$p$-harmonic functions in $\mathbb{R}^N_+$ with nonlinear Neumann boundary conditions and measure data
Natham Aguirre

TL;DR
This paper introduces a concept of renormalized solutions for p-harmonic functions in half-spaces with nonlinear Neumann boundary conditions involving measure data, establishing existence, stability, and nonexistence results.
Contribution
It develops a new framework for analyzing p-harmonic boundary value problems with measure data and nonlinear boundary conditions, extending previous bounded domain results to unbounded half-spaces.
Findings
Existence of solutions in subcritical and supercritical cases.
Nonexistence of solutions in the subcritical case for power nonlinearities.
Characterization of removable boundary sets in supercritical cases.
Abstract
We propose and study a concept of renormalized solution to the problem in , on , where , , , is the normal derivative of , is a bounded Radon measure, and is a nonlinear term. We develop stability results and, using the symmetry of the domain, apriori estimates on hyperplanes, and potential methods, we obtain several existence results. In particular, we show existence of solutions for problems with nonlinear terms of the absorption type in both subcritical and supercritical cases. Regarding the problem with source, we study the power nonlinearity , showing existence in the supercritical case, and nonexistence in the subcritical…
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Taxonomy
TopicsNonlinear Partial Differential Equations · Advanced Mathematical Modeling in Engineering · Numerical methods in inverse problems
-HARMONIC FUNCTIONS IN WITH NONLINEAR NEUMANN BOUNDARY CONDITIONS AND MEASURE DATA
Natham Matias Aguirre Quiñonez
(December 2018)
PONTIFICIA UNIVERSIDAD CATÓLICA DE CHILE
FACULTAD DE MATEMÁTICAS
DEPARTAMENTO DE MATEMÁTICA
-HARMONIC FUNCTIONS IN WITH NONLINEAR NEUMANN BOUNDARY CONDITIONS AND MEASURE DATA
POR
NATHAM MATIAS AGUIRRE QUIÑONEZ
Tesis presentada a la Facultad de Matemáticas de la Pontificia Universidad Católica de Chile para optar al grado académico de Doctor en Matemática
Directores de Tesis:
Marta Eugenia García-Huidobro Campos, Pontificia Universidad Católica de Chile.
Laurent Véron, Université François Rabelais, Tours, Francia.
Comisión informante:
Gueorgui Dimitrov Raykov, Pontificia Universidad Católica de Chile.
Ignacio Guerra Benavente, Universidad de Santiago de Chile.
Diciembre, 2018
Santiago, Chile.
©2018, Natham Matias Aguirre Quiñonez.
1pt
A mi amado esposo,
y a nuestro futuro juntos.
AGRADECIMIENTOS
Esta tesis fue parcialmente financiada por el programa de colaboración ECOS-CONICYT C14E08, por CONICYT-PCHA/Doctorado Nacional/2014-21140322, y por la Vicerrectoría de Investigación de la Pontificia Universidad Católica de Chile a través de sus programas ‘Estadía en el Extranjero para Tesistas de Doctorado’ y ‘Beneficio de Residencia para Alumnos en Vías de Graduación’. Agradezco también al Institut Henri-Poincaré por facilitarme un agradable lugar de trabajo en mis visitas a Paris.
Contents
Resumen
En este trabajo proponemos y estudiamos un concepto de solución renormalizada al problema
[TABLE]
donde , , , es la derivada normal de , es una medida de Radon acotada, y es un término no lineal. Obtenemos resultados de estabilidad y, haciendo uso de la simetría del dominio, estimaciones en hiperplanos, y métodos de potenciales, mostramos variados resultados de existencia. En particular, mostramos existencia de soluciones para problemas con términos no lineales del tipo sumidero tanto en el caso subcrítico como el supercrítico. En el problema con fuente estudiamos el término no lineal , mostrando existencia en el caso supercrítico, y no existencia en el caso subcrítico. Además, damos una caracterización de conjuntos removibles cuando y en el caso supercrítico.
Debemos resaltar que este trabajo está motivado por resultado obtenidos para la ecuación en dominios acotados. Notamos que existen algunos resultados de existencia para problemas similares al aquí estudiado, pero en dominios acotados, y que estos son bastante restrictivos ya que, por ejemplo, no admiten cualquier medida acotada de Radon como dato. En este sentido, los principales resultados aquí presentados son completamente nuevos.
Abstract
We propose and study a concept of renormalized solution to the problem
[TABLE]
where , , , is the normal derivative of , is a bounded Radon measure, and is a nonlinear term. We develop stability results and, using the symmetry of the domain, apriori estimates on hyperplanes, and potential methods, we obtain several existence results. In particular, we show existence of solutions for problems with nonlinear terms of the absorption type in both the subcritical and supercritical case. For the problem with source we study the power nonlinearity , showing existence in the supercritical case, and nonexistence in the subcritical one. We also give a characterization of removable sets when and in the supercritical case.
We remark that this work is motivated by results obtained for the problem in bounded domains. We note that there are some existence results for similar problems to the one that we propose here, although in bounded domains, and that these are fairly restrictive since, for example, not any Radon measure is allowed as datum. In this sense, the main results presented here are completely new.
Chapter 1 Introduction
In this work we consider the problem of finding solutions to
[TABLE]
where , , , and . Here is the space of Radon measures in with bounded total variation which are supported in , is the normal derivative of , is a nonlinear term, and
[TABLE]
Consider the related problem of finding a solution to
[TABLE]
where is a bounded domain in , , and . If a unique solution can be obtained by the theory of monotone operators from into its dual , since in this case any bounded measure in belongs to this dual.
When the study of problem (1.0.2) is based upon the theory of renormalized solutions. In the case the concept of renormalized solution was first introduced in [9], wherein the authors showed existence and partial uniqueness results. The proof of existence relies in a delicate and very technical stability result. The concept of renormalized solution has been since then the main tool to study degenerate elliptic problems with measure data. We refer the reader to [25] for an overview of the concept and further references. Let us note that in the special case the concept of renormalized solution coincides with the concept of entropy solutions to (1.0.2) introduced in [2] (see also [5]), in which it is shown both existence and uniqueness for the case .
When is nontrivial, the nature of equation (1.0.2) depends on the sign of . To emphasize this fact, and in accordance with the literature, we call it a problem with absorption when , and a problem with source when . Further, we say that the problem is subcritical whenever there are conditions imposed on the growth of ; otherwise we say that the problem is supercritical.
For the problem with absorption, existence of renormalized solutions to (1.0.2) in subcritical cases has been shown in [3] and [25]. In [3] the author considers , while more general nonlinearities are considered in [25]. Let us mention that in the power case one obtains the sufficient condition if , and if . In the case exponential-type nonlinearities are considered, but under a restriction in the size of the measures.
The problem with absorption in supercritical cases has been studied in [4]. There the authors show that given a fixed nonlinear term existence of renormalized solutions to (1.0.2) holds for a certain class of measures. Their results, which are quite general, are based mainly on a delicate study of the Wolff potential and can be applied to establish sufficient conditions for existence of renormalized solutions when the form of the nonlinearity is more explicit. For example, when , , a sufficient conditions on the measure is that it be absolutely continuous with respect to the Bessel capacity. A boundedness condition on the measure is obtained when the nonlinearity is of exponential-type.
Problem (1.0.2) is rather more difficult when it is of the source type. In fact, in this case only nonnegative solutions are considered. In [18] the authors show equivalent sufficient conditions to obtain nonnegative renormalized solutions to (1.0.2) when and is a nonnegative measure. It is also shown that, if the measure is compactly supported in , these conditions are necessary. Their results, which are obtained through a careful study of the Wolff potential and its relationship to the Bessel and Riesz potential, show in particular that if and , or and (i.e., the subcritical case), then any nonnegative measure with small enough norm admits a solution. In the supercritical case, a sufficient condition is that the measure must be ‘Lipschitz’ continuous with respect to the Bessel capacity. We note also that their main results allows them to present a complete characterization of removable sets for (1.0.2) in terms of some fractional Bessel capacities, as well as to prove Liouville-type results for problems in the whole .
Going back to problem (1.0.1), in the case we can similarly obtain a unique solution in the space by using the theory of monotone operators. This follows from the fact that if then functions in have well defined continuous and bounded traces in , and so any element in can be seen as an element in the dual of . Of course, this works whenever is in the dual of (even if ). In fact, this is the approach used in [26], where it is proven the existence of weak solutions to the subcritical problem with absorption
[TABLE]
where , , is a nonnegative constant, is a bounded domain, , and satisfies if .
In the case we turn to the idea of renormalized solutions. In [1] a concept of renormalized solution was proposed for a Neumann problem in bounded domains and with nonnegative measures in (see also [16]). However, to our knowledge, there is no proposed definition of renormalized solutions to Neumann problems such as (1.0.1) for general bounded Radon measures. In this work we propose such a definition and then prove existence of renormalized solutions for various types of nonlinearities. Indeed, we have Theorem 5.2.2 for the case , Theorems 6.1.11 and 6.1.12 for subcritical problems with absorption, Theorem 6.2.7 for supercritical problems with absorption, and Theorem 7.2.2 for a supercritical problem with source. On the other hand, in Theorem 7.3.2 we show nonexistence of nontrivial nonnegative solutions for the same problem with source but in the subcritical case.
Our approach to solving problem (1.0.1) is to turn it into an associated problem in the whole . Indeed, formally, if is a solution to (1.0.1) then we expect that , its even reflection across , should be a solution to
[TABLE]
where is a normalized -dimensional Hausdorff measure concentrated in . Note however that not every solution of the above problem would yield a solution to (1.0.1), unless it is a symmetric solution, and so the problems are not equivalent.
The advantage of looking at this extended problem is that we can obtain a solution to (1.0.3) by applying the theory developed in [9], [25], [4], and [18], to an increasing sequence of bounded domains. In order for this approach to work we need to establish some stability results. Then, to recover a solution to (1.0.1), we show that the solutions obtained through this process might in fact be taken to be symmetric with respect to . It is worth mentioning that with our definition of renormalized solution to problem (1.0.1), becomes in fact a local renormalized solution of the associated problem in , as defined for example in [3] and [25].
This thesis is organized as follows. In Chapter 2 we collect all the relevant preliminary definitions and results we shall need both to define renormalized solutions and to obtain the existence results. Since we consider measures and functions in both and , we will need to consider the problem of obtaining well defined traces, as well as the interplay of the Bessel capacities defined in and . In particular, we will make use of trace and extension operators in the Lizorkin-Triebel spaces.
In Chapter 3 we give the definitions of renormalized solutions in bounded domains and of local renormalized solutions in general domains, define renormalized solutions to problem (1.0.1), and state estimates and other results from [9] which will be used in the sequel. We prove some properties of renormalized solutions to problem (1.0.1), and also show that renormalized solutions to (1.0.1) do in fact exists by proving that the fundamental solution to problem (1.0.1), with , is a renormalized solution in the sense of our definition with the Dirac mass.
In Chapter 4 we study the problem of obtaining local renormalized solutions to in . The existence of such solutions is given in Theorem 4.0.1. The proof is based on two lemmas, both of which are of use later when dealing with nonlinear terms. The first states that given a sequence of renormalized solutions to (1.0.2) with , , and data , we can find a convergent subsequence such that the limit function has the necessary properties to be a local renormalized solution in . This is proven by a slight modification of the argument found in [9]. The second lemma is a stability result that will be used to show that the function is indeed a local renormalized solution. This is proven for more general equations than the ones considered in the first lemma, and its proof is based on the argument given in [17] to bypass the rather involved arguments developed in [9].
In Chapter 5 we show that the solution obtained by the above method is symmetric with respect to . We do this by showing that, in a bounded domain, if a measure is concentrated in and the domain is symmetric with respect to then any renormalized solution has the same symmetry. For this we use the partial uniqueness result obtained in [9]. Then, in Theorem 5.2.2, we use this symmetry to recover a solution to the original problem (1.0.1) when .
In Chapter 6, Section 6.1, we consider the problem of obtaining renormalized solutions to (1.0.1) in subcritical cases with absorption. Here we use the theory developed in [25] in the same spirit as the previous chapters, obtaining local renormalized solutions in as the limit of solutions in bounded domains, and then using symmetry to obtain solutions to (1.0.1). Our approach is to use the existence results developed for problem (1.0.2) to obtain solutions to
[TABLE]
as an intermediate step towards solving (1.0.1). We obtain solutions to the above equation by solving (1.0.2) when is multiplied by a sequence that is concentrating at the origin and then letting . The main result in this regard is Lemma 6.1.8 where we show, under very general assumptions, that if are the solutions with nonlinear term then converges, in a suitable sense, to . The result is proven by making a decomposition of the domain in order to use the assumptions on as well as the continuity properties of functions and their traces.
In the case the existence result is given in Theorem 6.1.11, while for the case is given in Theorem 6.1.12. Let us mention that when , , , Theorem 6.1.11 guarantees existence of renormalized solutions to (1.0.1) provided
[TABLE]
If then Theorem 6.1.12 only requires , and in fact exponential-type nonlinearities are allowed, but this imposes conditions on the size of the measure.
In Section 6.2 we consider supercritical problems with absorption under the condition . Here we use mainly the work in [4]. We have left the definition of the Wolff potential of a measure, and other related quantities, to this chapter since they are only used from this point forward. As in the previous section, we obtain solutions to (1.0.4) as an intermediate step towards solving (1.0.1). The main tool for this is the improvement of an estimate of renormalized solutions, in terms of the Wolff potential of their respective measures, from in to in any hyperplane. We also show that, given a fixed measure and a nondecreasing sequence of domains, it is possible to obtain a nondecreasing sequence of renormalized solutions in said domains. Both results are needed to show the main existence result, Theorem 6.2.7. This theorem is then used to obtain explicit conditions on the measure when more is known about the rate of growth of the nonlinearity. For example, when , , we obtain as sufficient condition that the measure must be absolutely continuous with respect to the Bessel capacity. Exponential-type nonlinearities are also considered.
Finally, in Chapter 7 we consider nonnegative solutions to the problem with source when and . Our work here follows closely the ideas in [18], particularly those used to treat problem (1.0.2) when . We begin by establishing necessary and sufficient conditions for existence of nonnegative renormalized solutions to (1.0.1). In particular, in the supercritical case, we obtain existence of renormalized solutions to (1.0.1) when the nonnegative measure is ‘Lipschitz’ continuous with respect to the Riesz capacity.
In Corollary 7.3.1 we note that if is a solution with datum , then must satisfy the above condition which, together with the properties of the Riesz capacity, implies the nonexistence of nontrivial nonnegative solutions to (1.0.1) in the subcritical case, that is, when
[TABLE]
This result is not surprising as it is a natural counterpart to the nonexistence result in [18]. It is also in agreement with the nonexistence result in [15] for the linear case (i.e., ) where it is shown that any classical, but possibly singular at the origin, nonnegative solution to (1.0.1), with , , and in the range , must be trivial.
We finish with the problem of characterizing when a compact set is removable for (1.0.1) in the case and . We say that such a set is removable if every nonnegative -harmonic function satisfying the Neumann boundary condition in can be extended to a solution of (1.0.1). The necessary and sufficient conditions for existence given in Corollary 7.3.1 and Corollary 7.2.3 allows us to show that a set is removable in the supercritical case if and only if its Riesz capacity is zero.
Chapter 2 Preliminary definitions and results
Here we collect basic definitions and results needed in the sequel. We remark that, as in [9], we shall make use of Bessel capacities to decompose measures in . Since we will frequently consider the behavior of functions and measures when restricted to hyperplanes, we will also consider capacities in . To this end, we will introduce the more general capacities associated with the Lizorkin-Triebel spaces .
Let us first introduce some notation. For any measurable set we denote by its Lebesgue measure. When we take this measure to be the -dimensional Lebesgue measure. We let be the open ball of radius centered at (simply when ). Depending on the context, when this could be either a -dimensional ball in or a -dimensional ball in . For any set , we let be the characteristic function of . The truncation of functions will be very important in the sequel. For any , we let .
By an abuse of notation, we define . Similarly, we define . We remark that given a domain , are the usual Lebesgue spaces, while are the usual Sobolev spaces. The norm in the spaces will be written indistinctly as , , or simply . The space, , is the usual space of times continuously differentiable functions, and is the subspace of elements with compact support in .
2.1 Bessel capacities
We start with the standard definition of Bessel capacities in (see [10] for details). For any compact set we let
[TABLE]
where is the Schwartz class, and define for any and
[TABLE]
with the convention that . Here is the norm in the Bessel potential spaces of functions with , where is the Bessel kernel of order , defined as (note that is a dense subset of this space). Then we extend the definition to open sets by
[TABLE]
and finally to arbitrary sets by
[TABLE]
Note that when we have , and so in this case the Bessel capacities can be defined using Sobolev spaces. We do not follow this approach since we will need to consider the case when . On the other hand, we remark that we have the following equivalent definition of capacity:
[TABLE]
where
[TABLE]
(see Proposition 2.3.13 of [10]).
We will also use the Riesz capacities. They can be defined as the capacities associated to the Riesz potential spaces , i.e., the space of functions with , where is the Riesz kernel of order . We will denote them by . Let us explicitly state however that our main interest are the capacity in and the capacity in (which we identify as ).
We say that a property holds quasi-everywhere in (abbreviated as ) if there exists a set such that the property holds in and .
We say that a function is quasi-continuous in if for every there is an open set such that and . Unless otherwise stated, we assume that quasi-continuous functions are finite. Whenever we cannot assert that a quasi-continuous function is finite, the statement means that is continuous with respect to the topology of the extended real line.
We say that a set is quasi-open if for every there exists an open set such that and . Clearly, countable unions of quasi-open sets are quasi-open. It is also immediate that if is quasi-continuous then the sets and are quasi-open. By a result of [8], for every bounded quasi-open set there exists a nonnegative sequence such that and in (see Lemma 2.2 of [17]).
Remark 2.1.1
When dealing with a bounded domain , it is more natural to define and use the so called condenser capacity associated with (see for example Section 7.6 of [10]). Indeed, this condenser capacity is the capacity used in works such as [9] and [17]. However, Theorem 2.38 of [14] shows that the condenser capacity is equivalent to our definition of capacity whenever for any fixed (see also section 2.7 of [10]). Since in our applications we always ultimately have for some , we see that we can always assume the two definitions are equivalent.
2.2 Decomposition of measures
Let be the set of Radon measures of bounded total variation. For any Borel set we let be the set of measures in supported in . For measures we let
[TABLE]
be its total variation in .
We will work mainly with measures supported in . Such measures can be naturally identified with measures in . Indeed, if is supported in then is the natural representative of in . Similarly, if then belongs to and is supported in . This gives a bijection between and . Hence, whenever convenient, we will identify the two spaces under the above construction.
We let be the -dimensional Hausdorff measure concentrated in , normalized so that for any measurable set . Then, we define for any domain and any (when we omit it from the notation). If a function belongs to we write as shorthand for the measure .
We will say that a sequence of measures converges to a measure in the narrow topology of measures in a domain if and only if
[TABLE]
for all functions continuous and bounded in . We recall that the convergence is in the weak- topology of if the above holds for all functions . Here is the space of continuous functions with compact support in .
It is standard that is a countably subadditive nonnegative set function (see for example [10]). This implies that any measure can be uniquely decomposed as
[TABLE]
where is absolutely continuous with respect to , and is singular with respect to (see [13], Lemma 2.1). That is, for every Borel set such that , while is supported in a Borel set such that . Moreover, by the Jordan decomposition theorem, one can write uniquely
[TABLE]
where and are the positive and negative part of .
In what follows we shall denote by the set of measures in that are absolutely continuous with respect to . Similarly, is the set of measures in which are supported in .
We remark that, whenever , the -dimensional Lebesgue measure is absolutely continuous with respect to (see [10]).
The following result is proved in [5].
Theorem 2.2.1**.**
Let be a bounded domain and . Then if and only if . Thus, if then in the sense of distributions for some functions and . Moreover, also holds when acting on functions in .
We note that in the above result one can further assume (see Lemma 3.6 of [4]).
2.3 Lizorkin-Triebel capacities
Now we consider the spaces mentioned earlier. The literature concerning these spaces is very extensive. Here we only record a few facts about them and refer the reader to [10] and [20] for details. Let us begin with their definition.
Let be any function in such that and in . For let
[TABLE]
so that and, setting ,
[TABLE]
in . Let be the set of tempered distributions, and for any let
[TABLE]
where is the Fourier transform. Then is an entire analytic function and it can be shown that
[TABLE]
in the topology of . For and we define
[TABLE]
and
[TABLE]
It is proven in [20] that this definition does not depend on the choice of , and that is a Banach space.
It can be shown that the spaces can be realized as potential spaces, and thus they can be used to define corresponding capacities, which we denote by (see [10] for the details).
The connection of these spaces with the Bessel potential spaces is given by the fact that for any , and , there holds in the sense of normed spaces. Given the above observation it is to be expected that the capacities are equivalent to the corresponding Bessel capacities. A surprising result (see Proposition 4.4.4 of [10]) is that in fact for all , , and , the capacity is equivalent to the corresponding Bessel capacity; we will point this out by writing
[TABLE]
An advantage of considering the more general spaces is the following theorem, which can be found in Chapter 4.4 of [20].
Theorem 2.3.1**.**
Let , and . Then the map
[TABLE]
is a bounded linear operator from onto . Moreover, there exists a linear bounded extension operator from into such that
[TABLE]
Thanks to the above theorem, we can define the trace of any function in .
Let us mention that we will also use Sobolev’s embedding-type results for these spaces in the sequel. We will point this out later.
The following proposition, which follows from Theorem 2.3.1, shows that the ‘trace’ of the capacity in is the capacity.
Proposition 2.3.2**.**
There exists a constant such that for all Borel sets and
- (1)
, and 2. (2)
.
Proof.
By the definition of capacity and the capacitability of Borel sets it is enough to consider and compact. Let be such that . By Theorem 2.3.1 has a trace such that
[TABLE]
Since we have , and since we conclude
[TABLE]
For the second assertion we consider the extension operator. Suppose and . Then its extension belongs to with
[TABLE]
Again, since we conclude
[TABLE]
∎
Thanks to the above result, we can describe the relationship between the decomposition of a measure in and its representative in .
Proposition 2.3.3**.**
Let and let
[TABLE]
be its decomposition with respect to . Let denote its identification as an element of . If
[TABLE]
is the decomposition of with respect to then
[TABLE]
In particular
[TABLE]
Proof.
We only prove the first assertion since the second follows easily. Let be such that and . By Proposition 2.3.2 we have and thus for any Borel set
[TABLE]
and
[TABLE]
Similarly, let be such that and . By Proposition 2.3.2 we have and so
[TABLE]
The previous inequality implies in particular that
[TABLE]
from which the proposition follows since then
[TABLE]
∎
2.4 Finer properties of functions
As we noted in the previous section, Theorem 2.3.1 guarantees the existence of a trace whenever belongs to . Since
[TABLE]
we see that every function has a trace in .
Since we want to integrate along the boundary of we study the regularity of these traces. The following proposition shows that functions in also have well defined traces and that, by selecting and adequate representative, we can assume they are quasi-continuous.
Proposition 2.4.1**.**
Let . Then has a quasi-continuous representative, defined in , which is unique up to sets of zero capacity. In particular, identifying with this representative, the trace of is quasi-continuous and unique in .
Proof.
Since is an extension domain we consider as an element in . Recalling that , we obtain the existence of a quasi-continuous representative which is unique in modulo sets of zero capacity (see Theorem 6.1.4 of [10]). In view of Proposition 2.3.2 the rest of the proposition follows easily. ∎
Remark 2.4.2
Thanks to the above proposition from now on we identify function in with their quasi-continuous representative in and refer to their quasi-continuous trace in whenever necessary. Note that this result also applies to functions in , or in by identifying elements in this space with their extension by zero.
Remark 2.4.3
For a function one can still define the boundary values of . Indeed, for any fixed we have and thus we can extend to a function in first by even reflection and then using that is an extension domain. The resulting extension has a quasi-continuous representative, which we call , coinciding with in . If we take then any quasi-continuous representative coincides with in and thus, by Theorem 6.1.4 of [10], in . Hence, from now on, we identify functions in with this locally defined, and unique, quasi-continuous representative in . In particular, if , we define the trace to be the value at of any representative such that . By the above considerations, and Proposition 2.3.2, the trace is quasi-continuous and unique in .
We shall make use of the following propositions regarding integrability and convergence with respect to measures in .
Proposition 2.4.4**.**
Let and let . Then is measurable with respect to . Furthermore, if the trace of belongs to then it belongs to .
Proof.
Since we have by Proposition 2.4.1 that has a quasi-continuous trace in , which is the restriction of any quasi-continuous representative of . Since every quasi-continuous function coincides with a Borel function it follows that is measurable with respect to any (Radon) measure . If moreover on then it holds on . That this is so follows from an application of Theorem 6.1.4 of [10] to the quasi-continuous functions and . Since is absolutely continuous with respect to we see that (see Proposition 2.3.3). ∎
One can similarly obtain the following proposition
Proposition 2.4.5**.**
Let and let . Then is measurable with respect to . Furthermore, if belongs to then it belongs to .
Remark 2.4.6
We will use the following fact: if in , where and are quasi-continuous functions, then in . This can be proven by applying Theorem 6.1.4 of [10] to the quasi-continuous function , which satisfies in .
Combining the last proposition with Lebesgue’s Dominated Convergence Theorem we obtain:
Proposition 2.4.7**.**
Let in with in and uniformly bounded in . Then for any measure , q.e. and
[TABLE]
The following result is Proposition 2.8 in [9]. It is a consequence of Egorov’s Theorem.
Proposition 2.4.8**.**
Let be a bounded open subset of . Let be a sequence in that converges to weakly in , and let be a sequence uniformly bounded in that converges to in . Then,
[TABLE]
2.5 superharmonic functions
Although not the focus of this work, we will use several results concerning superharmonic functions, especially on the relationship between them and renormalized solutions. We will give proper references whenever necessary, but most of the results are classic (see [14]). Here we record some definitions and basic properties.
Let be any domain. A superharmonic function is a lower semicontinuous function , not identically infinite, such that for all open sets and for all -harmonic in and continuous in we have that on implies in .
It is well-known that if is superharmonic then its truncation belongs to . This allows us to define its gradient in the same generalized sense as we will do for renormalized solutions (see Chapter 3), and in particular, it makes sense to define in the sense of distributions. In particular, when we say that a superharmonic function solves in for some (not necessarily bounded) Radon measure , we mean it precisely in the sense of distributions, where the derivative of is to be understood in the generalized sense. It is also known that if is superharmonic function in then is a nonnegative distribution, and so there exists a nonnegative Radon measure such that in .
Finally, we remark that when we say that a superharmonic function solves in , for some Radon measures and , we imply that so that the right hand side is actually a Radon measure.
Chapter 3 Renormalized solutions
3.1 Renormalized solutions in bounded domains
We start with the definition of renormalized solution given in [9] for bounded domains. In order to do this we first need to generalize the definition of .
Let be truncation by , i.e., . Then for any measurable and finite such that for every there exists a measurable vector-valued function such that
[TABLE]
in for all (see [2], Lemma 2.1). This function is unique and so we define as the gradient of and write . One similarly obtains that if for every then there exists a measurable vector-valued function such that
[TABLE]
in for all .
Remark 3.1.1
We note that, in general, is not the gradient of used in the definition of Sobolev spaces. In fact, may not even belong to (see [9] for details).
Definition 3.1.2**.**
Let be a bounded domain in . Let have a decomposition with respect to . Then a function is a renormalized solution of
[TABLE]
if
- (1)
is measurable, finite , and for all ; 2. (2)
for all ; 3. (3)
there holds
[TABLE]
for all satisfying the following condition: there exist , , and functions such that
[TABLE]
Remark 3.1.3
Note that the set of functions for which holds is not empty. Indeed, it contains since the condition is satisfied by any in choosing any and , and setting . But there are more admissible functions. In particular, is admissible with .
Remark 3.1.4
Theorem 2.33 of [9] shows that there are several equivalent definitions of renormalized solution. In particular, the last condition above can be replaced with the following one: for every there exists two nonnegative measures , supported in and respectively, such that , as , in the narrow topology of , and the truncations satisfy
[TABLE]
for every . Whenever convenient we use this equivalent formulation.
Remark 3.1.5
The conditions stated in definition 3.1.2 imply that any renormalized solution has a quasi-continuous representative which is in fact finite in (see remark 2.18 of [9]). We always identify renormalized solutions with this representative.
The following theorem is proved in [9] using Lemma 4.1 and 4.2 of [2].
Theorem 3.1.6**.**
Let be a renormalized solution of (3.1.1). Then
[TABLE]
If then for every ,
[TABLE]
[TABLE]
If then for every ,
[TABLE]
for every , and
[TABLE]
for every .
We note explicitly that the above constants do not depend on the domain . Note also that by putting in (3.1.2) we get
[TABLE]
The following result is proven in Section 5.1 of [9] as a first step in the proof of their stability result. It will be useful for us later when dealing with nonlinear terms.
Theorem 3.1.7**.**
Let be renormalized solutions to problem (3.1.1) with respective measures . Assume are uniformly bounded. Then there exists a function such that, up to a subsequence, in . Moreover, satisfies and of the definition of renormalized solution, as well as all the estimates stated in Theorem 3.1.6 (with instead of ), and
- (1)
* and in ,* 2. (2)
* strongly in for any ,* 3. (3)
* weakly in .*
Remark 3.1.8
It follows from Remark 2.11 of [9] that the function in the above theorem has a quasi-continuous representative which is in fact finite in . We identify with this representative.
3.2 Local renormalized solutions
A closely related concept is the one of local renormalized solutions (see [3], [25]) on domains which are not necessarily bounded. It is closer to our definition of renormalized solution of (1.0.1), and we will use it in the sequel. We remark that the derivative here is to be understood in the same generalized sense as described previously.
Definition 3.2.1**.**
Let be any domain in . Let have a decomposition with respect to . Then a function is a local renormalized solution of
[TABLE]
if
- (1)
is measurable, finite , and for all ; 2. (2)
for all ; 3. (3)
for all ( if ); 4. (4)
there holds
[TABLE]
for all compactly supported in satisfying the following condition: there exist , , and functions such that
[TABLE]
Remark 3.2.2
We remark that all functions in are admissible functions for . Note however that is no longer a valid test function. On the other hand, if then is admissible with .
Remark 3.2.3
Just as in the case of Definition 3.1.1, condition can be replaced by some other equivalent conditions (see Theorem 2.2 of [3]). We will use this fact in the proof of Lemma 4.2.1. On the other hand, our definition of local renormalized solution is not exactly the same as the definition in [3] since there the author does not require that is bounded. We have chosen to add this extra condition since we will need it when solving problem (1.0.1).
Remark 3.2.4
A fact that we will use frequently is that if is nonnegative and is a local renormalized solution of in , then coincides with a superharmonic function solving the same equation (see Theorem 4.3.2 of [25]).
Remark 3.2.5
Note that the estimates in Theorem 3.1.6 show that if is bounded then any renormalized solution of (3.1.1) is also a local renormalized solution of the corresponding equation. Indeed, we only need to show . To this end, we recall the known identity
[TABLE]
which holds for any measurable function , and any . From this identity one obtains the estimate
[TABLE]
In particular, if is a renormalized solution in a bounded domain , and , then combining the above estimate and (3.1.3) we have
[TABLE]
which is finite if . If then we use instead estimate (3.1.5) obtaining, for any fixed , the condition . Hence in this case any is allowed.
3.3 Renormalized solutions to the Neumann problem in the half-space
We now define a renormalized solution to (1.0.1). Recall that by the discussion of the previous chapter, any measure can be decomposed uniquely as
[TABLE]
where is absolutely continuous with respect to , and are singular with respect to and nonnegative.
Definition 3.3.1**.**
Let and . A function defined in is a renormalized solution to (1.0.1) provided the following holds:
- (1)
is measurable, finite , and for all ; 2. (2)
for all ; 3. (3)
for all ( if ); 4. (4)
is finite in , and ; 5. (5)
there holds
[TABLE]
- for all compactly supported in , with trace in , and satisfying the following condition: there exist , , and functions such that
[TABLE]
Remark 3.3.2
We remark that it makes sense to talk about the boundary values of a renormalized solution since, in fact, any finite and measurable function defined in such that for all has a locally defined quasi-continuous representative in which, however, could be infinite on a set of positive capacity. Indeed, by Remark 2.4.3 we can locally identify with a quasi-continuous representative in . Then, it can be directly verified that defines (locally) a quasi-continuous function that coincides with in and which is unique in . Notice that, in general, may be infinite on a set of positive capacity and so its trace could be infinite. We remark that similar considerations hold for finite and measurable functions defined in such that . From now on, we always identify renormalized solutions to (1.0.1) with their quasi-continuous representative in . In particular, under this identification, the trace of is quasi-continuous and unique in . Since could be infinite on a set of positive capacity, we explicitly ask that the trace must be finite in . We will show below that in fact renormalized solutions are always finite in .
Remark 3.3.3
If we consider quasi-continuous representatives in , then the condition in implies that in . To see this, apply Theorem 6.1.4 of [10] to extend from in to in (see also Remark 2.4.6). It follows that in , and in particular in . Similarly, in .
We verify that under the given assumptions all the integrals above are well defined and finite. The first integral on the left hand side can be divided into three integrals with domains of integration given by , , and . In the first case so and the integral is finite since has compact support. For the second case and implies so by assumption and the integral is also finite since we integrate over the support of . The third case can be treated similarly. The second integral on the left hand side is obviously finite since while .
As for the right hand side, observe first that since we have with the supremum norm. Since are bounded we conclude that the integrals with respect to the singular measures are well defined and finite. For the remaining integral Proposition 2.4.1 guarantees that has a well defined trace, while Proposition 2.4.4 and the boundedness of gives .
Remark 3.3.4
It follows directly from the definitions that if is a renormalized solution of (1.0.1) then , the extension of by even reflection across , is a local renormalized solution of in (where has the meaning indicated in Chapter 2).
Remark 3.3.5
We have noted in Remark 3.1.1 that is not, in general, the gradient of in the usual sense used in the definition of Sobolev spaces. However, it can be shown that if for some then and is the usual gradient of (see Remark 2.10 of [9]). In particular, when the definition of renormalized solution implies that and the gradient of coincides with the usual definition.
In the definition of renormalized solution we assumed is finite in . In the case this assumption could have been dropped. Moreover, the condition could also be removed by assuming is a function defined on the extended real line. However, we now show that whenever then must be finite in . Indeed, by our definition of trace, and in view of Proposition 2.3.2 and remark 3.3.4, it will be enough to show that local renormalized solutions of in are finite in . We will obtain this as a consequence of the following local version of the estimates on level sets stated in Theorem 3.1.6.
Theorem 3.3.6**.**
Let be a local renormalized solution of in , and let be such that . Then
[TABLE]
and there exists such that: if then for every ,
[TABLE]
[TABLE]
if then for every ,
[TABLE]
for every , and
[TABLE]
for every .
Proof.
Choose such that , in , and for some . Then, testing against we obtain
[TABLE]
and so
[TABLE]
which is estimate (3.3.1).
Next, we observe that since for some Chebyshev’s inequality gives
[TABLE]
Hence, we can choose such that
[TABLE]
for all . Define : the average of in . Then we estimate
[TABLE]
for all . Then, if , by Poincaré-Wirtinger’s inequality, Sobolev inequality, and (3.3.1), we obtain
[TABLE]
where . Since for all we have the inclusions
[TABLE]
we deduce
[TABLE]
which is estimate (3.3.2). In the case , the same procedure gives (3.3.4). The remaining estimates follow from the above ones just as in the proof of Theorem 3.1.6 in [9], using the results in [2]. ∎
Note that unlike the estimates in Theorem 3.1.6 the above estimates are not uniform on . However, they are enough for our purposes.
Proposition 3.3.7**.**
Let be a local renormalized solution of in . Then is finite in . In particular, if is a renormalized solution of (1.0.1) in the sense of definition 3.3.1 then the trace of , as defined in Remark 3.3.2, is finite in .
Proof.
As observed before, it is enough to show that is finite in . Fix . By the previous theorem, with and , we can find such that for all
[TABLE]
Then, we can proceed as in the proof of the previous theorem to obtain that
[TABLE]
satisfies
[TABLE]
for any . Now consider the function . We have and by combining Poincaré-Wirtinger’s inequality, estimate (3.3.1), and the above estimate we conclude
[TABLE]
for any . Further, we have on the set . Hence, by definition of we obtain
[TABLE]
for any . Since we conclude that . In a similar way we can control the set where . Since is arbitrary, this concludes the proof. ∎
Note that to obtain the estimates of Theorem 3.3.6 for a local renormalized solution in , it would have been enough to have instead of condition of Definition 3.2.1. Similarly, instead of condition we only used for some as a step in obtaining the level set estimate . As an interesting consequence of this, we have that conditions and in Definition 3.2.1 could be weakened. We remark that this result has already been shown in Theorem 3.1 of [3], although by a different method and with the stronger condition for some .
Corollary 3.3.8**.**
Let be any domain, , and let satisfy conditions and of Definition 3.2.1. If also satisfies
- (2’)
, 2. (3’)
for any there exists and such that
[TABLE]
then is a local renormalized solution of in .
Proof.
Since we have the estimates of Theorem 3.3.6, we can show and of Definition 3.2.1 following the ideas in Remark 3.2.5. Indeed, thanks to (3.2.1), we can write
[TABLE]
which is finite when and ( if ). Hence, we have . Similarly, the estimates on show that holds. ∎
We now show that renormalized solutions of (1.0.1) in fact exists.
Proposition 3.3.9**.**
Let , and let
[TABLE]
where is the surface area of . Then is a renormalized solution to
[TABLE]
Proof.
Let us first observe that is positive and singular with respect to since . This can be proven, for example, by using the known relationships between capacity and Hausdorff measure (see [10]).
We assume since the case is almost identical. We note that is finite , measurable, and clearly satisfies and so the first requirement holds. For the second one observe that and so . If then and so the singularity is integrable at the origin and . The third requirement is immediate.
Suppose now that has compact support in and trace in . Let and suppose in the set with and . Note that since we have that is continuous in . As in the considerations following definition 3.3.1, we see that belongs to . Hence, we can apply Lebesgue’s Dominated Convergence Theorem to obtain
[TABLE]
Since is smooth for every , vanishes as , and in we obtain
[TABLE]
Finally, it is well-known (cf. [12]) that this last integral satisfies
[TABLE]
since has bounded trace and is continuous in a neighborhood of the origin because near the origin (see Remark 3.3.3). ∎
Remark 3.3.10
The ideas above can be used to define renormalized solutions to Neumann problems in bounded domains. We do so now.
Let be a bounded extension domain, i.e., a domain such that there exists a linear bounded extension operator from into . Assume and is supported in . Let be the decomposition of with respect to . Then, a renormalized solution of
[TABLE]
is a function defined in such that
- (1)
is measurable, finite , and for all ; 2. (2)
for all ; 3. (3)
there holds
[TABLE]
- for all with trace in , and satisfying the following condition: there exist , , and functions such that
[TABLE]
Note that under the above conditions test functions have well defined traces on . Indeed, by using that is an extension domain, we can proceed as in Proposition 2.4.1 to show that has a quasi-continuous representative which is unique . Hence, we let the trace of be the restriction to of this quasi-continuous representative. Similarly, can be extended, uniquely, as continuous and bounded functions in .
It can be shown, just as in the case of definition 3.3.1, that all the integrals above are well defined and finite. Note that we have assumed that the trace of belongs to . This has to be contrasted with definition 3.3.1 where, thanks to Proposition 2.4.4, we only assumed that the trace is in .
Chapter 4 Local renormalized Solutions in
We now prove some preliminary results that will help us to obtain a renormalized solution to (1.0.1) in the sense of definition 3.3.1. We will mostly use ideas developed in [9] for the case . Note however that the theory developed there only applies to bounded domains and so it cannot be applied directly to our case. We circumvent this problem by working locally, that is, we first obtain a sequence of solutions on balls of increasing radii and then we consider the behavior of these solutions on any fixed ball .
As a corollary, we will prove the following theorem on the existence of local renormalized solutions in .
Theorem 4.0.1**.**
Let and . Then there exists a local renormalized solution to
[TABLE]
4.1 Preliminary convergence result
Consider the following restrictions of a measure
[TABLE]
where is the ball centered at the origin of radius . It is easy to see that
[TABLE]
For each we can use the results in [9] to obtain a renormalized solution to the problem
[TABLE]
Here and in the sequel we identify the functions as functions defined on the whole space extending them by zero outside of . Note that since the extension satisfies . Hence, by Remarks 3.3.2 and 3.1.5, the extension of has a quasi-continuous representative in . Clearly, up to a set of zero capacity, this representative is the extension by zero of the quasi-continuous representative of given by Remark 3.1.5.
In the following lemma we show that we can extract a point-wise convergent subsequence from . The argument follows closely the ideas used in Section 5 of [9].
Lemma 4.1.1**.**
Let . Let be a sequence of measures such that for all . Let be renormalized solutions to (4.1.1) with data , i.e.,
[TABLE]
Then there exists a function such that, up to a subsequence, in . Moreover :
- (1)
* is measurable and finite , weakly in for any fixed and , and in for any ;* 2. (2)
* and strongly in for any and ;* 3. (3)
* for all ( if ).*
Proof.
To begin we note that each satisfies the estimates stated in Theorem 3.1.6 uniformly in the sense that they hold with replaced by . Now fix any , , and . Observe that is contained in
[TABLE]
Thanks to (3.1.3) and (3.1.5) the measure of the first two sets is arbitrarily small, independent of and , provided is large enough.
Since for each fixed estimate (3.1.2) gives an uniform bound for we conclude that the sequence is uniformly bounded in for any fixed and . Since the injection is compact, this means that has a subsequence that converges strongly in , and hence, that it is a Cauchy subsequence in measure in .
Now take and apply the above argument in to obtain a subsequence such that is a Cauchy sequence in measure in . Since has the same properties as , we fix and apply again the argument above to obtain a subsequence such that is a Cauchy sequence in measure in . Proceeding inductively, we see that we can define a diagonal sequence . Going back to (4.1.2), it easy to see that this sequence, which we relabel as , is a Cauchy sequence in measure. Hence, passing to a subsequence, there exists a measurable and finite function such that in . Proceeding in a similar way, but now with respect to , we can obtain a subsequence , such that for every in . Relabeling this subsequence as , we see that there exists a measurable and finite function such that
[TABLE]
satisfying in .
We now consider the properties of the limit function. Note that since is continuous we have in . Estimate (3.1.2) implies that is uniformly bounded in for any fixed . Thus, for any subsequence a further subsequence converges weakly in to a limit function . But in , which implies (by the boundedness of the sequence) that . Therefore
[TABLE]
In particular
[TABLE]
and thus for any
[TABLE]
Let us make explicit that this allows us to define in the generalized sense described earlier. Also, using (3.1.2) and Fatou’s Lemma we further conclude that
[TABLE]
Now we want to show that for any fixed and , is a Cauchy sequence in measure in . For this we follow the approach in the proof of Theorem 4.3.8 in [25]. Fix any , , and , and let . Choose any such that in and . For we define
[TABLE]
and observe that
[TABLE]
Let and test against in the equations solved by the truncates and (see Remark 3.1.4) to find that
[TABLE]
for some measures and converging in the narrow topology of measures to and , respectively, as . By testing against in the equation solved by , and using estimate (3.1.2), we obtain that are bounded independently of . Hence, the right hand side in the above inequality is bounded by where is independent of and . On the other hand,
[TABLE]
where, again by (3.1.2), is independent of . Then, using the structural inequality (5.1.3), we can proceed as in the proof of Theorem 5.1.1 to show that
[TABLE]
where is independent of and . Hence, by combining all the above estimates we see that
[TABLE]
and so we can choose independent of and such that . Since is a Cauchy sequence in measure in , once is fixed we obtain that if and are large enough. Hence, the desired result follows. Note that we also obtain that there exists a subsequence such that in . Since is uniformly bounded in we conclude that in fact .
Now, noticing that is contained in
[TABLE]
we proceed as before to obtain that, passing to a subsequence, converges to a function in . Note that for fixed we can choose a subsequence to obtain
[TABLE]
in . Therefore
[TABLE]
It then follows that in fact, for any , in . Moreover, the identity (3.2.1) and the uniform decay estimates of Theorem 3.1.6 imply that the family is uniformly integrable over (see also Step 1 of Section 5 of [9]). Hence, by Vitali’s Theorem it follows that
[TABLE]
In particular
[TABLE]
In the same spirit one can show that
[TABLE]
when , whereas
[TABLE]
when (see Remark 3.2.5).
To finish the proof we show that is finite in for all , and thus in the whole . Fix . By estimate (3.1.3) and (3.1.5) we can choose such that for all and for all
[TABLE]
Thus, we can estimate
[TABLE]
for any . Let us define the following averages:
[TABLE]
Note that by Lebesgue’s Dominated Convergence Theorem we have
[TABLE]
and by the above estimate we get
[TABLE]
for any . Now, to finish, we can proceed as in the proof of Proposition 3.3.7, by considering the function . ∎
4.2 Stability
We now consider the problem of showing that the limit function defined in the previous lemma is a local renormalized solution of the desired equation. Since we will deal with nonlinear terms later, it will be useful to prove a more general result. Let us recall that if then, by Proposition 2.3.2, (see also Proposition 2.3.3). We also remark that if a function satisfies in Lemma 4.1.1 then has a quasi-continuous representative, which we identify with (see Remark 3.3.2).
Lemma 4.2.1**.**
Let and assume and are measurable functions defined in such that for some positive constant . Let be renormalized solutions to
[TABLE]
where is the restriction of to . Assume in , where is a function satisfying properties (1), (2), and (3) in Lemma 4.1.1. Suppose also that
[TABLE]
for any and any sequence converging to both in and weakly in and such that is uniformly bounded in . Then is a local renormalized solution of
[TABLE]
Moreover, strongly in for any fixed and .
Proof.
Since properties , , and of Lemma 4.1.1 hold, we have that solves the desired equation if we can prove the last property listed in Definition 3.2.1. We show this first, following the approach of [17].
First we note that by Theorem 2.2.1 we have in for some and . Note that this representation is also valid in for any and so . Then, by Lemma 3.1 of [17] there exists a set with of zero measure such that each satisfies the following condition: for every there exists two measures , supported in and respectively, such that up to a subsequence (possibly depending on ) , as goes to infinity, in the weak- topology of , and the truncations satisfy
[TABLE]
for every .
Let us consider the convergence, in , of the above terms. Given let and write . Since , is countable and thus of zero measure. Note that in except possibly in , thus in and weakly- in for all .
By hypothesis, we have that strongly in for any . It follows that
[TABLE]
for any and . Similarly, for any such and there holds
[TABLE]
Note that since are uniformly bounded in so are the functions . Then, up to a subsequence depending on , there exist a measure such that
[TABLE]
for any .
Now we turn our attention to the measures . Just as in the proof of Theorem 4.1 in [17] we can use the fact that and and are uniformly bounded as measures to conclude that for every
[TABLE]
for any in some subset with , and where is independent of or . Hence, for each , there exists nonnegative measures and defined in such that, up to a subsequence,
[TABLE]
In particular, given we can pass to a subsequence to conclude
[TABLE]
which implies, by the previous considerations, that for any and
[TABLE]
Note that while and thus, by Theorem 2.2.1, belongs to and
[TABLE]
for any and .
Since is quasi-continuous is quasi-open, and thus there exists a sequence of functions such that and in (see Chapter 2). For any we can put as test function in (4.2.3) and conclude
[TABLE]
for any . Since we can pass to the limit using Proposition 2.4.7 to conclude that for any
[TABLE]
As above, let now denote a sequence in such that and in . Let and put as test function in (4.2.3) with both and in to conclude
[TABLE]
and by passing to the limit
[TABLE]
which implies
[TABLE]
for any in . As in the proof of Theorem 4.1 in [17], this allows us to define a measure with support in such that
[TABLE]
for any in . Hence, if we define
[TABLE]
we can rewrite (4.2.3) as
[TABLE]
for any and .
Let us now consider the measures , , and . For any let be defined by
[TABLE]
and choose , . Plugging as test function in (4.2.3) and passing to the limit as we conclude
[TABLE]
Following the argument in the proof of Theorem 4.1 of [17] we see that there exists a sequence of positive numbers going to infinity such that weakly- in as , for some nonnegative measure . Choosing now
[TABLE]
we obtain
[TABLE]
and similarly conclude that, up to a sequence , weakly- in for some nonnegative measure .
Next, let us note that by the very definition of we have
[TABLE]
for any , , and thus taking limit
[TABLE]
(Note that we have used the assumptions on with ). On the other hand, for any such we can take a sequence , , in (4.2.4) to conclude
[TABLE]
where we have used that in the sense of distributions. Thus we get
[TABLE]
which implies in .
Consider now the function defined by
[TABLE]
For any nonnegative we have and so by (4.2.4) we have
[TABLE]
for . Using Lebesgue’s Dominated Convergence Theorem, the fact that , , the smoothness of , the fact that is finite , and that for all we may take , for some sequence of , to conclude
[TABLE]
where we have used again Theorem 2.2.1 to identify for functions in . Since weakly- in both and , thanks to Lebesgue’s Dominated Convergence Theorem and Proposition 2.4.7, we can take and conclude
[TABLE]
On the other hand, if we go back to the definition of and put as test function with , , for , we obtain
[TABLE]
Note that since is continuous we have in , and so we can pass to the limit in the second term above as . For the third term we use that belongs to and Theorem 2.2.1 to write
[TABLE]
Then, by Lebesgue’s Dominated Convergence Theorem, and combining the fact that weakly in with Proposition 2.4.8, we see that we may also take limit as above for almost every . Similarly, by the continuity of and Proposition 2.4.8, weakly in for almost every . Hence, since is uniformly bounded in , we can use condition (4.2.1) to obtain
[TABLE]
as for almost every .
Thus, since we can take in the second, third, and fourth term in (4.2.7), we can use Fatou’s Lemma to conclude
[TABLE]
for almost every . Passing to the limit as as before yields
[TABLE]
and so comparing with (4.2.6) we obtain
[TABLE]
which implies in . Similarly, one can conclude . This implies in particular that and are singular with respect to , and since we conclude that . Recalling that and have disjoint support we further conclude and in . In particular this allows us to rewrite (4.2.4) as
[TABLE]
for any and .
We are now ready to finish. Let with compactly supported, and let , for some , be compactly supported and such that . We write . Choosing large enough we can assume so that is a valid test function for (4.2.8) and thus
[TABLE]
where we have chosen to be the sequence such that weakly- as . Let be such that is constant in . Then, if ,
[TABLE]
Since we have that . Hence, and since is finite we take in the last two terms above and obtain
[TABLE]
We know that is finite in and so in . It follows that
[TABLE]
as . Recall that are concentrated in , respectively. Thus, assuming , we use that to conclude
[TABLE]
as . Putting together all the above we get
[TABLE]
Hence, by the results in [3], is a local renormalized solution of in .
Now we show the strong convergence of the truncates. Fix , , and let . By testing against in the definition of as renormalized solution, for any we have
[TABLE]
Similarly,
[TABLE]
Comparing the above identities we have
[TABLE]
Writing again we use that and that weakly in and weakly- in to obtain
[TABLE]
as . Note that by condition (4.2.1)
[TABLE]
as . Moreover, since strongly in for some , while strongly in for any , we get
[TABLE]
as . Hence,
[TABLE]
for any , which implies that
[TABLE]
for any . Using the above, the inequality with and , and the fact that in , we obtain that strongly in . Then, by Vitalli’s Theorem, strongly in , from which the claim follows. ∎
Proving Theorem 4.0.1 is now trivial:
Proof of Theorem 4.0.1..
Let be the restriction of to . Since we can apply Lemma 4.1.1 and Lemma 4.2.1 with . ∎
Chapter 5 Symmetric Solutions
5.1 Symmetry
In this section we show that any solution of the extended problem given by Theorem 4.0.1 must be symmetrical with respect to whenever the measure is supported in . This symmetry will allows us to recover a solution to the original problem, i.e., equation (1.0.1).
Theorem 5.1.1**.**
Let be any bounded domain in that is symmetric with respect to the hyperplane . Let be supported in and let be a renormalized solution to
[TABLE]
Then in .
Proof.
In what follows we write and for any defined in we denote by its reflection with respect to , i.e., .
Let us first show that is also a renormalized solution of the above problem. Indeed, this is clear when we observe that if is a test function with respect to then is a valid test function with respect to . Hence we conclude
[TABLE]
as required, since on and is invariant under .
To continue, let us note that for any . Indeed, since we can choose a sequence such that in . Then in and since vanishes in we conclude and thus our claim follows.
By the equivalence of definitions of renormalized solutions (see Remark 3.1.4), we have that for every there exists two nonnegative measures , supported in and respectively, such that as in the narrow topology of measures, and the truncations satisfy
[TABLE]
for every . In particular
[TABLE]
as since is supported in .
We now extend by [math] outside . Since is a valid test function for (5.1.1) which vanishes in we get
[TABLE]
Arguing in the same way for we obtain sequences converging to such that (5.1.1) holds with in place of , and so testing against and subtracting it from the previous equality we get
[TABLE]
Using the well-known inequality
[TABLE]
for some , it follows immediately from (5.1.2) that
[TABLE]
when . When we use Holder’s inequality first to get
[TABLE]
which then by (5.1.3), (5.1.2), and (3.1.2) yields
[TABLE]
Thus we see that for any there holds
[TABLE]
as . By symmetry, the same is true in . Hence we can apply the partial uniqueness result stated in Theorem of [9] to conclude that in . ∎
5.2 Existence from symmetry
Now we are ready to prove an existence result for problem (1.0.1) in the case . We will state it as a corollary to the following theorem.
Theorem 5.2.1**.**
Let and . Suppose is a local renormalized solution of in that is symmetric with respect to the hyperplane . Then the restriction of to is a renormalized solution of
[TABLE]
Proof.
It is clear from the definition of local renormalized solution that the restriction of to satisfies conditions , , and of Definition 3.3.1. Hence, we only need to show that holds.
Assume that has compact support in and trace in and there exist , , and functions such that
[TABLE]
Choose such that in and in . Let us extend and to by even reflection, i.e., for and similarly for . Note that since is symmetric with respect to we have
[TABLE]
Next, we let
[TABLE]
and
[TABLE]
Then for any we see that is an adequate test function and thus we get
[TABLE]
By now taking as test function we get
[TABLE]
By the symmetry of we have that and so
[TABLE]
Adding up the previous equalities we conclude
[TABLE]
and by Lebesgue’s Dominated Convergence Theorem we let to obtain
[TABLE]
Writing
[TABLE]
we use the fact that weakly in to take above, and so conclude
[TABLE]
thus completing the proof of the theorem. ∎
Theorem 5.2.2**.**
Let and . Then there exists a renormalized solution to
[TABLE]
Proof.
Apply Theorem 4.0.1 to obtain a local renormalized solution to in . By the construction of , and in view of Theorem 5.1.1, is symmetric with respect to . Then the result follows from an application of the previous theorem. ∎
Chapter 6 Nonlinear problems with absorption
6.1 The subcritical case
We now consider the problem of finding renormalized solutions to problem (1.0.1) with a nonlinear term . The fact that is subcritical is expressed in the following assumption.
Assumption 6.1.1
- (1)
is a continuous function such that . 2. (2)
Define by . If we assume
[TABLE]
If we assume that there exists such that
[TABLE]
Remark 6.1.2
In the special case when , , Assumption 6.1.1 holds whenever
[TABLE]
Hence, we say that is a critical exponent for problem (1.0.1), and the problem is subcritical whenever .
We will use the tools developed in Chapters 4 and 5 to obtain a renormalized solution of (1.0.1) as the limit of renormalized solutions to
[TABLE]
To find solutions of the above problem we use the theory developed in [25] for the equation
[TABLE]
in bounded domains. In order to pass from (6.1.2) to (6.1.1) we apply the theory for problem (6.1.2) to a sequence obtained by multiplying by an adequately chosen sequence , and then show that the associated sequence of solutions converges to a solution of problem (6.1.1).
We define as
[TABLE]
Note that . Then, for we define
[TABLE]
We start by defining renormalized solutions to problems (6.1.1) (in a general bounded domain ) and (6.1.2).
Definition 6.1.3**.**
Let be a bounded domain, , and . Then a function defined in is a renormalized solution to problem (6.1.1) if is finite in , and is a renormalized solution to problem (3.1.1) with datum in the sense of Definition 3.1.2.
Similarly, if then a function defined in is a renormalized solution to problem (6.1.2) if and is a renormalized solution to problem (3.1.1) with datum in the sense of Definition 3.1.2.
The following result is obtained in the proof of Theorem 5.1.2 in [25] by testing against , , and taking :
Proposition 6.1.4**.**
Let be a renormalized solution to problem (6.1.2), where is continuous and satisfies for all and . Then
[TABLE]
The next lemma collects some relationships between capacities and Lebesgue measure.
Lemma 6.1.5**.**
Let . There exists constants , , , and such that for all Borel sets there holds
- (1)
, 2. (2)
, 3. (3)
, 4. (4)
.
Proof.
The first two inequalities follow from (the proof of) Proposition 2.6.1 of [10], while the third is just Proposition 2.3.2. The last one follows from , , and the translation invariance of both the Lebesgue measure and capacities. ∎
Now we obtain estimates similar to (3.1.3) and (3.1.5) but on hyperplanes. We note explicitly that any quasi-continuous function on has a well defined quasi-continuous trace in any hyperplane , (see the above lemma and Remark 2.4.2).
Lemma 6.1.6**.**
Let be quasi-continuous in and such that satisfies
[TABLE]
If then there exists a constant such that for any
[TABLE]
If then there exists constants and such that for any
[TABLE]
Proof.
Suppose . By Sobolev’s embedding (see [21]), trace inequality, and Poincare’s inequality, we have for that
[TABLE]
Since we conclude
[TABLE]
which finishes the proof for the case . When , the results in [6] show that
[TABLE]
for some constants and . Since whenever and we conclude
[TABLE]
which gives the desired bound. ∎
Remark 6.1.7
Let us note that, in exactly the same way, one can prove that for any such function there holds
[TABLE]
when . The fact that does not depend on will be important to us when proving Theorem 6.1.12.
Next we prove a lemma that will allow us to obtain solutions to (6.1.1) from solutions to (6.1.2) under very general conditions.
Lemma 6.1.8**.**
Fix . Suppose satisfies part of Assumption 6.1.1, let be defined as in part of Assumption 6.1.1, and let be defined by (6.1.3). Let in , where are quasi-continuous in . Assume also that weakly in for any . Define
[TABLE]
and
[TABLE]
If and as , uniformly in and , then
[TABLE]
whenever is a bounded subset of such that both in and weakly in . Here is identified with its quasi-continuous representative in .
Proof.
We first note that . Now, for any and we write and . We note that
[TABLE]
and since we estimate
[TABLE]
where we have used that in . For all we can estimate
[TABLE]
and since uniformly we conclude
[TABLE]
as uniformly in . In a similar way we can write and estimate
[TABLE]
as . Thus, collecting the above estimates we have
[TABLE]
for some functions and such that and as uniformly in . Note that we have used that are uniformly bounded.
Fix now any and let be such that . Then
[TABLE]
and
[TABLE]
On the other hand, since has bounded derivative in we see that and belong to . It is easy to show, by using density of in , that
[TABLE]
for any pair of functions and . We also observe that
[TABLE]
and let
[TABLE]
Then, using that is smooth, we can write
[TABLE]
where
[TABLE]
and
[TABLE]
Note that and strongly in for any since , , , and are uniformly bounded in . Similarly strongly in . Thus, since and weakly in we conclude
[TABLE]
as for any fixed . Recall that in . Since , , , and are uniformly bounded in , we conclude as above that strongly in . Since weakly in we conclude
[TABLE]
as for any fixed . Collecting the above we can rewrite (6.1.4) as
[TABLE]
for any , where is a function such that as for any and fixed.
To continue we observe that since both and are quasi-continuous in , given we can find a closed set such that and . Then, and are uniformly continuous and bounded in , and we can find small enough so that
[TABLE]
for any . We can also assume is such that
[TABLE]
for all . Note that as for any . Then, we write
[TABLE]
and estimate
[TABLE]
and
[TABLE]
In view of Lemma 6.1.5 we also have
[TABLE]
Note that we have used that (see Proposition 2.4.5). Considering the above estimates we obtain from (6.1.5) that
[TABLE]
for any , where is a function such that as for any fixed and . Thus, taking large enough and then choosing small enough, we see that for any
[TABLE]
for all large enough. Hence, the result follows. ∎
When in , renormalized solutions to converge to a solution of by the stability result of [9] or [17]. Since in our case the convergence is not quite in we cannot simply use the same result. To pass to the limit, we use the following stability result.
Lemma 6.1.9**.**
Fix . Let be renormalized solutions of
[TABLE]
where , is defined by (6.1.3), and satisfies Assumption 6.1.1. Suppose , , and in where satisfies condition and of Definition 3.1.2 and is finite. Assume also that
[TABLE]
[TABLE]
and
[TABLE]
whenever is a bounded subset of such that both in and weakly in . If then is a renormalized solution of
[TABLE]
Moreover, strongly in for any .
Proof.
Note that since properties and of Definition 3.1.2 hold, to prove that is a renormalized solution of the above equation it is enough to show that also holds. Since we essentially repeat, with a few modifications and simplifications, the argument used to pass to the limit in the proof of Theorem 4.1 in [17] we only point out the main ideas (see also the proof of Lemma 4.2.1).
Before we begin, note that by choosing we have
[TABLE]
for all .
Now, by Theorem 2.2.1 in for some and . Using Lemma 3.1 of [17] we obtain a set with such that each satisfies the following: for every there exists two measures , supported in and respectively, such that up to a subsequence (possibly depending on ) , as goes to infinity, in the weak- topology of , and the truncations satisfy
[TABLE]
for every .
We consider the convergence of the above terms as . Let
[TABLE]
and write . Since , is countable and thus of null measure. Note that in except possibly in , thus in and weakly- in for all . Then, as in Lemma 4.2.1, we can show that
[TABLE]
and
[TABLE]
for any and .
By Proposition 6.1.4 we see that for each
[TABLE]
Hence, for each there exists a measure such that, up to a subsequence possibly depending on ,
[TABLE]
for any . Similarly, following the argument in the proof of Theorem 4.1 in [17], we can conclude that for every
[TABLE]
for any in some subset with . It follows that for each there exists nonnegative measures and such that, up to a subsequence,
[TABLE]
In particular, given we can pass to a subsequence to conclude
[TABLE]
Then, collecting all the above, we get that for any and
[TABLE]
From the above we see that belongs to and so
[TABLE]
for any and .
Since is finite, it follows that is quasi-open, and we can find a sequence such that and in . For any we can put as test function in (6.1.9) and conclude
[TABLE]
for any . Taking we conclude that for any
[TABLE]
Letting now be a sequence in such that and , we put as test function in (6.1.9) with both and in and take to conclude, as in the proof of Theorem 4.1 in [17], that there exists a measure such that
[TABLE]
for any in . Hence, defining
[TABLE]
we can rewrite (6.1.9) as
[TABLE]
for any and .
Proceeding as in the proof of Lemma 4.2.1, we can use (6.1.7) to show that , and that, up to a sequence going to infinity, weakly- in . In particular, we can rewrite (6.1.10) as
[TABLE]
for any and . At this point, the fact that is a renormalized solution of the desired equation follows exactly as in the proof of Theorem 4.1 of [17].
To finish the proof of our lemma, we observe that on one hand we have
[TABLE]
while on the other
[TABLE]
Comparing the above identities we have
[TABLE]
Writing again for some and , we use that weakly in and weakly- in to obtain
[TABLE]
as . Similarly, by (6.1.7)
[TABLE]
as , and so
[TABLE]
as . As in the proof of Lemma 4.2.1, we conclude from the above that strongly in , and then, by Vitalli’s Theorem, that strongly in . Hence the claim follows. ∎
The following lemma, similar to Lemma 6.1.8, gives a useful sufficient condition under which (4.2.1) holds. It will be used to obtain stability of local solutions throughout the sequel.
Lemma 6.1.10**.**
Let and be quasi-continuous functions such that in and weakly in for any fixed and . Suppose satisfies part of Assumption 6.1.1 and let be defined as in part of Assumption 6.1.1. For any fixed we define
[TABLE]
and
[TABLE]
If and as , uniformly in , then
[TABLE]
for any sequence converging to both in and weakly in and such that is uniformly bounded in .
Proof.
We follow very closely the ideas in the proof of Lemma 6.1.8 and so we omit some details.
As in Lemma 6.1.8, we use the assumptions on and to obtain that
[TABLE]
for some such that as uniformly on , and where . For any we let be the functions defined in (6.1.3). Hence,
[TABLE]
To continue we observe that since , , and are quasi-continuous in , given we can find a closed set such that all of them belong to and . Then, all of them are uniformly continuous in , and since they are also uniformly bounded, for any fixed and we can find small enough so that
[TABLE]
and
[TABLE]
for any . We also assume is such that
[TABLE]
for all . Then, by decomposing as
[TABLE]
we see that
[TABLE]
for any , where is a function such that as for any fixed , and . Since all the functions involved are uniformly bounded, we may approximate with a such that , and upon integrating by parts, obtain
[TABLE]
Let us consider the first integral in the right hand side of the above identity. Recall that strongly in for any . Since is uniformly bounded in and is uniformly bounded in we obtain that
[TABLE]
as uniformly in . On the other hand, as in Lemma 6.1.8,
[TABLE]
as . A similar reasoning applies to the second integral. Hence, we may write
[TABLE]
for some functions and such that as , uniformly on , and as , for any fixed and . Thus, collecting all the above estimates, we conclude that
[TABLE]
Hence, we obtain
[TABLE]
as desired. ∎
We are now ready to prove the existence of renormalized solutions to (1.0.1) in the subcritical case. We treat the cases and separately for clarity of exposition.
Theorem 6.1.11**.**
Let and . Suppose satisfies Assumption 6.1.1. Then there exists a renormalized solution of
[TABLE]
Proof.
Let be defined by (6.1.3) and fix . By Theorem 5.1.2 of [25] for any there exists a renormalized solution of
[TABLE]
where is the restriction of to . By Proposition 6.1.4 we have
[TABLE]
By writing
[TABLE]
we see that is a renormalized solution to in . Since
[TABLE]
we can apply Theorem 3.1.7 to obtain that, passing to subsequences, in as for suitable behaved functions . Note that each , and also , have quasi-continuous representatives that are finite in (see Remark 3.1.5 and 3.1.8) which implies that they have well defined quasi-continuous traces. By the same theorem, since each satisfies the estimate
[TABLE]
so does the functions .
Now we consider the convergence of for fixed . We fix and for any and we write and . Define . Proceeding as in Remark 3.2.5 we see that
[TABLE]
By Lemma 6.1.6
[TABLE]
while integration by parts gives
[TABLE]
Note that by Assumption 6.1.1
[TABLE]
and so we obtain
[TABLE]
as , uniformly in and . Using the same argument we can show
[TABLE]
as . Note also that
[TABLE]
so in particular .
By the above considerations, we see that we can combine Lemma 6.1.8 and Lemma 6.1.9 to obtain that is a renormalized solution of
[TABLE]
Moreover, since we have (6.1.12) and
[TABLE]
for any we get
[TABLE]
Thus, we can apply Lemma 4.1.1 with data to obtain a suitable limit function such that in . Note that the above estimate says that is uniformly bounded.
Now we obtain estimates on the level sets of and . Fix any . Since satisfies estimate (3.1.3) and is uniformly bounded, we can find independent of such that
[TABLE]
for all . Let be the average of in . Then we estimate
[TABLE]
for all . As in the proof of Lemma 6.1.6, replacing Poincaré’s inequality with Poincaré-Wirtinger’s inequality, we obtain
[TABLE]
with . Since for all we have the inclusions
[TABLE]
we similarly deduce
[TABLE]
In a similar way, by Fatou’s Lemma, satisfies estimate (3.1.2) in , while if is the average of in then, by Lebesgue’s Dominated Convergence Theorem, (see also the proof of Lemma 4.1.1). Thus, we also have
[TABLE]
Now we are ready to finish. As above, using the assumptions on we have
[TABLE]
as , uniformly on . Similarly
[TABLE]
as . Then, we can apply Lemma 6.1.10 to obtain condition (4.2.1) (with and ). Note that from the estimate and (4.2.1) we conclude that . Then, Lemma 4.2.1 implies that is a local renormalized solution of
[TABLE]
Since the measures are supported in , we apply Theorem 5.1.1 to obtain that , and thus , are symmetric with respect to . Hence, by Theorem 5.2.1 the restriction of to is a solution to the problem. ∎
Now we consider the case .
Theorem 6.1.12**.**
Let and . Suppose satisfies Assumption 6.1.1 with some . There exists a constant such that if then there exists a renormalized solution of
[TABLE]
Proof.
We repeat the ideas used in the proof of Theorem 6.1.11, so we only point out the main differences.
As before, the first step is obtaining solutions to
[TABLE]
This could be achieved by using Theorem 5.1.2 of [25], which guarantees the existence of a solution to
[TABLE]
provided that is bounded by , where is a constant that may depend on the domain . Note that, since we intend to take to infinity, this could be troublesome for us. Indeed, if happens to vanish as then requiring that the bound holds for all would lead to the conclusion that . Let us see that we can work around this problem.
A look at the proof of Theorem 5.1.2 of [25] shows that the constant is exactly the constant in the estimate
[TABLE]
which holds for solutions to problem (6.1.13) with replaced by a regularized . Since any such solution satisfies and we have, as noted in Remark 6.1.7, that we can use the results of [6] to replace the above estimate with
[TABLE]
for some independent of . Hence, by applying the same argument as in [25], but with the above estimate, it is easy to see that in fact a solution exists if we assume .
Next, as in the case , we obtain a limit function which we claim is a renormalized solution of
[TABLE]
The proof of this claim is as before: by using that
[TABLE]
as , we can apply Lemmas 6.1.6, 6.1.8 and 6.1.9 to show that solves the above equation.
In the final step, we similarly obtain a limit function which yields a renormalized solution to
[TABLE]
provided we can show (4.2.1) holds. By Lemma 6.1.10, it is enough to obtain
[TABLE]
and
[TABLE]
as , uniformly on .
As in the case we want to estimate the averages of the solutions and proceed as in the proof of Lemma 6.1.6. Let us first observe that by the results of [11] the solutions belong the Lorentz-Sobolev space , i.e., the space of weakly differentiable functions in such that (the absolute value of) their derivative belongs to the Lorentz space (note that in the case renormalized solutions have well defined derivatives; see Remark 3.3.5). Moreover, one has
[TABLE]
and so
[TABLE]
for any (see also [7]). Here is the space of functions of bounded mean oscillation (see [11] for a definition of ). On the other hand, by Theorem 2.5 of [6], we can assert
[TABLE]
for some constant and where is the average of in . Hence, just as in Lemma 6.1.6, we obtain
[TABLE]
with . Since
[TABLE]
we then get
[TABLE]
where we have used that . Thus we have
[TABLE]
which vanishes as provided (note that the above inequality can be obtained by the same argument as the one used in the case ).
We now obtain the same estimate for . We note that implies, by definition, that
[TABLE]
for all (see [19]). Since in , by Fatou’s Lemma we obtain that
[TABLE]
for all such that and so, in particular, for . Hence, by density, the bound can be seen to hold for all and, again by definition, we obtain . Thus, all the above computations remain true for and the desired estimate holds.
Hence, we obtain a solution to the problem provided where
[TABLE]
∎
Remark 6.1.13
Note that we have proven stability of solutions without using any type of convergence of to (or of to ) in . On the other hand, it is rather natural to expect that strongly in and strongly in for any . Let us see that in fact we can assume convergence in .
Indeed, by Lemma 6.1.9 we have strongly in . Then, by Proposition 2.3.8 of [10], up to a subsequence, in . By taking we may extract a diagonal subsequence from such that in as for any . We relabel this subsequence as . Then, since is finite, we conclude that in . Hence, we may assume in . Moreover, using the same estimates as in the above proofs, it is easy to show using Vitali’s Theorem that this implies strongly in . Similarly, one can use the strong convergence of in guaranteed by Lemma 4.2.1 to show that, up to a subsequence, in and strongly in for any .
6.2 The supercritical case
We now obtain renormalized solutions to equation (1.0.1) when and the absorption term does not necessarily satisfy the growth estimates of Assumption 6.1.1. In this case we can only guarantee existence of solutions if belongs to a subset of which, in general, is strictly smaller.
Throughout this section we will assume that
[TABLE]
Note that satisfies part of Assumption 6.1.1, and that if is the function defined in part of Assumption 6.1.1 then (). Note also that for any .
As in the subcritical case, our starting point is the existence results for the problem
[TABLE]
We will use the existence results obtained in [4] (see also [25]), which rest mainly on the study of the Wolff potential of the measure . As it turns out, the estimates involved are well suited to study trace problems such as ours.
We begin by defining the -truncated Wolff potential of a nonnegative measure by
[TABLE]
where , , , and is the -dimensional ball of radius centered at . If we just write .
It follows immediately from the definition that if is supported in then
[TABLE]
for any , . Moreover, we clearly have and so
[TABLE]
for any .
Remark 6.2.1
Let us record the following important relationship between Wolff potential and superharmonic functions: if is a nonnegative superharmonic function in , , and in then there exists positive constants , , , depending only on and , such that for any and there holds
[TABLE]
The following existence result is Theorem 4.1 of [4].
Theorem 6.2.2**.**
Let be a bounded domain and let be a Caratheodory function such that is nondecreasing and odd for . Then there exists a constant such that the following is true: if , , are nonnegative and there exists nondecreasing sequences of nonnegative measures in with compact support in converging to weakly and such that then there exists a renormalized solution of
[TABLE]
Moreover,
[TABLE]
Our first goal is to improve estimate (6.2.4) from in to in .
Lemma 6.2.3**.**
Let be a bounded domain and let be a Caratheodory function such that is nondecreasing and for and all . Let and let be a renormalized solution to
[TABLE]
Then
[TABLE]
* in with as in the statement of Theorem 6.2.2.*
Proof.
We know that for every the functions are renormalized solutions to
[TABLE]
for some nonnegative measures that converge to in the narrow topology of measures. Let be a renormalized solution to
[TABLE]
Since is nonnegative we have (see Remark 6.5 of [18]), and so in . Since is bounded we have and so we can use that is nondecreasing on and that all the measures involved are in to obtain, by an easy adaptation of the proof of Lemma 6.8 of [18], that in . By Theorem 3.4 of [9], passing to a subsequence we have in where is a renormalized solution to
[TABLE]
In particular, since is finite, in .
Since is nonnegative, by Theorem 2.1 of [18] coincides in with a superharmonic function satisfying
[TABLE]
in where is the same constant as in Theorem 6.2.2 (see the proof of Theorem 3.8 in [4]). Moreover, by Theorem 10.9 of [14] is quasi-continuous in . Considering the quasi-continuous representative of , and since in , we can conclude in (see Remark 2.4.6). Hence,
[TABLE]
in . The lower estimate can be obtained similarly. ∎
Remark 6.2.4
We note that in the second part of the above proof we have used that the superharmonic representative of a nonnegative renormalized solutions , mentioned in Remark 3.2.4, is a quasi-continuous representative of . We will use this fact in the sequel.
Let us also mention the following: if in , where and are superharmonic, then everywhere in . Indeed, this follows from applying Corollary 7.23 of [14] to the superharmonic function .
The above estimate is sufficient to obtain local solutions to (1.0.1). To obtain global solutions we need to compare solutions defined in nondecreasing sequences of domains. The following lemma asserts that for a nonnegative measure it is possible to obtain nondecreasing solutions defined on nondecreasing domains.
Lemma 6.2.5**.**
*Let and be bounded domains such that . Let be nonnegative, compactly supported in , and assume where and are as in Theorem 6.2.2. Then there exists renormalized solutions and to
[TABLE]
and
[TABLE]
respectively, such that in .
Proof.
Suppose first that is bounded. Then Lemma 4.2 of [4] shows that the desired solutions and exists and that they can be defined as the limit of sequences and of weak solutions to (6.2.5) and (6.2.6), respectively, with data converging to in a weak sense. Since the solutions are nonnegative, , and , the maximum principle shows that in . Hence, in . If is not bounded then one can proceed as in the proof of Lemma 4.3 of [4] and consider the truncations . The fact that shows that one can pass to the limit as to obtain solutions that conserve the desired property. ∎
Next we use Lemma 6.2.3 to show that we can obtain solutions with absorption term from solutions to problem (6.2.1).
Lemma 6.2.6**.**
Let be a continuous nondecreasing odd function, and let be the constant in Theorem 6.2.2. Let be such that is in . Let be defined as in (6.1.3) and let be renormalized solutions to
[TABLE]
Then there exists a function and a subsequence of , which we relabel as , such that in and is a renormalized solution to
[TABLE]
that satisfies
[TABLE]
q.e in .
Proof.
By Lemma 6.2.3 the functions satisfy
[TABLE]
and so, by (6.2.3), they satisfy estimate (6.2.8).
Since the measure is bounded independent of , Proposition 6.1.4 implies that the same is true for the measures . Hence, we can apply Theorem 3.1.7 and obtain that, up to a subsequence there exists, a suitable behaved function defined in such that in as .
Using than satisfies (6.2.8), which holds in the intersection of with any hyperplane, and that is nondecreasing we conclude
[TABLE]
as and similarly
[TABLE]
as , since .
The above estimates can be seen to hold also for the limit function . Indeed, it is enough to show that also satisfies (6.2.8). Looking at the proof of Lemma 6.2.3, we see that we obtain the right hand side of estimate (6.2.8) for from the inequality for some particular renormalized solution . Using that is the limit of the we get in . Then, considering quasi-continuous representatives, we conclude in (see Remark 2.4.6), and so, proceeding as in the proof of the lemma, we obtain that the right hand side of estimate (6.2.8) also holds for . The left hand side estimate follows in the same way, and so (6.2.8) holds for . With this estimate we obtain
[TABLE]
as and . Hence we apply Lemma 6.1.8 together with Lemma 6.1.9 to finish the proof. ∎
We are now ready to show the following trace version of Theorem 6.2.2. Recall that we assume .
Theorem 6.2.7**.**
Let be a continuous nondecreasing odd function, and let where is the constant in Theorem 6.2.2. Assume , , are nonnegative and for every there exists nondecreasing sequences of nonnegative measures in with compact support in converging to weakly- in such that is in and for each . Then there exists a renormalized solution of
[TABLE]
Moreover,
[TABLE]
* in .*
Proof.
Let be defined as in (6.1.3). It is easy to see that satisfies the assumptions of Theorem 6.2.2. Note that has compact support in . Since
[TABLE]
and is nondecreasing we obtain
[TABLE]
Hence, we may apply Lemma 4.3 of [4] to obtain renormalized solutions and , with , of
[TABLE]
with data , and , respectively, satisfying
[TABLE]
in . Let us remark that by the same lemma we can assume in . Note also that the functions are nonnegative (proceed as in Remark 6.5 of [18], testing against and using the hypothesis on ).
For any fixed , , and , the measures satisfy all the necessary conditions to guarantee, again by Lemma 4.3 of [4], the existence of renormalized solutions , , to problem (6.2.10) with data in . Since we can combine the results of Lemma 4.3 of [4] with Lemma 6.2.5 above to further assume in . That is, we may assume the solutions are nondecreasing in .
Now, applying Lemma 6.2.6 we take to obtain renormalized solutions , and to
[TABLE]
with data , and , respectively. By Lemma 6.1.9 (which is used in the proof of Lemma 6.2.6), we have and strongly in for any . Since renormalized solutions are finite, we can use Proposition 2.3.8 of [10] to obtain, passing to a diagonal subsequence, that and in (see Remark 6.1.13). Hence, we can assume that
[TABLE]
in . Here we have used again that we are considering quasi-continuous representatives, so that we can extend the inequalities from in to in (see Remark 2.4.6). Note that we also can assume
[TABLE]
in , and so in particular in .
Next we fix . Since the measures are uniformly bounded in norm by we obtain by Proposition 6.1.4 that
[TABLE]
By Lemma 6.1.8 we have
[TABLE]
for any . Thus,
[TABLE]
and by (6.2.12)
[TABLE]
With the above estimates we can apply Theorem 3.1.7 to obtain the existence of subsequences such that and in as for some suitable behaved functions and . Note that there is no loss of generality in assuming coincides with its superharmonic representative mentioned in Remark 6.2.4, so that in particular we can assume are nondecreasing in everywhere in . Then, Lemma 7.3 of [14] shows that is a superharmonic function in and so, by Theorem 10.9 of [14], also quasi-continuous in . Hence, is a quasi-continuous representative of , and we can assume in . Thus, considering quasi-continuous representatives, we conclude from (6.2.12) that
[TABLE]
in .
Since we have the estimate
[TABLE]
and are nondecreasing in and nonnegative, we obtain by Monotone Convergence that and moreover
[TABLE]
Then, by slightly modifying the arguments leading to Corollary 3.5 of [4] we obtain that is a renormalized solution to (6.2.11) with data . Indeed, to obtain the same stability result we only need to consider the terms and , since the focus of the corollary is the handling of the measures in order to apply the stability result of [9]. But, replacing this stability result by the one in [17], we see by the proof of Lemma 6.1.9 (or Lemma 4.2.1) that we can prove stability provided
[TABLE]
for any converging to both in and weakly in and such that is uniformly bounded in . By Lemma 6.1.10, it is enough to show that
[TABLE]
as uniformly in . But this is clearly true since are nonnegative and .
Similarly, we can show that is a renormalized solution to (6.2.11) with data provided we show that
[TABLE]
and
[TABLE]
as , uniformly in . Now, by the monotonicity of and the fact that is odd, we conclude from estimate (6.2.12) that
[TABLE]
while from (6.2.13) we have
[TABLE]
Moreover
[TABLE]
outside a set of zero measure in . Hence, since , the desired estimates hold.
To finish we can proceed exactly as in the proof of Theorem 6.1.11. Indeed, putting and using the uniform boundedness of we can apply Lemma 4.1.1 to obtain a suitable behaved function as the limit of the . Note that we can also take the limit of the to obtain suitable functions .
As we argued above, using that are nondecreasing in and passing to quasi-continuous representatives, we obtain from (6.2.13) that
[TABLE]
in .
Next, we want to show that for any given
[TABLE]
for any converging to both in and weakly in and such that are uniformly bounded in . By Lemma 6.1.10, it is enough to show that
[TABLE]
and
[TABLE]
as , uniformly on . From (6.2.13), (6.2.14), and the hypothesis on we conclude
[TABLE]
in . By the uniform bounds
[TABLE]
we use that are nondecreasing in to conclude that
[TABLE]
Then, the desired estimates follow and . Thus, by Lemma 4.2.1 we obtain that in . Applying Theorem 5.1.1 and Theorem 5.2.1 we obtain that the restriction of to is a solution of the desired problem satisfying (6.2.14) (which gives (6.2.9)). ∎
Remark 6.2.8
As in Remark 6.1.13, we observe that it can be shown that, passing to subsequences if necessary, and strongly in , and strongly in for any .
Theorem 6.2.7 can be used to obtain existence of renormalized solutions when satisfies more explicit conditions. For example, we have the following application to the case when is dominated by a power function.
Theorem 6.2.9**.**
Assume and let be a continuous nondecreasing odd function such that
[TABLE]
for some , , and . If is absolutely continuous with respect to then there exists a renormalized solution to (1.0.1) with datum .
Proof.
Since is absolutely continuous with respect to so are , , and , . Then for every we can apply Theorem 2.6 of [4] in dimension with , , and to obtain nondecreasing sequences of nonnegative measures in with compact support in converging to weakly- in and such that . It follows immediately that belongs to .
To apply Theorem 6.2.7 it only remains to show that we can assume for each . For this we note that the approximating sequences given by Theorem 2.6 of [4], which are defined in the proof of Theorem 2.5 of [4], can be taken equal to for some that approximate, and are bounded by, , where is a smooth function supported in a neighborhood of . Since coincides with in one can check directly that by redefining as one obtains approximating sequences with the same properties listed above and that moreover satisfy the desired condition . ∎
Remark 6.2.10
It must be noted that Theorem 6.2.9 agrees with Theorem 6.1.11 in the sense that if (see Remark 6.1.2) then (see Proposition 2.6.1 of [10]), and so any bounded Radon measure is admissible according to Theorem 6.2.9.
On the other hand, Theorem 6.1.11 gives that any bounded Radon measure is admissible for a wider range of nonlinearities than Theorem 6.2.9. For example
[TABLE]
is subcritical if (and is chosen large enough) since it satisfies Assumption 6.1.1, but there is no such that for large values of . Hence, in this case, Theorem 6.2.9 can only be applied with , and so it no longer guarantees that every bounded Radon measure is admissible since, for example, the Dirac measure is singular with respect to precisely when .
Let us also mention that, since , the -Lebesgue measure is absolutely continuous with respect to (see [10]), and so every measure in is admissible according to Theorem 6.2.9 (even when ).
To obtain similar conditions for other nonlinearities we need to introduce some terminology. First we define the Bessel-Lorentz capacities, which can be viewed as a generalization of the Bessel capacities.
For and we denote by the standard Lorentz space (see for example [19]). Then for one can define the Lorentz-Bessel capacities
[TABLE]
where is the Bessel kernel of order in (see [10] or [4]). The identification , which holds for , shows that indeed these capacities generalize the standard Bessel capacities.
Theorem 6.2.11**.**
Let and let be a continuous nondecreasing odd function such that
[TABLE]
for some . If is absolutely continuous with respect to then there exists a renormalized solution to (1.0.1) with datum .
Proof.
If is absolutely continuous with respect to then so are , , and . For every apply Theorem 2.6 of [4] in dimension with , , , and to obtain nondecreasing sequences of nonnegative measures in compactly supported in , converging to weakly- in and such that . Just as in the proof of Theorem 6.2.9 we may also assume that .
We observe that implies for every and where depends on (see [19]). Then, as in the proof of Theorem 6.1.11, we can obtain the inequality
[TABLE]
where is the norm of . Hence, we finish by applying Theorem 6.2.7. ∎
Remark 6.2.12
Let us make a few observations regarding this result. It is well-known that and that is the dual of . Thus
[TABLE]
which implies that if then . Since this happens precisely when , we conclude that if then any bounded Radon measure is admissible under the above theorem. In particular, this shows that Theorem 6.2.11 coincides with Theorem 6.2.9 when and .
Proceeding in a similar way, one can use the fact that whenever to prove (as in Proposition 2.6.1 of [10]) that the -Lebesgue measure is absolutely continuous with respect to . Thus, every measure in is admissible according to Theorem 6.2.11.
Note that, in general, if then Theorem 6.2.9 guarantees existence of a solution to (1.0.1) provided is absolutely continuous with respect to , while Theorem 6.2.11 guarantees existence if is absolutely continuous with respect to for any .
On the other hand, under the hypotheses on , if the growth condition of the above theorem is satisfied with then satisfies Assumption 6.1.1, and so it is subcritical. Hence, we expect that the above estimate , which implies existence for any bounded Radon measure, can be improved to the case . It can be proven directly that this is true. Indeed, following the ideas above, it is enough to show that . This can be shown by definition using that has exponential decay at infinity and that it is controlled by the Riesz kernel of the same order.
As a final application we consider nonlinearities of exponential type. To this end we define the truncated -fractional maximal operator as
[TABLE]
where , , and
[TABLE]
Then we have the following result.
Theorem 6.2.13**.**
Let and let be a continuous nondecreasing odd function such that
[TABLE]
for some , , and . Let be such that , where and , , are nonnegative. There exists such that if
[TABLE]
then there exists a renormalized solution to (1.0.1) with datum .
Proof.
Let with , define , and let be its restriction to . Define . Then are nonnegative, nondecreasing on , compactly supported in , and moreover . It is also clear that weakly- in . Hence, to apply Theorem 6.2.7 it remains to show .
Let us first note that since and we have
[TABLE]
On the other hand, it holds that for every , there exists such that if then . Using this twice we conclude
[TABLE]
for some to be fixed later, and so we have
[TABLE]
since . Now, an application of Theorem 2.4 of [4] in dimension with , , , and , shows that there exists such that
[TABLE]
for any . Hence, if we choose any such that
[TABLE]
then by hypothesis and the fact that
[TABLE]
we conclude that there exist such that
[TABLE]
for some and so
[TABLE]
which concludes the proof. ∎
Remark 6.2.14
It is immediate that the above theorem guarantees existence for data in .
When , i.e. , the condition imposed on reads
[TABLE]
This condition can be expressed in terms of the Riesz capacities (See Chapter 2). Indeed, it is known that in the case it holds for some independent of (see Chapter 5 of [10]), and so the above condition is equivalent to
[TABLE]
for every and .
Chapter 7 Nonlinear problems with source
In this chapter we consider nonnegative solutions to the following problem with source
[TABLE]
where , , and is nonnegative.
We begin obtaining necessary conditions for existence of solutions. Then, we show that under a smallness assumption on the constants involved, these conditions imply existence of solutions. Lastly, we use these conditions to show nonexistence results and also to characterize removable sets.
7.1 Necessary conditions for existence
To obtain necessary conditions for existence of solutions to (7.0.1) we follow the ideas in [18].
In order to state our first result we need to introduce the Riesz potential of order , , on , of a nonnegative Radon measure by
[TABLE]
where is a normalized constant. We recall that the Riesz capacities were defined in Chapter 2, while the Wolff potential was defined in Section 6.2.
Theorem 7.1.1**.**
Let and . Let in be nonnegative and suppose there exists a nonnegative renormalized solution to (7.0.1). Then
[TABLE]
holds for all balls (where is the restriction of to ).
Proof.
We know by Remark 3.3.4 that if solves (7.0.1) then , the extension of to by even reflection across , is a local renormalized solution to
[TABLE]
Let . Combining Theorems 4.3.2 and 4.2.5 of [25], we obtain that coincides with a superharmonic function satisfying
[TABLE]
By Remark 6.2.4 we can conclude that
[TABLE]
in and so, by Proposition 2.3.2, Thus, for any dyadic cube (i.e., for some and ) we have
[TABLE]
Using that, for any , , and any ,
[TABLE]
with the dimensional measure of , and where the sum is taken over all dyadic cubes contained in (see [10]), we conclude
[TABLE]
By Proposition 3.1 of [18] the above implies
[TABLE]
which, by an application of Theorem 3 of [22], yields
[TABLE]
for any nonnegative , where and the sum is taken over all dyadic cubes . Since
[TABLE]
and we obtain
[TABLE]
for any . Hence, is a bounded linear operator and so its dual satisfies
[TABLE]
for any . Taking we obtain (7.1.1). ∎
Remark 7.1.2
It is known that (7.1.1) is equivalent with the condition
[TABLE]
for all compact sets . The proof of this equivalence, which we will use in the following sections, can be found in [23]. On the other hand, it is known that (7.1.1) implies
[TABLE]
(see [24] or [18]). By Proposition 5.1 of [18]
[TABLE]
so we see that (7.1.1) implies
[TABLE]
for all balls . Note that, by Monotone Convergence, the above condition implies that if then .
As we will see, condition (7.1.1) is ‘almost’ sufficient to obtain existence of a solution. However, because of the method we use to show existence, it is convenient to work with another necessary condition which is actually a consequence of (7.1.1).
Theorem 7.1.3**.**
Let , , and let in be nonnegative. Then condition (7.1.1) implies and
[TABLE]
for some nonnegative constant depending on , , and .
Proof.
By Remark 7.1.2, it is enough to check that (7.1.3) implies (7.1.4). To this end we decompose the Wolff potential as , where
[TABLE]
for any . Setting
[TABLE]
we see that for any . Note that these are measures.
Now fix any and write for simplicity . If and then , and so in . Hence, by (7.1.3) we have
[TABLE]
and so
[TABLE]
Next, we study the rate of decay of as function of . If and then and so
[TABLE]
Comparing the above with (7.1.3) it follows that
[TABLE]
and then
[TABLE]
If and then and so
[TABLE]
which gives
[TABLE]
Combining the above estimates and using integration by parts we get
[TABLE]
that is,
[TABLE]
By combining (7.1.5) and (7.1.6) we conclude
[TABLE]
which is the desired estimate (7.1.4). ∎
7.2 Sufficient conditions for existence
Our strategy for solving problem (7.0.1) is to combine the techniques developed in [18], where the authors study the existence of superharmonic solutions to
[TABLE]
with our symmetry and existence results of Chapter 5. The results of [18] are based on a careful study of the Wolff potential, and the existence of solutions is guaranteed under any one of some equivalent conditions, among which is that the measure satisfies
[TABLE]
for some small enough constant .
Unlike the problem with absorption, we do not use directly the existence result of [18] to construct a global solution. Instead, we define a recursive sequence of solutions to
[TABLE]
where and , and then take limit as . In this way we dispense with the need to define a sequence of nonlinearities converging to (as was done in the previous chapter). As we show in the next theorem, this method gives a solution to (7.0.1) under a natural adaptation of condition (7.2.1). But before, we need the following lemma.
Lemma 7.2.1**.**
Let , be nonnegative measures and suppose . Let and let be a renormalized solution to
[TABLE]
then there exists a renormalized solution to
[TABLE]
such that in .
Proof.
The lemma (and its proof) is a slight modification of Lemma 6.9 in [18], so we omit some details. Let . Then solves in , on , where is a nonnegative measure (see Remark 3.1.4). Let solve in , on . By the stability results of [9], passing to a subsequence, converges to a function solving the desired equation. Since is finite, the result follows if we can show that in . For this we can proceed exactly as in the proof of Lemma 6.8 in [18]. We only remark that , where and , belongs to because is nonnegative and . ∎
Theorem 7.2.2**.**
Let and . Let be a nonnegative measure in satisfying and condition (7.1.4) with
[TABLE]
where and is the constant in Theorem 6.2.2. Then there exists a nonnegative renormalized solution to (7.0.1) satisfying
[TABLE]
where is a set of the form , , with and . In particular, the above estimate holds in any hyperplane .
Proof.
Let be a renormalized solution of
[TABLE]
where . Such a function exists by, for example, the results in [9]. By testing against one can see that implies that is nonnegative (see Remark 6.5 of [18]). By Lemma 6.2.3, satisfies
[TABLE]
in , where is the constant in Theorem 6.2.2. As observed in (6.2.2)
[TABLE]
so and, by (6.2.3),
[TABLE]
in , and in the whole if we extend the function by zero outside of . Suppose , , and is a renormalized solution to
[TABLE]
where and is nonnegative, supported in , and satisfies
[TABLE]
for some constant , where is a set of the form with and the set where is finite and condition (7.1.4) holds (note that ). Since the measure is nonnegative we have and, again by Lemma 6.2.3,
[TABLE]
By definition of the Wolff potential one can see that
[TABLE]
where . Therefore, we can use that and are supported in , together with (6.2.3), the monotonicity of the Wolff potential, assumption (7.1.4), and the induction hypothesis, to compute that
[TABLE]
for every , where , is as described above, and is the intersection of with the set where the first inequality holds. Note that . Hence, by induction starting with , we obtain a sequence of nonnegative functions such that
[TABLE]
with as described above, and where
[TABLE]
Since , it is easy to show by induction that the assumption
[TABLE]
implies that the sequence satisfies
[TABLE]
and so we obtain
[TABLE]
Note that we may assume in . Indeed, assume is a solution of (7.2.5) such that in . Set . Then, since , Lemma 7.2.1 shows that we can obtain a renormalized solution of (7.2.5) such that in . Extending by zero and using quasi-continuous representatives we conclude in .
Now, since these solutions are nonnegative, we may identify them with their superharmonic representatives and conclude everywhere in (see Remark 6.2.4). Then, by Lemma 7.3 of [14] defines a superharmonic function which, by Theorem 10.9 of [14], is quasi-continuous in (note that is finite in and for every ). Moreover, it follows that and in . Notice that is uniformly bounded in . Hence, by Lemma 4.1.1 satisfies properties , , and in the statement of that lemma. Note also that satisfies the desired estimate (7.2.3).
By Lemma 6.1.10, to show that (4.2.1) holds it is enough to have
[TABLE]
as , uniformly in . But this is clearly true since in and . Hence, we may apply Lemma 4.2.1, with and , to conclude that is a local renormalized solution to
[TABLE]
By Theorem 5.1.1 such a solution is symmetric, and so by applying Theorem 5.2.1 the result follows. ∎
Combining Theorems 7.2.2, 7.1.1, 7.1.3, and Remark 7.1.2 we obtain the following.
Corollary 7.2.3**.**
Let , , and assume in is nonnegative. Then the following are equivalent:
- (1)
For some there exists a nonnegative renormalized solution to
[TABLE]
satisfying
[TABLE]
where , , with and . 2. (2)
There exists such that for all balls
[TABLE]
where is the restriction of to . 3. (3)
There exists such that for all compact sets
[TABLE] 4. (4)
There exists such that for all balls
[TABLE] 5. (5)
* and*
[TABLE]
Proof.
We know implies from Theorem 7.1.1. We noted in Remark 7.1.2 that is equivalent with and implies . That implies was shown in Theorem 7.1.3. Finally, suppose holds for some constant . Then we see that for any
[TABLE]
in , and so follows from Theorem 7.2.2 provided is chosen small enough. ∎
7.3 Nonexistence for the subcritical case
We now turn to the problem of nonexistence.
Notice that when showing (7.1.1), in the proof of Theorem 7.1.1, we actually obtain
[TABLE]
where . Note also that the argument could have been applied directly to a superharmonic function solving in . On the other hand, we obtained
[TABLE]
for all dyadic cubes , which in the case implies
[TABLE]
This last inequality cannot hold for a bounded nonnegative defined in unless it is trivial. Hence, considering also the equivalences in Remark 7.1.2, we can conclude the following.
Corollary 7.3.1**.**
Let and . Let in be nonnegative and suppose is a nonnegative superharmonic solution to in . If then
[TABLE]
for all compact sets . If then in and .
Since whenever (see [10]) we have the following Liouville-type theorem for subcritical problems with source.
Theorem 7.3.2**.**
Let , , and nonnegative. If , or and , then there are no nontrivial nonnegative superharmonic solutions of in . In particular, there are no nontrivial nonnegative renormalized solutions of (7.0.1).
Proof.
Since every nonnegative local renormalized solution coincides with a superharmonic solution of the same equation (see Remark 3.2.4), by Remark 3.3.4, the hypothesis, and the previous corollary, we see that is enough to show that there are no nontrivial nonnegative superharmonic solutions of in whose trace vanishes in . As noted in Remark 6.2.1, any such solution satisfies
[TABLE]
in for any , and so .
∎
7.4 Characterization of removable sets
In this section we obtain a characterization of removable sets for problem (7.0.1) when . In order to properly define removable sets we first define what does it mean to have a renormalized solution up to a portion of the boundary. We give a definition which is a natural variant of definition 3.3.1.
Definition 7.4.1**.**
Let and . Given compact, a renormalized solution of
[TABLE]
is a function defined in such that:
- (1)
is measurable, finite , and for all ; 2. (2)
for all ; 3. (3)
for all ( if ); 4. (4)
is finite in , and for any closed set such that ; 5. (5)
there holds
[TABLE]
for all compactly supported in , whose trace belongs to , and satisfying the following condition: there exists , , and functions such that
[TABLE]
Remark 7.4.2
We note that, just as in Remark 3.3.2, it makes sense to talk about the boundary values of in .
Now we define removable sets.
Definition 7.4.3**.**
We say that a compact set is removable for (7.4.1) if every nonnegative renormalized solution of (7.4.1) is a nonnegative renormalized solution of
[TABLE]
We have the following characterization of removable sets.
Theorem 7.4.4**.**
If and then a compact set is removable for (7.4.1) if and only if .
Proof.
Let be a renormalized solution to (7.4.1) and suppose is equal to zero. Since we can combine Theorems 5.1.4 and 5.5.1 of [10] to conclude that . Let be the extension of to by even reflection. Then is a local renormalized solution to in . By Proposition 2.3.2 and by Theorem 4.3.6 of [25] this implies that the superharmonic representative of can be extended to as a nonnegative superharmonic function. By Remark 6.2.4, this superharmonic representative coincides with in . Let be the Radon measure associated to , i.e., the measure such that in . Let us show that .
Take nonnegative and let be such that , , and point-wise in . Note in particular that \mathcal{H}-$$a.e.. Hence, by Fatou’s Lemma,
[TABLE]
and so we conclude and in (recall that satisfies of Definition 7.4.1). It follows at once from considering the equations solved by that in fact in . Then, setting we have that is a superharmonic solution of
[TABLE]
where the measure is supported in (and hence bounded). Then, by Corollary 7.3.1,
[TABLE]
and so . By Theorem 4.3.4 of [25], is a local renormalized solution to in , and so, by Theorem 5.2.1, the restriction of to is a renormalized solution of (7.4.2).
For the converse, suppose . We let be the capacitary measure of (see Theorem 2.5.3 of [10]) and extend it to by setting . By Theorem 2.5.5 of [10] we see that satisfies (7.1.2) and so, by Corollary 7.2.3, there exists a renormalized solution of (7.0.1) with measure for some . Since is concentrated in , is also a solution of (7.4.1) and thus is not removable. ∎
The reference list from the paper itself. Each links out to its DOI / PubMed record.
- 1[1] E. Azroul, A. Barbara, M. B. Benboubker, and S. Ouaro. Renormalized solutions for a p ( x ) 𝑝 𝑥 p(x) -Laplacian equation with Neumann nonhomogeneous boundary conditions and L 1 superscript 𝐿 1 L^{1} -data. An. Univ. Craiova Ser. Mat. Inform. , 40(1):9–22, 2013.
- 2[2] P. Bénilan, L. Boccardo, T. Gallouët, R. Gariepy, M. Pierre, and J. L. Vázquez. An L 1 superscript 𝐿 1 L^{1} -theory of existence and uniqueness of solutions of nonlinear elliptic equations. Ann. Scuola Norm. Sup. Pisa Cl. Sci. (4) , 22(2):241–273, 1995.
- 3[3] M. F. Bidaut-Véron. Removable singularities and existence for a quasilinear equation with absorption or source term and measure data. Adv. Nonlinear Stud. , 3(1):25–63, 2003.
- 4[4] M.-F. Bidaut-Véron, N. Q. Hung, and L. Véron. Quasilinear Lane-Emden equations with absorption and measure data. J. Math. Pures Appl. (9) , 102(2):315–337, 2014.
- 5[5] L. Boccardo, T. Gallouët, and L. Orsina. Existence and uniqueness of entropy solutions for nonlinear elliptic equations with measure data. Ann. Inst. H. Poincaré Anal. Non Linéaire , 13(5):539–551, 1996.
- 6[6] A. Cianchi. Moser-Trudinger trace inequalities. Adv. Math. , 217(5):2005–2044, 2008.
- 7[7] A. Cianchi and L. Pick. Sobolev embeddings into BMO, VMO, and L ∞ subscript 𝐿 L_{\infty} . Ark. Mat. , 36(2):317–340, 1998.
- 8[8] G. Dal Maso. On the integral representation of certain local functionals. Ricerche Mat. , 32(1):85–113, 1983.
