This paper offers a new geometric proof of the Avalanche Principle using hyperbolic geometry, extending its applicability to general CAT(-1) spaces and deriving a polygonal Schur theorem.
Contribution
It introduces a geometric approach to the Avalanche Principle, broadening its scope to CAT(-1) spaces and establishing a related polygonal Schur theorem.
Findings
01
New proof of the Avalanche Principle using hyperbolic geometry
02
Extension of the principle to CAT(-1) metric spaces
03
Derivation of a polygonal Schur theorem for these spaces
Abstract
We use the geometric structure of the hyperbolic upper half plane to provide a new proof of the Avalanche Principle introduced by M. Goldstein and W. Schlag in the context of SL2(R) matrices. This approach allows to interpret and extend this result to arbitrary CAT(−1) metric spaces. Through the proof, we deduce a polygonal Schur theorem for these spaces.
Equations148
∥Aj∥≥κ−2 for 1≤j≤n,and∥Aj∥∥Aj−1∥∥AjAj−1∥≥ε for 2≤j≤n,
∥Aj∥≥κ−2 for 1≤j≤n,and∥Aj∥∥Aj−1∥∥AjAj−1∥≥ε for 2≤j≤n,
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The Avalanche Principle and Negative Curvature
Eduardo Oregón-Reyes
Abstract.
We use the geometric structure of the hyperbolic upper half plane to provide a new proof of the Avalanche Principle introduced by M. Goldstein and W. Schlag in the context of SL2(R) matrices. This approach allows to interpret and extend this result to arbitrary CAT(−1) metric spaces. Through the proof, we deduce a polygonal Schur theorem for these spaces.
1. Introduction
Lyapunov exponents play a major role in the theory of dynamical systems, codifying the asymptotic behavior of a sequence of composition of linear maps. In particular, the top Lyapunov exponent describes the evolution of the norms of matrix products. For matrices taking values in SL2(R), M. Goldstein and W. Schlag introduced the Avalanche Principle (AP) [10], which is a quantitative sufficient condition for the operator norm ∥AN⋯A1∥ to being similar to the product ∥AN∥⋯∥A1∥. Since then, several higher dimensional versions and refinements have appeared in the literature, being an important tool to prove continuity of Lyapunov exponents for linear cocycles coming from Schrödinger operators (see e.g. [2, 3, 6, 7, 15]). The following is the version for SL2(R) due to Duarte and Klein [8, Thm. 4.1]:
Theorem 1.1** (AP in SL2(R)).**
There exist constants c0,c1>0 so that if 0<ε<1 and 0<κ≤c0ε2, then for every chain of matrices A1,…,An∈SL2(R) satisfying
[TABLE]
we have
[TABLE]
Here ∥A∥ denotes the Euclidean operator norm (largest singular value) of the matrix A.
Note that the hypothesis only depends on the norms of the matrices A1,…,An and A2A1,…,AnAn−1, so we can think of the AP as a local to global principle for norms of matrix products. In fact, these hypotheses imply uniform hyperbolicity of infinite sequences of 2×2 matrices [16].
1.1. A version for the hyperbolic plane
The assumptions and conclusions of the previous theorem have natural interpretations in terms of hyperbolic geometry. Consider the upper half plane H2={z∈C:Imz>0} endowed with the Riemannian metric ds2=dz2/Im(z)2. The induced distance d on H2 takes the form [1, p. 130]
[TABLE]
We also have the natural isometric action of SL2(R) on H2 by fractional linear transformations:
[TABLE]
The relation between the operator norm ∥A∥ of A and its action A~ on H2 is given by the formula [14, Prop. 2.1]
[TABLE]
So, if we define x0=i and xj=A~n⋯A~n−j+1i for 1≤j≤n, then the left hand side of (1) translates to the following definition:
Definition 1.2**.**
The tension of a chain of points x0,…,xn∈H2 is the number:
[TABLE]
Example 1.3**.**
If x0,…,xn lie in a hyperbolic geodesic in H2 in that order, then τ(x0,…,xn)=0.
Example 1.4**.**
Let n≥4, and consider a regular hyperbolic n-gon x1,…,xn∈H2 inscribed in a hyperbolic circle of radius r. Defining x0=xn, the tension of the chain x0,x1,…,xn is
[TABLE]
Thus nτ(x0,…,xn) tends to infinity when r tends to infinity, and there are chains with arbitrarily large tension when compared to their lengths.
As the previous examples suggest, for n∣τ(x0,…,xn)∣ to be small we need some kind of control on the chain x0,x1,…,xn, making it close to lie in a geodesic. In H2, a sufficient condition for this is that the points x0,…,xn lie in that order in a curve of constant geodesic curvature less than 1 w.r.t. the hyperbolic metric (for a detailed explanation, see [12, Sec. 2.3]). By Example 1.4 this condition is in some sense necessary, since contrary to what happens in Euclidean geometry, a curve in H2 of constant geodesic curvature k is closed (i.e. is a hyperbolic circle) if and only if k>1 [12, Exe. 2.3.7]. We control the chains in H2 according to the following definition:
Definition 1.5**.**
A pair (a,b)∈R2 is good if a,b≥0 and
[TABLE]
For such a pair, we say that a chain x0,x1,…,xn of points in H2 is (a,b)-good if
[TABLE]
where ⟨x∣y⟩z:=2d(x,z)+d(z,y)−d(x,y) is the Gromov product.
Condition (3) is natural, since for an orientation-preserving isometry f of H2 with
[TABLE]
the chain of points i,fi,f2i,… lies in a curve of constant geodesic curvature less than 1 if and only if (3) holds. In that case the stable lengthd∞(f)=infn≥1nd(fni,i) of f is positive and satisfies [13, Cor. 3]:
[TABLE]
Gromov product is also natural. We have ⟨x∣y⟩z≥0, with equality if and only if x,y,z lie in a geodesic with z between x and y. Moreover, when d(x,z) and d(z,y) are large, ⟨x∣y⟩z is essentially a function of the angle determined by x,y,z with vertex at z, w.r.t. the hyperbolic metric. So when a is large, condition (4) may be regarded as an angular bound.
Let x0,…,xn∈H2 be a chain of the form xj=fji for some orientation-preserving isometry f of H2 satisfying (5). A chain of this form is called (a,b)-canonical. Note that two (a,b)-canonical chains of the same length are isometric, so we refer to any of these as the(a,b)-canonical chain.
In what follows, two chains x0,…,xn and y0,…,yn are considered the same if yj=fxj for some isometry f of H2. The heuristic is that among all chains which are (a,b)-good, those that are the farthest from a geodesic are the (a,b)-canonical ones.
For a good pair (a,b), consider the numbers λ>1 and 0<φ≤π/2 given by
[TABLE]
For these quantities the chain x0,…,xn given by xj=λjeiφ is (a,b)-canonical (see Corollary 2.3 below). Also, note that λ=ed∞(f) for fz=λz, and that the curve t↦teiφ has constant geodesic curvature equal to cos(φ)<1. We call the numbers λ and φ the translation number and curvature angle of the pair (a,b), respectively, and we say that a chain x0,x1,…,xn is φ-good if it is (a,b)-good of a good pair (a,b) with curvature angle φ.
We have enough notation for stating our first main result, the AP in the upper half plane:
Theorem 1.6** (Hyperbolic Avalanche Principle).**
Let (a,b) be a good pair, and let x0,x1,…,xn∈H2 be an (a,b)-good chain. Then
[TABLE]
where λ is the translation number of (a,b).
The conclusion of the AP is then that the quantity n∣τ(x0,…,xn)∣ is small when the chain x0,x1,…,xn is close to lie in a geodesic in the sense of Definition 1.5, and it implies Theorem 1.1. Indeed, the inequality [14, Thm. 1.1]
[TABLE]
holds for any orientation-preserving isometry f of H2, and for f satisfying (5) it turns out to be equivalent to λ≥41ea−2b. So, if c>1 and a−2b>log(4)+log(c−1c)>log(4), then (a,b) is a good pair and
[TABLE]
and we recover (1) with κ=e−a, ε=e−b, c1=4c>4 and c0=4cc−1.
Condition (3) is more flexible than Duarte-Klein hypotheses for AP, since it also includes chains x0,…,xn with d(xj,xj−1) arbitrarily close to [math]. This allow us to conclude results of continuous nature, as we see below.
1.2. AP for CAT(−1) spaces and Schur Theorem
The notions of tension and Gromov product are valid for arbitrary metric spaces, so the question is for which of them an Avalanche Principle holds. Natural candidates are CAT(−1) metric spaces, whose local and global geometry are more negatively curved than the geometry of H2. These are metric spaces whose geodesic triangles are thinner than the respective geodesic triangles in H2 (see Section 5 for a detailed definition). Examples of such spaces include metric trees, and complete simply connected Riemannian manifolds with sectional curvature bounded above by −1 with the induced Riemannian distance [4, Ch. II, Thm. IA.6].
Similarly to the definition given for H2, a chain x0,…,xn of points in a metric space X is good if there is a good pair (a,b) such that the points x0,…,xn satisfy (4) with the corresponding distance on X. For such chains there is an essentially unique convex comparison chain x0,…,xn∈H2 such that d(xj,xj−1)=d(xj,xj−1) for 1≤j≤n and ⟨xj−1∣xj+1⟩xj=⟨xj−1∣xj+1⟩xj for 1≤j≤n−1 (see Definitions 3.1 and 5.2).
Once we know that AP holds for convex chains in H2, the Avalanche Principle for CAT(−1) spaces follows from the next theorem:
Theorem 1.7**.**
Let X be a CAT(−1) space, and consider a good chain x0,x1,…,xn in X with respective comparison chain x0,x1,…,xn in H2. Then
The inequality τ(x0,x1,…,xn)≤τ(x0,x1,…,x3) in Theorem 1.7, which is equivalent to d(x0,xn)≤d(x0,xn), was proved by C. Epstein in H3 [9] by an elaborate argument, and by A. Granados when X is a complete simply connected Riemannian manifold with sectional curvature bounded above by −1 [11], under similar assumptions. Both authors used this inequality to prove extensions of the classical Schur comparison theorem for plane curves [5, p. 36]:
Theorem 1.9** (Extended Schur).**
Let X be a complete simply connected Riemannian manifold with sectional curvature bounded above by −1. Suppose that f is a curve in X with length L and g is a simple curve in H2 with the same length L that together with its chord bounds a convex region of the upper half plane. Suppose that the geodesic curvatures satisfy
kf(s)≤kg(s) , where s is the common arc-length parameter. Then the length of the chord of f is greater than or equal to the length of the chord of g.
Therefore, Theorem 1.7 implies the previous versions for the case of good chains, and hence Schur theorem 1.9 for curves with geodesic curvatures kf(s)≤kg(s)≤1. See also [12, Thm 2.3.13] for a result of similar spirit.
Organization of the paper:
Section 2 presents the main properties of the hyperbolic plane H2 that we use throughout the paper. In Section 3 we reduce the study of convex chains to the ones contained in curves of constant geodesic curvature. We use this reduction in Section 4 and prove Theorem 1.6 for the case of convex chains. Section 5 deals with the non convex case, as well as with Theorem 1.7.
2. Preliminaries of Hyperbolic Geometry
We start with some basic properties of the upper half plane H2. This is a geodesic metric space in the sense that every two points x,y∈H2 can be joined by an arc isometric to a closed interval of length d(x,y). This arc is unique and is denoted by xy. For every three distinct points x,y,z in H2, the Riemannian angle between the arcs zx and zy is denoted by ∠z(x,y). The relation between angles and distances is given by the hyperbolic laws of cosines and sines:
Proposition 2.1**.**
For a geodesic triangle in H2 with sides a, b and c and opposite angles α, β and γ:
Law of Cosines*:*
[TABLE]
Law of Sines*:*
[TABLE]
A quadrilateral with vertices x,y,z,w∈H2 such that ∠x(w,y)=∠y(x,z)=π/2 and d(x,w)=d(y,z) is called a Saccheri quadrilateral. As a consequence of the hyperbolic trigonometric laws we obtain:
Corollary 2.2**.**
If x,y,z,w∈H2 form a Saccheri quadrilateral with ∠x(w,y)=∠y(x,z)=π/2, d(x,w)=d(y,z)=a, d(x,y)=b and d(z,w)=ℓ, then
[TABLE]
Proof.
Applying (LC) to the triangles y,w,z and x,y,w respectively, we obtain
and hence
2sinh2(ℓ/2)=cosh(ℓ)−1=cosh2(a)[cosh(b)−1]=2cosh2(a)sinh2(b/2). Dividing by 2 and taking square root the result follows. ∎
Applying identity (2) we obtain cosh(d(i,eiφ))=csc(φ) for 0<φ≤π/2 and d(i,λi)=log(λ) for λ>1. In addition, the points i,eiφ, λeiφ and λi form a Saccheri quadrilateral, and the previous corollary implies
Corollary 2.3**.**
If λ>1,0<φ≤π/2, then
sinh(2log(λ))=csc(φ)sinh(2d(eiφ,λeiφ)).
3. Convex chains and distorted chains
By a chain we always mean an ordered set of points x0,x1,…,xn∈H2. Such a chain lies (or is contained) in a curve γ:I→H2 (where I⊂R is an interval) if xj=γ(tj) and t0,t1,t2,…∈I is a monotone sequence. In what follows we will only deal with hyperbolic geometry, so notions such as segments, polygons, half planes, convex hulls, etc. are always considered with respect to the hyperbolic distance.
Definition 3.1**.**
A chain x0,x1,…,xn∈H2 is called convex if the convex hull of x0,…,xn is the polygon with sides x0x1,x1x2,…,xn−1xn,xnx0.
By a simple induction argument, every convex chain has non-negative tension.
Definition 3.2**.**
Let x0,…,xn∈H2 be a φ-good chain with 0<φ≤π/2. The φ-distorted chain of x0,…,xn is the chain y0,…,yn in H2 contained in a curve with constant geodesic curvature equal to cos(φ) and so that d(yj,yj−1)=d(xj,xj−1) for 1≤j≤n.
Clearly all distorted chains are convex. The goal of this section is to prove the following proposition, allowing us to work with convex chains contained in curves of constant geodesic curvature:
Proposition 3.3**.**
Let x0,…,xn∈H2 be a φ-good convex chain and consider the corresponding φ-distorted chain y0…,yn.
Then
[TABLE]
We begin with a lemma.
Lemma 3.4**.**
Let x0,x1,x2 be a φ-good chain in H2 with 0<φ≤π/2. If y0,y1,y2 is the φ-distorted chain for x0,x1,x2, then ∠x1(x0,x2)≥∠y1(y0,y2).
Proof.
Assume that y0,y1,y2 lie in the curve μ:t→teiφ with ∣y2∣>∣y0∣ and consider the (a,b)-canonical chain z0,z1,z2 contained in μ, with z1=y1 and ∣z2∣>∣z0∣. The map (x,y)↦sinh(x)sinh(x−y) is increasing in x for 0≤x and decreasing in y for 0<y<x, which by (LC) implies
[TABLE]
and hence ∠x1(x0,x2)≥∠z1(z0,z2).
On the other hand, since min(d(y0,y1),d(y1,y2))≥a=d(z0,z1)=d(z1,z2), for j=0,2, the point zj lies between the points y1 and yj in μ, implying ∠z1(z0,z2)≥∠y1(y0,y2) and obtaining the desired inequality. ∎
Now we define the following process for a good convex chain x=x0,…,xn. Fix 1≤k≤n−1, and let α=∠xk(xk−1,xk+1). For α≤γ≤π, let x(k)(γ) be the unique convex chain x0(γ),…,xn(γ) satisfying d(xj(γ),xj−1(γ))=d(xj,xj−1) for 1≤j≤n, ∠xj(γ)(xj−1(γ),xj+1(γ))=∠xj(xj−1,xj+1) for 1≤j≤n−1 with j=k, and ∠xk(γ)(xk−1(γ),xk+1(γ))=γ.
For such construction we prove the following:
Lemma 3.5**.**
Assume d(x0,xn)≥d(xi,xj) for all 0≤i<j≤n with equality only if i,j=0,n. Then given 0≤p≤q≤r≤s≤n, the map γ↦tp,q,r,s(γ)=d(xp(γ),xs(γ))−d(xq(γ),xr(γ)) is non decreasing for α≤γ≤π. In particular, γ↦τ(x(k)(γ)) is non increasing.
Proof.
By an inductive argument it is enough to show the result for p=0, r−q=n−1 and s=n. Define di,j=d(xi(γ),xj(γ)) and αi,j,l=∠xj(γ)(xi(γ),xl(γ)). We will compute the derivative (tq,r)γ=(t0,q,r,n)γ=(d0,n)γ−(dq,r)γ presenting the computations for q=0,r=n−1 since the other case is similar. By (LC) we have the relations
Since x0(γ),…,xn(γ) is a convex chain for all α≤γ≤π, we have 0≤αk,0,n−1≤αk,0,n, and hence (t0,n−1)γ≥0 whenever αk,0,n≤π/2. Similarly, (t1,n)γ≥0 whenever α0,n,k≤π/2. To prove that both conditions hold for α≤γ≤π, let α≤u≤π be the maximal angle so that αk,0,n,α0,n,k≤π/2 and (t0,n−1)γ,(t1,n)γ≥0 for all α≤γ<u. We will prove that u=π.
Our assumption about x0,…,xn implies
[TABLE]
and hence ∠x0(γ)(xk(γ),xn(γ)),∠xn(γ)(x0(γ),xk(γ))<π/2 for γ in a neighborhood of α, implying α<u. But if u<π, since (t1,n)γ is non negative in (α,u), by the mean value theorem we have
[TABLE]
implying ∠x0(γ)(xk(γ),xn(γ))<π/2, in a neighborhood of u. This also happens for (t0,n−1)γ, contradicting the definition of u and completing the proof of the lemma.
∎
Let x=x0,…,xn, y=y0,…,yn, and consider the sequence z0,z1,…,zn−1 of convex chains defined inductively by z0=y, and zk=zk−1(k)(∠xk(xk−1,xk+1)) for 1≤k≤n−1. By Lemma 3.4, ∠xk(xk−1,xk+1)≥∠yk(yk−1,yk+1) for 1≤k≤n−1, and since z0 lies in a curve of constant geodesic curvature less than 1, we are in the assumptions of Lemma 3.5, therefore τ(z1)≤τ(z0). Inductively, this assumption holds for every 1≤k≤n−1, and hence τ(z1)≤τ(z0). Since zn−1=x, we are done.
∎
As an immediate corollary of the previous proofs we have:
Corollary 3.6**.**
If x0,x1,…,xn is a good convex chain in H2 then ∠x0(x1,xn)≤π/2 and d(x0,xn)≥d(xi,xj) for all 0≤i<j≤n.
Corollary 3.7**.**
Every sub-chain of a convex good chain is good.
Proof.
For x0,…,xn convex and φ-good, it is enough to show that x0,xk,xn is φ-good for arbitrary 1≤k≤n−1. If y0,…,yn is the φ-distorted chain for x0,…,xn, Lemmas 3.4 and 3.5 imply ∠xk(x0,xn)≥∠yk(y0,yn), d(y0,yk)≤d(x0,xk) and d(yk,yn)≤d(xk,xn). This means that the chain z0,zk,zn contained in a curve with constant geodesic curvature cos(φ) and with d(zk,zj)=d(xk,xj) for j=0,n satisfies ∠zk(z0,zn)≤∠yk(y0,yn)≤∠xk(x0,xn) and hence x0,xk,xn is φ-good by Lemma 3.4.
∎
4. Proof of the Avalanche Principle: convex case
For λ1,λ2,…,λn>1 and 0<φ≤π/2, consider the chain x(λ1,…,λn;φ)=x0,x1,…,xn given by x0=eiφ, and xj=λ1⋯λj⋅x0 for j≥1. Every φ-distorted chain can be considered of this form.
Proposition 4.1**.**
The function φ↦τ(x(λ1,…,λn;φ)) is non-increasing for 0<φ≤π/2.
We need a lemma:
Lemma 4.2**.**
If x,y,z,w≥0 satisfy min(x,y,z,w)=x, max(x,y,z,w)=y, and x+y≤z+w, then:
[TABLE]
Proof.
The tanh function is increasing, so it is enough to prove the result replacing x by x′=z+w−y under the assumptions z≤w≤y and x′≤y. In this case we have
it is enough to show that g(t)=τ(x(a,b,c;arccsc(t))) is non-decreasing for t≥1, which is the same as g′(t)≥0.
For 0≤i<j≤3, let di,j=d(xi,xj) and si,j=d(λ1⋯λi,λ1⋯λj). By Corollary 2.3 we have sinh(di,j/2)=t⋅sinh(si,j/2) and hence (di,j)′:=∂t∂di,j=2cosh(di,j/2)sinh(si,j/2)=2t−1tanh(di,j/2). We obtain
g′(t)=(d0,2)′+(d1,3)′−(d1,2)′−(d0,3)′=2t−1(tanh(d0,2/2)+tanh(d1,3/2)−tanh(d1,2/2)−tanh(d0,3/2)), and since d0,2+d1,3≥d1,2+d0,3 and d0,3≥d0,2,d1,3≥d1,2, Lemma 4.2 applies, concluding g′(t)≥0.
∎
If we define gα(x,y)=∣y−x∣+(y−x)2+4xysin(α), t0=1 and tj=λ1⋯λj for 1≤j≤n, by using (2) we obtain the formula
[TABLE]
Also, the identity g0(x,y)=2∣y−x∣ implies
[TABLE]
Since λj>1 for each j, we also have the inequality
[TABLE]
implying
[TABLE]
It only remains to note that λj≥λ for 2≤j≤n−1, which follows from (6) and (10) since
[TABLE]
The proof is complete in this case.
∎
5. Avalanche Principle for CAT(−1) spaces
In this section we define CAT(−1) spaces and prove Theorem 1.7. For three distinct points x,y,z in a geodesic metric space X, a geodesic triangle with vertices x,y,z will be denoted by △(x,y,z). For such a triangle, a comparison triangle will be a geodesic triangle △(x,y,z)=△(x,y,z)⊂H2, with d(p,q)=d(p,q) for p,q=x,y,z. If p belongs to a side of △(x,y,z), say at xy, the comparison point of p is the unique point p in the side xy of △(x,y,z) satisfying d(p,x)=d(p,x).
Definition 5.1**.**
The metric space X is a CAT(−1) space if it is geodesic, and for every geodesic triangle △(x,y,z) in X and every pair of points p,q in sides of △(x,y,z), the corresponding comparison points p,q in △(x,y,z)⊂H2 satisfy d(p,q)≤d(p,q).
We have a characterization of CAT(−1) spaces in terms of the law of cosines. For a,b>0 and 0≤γ≤π, let
[TABLE]
The law of cosines implies c=L(a,b,γ) if and only if a geodesic triangle in H2 with sides a,b,c has the property that the angle corresponding to c equals γ. Clearly L is symmetric in the first two variables and increasing in the third variable, and the identity
[TABLE]
implies that for b and γ fixed, L is increasing in the first variable while a≥b or γ≥π/2. With this notation, a metric space X is CAT(−1) if it is geodesic, and for every geodesic triangle △(x,y,z) with a=d(y,z),b=d(z,x),c=(x,y) and ∠z(x,y)=γ, we have
[TABLE]
where ∠z(x,y) denotes Alexandrov angle (see [4, Ch. II, Prop. 1.7]).
Definition 5.2**.**
For a chain x0,…,xn in a metric space X, its comparison chain is the essentially unique convex chain x0,…,xn∈H2 so that △(xj−1,xj,xj+1)=△(xj−1,xj,xj+1) for 1≤j≤n−1.
We begin the proof of Theorem 1.7 with a lemma relating convex and non-convex chains in H2.
Lemma 5.3**.**
Let x0,x1,x2 be a good chain in H2, with a=d(x0,x1), b=d(x1,x2), and fix e>b. For 0<γ<π, let x3(γ) the unique point in the same half-plane of x0 w.r.t. the geodesic determined by x1x2, such that ∠x1(x2,x3(γ))=γ and d(x1,x3(γ))=e. Let y3(γ) be the reflection of x3(γ) with respect to the geodesic containing x1x2, and let 0<u<π be such that x0,x1,x2,x3(γ) is a good convex chain for all 0<γ<u. Then the map γ↦τ(x0,x1,x2,x3(γ))+τ(x0,x1,x2,y3(γ)) is non-decreasing for 0<γ<u.
Proof.
Let β=∠x1(x0,x2), c=c(γ)=d(x2,x3(γ))=d(x2,y3(γ)), f=f(γ)=d(x0,x3(γ)), and g=g(γ)=d(x0,y3(γ)). It is enough to show that fγ+gγ≤0 for 0<γ<u. We will use the following relations coming from (LC):
[TABLE]
[TABLE]
Implicit differentiation gives us
[TABLE]
[TABLE]
and by (LS) applied to the triangles x0,x1,y3(γ) and x0,x1,x3(γ) respectively, we obtain
[TABLE]
Since x0,x1,x2,x3(γ) is a good convex chain, by Corollary 3.6 we obtain 0≤∠x0(x1,y3(γ))≤∠x0(x1,x3(γ))≤π/2, and hence fγ+gγ≤0, as desired.
∎
Corollary 5.4**.**
Let x0,x1,x2,x3 be a good convex chain in H2, and let y3 be the reflection of x3 with respect to the segment x1x2. Then
[TABLE]
Proof.
Consider x3=x3(γ) as a variable point depending on γ=∠x1(x2,x3), as in the statement of Lemma 5.3. By this lemma we obtain
[TABLE]
At γ=0 we have x3(0)=y3(0), and d(x1,x3(0))=d(x1,x2)+d(x2,x3(0)). Then
[TABLE]
The conclusion follows.
∎
The main ingredient of the proof of Theorem 1.7 is the case for n=3, which we prove now:
Proposition 5.5**.**
Suppose that X is a CAT(−1) space, and consider a good chain x0,x1,x2,x3 in X with respective comparison chain x0,x1,x2,x3 in H2. Then
[TABLE]
Proof.
The inequality τ(x0,x1,x2,x3)≤τ(x0,x1,x2,x3) turns out to be equivalent to d(x0,x3)≥d(x0,x3), so we will prove it first. Let P=x0x2∩x1x3, and consider the point P∈x0x2 such that P is the comparison point for P in △(x0,x1,x2). The CAT(−1) inequality implies d(P,x1)≤d(P,x1), and hence d(P,x3)≥d(x1,x3)−d(P,x1)≥d(x1,x3)−d(P,x1)=d(P,x3). In addition, since x0,x1,x2,x3 is a convex good chain in H2, Corollary 3.6 implies
[TABLE]
and we have d(P,x3)≥d(P,x3)≥d(P,x2). The monotonicity properties of L imply
[TABLE]
so ∠P(x2,x3)≥∠P(x2,x3), and since ∠P(x2,x3)≤π/2 we obtain ∠P(x0,x3)≥∠P(x0,x2)−∠P(x2,x3)≥∠P(x0,x2)−∠P(x2,x3)=∠P(x0,x3)≥π/2.
Therefore
[TABLE]
The second inequality is τ(x0,x1,x2,x3)≥−τ(x0,x1,x2,x3). For this one, let y3 be the reflection of x3 with respect to x1x2. We separate into two cases:
Case 1: The chain x0,x1,y3,x2 is convex.
Let P=x1x2∩x0y3 and consider the point P∈x1x2 so that P is the comparison point of P in x1x2. The CAT(−1) inequality applied to △(x0,x1,x2) implies d(P,x0)≤d(P,x0), and similarly d(P,x3)≤d(P,x3), obtaining d(x0,x3)≤d(x0,P)+d(P,x3)≤d(P,x0)+d(P,x3)=d(x0,y3). This last inequality is equivalent to τ(x0,x1,x2,x3)≥τ(x0,x1,x2,y3) and by Corollary 5.4 we obtain
τ(x0,x1,x2,x3)≥−τ(x0,x1,x2,x3).
Case 2: The chain x0,x1,y3,x2 is not convex.
W.l.o.g. suppose that x2 is an interior point of convex hull of x0,x1,y3, and consider x3 and y3 as points depending on γ=∠x1(x2,x3) as in Lemma 5.3. Let β=∠x1(x0,x2), a=d(x0,x1), b=d(x1,x2), c=c(γ)=d(x2,x3(γ))=d(x2,y3(γ)), d=d(x0,x2), e=d(x1,x3(γ))=d(x1,y3(γ)), f=f(γ)=d(x0,x3(γ)), and g=g(γ)=d(x0,y3(γ)).
Also, let 0<u<π be the angle so that ∠x2(x0,y3(u))=π. By triangle inequality, d(x0,x3)≤d(x0,x2)+d(x2,x3)=d+c, and it is enough to prove that
[TABLE]
To do this, note first that at γ=0 we have d+2e−(f(0)+2b+c(0))=d+2(b+c(0))−(f(0)+2b+c(0))=d+c(0)−f(0)≥0. In addition, at γ=u we have
d+2e−(f(u)+2b+c(u))=(d+e−f(u)−b)+(d+e−(d+c(u))−b)=τ(x0,x1,x2,x3(u))+τ(x0,x1,x2,y3(u)), which is nonnegative by Corollary 5.4.
The conclusion follows if we prove that the derivative of the map γ↦f+2b+c−d+2e (which is fγ+cγ) does not change sign on the interval (0,u). But, similarly to the computations made in the proof of Corollary 5.3, we obtain
where in the first inequality we used π≥∠x2(x1,y3)≥∠x2(x1,y3(u))=π−∠x2(x0,x1)≥π/2, and in the second inequality we used 0≤∠x0(x1,y3(u))≤∠x0(x1,x3)≤π/2.
We conclude sin(∠x3(x0,x1))≥sin(∠y3(x1,x2), implying fγ+cγ≤0 for all 0<γ<u and completing the proof of the proposition. ∎
We will use induction on n. The case for n=3 is Proposition 5.5, so suppose n≥4, and assume that the result holds for all good chains of length less than n. Let x0,…,xn∈X be a good chain with comparison chain x0,…,xn∈H2.
Since we have the decomposition
[TABLE]
it is enough to show that
∣τ(x0,x2,x3,…,xn)∣≤τ(x0,x2,x3,…,xn). To do this, let y0,y2,y3,…,yn∈H2 be the comparison chain for x0,x2,x3,…,xn. The chain x0,x2,x3,…,xn is good by Corollary 3.7, so our inductive assumption implies ∣τ(x0,x2,x3,…,xn)∣≤τ(y0,y2,y3,…,yn). In addition we have d(y2,y0)=d(x2,x0) and ⟨yj−1∣yj+1⟩yj=⟨xj∣xj−1⟩xj+1 for 3≤j≤n−1, implying d(yj,yj−1)=d(xj,xj−1) for 3≤j≤n and ∠yj(yj+1,yj−1)=∠xj(xj+1,xj−1) for 3≤j≤n−1. But we also have τ(x0,x1,x2,x3)≤τ(x0,x1,x2,x3), which means d(x0,x3)≤d(x0,x3)=d(y0,y3), and hence ∠y2(y3,y0)≥∠x2(x3,x0). In this case Lemma 3.5 implies τ(y0,y2,y3,…,yn)≤τ(x0,x2,x3,…,xn), concluding the proof of the theorem.
∎
Acknowledgment I thank Jairo Bochi for very interesting and valuable discussions and corrections. I was partially supported by CONICYT PIA ACT172001 during the preparation of this article.
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