This paper classifies finite-dimensional pointed Hopf algebras over certain finite simple groups of Lie type, showing that most conjugacy classes do not support such algebras, except for the group algebra itself.
Contribution
It proves that all non-semisimple, non-unipotent classes in specified Chevalley and Steinberg groups collapse, except for PSL_n(q), and identifies the only finite-dimensional pointed Hopf algebras over certain groups.
Findings
01
All classes that are neither semisimple nor unipotent in specified groups collapse.
02
The only finite-dimensional pointed Hopf algebra over these groups is the group algebra.
03
Classification of finite-dimensional pointed Hopf algebras over certain finite simple groups.
Abstract
We show that all classes that are neither semisimple nor unipotent in finite simple Chevalley or Steinberg groups different from PSLn(q) collapse (i.e. are never the support of a finite-dimensional Nichols algebra). As a consequence, we prove that the only finite-dimensional pointed Hopf algebra whose group of group-like elements is PSp2n(q), PΩ4n+(q), PΩ4n−(q), 3D4(q), E7(q), E8(q), F4(q), or G2(q) with q even is the group algebra.
Table 4. Table 4. Pairs ( Π , w W Π ) Π 𝑤 subscript 𝑊 Π (\Pi,wW_{\Pi}) discussed separately in type E 6 subscript 𝐸 6 E_{6}
(up to isogeny)
Table 5. Table 5. Center of 𝔾 s c F superscript subscript 𝔾 𝑠 𝑐 𝐹 {\mathbb{G}}_{sc}^{F} , Steinberg groups
type
conditions
odd
,
a primitive root of
,
Table 6. Table 6. Pairs ( Π , w F J W Π ) Π subscript 𝑤 𝐹 𝐽 subscript 𝑊 Π (\Pi,w_{FJ}W_{\Pi}) in type E 6 2 superscript subscript 𝐸 6 2 {}^{2}E_{6} , for w F J ≠ 1 subscript 𝑤 𝐹 𝐽 1 w_{FJ}\neq 1 that are dealt with separately
(up to isogeny)
Table 7. Table 7. Pairs ( Π , W Π ) Π subscript 𝑊 Π (\Pi,W_{\Pi}) in type E 6 2 superscript subscript 𝐸 6 2 {}^{2}E_{6} , for w F J = 1 subscript 𝑤 𝐹 𝐽 1 w_{FJ}=1
=g▹(w0∣θ∣−1θtq)={g▹tq=sq,g▹t−q=s−q, if θ=id, if θ=−w0,
(gw˙0g−1)▹s
(gw˙0g−1)▹s
yszu=zuys and zsyu=yuzs,
yszu=zuys and zsyu=yuzs,
x1,x2∈X1\mboxsuchthat(x1x2)2=(x2x1)2,
x1,x2∈X1\mboxsuchthat(x1x2)2=(x2x1)2,
y1=y2∈X2\mboxsuchthaty1y2=y2y1.
d=diag(ζ,ζq−1,ζ−q),
d=diag(ζ,ζq−1,ζ−q),
OxuK≃OxuK↪OxG,
OxuK≃OxuK↪OxG,
H=⟨T,Uα∣α∈Φ,α(t)=1⟩.
H=⟨T,Uα∣α∈Φ,α(t)=1⟩.
K
K
[H,H]=G1⋯Gr,
[H,H]=G1⋯Gr,
[H,H]=H1⋯Hl,
[H,H]=H1⋯Hl,
j=1∏lFw(vj)=Fw(v)=v=j=1∏lvj
j=1∏lFw(vj)=Fw(v)=v=j=1∏lvj
j=1∏auj=v=Fw(v)=j=1∏aFw(uj),
j=1∏auj=v=Fw(v)=j=1∏aFw(uj),
uj=Fwj−1(u1),j∈I1,a
uj=Fwj−1(u1),j∈I1,a
Fwa
Fwa
\displaystyle|{\mathbb{J}}_{v}|=1\text{ and }{\mathcal{O}}_{v_{1}}^{G_{1}}\text{ occurs in Table \ref{tab:unip-kthulhu}, or}\qquad\qquad\qquad\qquad\quad\ \
\displaystyle|{\mathbb{J}}_{v}|=1\text{ and }{\mathcal{O}}_{v_{1}}^{G_{1}}\text{ occurs in Table \ref{tab:unip-kthulhu}, or}\qquad\qquad\qquad\qquad\quad\ \
∣Jv∣≥2 and for every j∈Jv the rack OvjGj occurs in Table \reftab:unip-not-y1y2.
g▹:OtvGFw→∼OxGF,
g▹:OtvGFw→∼OxGF,
X:=tOvHFw,
X:=tOvHFw,
r=tv∈X,
r=tv∈X,
OrH=tOvH=OvH=Ov⟨v,v′⟩≥3
OrH=tOvH=OvH=Ov⟨v,v′⟩≥3
I(τ)
I(τ)
I(s)
G is of type Bℓ,
G is of type Bℓ,
ωi(xs)
ωi(xs)
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Full text
Finite-dimensional pointed Hopf algebras
over finite simple groups of Lie type V.
Mixed classes in Chevalley and Steinberg groups
Nicolás Andruskiewitsch, Giovanna Carnovale∗ and
Gastón Andrés García
FaMAF,
Universidad Nacional de Córdoba. CIEM – CONICET
Medina Allende s/n (5000) Ciudad Universitaria, Córdoba,
We show that all classes that are neither semisimple nor unipotent in finite simple
Chevalley or Steinberg groups different from PSLn(q)
collapse (i.e. are never the support of a finite-dimensional Nichols algebra).
As a consequence, we prove that the only finite-dimensional pointed Hopf algebra whose group
of group-like elements is PSp2n(q), PΩ4n+(q), PΩ4n−(q), 3D4(q),
E7(q), E8(q), F4(q), or G2(q) with q even is the group algebra.
Keywords: Nichols algebra; Hopf algebra; rack; finite group of Lie type; conjugacy class.
The work of N. A. was partially supported by CONICET, Secyt (UNC) and the Alexander von Humboldt Foundation
through the Research Group Linkage Programme.
The work of G. A. G.
was partially supported by CONICET, Secyt (UNLP) and ANPCyT-Foncyt 2014-0507.
The work of G. C. was partially supported by Progetto BIRD179758/17 of
the University of Padova. The results were obtained during visits of N. A.
and G. A. G. to the University of Padova, and of G. C. to the University
of Córdoba, partially supported by: the bilateral agreement between
these Universities, the ICTP-INdAM Research in Pairs fellowship programme
and the Coimbra group Scholarship Programme for Young Professors and
Researchers from Latin American Universities. The authors wish to thank the referee for his/her careful reading and suggestions.
This is the fifth of a series of papers where we study a set of group-theoretical questions on conjugacy classes of finite simple groups of Lie
type because of their consequences on the classification of finite-dimensional Hopf algebras (over an algebraically closed field of characteristic 0, say C).
Let us start with a brief discussion of the reduction from the latter problem to the former. See the Introductions of [2, 5] for a more detailed exposition.
(1)
Let G be a group. There is a braided tensor category CGCGYD of so called Yetter-Drinfeld modules over
(the group algebra of) G. Each V∈CGCGYD gives rise to a graded Hopf algebra B(V) in CGCGYD,
called the Nichols algebra of V. See e.g. [1] for details.
2. (2)
Let H be a pointed Hopf algebra whose group of group-like elements is isomorphic to G.
There is a Nichols algebra B(V) attached as a fundamental invariant to H.
For instance dimH<∞ implies dimB(V)<∞; in fact B(V) controls much of the structure of H.
3. (3)
Assume that G is finite. Then CGCGYD is semisimple and its simple objects are parametrized by pairs
(O,ρ), where O is a conjugacy class of G and ρ∈IrrCG(x) is an irreducible representation
of the centralizer of a fixed element x in O; let M(O,ρ) be the simple object corresponding to (O,ρ).
By the previous discussion, we need to determine the pairs (O,ρ) with dimB(M(O,ρ))<∞
as a necessary initial step to classify finite-dimensional pointed Hopf algebras with group of group-likes G.
4. (4)
The second reduction goes as follows. It turns out that the Nichols algebra B(M(O,ρ)) depends
only (in an appropriate sense) on the rack structure of O (with rack operation given by conjugation: x▹y=xyx−1)
and a suitable 2-cocycle q arising from ρ. In this way, it is more efficient to deal with Nichols algebras
B(O,q) of
pairs (O,q) where O is a rack and q is a 2-cocycle, as the same such pair may arise from different groups.
5. (5)
Let us say that a rack Ocollapses if B(O,q) has infinite dimension for any
suitable cocycle q, cf. [6, 2.2].
Remarkably there are rack-theoretical criteria that imply that a rack collapses, without computing
neither cocycles nor Nichols algebras. These criteria can be spelled out in group-theoretical terms,
once a realization of the rack in consideration as a conjugacy class is fixed. See §2.8.
In this series we investigate the applicability of these criteria for finite simple groups of Lie type,
excluding the Suzuki and Ree groups treated in [9]. For
alternating and sporadic groups, see [6, 11, 7, 12].
Let G be a finite simple Chevalley or Steinberg group defined over a finite field Fq where q=pm,
with m∈N and p prime.
An element of G is semisimple, respectively unipotent, if its order is coprime to p, respectively a power of p.
These notions are unambiguous except when G is one of the following:
[TABLE]
A class is semisimple or unipotent if any element of it is so.
This paper deals with mixed conjugacy classes i.e., which are neither semisimple nor unipotent;
evidently there are no mixed classes in PSL2(q).
For the groups in (1.1),
unipotent, semisimple or mixed will mean so in one of the realizations (with some ambiguity unless the realization
is clear from the context).
The mixed conjugacy classes of PSLn(q)
were treated in [2]. In the previous four papers of the series [2, 3, 4, 5]
we concluded the analysis of the unipotent conjugacy classes of G
which is summarized in Table 1.
Elaborating on these results we obtain the first main theorem of this paper:
Theorem 1.1**.**
A mixed conjugacy class in a simple Chevalley or Steinberg group collapses.
This Theorem and its proof propagate in many directions. For instance, if ϖ:H→G
is a projection from a finite group H to our G and x∈H is such that ϖ(x) is neither semisimple nor unipotent, then OxH collapses.
Here and below we use the notation OxH for the conjugacy class of x in H and we omit H if clear from the context.
For example let H=G1×G2⋯×Gt, where all Gj’s are simple Chevalley or Steinberg groups and
x=(x1,…,xt)∈H. If xj is neither semisimple nor unipotent for at least one j, then
OxH collapses.
Another application of Theorem 1.1 is to Nichols algebras of Yetter-Drinfeld modules over
our G.
Theorem 1.2**.**
Let G be a simple Chevalley or Steinberg group and V∈CGCGYD. Assume that G is not listed in (1.1).
If dimB(V)<∞, then V≃M(O,ρ) is simple and O is semisimple.
Notice that we are not claiming the converse in Theorem 1.2. Indeed Theorem 1.1
is the culmination of our analysis of unipotent classes where we rely on the combinatorial description of such classes in the algebraic group behind G.
We started the consideration of the semisimple classes in G=PSLn(q) in [4]; already in this case the situation is
much more involved and requires a different type of arguments.
As for the groups listed in (1.1), we have the following. Let V∈CGCGYD.
G≃PSL3(2)≃PSL2(7): If dimB(V)<∞, then V is simple,
hence isomorphic to M(Ox,ρ)
for some x and ρ by [19, Corollary 8.3]. We conclude that the order of x is 4 and ρ(x)=−1 by [15].
∘
G≃PSU4(2)≃PSp4(3): dimB(V)=∞. Indeed,
assume otherwise. Arguing as in the proof of Theorem 1.2, necessarily V≃M(Ox,ρ)
and the order of x is odd and not divisible by 3; by inspection, it is 5.
Now there is only one class of elements of such order, hence this class is real. But this contradicts [8].
For some Chevalley or Steinberg groups the arguments for Theorem 1.2 can be pushed even further.
A folklore conjecture claims that there is no finite-dimensional pointed Hopf algebra whose group
of group-like elements is simple non-abelian, except the group algebra.
The conjecture is known to hold for the simple alternating groups [6],
the sporadic groups (including the Tits group) except Fi22, B and M [7] and for some families of
PSLn(q)’s [14, 4]. As we just saw, it also holds for PSU4(2)≃PSp4(3);
otherwise the Conjecture is open.
We add to the list of confirmations of the Conjecture the families in (1.2), except from PSL2(q)
for q even, that had already been treated.
Theorem 1.3**.**
Let q be even and let G be a simple group in one of the following families:
[TABLE]
Let H be a finite-dimensional pointed Hopf algebra whose group of group-like elements is isomorphic to G.
Then H≃CG.
Here is the structure of the article. In Section 2 we set
the notation and collect basic preliminary results used in the paper.
In order to prove Theorem 1.1 we adopt the following strategy.
Let x=xsxu be the Chevalley-Jordan decomposition of x∈G
(which amounts to the p-decomposition in the theory of finite groups)
where we assume that neither xs nor xu are trivial.
Recall that there is a surjective group homomorphism π:GF→G,
where G is a simply connected simple algebraic group and F is a Steinberg endomorphism–see Section 2 for details.
We pick x∈GF such that π(x)=x. If x=xuxs is its Chevalley-Jordan decomposition, then
xu=π(xu).
There is a natural inclusion of racks (3.1)
of OxuK in OxG, where K is
the centraliser of xs in GF; we restrict our attention to OxuK.
The structure of K is known and
OxuK contains a product of unipotent conjugacy classes of smaller
groups of Lie type.
Thus the unipotent classes in the factors of the centraliser must occur in
Table 1.
In this way we are able to provide strong restrictions to potential kthulhu classes,
see (3.5) and (3.6).
Then we focus on the resulting reduced list of classes and we bring the action of the
Weyl group into the picture, providing further techniques to deal
with most of the potential kthulhu classes.
These methods are still quite general and allow to
cover a considerable list of groups, see Proposition 3.8,
and leave out a few exceptions in the remaining ones.
The substance of the preceding sketch is contained in Section 3.
The classes for which all above techniques
fail can be described with sufficient precision,
allowing us to carry out the final analysis.
However, this part of the proof is laborious and it needs several ad-hoc
considerations and a separation of the treatment for Chevalley (Section 4) and Steinberg groups
(Section 5), where a case-by-case analysis is performed.
Finally we prove Theorems 1.2 and 1.3 in Section 6.
2. Notation and Preliminaries
In this Section we establish notation, recall some known facts about racks and simple algebraic groups over finite fields, and collect
some results on unipotent conjugacy classes
that are used throughout the paper.
For k≤l, k,l∈N we set Ik,l:={k,k+1,…,l} and Il=I1,l.
Let p be a prime, q=pm for m∈N, k=Fq.
Let G be a simple algebraic group over k; we fix a maximal torus T and a
Borel subgroup B⊃T. We denote by U the unipotent radical of B.
Let Φ be the root system of G, let Φ+ be the set of positive roots
associated with (T,B) and let Δ={αi,i∈Iℓ}
be the corresponding base, with
ωi, for i∈Iℓ the set of fundamental weights.
The root subgroup corresponding to α will be denoted by Uα. It is the image of
a monomorphism of groups xα:k→G.
Since we will consider conjugacy classes as racks (see Subsection 2.8),
the conjugation action of g∈G on h∈G will be indicated by g▹h.
Adopting the notation from [24, 8.1.4], we have the commutation rule:
[TABLE]
We shall also make use of Chevalley’s commutator
formula [27, Lemma 15, p. 22 and Corollary, p. 24]. Namely, for α,β∈Φ+ such that α+β∈Φ+ and any order on the set
Γ of positive roots of the form iα+jβ for i,j∈N, there exist integers cijαβ such that
[TABLE]
For further unexplained notation and commutation rules we refer to [3, Section 3].
By α0 we will denote the highest root in Φ, and we set Δ:=Δ∪{−α0}.
As usual, W=NG(T)/T denotes the Weyl group,
acting naturally on T and sα is the reflection with respect to the root α.
Let σ∈W be represented by σ˙∈NG(T) and let M be a subgroup of G normalized by T. Then the subgroup σ˙Mσ˙−1 is independent of the choice of σ˙ and we shall simply write σM.
If we insist that G is simply-connected, we shall write Gsc.
For an algebraic group M, we shall denote by M∘ the connected component containing the identity.
If ϕ is an automorphism of a group H, then Hϕ will denote the set of elements of H that are fixed by ϕ.
2.1. The groups G
Let F be a Steinberg endomorphism of G, and assume T and B are F-stable.
Let G:=GscF/Z(GscF) and let π:GscF→G be the natural projection.
In most cases G is simple and, conversely, every finite simple group of Lie type is obtained this way
(except the Tits group that was treated in the paper [7] with the sporadic groups).
Here we deal with Chevalley or Steinberg groups; thus, F is the composition of a standard graph automorphism ϑ of G with the Frobenius map Frq. Then ϑ determines an
automorphism θ of the Dynkin diagram of G.
If θ=id, then G is a Chevalley group, whereas if θ=id, then G is a Steinberg group.
In the latter case, T and B are chosen to be both F-stable and Frq-stable and in both cases Frq(t)=tq for any t∈T.
Since T is F-stable, F acts on W and we denote by WF the subgroup fixed by F.
Thus WF=W for Chevalley groups.
For each w∈WF, there exists a representative w˙∈NGF(T), see [21, Prop. 23.2].
Also, for any representative w˙∈NG(T) of w∈W and any α∈Φ one has that w˙▹Uα=Uw(α).
2.2. F-stable tori
We recall that a maximal torus gTg−1 in G is F-stable if and only if
w˙=g−1F(g)∈NG(T) and this relation induces a map ϕ from the set of F-stable
maximal tori to W.
In addition, two F-stable maximal tori T1 and T2 are conjugate by an element in GF if and only if their images ϕ(T1) and ϕ(T2)
lie in the same F-twisted conjugacy class in W [21, Prop. 25.1]. If this is the case, their fixed points subgroups T1F and T2F are also conjugate in GF.
We will indicate by Tw a maximal torus gTg−1 such that g−1F(g)=w˙∈NGFrq(T).
Observe that every w in
WFrq=W has a representative
w˙ in NGFrq(T) by [21, §23.1] and existence of a g∈G such that
g−1F(g)=w˙ is guaranteed by the Lang-Steinberg theorem. Hence, such a torus always exists.
2.3. The elements wθ
Let ϑ be as above and let θ be the associated automorphism of the Dynkin diagram; it
extends to an automorphism of the root system of G that we denote again by θ.
Assume that θ=id or θ=−w0,
where w0 is the longest element in W.
The latter occurs for Steinberg groups with root system of type: Aℓ for ℓ≥2; Dℓ
for ℓ≥5 and odd; and E6.
Let w∈W and take Tw, w˙∈NGFrq(T) and g as in Subsection 2.2.
We set wθ:=ww0∣θ∣−1.
Since CW(wθ)=CW(wθ),
[21, Prop. 25.3] guarantees that there exists a representative
w˙θ of wθ in NG(T) such that gw˙θg−1∈NGF(Tw).
If θ=−w0, then we set w˙0:=w˙−1w˙θ.
2.4. Semisimple classes
Every semisimple element of GF lies in an F-stable torus
T [21, Prop. 26.6]. In particular, if ϕ(T)=w and
s∈GF∩T, then TwF is GF-conjugate to TF,
so OsGF∩Tw=∅.
Let s∈GF∩Tw=TwF, with g,w˙ as in Subsection 2.2.
We set Fw:=Ad(w˙)∘F. Then s=gtg−1 for some t∈TFw,
so
[TABLE]
Sometimes it is convenient to consider other F-stable tori intersecting OsGF.
Assume that G=Gsc and pick σ∈W such that σ−1(t)=F(t), i. e.
σ and w lie in the same left coset for the stabiliser of t in W.
Then for every representative σ˙∈NG(T)
and every gσ such that gσ−1F(gσ)=σ˙ we have
[TABLE]
so OsGF has a representative in TσF for any such σ. Here ⋆ holds because CG(s) is connected, since G=Gsc is simply-connected, [20, Theorem 2.11].
2.5. Commuting elements in a semisimple class
Let s,w,g and t be as in Subsection 2.4.
We look for powers of s lying in OsGF.
If θ=id or θ=−w0, we have:
[TABLE]
so either OsGF=OsqGF (when θ=id) or
OsGF=Os−qGF (θ=−w0).
Assume that θ=id. Even when sq=s we get some information.
In this case, t∈GF, so t∈OsG∩GF.
If, in addition, G=Gsc then CG(s) is
connected, [20, Theorem 2.11], and OsGF=OtGF. Hence OsGF∩TF=∅,
that is, the class intersects T.
2.6. Real classes
Assume w0=−id and let s, Tw, w˙ and g as in Subsection 2.2. Then w0∈CW(wθ)
so there exists
a representative w˙0 of w0 in NG(T) such that gw˙0g−1∈NGF(Tw). Then
[TABLE]
2.7. Non-central elements in the torus
We need the following fact on algebraic groups.
Assume G=Gsc.
We recall that, for t∈T−Z(G), there always exists α∈Δ such that sα(t)=t. Indeed, suppose that sα(t)=t for every α∈Δ.
Then w(t)=t for every w∈W.
By [20, §2.2], W is then the Weyl group of the reductive group
CG(t)=⟨T,Uα∣α(t)=1⟩.
Now the Dynkin diagram of CG(t) can be read off from the Coxeter graph of W, except when G is
of type Bℓ or Cℓ.
This forces CG(t)=G (because the two groups have the same Dynkin diagram,
or by comparison of the dimensions), a contradiction as t is not central.
Such an α also satisfies α(t)=1.
Indeed, t commutes with Uα if and only if α(t)=1 if and only if t commutes
with U−α. In addition,
sα(t)=s˙α▹t for any representative s˙α of sα in NG(T).
Since there is a representative of sα lying in UαU−αUα [24, 8.1.4],
we get a contradiction and whence the claim follows.
2.8. Racks
We recall the notion of rack and some
definitions that will be needed later. In the present paper all racks are (unions of) conjugacy classes.
See [4] for details and more information.
A rack is a set X=∅ with a self-distributive
operation ▹:X×X→X such that x▹ is
bijective for every x∈X. The standard example is the conjugacy class OzM
of an element z in a group M with the operation x▹y=xyx−1,
for x,y∈OzM.
A subrack of a rack X is a non-empty subset Y such that x▹y∈Y for all x,y∈Y.
A rack X is abelian if x▹y=y, for all x,y∈X.
In [6, 2, 4] the notions of racks of type D, F and C were introduced.
Since we will deal with subracks of conjugacy classes,
we recall the translation of these notions in this case.
Definition 2.1**.**
A conjugacy class O in a finite group M is of type
C
if there exist H≤M and r,s∈O∩H
such that
(a)
rs=sr,
2. (b)
OrH=OsH,
3. (c)
H=⟨OrH,OsH⟩,
4. (d)
either min(∣OrH∣,∣OsH∣)>2 or max(∣OrH∣,∣OsH∣)>4;
2. D
if there exists r,s∈O such that
(a)
(rs)2=(sr)2,
2. (b)
Or⟨r,s⟩=Os⟨r,s⟩;
3. F
if there exists ri∈O, for i∈I4 such that
(a)
rirj=rjri, for i=j,
2. (b)
Ori⟨ri,i∈I4⟩=Orj⟨ri,i∈I4⟩, for i=j.
A rack is kthulhu if it is neither of type C, D nor F.
Remark 2.2*.*
The properties of type C, D, F are well-behaved with respect to projections and inclusions, [6, Section 3.2], [2, Remark 2.9 (a)],[4, Lemma 2.10].
In other words, if a rack X has either a quotient or a subrack which is not kthulhu, then X is not kthulhu.
The main motivation for seeking conjugacy classes that are not kthulhu stems from the classification of finite-dimensional Nichols algebras.
Theorem 2.3**.**
[6, Theorem 3.6]**,
[2, Theorem 2.8], [4, Theorem 2.9].
A conjugacy class O of type D, F or C collapses. ∎
Remark 2.4*.*
Let M be a finite group whose order is divisible by p.
Let y,z∈M and
write y=ysyu and z=zszu as
products of their p-regular and p-parts. Then ⟨y,z⟩=⟨ys,yu,zs,zu⟩ and if
yszu=zuys or yszs=zsys then
yz=zy. In particular, if M is a finite group of Lie type, then
⟨y,z⟩ is generated by the semisimple and unipotent parts of y and z and non-commutation of
y and z can be checked on their semisimple or unipotent parts.
The next lemma is instrumental to detect classes of type C in finite groups.
Lemma 2.5**.**
Let M be a finite group whose order is divisible by p.
Let y,z∈M and write y=ysyu and z=zszu as
products of their p-regular and p-parts.
If
[TABLE]
then yz=zy, ∣Oy⟨y,z⟩∣≥3 and
∣Oz⟨y,z⟩∣≥3.
If in addition y and z are conjugate in M
and Oy⟨y,z⟩∩Oz⟨y,z⟩=∅, then OyM
is of type C.
Proof.
By Remark 2.4 any of the inequalities in (2.4) implies that
yz=zy. Moreover, Oy⟨y,z⟩ contains
the orbits ⟨zs⟩▹y
and ⟨zu⟩▹y.
Since by (2.4) we know that zu and zs are nontrivial,
one of these two elements has odd order bigger than 1. This implies that
∣Oy⟨y,z⟩∣≥3. The inequality ∣Oz⟨y,z⟩∣≥3
follows by symmetry. The last assertion follows by taking the subgroup H=⟨y,z⟩.
∎
2.9. Known results on unipotent classes
In this paper we analyze conjugacy classes that are neither semisimple nor
unipotent in finite simple groups of Lie type (mixed classes), in order to determine when such a class is non-kthulhu.
By Remark 2.2, it is enough to find subracks or
quotients which are not kthulhu.
With this aim, we will first look for non-kthulhu subracks that are isomorphic to unipotent classes in
simple groups, relying on the results in [2, 3, 4, 5]
on unipotent conjugacy classes. These are summarized in the following theorem.
Theorem 2.6**.**
Let G=GscF/Z(GscF) be a Chevalley or a Steinberg group and let O={e} be a
unipotent conjugacy class in G, not listed in Table 1. Then O is not kthulhu.
∎
Remark 2.7*.*
We list some properties of the unipotent classes from Table 1, see
[2, 3, 5].
(1)
For every group in Table 1 there are at most two unipotent conjugacy classes
labeled as in the second column of the table and they are isomorphic as racks. There is only one class labeled by (3) in PSL3(2).
Also, there is only one class labeled by (2) in PSL2(q) for q even.
2. (2)
Assume O is a class different from the one labeled by (3) in PSL3(2). Then
O is represented by an element in Uβ where β is either the highest root in
Φ+ or the highest short root in Φ+, so F(Uβ)=Uβ.
If there are two such classes, then one of these is represented by xβ(1).
3. (3)
All classes in Table 1 are Frp-stable. Indeed, Frp being an automorphism of
G, stabilizes the set of kthulhu classes and preserves the label and the order of the elements.
If there are two classes with the same label, the one represented by xβ(1) is clearly Frp-stable,
therefore Frp must stabilize the second one, too.
4. (4)
Let q be even. When n=2, the non-standard graph automorphism interchanging long and
short roots in PSp4(q) maps the class labeled by W(2) to the one labeled by W(1)⊕V(2). For any n≥2,
there is only one class labeled by W(1)n−1⊕V(2) in PSp2n(q).
5. (5)
There is only one class labeled by (2,1n−2) in PSUn(q) for q even.
Indeed, let u∈SUn(q) have label (2,1n−2). Then u is conjugate in GUn(q) to
xβ(1). Since every element in GUn(q) is the product of a diagonal matrix d fixed by F and a matrix in SUn(q),
u is conjugate in SUn(q) to an element in UβF. A direct computation shows that UβF=UβFrq
and that all nontrivial elements in UβFrq are conjugate to xβ(1) by a matrix in SUn(q) of the form
diag(η,1…,1,η−1) for η∈Fq×.
6. (6)
Some of the groups occurring in the table are not simple. We need to consider them to implement an induction procedure.
We also recall, for the purpose of application of Theorem 2.6, that unipotent conjugacy classes in a simple group of Lie
type G=GscF/Z(GscF) are isomorphic as racks to the corresponding unipotent conjugacy class
in GF for any G isogenous to Gsc.
2.10. Results on products of racks
Another approach for detecting non-kthulhu conjugacy classes
is to find subracks isomorphic to
a product of conjugacy classes in a smaller group and apply results from [2, 3].
With this in mind, we will make use of the following Lemma.
Lemma 2.8**.**
[2, Lemma 2.10]**
Let O be a conjugacy class in a finite group M containing a subrack
of the form X1×X2 such that
[TABLE]
Then O is of type D.∎
In order to apply Lemma 2.8, we determine which unipotent conjugacy classes
satisfy (2.5) or (2.6).
Lemma 2.9**.**
If X1 is a conjugacy class occurring in Table 1, then it satisfies (2.5). If X2 is a
class occurring in Table 1 but not in
Table 2, then it satisfies
(2.6). In particular, if O is a conjugacy class of a finite group M containing a
subrack isomorphic to a product of unipotent conjugacy
classes in Chevalley or Steinberg groups, not both listed in
Table 2, then O is not kthulhu.
Proof.
Let O be the class in PSUn(q) occurring in Table 1.
For all conjugacy classes occurring in Table 1 different from O,
conditions (2.5) and (2.6) are proved in [5, Lemma 3.5].
Assume X1=O. We set x1=idn+e1,n, σ:=e1,n+en,1+∑i=1,nei,i, x2:=σ▹x1
and (2.5) holds. We now prove (2.6) for X2=O and (n,q)=(3,2). Let ζ be a generator of Fq2×.
If n=3 and q>2 we take
[TABLE]
If n>3, we take
σ:=e1,2+e2,1+en−1,n+en,n−1+∑i∈I3,n−2ei,i, y1=idn+e1,n and y2:=σ▹y1. This settles the first statement.
Let now X=X1×X2⊂O with Xi for i=1,2 isomorphic to a product of unipotent classes in Chevalley or Steinberg groups. If X1 or X2 is not in
Table 1, then X is not kthulhu. If X1 nd X2 are in Table 1 and X2 is not in
Table 2, then the statement follows from the preceding and Lemma 2.8.
∎
Lemma 2.10**.**
Let O=O′⊂GF be unipotent conjugacy classes in
Table 1 corresponding to the same label. If q=3, then there exist x1∈O, x2∈O′
such that (x1x2)2=(x2x1)2. If q=3, then there exist x1∈O, x2∈O′ such that x1x2=x2x1.
Proof.
By Remark 2.7 (1) and (5) the classes O
and O′ occur either in PSL2(q) or in PSp2n(q). By Remark 2.7 (2)
we may assume xβ(1)∈O for β the highest root or the highest short root in Φ+ and y1∈O′∩UβF.
Let s˙β be a representative of sβ in NGF(T) and let s˙β▹y1=x−β(ξ)∈O′∩U−βF.
A computation in ⟨Uβ,U−β⟩ shows that
xβ(1)x−β(ξ)=x−β(ξ)xβ(1) always and that
(xβ(1)x−β(ξ))2=(x−β(ξ)xβ(1))2 if and only if ξ(2+ξ)=0.
A direct verification in SL2(q) and Sp2n(q) shows that if q=3, then s˙β can always be chosen in such a way that
ξ satisfies the latter condition. We take x1=xβ(1) and x2=s˙β▹y1.∎
Remark 2.11*.*
The inequalities in Lemmata 2.9 and 2.10 can be written as inequalities between unipotent elements.
Since the restriction of an isogeny to unipotent elements is an isomorphism, such inequalities hold independently of the isogeny type of G.
3. Mixed classes
In this Section we introduce some reduction techniques in order to deal with mixed classes.
From now on G=Gsc is simply-connected and G=PSLn(q), since
these last groups have been treated in [2].
Let x∈G and let x∈GF such that π(x)=x, with Chevalley-Jordan decomposition x=xsxu.
Then x has Chevalley-Jordan decomposition x=xsxu with xs=π(xs), xu=π(xu).
We assume that OxG is mixed, that is xs,xu=1.
By construction xu belongs to K:=CG(xs)∩GF, thus xu∈K:=π(K).
We recall the morphisms of racks from [2, Lemma 1.2]
[TABLE]
where the isomorphism follows from injectivity of the restriction of the isogeny
G→G/Z(G) to unipotent elements.
This motivates the quest for classes OxGF such that OxuK is
not kthulhu and a better understanding of the group K. For the latter we will use [10].
3.1. Classes in centralisers of semisimple elements
By the discussion in Subsection 2.4, we may assume that
xs=gtg−1 for some t∈T, and some g∈G such that
g−1F(g)=w˙∈NGFrq(T). Let H:=CG(t). By [20, 2.2],
H is connected and reductive, so H=Z(H)∘[H,H], it is given by
[TABLE]
and FrqH=CG(tq)=H. Since Φt:={α∈Φ∣α(t)=1} is
W-conjugate to a root system with base a subset of
Δ, [23, Proposition 30],
up to replacing t by σ˙▹t, g by gσ˙−1 and w˙ by σ˙w˙F(σ˙−1) for σ˙ a
suitable element in NG(T), we may always assume that Φt has a base Π contained in Δ.
The subset Π is unique up to W-action.
If Ad(w˙)−1(t)=F(t), then Ad(hw˙)−1(t)=F(t) for every h∈H,
so w˙ could be replaced by σ˙w˙∈GFrq for any σ˙∈NH(T) and w could be replaced by
σw, for σ∈NH(T)/T=WΠ, the group generated by the reflections with respect to roots in Π.
Let Fw:=Ad(w˙)∘F. Then H is Fw-stable and
[TABLE]
[3, Remark 2.5(c)].
By uniqueness of the Chevalley-Jordan decomposition, xu lies in
(g[H,H]g−1)F=g[H,H]Fwg−1 .
For the rest of the paper, we assume that
x=xsxu=gtvg−1 with t∈T, v∈[H,H]Fw and
xs=gtg−1, xu=gvg−1.
This leads us to the following statement.
Lemma 3.1**.**
With notation as above,
if Ov[H,H]Fw is not kthulhu, then OxG is again so.
Proof.
This follows from (3.1) and the inclusion g▹Ov[H,H]Fw⊂OxuK.
∎
We explore now several conditions ensuring that the hypothesis of
Lemma 3.1 is satisfied.
In order to do so, we describe the structure of the Fw-stable and Frq-stable,
hence Ad(w˙)ϑ-stable,
semisimple group [H,H]. There exist uniquely determined
Frq-stable simple algebraic subgroups Gj≤[H,H] for j∈Ir
satisfying:
[TABLE]
We will denote by Φti the root system of Gi with base Δi⊆Δ.
The automorphism Ad(w˙)ϑ permutes the factors Gi and the systems Φti,
inducing a permutation of the indices i∈Ir
which we denote by ω.
By suitably rearranging the indices, we may assume that ω is a product of l disjoint cycles of the form
cj=(ij+1,…,ij+aj) with ∑jaj=r and ij=∑b=1j−1ab,
so ω is completely determined by the
aj, j∈Il. Let Cj:={ij+1,…,ij+aj} and Hj:=∏l∈CjGl.
Then each Hj is
semisimple and Fw-stable, since it is Frq-stable and
Ad(w˙)ϑ-stable. As a consequence of (3.2) we have:
[TABLE]
The element v decomposes accordingly as v=∏j=1lvj with vj∈Hj unipotent. The equation
[TABLE]
implies that
vjFw(vj)−1=zj∈Z([H,H]). Hence, vj=zjFw(vj) with vj, Fw(vj)
unipotent, forcing zj=1 for every j∈Il.
Thus, v∈∏j=1lHjFw.
We analyse now the structure of HjFw, for j∈Il.
For simplicity, we assume for the moment that l=1, so v=v1. We set a:=a1.
Let uk be the (unipotent) component of v in Gk. Since v is Fw-invariant, we have
In other words, v lies in the subgroup G1 of H1 consisting of elements whose components satisfy (3.4).
Projection onto the first component induces an isomorphism G1≃G1Fwa.
Since, by construction, Frq(w˙)=w˙, we have
[TABLE]
where (Ad(w˙)ϑ)a is an automorphism of the simple algebraic group G1 and Fwa
is a Steinberg endomorphism of G1.
The corresponding finite simple group will be Chevalley or Steinberg
according to whether (Ad(w˙)ϑ)a is an inner automorphism of G1 or not [26, 10.9].
If l>1, a similar analysis shows that v∈∏j=1lGj where Gj≃Gij+1Fwaj.
Thus, the rack Ov[H,H]Fw
contains the subrack Ov∏jGj which is isomorphic to ∏jOvjGj.
Each component is a unipotent conjugacy class among those studied in [2, 3, 4, 5].
By abuse of notation we will identify Gj and Gij+1Fwaj and vj
with its component in Gij+1Fwaj.
Let Jv:={j∈Il∣vj=1}.
Lemma 3.2**.**
Assume that one of the following conditions holds for OxG:
(1)
For some j∈Jv, the class OvjGj is not in Table 1,
2. (2)
∣Jv∣≥2* and for some j∈Jv, OvjGj
is not in Table 2.*
Then OxG is not kthulhu.
Proof.
(1) The rack OxuK contains OvjGj which is not kthulhu.
(2) The rack OxuK contains a subrack satisfying
the hypothesis of Lemma 2.9.
∎
3.2. Subracks obtained by the action of the Weyl group
From now on we assume that we are in the following situation: either
[TABLE]
The latter case occurs only when qaj∈{2,3} for every j∈Jv,
whence ω(j)=j for every j∈Jv.
Observe that if (wθ)aj(Φtj∩Φ+)=Φtj∩Φ+
for some j∈Jv, then we may always assume vj∈U. In particular, if q=2 and wθ acts trivially on Φtj,
then by Remark 2.7 we may take vj∈UβF for β the highest root or the highest short root in Φtj.
Remark 3.3*.*
In order to deal with mixed classes satisfying (3.5) or (3.6), we need to look at subracks of OxGF
that are different from those in Lemma 3.2.
Since for every Fw-stable subgroup M of G, we have
(gMg−1)F=gMFwg−1, we have the rack isomorphism
[TABLE]
and we will mainly perform calculations in GFw.
We will often make use of the fact that any
σ in the centraliser CW(wθ) has a representative in NG(T)∩GFw,
[21, Proposition 25.3]. In addition Z(GF)=Z(GFw)
so the isomorphism of racks (3.7) is compatible with the isogeny Gsc→Gad.
Lemma 3.4**.**
Assume that there exists σ∈W such that:
(1)
σ∈CW(wθ);
2. (2)
σ(Hj)=Hj* for some j∈Jv;*
3. (3)
σ(t)∈Z(GF)t.
Then OxG is not kthulhu.
Proof.
Observe that the subgroup σHj is well-defined because Hj is normalized by T. Let σ˙∈NG(T)∩GFw be a
representative of σ. Let
[TABLE]
Condition (3) ensures that X∩Y=∅ and that
the restriction of π to X∐Y is injective.
By Condition (1), σ(t) commutes with σ(Hj)=Hj, whence with Gj. In addition,
Hj commutes with all Hi and σ(Hi) for i=j, hence it commutes with the subgroup they generate.
Thus, in order to verify the non-commutation of elements in X and
Y it is enough to look at the components in OvjGj and Oσ˙▹vjGj.
For this reason we assume for simplicity that Jv={1}, so v=vj=v1. Notice that σ˙▹v∈G1 has the same label as v.
(a)
Assume q even. Since v and σ˙▹v have the same label, σ˙▹v∈OvG1 by Remark 2.7.
By Lemma 2.9 applied to OvG1,
there exist x1,x2∈OvG1 such that
(x1x2)2=(x2x1)2. Then, for r:=tx1∈X and s:=σ(t)x2∈Y
we have Or⟨r,s⟩⊆X, Os⟨r,s⟩⊆Y and (rs)2=(sr)2.
This shows that OxGF is of type D.
2. (b)
Assume q odd. Either by Lemma 2.9 or by Lemma 2.10, there exists v′∈Oσ˙▹vG1 such that vv′=v′v.
Let
[TABLE]
By construction, t,σ(t)∈Z(H), rs=sr, OrH⊂X, OsH⊂Y, so
OrH∩OsH=∅. Also,
H≤⟨OrH,OsH⟩≤H.
Finally, v and v′ are p-elements, so v,v′▹v and (v′)2▹v are all distinct, hence
[TABLE]
and similarly for OsH.
Since OxG contains the subrack π(X⨿Y)≃X⨿Y, from the discussion
above it follows that OxG is of type D or C.
∎
Remark 3.5*.*
Conditions (1) and (2) from
Lemma 3.4 are verified in the following situations:
(a)
θ=id or θ=−w0 and σ=wθ−1. Here σ(t)=t±q.
2. (b)
w0=−1 and σ=w0. Here σ(t)=t−1.
In the above situations, CG(σ(t))=H, so (2) holds for any j∈Jv.
Lemma 3.6**.**
Assume that one of the following conditions holds
(1)
G* is Chevalley and tq∈Z(GF)t.*
2. (2)
G* is Steinberg with θ=−w0 and t−q∈Z(GF)t.*
3. (3)
w0=−1* and t2∈Z(GF).*
Then O is not kthulhu.
Proof.
It is a direct consequence of Lemma 3.4 and Remark 3.5 because wθ−1(t)=tq
when θ=id and wθ−1(t)=t−q when θ=−w0.
∎
The following remark will be useful to locate the cases in which the hypotheses of Lemma 3.4 or,
more specifically, 3.6 do not hold.
Remark 3.7*.*
Let τ∈W and s=∏j∈Iℓαj∨(ξj)∈T. We set
[TABLE]
We recall that I(τ) does not depend on the chosen reduced decomposition and that the coefficients ξj are uniquely determined.
(1)
For τ and s as above, τ(s)∈s∏i∈I(τ)αi∨(k).
2. (2)
If for some σ∈W, z∈Z(GF) and t∈T we have σ(t)=zt then I(z)⊆I(σ).
3. (3)
In the special case in which θ=id or θ=−w0, z∈Z(GscF)−1 and
t∈TFw satisfy wθ−1(t)=zt, we necessarily have I(z)⊆I(wθ).
Proposition 3.8**.**
Assume q is even and Φ is of type
A1, Bn, Cn, D2m, E7, E8, F4 or G2. Then OxG is not kthulhu.
Proof.
In this case w0=−1 and ordt is odd. By Lemma 3.6 the statement could fail only if t2∈Z(GF),
but this would force t∈Z(GF) contradicting our assumption on xs.
∎
We end this Subsection
with a lemma
that will be useful to discuss some of the cases not covered by Lemmata 3.2, 3.6 or Proposition 3.8,
both in Chevalley and Steinberg groups.
Lemma 3.9**.**
Let {βi,i∈I3}⊂Φ be the base of a root subsystem of type A3 such that
(1)
{β1,β3}⊂Φt* and {β1,β3} is wθ-stable;*
2. (2)
Uβ2* is Fw-stable and β2∈Φt;*
3. (3)
v∈((Uβ1−1)Uβ3)Fw.
Then OxG is of type C.
Proof.
Let U=⟨Uβi,i∈I3⟩
and B=TU. Then U and B are Fw-stable
as well as Frq-stable.
Let r:=tv=txβ1(ξ)xβ3(ξ′)∈tU
for ξ∈k×, ξ′∈k.
Since wθ(β2)=β2 we have wθsβ2=sβ2wθ
so we may find a representative s˙β2 of sβ2 in GFw∩NG(T).
We set: t′=s˙β2▹t, v′:=s˙β2▹v=xβ1+β2(ζ)xβ2+β3(ζ′) for some ζ∈k× and ζ′∈k, and
s:=s˙β2▹r=t′v′∈t′U. Since ⟨r,s⟩⊂B, then
Or⟨r,s⟩⊂tU and
Os⟨r,s⟩⊂t′U.
In addition, since sβ2(β1)∈/Φt by (2),
it follows that CG(t′)=H so t′∈Z(G)t.
Therefore, π(Or⟨r,s⟩)∩π(Os⟨r,s⟩)=∅.
Since (β1+β2)(π(t))=(β1+β2)(t)=1 and
β1(π(t′))=β1(t′)=1, by (2.1) the inequalities (2.4)
in Lemma 2.5 hold for y=π(r) and z=π(s).
Hence, π(OrGF) is of type C.
∎
4. Mixed classes in Chevalley groups
In this Section, F=Frq and Φ is not of type An.
We keep the notation introduced in
Section 3.
By Lemma 3.6 and Proposition 3.8 it remains to deal with the cases
xs2∈Z(GF) if w0=−1 and q is odd, and
xsq−1∈Z(GF) if w0=−1. In the latter situation q>2 because
xs∈Z(GF). In other words, we have to deal with the following cases:
(1)
Φ of type Bℓ, ℓ≥3; Cℓ, ℓ≥2; D2n, n≥2;
E7; E8; F4; G2; q is odd and xs2∈Z(GF) (every z∈Z(GF) has order ≤2)
[21, Table 24.2];
2. (2)
Φ of type D2n+1, n≥2; E6 and xsq−1∈Z(GF) (here ∣Z(GF)∣≤4);
We recall from Subsection 2.5 that
if xsq−1=1, then t∈TF and we may assume xs=t∈TF.
We now deal with this situation.
Lemma 4.1**.**
Let xs∈TF−Z(GF).
By Subsection 2.7 there always exists α∈Δ such that
sα(xs)=xs. Assume that we are not in the situation:
[TABLE]
Then the root α can be chosen so that
sα(xs)∈xsZ(GF).
Proof.
The statement follows when G is of type E8,F4,G2,
because Z(G)=Z(GF) is trivial in these cases. In the general case, assume that
sα(xs)=⋆zxs for some z∈Z(GF)−1.
Applying sα, we get z2=1. Thus G is not of type E6
(here Z(G)≃Z/3) and q should be odd. By ⋆, we have
[TABLE]
Say α=αj, j∈Iℓ. If i=j then sα(ωi)=ωi, hence
ωi(z)=1. Now such z exists only if we are in (4.1), see
the description of Z(GF) in Table 3.
∎
Lemma 4.2**.**
Let xs∈TF−Z(GF), let α∈Δ be as in Subsection
2.7, and let P be the minimal standard F-stable parabolic subgroup with standard
Levi complement L associated with α. Let L=LF. Then OxsL is of type C.
Proof.
Let X1=xsUαF and X2=sα(xs)UαF.
Then X1=UαF▹xs=UαFxs and
X2=UαF▹sα(xs)=UαFsα(xs), using (2.1) and
α(sα(xs))=1. Hence, Xi▹Xj=Xj for i,j∈I2.
Set Y=X1∪X2.
Note that ⟨Y⟩=⟨xs,sα(xs),UαF⟩⊆L.
Then X1∩X2=∅, xs∈X1=Oxs⟨Y⟩,
sα(xs)∈X2=Osα(xs)⟨Y⟩ and
∣X1∣=∣X2∣=q>2. Taking
r=xs and s=sα(xs)xα(1), we conclude that Y is of type C.
∎
Lemma 4.3**.**
If xs∈TF−Z(GF) and
we are not in the situation (4.1), then OxG is not kthulhu.
Proof.
In this case we take g,w˙=1, so Hi=Gi for all i∈Ir
(cf. Subsections 2.4, 3.1).
Recall that v satisfies either (3.5) or (3.6).
Since w˙=1, the class in PSUn(q) does not occur
because PSUn(q) does not occur in the decomposition of [H,H]F, see Subsection 3.1.
Also, we may assume that q>2, as the classes in groups over F2 occur only for
xs=1
Thus, each component in v=xu can be chosen to lie in a
UβF for some β∈Φ+ such that β(xs)=1.
By the hypothesis on xs, there is α∈Δ as in
Lemma 4.1. Let P be the standard F-stable parabolic subgroup with
standard Levi complement L associated with α, and let P=PF, L=LF.
Then for πL:P→L we have that πL(OxsxuP)=OxsL is of type C by
Lemma 4.2.
Let Y as in the proof of Lemma 4.2 and let
[TABLE]
Let π:GF→G be the isogeny and let a=b∈Y′ such that π(a)=π(b),
i.e. there is z∈Z(GF), z=1, such
a=zb. Hence either a=xsu and b=sα(xs)v for some u,v∈UF, or vice versa.
In any case, xs=zsα(xs), impossible by our choice of α.
Hence, the restriction of π to Y′ is injective and OxG is of type C.∎
In the next lemma we deal with the case in which xs∈TF−Z(GF) is as in (4.1).
Then xs has the form
[TABLE]
Notice that if ℓ is odd, then such an xs belongs to GF if and only if q≡1(4).
We shall also need a realization of the symplectic group Sp2n(k) for q odd. We choose it to be the subgroup of GL2n(k)
consisting of matrices preserving the skew-symmetric bilinear form with associated matrix
[TABLE]
When clear from the context, we shall omit the index n from Jn and J2n.
Lemma 4.4**.**
Assume Φ is of type Bℓ and q is odd.
Let x=xsxu with xu=1 and xs is as in (4.1). Then OxG is not kthulhu.
Proof.
Here H=CG(xs)=CG(t) is simple with Φt of type
Dℓ. As ℓ>2 is not compatible with (3.5) nor (3.6), we have
ℓ=2, G≃Sp4(k) and H≃SL2(k)×SL2(k) is semisimple.
Our assumptions on xu=v give either:
(1)
q=9 or not a square and only one component of
xu in SL2(k)×SL2(k) is non-trivial; or else
2. (2)
q=3 and the two components of xu in SL2(k)×SL2(k) are non-trivial.
To deal with (1), we work in GF=Sp4(9) for simplicity. In this case,
BF is the subgroup of Sp4(9) consisting of upper triangular matrices. Let π:GF→G.
We take
[TABLE]
Let
[TABLE]
A direct computation shows that (π(r)π(s))2=(π(s)π(r))2. Also,
r,s∈BF=TFUF and, for V=⟨UβF∣β∈Φ+−α2⟩
by Chevalley’s commutator formula we have
BF▹r∈TFV whereas BF▹s∈TFxα2(F9×)V.
Hence, Oπ(r)⟨π(r),π(s)⟩=Oπ(s)⟨π(r),π(s)⟩
and OxG is of type D.
There are 2 classes in case (2), namely the classes represented by
[TABLE]
They lie in the same orbit for the conjugation action of the group of diagonal matrices diag(ξ,η,λξ−1,λη−1),
for ξ,η∈F9×, λ∈F3× on Sp4(q). Hence Ox1≃Ox2. Let r:=x1.
With notation as in (1), let
[TABLE]
Again, (π(r)π(s))2=(π(s)π(r))2. Also, r,s∈BF and
BF▹r∈TFxα2(2)V whereas BF▹s∈TFxα2(1)V. Hence,
Oπ(r)⟨π(r),π(s)⟩=Oπ(s)⟨π(r),π(s)⟩ so this class is of type D.
∎
Proposition 4.5**.**
Assume Φ and q fall into one of the following cases:
(1)
E8, F4, G2, q arbitrary;
2. (2)
E6* and
q≡1(3);*
3. (3)
D2m+1* and q is even.*
Then OxG is not kthulhu.
Proof.
In these cases, we have that Z(GF)=1, see [21, Table 24.2]. Thus,
by Subsection 2.5, the condition
xsq−1∈Z(GF) reads xs∈TF. This is dealt with in Lemma 4.3.
∎
4.2. The remaining cases
According to the list at the beginning of Section 4,
we are left with the following cases:
Setting 4.6*.*
xsq−1=z∈Z(GF)−{1}; either (3.5) or (3.6) holds for v;
and Φ, q and xs satisfy:
(1)
Cℓ, ℓ≥2; xs2=z, so q≡3(4);
2. (2)
Bℓ, ℓ≥3; xs2=z, so q≡3(4);
3. (3)
D2n, n≥2; xs2=z, so q≡3(4);
4. (4)
E7; xs2=z, so q≡3(4);
5. (5)
D2n+1, n≥2, q is odd;
6. (6)
E6, q≡1(3).
Assume that we are in either of the situations (1),…,(4). By Table 3, we must have that
q≡3(4), since otherwise xsq−1=1. Analogously, q≡1(3) if Φ is of type E6.
In what follows, we provide several technical remarks and lemmata to deal with these cases.
Remark 4.7*.*
If Φtj is of type A1 with base Δj={αj1} and Ad(w˙)Gj=Gj,
then, by replacing w
by sαj1w, we can always ensure that w acts trivially on Φtj.
Observe that this replacement does not affect the action of w
on other subsets Δl, for l∈Jv−{j}.
Lemma 4.8**.**
Assume that (3.6) holds for v,
that Ad(w˙)−1(t)=tq=zt=t with z∈Z(GF), and that w acts trivially on Φti for all
i∈Jv.
If there exists α∈Δ such that:
(1)
sαw=wsα;
2. (2)
sα(β)∈Φt* for some β∈(Φti0)+
and some i0∈Jv with β=α0;
*
then OxG is of type C.
Proof.
Note that in this situation q=2. As ∣Jv∣>1, we necessarily have q=3
and Φti is of type A1 for all i∈Jv.
We set for simplicity i0=1.
Then v1∈H1=G1, G1=G1Frq, and since w acts trivially on Φt1
we may assume that v1=xβ(ξ) for some ξ∈Fq×.
Let Δ1⊂Δ be the base of Φt1; let Π=Δ1∪{α}; let P be the Fw-stable standard parabolic subgroup of G
associated with Π; V be its unipotent radical and L be the Fw-stable standard Levi subgroup.
Up to conjugation in HFw, we have that v=xβ(ξ)v′ for some v′∈V.
Let
[TABLE]
Condition (1)
and [21, Proposition 25.3] applied to Fw ensure that there exists a representative s˙α∈NG(T)∩GFw.
We set
[TABLE]
for some ζ∈k× and some v′′∈V, since s˙α∈L.
Condition (2)
ensures that α∈Φt so sαγ∈Φ+ for every γ∈Φt+.
Hence, ⟨r,s⟩⊂TU. Thus:
[TABLE]
Condition (2) also gives sαΦt=Φt whence s˙α∈NG(H).
In particular, s˙α∈H, so sα(t)=t and therefore
Or⟨r,s⟩∩Os⟨r,s⟩=∅.
Since s˙α∈NG(H), we have sα(t)∈Z(G)t.
Thus, the restriction of the isogeny
to Or⟨r,s⟩∐Os⟨r,s⟩
is injective and π(Or⟨r,s⟩)∩π(Os⟨r,s⟩)=∅.
As α(π(t))=α(t)=1 and
β(π(t′))=β(t′)=β(sα(t))=(sαβ)(t)=1,
by (2.1) the inequalities in
Lemma 2.5 hold for y=π(r) and z=π(s).
Hence, π(OrGF) is of type C, and consequently,
OxG is also of type C, by Remark 3.3.
∎
Remark 4.9*.*
If (3.5) holds for OxG,
Ad(w˙)−1(t)=tq=zt=t with z∈Z(GF), and w acts trivially on Φt1, then
q=2. By the discussion at the beginning of Subsection 3.2 we can always
make sure that
v=v1=xβ(ξ) for some β∈(Φt1)+ and ξ∈Fq×.
Lemma 4.10**.**
Assume Ad(w˙)−1(t)=tq=zt=t with z∈Z(GF),
v=v1=xβ(ξ)∈G1 for some β∈(Φt1)+ and ξ∈Fq×.
If there exists α∈Φ+ such that
sαw=wsα and
sα(β)∈Φ+−Φt,
then OxG is of type C.
Proof.
Similar to that of Lemma 4.8.
Since ∣Jv∣=1, the computations for r=txβ(ξ) and s=s˙α▹r
follow as before without introducing P and V.
The condition sα(β)∈Φ+−Φt ensures that s∈TU.
∎
We are now ready to state the main result of this Subsection.
Proposition 4.11**.**
Assume that we are in the Setting 4.6. Then OxG is not kthulhu.
We prove this proposition by analysing the different groups separately.
Lemma 4.12**.**
Assume that we are in Setting 4.6 with Φ of type Cℓ, so that G=Sp2ℓ(k), ℓ≥2 and q≡3(4).
Then OxG is not kthulhu.
Proof.
Here T is the subgroup of diagonal matrices of the form
[TABLE]
The assumption on xs gives xs2=−id so
[TABLE]
Since permuting eigenvalues compatibly with (4.5) gives a new element
in OtG and OtG∩GF=OxsGF,
we can reorder the eigenvalues and assume that t=diag(ξidℓ,−ξidℓ) for ξ2=−1.
The matrices in
H have a diagonal block form of shape diag(A,JtA−1J) for
A∈GLℓ(k), i.e., [H,H]≃SLℓ(k) is simple.
Since v=v1 occurs in Table 1, this is possible only if ℓ=2.
In this case t is conjugate to S=(0−1001000000100−10).
By a direct computation of unipotent matrices in CG(S) we see that
OxGF is represented by a matrix of this form.
[TABLE]
Assume first q=3,7. Let P be the standard F-stable parabolic subgroup with
standard Levi factor L associated with α1, and let P=π(PF),
L=π(LF), with πL:P→L the corresponding projection.
Then OxG contains the subrack OxP, which in turn projects onto
OπL(x)L. The latter is isomorphic as rack to OyPGL2(q), with
y the class of (0−110).
Since by [4, Theorem 1.1] this class is not kthulhu, the same holds
for OxG.
Assume now that q=3 or 7.
Let u:=(01001100bb01001−1) and s:=u▹r=(1200−1−100−2b−2b1−2001−1).
A direct computation shows that u∈GF and
(rs)2=(sr)2, since
(rs)2:=(5−300−3200−7b14b53b5b32) and (sr)2=(23003500b4b2−311b13b−35). Moreover, this inequality also holds in the projection to G as
(rs)2(sr)−2:=(100001002b2b10b2b01) if q=3 and
(rs)2(sr)−2:=(−10000−100−b4b−10−b−b0−1) if q=7.
In addition, if q=3 we have
[TABLE]
whereas if q=7 we have
[TABLE]
In both cases π(Or⟨r,s⟩)=π(Os⟨r,s⟩), whence
OxG is of type D.
∎
Lemma 4.13**.**
Assume that we are in Setting 4.6 with Φ of type Bℓ, ℓ≥3, so that q≡3(4). Then OxG is not kthulhu.
Proof.
Let π:G→Gad=SO2ℓ+1(k) be the natural projection.
We realize SO2ℓ+1(k) as the subgroup of SL2ℓ+1(k)
consisting of matrices preserving the symmetric bilinear form with
associated matrix J2ℓ+1 as in (4.4),
and π(T) to be the group of diagonal matrices of the form
[TABLE]
Since π(t)2=1, its eigenvalues are ±1.
Reordering eigenvalues (i.e., acting via the Weyl group) we assume
that π(t)=diag(−idk,id2ℓ−2k+1,−idk), i.e.,
[TABLE]
The condition t2∈Z(GF)−1 forces k to be odd.
If k≥3 the root system Φt is the union of two orthogonal subsystems,
with base Δ1={αi,i∈I0,k−1} of type Dk and
Δ2={αj,j∈Iℓ−k+1,ℓ} of type Bℓ−k, whereas if k=1,
Φt has base Δ2={αj,j∈I2,ℓ} of type Bℓ−1.
Let γ=α1+⋯+αℓ=ε1. A direct calculation
shows that we can take w˙=sγ.
Indeed, sγ(α1)=−α0 and sγ(t)=αℓ∨(−1)t. So from
Table 3, sγ(t)=zt=tq−1 as desired.
Observe that when k=3 we have D3=A3.
Then (3.6) holds with Jv={2} and ℓ−k∈{1,2}.
Remark 4.9 applies with β=αℓ if ℓ=k+1 and β=αℓ−1 if ℓ=k+2.
Lemma 4.8 applies with α=αℓ−1, or α=αℓ−2,
respectively with the exception of the case ℓ=3,k=1.
In this case, t=α1∨(−1)α2∨(−1)α3∨(ξ),
w(α1)=−α0, w(α2)=α2, w(α3)=α3,
Φt is
of type B2 and tv=α1∨(−1)α2∨(−1)α3∨(ξ)xα2(ζ) for
some ζ∈Fq×.
Let us set α1=β1, α2=β2 and β3=−α0.
This is a base for a root system of type A3. Let U=⟨Uβi,i∈I3⟩,
and let K=⟨U,w˙0(U)⟩ be the corresponding Fw-stable
algebraic subgroup of G. Let P be the Fw-stable standard parabolic subgroup of K
associated with {β2}, let L be the corresponding standard Levi subgroup and let V be
the unipotent radical. Thus
[TABLE]
By the discussion in Subsection 2.1 the element tv is conjugate in [H,H]Fw to an
element r of the form:
[TABLE]
Let y=xβ1(η)xβ3(η′)∈UFw, with ηη′=0. The existence of
such an element is guaranteed by [21, Proposition 23.8]. Let
s:=y▹tv.
Then
[TABLE]
lies in txβ2(ζ)V and its semisimple part equals y▹t=txβ1(−2η)xβ3(−2η′).
Thus, ⟨r,s⟩⊂⟨t,U⟩.
Since t commutes with Uβ2, we have the inclusions
Or⟨r,s⟩⊆tV
and Os⟨r,s⟩⊆txβ2(ζ)V.
As a consequence,
Or⟨r,s⟩∩Os⟨r,s⟩=∅.
Moreover, t does not commute with Uβ1, hence it does not commute with y▹t and so rs=sr by Remark 2.4.
To finish
the proof we estimate ∣Or⟨r,s⟩∣,∣Os⟨r,s⟩∣.
A direct computation shows that
[TABLE]
Therefore ∣π(Or⟨r,s⟩)∣>2, ∣π(Os⟨r,s⟩)∣>2,
so π(OrGF) is of type C.
By Remark 3.3 the class OxG is also of type C.
∎
Lemma 4.14**.**
Assume that we are in Setting 4.6 with Φ of type Dℓ, ℓ=2n≥4 so that q≡3(4). Then OxG is not kthulhu.
Proof.
Recall that tq−1=t2=z∈Z(GF)−1. By looking at
Table 3 we see that z can be either
z1=∏i odd αi∨(−1), or z2=αℓ−1∨(−1)αℓ∨(−1)
or z3=z1z2.
Let π:G→SO2ℓ(k) be the isogeny with kernel ⟨z2⟩.
We realize SO2ℓ(k) as the group of matrices in SL2ℓ(k) preserving the form J2l from
(4.4). Then the group π(T) is given by diagonal elements of shape (4.5).
Assume first that z=z1. Then π(t)2=−id2ℓ, so
[TABLE]
Up to reordering eigenvalues by acting with the Weyl group we see that π(t) has the form:
[TABLE]
In both cases CSO2ℓ(k)(π(t))∘=π(H) has semisimple part of type Aℓ.
This implies that [H,H] is simple so ∣Jv∣=1 but (3.5) cannot hold. The case z=z3 is dealt with in the same way.
Assume now that z=z2. Then π(t)2=id2ℓ, so
[TABLE]
Up to reordering eigenvalues by acting with the Weyl group we see that π(t) has the form:
[TABLE]
Then π(H)=CSO2ℓ(k)(π(t))∘ is semisimple with root system of type
Db×Dℓ−b, with the understanding that D1 is a torus, D2 is A1×A1
and D3=A3. If either (3.5) or (3.6) holds, then necessarily
b=2 and/or ℓ−b=2. Since these two cases are obtained from one another by multiplying π(t)
by −id2ℓ we focus on b=2. Up to a central element, t=α1∨(−1).
A direct calculation shows that we can take
w=sε1−εℓsε1+εℓ.
Let us first assume ℓ>4. Here, [H,H]=G1G2G3 with Δ1={α1},
Δ2={−α0}, Δ3={αi,i∈I3,ℓ}. Then H1=G1G2, H2=G3
and G1=H1Fw≃SL2(q2). Hence, v satisfies (3.5) and q=3.
If, instead, ℓ=4, then [H,H]=G1G2G3G4 with Δ1={α1},
Δ2={−α0}, Δ3={α3} and Δ4={α4}. Here,
H1=G1G2, H2=G3G4 and Gi=HiFw≃SL2(q2) for i=1,2.
So condition (3.5) holds and v has only a non-trivial component
in G1 or G2 and q=3. A diagram automorphism interchanges the roles of G1 and
G2, hence it is enough to look at v=v1∈G1 for ℓ≥4 and q=3.
We set α1=β1, α2=β2 and β3=−α0.
This is a base for a root system of type A3. Let U=⟨Uβi,i∈I3⟩
and B=TU. Then U and B are Fw-stable as well
as Frq-stable. Up to conjugation in [H,H]Fw we may assume that
r:=tv=β1∨(−1)xβ1(ξ)xβ3(ξ′)∈β1∨(−1)U
for ξ,ξ′∈Fq2×. In such a case the lemma follows,
since Lemma 3.9 applies.
∎
Lemma 4.15**.**
Assume that we are in Setting 4.6 with Φ of type E7 and q≡3(4). Then OxG is not kthulhu.
Proof.
Recall that xsq−1=xs2=z∈Z(GF)−1. By looking at Table 3 we see that t is necessarily of the form:
[TABLE]
for η a primitive fourth root of unity and ϵi∈{±1}.
Since E7 is simply-laced, the components of v
can only be non-trivial unipotent classes in PSL2(qai).
Also, by the discussion at the end of Subsection 2.4, we may take w=w0,
so the action of Ad(w˙) does not permute the simple factors Gi of H.
Hence, for every j∈Jv we have Φtj={±αij} and
Hj=⟨U±αij⟩. Assume αk∈Φt1.
For every possible choice of k∈I0,7 we will provide a σ∈W satisfying the
hypotheses of Lemma 3.4. Note that Condition (1) of Lemma 3.4 is always satisfied because
w0=−1 and θ=id.
The construction of σ relies on the fact that if αk∈Φt1,
then all roots in Δ that are adjacent to αk do not lie in
Φt. These conditions pose a series of constraints on some of the ϵj’s
ensuring that there exists βk∈Δ such that βk⊥αk and
βk∈Φt. The first property guarantees condition (2) in Lemma 3.4
for σ=sβk. The second property implies sβk(t)=t.
Condition (3) from Lemma 3.4 follows from Remark 3.7 (2) if βk∈Δ, whereas
if βk=−α0, it follows because the equation
sβk(t)=tα2∨(ϵ1)α5∨(ϵ1)α7∨(ϵ1) cannot be satisfied.
If k=0, then we have ϵ1=1, ϵ3=−1. Also, α3∈Φt⇔ϵ4=1⇔α2∈Φt. We take either β0=α2 or α3.
If k=1, then we have ϵ1=−1, ϵ3=ϵ4=1 so
α2∈Φt and we take β1=α2.
If k=2, then we have ϵ4=−1 and ϵ2ϵ3ϵ5=1.
Also, α5∈Φt⇔ϵ6=1⇔α7∈Φt.
We take either β2=α5 or α7.
If k=3, then ϵ1ϵ4=1, ϵ3=−1 and ϵ2ϵ5=−1.
Then α0∈Φt⇔ϵ4=1⇔α2∈Φt.
We take either β3=α2 or α0.
If k=4, then ϵ2ϵ3ϵ5=−1, ϵ1=−1,
ϵ4=ϵ6=1, so β4=α7∈Φt.
If k=5, then ϵ2ϵ3ϵ5=1, ϵ4ϵ6=−1,
ϵ5ϵ7=1.
Then α7∈Φt⇔ϵ4=1⇔α2∈Φt.
We take either β5=α2 or α7.
If k=6, then ϵ4=ϵ6=1 and ϵ5ϵ7=−1,
so β6=α2∈Φt.
If k=7, then ϵ6=−1 and ϵ5ϵ7=1.
Also, α5∈Φt⇔ϵ4=1⇔α2∈Φt.
We take either β7=α2 or α5.
∎
Lemma 4.16**.**
Assume that we are in Setting 4.6 with Φ of type Dℓ, ℓ=2n+1≥5 and q odd.
Then OxG is not kthulhu.
Proof.
Recall that tq−1=z∈Z(GF)−1. By looking at
Table 3 we see that z can be either
z1=(∏i≤ℓ−2 odd αi∨(−1))αℓ−1∨(ζ)αℓ∨(ζ3),
or z2=z12
or z3=z13 and the latter case is treated as the case z=z1.
Let us assume z=z1. This can occur only if q≡1(4).
We proceed as in the proof of Lemma 4.14, notation as therein. We have π(z1)=−id2ℓ, so
π(t)q−1=−id2ℓ, and the eigenvalues of π(t) do not lie in Fq.
Therefore, no eigenvalues of π(t) are equal to ±1.
By direct calculation this implies that there are no components of type D in [H,H].
Conditions on v and q imply that (3.5) holds and v=v1 must
live in a subgroup of type A1. Such factor occurs
when exactly two eigenvalues are repeated. Since
F(t)=zt is conjugate to t, it follows that π(t) is conjugate to −π(t). Hence
if ξ is an eigenvalue π(t), then
−ξ is again so, and ξ−1=−ξ, otherwise ξ=±ζ∈Fq. Up to reordering, we have
[TABLE]
where d is a diagonal matrix in SO2ℓ−8(k) and ξ=±1. Next we identify w.
We have w˙−1▹(π(t))=π(t)q=−π(t) for some w∈W, so w˙ acts on
the first 4×4-block as C=(0id2id20). This shows that w interchanges the simple factors
G1, G2 of type A1 in [H,H] and therefore the corresponding group G1
is isomorphic to SL2(q2). Since q≡1(4), condition (3.5) cannot be verified, concluding the case z=z1.
Let us assume z=z2=αℓ−1∨(−1)αℓ∨(−1)∈Ker(π).
In this case, π(t)q=π(t) so π(w˙)∈CSO2ℓ(π(t))−π(H) and
all eigenvalues of π(t) lie in Fq. We observe that 2k eigenvalues equal to ±1
give a component in CSO2ℓ(k)(π(t)) isomorphic to O2k(k),
whereas k repeated eigenvalues different from ±1 give a component of type GLk(k), embedded in SO2ℓ(k)
as the group of block diagonal matrices of the form diag(idc,A,id2c′,JktA−1Jk,idc), for c,c′≥0.
Therefore, CSO2ℓ(k)(π(t)) is the subgroup of matrices of determinant 1 in a group
isomorphic to O2a(k)×O2b(k)×∏j=1mGLaj(k) with a,b,aj≥0.
Since CSO2ℓ(k)(π(t)) is not connected, we necessarily have ab=0, i.e., we have 2a>0
eigenvalues equal to −1 and 2b>0
eigenvalues equal to 1.
Up to multiplication by z1 this gives
[TABLE]
and w=sε1−εℓsε1+εℓ.
Thus, w acts trivially on the root system generated by {αj,j∈I2,ℓ−2}.
If all components of v are in the groups of type A1 in [H,H], then each of them can be chosen to
be of the form xαj(ξ) for some j∈I3,ℓ−3. In this case, either Lemma 4.8
or 4.10 applies with β=αj and α=αj±1. Assume a component of v occurs in a factor
G1 of type Da. Then a=2 and it corresponds either to {−α0,α1} or to
{αℓ−1,αℓ}. Also, G1≃SL2(q2), so this is possible only if q=3 and v=v1.
In this case we apply Lemma 3.9 either to {−α0,α2,α1} or to
{αℓ−1,αℓ−2,αℓ}.
∎
Lemma 4.17**.**
Assume that we are in Setting 4.6 with Φ of type E6 and q≡1(3). Then OxG is not kthulhu.
Proof.
Since q≡1(3), the element v satisfies necessarily (3.5).
As Φ is simply laced, Ov1G1 is not a unipotent conjugacy class in PSp2k(qa).
Thus, Ov1G1 is either isomorphic to the rack labeled by (2) in PSL2(qa) with qa not a square
if q is odd, or the rack labeled by (2,1m−2) in PSUm(qa) and the latter occurs only if q is even.
Therefore, [H,H] must have a component Gi of type Ak and the action of Fwa on G1 should
be twisted if k>1.
Recall from Section 3.1 that to each xs∈GF we can associate a base Π⊂Δ
of the root system Φt of the connected centraliser H and a Weyl group element w such that w−1(t)=tq.
The element w is determined up to multiplication by elements in WΠ. Also, w∈NW(WΠ) because it stabilises Φt. The pair
(Π,[w]), where Π is a proper subset of Δ (up to W-action) and [w]=wWΠ ranges through the
set of representatives of the conjugacy classes in NW(WΠ)/WΠ is uniquely determined up to W-action.
In our situation, w˙∈H and w˙3∈H, since w˙−3(t)=z3t and z3=1 by Table 3.
Thus, w∈NW(WΠ)−WΠ and its class in NW(WΠ)/WΠ has order 3.
In addition, by Remark 3.7 (3) and Table 3 any reduced expression of w must contain the reflections s1,s3,s5 and s6.
The order of a class [w]∈NW(WΠ)/WΠ can be calculated by using the package CHEVIE of GAP3 [16, 22].
For those of order 3 we will make use of the list in [13] of all possible pairs (Π,[w]) up to conjugation in W and of the isomorphism classes of the
corresponding GiFw. The reader should be aware that the numbering of simple roots therein differs from ours. We look through the list considering
only the pairs (Π,w) for which Π is non-trivial, wWΠ=3, the condition from Remark 3.7 (3) is satisfied, and G1 corresponds either to SL2(qa) or SUm(qa).
The class wWΠ is given by means of a representative w∈W.
The following roots are used to describe w as a product of
reflections: numbering of these non-simple roots is conformal to [13] to simplify double-checking.
[TABLE]
We remain with the possibilities for (Π,w) listed in Table 4. Here, we know w and how it acts on each factor
of [H,H] and we proceed case-by-case.
Let Π={−α0} with w=s1s3s5s6 or Π={α4,α6,−α0} with w=sβ11sβ19sβ20sβ10.
Then Lemma 3.4 applies for σ=s1s3 or σ=s1.
Let Π={α1,α4,α6,−α0}, with w=sβ19sβ11sβ21sβ22. Here
w(α0)=α0, w(α1)=α6, w(α6)=α4 and w(α4)=α1, so v=v1 lies either in
⟨U±α0⟩ or in ⟨U±αj,j=1,4,6⟩.
In the former case, Lemma 3.4 applies with σ=sβ11sβ21. In the latter, the condition −α0∈Π
implies that tv∈K:=⟨U±αj,j=1,3,4,5,6⟩≃SL6(k) by [25, Corollary 5.4]. Also, w can be
represented by an element in NG(T)∩K, so KFw≃SL6(q), [26, 10.9]. The claim follows from the main result in [2].
∎
Proof of Proposition 4.11.
By Lemmata 4.12 up to 4.17.
∎
Putting together Lemmata 3.2, 3.6 and Propositions 3.8, 4.5, and
4.11 we have the main result of this Section.
Theorem 4.18**.**
Let G be a Chevalley group and x=xsxu∈G with xs,xu=1.
Then OxG is not kthulhu, and consequently OxG collapses.∎
5. Mixed classes in Steinberg groups
In this Section, θ=id. By Lemma 3.6 and Proposition 3.8 it remains to consider the following cases:
Setting 5.1*.*
xsq+1=z∈Z(GF); either (3.5) or (3.6) holds for v; Φ, q and xs satisfy:
(1)
Aℓ, ℓ≥2;
2. (2)
D2n+1, n≥2;
3. (3)
E6, q arbitrary;
4. (4)
D2n, n≥2, θ2=id, xs2∈Z(GF) and q is odd;
5. (5)
D4, θ3=id, xs2=1 and q is odd.
For the reader’s convenience the center Z(GF) is recalled in Table 5.
We begin with the groups for which w0=−1, i.e., cases (4) and (5).
Lemma 5.2**.**
Assume that we are in Setting 5.1, with Φ of type Dℓ=2n, θ2=id and q odd. Then O is not kthulhu.
Proof.
We proceed as in the proof of Lemma 4.14, from which we adopt notation.
Since q is odd, v has only components in type A1 and ∣Jv∣>1 only if q=3. By Lemma 3.6
we need to consider the two possibilities
t2=z2 or t2=1.
We consider π(t) as in (4.8). It is always an involution, its connected centralizer
π(H) has root system of type Db×Dℓ−b and [H,H] decomposes as in
Lemma 4.14. Here however, ϑ acts on T as sεℓ
and we need to describe w.
We observe that if b,ℓ−b>2, the unipotent part has no components in
Table 1, whereas if b=1 or ℓ=b+1 the component of type D1
is a torus and has no unipotent component. Hence b=2 and/or ℓ=b+2, so b is always even.
Up to W-action and multiplication by z2 we have
[TABLE]
so ϑ(t)=t and t2=1 necessarily. Therefore t∈TF and w=1, so GFw=GF.
The following cases may occur:
∙b=2 and ℓ>2+b. Then we have H1=G1=⟨U±α1⟩,
H2=G2=⟨U±α0⟩, H3=G3=⟨U±αj,j∈I3,ℓ⟩.
Then up to W-action, either Jv={1}, or else Jv={1,2} and q=3.
∙b>2 and ℓ=b+2. Then we have H1=G1=⟨U±αj,j∈Ib⟩,
G2=⟨U±αℓ−1⟩, G3=⟨U±αℓ⟩=ϑ(G2) so
H2=G2G3, and G2≃SL2(q2). Then Jv={2} and q=3.
∙b=2 and ℓ=4. Then we have H1=G1=⟨U±α1⟩,
H2=G2=⟨U±α0⟩, G3=⟨U±αℓ−1⟩,
G4=⟨U±αℓ⟩=ϑ(G3) and H3=G3G4 with
G3≃SL2(q2).
Then either Jv={1}, or Jv={3}, or Jv={1,2} with q=3.
Summarizing, we have either b=2 and v=xα1(ξ)x−α0(ζ) for ξ∈k×
and ζ∈k (with q=3 if ζ=0) or
ℓ=b+2 and v=xαℓ−1(ξ)xαℓ(η) (with ξ,η∈k× and q=3).
We set: β1=α1,β2=α2,β3=−α0 in the first case and
β1=αℓ−1, β2=αℓ−2, β3=αℓ in the second case.
The statement then follows from Lemma 3.9.
∎
Lemma 5.3**.**
Assume that we are in Setting 5.1 with Φ of type D4, θ3=id and q odd. Then O is not kthulhu.
Proof.
We proceed as in the proof of Lemma 5.2, from which we adopt notation.
We take ϑ to be a graph automorphism with associated θ given by
α1↦α3↦α4.
Here again q is odd, t2=1
and v has components only in type A1. Also, F(t) is conjugate to t.
These conditions imply that up to conjugation by an element in NG(T)
we have either
t=t1=α1∨(−1)α3∨(−1)α4∨(−1)∈GF, or
t=t2=α1∨(−1).
We have
F(t2)=ϑ(t2)=α3∨(−1)=sα2sα1+α2+α3(t2).
For both choices of t we have G1=⟨U±α1⟩, G2=⟨U±α3⟩,
G3=⟨U±α4⟩ and G4=⟨U±α0⟩.
If t=t1, then w=1, so H1=G1G2G3 and G1 is either SL2(q3) or
PSL2(q3), and H2=G4.
If t=t2, then w−1=sα2sα1+α2+α3 so
H1=G1, H2=G2G3G4 and G2 is either SL2(q3) or PSL2(q3).
Thus, ∣Jv∣=1 and v can be chosen of the form
xβ1(ξ1)xβ2(ξ2)xβ3(ξ3)
with β1,β2,β3∈{α0,α1,α3,α4}, ξ1∈k×, ξ2,ξ3∈k.
We deal with the case w=1, the other is similar.
We consider sα2∈WF and its representative s˙α2 in NGF(T).
Let r=tv and s:=s˙α2▹r=t′v′.
Since sα2(β1)∈/Φt,
it follows that CG(t′)=H so t′∈Z(G)t.
Therefore, π(Or⟨r,s⟩)∩π(Os⟨r,s⟩)=∅.
As α2(π(t))=α2(t)=1 and
β1(π(t′))=β1(t′)=β1(sα2(t))=(sα2β)(t)=1,
by (2.1) the inequalities in
Lemma 2.5 hold for y=π(r) and z=π(s).
Hence, π(OrGF) and OxG are of type C.
∎
In the remaining groups we always have θ=−w0, so
[TABLE]
Therefore, ww0∈NW(WΠ) and ww0∈WΠ if and only if z=1.
If this is the case, since σ=w0w−1∈WΠ, we may replace w by σw=w0, so CW(wθ)=CW(−id)=W.
Remark 5.4*.*
Assume that θ=−w0 and tq+1=1, w=w0.
(1)
Suppose in addition that for some irreducible component Δj of Π there exists a
simple root αj∈Π such that αj is orthogonal to Δj. If
j∈Jv, then σ=sαj satisfies the hypothesis of Lemma 3.4 by virtue of
Remark 3.7 (2) and Table 3.
2. (2)
If for any component Δj of Π there exists a simple root αj∈Π such that
αj is orthogonal to Δj, then the corresponding class is not kthulhu. Indeed, Lemma 3.4 applies by virtue of (1).
We consider now the Steinberg groups for Φ of type Aℓ. Here G=SLℓ+1(k) and F is realised as the map
(aij)↦Jt(aij)−qJ on any matrix of G, so GF=SUℓ+1(q) and G=PSUℓ+1(q).
Remark 5.5*.*
We shall not consider PSU3(2) because it has no mixed classes,
since every semisimple element in SU3(2) is either central or regular.
Lemma 5.6**.**
Let G=PSU3(q) with q>2.
Let λ∈Fq2 with λq+1=1, λ3=1 and let
[TABLE]
Then Oπ(x1)G is not kthulhu.
Proof.
If q is odd, then a slight modification of the proofs of [5, Lemma 5.3] shows that
Oπ(x1)G is of type D for q>3 and type C for q=3.
Let thus q be even >2. We show that in this case,
Oπ(x1)G is of type D.
Under these assumptions UF is the group of matrices of the form
(100ξ10ηξq1) for ξ,η∈Fq2 such that ηq+η=ξq+1. The inverse of such a matrix is (100ξ10ηqξq1). These elements have order 4 if ξ=0 and order 2 if ξ=0, η=0.
Since λq=λ−1 and λ3=1, it follows that
λ6=1 so λ3q=λ−3=λ3 and thus
λ3∈Fq. Let a∈Fq2× such that aq+1=1 and η∈Fq2 such that
η+ηq=1. We set r:=x1 and
[TABLE]
so s=tu and r=t(id+e13).
The (1,2) entry of (rs)2 equals (λ+λ−2)λ3(1+λ−6)
whereas the (1,2) entry of (sr)2 equals (λ+λ−2)(1+λ−6), hence (rs)2=(sr)2.
These products have same diagonal part, so π(rs)2=π(sr)2. Let H=⟨r,s⟩=⟨t,(id+e1,3),tu⟩=⟨t,(id+e1,3),u⟩.
Observe that u2 and (id+e1,3)∈Z(H) so the elements in OrH and OsH have same
diagonal part. Thus OrH=OsH implies π(OrH)=π(OsH). We verify the former. We have:
[TABLE]
Since t▹r=r we obtain
[TABLE]
Observe that for mi≥1
[TABLE]
for some f∈Fq2 such that f+fq=(∑iλ3mi)(1+λ−3)(∑iλ−3mi)(1+λ3) and
[TABLE]
Thus, if s∈OrH, then comparing (1,3)-entries we would have
[TABLE]
for some nonnegative integers mi, or, equivalently
[TABLE]
Our choice of a implies that the left hand side lies in Fq×, whereas the right hand side is a product of
(1+λ−3)∈Fq2∖Fq with an element in Fq. The latter cannot lie in Fq, unless it is zero, so this equality cannot hold.
∎
Lemma 5.7**.**
Let G=PSUℓ+1(q) for ℓ=3,4.
Assume tq+1=1 and that tv is conjugate in G to one of the following matrices, for
λ1,λ2∈Fq2× with λ1=λ2:
[TABLE]
Then OxG is of type D.
Proof.
Let x=x2, σ=diag(J2,J2)∈SU4(q), y=(10001100001000−11)∈SU4(q) and
[TABLE]
By looking at the (1,2) entry we see that (rs)2∈k(sr)2.
In addition,
[TABLE]
hence looking at the diagonal or at the (2,3)-entry we see that
π(Or⟨r,s⟩)=π(Or⟨r,s⟩), so OxG is of type D,
with a possible exception when λ1=−λ2 and λ1′=−λ2′=0 and q=3.
Assume this is the case, so λ12+λ1′2=0
and (λ1′)4=λ14=1.
For every choice of λ1 there are two possible choices of λ1′ but the corresponding elements are conjugate by
diag(ζ,ζ−1,ζ3,ζ−3) where ⟨ζ⟩=F9×.
In addition, the different choices of λ1 correspond to multiplication by a central element. Therefore it remains to consider
x2=(ζ20000ζ60001ζ60200ζ2). The element
y:=(0ζ500ζ70000ζ0ζ3ζ70ζ0) lies in Ox2GF because it has the same Jordan form as x2 and
(x2y)2(yx2)−2=(10000100ζ50100ζ301)∈Z(SU4(q)).
A computation with GAP shows that Ox2SU4(q)=OzySU4(q) for any z∈Z(SU4(q)), so OxG is of type D.
Let now x=x3, σ′=diag(J2,1,J2)∈SU5(q), z=(10000110000010000010000−11)∈SU5(q) and
[TABLE]
As in the previous case we see that (rs)2∈k(sr)2 and that
[TABLE]
Hence looking at the diagonal we conclude that π(Or⟨r,s⟩)=π(Or⟨r,s⟩) so OxG is of type D.
∎
Lemma 5.8**.**
Assume that we are in Setting 5.1 with Φ of type Aℓ, ℓ≥2
and xsq+1=1. Then OxG is not kthulhu.
Proof.
Observe that (5.1) gives w=w0 and CW(wθ)=W.
Also, Fw preserves each irreducible component of Φt mapping each root to its opposite, hence,
each Hi is simple. An eigenvalue of t of multiplicity k≥2 gives a component of type Ak−1 in Π.
If t has at least 3 different
eigenvalues, then Δ−Π≥3, so the statement follows from Remark 5.4.
Assume t has exactly two eigenvalues λ1,λ2 of multiplicity m1,m2. They satisfy λiq+1=1.
According to the parity of m1 and m2, and up to interchanging indices, t is conjugate in G to one of the following matrices:
[TABLE]
Then t1∈SUℓ+1(q) so we take xs=t1=t (and we replace for convenience w=w0 by w=id)
in this case, whereas t2∈GFw for the choice w=sa+b+1.
Let xs=t1. Then [CG(t1),CG(t1)] is given by matrices of block form
(A10A30B0A20A4) with Aj of size a×a for j∈I4 and B of size
m2×m2 and [CG(t1),CG(t1)]F≃SUm1(q)×SUm2(q). We take
xu=v∈id+ke1,m1+m2+kea+1,a+bid∈SUm1+m2(q). All cases can be reduced to computations
in orbits represented by elements with shape xj, for j∈1,2,3 as in
Lemmata 5.6 and 5.7, under the action of subgroups isomorphic to SUj(q) for j=3,4,5.
Such elements may have determinant different from 1 but the proof of these Lemmata does not require this assumption.
Hence all cases are covered, in view of Remark 5.5.
We study now the class of t2v∈Ot2vGFw for w=sa+b+1.
The non-trivial factors in [CG(t2),CG(t2)] are of type A2a and A2b, so q is necessarily even.
We work in
GFw
where Fw=Ad(s˙a+b+1)F, s˙a+b+1=(ida+b00000100100000ida+b). We may take v∈id+ke1,ℓ+1+kea+1,ℓ+1−a where
two nonzero elements outside the diagonal can occur only for a=b=1 and q=2.
It represents the class because it has the right Jordan form, centralises t2 and,
for suitable choice of the scalars, it lies in GFw. We take
[TABLE]
the case ξ2=0 is treated similarly. Let
[TABLE]
By looking at the (1,1) and (1,ℓ+1) entries we verify
that π(rs)2=π(sr)2 and by looking at the entries
(j,j) for j∈Ia+b,a+b+2
we verify that π(Or⟨r,s⟩)=π(Os⟨r,s⟩), hence OxG is of type D.
∎
Lemma 5.9**.**
Assume that we are in Setting 5.1 with Φ of type Aℓ, ℓ≥2
and xsq+1=z∈Z(GF)−1. Then OxG is not kthulhu.
Proof.
Here tq+1=ηid for some η∈k× such that ordη=b is a divisor of d=(q+1,ℓ+1), see Table 5.
Equation (5.1) shows that t and zt are conjugate,
hence the spectrum of t is the disjoint union of sets of the form
Sj={λjηl,l∈I0,b−1}, for j∈Ik, and the multiplicity is constant in Sj:
we denote it by mj. Hence t can be chosen to have form
[TABLE]
Then w(F(t))=t for w=τw0, where τ is the permutation represented by
the block-diagonal monomial matrix in GLℓ+1(k)
[TABLE]
Decomposition (3.3) consists of a factor Hj≃∏j=1dSLmj(k),
for each j∈Ik such that mj>1. More precisely, ω=τw0θ cyclically permutes
the irreducible components of the root systems of Hj and
maps a simple root in one factor to the opposite of a simple root in the following factor.
Hence, Gj≃SLmj(qd) when d is even or mj=2 and
Gj≃SUmj(qd) when d is odd and mj>2.
Assume k>1 and let j0∈Jv. By construction, CW(wθ)=CW(τ),
so it contains the permutations corresponding to each factor τj, they preserve every Hj, and
[TABLE]
Thus, for any j=j0, the element τj satisfies the hypotheses of
Lemma 3.4 and OxG is not kthulhu.
Assume now k=1, so ∣Jv∣=1 and write for simplicity λ1=λ, m1=m, so ℓ+1=dm. Then
[TABLE]
Hence, if either m is even or d is odd, we have λℓ+1=1 so
λid∈Z(SUℓ+1(q)) and multiplying by λ−1id we reduce
to the case in which tq+1=1 and invoke Lemma 5.8. If, instead, m is odd and d is even, then
G1≃SLm(qd) with m>2 and qd>2, so x cannot satisfy condition (3.5).
∎
Lemma 5.10**.**
Assume that we are in Setting 5.1 with Φ of type Aℓ, ℓ≥2.
Then OxG is not kthulhu.
Proof.
The case xsq+1=1 is covered by Lemma 5.8
whereas the case xsq+1=1 is covered by Lemma 5.9.∎
Lemma 5.11**.**
Assume that we are in Setting 5.1, with Φ of type Dℓ with ℓ=2n+1≥5.
Then O is not kthulhu.
Proof.
We adopt the notation
of Lemma 4.14. The non-trivial element z∈Z(GF) generates the kernel of the projection
G→SO2ℓ(k), so for t′∈T we have t=zt′ if and only if π(t)=π(t′).
In this situation [H,H] has root system of type Da×Db×∏jAkj, where
D1 corresponds to a torus, D2 is A1×A1, D3=A3.
Recall that the components of type Akj correspond to equal eigenvalues λ of
π(t)∈SO2ℓ(k) distinct from ±1, whereas Da and Db
correspond to a sequence of
equal eigenvalues λ=±1. Thus, if q is even there is at most one component of type D in [H,H].
Assume first that tq+1=1 and take w=w0 so CW(wθ)=W.
Thus, wθ acts as −id on Φ, so all Gi are Fw-stable and
if Gj is of type Ak, then Gj≃SUk+1(q) for k≥1, where we set
SU2(q):=SL2(q). By hypothesis, Jv=∅ and (3.5) or (3.6) impose restrictions on the subgroups Hj with j∈Jv.
For most possibilities for Hj we will prove the statement by exhibiting a σ∈CW(wθ) satisfying the hypotheses of Lemma 3.4. In the remaining case we will apply Lemma 3.9
If Hj≃SL2l(k) is of type A2l−1 with base
{αc,…,αc+2l−2}={εc−εc+1,…,εc+2l−2−εc+2l−1},
then we take
σ=∏i=0l−1sεc+2i−εc+2i+1sεc+2i+εc+2i+1.
Condition σ(π(t))=π(t) holds because σ interchanges the eigenvalue λ with λ−1.
If Hj≃SL2l+1(k) is of type A2l for some l, and has root system with base
{αc,…,αc+2l−1}={εc−εc+1,…,εc+2l−1−εc+2l},
then we take
σ=(∏i=0l−1sεc+2i−εc+2i+1sεc+2i+εc+2i+1)sεc+2l−1−εc+2lsεc+2l−1+εc+2l.
If Hj is of type D3≃A3 then the eigenvalue λ=±1 has multiplicity 6 and q
is necessarily even so λ=1 and all remaining eigenvalues of π(t) are different from their inverses.
We take σ=∏i=0n−2sε4+2i−ε4+2i+1sε4+2i+ε4+2i+1, recalling that ℓ=2n+1.
Assume finally that there are no factors as above, so Hj is a simple factor contained in the component of type D2≃A1×A1.
The base of the root system of type D2 is either {α0,α1} or {αℓ−1,αℓ}.
In the first case we take σ=sε3−ε4sε3+ε4, in the latter we take
σ=sε1−ε2sε1+ε2. Condition 3 in Lemma 3.4 holds
unless π(t) has only eigenvalues ±1, or, equivalently, Φt has type D2×Dℓ−2.
If this is the case, we replace w by w′=w0wΠ, where wΠ is the longest element in WΠ and we replace Fw by Fw′.
Then w′θ acts trivially on the root system of type A3 containing D2, so Lemma 3.9 applies with
β1=α1,β2=α2,β3=−α0. This concludes the case tq+1=1.
Assume now tq+1=z∈Z(GF)−1. Then q is necessarily odd, see Table 5.
Also, (5.1) shows that
ww0∈WΠ whereas ww0 fixes π(t). Hence, CSO2ℓ(π(t))⊋π(H).
Arguing as in the proof of Lemma 4.16 we deduce that this can happen only if π(t) has both eigenvalues equal to
1 and −1. Since π⊂Δ, we have
π(t)jj=ϵ for ϵ2=1 and j∈I1,a∪I2ℓ−a+1,2ℓ and π(t)jj=−ϵ for j∈Iℓ−b+1,ℓ+b. Also,
[TABLE]
and by [20, 2.2] it is isomorphic to ⟨WΠ,ww0⟩/WΠ.
Thus, ww0WΠ=sε1+εℓsε1−εℓWΠ and therefore we may assume
w=sε1+εℓsε1−εℓw0. Hence,
CW(ww0)=CW(sε1+εℓsε1−εℓ).
Since q is odd, Gj is of type A1 for every j∈Jv. Such a factor comes from an eigenvalue
λ of π(t) of multiplicity 2 if λ=±1 and of multiplicity 4 if λ=±1.
Let j∈Jv. If the corresponding λ=±1 and π(t)ll=π(t)l+1,l+1=λ, then
σ=sεl+εl+1sεl−εl+1 satisfies the hypotheses of Lemma 3.4.
If, instead π(t)jj=±1 for every j∈Iℓ, then (3.5) or (3.6) holds only if either 1 or −1 has multiplicity
4 and the root system of Gj is one of the irreducible components of the root system of type D2.
Acting possibly by τ=sε1−εℓsε2−εℓ−2 we may assume that the multiplicity 4
eigenvalue occurs in the entries indexed by 1,2,2ℓ,2ℓ−1. In this situation, D2 has base {α0,α1}.
As in the case tq+1=1 we replace w by w′=wwΠ and apply Lemma 3.9 to {−α0,α2,α1}.
∎
Finally, we deal with the groups 2E6(q). In order to use the list in [13], we need to establish a dictionary between pairs
(Π,[w]) coming from different choices for the Steinberg endomorphism F.
Remark 5.12*.*
For j=1,2, let Fj=ϑjFrq be Steinberg endomorphisms of G such that
F1=Adσ˙F2 for some σ∈NG(T) and let g0∈G be such that g0−1F2(g0)=σ˙.
Then GF2=g0GF1g0−1 and if for some z∈G we have x∈GF1∩OzG, it follows that
g0xg0−1∈GF2∩OzG. Assume s1∈GF1 is a semisimple element and let t1∈T, w˙1∈NG(T) and
g1∈G be such that g1−1F1(g1)=w˙1; s1=g1t1g1−1 and Ad(w˙1)F1(t1)=t1.
Then s2:=g0s1g0−1, t2:=t1, g2:=g0g1 and w˙2:=w˙1σ˙ satisfy
g2−1F2(g2)=w˙2; s2=g2t2g2−1 and Ad(w˙2)F2(t2)=t2.
Thus, if Π1 is a base for the root system of CG(t1), then it is also a base for the root system of CG(t2) and
comparing the actions of wjθj for j∈I2 on Φ gives
w1θ1=w1σθ2=w2θ2, hence the isomorphism classes of the groups [H,H]Ad(w˙j)Fj for j∈I2 coincide.
Lemma 5.13**.**
Assume that we are in Setting 5.1, with Φ of type E6. Then O is not kthulhu.
Proof.
We proceed as in the proof of Lemma 4.17, using the list in [13]
of pairs attached to a semisimple conjugacy class. The Steinberg endomorphism FFJ
used therein differs from our choice of F and there exists σ˙∈w0T such that FFJ=Adσ˙F.
By Remark 5.12 the pair (ΠFJ,[wFJ]) attached to a semisimple conjugacy class in GFFJ
is related to the pair attached to the corresponding semisimple conjugacy class in GF by the law
(ΠFJ,[wFJ])=(Π,[ww0])=(Π,[wθ]). Also, the groups GiFw can be extracted from the list in [13].
We have to deal with the case in which tq=zt−1 for some z∈Z(GF). By (5.1)
the element wFJ=ww0 normalises H, whence WΠ. Also, (ww0)3t=t, so ∣ww0WΠ∣∈{1,3}.
Observe that in all cases in which α0∈Π, then t∈∏i=2αi∨(k) so it lies in the subgroup
K:=⟨U±αj,j=1,3,4,5,6⟩≃SL6(k).
All mixed classes in KFw are not kthulhu by [2] and Lemma 5.10.
Assume first ∣ww0WΠ∣=3 so (5.1) forces z=1. In particular, q≡2(3) in this case.
All pairs as in Lemma 4.17 with wJF=ww0=1 that have been discarded because of the order,
can be again discarded for the same reason, as well as those that were discarded by using Remark 3.7 (3).
As observed in [13], the groups GiFw for 2E6(q) are obtained from those in the list for E6(q) by interchanging
Chevalley and Steinberg’s types in each factor of type A,D or E6. We are thus left with the cases in Table 6.
There, βi for i=10,11,19,20,21,22 are as in Lemma 4.17 and
[TABLE]
If Π={−α0} or {α2,−α0} or {α4,α6,−α0}, then Lemma 3.4
applies with σ=s1s3 in the first two cases and σ=s1 in the third one.
Let Π={α1,α4,α6,−α0}. If v∈⟨U±α0⟩, then Lemma 3.4
applies with σ=sβ11sβ21. If, instead, v∈⟨U±αj,j=1,4,6⟩, then tv∈K and it is mixed therein.
We claim that the case Π={α1,α3,α5,α6,α2,−α0} with tq+1∈Z(GF)−1 cannot occur.
Indeed, here t=α1∨(ξ)α3∨(ξ2)α5∨(ζ)α6∨(ζ2) with ξ3=ζ3=1,
ξ=ζ, so tq+1=1 because q≡2(3).
We deal now with the case ∣ww0WΠ∣=1. Then (ww0)−1∈WΠ so (5.1) implies
tq+1=z=1 and we take w=w0, so CW(wθ)=W. Since either (3.5) or (3.6) holds,
we discard all choices of Π for which no Gi is isogenous to SUm(q), PSL3(2) or SL2(q). This leaves us
with Table 7. In most remaining cases we apply Remark 5.4 and we list the simple roots we use in
the third column of Table 7. We deal with the remaining cases separately. Observe that since w=w0, the subgroup
K is Fw-stable and wθ acts as −1 on its root system, so KFw≃SU6(q).
Let Π={α1,α3,α4,α6,−α0}. If v has a component in either ⟨U±α0⟩ or
⟨U±α6⟩, then Lemma 3.4 applies with either σ=s5 or σ=s2. Assume
∣Jv∣=1 and v∈⟨U±αj,j=1,3,4⟩. Since −α0∈Π we have tv∈K and it is mixed therein.
Let Π={α1,α3,α4,α5−α0}. If v has a component in ⟨U±α0⟩ then
Lemma 3.4 applies with σ=s6. If v∈⟨U±αj,j=1,3,4,5⟩, since −α0∈Π we
have tv∈K and it is mixed therein.
Let Π={α1,α2,α3,α5α6,−α0}. Here
t=α1∨(ξ)α3∨(ξ2)α5∨(ζ)α6∨(ζ2) with ξ3=ζ3=1, ξ=ζ.
The Weyl group involution σ=sβ13sβ14sβ15 satisfies
σ(α1)=α5, σ(α3)=α6 and σ(α0)=α2. Hence, if v has a component in
⟨U±α0⟩, then Lemma 3.4 applies. If, instead, v has no component in
⟨U±α0⟩, then tv∈K and it is mixed therein.
Let Π={α1,α3,α4,α5,α6,−α0}. A direct computation shows that,
t=α1∨(ζ)α3∨(ζ2)α4∨(−1)α5∨(ζ4)α6∨(ζ5) for
ζ∈k such that ζ6=1, ζ3=−1=1. Hence q is odd and (3.5) implies that v∈⟨U±α0⟩.
Also, the condition tq=t−1 gives F(t)=ϑtq=ϑt−1=t, so t∈GF and we may take
xs=t and replace w=w0 by w=1. By Remark 4.9 we assume v=xα0(ξ)
for some ξ∈k×. Lemma 3.9 applies taking β1=α0, β2=α2 and β3=α4.
∎
Putting together Lemma 3.6, Proposition 3.8
and Lemmata 5.2 up to 5.13, we prove the main Theorem of this Section:
Theorem 5.14**.**
Let G be a Steinberg group and x=xsxu∈G with xs,xu=1.
Then OxG is not kthulhu, and consequently OxG collapses.∎
6. Nichols algebras over Chevalley and Steinberg groups
In order to prove Theorems 1.2 and 1.3, we have to consider now Nichols algebras attached to Yetter-Drinfeld
modules over some specific finite groups, in other words, the cocycle q is not arbitrary, but determined by a representation of the centraliser
of a fixed element in the conjugacy class.
6.1. Unipotent orbits in Chevalley and Steinberg groups
Let G be a Chevalley or Steinberg group isomorphic to neither PSL3(2) nor PSL2(3)≃A4, the latter being non-simple.
Note that, as PSL3(2)≃PSL2(7),
the only unipotent conjugacy class in PSL3(2) which is kthulhu is isomorphic to a semisimple
class in PSL2(7).
We now deal with Nichols algebras associated with unipotent classes O in G and representations of the centraliser of x∈O.
In most of the cases we will prove that they are infinite-dimensional by reducing to a subgroup of G for which a similar statement is known.
We begin with a case for which this strategy cannot be implemented, see Remark 6.4 below.
Lemma 6.1**.**
Let G=Sp4(3), G=PSp4(3) and π:G→G the natural projection.
Let O be the unipotent class of an element g0∈G whose Jordan form has blocks of size (2,1,1).
Then, dimB(M(O,ρ))=∞ for every ρ∈IrrCG(g0).
The same statement holds replacing g0 by π(g0) and CG(g0) by CG(π(g0)).
Proof.
There are two such unipotent classes in G and they are represented by g0=idηe1,4, with η2=1.
We find a suitable abelian subrack of O
and apply the results in [17] on Nichols algebras of diagonal type.
For both choices of g0,
we consider the abelian subgroup H of CG(g0) consisting of matrices of block form
g(X):=(id20Xid2) where X=(acba) for a,b,c∈F3. Then
[TABLE]
with:
[TABLE]
Observe that
[TABLE]
As H is abelian, the restriction of ρ to H decomposes as a direct sum of 1-dimensional representations; let Cv
be one of these and let ρ(gi)v=ζiv for every
i∈I0,3.
We necessarily have ζi3=1 and ζ0ζ1ζ2ζ3=1.
Then spanC{xi⊗v,i∈I0,3} is a braided vector subspace of M(O,ρ), where
[TABLE]
By direct computation we obtain
[TABLE]
so
[TABLE]
Let W=spanC{xi⊗v,i∈I1,3}. If either ζ0=1 or dimB(W)=∞, then dimB(M(O,ρ))=∞,
so we assume that ζ0 is a primitive third root of 1 and that dimB(W)<∞.
Since the generalized Dynkin diagram of W does not occur in [17, Table 2], it must be
disconnected. This forces ζ1=ζ02, but then the generalized Dynkin diagram of
W′=spanC{x0⊗v,x1⊗v} is connected and does not occur in
[17, Table 1], so dimB(W′)=∞, and a fortiori dimB(M(O,ρ))=∞.
The statement for G follows similarly because the restriction of π to O∩H is injective.
∎
Proposition 6.2**.**
Let n≥2, let M be either Sp2n(3) or PSp2n(3), and let O be the unipotent class of an element xu in M
whose Jordan form has blocks of size (2,12n−2).
Then, dimB(M(O,ρ))=∞ for every ρ∈IrrCM(xu).
Proof.
If n=2 this is Lemma 6.1. If n>2 we use the embeddings of Sp4(3) into Sp2n(3) and PSp2n(3) given by
(ACBD)↦(ACid2n−4BD) and [6, Lemma 3.2].
∎
We are now in a position to prove our next theorem.
Theorem 6.3**.**
Let x be a unipotent element in a Chevalley or Steinberg group G≃PSL3(2), PSL2(3).
Then dimB(Ox,ρ)=∞ for all ρ∈IrrCG(x).
Proof.
We may assume that x is non-trivial.
By Theorem 2.6 it is enough to prove the statement for the conjugacy classes in Table 1.
If q=3, then we invoke Proposition 6.2. Let q=3. These conjugacy classes are represented by an element
xβ(ξ) with ξ∈Fq× and β a positive root by Remark 2.7.
Since xβ(ξ)∈⟨UβF,U−βF⟩≤SL2(q) or ≤PSL2(q),
the statement follows from [6, Lemma 3.2] together with: [14, Proposition 3.1] for q even;
[15, Lemma 2.2] for p>3,
and the proof of [14, Lemma 3.7] for q=32h+1, h>0.
∎
Remark 6.4*.*
(a) We do not know whether dimB(M(O),ρ)=∞ for Ou a non-trivial unipotent conjugacy class in G=PSL2(3)
and ρ an irreducible representation of CG(u). Indeed, the proof of [15, Proposition 4.3]
does not cover the case of non-trivial unipotent conjugacy classes in PSL2(3) because they are not real.
These conjugacy classes correspond to the tetrahedral rack associated with a class of 3-cycles in A4.
(b) There are examples of finite-dimensional Nichols algebras associated with the rack Ou as in (a)
and a cocycle that does not come from a representation of CG(u), see [18, Proposition 36].
Proof of Theorem 1.2. By [19],
V should be simple, say V≃M(O,ρ).
By Theorem 1.1, we know that O is either semisimple or unipotent,
but the latter is discarded by Theorem 6.3.
□
Proof of Theorem 1.3.
Let V=M(O,ρ)∈CGCGYD. Assume that dimB(V)<∞.
By Theorem 1.2, O=Ox is semisimple, hence ordx is odd since q is even.
Since G is one of the groups in (1.2), −id belongs to the Weyl group W.
Thus O is real by §2.6.
This contradicts [8], hence dimB(V)=∞. We conclude by [6, Lemma 1.4].
□
Notice that [19] is not needed for the last proof.
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