This paper establishes rigidity results for proper holomorphic mappings between generalized Fock-Bargmann-Hartogs domains by explicitly computing Bergman kernels, demonstrating the mappings' structural constraints in these complex, unbounded, and non-hyperbolic domains.
Contribution
It provides the first explicit formula for Bergman kernels on these domains and proves rigidity of proper holomorphic mappings, extending understanding of complex mappings in unbounded non-hyperbolic domains.
Findings
01
Rigidity results for proper holomorphic mappings between generalized Fock-Bargmann-Hartogs domains.
02
Explicit formulas for Bergman kernels on these domains.
03
Identification of unbounded weakly pseudoconvex domains with mapping rigidity.
Abstract
A generalized Fock-Bargmann-Hartogs domain Dnm,p is defined as a domain fibered over Cn with the fiber over z∈Cn being a generalized complex ellipsoid Σz(m,p). In general, a generalized Fock-Bargmann-Hartogs domain is an unbounded non-hyperbolic domains without smooth boundary. The main contribution of this paper is as follows. By using the explicit formula of Bergman kernels of the generalized Fock-Bargmann-Hartogs domains, we obtain the rigidity results of proper holomorphic mappings between two equidimensional generalized Fock-Bargmann-Hartogs domains. We therefore exhibit an example of unbounded weakly pseudoconvex domains on which the rigidity results of proper holomorphic mappings can be built.
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Taxonomy
TopicsHolomorphic and Operator Theory · Analytic and geometric function theory · Algebraic and Geometric Analysis
Full text
Rigidity of proper holomorphic mappings between generalized Fock-Bargmann-Hartogs domains
Enchao Bi1**∗ & Zhenhan Tu2
1School of Mathematics and Statistics, Qingdao
University, Qingdao, Shandong 266071, P.R. China
2School of Mathematics and Statistics, Wuhan
University, Wuhan, Hubei 430072, P.R. China
Abstract A generalized Fock-Bargmann-Hartogs domain
Dnm,p is defined as a domain fibered over
Cn with the fiber over z∈Cn being a generalized complex ellipsoid Σz(m,p). In general, a generalized Fock-Bargmann-Hartogs domain is an unbounded non-hyperbolic domains without smooth boundary. The main contribution of this paper is
as follows. By using the explicit formula of Bergman kernels of the generalized Fock-Bargmann-Hartogs domains, we obtain the rigidity results of proper holomorphic mappings between two equidimensional generalized
Fock-Bargmann-Hartogs domains. We therefore exhibit an example of unbounded weakly pseudoconvex domains on which the rigidity results of proper holomorphic mappings can be built.
A holomorphic map F:Ω1→Ω2 between two domains Ω1,Ω2 in Cn is said to be proper if F−1(K) is compact in Ω1 for every compact subset K⊂Ω2. In particular, an automorphism F:Ω→Ω of a domain Ω in Cn is a proper holomorphic mapping of Ω into Ω.
There are many works about proper holomorphic mappings between various bounded domains with some requirements of the boundary (e.g., Bedford-Bell [3], Diederich-Fornaess [8],
Dini-Primicerio [9] and Tu-Wang [24]). However, very little seems to be known about proper holomorphic mapping between the unbounded weakly pseudoconvex domains. There are also
some works about automorphism groups of hyperbolic domains (e.g., Isaev [10], Isaev-Krantz [11] and Kim-Verdiani [14] ). In this paper, we mainly focus our attention on some unbounded non-hyperbolic weakly pseudoconvex domains.
The Fock-Bargmann-Hartogs domain Dn,m(μ) is defined by
[TABLE]
where
∥⋅∥ is the standard Hermitian norm. The
Fock-Bargmann-Hartogs domains Dn,m(μ) are strongly
pseudoconvex domains in Cn+m with smooth real-analytic boundary. We note that each
Dn,m(μ) contains {(z,0)∈Cn×Cm}≅Cn. Thus each
Dn,m(μ) is not hyperbolic in the sense of Kobayashi and
Dn,m(μ) can not be biholomorphic to any bounded domain in
Cn+m. Therefore, each Fock-Bargmann-Hartogs domain
Dn,m(μ) is an unbounded non-hyperbolic domain in
Cn+m.
In 2013, Yamamori [25] gave an explicit formula for the
Bergman kernels of the Fock-Bargmann-Hartogs domains in terms of the
polylogarithm functions. In 2014, by checking that the Bergman
kernel ensures revised the Cartan’s theorem, Kim-Ninh-Yamamori
[13] determined the automorphism group of the
Fock-Bargmann-Hartogs domains as follows.
The
automorphism group Aut(Dn,m(μ)) is exactly the group
generated by all automorphisms of Dn,m(μ) as follows:
[TABLE]
where U(k) is the unitary group of degree k, and
⟨⋅,⋅⟩ is the standard Hermitian inner
product on Cn.
Recently, Tu-Wang [23] has established the rigidity of the proper holomorphic mappings between two equidimensional Fock-Bargmann-Hartogs domains as follows.
If Dn,m(μ) and Dn′,m′(μ′) are two equidimensional
Fock-Bargmann-Hartogs domains with m≥2 and f is a proper
holomorphic mapping of Dn,m(μ) into Dn′,m′(μ′), then
f is a biholomorphism between Dn,m(μ) and
Dn′,m′(μ′).
A generalized complex ellipsoid (also called generalized
pseudoellipsoid) is a domain of the form
[TABLE]
where n=(n1,⋯,nr)∈Nr and
p=(p1,⋯,pr)∈(R+)r. In the special
case where all the pk=1, the generalized complex ellipsoid
Σ(n;p) reduces to the unit ball in
Cn1+⋯+nr. Also, it is known that a generalized
complex ellipsoid Σ(n;p) is homogeneous if
and only if pk=1 for all 1≤k≤r (cf. Kodama [15]).
In general, a generalized complex ellipsoid is not strongly
pseudoconvex and its boundary is not smooth. The automorphism group Aut(Σ(n;p)) of
Σ(n;p) has been studied by Dini-Primicerio
[9], Kodama [15] and Kodama-Krantz-Ma
[16].
In 2013, Kodama [15] obtained the result as follows.
(i)*
If 1 does not appear in p1,⋯,pr, then any automorphism
φ∈Aut(Σ(n;p)) is of the form*
[TABLE]
where σ∈Sr is a permutation of the r numbers
{1,⋯,r} such that nσ(i)=ni,pσ(i)=pi,
1≤i≤r and γ1,⋯,γr are unitary
transformation of Cn1(nσ(1)=n1),⋯,Cnr(nσ(r)=nr) respectively.
(ii)* If 1 appears in p1,⋯,pr, we can assume, without
loss of generality, that p1=1,p2=1,⋯,pr=1, then
Aut(Σ(n;p)) is generated by elements
of the form (1.1) and automorphisms of the form*
[TABLE]
where Ta is an automorphism of the ball Bn1 in
Cn1, which sends a point a∈Bn1 to
the origin and
[TABLE]
In this paper, we define the generalized Fock-Bargmann-Hartogs
domains Dn0n,p(μ) as follows:
[TABLE]
where p=(p1,⋯,pl)∈(R+)l,n=(n1,⋯,nl),w(j)=(wj1,⋯,wjnj)∈Cnj, in which
nj is a positive integer for 1≤j≤l. Here and
henceforth, with no loss of generality, we always assume that pi=1
(2≤i≤l) for Dn0n,p(μ).
Obviously, each generalized
Fock-Bargmann-Hartogs domain Dn0n,p is an
unbounded non-hyperbolic domain. In general, a generalized
Fock-Bargmann-Hartogs domain is not a strongly pseudoconvex domain and its
boundary is not smooth.
In this paper, we prove the following results.
Theorem 1.4**.**
Suppose Dn0n,p(μ) and Dm0m,q(ν) are two equidimensional generalized Fock-Bargmann-Hartogs domains.
Let f:Dn0n,p(μ)→Dm0m,q(ν)
be a biholomorphic mapping. Then there exists ϕ∈Aut(Dm0m,q(ν)) such that
[TABLE]
where
σ∈Sl is a permutation such that nσ(j)=mj, pσ(j)=qj(1≤j≤l),
μνA∈U(n)(n:=n0=m0), and Γi∈U(mi)(1≤i≤l).
Corollary 1.5**.**
Let f:Dn0n,p(μ)→Dn0n,p(μ) be a biholomorphic mapping with f(0)=0. Then we have
[TABLE]
where σ∈Sl is a permutation such that nσ(j)=nj, pσ(j)=pj(1≤j≤l),
A∈U(n0) and Γi∈U(ni)(1≤i≤l).
As a consequence, it is easy for us to prove the following results.
Theorem 1.6**.**
The automorphism
group Aut(Dn0n,p(μ)) is generated by the following
mappings:
[TABLE]
[TABLE]
[TABLE]
where a∈Cn0, A∈U(n0), σ∈Sl is a permutation such that nσ(j)=nj, pσ(j)=pj(1≤j≤l), and
[TABLE]
in which Γi∈U(ni) (1≤i≤l).
Now, for p and q, we introduce notation:
[TABLE]
Theorem 1.7**.**
Suppose Dn0n,p(μ) and Dm0m,q(ν) are two equidimensional generalized Fock-Bargmann-Hartogs domains with min{n1+ϵ,n2,⋯,nl,n1+⋯+nl}≥2 and min{m1+δ,m2,⋯,ml,m1+⋯+ml}≥2. Then any proper holomorphic mapping between Dn0n,p(μ) and Dm0m,q(ν) must be a biholomorphism.
Remark 1.1**.**
The conditions min{n1+ϵ,n2,⋯,nl}≥2 can not be removed. For example, n1=1 (i.e, w1∈C), p1=1, and
[TABLE]
Then F is a proper holomorphic mapping between Dn0n,p(μ) and Dn0n,q(μ) where q=(p1/2,p2,⋯,pl). F is not a biholomorphism.
Corollary 1.8**.**
Suppose Dn0n,p(μ) is a generalized Fock-Bargmann-Hartogs domain with
[TABLE]
Then any proper holomorphic self-mapping of Dn0n,p(μ) must be an automorphism.
Remark 1.2**.**
The conditions n1+⋯+nl≥2 can not be removed. For instance, with no loss of generality, we can assume n1=1 and ni=0 (2≤i≤l). Then
[TABLE]
is a proper holomorphic self-mapping of Dn0n,p(μ) which is not an automorphism.
The paper is organized as follows. In Section 2, using the explicit formula for the Bergman kernels of the generalized Fock-Bargmann-Hartogs domains, we prove
that a proper holomorphic mapping between two equidimensional generalized Fock-Bargmann-Hartogs domains extends holomorphically to their closures and check that the Cartan’s theorem holds also for the generalized
Fock-Bargmann-Hartogs domains. In Section 3, we exploit the boundary structure of generalized Fock-Bargmann-Hartogs domains to prove our results in this paper.
2 Preliminaries
2.1 The Bergman kernel of the domain Dn0n,p
For a domain Ω in Cn, let A2(Ω) be the
Hilbert space of square integrable holomorphic functions on Ω
with the inner product:
[TABLE]
where dV is the Euclidean volume form. The Bergman kernel K(z,w)
of A2(Ω) is defined as the reproducing kernel of the Hilbert
space A2(Ω), that is, for all f∈A2(Ω), we have
[TABLE]
For a positive continuous function p on Ω, let
A2(Ω,p) be the weighted Hilbert space of square integrable
holomorphic functions with respect to the weight function p with
the inner product:
[TABLE]
Similarly, the weighted Bergman kernel KA2(Ω,p) of
A2(Ω,p) is defined as the reproducing kernel of the Hilbert
space A2(Ω,p). For a positive integer m, define the
Hartogs domain Ωm,p over Ω by
[TABLE]
Ligocka [17, 18] showed that the Bergman kernel of
Ωm,p can be expressed as infinite sum in terms of the
weighted Bergman kernel of A2(Ω,pk)(k=1,2,⋯) as
follows.
Let
Km be the Bergman kernel of Ωm,p and let
KA2(Ω,pk) be the weighted Bergman kernel of
A2(Ω,pk)(k=1,2,⋯). Then
[TABLE]
where (a)k denotes the Pochhammer symbol
(a)k=a(a+1)⋯(a+k−1).
The Fock-Bargmann space is the weighted Hilbert space
A2(Cn,e−μ∥z∥2) on Cn with the
Gaussian weight function e−μ∥z∥2(μ>0). The
reproducing kernel of A2(Cn,e−μ∥z∥2), called
the Fock-Bargmann kernel, is μneμ⟨z,t⟩/πn (see Bargmann [2]). Thus, the
Fock-Bargmann-Hartogs domain Dn,m={(z,w)∈Cn×Cm:∥w∥2<e−μ∥z∥2}(μ>0) and the
Fock-Bargmann space A2(Cn,e−μ∥z∥2) are closely
related. In 2013, using Theorem 2.1 and the expression of the
Fock-Bargmann kernel, Yamamori [25] gave the Bergman kernel of
the Fock-Bargmann-Hartogs domain Dn,m as follows.
The Bergman
kernel of the Fock-Bargmann-Hartogs domain Dn,m is given
by
[TABLE]
where (a)k denotes the Pochhammer symbol
(a)k=a(a+1)⋯(a+k−1).
Following the idea of Theorem 2.1, we compute the Bergman kernel for the generalized
Fock-Bargmann-Hartogs domain Dn0n,p. In order
to compute the Bergman kernel, we first introduce some notation.
Let
[TABLE]
where
α(i)=(αi1,⋯,αini)∈(R+)ni for 1≤i≤l.
For α∈(R+)n, we define
[TABLE]
see D’Angelo [7]. Here Γ is the usual Euler Gamma function.
where dV is the Euclidean n-dimensional volume form,
dS is the Euclidean (n−1)-dimensional volume form, and
the subscript ‘‘+" denotes that all the variables are positive,
that is, B+n=Bn∩(R+)n and
S+n−1=Sn−1∩(R+)n, in which Bn is
the unit ball in Rn and Sn−1 is the unit sphere
in Rn.
Theorem 2.4**.**
Suppose
α=(α(1),⋯,α(l))∈(R+)n1×⋯(R+)nl,α(i)=(αi1,⋯,αini)∈(R+)ni,1≤i≤l. Then we have the
formula:
[TABLE]
Proof.
For the integral
[TABLE]
by applying the polar coordinates w=seiθ (namely,
wij=sijeiθij,1≤j≤ni,1≤i≤l, s=(s(1),⋯,s(l))), we have
[TABLE]
Using the spherical coordinates in the variables s(1),s(2),⋯,s(l) respectively, we get
[TABLE]
Let ρipi=ri,1≤i≤l. Then we have
dρi=pi1ρi1−pidri=pi1ripi1−1dri. Therefore, Lemma 2.3 and the
above formulas yield
[TABLE]
Let r=(r1,r2,⋯,rl)∈(R+)l and
k:=t−21r. Then dr=t2ldk. After a straightforward computation, we obtain
that (2.2) equals
where
α′=(p1∣α(1)∣+n1,⋯,pl∣α(l)∣+nl)∈(R+)l.
∎
Now we consider
the Hilbert space A2(Dn0n,p(μ)) of square-integrable holomorphic functions on Dn0n,p(μ).
Lemma 2.5**.**
*Let f∈A2(Dn0n,p(μ)). Then
[TABLE]
*where the series is uniformly convergent on compact subsets of
Dn0n,p(μ),fα(z)∈A2(Cn0,e−μλα∥z∥2) for any α=(α(1),⋯,α(l))∈Nn1×⋯×Nnl,α(i)=(αi1,⋯,αini)∈Nni,1≤i≤l,
λα=i=1∑lpi∣α(i)∣+ni,
in which A2(Cn,e−μλα∥z∥2) denotes the space of square-integrable
holomorphic functions on Cn with respect to
the measure e−μλα∥z∥2dV2n.
Proof.
Since Dn0n,p(μ) is a
complete Reinhardt domain, each holomorphic function on
Dn0n,p(μ) is the sum of a locally uniformly
convergent power series. Thus, for f∈A2(Dn0n,p(μ)), we have
[TABLE]
where the series is uniformly convergent on compact subsets of
Dn0n,p(μ). We choose a sequence of
compact subsets Dk(1≤k<∞)
[TABLE]
where B(0,k) is the ball in Cn0+n1+⋯+nl
of the radius k. Obviously, Dk⋐Dk+1 and
k=1⋃∞Dk=Dn0n,p(μ).
Since Dk is a circular domain, then
Consequently, fα(z)∈A2(Cn0,e−μλα∥z∥2), where λα=i=1∑lpi∣α(i)∣+ni.
∎
Lemma 2.5 implies that f(z)wα where f(z)∈A2(Cn0,e−μλα∥z∥2) form a linearly dense subset of
A2(Dn0n,p(μ)). Now we can express the Bergman kernel of Dn0n,p(μ) as follows.
Theorem 2.6**.**
The Bergman
kernel of Dn0n,p(μ) can be expressed by the
following form
[TABLE]
where α=(α(1),⋯,α(l))∈Nn1×⋯×Nnl,α(i)=(αi1,⋯,αini)∈Nni,1≤i≤l, and
[TABLE]
Proof.
Since Dn0n,p(μ) is a complete Reinhardt domain,
it follows
[TABLE]
where the sum is locally uniformly convergent,
by the invariance of the Bergman
kernel KDn0n,p(μ) on Dn0n,p(μ) under the unitary subgroup action
[TABLE]
For any
α=(α(1),⋯,α(l))∈Nn1×⋯×Nnl with α(i)=(αi1,⋯,αini)∈Nni(1≤i≤l), any f(z)∈A2(Cn0,e−μλα∥z∥2)(λα=i=1∑lpi∣α(i)∣+ni), we have f(z)wα∈A2(Dn0n,p(μ)).
Thus
[TABLE]
By Bargmann [2], we get that the Bergman kernel of
A2(Cn0,e−μλα∥z∥2) can be described by the form
[TABLE]
Thus we obtain
[TABLE]
This completes the proof.
∎
The transformation rule for Bergman kernels under proper
holomorphic mapping (e.g., Th. 1 in Bell [4]) is also
valid for unbounded domains (e.g., see Cor. 1 in Trybula
[21]). Note that the coordinate functions play a key role
in the approach of Bell [4] to extend proper holomorphic
mapping, but, in general, are no longer square integrable on
unbounded domains. In order to overcome the difficulty, by combining
the transformation rule for Bergman kernels under proper holomorphic
mapping in Bell [4] and our explicit form (2.4) of the Bergman
kernel function for Dn0n,p(μ),
we prove that a proper holomorphic mapping between two equidi-
mensional generalized Fock-Bargmann-Hartogs domains extends holomorphically to their closures as follows.
Lemma 2.7**.**
Suppose that f:Dn0n,p(μ)→Dm0m,q(ν) is a proper holomorphic mapping
between two equidimensional generalized Fock-Bargmann-Hartogs
domains. Then f extends holomorphically to a
neighborhood of the closure Dn0n,p(μ).
In fact, using the explicit form (2.4) of the Bergman
kernel function for Dn0n,p(μ), we immediately have Lemma 2.7 by a slightly modifying the proof of Th. 2.5 in Tu-Wang [23].
2.2 Cartan’s Theorem on the Dn0n,p
Suppose D is a domain in CN and let KD(z,w) be its Bergman kernel. From Ishi-Kai [12], we know that if the following conditions are satisfied:
(a)KD(0,0)>0;
(b)TD(0,0) is positive definite,
where TD is an N×N matrix
[TABLE]
Then the Cartan’s theorem can also be applied to the case of unbounded circular domains. The above conditions are obviously satisfied by the bounded domain.
Kim-Ninh-Yamamori [13] proved the following result.
Suppose that D is a circular domain and its Bergman kernel satisfies the above conditions (a) and (b). If φ(∈Aut(D)) preserves the origin, then φ is a linear mapping.
Ishi-Kai [12] proved the generalization of Lemma 2.8 as follows.
Let Dk be a circular domain (not necessarily bounded)
in CN with 0∈Dk(k=1,2), and let
φ:D1→D2 be a biholomorphism with
φ(0)=0. If KDk(0,0)>0 and TDk(0,0) is positive
definite (k=1,2), then φ is linear.
Therefore, by using the expressions of Bergman kernels of generalized Fock-Bargmann-Hartogs domains, we have the following result.
Theorem 2.10**.**
Suppose that φ:Dn0n,p(μ)→Dm0m,q(ν) be a biholomorphic mapping
between two equidimensional generalized Fock-Bargmann-Hartogs domains with φ(0)=0. Then φ is linear.
Proof.
By using the expressions (2.4) of Bergman kernels of generalized Fock-Bargmann-Hartogs domains and a straightforward computation, we
show that the Bergman kernel of every generalized Fock-Bargmann-Hartogs domain satisfies the above conditions (a) and (b). So we get Th. 2.10 by Lemma 2.9.
∎
3 Proof Of The Main Theorem
To begin, we exploit the boundary structure of Dn0n,p(μ) which is comprised of
[TABLE]
where
[TABLE]
[TABLE]
[TABLE]
Now we give the following proposition.
Proposition 3.1**.**
(1)* The boundary b0Dn0n,p(μ) is a real analytic hypersurface in Cn0+n1+⋯+nl and Dn0n,p(μ) is strongly pseudoconvex at all points of b0Dn0n,p(μ).
(2)Dn0n,p(μ) is weakly pseudoconvex but not strongly pseudoconvex at any point of b1Dn0n,p(μ) and is not smooth at any point of b2Dn0n,p(μ).*
Proof.
Let
[TABLE]
Then ρ is a real analytic definition function of b0Dn0n,p(μ). Fix a point (z0,w(1)0,⋯,w(l)0)∈b0Dn0n,p(μ) and let
T=(ζ,η(1),⋯,η(l))∈T(z0,w(1)0,⋯,w(l)0)1,0(b0Dn0n,p(μ)).
Then by definition, we know that
[TABLE]
[TABLE]
[TABLE]
Thanks to (3.1), (3.2) and (3.3), the Levi form of ρ at the point (z0,w(1)0,⋯,w(l)0) can be computed as follows:
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
by the Cauchy-Schwarz inequality, for all T=(ζ,η(1),⋯,η(l))∈T(z0,w(1)0,⋯,w(l)0)1,0(b0Dn0n,p(μ)). Obviously, if ζ=0, then Lρ(T,T)>0.
On the other hand, combining with (3.1), (3.2) and (3.3), we know that the equality holds if and only if
[TABLE]
[TABLE]
[TABLE]
Suppose ζ=0, then T=(ζ,η(1),⋯,η(l))=0 implies that there exists ηi0=0. If Lρ(T,T)=0 for all T=0∈T(z0,w(1)0,⋯,w(l)0)1,0(b0Dn0n,p(μ)), then by (3.1), (3.2), (3.3) and (3.6), we have ηk=0 (1≤k≤l). This is a contradiction.
When there exists j0≥1+ϵ such that w(j0)02=0 and pj0>1, then (z0,w(1)0,⋯,w(l)0)∈b1Dn0n,p(μ). Let T0=(0,⋯,η(j0),0,⋯,0),∥η(j0)∥=0. Then Lρ(T0,T0)=0. Hence Dn0n,p(μ) is weakly pseudoconvex but not strongly pseudoconvex on any point of b1Dn0n,p(μ).
It is obvious that Dn0n,p(μ) is not smooth at any point of b2Dn0n,p(μ). The proof is completed. ∎
Let Σ(n;p) and Σ(m;q) be two equidimensional generalized pseudoellipsoids, n,m∈Nl, p,q∈(R+)l (where pk,qk=1for2≤k≤l). Let
h:Σ(n;p)→Σ(m;q) be a biholomorphic linear isomorphism between
Σ(n;p) and Σ(m;q). Then there exists a permutation σ∈Sr such that
nσ(i)=mi,pσ(i)=qi and
[TABLE]
where Ui is a unitary transformation of Cmi(mi=nσ(i)) for 1≤i≤r.
Define
[TABLE]
[TABLE]
Then we have the following lemma.
Lemma 3.2**.**
Suppose Dn0n,p(μ)
and Dm0m,q(ν)
are two equidimensional generalized Fock-Bargmann-Hartogs domains, f:Dn0n,p(μ)→Dm0m,q(ν)
is a biholomorphic mapping. Then we have f(V1)⊆V2 and f∣V1:V1→V2
is biholomorphic. Consequently n0=m0.
Proof.
Let
f(z,0)=(f1(z),f2(z)), then we get
i=1∑l∥f2i∥2qi<e−ν∥f1(z)∥2≤1.
Then we obtain that the bounded entire mapping
f2i(z) on Cn0 is constant (1≤i≤l) by Liouville’s Theorem. Since
f(z) is biholomorphic,
f1(z) is an unbounded function. Hence there exist
{zk} such that
f1(zk)→∞ as k→∞. It implies f2(z)≡0. This proves f(V1)⊆V2.
Similarly, by making the same argument for f−1,
we have f−1(V2)⊆V1. Namely, f∣V1:V1→V2 is biholomorphic.
Hence n0=m0.
∎
Let f(0,0)=(a,b) (thus b=0 by Lemma 3.2) and define
[TABLE]
Obviously, ϕ∈Aut(Dm0m,q(ν)) and ϕ∘f(0,0)=(0,0).
Then ϕ∘f is linear by Theorem 2.10. We describe ϕ∘f as follows:
[TABLE]
According to Lemma 3.2, we have f(z,0)=(f1(z),0). Thus B=0. Since g:=ϕ∘f is biholomorphic, A and D are invertible matrices. We write g(z,w) as follows:
[TABLE]
which implies that
[TABLE]
Set Σ(n;p)={(w(1),⋯,w(l))∈Cn1×⋯×Cnl:j=1∑l∥w(j)∥2pj<1}. Then, if j=1∑l∥w(j)∥2pj<e−μ∥0∥2=1, we obtain
[TABLE]
and
if j=1∑l∥w(j)∥2qj<e−ν∥0∥2=1,
we have
[TABLE]
Therefore, we conclude that the mapping
g2(w):Σ(n;p)→Σ(m;q) given by
[TABLE]
is a biholomorphic linear mapping. By Lemma 3.1, g2 can be expressed in the form:
[TABLE]
where σ∈Sl is a permutation with
nσ(j)=mj, pσ(j)=qj(j=1,⋯,l) and Γi∈U(mi)(1≤i≤l).
Hence g can be rewritten as follows:
[TABLE]
Next we prove that C=0. The linearity of g yields that
g(bDn0n,p)=bDm0m,q.
Let
(0,w)=(0,0,⋯,w(j),0,⋯,0)∈bDn0n,p,
namely, ∥w(j)∥2=(e−μ∥0∥2)pj1=1. As Γj(1≤j≤l) are unitary matrices, moreover,
assuming σ(i0)=j, we have
[TABLE]
This implies
w(j)Cj1=0 for all ∥w(j)∥2=1. So Cj1=0(1≤j≤l).
Thus we have
[TABLE]
Lastly, we show μνA∈U(n)(n:=n0=m0). For z∈Cn0, take (w(1),⋯,w(l)) such that
e−μ∥z∥2=j=1∑l∥w(j)∥2pj.
By g(bDn0n,p)=bDm0m,q, we have j=1∑l∥w(σ(j))Γj∥2qj=e−μ∥zA∥2.
Since Γj(j=1,⋯,l) are unitary matrices,
we get
[TABLE]
Therefore, ν∥zA∥2=μ∥z∥2(z∈Cn). Then we get μνA∈U(n), and the proof is completed.
∎
Obviously, φA,φD and φa are biholomorphic self-mappings of
Dn0n,p(μ).
On the other hand, for φ∈Aut(Dn0n,p(μ)), we
assume φ(0,0)=(a,b) (then b=0 by Lemma 3.2). Hence φ−a∘φ preserves the origin. Then by Corollary 1.5, we obtain φ−a∘φ=φD∘φA
for some φA,φD.
Hence φ=φa∘φD∘φA, and the proof is complete.
∎
Let f be a proper holomorphic mapping between two equidimensional generalized Fock-Bargmann-Hartogs domains Dn0n,p(μ) and Dm0m,q(ν). Then by Th. 2.7,
f extends holomorphically to a neighborhood Ω of Dn0n,p(μ) with
[TABLE]
Then by Proposition 3.1 and Lemma 1.3 in Pinčuk [19], we have
[TABLE]
where
M:=\big{\{}z\in\Omega,\mathrm{det}(\frac{\partial f_{i}}{\partial z_{j}})=0\big{\}} is the zero locus of the complex Jacobian of the holomorphic mapping f on Ω.
If M∩bDn0n,p(μ)=∅, then, from min {n1+ϵ,n2,⋯,nl}≥2, we have M∩b0Dn0n,p(μ)=∅. Take an irreducible component M′ of M with M′∩b0Dn0n,p(μ)=∅. Then the intersection EM′ of M′ with b0Dn0n,p(μ) is a real
analytic submanifold of dimensional 2(n0+n1+⋯+nl)−3 on a dense, open subset of EM′. By (3.7), we have f(EM′)⊂b1Dm0m,q(ν)∪b2Dm0m,q(ν). Hence
[TABLE]
where Pri(Dm0m,q(ν)):={(z,w(1),⋯,w(l))∈Dm0m,q(ν),∥w(i)∥=0} (1+δ≤i≤l), by the uniqueness theorem. Since codimM′=1, codim[j=1+δ⋃lPri(Dm0m,q(ν))]≥min{m1+δ,⋯,ml,m1+⋯+ml}≥2 and f:Dn0n,p(μ)→Dm0m,q(ν) is proper, this is contradiction with (3.8). Thus we have M∩bDn0n,p(μ)=∅.
Let S:=M∩Dn0n,p(μ). Hence we have
[TABLE]
If S=∅, then S is a complex analytic set in Cn0+n1+⋯+nl also. For any (z,w)∈S, we have
∣wlnl∣2pl≤j=1∑l∥w(j)∥2pj≤e−μ∥z∥2≤1.
Thus
[TABLE]
where w=(w′,wlnl). Then S is an algebraic set of Cn0+n1+⋯+nl by §7.4 Th. 3 of Chirka [5].
Suppose S1 is an irreducible component of S. Let S1 be the closure of S1 in Pn0+n1+⋯+nl. Then by §7.2 Prop. 2 of Chirka [5], S1 is a projective algebraic set and dimS1=n0+n1+⋯+nl−1.
Let [ξ,z,w] be the homogeneous coordinate in Pn0+n1+⋯+nl, we embed Cn0+n1+⋯+nl into Pn0+n1+⋯+nl as the affine piece U0={[ξ,z,w]∈Pn0+n1+⋯+nl,ξ=0} by (z,w)↪[1,z,w]. Then we have
[TABLE]
Let H={ξ=0}⊂Pn0+n1+⋯+nl. Consider another affine piece U1={[ξ,z,w]∈Pn0+n1+⋯+nl,z1=0} with affine coordinate (ζ,t,s)=(ζ,t2,⋯,tn0,s(1),⋯,s(l)). Let t′=(1,t2,⋯,tn0).
Since ∣ξ∣2pj∥w(j)∥2pj=∣z1∣2pj∥w(j)∥2pj∣ξ∣2pj∣z1∣2pj=∣ζ∣2pj∥s(j)∥2pj and e−μ∣ξ∣2∥z∥2=e−μ∣z1∣2∥z∥2∣ξ∣2∣z1∣2=e−μ∣ζ∣21+∣t2∣2+⋯+∣tn0∣2, we obtain
[TABLE]
Let S′=S1∩U1 and H1=H∩U1={ζ=0} (note ξ=z1ζ). For every u∈S′∩H1, there exists a sequence of points {uk}⊂S1∩((U0∩U1)\H1) such that
uk→u(k→∞), The formula (3.10) implies
[TABLE]
Since u∈H1, that means ζ(u)=0 and ζ(uk)→0(k→∞). Therefore we have ∥s(j)(u)∥2pj≤0(1≤j≤l) as k→∞. Hence
[TABLE]
Then dim(S′∩H1)≤n0−1. Shafarevich [20] §6.2 Th. 6 implies
[TABLE]
This means dimS′≤n0, and thus n0+n1+⋯+nl−1=dimS′≤n0. Therefore, we get n1+⋯+nl≤1, a contradiction with assumption min {n1+ϵ,n2,⋯,nl,n1+⋯+nl}≥2.
Therefore, S=∅ and thus f is unbranched. Since the generalized Fock-Bargmann-Hartogs domain is simply connected, f:Dn0n,p(μ)→Dm0m,q(ν) is a biholomorphism. The proof is completed. ∎
Acknowledgments
We sincerely thank the referees, who read the paper very carefully and gave many useful suggestions. E. Bi was supported by the Natural Science Foundation of Shandong Province, China (No.ZR2018BA015), and Z. Tu was supported by
the National Natural Science Foundation of China (No.11671306).
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