Blow-up analysis for a Hardy-Sobolev equation on compact Riemannian manifolds with application to the existence of solutions
Youssef Maliki, Fatima Zohra Terki

TL;DR
This paper analyzes a singular elliptic equation with critical Sobolev and Hardy potentials on compact Riemannian manifolds, providing a decomposition of Palais-Smale sequences and establishing existence of solutions at various energy levels.
Contribution
It introduces a new $H^2_1$ decomposition for Palais-Smale sequences and applies it to prove the existence of solutions with different energies.
Findings
Decomposition of Palais-Smale sequences on manifolds
Existence of solutions at multiple energy levels
Application to Hardy-Sobolev equations
Abstract
On a compact Riemannian manifold, we study a singular elliptic equation with critical Sobolev exponent and critical Hardy potential. In a first part, we prove an type decomposition result for Palais-Smale sequences of the associated energy functional. In a second part, we apply the decomposition result to obtain solutions of different energy levels.
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Taxonomy
TopicsNonlinear Partial Differential Equations · Advanced Mathematical Modeling in Engineering · Advanced Mathematical Physics Problems
Blow-up analysis for a Hardy-Sobolev equation on compact Riemannian manifolds with application to the existence of solutions.
Y. Maliki∗ and F.Z. Terki
Y. Maliki, F.Z. Terki Département de Mathématiques, Université Abou Bakr Belkaïd, Tlemcen, Tlemcen 13000, Algeria.
[email protected], [email protected]
Abstract.
On a compact Riemannian manifold, we study a singular elliptic equation with critical Sobolev exponent and critical Hardy potential. In a first part, we prove an type decomposition result for Palais-Smale sequences of the associated energy functional. In a second part, we apply the decomposition result to obtain solutions of different energy levels.
1. Introduction
Let ) be a compact dimensional Riemannian manifold. Denote by its injectivity radius. For a fixed point , define (after [6]) on a function as follows
[TABLE]
Let be a continuous functions on and consider the following Hardy-Sobolev equation:
[TABLE]
where is the Laplacian operator on the manifold and is the Sobolev critical exponent.
Equation (), when the Hardy potential replaced by , is the famous Yamabe equation arising from the conformal deformation of the metric and which has been largely studied( see [1] for an exposure of the main pioneering works). When the function is of power , equation() appears as a case of equations that arise in the study of conformal deformation to constant scalar curvature of metrics which are smooth only in some ball ; it is a kind of a singular Yamabe problem that has been formulated and studied in [6].
On the Euclidean space , equation (), with a function involved in the right-hand side, has been studied in [10]. The author obtained some existence results after having proved a result on decomposition of Palais-Smale sequences of the functional energy. About this decomposition result, the author showed that the singular term does interfere in the decomposition and gives rise to a second type of bubbles in addition, of course, to bubbles which results from the existence of the Sobolev exponent.
In this paper, we aim at extending this decomposition result to the context of compact Riemannian manifolds and equations like (). To achieve this aim, we follow the authors in [3] in their constructions when they extended, to Yamabe type equations on compact Riemannian manifold, the Struwe’s [11] decomposition result. More precisely, for our decomposition result we prove that Palais-Smale sequences split into the sum of a solution of equation() and bubbles which construct from solutions and on of equations
[TABLE]
and
[TABLE]
As an application, we use the decomposition result to determine energy regions in which Palais-Smale sequences are compact and then converge, up to subsequences, to solutions of () of different energy levels.
2. Notations and background materials
In the following, we introduce some notations and materials that will be used throughout the paper.
Denote by , the Euclidean Sobolev space defined as the completion, with respect to the norm
[TABLE]
of the space of smooth functions on with compact support.
Let denote the best constant in the Sobolev inequality
[TABLE]
It is well known that the exact value of is
[TABLE]
where denotes the volume of the unit sphere in the Euclidean space .
Let denote the best constant in the Hardy inequality on ,
[TABLE]
Let and consider on the equation
[TABLE]
By a classification result in [12], positive solutions of (2.2) are the family of functions
[TABLE]
where
[TABLE]
and
[TABLE]
Moreover, the family of functions satisfies
[TABLE]
On the compact Riemannian manifold , we consider the Sobolev space consisting of the completion of with respect to the norm
[TABLE]
By the Rellich-Kondrakov theorem ( see [4] ), if is compact and , the inclusion is compact. If , the inclusion is only continuous. On the Sobolev space , the following optimal Sobolev inequality holds ( see [5] , Theorem 4.6)). For any , there exists a positive constant such that
[TABLE]
We denote by the space of functions on such that . This space is endowed with the norm
[TABLE]
In [6], it is shown that the Sobolev space is continuously embedded in and the following Hardy inequality on holds: for every there exists a positive constant such that for any ,
[TABLE]
If is supported in a ball , then
[TABLE]
with goes to when goes to [math].
In the paper, we will denote by a ball of center and radius , the point will be specified either in or in , and is a ball in of center [math] and radius .
Finally, we denote by , where , a cut-off function that satisfies , and .
3. Decomposition of Palais-Smale sequences
Let be the functional defined on by
[TABLE]
A Palais-Smale sequence of at a level is defined to be the sequence that satisfies and .
In this section, we prove an type decomposition theorem for Palais-Smale sequences for the functional . We follow closely the blow-up theory given in [3] where the authors establish a decomposition result for a regular elliptic equation on compact manifolds and prove that a sequence of solutions of this equation decomposes into the sum of a solution of a limiting equation and bubbles which are solutions of equation(1.0). The energy of this sequence decomposes, in the same manner, into the sum of the energy of and the energy of bubbles. This result is known as the Decomposition for Palais-Smale sequences. In our case, the singular term interferes in the decomposition process and appeals to an analysis near the singular point to be done. Inspired by a decomposition result in [10], we show that two kinds of bubbles contribute in the decomposition of Palais-Smale sequences. Note that in [7], we proved, by the same techniques, a decomposition result for an arbitrarily bounded energy sequence of solution of equation ().
Before we formulate our decomposition theorem, we introduce on the functionals
[TABLE]
Now, we state the following decomposition theorem:
Theorem 3.1**.**
*Let be a compact Riemannian manifold with and let be a continuous function on that on the point , it satisfies .
Let be a Plais-Smale sequence of the functional at level . Then, there exist , sequences , sequences , converging sequences in , a solution of (), solutions of (1.0) and nontrivial solutions of (1.1) such that up to a subsequence*
[TABLE]
and
[TABLE]
The proof of the above theorem goes through several steps that we organize under the form of lemmas
Lemma 3.2**.**
Let be a Palais-Smale sequence for at level that converges to a function weakly in and , strongly in and almost everywhere in . Then, is a weak solution of () and the sequence is a sequence of Palais-Smale for such that
[TABLE]
Proof.
Let be a Palais-Smale sequence for , at level . Then, which implies that
[TABLE]
which means that is bounded in and then in . Furthermore, we have
[TABLE]
By continuity of on , for all there exists such that
[TABLE]
then, by applying Hardy inequality (2.7) that for every small there exists a constant such that
[TABLE]
since , we can find small such that which implies that is bounded.
Now, if the sequence converges to a function weakly in and , strongly in and almost everywhere in , then must satisfy
[TABLE]
In fact, the sequence is bounded in and converges almost everywhere to , we get that converges weakly in to . This clearly implies that (3.8) is satisfied.
Moreover, for , we can write
[TABLE]
with
[TABLE]
Knowing that there exists a positive constant independent of such that
[TABLE]
we get, after applying Hölder inequality, that there exists a positive constant such that
[TABLE]
which gives that , since both and are smaller than and the inclusion of in is compact for . By (3.8), we get then that
[TABLE]
On the other hand, by the weakly converges in and , we can also write
[TABLE]
with
[TABLE]
which by the Brezis-Lieb convergence Lemma equals to , hence we obtain
[TABLE]
This ends the proof of the lemma. ∎
Lemma 3.3**.**
Let be a Palais-Smale sequence of at level that converges weakly to [math] in . If , then converges strongly to [math] in .
Proof.
Let is a Palais-Smale sequence of at level that converges to [math] weakly in , then and
[TABLE]
This implies that . Hence, on the one hand, by Hardy inequality (2.7) we get as in Lemma 3.2, that for small enough ,
[TABLE]
and on the other hand, by Sobolev inequality (2.6), we also get
[TABLE]
Now, suppose that , then the above inequalities (3.10) and (3.11) , for big enough, give
[TABLE]
that is
[TABLE]
By assumption , if we take small enough so that
[TABLE]
we get a contradiction. Thus and (3.10) assures that
[TABLE]
that is strongly in . ∎
Lemma 3.4**.**
Let be Palais-Smale sequence for at level that converges weakly and not strongly to [math] in . Then, there exists a sequence of positive reals such that, up to a subsequence
[TABLE]
where , converges weakly in to a function weak solution of (1.1).
Proof.
Since the Palais-Smale sequence of at level converges weakly and not strongly in to [math], then by Lemma 3.3 .
Up to a subsequence, converges strongly to [math] in .Then, similar computations as in Lemma 3.2 give that for all small
[TABLE]
In such way that there exist two positive constant such that
[TABLE]
Let a small positive constant such that
[TABLE]
Up to a subsequence, for each we can find the smallest constant such that
[TABLE]
Note that for , it holds
[TABLE]
Let and take , such that , in such way that .
Let , and define
[TABLE]
We show that the sequence is bounded in . First we have
[TABLE]
here we have used the strong convergence of to [math] in . Similarly, we can obtain that
[TABLE]
for some positive constant and thus is bounded.
On the other hand, since goes smoothly to the Euclidean metric on , we can find a constant such that for large and such that , it holds
[TABLE]
thus, we get that is bounded in .
Consequently, up to a subsequence, converges weakly to some function .
Suppose that , we show that is a weak solution on to (1.1). First, notice that since the sequence converges strongly in to [math] and the sequence converges strongly in to , it follows that .
Let be a function with compact support included in the ball . For large, define on the sequence as
[TABLE]
Then, is bounded in and
[TABLE]
by the strong convergence of in to [math], after doing a Holder inequality, the second term of the left-hand side converges to [math]. Then we obtain
[TABLE]
Moreover,
[TABLE]
Since is a Palais-Smale sequence of , by passing to the limit when , we get that is weak solution of (1.1). ∎
Lemma 3.5**.**
Let be the solution of (1.1) given by Lemma 3.4 and such that , then up to a subsequence,
[TABLE]
where , is a Palais-Sequence for that weakly converges to [math] in and .
Proof.
For , put
[TABLE]
in such way that
[TABLE]
We begin by proving that converges weakly to [math] in and thus does .
Take a function , then we have
[TABLE]
then, for a positive constant such that , it follows that
[TABLE]
Thus, when tending , we ge that weakly in .
Now, let us evaluate . First, we have
[TABLE]
and of course
[TABLE]
Direct calculation gives
[TABLE]
It can be easily seen that the second term of right-hand side member of the above equality tends to [math] as . Furthermore, for , a positive constant, we write
[TABLE]
with
[TABLE]
where is a function in such that as .
Noting that, that goes locally in to the Euclidean metric , we get then
[TABLE]
Moreover, we have
[TABLE]
with .
We have
[TABLE]
Since is bounded in , the quantities and are bounded and hence the second term of the right-hand side member of (3.22) is . Thus, by using the weak convergence of to in that
[TABLE]
so that
[TABLE]
In similar way, for a positive constant and large, we write
[TABLE]
with
[TABLE]
with as .
Hence, when letting and , we get
[TABLE]
Also, in similar way, since is bounded in , after using Hölder and Hardy inequalities, we can easily have
[TABLE]
which yields
[TABLE]
so that in the end we obtain
[TABLE]
In similar way, we can prove that
[TABLE]
Finally, summing up all the calculations, we obtain
[TABLE]
It remains to prove that in . Let , for put and , then we have
[TABLE]
Knowing that , we get that
[TABLE]
which gives that
[TABLE]
Next, for write
[TABLE]
note that
[TABLE]
where as . Since the sequence of metrics tends locally in when to the Euclidean metric, we obtain
[TABLE]
Moreover, for a given , we have for large,
[TABLE]
On the one hand, we have
[TABLE]
and a straightforward computation shows that
[TABLE]
which implies that
[TABLE]
with as .
On the other hand, we have
[TABLE]
which leads to
[TABLE]
with
[TABLE]
so that
[TABLE]
In the same way, we can also have
[TABLE]
Summing up, we obtain
[TABLE]
and since is weak solution of (), we get the desired result. ∎
Lemma 3.6**.**
Let be a Palais-Smale sequence for . Suppose that the sequence of the above lemma converges weakly to [math] in . Then, there exist a sequence of positive numbers and a sequence of points such that up to a subsequence, the sequence
[TABLE]
converges weakly to a nontrivial weak solution of the Euclidean equation (1.0) and the sequence
[TABLE]
is a Palais-Smale sequence for that converges weakly to [math] in and
[TABLE]
Proof.
Take a function and put . By the strong convergence of to [math] in , we have for large
[TABLE]
Thus, for (in (3.14)) chosen small enough, we get that for each
[TABLE]
Now, for consider the function
[TABLE]
Since is continuous, under (3.12) and (3.13), it follows that for any , there exist small and such that
[TABLE]
Since is compact, up to a subsequence, we may assume that converges to some point .
Note first that for all , , otherwise if there exists such that , we get a contradiction due to the fact that
[TABLE]
and is chosen such that . Since , it follows that as .
Now, suppose that for all , there exists such that for all . Choose such that, and take , we get that for some and
[TABLE]
which, by virtue of (3.24) and (3.25), is impossible. We deduce then that .
For and we can find a positive constant such that for all
[TABLE]
Take such that . Then, for and a constant such that , we have
[TABLE]
and
[TABLE]
For consider the sequences
[TABLE]
As in the proof of the above lemma, we can easily check that there is a subsequence of that weakly converges in to some function , a weak solution on to (1.0). Note that this time the singular term disappears because and because of course .
It remains to show that . For this purpose, take a point and a constant such that . Since we have
[TABLE]
we get by construction of and (3.27) that for such and ,
[TABLE]
Suppose now that . Take any function with support included in a ball , with and as above. Then, by taking small enough, we get by the same calculation done in (3) that converges to [math] for all and such that . In particular, for small such that , we get
[TABLE]
which makes a contradiction. Thus .
The proof of the remaining statements of the lemma goes in the same way as in lemma 3.6. ∎
Proof of theorem 3.1.
Let be a Palais-Smale sequence for at level . It can easily seen that is bounded in , then up to a subsequence it converges to a function weakly in , strongly in and almost everywhere to in .
Thus, by Lemma 3.2, the function is weak solution of () and the sequence is a Palais-Smale sequence for at level . If converges strongly to 0 in , then the theorem is proved with . If not, then by lemma 3.4, there exists a sequence of reals such that, the sequence
[TABLE]
converges in to a solution of (1.1).
If , then by lemmas 3.5 and 3.2 the sequence
[TABLE]
is a Palais-smale sequence for at level that converges weakly to [math] in . If converges strongly, the theorem is proved with and . If not, we repeat to the procedure already applied to to obtain a Palais-Smale sequence at level that either converges strongly to [math] in and in this case the theorem is proved with or it converges only weakly, and in this case we repeat again the procedure applied to . We keep repeating this proceeding until we get a Palais-Smale sequence at level
[TABLE]
and int his case, by lemma 3.3 the Palais-Smale sequence associated to the level converges strongly to [math].
If , then by lemma 3.6, there exists a sequence of positive reals and a sequence of points such that the sequence
[TABLE]
converges, up to a subsequence to a solution of equation (1.0) and the sequence
[TABLE]
is a Palais-Smale sequence of the functional at lower level that converges weakly to [math] . If , then the sequence converges strongly and the theorem is proved with , otherwise we apply the procedure from the beginning of the proof to to obtain a palais-Smale sequence at much lower level. We keep doing this procedure so on until we obtain a Palais-Smale sequence at level that converges strongly to [math] in . ∎
As it will be shown in the following corollary, the conclusion of the above theorem is very useful in obtaining levels for which Palais-Smale sequence of converges to non zero critical points of the functional .
First, put
[TABLE]
By taking in equation (2.2), we deduce, by (2.5), that if is a constant sign solution, then
[TABLE]
On the other hand, if changes sign, then
[TABLE]
In fact, write , where and . We then get
[TABLE]
Then, since cannot be one of the functions , where defined by (2.3), then by (2.5) we get
[TABLE]
By the same way, we get
[TABLE]
Thus, we obtain
[TABLE]
Now, define
[TABLE]
We prove the following corollary:
Corollary 3.7**.**
Let be a Palais-Smale sequence of at level such that
[TABLE]
*Then, up to a subsequence, converges strongly in to a function such that .
Moreover, suppose that*
[TABLE]
Then, if
[TABLE]
the sequence converges, up to a subsequence, strongly in to a function such that .
Proof.
By theorem 3.1, there is a critical point of , a sequence of reals, , a sequence of points , a sequence of solutions of (1.1) and sequence of non trivial solutions of (1.0) such that, up to a subsequence of , we have
[TABLE]
and
[TABLE]
First, let be such that
[TABLE]
and suppose that . If there exists such that and (3), (3.36) hold, then by (2.5) we get
[TABLE]
Thus, . In the same way, if there exists such that (3) and (3.36), then
[TABLE]
which also makes a contradiction. Hence, which implies that and thus, for the same reasons as above, the converges, up to a subsequence, to in .
For the second part of the corollary, let be such that , and suppose that . First, note that by the proof of theorem 3.1, is nothing but the weak limit in of . Since , the sequence cannot converge strongly in to [math]. Then, it follows from lemmas 3.4 and 3.5 that there exists of (1.1) such that if , the sequence
[TABLE]
is a Palais-Smale sequence of that converges weakly to [math] and
[TABLE]
By (2.5), since , either changes sing or not, . Hence,
[TABLE]
which implies by the first part of the corollary that the sequence converges strongly to non zero function such that which is impossible since, if it is the case, by (3.38) and (3.33), it follows that
[TABLE]
which is against (3.34). Hence, .
On the other hand, by lemma 3.6 there exists such that the sequence
[TABLE]
is a Palais-Smale sequence that converges weakly to [math] in and
[TABLE]
Since is solution of (1.0), then which, under (3.32), implies that
[TABLE]
which also impossible since is a Palais-Smale sequence of . Hence, the function under conditions (3.32),(3.33) and (3) cannot be identically zero.
Now, suppose that there exists a solution of (1.1) such that (3) and (3.36) hold, then
[TABLE]
Thus, . Similarly, we obtain . Hence, the sequence converges, up to a subsequence, strongly to in with . ∎
4. Existence of solutions
As a consequence of corollary (3.7), we obtain the following existence result. We construct Palais-Smale sequences of the functional at levels confined between the values given in corollary 3.7. In this way, we prove the following theorem
Theorem 4.1**.**
Let be a compact Riemannian manifold of dimension , where is defined by (1.1). Let be a smooth function on . Under the following conditions:
[TABLE]
*where ** A(n,a) is defined by (4.50),
there exists a non zero weak solution of () such that , where is defined by (2.5).
Moreover, under the following conditions:*
[TABLE]
there exists a non zero weak solution of () such that .
For the proof of the above theorem, we introduce the Nehari manifold for the functional
[TABLE]
Note that for each , the function
[TABLE]
belongs to and .
Let be a cut-off function on such that, and , for some constant .
Put and for , consider on the function
[TABLE]
where and .
We begin by proving the following lemma:
Lemma 4.2**.**
There exists a constant such that if
- (1)
* and* 2. (2)
**
there holds
[TABLE]
Proof.
Consider a geodisic normal coordinate system around . In this system, the function writes (see for example the book [4], page 283.)
[TABLE]
Define for
[TABLE]
Then, one can easily have for and
[TABLE]
We have
[TABLE]
The change of variable gives
[TABLE]
The function is bounded in , then
[TABLE]
together with
[TABLE]
and
[TABLE]
Observe that for ,
[TABLE]
and
[TABLE]
Hence, we get
[TABLE]
with .
Now, by using (4.45), we get
[TABLE]
Finally, by observing that
[TABLE]
where
[TABLE]
we get
[TABLE]
with
[TABLE]
Similarly we develop the term . First, by choosing small we can write for
[TABLE]
Using the fact that and for , we obtain
[TABLE]
with .
using , (4) we get
[TABLE]
with
[TABLE]
As to the term , it develops as
[TABLE]
with . Again, we use (4.45), we obtain
[TABLE]
with
[TABLE]
Using the fact that
[TABLE]
the expansions (4), (4) and (4) give
[TABLE]
with .
Now, writing
[TABLE]
we obtain
[TABLE]
Finally, take
[TABLE]
and
[TABLE]
we get
[TABLE]
Hence, if
[TABLE]
we get (4.44). ∎
Proof of theorem 4.1.
Since the functional is bounded from below on the Nehari manifold , the variational principle of Ekland gives a Palais-Smale sequence of at the level . By definition of the manifold , is still a Palais-Smale sequence of on . Under condition (4.40) of the theorem, lemma 4.2 implies that . Therefore, converges, by corollary 3.7, strongly in to a nontrivial solution of () which then satisfies .
For the second part of the theorem, Since , then . On the other hand, the expansion (4) together with condition (4.41) of the theorem give that . Now, again by the Ekland variational principle there exists a Palais-Smale sequence at level , which by corollary 3.7 converges, up to a subsequence to a weak solution with . ∎
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