). To end this, we apply Theorem 2 to show that the operator defined by
[TABLE]
for all , is surjective.
First, we show that there exists such that, for all , is a pseudomonotone operator. Indeed, by hypotheses (i)-(ii), (i)-(ii), and , we can easily get that the operator
[TABLE]
is bounded, continuous and monotone for , where with and . From [23, Theorem 3.69], we conclude that the operator defined by (7) is pseudomonotone. On the other hand, taking into account assumptions (i)-(ii), and Proposition 4, it is clear that the operator is pseudomonotone as well. Therefore, by using [23, Proposition 3.59(ii)], we infer that is a pseudomonotone operator too.
Subsequently, we prove that the operator is coercive. From hypothesis we derive the estimate (see [12])
[TABLE]
for all . This inequality together with (ii), (ii), and implies
[TABLE]
for all . From the smallness condition , we choose . Hence, we deduce that the operator is coercive for all . Therefore, by the use of Theorem 2, we obtain that is surjective, i.e., Problem 8 has at least one solution .
For uniqueness part, we assume that and are two solutions in of Problem 8, that is,
[TABLE]
and
[TABLE]
where the elements and are defined by
[TABLE]
and
[TABLE]
respectively. We take in the first inequality and in the second one. We add the resulting inequalities to get
[TABLE]
Hence
[TABLE]
The smallness condition guarantees that , which completes the proof of this lemma.
Next, we establish the estimates for the solution of Problem 8.
Lemma 10**.**
Under assumptions of Lemma 9, there exists and independent of , such that for all , the solution of Problem 8 satisfy
[TABLE]
where .
Proof. We choose in (6), then use the hypotheses , and the equality
[TABLE]
to get
[TABLE]
Next, the assumptions and imply
[TABLE]
Combining (4) and (13), and using the Cauchy inequality with , we have
[TABLE]
We now choose and . Then, for all , it follows
[TABLE]
Summing the above inequalities for , where , and then applying , we get
[TABLE]
Now, we use the discrete version of the Gronwall inequality in Lemma 5, to verify estimates (8) and (9). The estimate (10) follows directly from (8) and (ii).
Denote for . We take in (6) to get
[TABLE]
hence,
[TABLE]
The latter together with (8), (10), , and the Cauchy inequality with implies
[TABLE]
We choose now to get
[TABLE]
So, we obtain the estimate (11), which completes the proof of this lemma.
Subsequently, for a given , we define the piecewise affine function and the piecewise constant interpolant functions , , and as follows
[TABLE]
Now, we rewrite Problem 8 in the following equivalent form
[TABLE]
for all and a.e. , where for a.e. .
The main results of this section is delivered in the following theorem.
Theorem 11**.**
Under assumptions of Lemma 9, Problem 6 has a unique solution .
Proof. The bound (8) ensures that is bounded in due to the following inequality
[TABLE]
It follows from the reflexivity of that there exists a function such that, passing to a subsequence again indexed by , we have
[TABLE]
Also, from (8), we have that the sequence is bounded in , and therefore, there exists such that
[TABLE]
Hence, we get weakly in , as . By the Hölder inequality and the boundedness of (see (11))
[TABLE]
we have
[TABLE]
From estimate (4) we deduce that . On the other hand, by the boundedness of (see (11)), we also obtain (cf. [42, Proposition 23.19. p. 419])
[TABLE]
In addition, using the boundedness of (see (10)) and the reflexivity of the space , we conclude
[TABLE]
By virtue of the hypothesis and boundedness of (see (8)), one has the following estimate for
[TABLE]
for some , which is independent of . Moreover, [4, Lemma 3.3] implies that
[TABLE]
Next, we shall show that is a solution of Problem 6. To this end, we define the Nemytskii operators , by and for all and a.e. . From hypotheses and , it is clear that and are both linear and bounded, so they are also weakly continuous. Thus from (23) and (20) we obtain and both weakly in , as , i.e.,
[TABLE]
for all . Now, we consider the Nemitskii operators , by
[TABLE]
for all and a.e. . It is obvious that is weakly continuous being bounded and linear. From the convergence (20), one has
[TABLE]
for all . Next, from , and (4), we have
[TABLE]
which implies
[TABLE]
for all .
Since the embedding is continuous, from the convergences (21) and (23), by [24, Lemma 4(a)], we have
[TABLE]
for all . Using the convergence strongly in , as , by the converse Lebesgue dominated convergence theorem, [23, Theorem 2.39], we may assume that strongly in for a.e. , as . This together with (29) implies
[TABLE]
From the compactness of the operator , we deduce strongly in for a.e. . Since for a.e. , we use also the convergence (24), and by [2, Theorem 1, Section 1.4], we have
[TABLE]
Now, we introduce the Nemitskii operator defined by for all and a.e. , so, from (24), we have
[TABLE]
for all .
From (26)–(4), (30) and (31), we infer that
[TABLE]
for all with for a.e. . Furthermore, we shall show that with is also a solution of Problem 6. Arguing by contradiction, we suppose that is not a solution to Problem 6. This means there exist a measurable set with and such that
[TABLE]
We now denote a function by
[TABLE]
Inserting into (32) and taking account of (33), it follows from [23, Theorem 3.47] that
[TABLE]
This results a contradiction, so, with is also a solution of Problem 6.
Finally, we will verify that the solution of Problem 6 is unique. Let and be two solutions of Problem 6. Then
[TABLE]
and
[TABLE]
for all and a.e. . Taking in the first inequality and in the second one, we add the resulting inequalities to get
[TABLE]
for a.e. . We use the assumptions , , , , and (iii) to obtain
[TABLE]
We integrate this inequality on , where , and use (ii) and to deduce
[TABLE]
for all . Hence
[TABLE]
for all . Finally, we use the Gronwall inequality (see e.g. [36, Lemma 2.31]) to obtain . This completes the proof of the theorem.
5 A fully discrete approximation scheme
In this section, we study a fully discrete approximation scheme for the history-dependent hemivariational inequality stated in Problem 6. In this method the time variable is discretized by finite difference and the spatial variable is approximated by finite elements.
Assume that is a finite dimensional subspace of and is an approximation of the initial point . For , given, we denote the time step length by and for . For a continuous function defined on the interval , in the sequel, we will write for . In addition, for a sequence , we use the notation
[TABLE]
For the history-dependent operator
[TABLE]
we introduce a modified trapezoidal approximation for defined by
[TABLE]
for . In addition, if , then the expression is understood as follows
[TABLE]
Subsequently, we consider the following fully discrete approximation problem for Problem 6.
Problem 12**.**
Find such that and
[TABLE]
for all .
We will provide an error analysis of the fully discrete approximation (12). Our goal is to prove the Céa type inequality for Problem 12.
First, exploiting the definition of , the inequality (12) can be reformulated as follows
[TABLE]
This inequality represents a stationary hemivariational inequality. When small enough, from Lemma 9, we know that under the hypotheses , , , , , and , it has a unique solution . Moreover, Theorem 11 reveals that Problem 6 has a unique solution .
Since is coercive, in what follows, for a convenience, we introduce the norm by for all , which is equivalent to the norm . In the sequel, we denote by a constant which may differ from line to line, but it is independent of and .
For an error analysis, we have from (1) at that
[TABLE]
for all , where . Denote the errors
[TABLE]
for , . Taking in (38), one has
[TABLE]
[TABLE]
for all . Hence
[TABLE]
for all . We use the fact that the function is subadditive (see e.g., [23, Proposition 3.23(i)]), to obtain
[TABLE]
So, we have
[TABLE]
for all . Combining this inequality with the identity
[TABLE]
and using the hypotheses and (iii) (see Remark 7), it follows that
[TABLE]
for all . Furthermore, we introduce a residual type quantity by
[TABLE]
Using the fact that (see Theorem 11), we have
[TABLE]
with some , and
[TABLE]
From these inequalities, we obtain
[TABLE]
where . Therefore, from (5), we have
[TABLE]
where and .
Note that the hypothesis (ii) and imply that the sequence is uniformly bounded. It follows from Lemma 10 that is uniformly bounded as well. Hence, we have
[TABLE]
Applying (41) again, we obtain
[TABLE]
Combining (5)–(44) and applying the Cauchy inequality with , we have
[TABLE]
Now we take and , which implies
[TABLE]
for all . Subsequently, from (5), we have
[TABLE]
Now, we replace by in the above inequality, and then sum it from to , where to get
[TABLE]
This together with the following estimates
[TABLE]
and
[TABLE]
implies that
[TABLE]
It follows from the discrete Gronwall inequality, , and Lemma 5, that
[TABLE]
for all .
We now summarize the results of the section in the form of a theorem.
Theorem 13**.**
Suppose that assumptions of Lemma 9 are satisfied. Let and be the solutions of Problems 12 and 6, respectively. Then, we have the estimate
[TABLE]
for all .
The inequality (13) is called the Céa type inequality of the fully discrete approximation problem, Problem 12.
6 A quasistatic viscoelastic contact problem
In this section we study the quasistatic contact problem between a viscoelastic body and a foundation. The volume forces and surface tractions are supposed to change slowly in time and therefore the acceleration in the system is negligible. Neglecting the inertial terms in the equation of motion leads to the quasistatic approximation for the process. We show that the variational formulation of the quasistatic contact problem is a time-dependent hemivariational inequality in Problem 6. For the latter, we apply the abstract result stated in Theorem 11 and prove a result on existence and uniqueness of weak solution. Further, we use the fully discrete approximation method discussed in Section 5 to study the numerical analysis of this contact problem and establish the result concerning optimal error estimate for the fully discrete scheme.
6.1 Mathematical model
and its variational formulation
The physical setting of the contact problem is as follows. A deformable viscoelastic body occupies an open bounded subset of , , in applications. The volume forces of density \mbox{\boldmath{f}}_{0} act in and surface tractions of density \mbox{\boldmath{f}}_{N} are applied on . They both can depend on time. We are interested in the quasi-static process of the mechanical state of the body on the time interval with . The boundary of is assumed to be Lipschitz continuous and it consists of three measurable parts , and which are mutually disjoint, and . The unit outward normal vector exists a.e. on . We suppose that the body is clamped on part , and the body may come in contact with an obstacle over the potential contact surface . We also put , , , and . We often do not indicate explicitly the dependence of functions on the spatial variable \mbox{\boldmath{x}}\in\Omega.
Let denote the space of symmetric matrices. The canonical inner products and norms on and are given by
[TABLE]
[TABLE]
In what follows we always adopt the summation convention over repeated indices.
Moreover, for a vector \mbox{\boldmath{\xi}}\in\mathbb{R}^{d}, the normal and tangential components of on the boundary are denoted by \xi_{\nu}=\mbox{\boldmath{\xi}}\cdot\mbox{\boldmath{\nu}} and \mbox{\boldmath{\xi}}_{\tau}=\mbox{\boldmath{\xi}}-\xi_{\nu}\mbox{\boldmath{\nu}}, respectively. The normal and tangential components of the matrix \mbox{\boldmath{\sigma}}\in\mathbb{S}^{d} are defined on boundary by \sigma_{\nu}=(\mbox{\boldmath{\sigma}}\mbox{\boldmath{\nu}})\cdot\mbox{\boldmath{\nu}} and \mbox{\boldmath{\sigma}}_{\tau}=\mbox{\boldmath{\sigma}}\mbox{\boldmath{\nu}}-\sigma_{\nu}\mbox{\boldmath{\nu}}, respectively.
We denote by \mbox{\boldmath{u}}\colon Q\to\mathbb{R}^{d} the displacement vector, by \mbox{\boldmath{\sigma}}\colon Q\to\mathbb{S}^{d} the stress tensor and by \mbox{\boldmath{\varepsilon}}(\mbox{\boldmath{u}})=(\varepsilon_{ij}(\mbox{\boldmath{u}})) the linearized (small) strain tensor, where , . Recall that the components of the linearized strain tensor are given by \mbox{\boldmath{\varepsilon}}(\mbox{\boldmath{u}})=1/2(u_{i,j}+u_{j,i}), where .
The classical formulation of the contact problem reads as follows.
Problem . Find a displacement field \mbox{\boldmath{u}}\colon Q\to\mathbb{R}^{d} and a stress field \mbox{\boldmath{\sigma}}\colon Q\to\mathbb{S}^{d} such that
[TABLE]
The relation (48) represents the equilibrium equation in which “Div” denotes the divergence operator for tensor valued functions defined by {\rm Div}\mbox{\boldmath{\sigma}}=(\sigma_{ij,j}). Equation (49) is the viscoelastic constitutive law with long memory, where and are linear viscosity and elasticity operators, and denotes the relaxation operator. Next, conditions (50) and (51) represent the displacement and the traction boundary conditions. The multivalued relations (52) and (53) are the contact and friction conditions, respectively, in which and denote the Clarke generalized gradients of prescribed locally Lipschitz functions and . Finally, condition (54) represents the initial condition where \mbox{\boldmath{u}}_{0} denotes the initial displacement. For concrete examples of boundary conditions (52) and (53), we refer to [9, 14, 23, 31, 32, 33].
Subsequently we introduce the spaces needed for the variational formulation. Let be a closed subspace of defined by
[TABLE]
and . Then forms an evolution triple of spaces. Moreover, the trace operator is denoted by . Given an element \mbox{\boldmath{v}}\in V we use the same notation for the trace of on the boundary. The space is equipped with the inner product and the corresponding norm given by
[TABLE]
where . Since , from the Korn inequality \|\mbox{\boldmath{v}}\|_{H^{1}(\Omega;\mathbb{R}^{d})}\leq c\|\mbox{\boldmath{\varepsilon}}(\mbox{\boldmath{v}})\|_{\mathcal{H}} for \mbox{\boldmath{v}}\in V with , it follows that and are equivalent norms on . In addition, we denote by the space of fourth-order tensor fields given by
[TABLE]
We assume that the viscosity and elasticity tensors have the usual properties of ellipticity and symmetry.
is a viscosity tensor, such that there exists satisfying for all , a.e. in .
is an elasticity tensor, such that there exists satisfying for all , a.e. in .
is Lipschitz continuous with constant .
The body forces, surface tractions and initial displacement satisfy
\mbox{\boldmath{f}}_{0}\in L^{2}(0,T;L^{2}(\Omega;\mathbb{R}^{d})), \mbox{\boldmath{f}}_{N}\in L^{2}(0,T;L^{2}(\Gamma_{2};\mathbb{R}^{d})), \mbox{\boldmath{u}}_{0}\in V.
The superpotentials satisfy
is a function such that
- (i)
is measurable for all , ,
- (ii)
j_{\nu}(\mbox{\boldmath{x}},\cdot) is locally Lipschitz for a.e. \mbox{\boldmath{x}}\in\Gamma_{3},
- (iii)
|\partial j_{\nu}(\mbox{\boldmath{x}},r)|\leq c_{\nu}(1+|r|) for a.e. \mbox{\boldmath{x}}\in\Gamma_{3}, all with ,
- (iv)
for all \eta_{i}\in\partial j_{\nu}(\mbox{\boldmath{x}},r_{i}), for a.e. \mbox{\boldmath{x}}\in\Gamma_{3} with .
is a function such that
- (i)
j_{\tau}(\cdot,\mbox{\boldmath{\xi}}) is measurable for all \mbox{\boldmath{\xi}}\in\mathbb{R}^{d}, ,
- (ii)
j_{\tau}(\mbox{\boldmath{x}},\cdot) is locally Lipschitz for a.e. \mbox{\boldmath{x}}\in\Gamma_{3},
- (iii)
\|\partial j_{\tau}(\mbox{\boldmath{x}},\mbox{\boldmath{\xi}})\|_{\mathbb{R}^{d}}\leq c_{\tau}(1+\|\mbox{\boldmath{\xi}}\|_{\mathbb{R}^{d}}) for a.e. \mbox{\boldmath{x}}\in\Gamma_{3}, all \mbox{\boldmath{\xi}}\in\mathbb{R}^{d} with ,
- (iv)
(\mbox{\boldmath{\eta}}_{1}-\mbox{\boldmath{\eta}}_{2})\cdot(\mbox{\boldmath{\xi}}_{1}-\mbox{\boldmath{\xi}}_{2})\geq-m_{\tau}\|\mbox{\boldmath{\xi}}_{1}-\mbox{\boldmath{\xi}}_{2}\|^{2} for all \mbox{\boldmath{\eta}}_{i}\in\partial j_{\tau}(\mbox{\boldmath{x}},\mbox{\boldmath{\xi}}_{i}), \mbox{\boldmath{\xi}}_{i}\in\mathbb{R}^{d},~{}i=1,2 for a.e. \mbox{\boldmath{x}}\in\Gamma_{3} with .
In the hypotheses and the subdifferential is taken with respect to the last variables of and , respectively.
Next, we define the operators , by
[TABLE]
for , \mbox{\boldmath{v}}\in V, and the operator by
[TABLE]
for all \mbox{\boldmath{w}}\in{\mathcal{V}}, \mbox{\boldmath{v}}\in V, a.e. .
To obtain the weak formulation of the problem (48)–(54), we assume the sufficient smoothness of the functions involved, use the equilibrium equation (48) and the Green formula. We obtain
[TABLE]
for \mbox{\boldmath{v}}\in V. Taking into account the boundary condition (50) and (51), we have
[TABLE]
where \mbox{\boldmath{f}}\in{\mathcal{V}}^{*} is given by \langle\mbox{\boldmath{f}}(t),\mbox{\boldmath{v}}\rangle=\langle\mbox{\boldmath{f}}_{0}(t),\mbox{\boldmath{v}}\rangle_{H}+\langle\mbox{\boldmath{f}}_{N}(t),\mbox{\boldmath{v}}\rangle_{L^{2}(\Gamma_{2};\mathbb{R}^{d})} for \mbox{\boldmath{v}}\in V. On the other hand, by the ortogonality relation, cf. (6.33) in [23], we get
[TABLE]
The contact and friction boundary conditions (52) and (53) can be equivalently formulated as follows
[TABLE]
Using (49), (56), (59) and (60), from (58), we obtain the following hemivariational inequality which is a weak formulation of the problem (48)–(54): find \mbox{\boldmath{u}}\colon(0,T)\to V such that , \mbox{\boldmath{u}}^{\prime}\in{\mathcal{V}} and
[TABLE]
6.2 Existence and uniqueness for contact
problem
Let and consider the functional defined by
[TABLE]
Following [25, Theorem 5.1] and [23, Corollary 4.15], we recall the following properties of the functional .
Lemma 14**.**
Under the hypotheses and , if, in addition,
[TABLE]
then the functional defined by (65) satisfies
- (i)
* is Lipschitz continuous on bounded subsets of ,*
- (ii)
\|\partial J(\mbox{\boldmath{v}})\|_{X^{*}}\leq c_{1}\left(1+\|\mbox{\boldmath{v}}\|_{X}\right)* for all \mbox{\boldmath{v}}\in X with ,*
- (iii)
for all , \mbox{\boldmath{w}}\in X, \mbox{\boldmath{\xi}}\in\partial J(\mbox{\boldmath{v}}) and \mbox{\boldmath{\eta}}\in\partial J(\mbox{\boldmath{w}}), we have
[TABLE]
with ,
- (iv)
for all , \mbox{\boldmath{w}}\in X, we have
[TABLE]
- where J^{0}(\mbox{\boldmath{v}};\mbox{\boldmath{w}}) denotes the directional derivative of at a point \mbox{\boldmath{v}}\in X in the direction \mbox{\boldmath{w}}\in X.
Under our notation we associate with the hemivariational inequality (64), the following inclusion: find \mbox{\boldmath{u}}\in{\mathcal{V}} such that \mbox{\boldmath{u}}^{\prime}\in{\mathcal{V}} and
[TABLE]
Note that if the hypotheses and hold, then every solution to (74) is a solution to (64). The converse holds provided and satisfy the regularity condition (68). These facts follow from the definition of the Clarke generalized gradient and Lemma 14.
The existence, uniqueness and regularity result for the hemivariational inequality (64) is given in the following result.
Theorem 15**.**
If the hypotheses , , , , , , regularity condition (68) hold, and the inequality is satisfied, then problem (64) has a unique solution \mbox{\boldmath{u}}\in H^{1}(0,T;V).
Proof. It follows from and that the operators and defined by (56) satisfy with and with , respectively. It is obvious from the definition of (see (57)) and hypothesis that and are satisfied with and . Moreover, we put , is the trace operator. It is a consequence of Lemma 14 that the functional given by (65) satisfies with and (see Lemma 14). Also follows easily by the properties of the trace operator. The conclusion is a consequence of Theorem 11, which completes the proof of this theorem.
We say that a couple of functions (\mbox{\boldmath{u}},\mbox{\boldmath{\sigma}}) which satisfies (49) and (64) is called a weak solution to Problem . We conclude that, under the assumptions of Theorem 15, Problem has a unique weak solution. Moreover, the weak solution has the following regularity \mbox{\boldmath{u}}\in H^{1}(0,T;V), \mbox{\boldmath{\sigma}}\in L^{2}(0,T;L^{2}(\Omega,\mathbb{S}^{d})) and {\rm Div}\,\mbox{\boldmath{\sigma}}\in{\mathcal{V}^{*}}.
6.3 Numerical analysis of contact problem
In this section, we will apply the results from Section 5 to establish an optimal order error estimate for the fully discrete solution of the contact problem in Problem . Here, we consider the frictionless boundary condition on , i.e., the frictional boundary (53) will be reduced to
[TABLE]
In addition, without loss of generality, we may assume that \mbox{\boldmath{u}}_{0}={\bf 0}. We use the same the spaces as introduced in Section 6.1. Then, consider the trace operator . It follows from the Sobolev trace theorem that
[TABLE]
for some constant , which depends only on , and . Let and define the operators , \gamma_{\nu}\mbox{\boldmath{v}}=v_{\nu} for \mbox{\boldmath{v}}\in L^{2}(\Gamma_{3};\mathbb{R}^{d}), and . We also consider the functional defined by
[TABLE]
If either j_{\nu}(\mbox{\boldmath{x}},\cdot) or -j_{\nu}(\mbox{\boldmath{x}},\cdot) is regular and holds, then by Lemma 14, (56) and (57), the contact problem (48)–(54) with has following equivalent variational formulation.
Problem 16**.**
Find \mbox{\boldmath{u}}\in\mathcal{V} such that \mbox{\boldmath{u}}^{\prime}\in\mathcal{V} and
[TABLE]
From Theorem 15, we deduce that under the hypotheses , , , and , . If either j_{\nu}(\mbox{\boldmath{x}},\cdot) or -j_{\nu}(\mbox{\boldmath{x}},\cdot) is regular and the inequality hold, then Problem 16 has a unique solution \mbox{\boldmath{u}}\in H^{1}(0,T;V).
Next, we pass to the numerical approximation of Problem 16. Likewise in Section 5, for an integer , let be the time step length. For simplicity, we suppose that is a polygonal/polyhedral domain and express the three parts of the boundary, , , , , as a union of closed flat components with disjoint interiors
[TABLE]
Subsequently, we consider a regular family of meshes that partition into triangles/tetrahedrons compatible with the splitting of the boundary into , , . This means that if the intersection of one side/face of an element with one set has a positive measure with respect to , then the side/face lies entirely in . Corresponding to the family , we define the linear element space
[TABLE]
where denotes a set of all linear functions whose domain of definition is (cf. [16, p. 70]).
Now, we are in a position to formulate the following fully discrete approximation problem for Problem 16.
Problem 17**.**
Find \mbox{\boldmath{u}}^{hk}=\{\mbox{\boldmath{u}}_{n}^{hk}\}\subset V^{h} such that \mbox{\boldmath{u}}_{0}^{hk}={\bf 0} and
[TABLE]
for all .
In the sequel, we assume that the solution of Problem 16 has the following additional regularity
[TABLE]
for . Then the function (t,\mbox{\boldmath{x}})\to\mbox{\boldmath{u}}(t,\mbox{\boldmath{x}}) is continuous. This means that the pointwise values of are well-defined. So, take \mbox{\boldmath{v}}_{n}^{h}=\Pi^{h}\mbox{\boldmath{u}}_{n}\in V^{h} to be the finite element interpolant of \mbox{\boldmath{u}}_{n}(\mbox{\boldmath{x}})=\mbox{\boldmath{u}}(t_{n},\mbox{\boldmath{x}}), where \Pi^{h}\mbox{\boldmath{u}}_{n} denotes the piecewise constant Lagrange interpolation of \mbox{\boldmath{u}}_{n} (cf. [16, p. 122]). We use the Céa type inequality (5) to get
[TABLE]
where
[TABLE]
It follows from [13, Lemma 11.5] that
[TABLE]
This together with Hlder inequality implies that
[TABLE]
and
[TABLE]
Next, we use the fact
[TABLE]
to obtain
[TABLE]
Hence, we have
[TABLE]
and
[TABLE]
Recall that is the finite element interpolant of on each component . Combining (89) with the hypothesis (86), we get
[TABLE]
On the other hand, we estimate the residual quantity |S_{n}(\mbox{\boldmath{v}})|. To this end, we use the fact (see (58), (59) and (75)) that
[TABLE]
to get
[TABLE]
for some \xi_{n}\in\partial J(M\mbox{\boldmath{u}}_{n}). This implies
[TABLE]
and, therefore, we have
[TABLE]
This estimate together with (88)–(90) implies the following optimal estimate for the fully discrete scheme (83).
Theorem 18**.**
Assume that and \mbox{\boldmath{u}}^{hk} are solutions to Problems 16 and 17, respectively, and the regularity condition (86) holds. Then, we have
[TABLE]
where is independent of and .
In the optimal error estimate of Theorem 18, the method is of first-order in spatial mesh size and in the time step.
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